1-11 Exercise 3: Prefix of a string

0 like 0 dislike
15.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 15.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   **  *  *  * 
#include   *** ****    ** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* *** *** **** ****  * **  **
 
*    *** ** * *  ***  ***** * * **    ***   ** *   
  * *   * **         * *   *   *  *  
 ** *    *  ***** **    *    **  ******** **  * *   ***  *  == s2[i])
  * ******    *** * ******   * *  ** *  * **** *      **   
*  **  *  *  *   * * ***  **** *** ** **  *  *  ********         ***
** ** *  ** **   *** *  *      **** * *** **** *
 
***** ***  *   * *  **  *  ***   * * *
 
**** **   ***  * ***   * **** * *  ****** == length)
   ******    ** * *  * *   *  **  **  *
 *  **  **   * **** **   ** *   ****  *   ****   *** * *   **    * *    ** is a prefix of %s",s1,s2);
***   ****** ***   *     ** *  **   
 
***     *  * **   ** **** **    
   **     ******  ****** *  ****
 * **** * ******   *  **** *  * *  *       ****  * *     **  * **    *    *  is not a prefix of %s",s1,s2);
*  *     *  ** **  **  **  **   *** 
 return 0;
  **  * * *  * ***   *  **   
 }

int main(void)
{
  *  **  * ** * ***    *  *    s1[100];
    * *       **  **  * s2[100];
  * ***    * * ****   *    *  * i,j;
 *  ** *  *** ** * * **** ** **
**  *  * *  **** ** **    * * *****  ***  *   * *    s1);
*  *  ** *** * ***   * **  * *   ***  ** **  s2);
           *      **  ** **
  *** **   *      **  **   * ***  *
 ****  **** * ** *  
*  **** * * **  *  *   **** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  *  ****  * *
#include  **    *   *  ****

int prefix (char st1[],char st2[]){
   ***  **  **  *   ****  *  ** len=0, i, cnt=0;
 * **** *      **** * ** ** 
*  * * **    ** *  ***    ** = (unsigned)strlen(st1);
*** ***  *  ****    **** *
*  **  ******  ***   **** ****   (i=0;i<len;i++)
  ***  ** *  ** **  **   **  **
  *  * ** * ***** (st1[i]==st2[i]){
* ***** ********  *  * * ***** *** ** ** ******  * * ** * * *  ***  *  **   **  ***     **  **
** *    ** *** **  ***    **  *   **  ** * **** * 
  * ** *         * * **     
  **** * **** * ** * * ***  (cnt == len){
   ****   **    *  *      * * ** *   *****  ***   ****** ******  * 1;
 ********** **** **   * ****  *
* *  *  * *  *   ** ** 
   ****   *  *  *** * ****  0;
     ** * ** ****   * **    *****
}

int main(void) {
* ** **  ** **    * *    *  ** ** st1[256];
** *             * ** ***   **  st2[256];
  ** ** * * ** *   * * *  * * ***   ** * ***** *   *  *    st1);
  *  * *   *  * * ***********  ***  * *    * **   st2);

*  **   *  * ** ** *  * *** *** (prefix(st1,st2)){
 ** **  * * ***  *   *  *   *  *   * *  * * **  **   * * *   ***** is a prefix of %s", st1, st2);
 *   ** *** ** **   * * ** 
*** ****  *****   **** **      
*   *** **   * ***  *  *  *  *  **  ***   *** *  ** **  *** * * is not a prefix of %s", st1, st2);

    ** * ***  **** *****  *****  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
******* ** * *  *      ** * **  ** ****   *    *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
   ** * *  ****  ****   ** *  ***** * *** **  **
   ****** * ********** *  * ********** *  *  * ***** *   *   ****  **  ** *  **  **  
**** ***  * ******    *** *****   **  *** ** **  *      **  *** *  *** ***  *   * * * **   ** ******    
  *** **      ** ***   *  * *     * *   ** ******  **    ***     * **   ******* **  **   **                ****  *** * * **** *  *** **   is not a prefix of %s",a,b);
 * **** ***  **  **    * * ****    ** *****    ***        * ** **  ** *  ** **    *** *****  * *   * ** **    ******* *  *  *  *  
    * **  ***  **  *  * **  *   * ** **      * * *** ******* ** *    * **** * *  ** *   *  ** ***     ***
*  *** ** *   ***  * ******* **  ****** * * *  **********  ** *** ***** *    
  * *** ***** * **  **  ** *  **    ** *  *   * *   * *    * *    * **** ***  * *** *** *   *    ** 
 *** *   * * ***   ****  * ** * **    *   * * **   *    * ** * *   *      * * * **  *  ** **  **     ***   *****   * * ********  * ***   *     *  *** *  is a prefix of %s",a,b);
* * ** * * ***  * ******* *  * ****  * * * *  *  * * **  ** * *  * ***  *  *** * *  **   ** *  ** *** ***** *   *  **   *  * *   ** *   *   * ****
  * * * **  *** * *  *   *** *    * * **** *     *   *   *****  * ** ** ** *   **    **   **   ****    *
  *  *   * **   *** * **  * *   ** *  *  *  *    **** * ** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 * *  ** *****  *   ** ** *** **    ********* * *  *     
   **   ****  **  ***  * * **   **  *  **  *  **

