1-11 Exercise 3: Prefix of a string

0 like 0 dislike
4.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 4.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*   *****  * * * * *  **  * ***
 * * ***  *  ** * *   *  ******  ** * **     *  ***   *  *  
    {
*   **  *   ***  *   ** ** ***     *  ***    **  * (i=0; i<=strlen(string2)-1;i++)
 *** **** *******  **       *  **    * *** ********* *******
 ** * ** **** *   ****   ***  * ** *  ******* * *  * **      ***         * * (string2[i]==string1[i])
*****   *  * **  *  *   *  ** * **   *  ***  ** * *  * ** *    *  ******     ** * ** **
   *** *  *       **** **   *  *   * *    * *   *  *** **       *    **** *     **  * *  ****   *** ****    * ** 
  ***     * *** *   **  ** ***  *** * *   ***   *  **   *** ** *    * ** ** *
**   *****    **  *** *   * *   **   **      * **  * *
* *    *   *   *       *** *** * ** *  * ** *    ***  *    *  
 ** *  * ***   ***     *********    ***   **  * 
** *    *   *       *** *   **    ** *** **  ****  *  *      **   *  * *  * **    ** ***   **  is a prefix of %s", string2, string1);
 *********     ****     ****  *      **** * ****  *
*    ***   ***  ***** * ****** * * * * ***   ** * *** *   
   * * * ****   ** *  * * * *** *  *    ***   ***  
 ** **  * *    * * ** * *  *** *   *   ***** * * *  *  *    * *** ** ***  **     * * is not a prefix of %s", string2, string1);
****   ** ****    ***   *   **   ****   *   * ******  
    }
  ***  *   *  * ***  ** **  * ****     *   * * *   ** ** *  
    {
 **   ****  *  *    ** ** ** *   *   * * * *    * * * ** (i=0; i<=strlen(string1)-1;i++)
 * *** *  * *** * * * * ******* *  *    *** ***  **  **
  *  * * * *  **** *         *    *  * ** ****  *  ***  *    ****** * * *  * **  ** (string2[i]==string1[i])
** ***        * ** * *   *            ***     * ** ***    ** *** * ***  ** **** *** 
****  ** * *  *    **   ** ***  *** *  *  **  **  * ***  ** *   *  *    * ***   * *    ***  *  *    * *   * ** * 
**  * *** ** * ** ***  * *    *   ** *    ** ** *       ***    *  ** **** ** * ** * 
  *  *  *   ** ***      **** *    * * * **   **** *** * *  
***  ** **  * * **  *      **  * * *  * ** **  *** ***  *
*  *    ***  ** *  * ** * ***  ****** * * * *** *****   
  *  **** *   * ****    ** *  *     * *  **   ***  * ** * *  * * ******  *    ** * * *** **   **** * is a prefix of %s", string1, string2);
  *  ***** * **     **    *   *  * *  **  ***  *   **  
** ***** *  * *      *  *   * * * **  **   **** * * * 
  * *  ***  ***  *    * ** ** ***  *****  * **   ***** * **
****    *     *  *** * *  ***  *  **  * *   * * ***      * *        *    *  ******* **   * *  ** is not a prefix of %s", string1, string2);
* * *** *** *  **** * * * *** **  * ** **   * *  **  *   
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
*  * * *  **** * *** *** ** ** ***  *  %s", chaine1,chaine2);
* * ** * ** **   ** * *  *           * * ** *
    * *    **         * **  * * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   **** ***   * ****  ****   lenght1,lenght2,c;
**  * *   *  *  *** *** ***  * b[100];
** ****  *      *    *     **  a[100];
     **   * ** ***  ****  ** d[100];
    ** **** ** **  **   *** *    * * * *  * ***
   *      * *  ******  *   ** * ** ** ** ** *
  * * * *   ** * *    * **  *   *  ** 
* **** * * * *** ***     * ********   *
***         *    ***   ******   ** *    * 
  *** **  ** *   **   *  * ** * 
 * ******  * *  **   ** * *  ***  *   *    ***  * *    * is a prefix of %s",a,b);
** **** *   *   *  ****** **   
***** *   *   * *** *     * * **
 *   *   *    *   * * **  *  
 * *** ***    * * *   * ** ** * *** *  ***   ** *** **** ** ***  ***  is not a prefix of %s",a,b);
 *   *  ** **     **** *  *
 **** ** ****   * ****   *   *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** * *  * *   *
#include    **  **** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*    * * *  *  i;
  ****  * *  ** **  ** ** * 
  {
*  * ***  **  * ** * *** **    **   *  **   A[i]!='\0' && A[i]!=B[i]   )
*  * *** *   ** ** *    * ** * **   ****  * *** ** **    ***  **   *  *    0;
*  *     ** *  *** ** ** * ** ** ****  **  * *      * 
****   ** ****  **  * **     *** **      **     **** ***  ******    *   *** *     **
  }
  * ****       *  1;
}


