1 like 0 dislike
11.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 11.9k views

37 Answers

0 like 0 dislike
Hidden content!
#include **** * * *
#include ** * *** *** **
* **** *** ** **
* * ******

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * * * ***

******** **** ** ** ** * * ** *
**** * * * *** *** *** ** == b[i]){
* **** ** *** ** * * * * *** * **** * **** *
** * * * ** ******* * * *

** * * * **** * *
if (cnt == n){
***** ** * ** ** * ** * * *** ** * * ** * * * 1;
* *** ** ** * *** * *** * * ** * * *
****** * * ** * **** *** *
** * * ** ** * * * ** * ** ******* * * * 0;

}

int main()
{
*** **** ** ** ** ***** s1[100], s2[100];
** * * * ** * ** * * * i,j;

* *** * * * ** ** ****** **** * * * s1);
* * * ** * * * *** ** * ** * ** *** * * s2);
*** *** ** * (prefix(s1, s2)){

* ******* ** ** * * *** ***** ** * ** * *** ******* is a prefix of %s", s1,s2);
** * * * ** **** ** *** * * *****
******* ** ** * * *** ** * ** * * * * *
** * * * *** * * * * ** * * ** *** *** ** * * * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * * ** ** *** * ** c;
** ** * * * ** ** * *** * a[100],b[100];
* * ***** * ** ***** * ** %s",a,b);
**** * * * ** * * ****** * *** * * * *** *
** * * ** * *** *** * ** * * * *** * * * ** * * 0;
**** * * ** * * * ** * **** **** %d",strlen(a),strlen(b));
** ** * ***** * * **** * * ** * *** ****
* ** ** *** * ** ***** ***** * * * * **** * * * * **** * ** * ** *
****** ** ** * * * ** * *** ** ** ** ***** ****** *** * *** **** * * * *** ***** * *** *** * is not a prefix of %s",a,b);
** * ** * *** * * ** ** * ** * * * * * * ** * * * *** * * * *** **** ** *** ** * ** **
* **** * *** ** * **** * * * *** ** ***** ** *** ****** * * ** **** * *
* * * ** ** * * *** * ** * * ** * ** * *** ** * ** * ** * * if(c==strlen(a)-1)
** ** *** ** **** ***** * ** * ** * * * *** * ** * *** * ** * ** * *** ** **** ******* ** ** is a prefix of %s",a,b);
    }
* * * * * **** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** ** * **** * * ** n,count;
****** ***** * * * * ** *** *** * * * * *
* **** * * **** ** * * * **** *** %s",a,b);
****** *** * *** **** **

***** *** ** * ** * ** * * * * * ***
* * * * * * * * ***
*** *** * *** * * ****** * * * ******* **** *** ****** ***
**** * *** * ** ** **

* ** * ** * ** * ** * (strcmp(a,c)==0)
** * * *** ****** * *
**** * * ** * ** * * *** * * * * * ***** is a prefix of %s",a,b);
** **** * * * *** * * *
* * * * *** * ** * ******* **
*** * * * ** * *** * **
* * * * * ** ** ***** * *** *** * *** ** is not a prefix of %s",a,b);
*** ** ** * * * ***** * *
** ** * * **** *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** *** * **** * * a[100],b[100];
** * *** *** * ** ** * ** * * **
    int l1,l2;
* * *** * ** *** * * * ** ** *
* *** * * * * * ** ** *
**** * ****** **** *** **
* * * ** * *** ***** ** ** * *** * ** * *** is not a prefix of %s",a,b);

    }
* ****** ** * * * * ** * if(l1<=l2){
**** * * * ** * * * * * *** *** ** ****** prefix=1;
** ** ** * * ** ** * ** * * ** ** *** * *** i=0;
* * * *** * *** *** ** * ** ** * *** ** * *
* ** ***** * * * * * * **** * * ** ** ** * *** * ***** * * ** ** (a[i]!=b[i]){
** * ** * ** * ** * ** **** * * * **** *** *** * *** *** *** * * ** *****
* ** ** * * * * * *** ** *** ** * * *** * ** * * * * * ** * ** *** *** **
*** *** ** * * * * **** * ** ** **** **** * *** ** **


*** * *** * ** **** *** ** ** **
* ** ** * *** * * *** ** * **** * *********** ** *
** ** **** ****** * *** *** * * *** ***** * * **** ***** * * * *** * ** * is not a prefix of %s",a,b);
* * * * *** * *** * ****** *
** * * * * *** * ** * **** * ** * **** **
** ** * ** *** * * * ** ***** *** * *** * ** *** ** * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * *** * * * *
int main(void)
{

* * * ** ** * ** * ** **** pre[100];
* * ********** * * word[100];
*** * * ** * * ***** * * * * * %s",pre,word);
*** * * ***** *** * * ** ******** * * *
**** ** * * * *** ** * ** * * ** ** **

** ********* ** *** *** i;
* * ****** ** * * ** * ****** * *
* ** * ***** *** ** **
**** * * ** ** * *** ** * ** **** *** * * * ** **** ** *** **
* * **** ****** ******* **** *** * * * * *
**** * * * ** * * ***** *** * * ** * * ** * * ** * ** * * ** *** * ** * is not a prefix of %s",pre,word);
* ***** ****** **** ** * * ***** * * * ***** ** * ** * * ** ** * ** 0;
** * *** **** ***** **** * * ** * *** * *

