1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   * *****   *
#include * ** ** ***  * * 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
 *    **** ** ** ***   *     
 
 **** *    ** ** *    * ***  ***  ** **    *       ** ** * * *
 *     * *   * ****  *  *  ** ***   *
     *  * * *** * * ** *  **** **  *  * *  ***    *** *  == s2[i])
  ****  * *    *  ***   ** *  ******* * * ***  *** 
   * *  * * **  *  *      * *  * *  *  ** * **  * *** * * *     ** ***     *  * *  *** **
 *    *  ***  *** **  **  * * *  *   ****  *  *** *   
 
***** ***  ***  ** *  * * *   
 
 ******  **    ** **  **  ****  *** * * ** == length)
  * *** **    ******  * *    **** * ***
  **   *   * *     *      *   * *  * ****  * *  * *  *  *  ***     * *  is a prefix of %s",s1,s2);
  *    *  *** * *  * *   * ** **
 
****  **       *    **  ****  * * 
***   * ********** **   ****  **** * 
 * * *    * *** * * ****     ***   *********** * ****    ***  **   *  is not a prefix of %s",s1,s2);
**  *  * **  *     ***  * * * * **
 return 0;
***   ** **  *  ** *      **** *
 }

int main(void)
{
 *  * *  **  *** ******** *  s1[100];
*  * *  ****   *  *  **** ** s2[100];
*  **    *      **** *    * i,j;
 *  *** *  ** *****  ** ** 
**  * ** **  * * * *** ** ***  *   *** *   ** s1);
    ** *** * ***   *   ** * * ** **  ** s2);
   * **   ***** *  ** * *** **
** **  **   *  ** * *****  *** * *  
*** ***   ** ****    * **  
 *  **    ** ***  ****** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  *  ** * *****
#include *  * *  * *  

int prefix (char st1[],char st2[]){
 * * *  *  *** **  *****  *      *  len=0, i, cnt=0;
  **     **   ***   * * *
*  * ***   ** *  *   **   **   = (unsigned)strlen(st1);
** * * * * **  * * *****     * 
    * * **  **** *****  * * *   ** (i=0;i<len;i++)
*  **  * * *  **  * * * *   **  
 *    *****   *  (st1[i]==st2[i]){
 **  **  *  ** *  ********* ** ***  * *       **   ** **  **   ****    *  *****   ***   *  
* * ** * *  *      ***  **    ***  *****  **** *   
 *  ******    ** **   
 *  ** ***  *    ***  ****** (cnt == len){
    **** ***   * ** * ** ** **     ** ** *     ***   *** *  1;
* * ***  ** * **   * ** * ** *
* * *    *  *  *   **  * **  *
 ** * ***  * ** *** *  *****  0;
**** **  **** **  *   ***
}

int main(void) {
   ** ***** * *    * **   **** ** st1[256];
*    *  * *  ** *  *** ***** st2[256];
    ***   *    ** * ***  *  ** *  * * **  * *** * *   st1);
    ****** ****  * *     ********** *   * st2);

 * *  ****   **** **  **  *  (prefix(st1,st2)){
****  * **** ** **  *******    ** * *  *****   **** *** **** * ** is a prefix of %s", st1, st2);
*  *  * **   *** *** *   **   
   *******    *** **   *  
   *** ****    ***    **  **   *   **  ****  ** *    **  *  ** *   is not a prefix of %s", st1, st2);

 ******** *  *  * ** ** * *  **    0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
    * **    ******   ***** * ****  *  *    *  *** *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
     * *** * ** *  * *** *  * ***   * ****  ** *   * **   *
  * * ** *** **   *  * **  *    * * ** ****   * * ****     * * ****  * ** *** * *     * ** 
      * ***     *  * * *   **   ** *        *** **** *  * * ** ****** *  *** *  **      *   ***   **** ***** 
* ******  *** * *  * * **  ********* ****  *  * ***     *  **   ***     *  **     **  ***    ***        *  **  ***   *  ** *   * ** ****  *  ** *     ** is not a prefix of %s",a,b);
    **** ***  ****  ***  **  ****  *  ** * *** *   ** **** ** *   **  *****   ** **  *  **  ***** * * * *   *   *      * *     * * *      * *
   ** ***   * * *    **  ****** *** * * *     *  * *** *******  **    *   **  *  **  * **  *   * ****   ** ***
  *** *    * ** * **     * * *** * **   **  * ***   * * *  *     **  * **   ***   **  * ***
 *  *  ** * ** *****  * ****  *  **** * ***   *  ** ***  ** *** *     **  ***  *   *  *** ** ** ***
* *  ** **   *   * **           *  * * *   *  * **  ****    **  * * **       *    * *      * * * *    *** *    **  *****  *   ***    *    is a prefix of %s",a,b);
***   *   *  * **  **    ** ** ***  ** ************     * * *  ** * *** **    *     *  **** ***  *****  * **   ******  **** *  *  * *   *
*      * * *****  *  * * * * **   * ****         *** * * ** ***  *****  *  ** * **    * *   * **** **  ** * * 
*  *   *   ***  *   ***  * ***     *** *  ** ** ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
**   **    **  ** **      * *       *  
** ** * * *     *          ****   **** **    

