1-11 Exercise 3: Prefix of a string

0 like 0 dislike
13.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 13.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include *   *   **     **
#include  * * **** ** ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* * *   * **    **  ** ***
 
****** * ***  **    ******      **  *     ** *     **
*** ***   ** ** *  * * *   *  * *
    ** **** *** ** * ** **     ***  *****  *    ** **    == s2[i])
*  ** * ***  **** *  ** * * ****** * * * * *   * *** 
* * * * * ***  ** **     *   *   **    * * * *  ** * *****  ** **** ** **    **
  *** ** * *** * * ***    * * *   **** *  *** *  *   
 
        * ***  *  * *  ** **** 
 
******   * * * * ***  * *       * *  == length)
* **     ** *   ***      **   *
 * *     **  **  * ******** * * ****           *** **  *   ***    ****** ********** is a prefix of %s",s1,s2);
*    **** * * ** ***** * *    ***
 
 ****  **  *   * ***  *    *** * * 
* **    *******  *  ** * **  ***    
* * *  *   ** ** ******* ****    *    ******** * *  **** *  ** **  *** * *   is not a prefix of %s",s1,s2);
***  ****  *** *** * *  *    ** **  * * **
 return 0;
*   * * *   **   ***    **  * * *   *  * 
 }

int main(void)
{
**** **  *  ******  * **  * s1[100];
**    *   **  * * * ** * *  **  s2[100];
**   *****  ****   ** *     * i,j;
 * **  **     ***  *  * 
 *  *  ** * **** *   ***   * *  *   *   ** *****   s1);
*   *   * *  **** ***  **** *  * * ** * *    * s2);
* *  *     ***    ****  *  * **
*  ***   * * *  ***  * ** * **  **   * **
 * *      ** * * **    ***
     * *   ***  **   *  *  **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *** *  **** *
#include ** *  * *  

int prefix (char st1[],char st2[]){
** *  *****   * * *   *    **  len=0, i, cnt=0;
 *  *******   *** ** **
  *  * ** ***  * ****  **   = (unsigned)strlen(st1);
  *   ****    ****** **
* *** ********     * * *    (i=0;i<len;i++)
 *   * ** * **  **  * *     *  
    **  * ****  (st1[i]==st2[i]){
  * **    * **   **  *  * *   *  **    ** ** *           *  ** *  *  *   *** **    ***
    *  **      *  *  ***     **  *    *****    *****
  ** **  * **     * **  ****** *  *
   * **   ** *    ** *  ** (cnt == len){
**   *   *       ***   *  *    * * *  ***   * * *** * * * 1;
** * *** **   * * ****** *  
*      ** **** *  *    *** ** 
* * * * ***    ** *****   **   *  0;
    *  *** ** *** *  *** 
}

int main(void) {
* *   * *  ******* ** **     * st1[256];
 * *      ***  * **** ****   *   st2[256];
  *** ** * * ** *    **  *      ***** *  *    *   **   st1);
 *   ******  * ******  **  *  *  **  *     **  st2);

 * ** *** **  ****** *  ***** (prefix(st1,st2)){
  **  *  * ****** *** *   * *    *   *  * * ***  * * * ***** *  * is a prefix of %s", st1, st2);
*  * ***    * *  *** * **** *
 ** *   * * * *  **** *    * 
*** ******** * * *** * * ***   * *  *******    ** * * **** **  ** *** * * is not a prefix of %s", st1, st2);

      **      * ** **   * *    0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 *** * *   * ** **  *    *  *   * *    ** *  *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 *     **   * ** ** ** ***  **  *  *  *   * *  * **** 
*  *  ** *  *   *       * ****   *******       ** ** **   **    **  *    *   *  * *  *****   
**   * **    *   * * ** *  *** *  *    *  * **   *   * * **    **** **   **       *   ***    ***  * ** *  **  
    *****  * * ** *** * *** ** * * **  * ** * * **   ** * *    *** *  *** ** **  * *  *** ******  *  ** ****   ******   *     * **    **   ** is not a prefix of %s",a,b);
* *** *  * **  * *  * ********   * ** ***   **  *** * * * * ** **** * * *   * ***  * **    *   * **  ** * **    **  * **   *****   ** ***
 *      *  *  **  *    * **  ** *  *           **  ** *  ** * * * **   ** ** **   ** ** * **   ****     *** *
**     * ** **  *   *   ** ****  *     *   **   **  * * * ****  ***  * **
* *    *** * ** *   **** * **   ** * *       *  ***     * *   *   * **  * *     ** * *** * **   *** * **   **  ***
*   **    *** **      * ** *  ***   * *   * * * * * *  **  *  ** * ******* *  *** **  * **  **    *** ***** * ** **      * *  *   **    **   **      *  is a prefix of %s",a,b);
**  **  *     *    *   ** **  ********    ****  *   *** **    ** * **** **  *** ** ***** *   ****** **     ****** **   * *** * *
** *   *** **    *  **  *  *** ** * * * *          **    *     ***   **  * ***    ****** * ****  **    ****
 **       * ***  * * ** ***  * *****  **** *   * *** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 *    *  *    * **   * ** * ** *** * *  *  ** * 
  **   ****  **** ** ***  ** **** *** **  *  *   *   **