int main()
{
** *   * * ***  * ******   * *  * a[n],b[n],c[n];
* * * *  * **  **      * **  i;
   * *  **    * **   * *  ***  **  *** *****     ** ***
** **   ** *  *  ***** *  * *** ***  **  ******   *
 ***   * *  ** ** ***** *  * *  *  ** (aa(a,b)){
******  *  *  * **** ** * * **      *  ****    * * ****  *  * *  
*  *****   *   * * *   *   *   ***   **********  *** *       ** ** **** ***  **    * 
*  ** *   *      **         * *******   * **  * **** ****           ****      **      **    **** ***** ***  ** ***  * 
   *** * ***  *   **** *     *  *****  **** *    * **** *     *** ** **** **  *   ** * 

* *  *** *  *  *** * *****  ***    *****  * **  *      * *  *
***** *  *   ** *    *** ** *** *  *** * *** **** ** *** * ** * ***  *  is a prefix of %s",c,b);
**        ** ******* ***      *
  *** ***** ***  **  ** *** **
****    * **   ***** *  ***  ***  **   ** * * *  *  * *** **  **** *  is not a prefix of %s",a,b);
 ** *    ***  *   * *** *       0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *  ***** *** 
* *  *  * * ***  *  
int main (){
char  **    *** 
char  *  * *
* *  ***   *  *** string1:    ****
**    * * ******  *   *  ** *****  
*    * * *  * ** string2: ***   *
 **  ** *  *   * ** * ***
**  * *** * *** **  * 
* **  *** ** *   ** * * **** * **  *  is * *  *  * of *  **  ** * * *  *** 
else
*****    * ** *   *    * *     ***** *** is not prefix of *****  * *******       

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** ***  **
#include *** *******  *
#include *  ****** * ** **** 
#include ** * * **** *
int prefix(char p[],char s[])
{
* ** ******  ****** ********* * *  **
  *  *   *** * * ****   ** * * 0;
***  * ********  ** *   ** if       ** *  
*   *  * **   ****  *    *  * * *  1;
** *   * **  ** ** *
**  *     *   *  *  * *  * * 0;
}

int main()
{
**   * **** * * *  * * p[999],s[999];
*    ** * *** * * * * *   **** * *     
 * *  ****     ****  *  *******   *  ******** 

*** *   *   *      **      ***  *
   * * ***  *  **     ****  **   *  * * * is a prefix of %s",p,s);
  * *       * **  * 
*  **  * *  ** *****     * *  * *  * is not a prefix of ** * * ****

*    * ***  ******  **  *   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** *** ***** *
int main()
{
  *    *   * *  *      ****  length1,length2,c;
*  ***  ***  * *    ** **** a[100];
*  *     * **       **  ** *** b[100];
* **  ***   *** **** **    ** **   d[100];
   *** * ***  *** * *******  ** *  *  **  *   ** **
    *      ***** ** ** * *    * *  *  ***  * *** *  
  **  *   * * *  *      ***   * *  * **  *  
*  * *   *  *  *  *  *  *** * * * *     ***** *
if (strcmp(a,d)==0)
       *********** ** *  * **
*  *   ** ****   * * ****  ***       * **** *  *     * * *  *  *     is a prefix of %s",a,b);
*** *  ** *  **  *     ****   
 * *   **   * **  ** *  ***   
 *    **  *   **  *   **  *
**    *  ***  *** ***** ** *** *  * * ** *    * * **** * *** ***  ** is not a prefix of %s",a,b);
** *****    * *  *****  
   * ** *   **  *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *     * *** **
#include  *    *  *   * 

