1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ***  *  * ** ** *
#include * *    *** ***  *  

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
  *** *********** ** *****
 
*  * *****    ** ***** *** *  *** *  *    *  * **   *
 ** *  **** *  ***  *    *  * ***
**** * *****   ****  * **   ** *  * ** *  **    * ***    ****   == s2[i])
*** *   * *   ** **  * * * *  *  *** *   **  * *    **  *
*      * *  *  ** *  *  ***  **   ********* * *** ********   *    **   * **** ***   * *** **
*** * *   *  **    ** * *     ** ** *  * **  *  ***** 
 
   *** *** ***   * *** *** ** 
 
 * ** *   *  *  *  **   *    ** ** ** * == length)
*  ****** ***   * ******     ***  
 * * * **  ***  *****     ******     **       ******   *** *  *   **** ** is a prefix of %s",s1,s2);
* * ***   *  ********    *  ** 
 
 **  *** *   **     ***   * * *****
*  **** *    * *  * ***  *   * ** 
* **    * **** * * ***  *   ***        **   *   **    * *     *      * * is not a prefix of %s",s1,s2);
**  * ***   * ***  **  ******* * ****** 
 return 0;
* ** *** **    *   ** ** * *  *
 }

int main(void)
{
*** *  ********** ***    s1[100];
* ******* *   *  **  ** * ****** s2[100];
 * **********   * * * **** *  * i,j;
**** *  ****  *   * * ***  * 
*   * *    ** *****  * *** *     ***** * * *** s1);
  ***          *    ****** ******* *  ** ** s2);
**   * ****  *    *  * ****
*   *** * **  * **  ** ****** 
 **** * *** *  *** *  
**** *   *  *  **  ********* *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***********     * 
#include * ** *  ** **** * 

int prefix (char st1[],char st2[]){
 * *   *  *   *     *  ** *   ** len=0, i, cnt=0;
 ** **   * * * ***** *** 
 ** *   * **   * ***   *       *   = (unsigned)strlen(st1);
        **  * *  ** *** *** *
** ***   *   * * * **  * **  ** **   (i=0;i<len;i++)
 * * ***      ** **  ***** *
* **    ***   ** (st1[i]==st2[i]){
    ***** *******    * ***    **  **** **  * **    *** * ******  *   *** ******* **
 *   ** * **   ** **** ****  ****  * ****  *  ** *  **  *  *
 ** ***** * **   * *  * **   **
         ** * *  * **  * **   (cnt == len){
** **** *** * * *  ****   *   *** ** **  *** *  ***   *  1;
 ***** ******* ** ******* **
 **     *  **   * **** *    *
**   ***   *    ** *** * * ** 0;
* *   ***  * ** * ** **** * 
}

int main(void) {
  * ** * ***** ****  *    st1[256];
  ***   * *     *    **   ** st2[256];
 ** * *** ****  *  ** * * ** * *  *****    * *     *   ** st1);
***  *    *    *  *   ** *** *    * *     *  ******* st2);

*   *******   *    ***  ** * (prefix(st1,st2)){
  *** * *  * ** ** * * ** *  *  *   **** *     ********  ** * is a prefix of %s", st1, st2);
    ** * *   *  *  **  * ** *
 ** * *   **  ******    *   * * 
 *  *** *  *  **  * * ***   **    * *      ** *   * *  **** ** is not a prefix of %s", st1, st2);

        ** *** * * ** *  ** ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  ***    **  **** ** * *  **  * ** * * ***** *** * 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  ** **  *   ***  *    * *   * * ** ****   ******* * * **     
*** *** *  **** * * ***      *    **   ****** ***  *  *******    * **  **** **   ***  **  **** * 
* *  * **      * *****  **   **          *** * *** *  *  ****** ** * *  **  ** *** *****  ***  ****  ** 
  *   **    *     *   ** * ***  *  * ***  *  *    **   * *  *** * * *    ***  *** *  ***    **  * ** * *   ****   *  ** ***   *** *** **  *   is not a prefix of %s",a,b);
 ** **    *  ** **  *   ****  *   *      * * ** *   *    * ** * *  *      * *** *  ** *  *  *  *    *  *    * * * ** **** *  * ** 
*  **  **   * * *****  **  *   ** *     *  **     * * *  ** ***    ** * * *   **    * **   *    * * * * * 
 ***  *  ** **    ****** * * *  * ***** **  *  **** ****   * * ***    * **** **  *    ***   *
*** ******   *     * **     *   **  ****   *  * ** **      *   *** * * * ***   *** ** * * * * * **  *   ***** * **
**** **  **** ** ** *      * ****  * **    *   * *  ******  * * * ** *** * ***   ****  **  * * *   *       *** * *** ** * ******** ***  * *  * *  is a prefix of %s",a,b);
  *  ** *  *   * ***    *   * *     ** *    * ****  ** *** ***  ** *    *  **   ****  *       ***   *   * ****  **  ****  * **    *
   *   * ** *  * * * ** **     ** * *  **** *  **   *   * ** *  ****    **    *****  *** ***  ** 
* *   **  **  * **** *      *  * *** *** ** * *    **   **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*   **    ** * **** *   *   **** ** *** ** **    * 
 *    ** *  *    **  **  * ** *** *   *  *  *** * *

