1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include    * *  * **  *  
#include * * *  *** * ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
**  * ***  *  * ** *** * *
 
 ****     ******* * *** ****   ***  *  *** ** 
   ***  **** **     *  * *** * *      
*** *   ***   * *  **** **   **** *   ***   **** **** *     * ***   == s2[i])
*   *** * * * * * ***** *** **  * * * ***   **** ***
****    * * *******  *   *   ******   *    * *  *  *** *** * * ********   * **  ***
 **   * ******  *  *  *   ** *   ****  ***  *  *   ** * 
 
*  * *** **  ** **  * * *  ** * * 
 
 * ** *  * *   * ** ** * **   * *****   ** == length)
* * *    *** *       ***  **   * * *
 **  ****  **  * *   * **  ** ****** *** * *     **** ** **  *    * *     is a prefix of %s",s1,s2);
  ** * *   ** **  *  *****  *  ***** 
 
  ********        * ** **   *  *   **  
*  *  * ** * *** * * *** **  ** *   
*** *  ** **** * *  * **** * *  ** *  * ***  **  ** *   ** *  *   * *  **  *  *** is not a prefix of %s",s1,s2);
*****     *  ** ** ******  **  **
 return 0;
*   ** *      * **  * ** *   *****
 }

int main(void)
{
***** *    * *   * ****   ** s1[100];
 * **     *    * ** ***   * **  ** s2[100];
   ***** **** ** ***** *      i,j;
 * *  *** ** *  *  ** *  
****  ** ***   *  ***  *  ** **** ** ***** *        s1);
   ** ******    *****  * * *** *** *  *** *  s2);
**   * *  * **  ***  ** *
**** * ***   *  ** ** *****  ***     
 * *  * ***   *   * * *****
        *    * *****   *** *      0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** * *  *
#include ****   **  *  **

int prefix (char st1[],char st2[]){
    ** **** * **    ****   len=0, i, cnt=0;
 * *      **   *     * ***    **
 ** ** **  * * *  *  *  = (unsigned)strlen(st1);
 **   * ***  * *  * * ** **  ***
 ***** * * ** *  *  *  ** *  (i=0;i<len;i++)
   * * *   * **  ***  * *  * *
   ** *  ***    (st1[i]==st2[i]){
* *   * ***** *** *  *** * *    * * **  ***  **   * * **       * * * *  *   *  * 
 *  **  ***  *      ** *  * *** ***   * ****    *  
*      ***   ** *  * * ****
**     *** **     ** *  * (cnt == len){
    ** * *** ****  *  *** **  **  * ** *    **  * * ***  ** *  *** * 1;
  * **     *  *   *** 
   *    **   * ** * ** * * *  *
  ** *** *    * * * **      ** 0;
 * ***  *  ******* **   * ** *
}

int main(void) {
*   ***      ***   * ****    st1[256];
* *  *       ** **   *  *  *  * st2[256];
*   **  ** **  ** **    *** **   **  *  *  * *     st1);
  **  **  ****      ** **  *  *** ********  st2);

 *     * * ***    **  *   (prefix(st1,st2)){
* *   ** ***  * ****    ***    ** *  * *  **** **  **     ***  * is a prefix of %s", st1, st2);
 ****** ****    *** ***   
  *  *  * *   *    ****  
* *    **** ** *** *    *** ** ***      *    * **  ** ** * ***** * is not a prefix of %s", st1, st2);

** ****  ***   * ***** *   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  * ***   ******     ** *   *    *  **        *  * 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*  *** **  * *** *****    *     ** * * *   *  ** ** 
 ** * *  **** ***     ***     ***** **     *** ****** *** ***  * **  ** ** *    ** * ** *
***  ** **  ***  * *****  *  ** *  ***      ***        **  *   ** **  ** **   ***  * *   *** *   ****
 *  ***** *  *  *       *  *** **    * *     *** * * **  ** * * * *  ** * *   * ****  *   ** * *  *  ***  ** * ** ** *   *** *  ** *    **** * * * *  is not a prefix of %s",a,b);
  * *   *****  **  * **  ** ** *    * * ** *** * *   *   ** ***** **     * *     * **   ** * ** ***   *****  ****  ***    *    ** * *  *  * **
    *    **     **  *** *   ****    ** * * ** **      ****  **     ** *** *  * *  *  *     *  ********  ** * *   
*  ** *  * **  *  **    * *   *** **  ** *   * * **** ** ***         * **  *   * *  *
*    ** *  **  * * * ***  * ** **     ******  * * ** **** * ***  * **    **** ***** *****   *  * * 
**  * * *  ****** * **          *****   *     **** * * ****** *   *  ***    ************ * ****  *   * ***    * ** * * *      * * * **   ** *  * is a prefix of %s",a,b);
***  * *** ****    * *   ** ****  *  **  * * **  ** *  ***     * *  ** *  **    * *  *    *  * *     *   ****** * ***  *     ** ***
    ** ** **  ** ** ****   **** *  * * ****   ** * **   *   * ****    * *** **** *   ** ** *  *   *********    **
 ** **** * * *****    ***  **** ***  **** *   *** *** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
***  * ***    * ***  **  **  ** ***     *   * *   
     ** *  *  **    ********  *           *  * *    