 * ******   *      ** ***  * **   * **   **** ** **  * *    ** *  * ** **  *  * **   0)
 *    * *  ****  *** *  * * * * * **    *    ** **   **** *** ** *****  * **   *
  *      * *   *  * *       ** * **** **     *  *** * ** *   *   * **  *** ** *  * *** ***  *  ***  ** *    * *   is a prefix of %s",pre,str);
  * * ******* ***  ***       **     * *** * **   *** * *  *******  *   
*   ** ***  * **  **  *  **    ** **    *   * ***** **
  ***   * *** ****     ** ***   ** *** ***  *       *****  *   ** ** ** **  * ***   
***  **   *  * ** ****** * ***  ****  * *** *  **   *  ** **** **   **  ** *  * * ******  *   **  *   * ** ***** ** * *  is not a prefix of %s",pre,str);
* *  *** ****  *****   *  *  *  * * *    **  ****  **  *  ** * ****** * * *  * * ***  * 

***  * * * *    *  * **  ***  *  *  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 *  ******  * * **   * *******  a[100];

     ** **  ****       *  ** b[100];

 *   ** ***   *  ** *****     i = 0;

*  * *  * **** *  *****   prefix = 1;

**   *     ****  *** ** *****     **     **  *   a, b);

*  ** * ** **   *      * * **    len = strlen(a);

*  *   ** *  ***  ** **** *  = 0; i < len; i++)
***  *  * *  **   ********  
  ***     **** **  ******  ***** * *     *** *** *   *  *   != b[i])
 ****      **  *  *  ***** ******** *** **  *****      
 ** ***  **  ***** ******   **    * *** ****  *** * *** *  ***    *   *  ******   = 0;

* ** ** ** ********   **  **     *  ** ******   ***** *  *      **  * **   *   **   **  *  *  is not a prefix of %s", a, b);

    ** ** *  *****   *** ****  *  * **  **** *     **   *  ***** ** *  * * **  **  * 
**   **  ** *   *     ** * *  * **** *  *    * **  
*  * * *** * *******  * 
*** *    *********  * * * * ****  * == 1)
* *    ** ****** *** * *******
*  * *** * * ** ** * ** *** ** ****  **** *** * ** * **** ** * ****  *** is a prefix of %s", a, b);

* *  ** ***  * *  *  *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include          * ***  
#include *     ** *** *  

int main() 
{ 
*    *** *   ** *** *******  *   a[100],b[100]; 
* *  ****  *  **** ** *******  i,j,prefix = 1; 
  ****  *  ***  * *    * **   * * * *  *****  %s",a,b); 
   *** ******* * * * * ****   len = strlen(a); 
 ***        * *  *   *    = 0 ; i < len ; i++) 
 ** *      *** * *  ***  * * *  
*****    *       * ** *    * * ** *** ***  *****   *  * != b[i]) 
  ******     ** ******     * **  * *     *  ***     *** 
   *    ***  ***      *   * *   **    *  ** *  ** * **  ** *  **** ***     *  * *    = 0; 
   *   **  *        *  ** *** * **   ***          * ***  **  *** **  ***  * ** *  *   is not a prefix of %s",a,b); 
* ** * **     * **** ** *** * ***  ******* ***   * * * ****     ** **** *      **  *  * 
   **** ***** * *    * * ***** **   *     ***      **  

 *   *   ** * * * ****** *  
*  * *  **     ** ****** ** **** == 1) 
* **** ****   *  * *  *            *  ** **** **** *  * * *  *  *   * * ** is a prefix of %s",a,b); 