 * * **  * **   ** *****   * *   *     *   * *  *  *   ***  ***    *** ***  * * *** 0)
 *  ***** ****     *   **  ** *  **** **  * *  **   * ** ******* * **  
 **   **     ****    * **  **********   * **** * **   *****     ***   ** **  *  *    ***** ***    * **    *       is a prefix of %s",pre,str);
     ****  * * * * ** *  * *    **  **   * * * * *  *  * * * * **    *   
 *   *  * * * * ** * * *** ** * *  ****   * *** ******  
 ** ** * **  **** *   * * *   *    ***   *** *    ** ******   * **   *** *   **    * 
  * ** *      *  ** *** * *   * *   * *** ** * *   ** *  * *  ** * ***   * *  **** *  **  * *  **     *****      is not a prefix of %s",pre,str);
*  *  **** ** *    * *** * *  * **  * *  * *   *   ***   ** * *  *   * ****  **** ** 

  *** ** *** * * ***  *  * ****   0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
    * ** *    *  ***   **  * * a[100];

 * *  ***         ** **    *** ** b[100];

*  * ** *  * *     ** * ****** *    i = 0;

**  ** ***  ****  *   ****   prefix = 1;

      ****    *  **** **  * **** * *  *   *  **  a, b);

 *  *** *    * *  *** * * **** len = strlen(a);

** * *    * ****   *  ***** * = 0; i < len; i++)
 ** *** *       **  **    *   
  ****  * *    * ***    **    *** ****** *  ** * ***   ** * * != b[i])
 *   ***  ****   * * *    *  **** * **  *   * **  * 
   *** *  *   * ** * * **   *  *** ** *****    ** **** **  ** * **  *      *****  = 0;

* **     ** *   **  * * * *  * ***   **** *** ** *****    ** **** ** **  *****   *      * * * * is not a prefix of %s", a, b);

    *   **  **** ****  *  **** *  **   *    * ****  ****  ****    *    ** *
** **   * **** *  *   *** **** **  ****    * ****    **  * ** 
  ** * **   **     **    
* *   ** * ******     ****  **    * *** == 1)
   * *****  ***  *  **** * 
***  *   * * *   * * * * ***  *** *  ****** *  * **  *  ****    *   *    ** is a prefix of %s", a, b);

   *** * * ****    *  **  **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *   * * *    
#include ****** *   *  * 

int main() 
{ 
 *  **   *  **** **   ** * ** a[100],b[100]; 
* ********* *   * ****    i,j,prefix = 1; 
**********  * ***** **   *  **   ** *** * **  %s",a,b); 
 * *   *  *** *   *  ** ** len = strlen(a); 
 * *** ** * * **   ****   **  **  = 0 ; i < len ; i++) 
   *  ***  ****  *   * * ****  
  **** **  ***** *** *   ** * *   * *     *****  *  *  ***   * * ** != b[i]) 
 * ** *** ****** * ***   * *    *** *  *** * **  
***   *  * * *   *** * ****    *  * * **** *    **** * * ****  *  * *****  **   * ***  * * * = 0; 
* * **  * ***    *** * ** **  *  * ****  *      *  ***   ****  ** * **     **  * *** **     * is not a prefix of %s",a,b); 
 ** **   *  ********  ***  * * * ****  **  **           * * * ****  * ** *  *      
 *   ** ***  **    ** **  ** *  ***   * * **   **  *******  

 *   * *****  ***** **    ** * 
 ***    ** * * *  ***    *   ** == 1) 
 *  *     *  *  * * *  ***  *   *     *  * ***  * **** *  ****   is a prefix of %s",a,b); 