* * **  ***     * * *     **   * *  * *    *   **** ** *  *    *** **** 0)
* **  *** * *  *    *   *   * * * *    ***** *   * *  * * *    *** * *****
*** *****     * *** ** * *  * * *** * **  ** **  **  *** *     ** * *     *** * ** * * * ** ****  * ** **  ** *  * is a prefix of %s",pre,str);
* ** **   * *** * ***  * ***  * *  *  ** *       * **  * * ***  *   ****
  ** * ***** *   **** ****  *  *    **    **  ** *** *****  **
*   ***  * ***  **  **    * *** * **    *   * *  **  *       ***   ** *  *** ***** 
  ** ******     *  *    * ****   *      * *  **     ****    * ** ** * ** *   *  **    ** *       ***  **  * **  * * * ** *  *   is not a prefix of %s",pre,str);
*  *   **  *   ***  **   * ** * **  **  ** *** *   ***   *  *** ** *  *  *    *  

  *   ** ***  ***  **  *  *  ***  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*  *  ** * ***  **** ** **** a[100];

***  *** *  **     *  *   ** b[100];

 * *      ***     ** **   ** * i = 0;

*   * ****  * ** * *    **** *  prefix = 1;

***     * *** *****   * *        *    *   **  *    ** a, b);

*** *   *  *    **   ** * ** len = strlen(a);

*  *    *** *** *** ** **   *  = 0; i < len; i++)
 *  * **  *  **    *    * **
*  **** ** ***  * * **  ** * *   **  **    * *** **    ***   ** != b[i])
   *  **   * *** * *   *  **    * ****  *    * ** ** 
*    *    ****    *  ** *   * *    *  **  **  ** *  **  **  *  *   ** **** = 0;

*** ** ***   ***  *  **  *  *  **   ** **  * ****** **  **  * ******* * * *   *   ** ***  ** * ** * is not a prefix of %s", a, b);

  *** ***** * **   *  * ****  ******   *      *** *    *  ***   ** *  * ****  **
**** **** *  ***  ** *   ****    ** ** ** **    *  **     
*  * * *    *  *** *** * *** *
*** * *   *  *** **  *** *    *     ** == 1)
** * *** **     ** *  * ****
** * *      ** *** *  ***     * ***  *****  *  * ** * ** **  is a prefix of %s", a, b);

*     *   ** ** ***  **** ** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *    ***  *  
#include *  **      * *** 

int main() 
{ 
   **  *  * *   *  * **** *      a[100],b[100]; 
** ** ** ** *  * * ** *** **   i,j,prefix = 1; 
*  ***   ** * *** **    * ***    *** **   %s",a,b); 
 ** * ***  **** * *** ***  **  len = strlen(a); 
**  ***   * ** ** ***** * *    = 0 ; i < len ; i++) 
 ** ***** ** *  *   ****** 
 * *  ********    ****  ** **  * **   * * ** *   **  *** != b[i]) 
    ***   *  ***    **  *   **  *** ** ** **   **** ** *  
  *  **** * * **** *  * **       *  *  ** * *       * *    *****    ***    *  **   ** = 0; 
**       * ****    *    **   * ** * *****    *  ***   *  * **  *  **  ** ** *  ** *** ** ***    * *  is not a prefix of %s",a,b); 
  * **   * *** **  ** *    ** *  * * *   * * * * *   *    * **  ** * **   ******  * * *   *  
*  * ** * *** * **      ***  **** ***   **  ****    * * ** ** 

 ***** * ** *  *  **    **   
 *   ***  *** *     * * * **   ** * == 1) 
*  *     *  * ***  **  **   * *** ***     **    ** **  * ** *  is a prefix of %s",a,b); 