*  *    **  *    * *    **   *   ***** *  *     *  *** *  *    *  **** * **  ** 0)
*** * * *** **   *****   * ** * * * *  ***  * *** *  **   * * ***    * * *** * *  
 ***** **** ***********  *  ** *  *        ****  *  ** * ***** ** * *   * *  *** **** ** *****      *  * is a prefix of %s",pre,str);
   ******      *  ***** *  * * *  *** *  * *  * ** **    * *  *** *   *  *** *   **
***   **  ** * * * * *  * * *    **  ** * * ****** *     
*  *    *** * ****  * *** **   * *    * ***  *    *  **** **  *  ** *  * *****   * 
****  *       ** *** *      * **  ***  *    * ***   **  *** *  * *   *** ****** *    * ** * *    **       **  *** ******  *  *   is not a prefix of %s",pre,str);
* ***   * *   ** ***** **  *****  ***   ***** *  * **** * ** * *** ** 

* *  *    **   * *** **   * **** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* * *   **      ** *    a[100];

* * *******    **   ** * *  *  b[100];

 **** ** ** * * *  *  **   * **  i = 0;

 *** **  *  *   * ***** *** **     prefix = 1;

  *  * **  * ** **  *  * ** *  **  ***  *** * * a, b);

 *** ***   *   ** **    ******* len = strlen(a);

*   * ***  *   *  *   ** *  *     = 0; i < len; i++)
*****  * * ** *   ** ** *
**  *  ** ***** *        ** *     *  *******  *   *     != b[i])
  **** **   * ** *****    ***  ****   ***  * *** ** *
***   *     ** ** **   * *  *  * ** *  *******  ***** *  * ***      ****  * **    = 0;

       *   *  *  *  ** ******* *  *     *  ******** ****    *   *  *  * ** *** *   ** *  * *   is not a prefix of %s", a, b);

* * *** * *****   * *  **  *  ****   * ********** *********** ******   ** ********
 ****  **   *  *** *****  **** *  *  *  * * *  
 **      *  *****  **  *   * **
   * ** *** *   * **  *  *   *   * == 1)
 * *  ** ** **   *  ** *  ** ***
*      * *  *** *  * * *     * * *  **   * ***   * **  **  *   ***** **   * is a prefix of %s", a, b);

* * *****  ****  ****** ** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** *  * * * * 
#include   * **** ** ***   

int main() 
{ 
 **      ***   * *  ****  *     * a[100],b[100]; 
  **** *** *****   ***** i,j,prefix = 1; 
 *       ***  ** *   *****  * ***  ***   %s",a,b); 
* * **** **       * **** * * * len = strlen(a); 
*    ***    *      ** *   ** * * = 0 ; i < len ; i++) 
**  *   ** *   ***    *     
** ** *  * *** *     ***   *****    * ***   **** * *  * != b[i]) 
 *   * ****  * * *  **** ** *   * * **  ***     *  **  *  
***   **    ***    **** **       **** *  * * **  * ****   *** **** *  ** ***  * *     ** = 0; 
*     ****  * *   **   ** *  **** * ***    **********    *  **  ***  ***** ***  **  * * *   ** is not a prefix of %s",a,b); 
 ***  * *** *      **** ** **       * ** * ***  *   **** ****** * ***** * **   ** * *      
**    * **  ***   **** ***   *     * *     ****** * 

 *** * *  *   *  *  *   ** 
 **** *    ***** * * *  *  *    ***   == 1) 
   *** ***  **  *           ** ****   * *   ******  * **** *  ** ** is a prefix of %s",a,b); 