 
**   *      *  *******  *   **  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *  *** **** *
#include ****  **   * **

int main()
{
 ******      * *** *    ** * a[100],b[100];
  * *  *  ** *** ***       ***  ** i,j,prefix = 1;
*     ****  ** *   *     ***  *** * ** %s",a,b);
   *  **  *  * * ** *   *  * len = strlen(a);
    ** * ** * ****  *** * = 0 ; i < len ; i++)
**  * **       *  * ** 
******   *  *** **    *  ***  ****  ** *        ********   != b[i])
   ** **   * * *** ***** *   **** ***  *  ***    * *  * *
   *  *   ******  *** ** **  * * * *******   * **           * ****    *  * * ***   * * *** = 0;
* *** *   *** * * * * * *  * * **  *****    *** ***** * * *  *    **  **** **  *      * * *** is not a prefix of %s",a,b);
 *** ****   ****** **  *  ** ****   *** ***   ***  *   *** **      **    *  *** * *
** ****    ** *     ** * **   ** *      ** **** **  ****    ** 

*** * *   *** * ** * **  ** *
*   * * * * ** ****  * * **  *  *  == 1)
*   *   * **  ***  * **** ** *        ** * * * ** ***    **    *****  is a prefix of %s",a,b);


  * ****** * *** * *   * *** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** ***  *  **
#include   ***   ****   

int prefix(const char *pre, const char *str)
{

    *  *** *    ***  ****** **         *  * * **    *
 **   **** ** * * * *  ** * * * **  ** **         * ****  *** 0;
* **  * ** * ***  **     *     **** ** *  ** **** *   * 
*  ** ** *  *   * * * *     * *******    *** *  ** **    * 1;
    *    **  * * **  * **  return 0;


}

int main()
{
* ***    ** ****  *  *   *  *  pre[100],str[100];
*  ***   *   ***     * **
    * *** *** ** * ** * *     ****  *   **  ***
  * * * *  ******       * * * * *    ** *
***** *    ***    * ** * * * *  ***    **** *** *  * ***  ***      is a prefix of %s",pre,str);
 ****  *    ***** ***   *  ******  *
 *   *****  * * ****      *   * * ****   ***   **  * ** *** *   is not a prefix of %s",pre,str);
* * * **   ** *  ** ******* * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *** ***   ** *** * *** * *     c;
 ***   *     * *  *** ***** *** * * ** *   * ** 
* ***   * ** * ***   **     **      *** ****      ****** 0;
* *    ***  ***   *    * *  
   **  **** ****   *  **    * *** ***
* *** *** ** *  * * *  ****** * *** *  *    **** *    *     *     of a string
*    ***    *** ** *****        * **     * ***    * * * *   *    *****   * **   **  * * 
 * **   *** *  ** ** *  *       *    **   ** * **  *** * * ** * * ** **  **  **   **** ****  **   **** *     **** 0;
  *      * **  * *** ***** *   *   ****  * *    **  **  *  
**   * * *** *  ***    **** ***   * * **         * * * *  *** 1;
    }
}

int main(){
* * *  ** * ** *** *   *  *  a[100],b[100];
** **  **    * *  ***** *** *  ** **  %s",a,b);
**  ***** **   *** * ** *  * ***    *** 
 * * ***  ** ***  ** *   ** ***         * * *       **  **    * **   is a prefix of %s",a,b);
**** * * *   *  ***       
  *   **  ****** ** * *  ** **   * * *    ***   **   * *** ** ***      is not a prefix of %s",a,b);
   *   **   **  * * *** *** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * *  **    * * * **   *  p[100],s[100],a[100]={};
   * * *    * * ******** * t;
    *** **  * * * ** * *  **      
** *** ***** **  ***  *** * *    ** *** * *  
*   * * ** * *****  *** *      * *** %s",p,s);
* ***  * * *** **  *   *  ***  * 
*****  *  ** *   *   *    *  * *   ** *
 ** ********* *** ****** *  * *** **
 *** ***** * *  **  * *     *  ***  ******* *  * 
* **  * *     *  * ****  ***   ***
* *  *  *   *** *   *  * **  ****   * * **** ***   ***  *  *****  **  *  is a prefix of %s",p,s);
* *** *   **  *  *** * 
 *  **   *   ***  ** * * ****  
*  *  ** *  *  *  * **** *   * * * * * * * *       * ** ****  *** *  *   * is not a prefix of %s",p,s);
 *  ***** ** *** *  *  *** *** 
 **     **  ***  ** * *  ** *   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 19.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 12.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 16.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users