 
      * ** ***     * * * * ** * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** * *    *   
#include  * * **  ***  

int main()
{
**   **    * *** *  * *   *** a[100],b[100];
 *   * ** ** ** ****   ** i,j,prefix = 1;
 **  * *   *   * ****   * ****   * %s",a,b);
** * *  * *** * **** * ** ** len = strlen(a);
* **  * *       ****   **** *** = 0 ; i < len ; i++)
    ***** * *  *  *   ** *
 * **  *    ***  *  *   ** ******  **   ** * * *  * **   != b[i])
****  * *** ****  *   *    * ***  ** *** *  *** **  
  *   *   **     ** **  ** * *  *** *  **   * ****   ********* *    *  *  *  *     = 0;
 * *   **   * ***   *      **** **    *****   **     *** *****  * *   ** * ******      * **   is not a prefix of %s",a,b);
 * * *   ** **** **    ** * *   * **  * ** **    *** * * **  * ***   *  *** **  * * **  
** **      * ***  **** *   * *** ***** *   *** * ** 

  ** **   **  **  * ***   **** 
 * ***** ** * * *  * * * * ** * * *** == 1)
 * *     *   ** *  ***  ** *************** **** * *   *  * *  *  * * *  * * * is a prefix of %s",a,b);


 * *      *    **   ** * ******  *   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ***** **   *
#include  * * *  *   ** * 

int prefix(const char *pre, const char *str)
{

**    **  ***** * ** *    *** * **  * **  **  *  
** **    **   * *  * ***  * *  ***** * **** **  **** *   0;
   * ** **** **   ***** * *  * * **  * *   ** *  *   **  
****  **  **  **** *  ****** *   * **   **** ****  *   ******** 1;
   * * **   ** *********    *  *  * return 0;


}

int main()
{
*       *  * *        * * *  pre[100],str[100];
   *   ******    *    *  **
*   ***  ** ***   **  *    ***   * * * *  * **  
* *  * * *    *    * **   ** * * ****  
  *  * ****  **** *   *  *       **** **  ***   **  ***  * ** **  *  is a prefix of %s",pre,str);
   * ***** ** ***** * **  ****    
  *   *  *** **  **  ****** ** * **  ** *    ** ***   * **** ** * * is not a prefix of %s",pre,str);
***** ** * * **  ** **     *  * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
   ***  **  *** * * *****  * c;
 *** **   **    ******  * *** ** *  ** *    ***
   ****  ** *  ****  **   *  ** ***   * * ***** ** * 0;
**   *    **  ***  * * *******
  ***    ** *    *  * *** ****
*   *     ***   * **  *     *      ** **** **   ** *****   * ***  * * ***  * * *  of a string
* ** ** *** * *   *    ** ** *** ** **   * * **          * *   * *** * * **  * * *** 
 *  * ***    **   * **** *  ** ****  **    * *   *** *  **  * ** *** ****** ****  *  ** ***  *   *   * ** ** * * 0;
   **** * **  *  *  ** ** ** ****  * *  *** ** *  *  
 *  * *  ** **   *****    * **** *** *  ** *   1;
    }
}

int main(){
   * * * **   *  * *     *  a[100],b[100];
 *** **   * *  * * * * ****  *  * * %s",a,b);
*  *  *     * ** * *  **    * * **   
*   *****   *** ** *  ** *     *   **   * *** **       *   *    **** ** * is a prefix of %s",a,b);
* *  * ** **** * *  *  ** **  
      *  *  *    * * * **  **    * *****   **** *  * *  *  *   *  * is not a prefix of %s",a,b);
  * ***** *  ******* *  *   * *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ***  ***   *  *** *   *   *  p[100],s[100],a[100]={};
**** *   *    *   ** * ** * t;
*   *    * * * **  ** * * **  *      **   * * 
 ******** * **** *  * **  ******  ******  ** 
  ** ** *  * ***  **     **  **  *** ** %s",p,s);
 *    ****  *  *  *** ** ********
*** *    *** ***       **   ***     
***  *    **    **  * * ** **** ****  *
* **  ***    *  *     **** * *   **** *** *
 * *    ****** *  ** ******  *  * * 
*   *    * **  *    *     * * *** **   **  ****    ***   * ****   is a prefix of %s",p,s);
**  *** * *        * ***   ***** 
 ****      **  **    * *       *  
**  **  *      **   *  * *  * ** *   **   *** * *  **  *  * is not a prefix of %s",p,s);
 ***      ***   ***** **
****  ** *   **      * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 20.9k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 18.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users