* * * **** ** ** ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* *** * * *** *** ** * * pre [100],a[100];
** ** * ** * * * * ** ** n ,i;
* ** ** **** ** * ** * ** * * * **
* * * **** ***** ** * **** * * * ** *
* * * *** * ** **** * * * * ** * * *
* *** *** ** * * **
***** * ** ** * *** ** * ** * *** **** * (n=0;n<strlen(pre);n++)
* ******** ***** ***** * * ** * ** * ** * * **
* ** ** * * **** ** *** * ** * * **** **** ****** * * ** **** ** * (pre[n]==a[n])
** * * ** ** * * * * ** ** *** * *** ** * * ** ***** ** ** * * ** * * *** is a prefix of %s",pre,a);
*** *** * ** ** * * *** *** **** ** ***** ** * * * * ** *** **
***** * * ** * *** ***** * *** *** ** * *** ***** *** *** * *** * ** * ** * *** * **** * * ** * is not a prefix of %s",pre,a);return 0;
** **** * ** * **** ** *
** * * *** * * * * ** *** ** ** * * * * * ** * * ** ** * ********

* *** ** ** ** ** * ****** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include **** ***
#include ** ****** ***

int main()
{
* ********* * ** ** ** * a[100];

* **** ** ** ** * b[100];

* * ** * * * ** *** * * * **** * %s", a, b);

**** * * * * * * * len_a = strlen(a);

*** * * * * ** *** i = 0;

***** ** * *** ** * * * ** flag = 1;

**** ** * **** ** ** = 0; i < len_a; i++)
* * * ** * * * **** *
* * * * ** ** * * *** * *** * * * ** * * * * * * != b[i])
* ** **** * ** *** ***** * *** * * * ** * * *
** * ***** * * * *** * ** ** ** * * * * * ****** * ** **** ** * = 0;
** *** * ******** * *** * **** * ***
* * ** * * * ** *****

** *** **** ** **** * *** * == 0)
* ******* *** * *** * *
* * * * ** * ** ** * ***** * * * ** * ** *** *** ** ** * **** * is not a prefix of %s", a, b);
* * *** * *** *
* * **** ** **** * **
* * ** * ** *** ** **
* **** * * * * ** * ** * * ** * * *** * ** is a prefix of %s", a, b);
* ** * * *** * **
* * ** *** * * ** * ** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * **** * * ** **
int main()
{
* *** *** * * * * * ** * * i,n;
** **** **** *** *** p[100],s[100],a[100]={};
** * *** ** *** * * * ** * * %s",p,s);
* * ****** ** * * * *
** **** ** * ** * * ***
* * * ** * ** * * * * * * * * * * *
* * * ** * ** *** * * **
* ** * * * * ** * ** ** * * **** ***** *** * ** * * is a prefix of %s",p,s);
******* * * * *
** *** ** ***** * **
* * * * * *** ** * * * *** ** ** ** * * * * ** * * * ** is not a prefix of %s",p,s);
*** ** * * * * * * *
** **** ** **** * * **** ** * * * * * *** * ***
* ** * ** * * *** *** ***** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* **** * * * * ** *** ***** * ** **** ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ** ** **** *** ** * * * **** ** *** * * * *
****** *** *** * ** * *** ** * * ***** * * *** *** * **** * * * != b[i])
** ** *** ** ** ** * * * **** ***** * **** * * * * ** *** ** *** * ******* **
* ** *** ** * **** * * * * *** ** ** * **** ** * ** * * ** * * ** ** ***** *** * ** * * ** * ***** is not a prefix of %s",a,b);
* ** * * *** * * ****** **** ** * *** ** * * * ***** ** * * ** ** * ****** * **** *
* * ** ** **** ** * * **** *** * * *** * ** ** * *** **** * ****** ** * ** * * ** **
* * * **** ** * *** * ** **** * * * * ** * ** ** * **** *** ******* * * == b[strlen(a)-1])
*** * **** *** **** * ** ***** **** *** *** * * * * * ** ** ** * ** * * *** * ** ** *** * * * * *
* * * * ******* * * *** * * *** ** * * ** ** * ** ** * * *** **** ** * * ** * * * * * * ******* * * ** * * ****** * is a prefix of %s",a,b);
* * * *** ***** * ** * *** ** * * *** * * * **** * * ** ** ** ** *** *** * * * ** ***** ****** **** ****
** ******* * ** * ** *** * * * ** * ** * * *** *** * * * * ** * * ** *** ******
* * ** * * * **** * * *** * ******* ** * ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ***** * **** * * ** * i;
* * * *** * * ** ** ** * (a[0]!=b[0]){
* ** * * * * ** * * * * * ** * * * ** 0;
* * * * * ***** *
* ** * ****** ** ** * * ** * * ** ** * *
** *** * ** * * **** * * * * * * * * ** ** * ** *** a[i]==b[i])
** ** ** ** * ** * * * * * **** *** * ** **
** ** *** * ** ** * ***** ** **** ** * * * ***** ** * * * * 1;
**** * **** ** ** * * ***** * ****** ** * ** *** ** * * **** ** * *
****** * * **** *** **** ** **** ** *** ***
** *** * * * * * * ** * * ****
*** ** * * ** * * ** ** *** 0;

}

int main(){
* ** * ** * * * **** c[n],d[n],e[n];
**** * * * ** *** *** *** i;
* * ** ** * * *** * * %s",c,d);

** ** * *** * ** * ** * **** *
**** * * * * *** ** *** * * * * * * ** ** * * ** * is a prefix of %s",c,d);

*** ** *** * *** ** * * *
* ** ** *** * * **** * * * * ** * * *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.71
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.9k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.9k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.6k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users