 
**** * * **   **   *** ***  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *******  **  
#include * **  **** *  *

int main()
{
*    *  ******    * *  ***   **  a[100],b[100];
**  ** * *****  ** * **** * *** *  i,j,prefix = 1;
*** *   **  * * *   *  *   *** *  ****** *** %s",a,b);
***  * * * ***   ** **  * *** *   len = strlen(a);
 **  * *  ** ** * ***** ***  *  = 0 ; i < len ; i++)
*      * **  **  * * **
      * ** * * **  **   *    *   ** *******  ** ****     * != b[i])
***** * * * * **  **      *  ***** ******   **** ** **  *   * *
 * * ****    * ** *    ****** ****     * * * ** * *   *      * * **   *   *  = 0;
  * *   * *  **  *  **  **   * *  ** ***  * *   *   * * *   **** * **   *     ******** * * ** *    is not a prefix of %s",a,b);
  ** *** ** *   * ***   **    *  ***** *   * **  * *** * *     *   *** *****
  * ****   *   *  *  *   * *********  **  ***** * ** * *

    **    * **   *   ***   
  ***  * *     *****  *  * == 1)
 * **   *  **  **  *  *** ** ******  ** * * *  ** * **   * ****   is a prefix of %s",a,b);


**   * ***** * **   * * *    *    0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *** **   *
#include *   *  ***  **

int prefix(const char *pre, const char *str)
{

 ** **  * *    *****  *  ***  * ** *  *  *  *  *  ** *  **
 * *   * ** * *  *  ****  ***  **  * * **    *  *  *  0;
*  * *  *** ********* ****  *  *****  * *   ** * **   * 
*   **      *  * * *      **     * **   * **  ***  ***  * * **   * 1;
**  *  *  ***     *      return 0;


}

int main()
{
***       * *** **  *   *  **** pre[100],str[100];
* *** * *** *******  * 
   ** ****  ***    ** *  ** ***** ** ** *  
  * **   * ***   **** ****   ** * * **  **
*  *  ** *****  *  ** **     ***  **  *   * ******     ** * ****  *  is a prefix of %s",pre,str);
**** **  * ******         *
  * *** **** * ***     * * *   ** *    *   * *    **   *  *   **** is not a prefix of %s",pre,str);
** *** *  *  *   *  * *   *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*   **    **   *  *  *  * **  c;
 *** *     *** **  *   *  * * *   ****   *  
 ** ** *** ******* * *   ***    ****  *** * *   **** 0;
      **   ***  *  * * ****
* * ** *   *  **** * ** ****  *   
 * ****** ** ** * * **  **** *  *  * *       *****     * ***   * **  ***    * * of a string
 **   ** ***  *  * *** ******* * * * ** *** *   * * *    ****  *  ***   * * **  * * * *** *
* **** *  ****  ** ****** *** *  ** **   **  * *    *   *** ** * *** * ******  *  ** **** * *  *  *   ** *    **  *  0;
*  **   ****  * *   *** * *   **  ***** * * ** *      
********  ***       * * ** ** *** * * * *    *****    **  * 1;
    }
}

int main(){
   * **    * * ****  **  *** * * *** a[100],b[100];
 *  **  ** * * **  *    *  * *  *  *   %s",a,b);
* *  *  ***       * * *  * * * **  * * 
*** **  ****   ** * ** *** * **    *** *        * *     *   ***  ** is a prefix of %s",a,b);
* *    * **  ** ** *** *  **
******* ***   * ** * ** ****  * ** ** *** ** **  *   * * *  * * ** *  is not a prefix of %s",a,b);
****      **** *  * *** *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*   *  *        ** ***  * * **  * * p[100],s[100],a[100]={};
   *   **  ******      ** * t;
***  ** **  *  * * * **  * *   *****    *****
    *** ** *      **   ***  *** ** *  * ** ***
* ******* *  * ** *  * * * *  ***   * %s",p,s);
  ****   *  ***   **   ** **     *  **   *
 *****     **** *  *      ***  * * *   
   * *   **  *  *    ** **   * ** * * *
 * ***  * **  **    *   ****    *  *  * *  ** *
* *  * *    * * *   ***** ******* ***  *****
    *    * ** ***   **  ***  * *** ** * *     ***  *   *  *  is a prefix of %s",p,s);
**  *  *     *   *  *   *   * * 
*     ***** *  * * *  *  ** **    **
 ******** ** * *** ***  ** *   * *  *  ***  **** * * ****      *   **   is not a prefix of %s",p,s);
* ** **    ***  *** ** *
**    *  *  *  ***   **     * ***  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 21.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 14.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 19.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users