int prefix (char  * ***   str2[])
{
*    * *  **** **   **** *   length=0, **    *
**   * **** ******* *  
* *   * *  *   * ** * *  *    =  **   *   **    * *  
** *   **  *  * **   * * *   
 *******  **   **    *  * *  *      ** * *  * * ** *
**   * **  *  *** **  * **** **** ***  **
*** *       **   ***      ****  **  if ** *  * * * **
  * *     *  ** *   *       *  ****     **    * ** *  
  ***   **   ** *  *******  * **  *   }
 * ***           ** **         * ****
 *  ** * **   * ***  ** (count == length)
 * * * ** ** **  **** ** * * ***** * *     1;
 ** ** * * * *     **  **  else  * ** *     0;   ** * * *    **     *
  **   *** ***  * **     **  *   
}
int main(void)
{
    **  *   * **  * ****    *  * * * *   *  * 
  *  *      *** *    ****
* ***** **   ***  ***   **     * ** *  **    **     str1, str2);

* **   * * *** *  ** **     * ***  * **
 *** **   * **  {
* * **      ** *** *     * ** *   * * ***  *  **     *  * ****** is a prefix of   **** str1, str2);
 ****** * * *  ** **   *   ** 
* * *    *****  ****    **     **
*   *       ** *    *      * * * *  ********    *  ** *  ** * *  is not a prefix of   *** ****  str1, str2);

  * **** * *** **  * ***   *  ** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * ******   
#include **  *   ** *  
#include  * * *** **  *  * *

int main()
{
 *   **** *** ****  *      * ** prefix[100];
***** ****     ** * *****  ***  word[100];
*  ****** **      **  *** ** *****  *  ** %s", prefix, word);
*  ***  * *   * ** *  ** * * i;
** *** * * *  *         * * *** *   = 0; i< strlen(prefix); ++i)
***      *  ** * *   **  * * ***
****     ***   * ** ***  *** * ** ***      ***** ** ***** ***
   * *   * ** ** *   *  ** *  ** * ** **   ***  ** ***  **
*** *** *  * **** *****   *  **  * *****   *** **  *  **  *  ***    * ** *   * ****** ***   *   is not a prefix of %s", prefix, word);
 ** ** ** *  *     ** *   *    **** ** * *       ** * ** * *  *  *   *****    *   ** *** 0;
***** ***** ** ****  *   ** **  *    * *** ** **  **
*   *  *****    ***** *  *** *
***** ***   *  *  *   ****     * *   is a prefix of %s", prefix, word);
*    *** * ******* **  **  *   * ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **** ** * **   
#include   ** *** * * *** 
#include  * ** *    ** **** *

int main()
{
 *    ***  ***  ** * ****** * * prefix[100];
* ***  * *** **  **   *    ** * word[100];
**       ** **    ***  * *   * *  *   %s", prefix, word);
 *    ****  **  * ******   * * i;
 * *  * ****  *   *  **   ** = 0; i< strlen(prefix); ++i)
*  ***  *** *  *  *  * 
* **  *  *  *  * **   **** ** * **  **   ** **** *   * *  **   *** *  
** *     ** *  ***  ****   *   ****  **** **    * ** *   * 
*  * *  *  **  *  * *    *** * * *****  **   * *  ****** *   * **  *   ****** **  *  **  * * * * is not a prefix of %s", prefix, word);
  ** * ***  *** ** * ****  * * * *  ***  ** ** **  *** **** *   ****** * ** *  *  0;
*** ****    *    *   * *     * **  **  ***
 * * * * ***  * ***** * *   **
    * ***  ** **  *   ******** *** ***  is a prefix of %s", prefix, word);
  *** *  ** * *   *   **** ****** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*        * **  * ******
 ****  **    *  *   *
**     ** * *** * * *

int main()
{
***  * ** * **** char *   ** 
  *****   * *    char  *****
  *  *     ** *    * **   *   *** *  **  word);
***       ** int i;
* ***      ****   for(i = 0; * ** *  **  * * ++i)
   *   **  **  {
* **   * * **  * * * ***   * ***     * *    **
* ****  *** * *   **  ** * {
  * ** * *  * *   **  *   * *** * *  *   * * **      ** is not a *  of ** *   *   *** word);
  ***     ****  ** *** *      * **   ** *  * 0;
 * ** *  ** **   **   ** }
** ***  * **  * }
   ****   * * *  *   ** *  *  is a prefix of   *  **   **  word);
*** *  *  ** **** *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.133
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 6.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 4.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 6.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users