 
 *** * ** * * * ****  * ***   **   * * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *     *** * *
#include  * **** * **  * * 

int main()
{
***** * ***   * *       *     a[100],b[100];
* *** * * *  * *****   * i,j,prefix = 1;
 * * **   ***  *  *** **     *****       %s",a,b);
** * *  **  *             ** len = strlen(a);
    * *        ***     ***  *  = 0 ; i < len ; i++)
 * ** * * * *** * **   ** 
** ** * **** *  *   *    *   *   ***  * ***  ***** **   *  ** != b[i])
*****   * **    * **   ***** *   * *  ****  ** ****   * 
  **  *  *    **   * ***   **  ** *    *  * *** * * * ** **** ** ***  ** * ***   = 0;
*  **  *   *  *** * ** *    * * * ***  ***  ***** * *  *  **     *  ** *    **   ** ** ***   ** is not a prefix of %s",a,b);
  * ** *** **  ** *  * ** *  *   *   **  ** ***  *** **** * **     **   ** ****  ***  *  
* * **     ** * *  * ** ****** *   **     * ** *  * **  

  ***** * *  ****  *
    **** * *** *  ** * **    ***     == 1)
 ** * *  *  **** *  * *  *     *****    *     *     *  **  * ***     is a prefix of %s",a,b);


     * *** **   *** * ***** ** ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * * ** ***  **
#include   * *   ** **  **

int prefix(const char *pre, const char *str)
{

* **** * * ** ****   **   *  ****** * *    
***   ** *  ***  * **   **  ** **  ***** * *    *  * 0;
     *  * * * * *** *** *  ** *** *  ****    ** **    * *
 *      *    *     **    * **     ** *  ** * ** **     * *   * 1;
*   **   *  **  * * * *  * ***   *  return 0;


}

int main()
{
*  *  ****  *    **  *   * **  pre[100],str[100];
  *   * **   * *  ****
***  ****** * ** * ********* *    **  *   * * 
**  *******      ***  * * * * * ** **** *   *
****** ***** * * **  * ***  * **  *** *   *    **  * **** * ** *     is a prefix of %s",pre,str);
* *      *  ** *  * * ***** *** ****
**  ** * *  ** ** ***  **      ** *   *      *** *    ***    ** *  is not a prefix of %s",pre,str);
 *** ***  *** *  *    ***   *  * *  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *  * *  *    * * *  * **  c;
 * ** ****   * * ** * *** *   * **  * *     
  *   *  *** *  *** ***  *** *  *   ** *    *  * *** ** * *** * * 0;
* ** **    **    * *  **    * 
  *****  ***** ** * ****  * * * ****
*        ** *  * * **   *  ***    * * ** **** ***  * * * ***    *  ** * * **  of a string
 *** * **   ** **** * ** *   * **  *** * *** *   * *** * ****  ** **   *  **   *    
 **** *  * *** ****** ***  * *  ** * * * * * *   *  **  *** ** ** ** **   *  *** * * **  ** * **  * * *       ***   *  * 0;
   ***  * **  * *    *     *****   * ** * *    *** *    *
*  **** * **  *   *** * **** ** ****  ** ** *  **  **   ** *** 1;
    }
}

int main(){
  **    * **      **   ***   ** a[100],b[100];
* * ***   **  *   ***  * ******   *  %s",a,b);
* * ** *** * *** ***** *****   *** * * *
   * *  *  *   * *****    * * ** *   **      ** * * ****  *  **   *  is a prefix of %s",a,b);
 *  ** ** **  *  * ** **    ** * 
**    ***   *** * *      * * *** *  ** ******   *** * ** * * * is not a prefix of %s",a,b);
* ****    ***  *     * *      ***** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  * ** *** *** *   ** **** ** *  p[100],s[100],a[100]={};
  * *   *  * *  *******   ** ** t;
*  **  *  *** *   ****   *   ****  ******* 
   * *  * **** *       *** * * *   
 * **   *** * ** ** *       *  *** ** %s",p,s);
  **  *    ** ****   * *   *     *
 *  *** **  *    * * **  *  ** ** * *  
 *****  *   ***  * * **** ** * *  **
   ** * *  * ** **     * ****  *  * ****  **
    * ** **** *  ***   **** *    ******
**** * **** *****    ** ** *    ** ***         *   *   ** *  is a prefix of %s",p,s);
* ***  *  *  **  * **** * 
  ***   *   * **     *  ** *   *
      **** *    *****   ** *     *    * *    * **   *   ***   *  is not a prefix of %s",p,s);
 *** ***  **       *  * *
**    *   **  **   *  * *  * *    0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users