Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include **  *  *     ***   
#include  * * *  *  * * 
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int prefix(char a[], char b[]){
int i, j,n;
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}
answered by (323 points)
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** *  **  * *     *** * *** c;
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
answered by (-284 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
*      *  * *  ***** 
int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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 * ** ** * **  *** *   *
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}
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Hidden content!
#include <stdio.h>
#include  *  * **  *  ****
#include   *  *  *** * 

int main()
{
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** *********** *    *   *  * **  == 0)
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   **  ***  *   * ** * ** ***   *
 * ***   *  **** * *** *  * ** ** 0;
}
answered by (-285 points)
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Hidden content!
#include<stdio.h>
   ** ** *      *   ** 
int main()
{
* *** * * * * **  ** **   * *** * i,n;
*  *      ***   * * *  ** * *   p[100],s[100],a[100]={};
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*** *  * **** ***   **  ** * 
*   *  **  *** ***  *****    *    * ***  *  **    ** ** ***
** *  ******  * * **  ** **** ***   0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ******* *****  *   *    **      * * **    
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    for(i=0;i<strlen(a);i++)
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**     **  *  ***  *** *  **  *  *  **   * * **** *** ** *
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
  *** *** ** ** * ** * *** *  * *     * ** i;
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 * *   *** *** * ****   *    *  *     *   * * **  * *  *
 **   * ***** ****  ****  **** *  **
**** **        *     ** ** ***      0;

}

int main(){
  ***    **    * ******** ***  c[n],d[n],e[n];
 *  *  ** **  ****  *  i;
  **  *       *  **    * *** * ****  %s",c,d);

  ** *  ** ** ** ** **  **   *  *    
 *  *    * * * * *    ****  *  * ** ***    ***  *** **  ****** is a prefix of %s",c,d);

 *** **   ** *  ** * *  **     *
***  ****   *     * ***** * *    **** * * ***     *** *  ** ***   ***** is not a prefix of %s",c,d);


}
answered by (-32 points)
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