** **  ** * *** *** ** *     *  *  **** *   * *  ** * * ** ** * *  **  **** * *  0)
 ***  *** **    ** *** *        *  *   *  *   *  *     *****  *   * **   *  **  
 *   * *   * * *   *** **   ** **    **  ** * ******* *   * *    ** ** ** * ****   *  * *** **     *  * ** **  * is a prefix of %s",pre,str);
** * *    ** ** ** ** **  ** *  **   *        ***  **** ** ****   ******* * 
**  ****  ** * **** *   ****  **** * ***  **  * * * ** ** *
 ** ** * *   **    ***   * ***** * **   *** *** ** *  * ** **** ***    *
* * ***** * * * ** * **   *  * *** * **        ***  * ** ** * * ****  **  **** ** *  ** * *  *** **   **  ****  * * * is not a prefix of %s",pre,str);
    ***   * *    **     ** * **  * ***   ***  * *  *  * *  *     *  * *  **  **** 

     * *  **  *   **   ***  *** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
****     * *   *   * *** ** * *  a[100];

 ** *  ****** ** ** * * * * * b[100];

    * **   **  ***** **** i = 0;

 *  ** * **   * * **   * **   prefix = 1;

    * ***** * **  ** *** *    **** *          ** a, b);

    ****   ** ** *    *    * * len = strlen(a);

**   * *  *** ** * * * **  * = 0; i < len; i++)
 ****  *   **  *     * ***
***  **  * * **   ** ** ***     *    ***    **  ***   *   != b[i])
 *     ** * *  *      **   *  ****  ******    **** *   
 **** *** ** *      * *  ********  * *** * *  ****   *  * ****** *    **** *  * **   ** = 0;

  * **     *      *   *  **  ****    ****    *  *    * *** * **  **        * * *    **   ** ** is not a prefix of %s", a, b);

* * * *  *****  * * * *    *    **   * * ***  **  **    ********   ** * ** ***  *  *
* **  **  *** *   *   ****   **  **** **  * * *** **** *
    ****** ** *** *  * ** *****  *
 *  ***   *  ** *  * *  ** *** == 1)
   ** **** *   *     *
***       *  ** **** *    ***** * * * *   * ** *    *       * * is a prefix of %s", a, b);

 ***     * * * **** **   *  
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * * **    
#include **   *  *** **  

int main() 
{ 
 * *  **** * **  ** ***    a[100],b[100]; 
**   ** * *  * * **** * *****  i,j,prefix = 1; 
 **   ** * ** *   *** **** *** * *     *  **  %s",a,b); 
** * *  **      ** *  ** ** len = strlen(a); 
 * *     ** *  ***   * * * = 0 ; i < len ; i++) 
 **  * ****  **    *  
 **  **          *** **  ** ** *    *** **   ** *   * != b[i]) 
  *  ****    * **    * ** * ***  *  ***** ** ** **    * 
** *  ***  * *  **   ********  ** **    *** ****    * ** ** ** *  *    * *  ** *** * * *   * = 0; 
* *   *** *** **** *   * * **  *  **** *************  * *   *** *    *  *     **  *   is not a prefix of %s",a,b); 
**** ** **  * * *     * *  *   ** * *** *   ***     *    *  * *  *** *  ** * **** * 
   *  **    * *    **  **   *  ****   *** *****  * * 

   *    *  *   * * ***  ***  
* **  ***  ** * ** *   * * *  * * == 1) 
  * * ****** **** *  *    *   ** **     ** **  ** * is a prefix of %s",a,b); 

 
     *    *** ***      *  **  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *******  * **
#include *  ***   * *  * *

int main()
{
     ****  * * **  **    ** ** ** a[100],b[100];
* ** ***   *  *  **** **  * ** *  i,j,prefix = 1;
** ***    * ***** *** * * **   *  ** %s",a,b);
** ** *** ***  ***** len = strlen(a);
 **** *  **  * * ** * *******    = 0 ; i < len ; i++)
* *   * *  *  *  ** *   *
*  **       **  * *** *  * ** ** * * *    *   *** *****      != b[i])
 ***** * *   *   *  * ***  ****** * ***  *** *     ** * * 
* * *** *******   ** * ***  **** ** ***  *  ** * *****   **     *** **  * **  *  ***    = 0;
  ***    **  *** *    * *  *    *     ****    * ** *****  **     * ** * * *    *** *  ****  *    ***** is not a prefix of %s",a,b);
* **   ***  * *****  * **    ** ** * **  ** **** *      *  **  ** *  * * *  *** **  *
 * ****** * * *     ** *   * ***  *   * **** *      **

* *   *  * *  **  *** **  * *
* * * ** * * **  ** * *  * * ** ** ** == 1)
 **  ***  *      *  *    * **  * **** ***    *** * *  ** *   ** is a prefix of %s",a,b);


** * * *** *      **  *  *****    * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** *   ** * 
#include ****   ** * **** 

int prefix(const char *pre, const char *str)
{

   ** ***   *  ***   *  * ** * *    *  **     *** **  
** ** * *    *         * * *** **   ** **  **   * *  **   0;
 *  * * *     **   ** *    ** * *** **  *  *   **  
    ****  ** *** * *****   *  * ** ****  *****   ** * * **  * ** 1;
 ** *  ****   ** **** * *  *** return 0;


}

int main()
{
***   *  *     *** ***    * *  pre[100],str[100];
*** ***  *  *  *     *  
  *  ***    **   ***   *  *   *  * *   * *** ** *    *  *
* * ******  * *  *  * **  * **  ** * * *
   ******* **  ***  *    ***** ** **   **     *  **   ***** ** * * *   ** * ** is a prefix of %s",pre,str);
   * * ***  ****** ***
** * *      **  ****    * ** **  * *   *        * **  ** **  *     ** is not a prefix of %s",pre,str);
   *   * *  ****** ** * ****** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
  *** ***** * * * * *  ** * c;
  **  *  *     *** * * *** **   *** ** * *   
      **   *** ** **    ***  ** **   ** * * *       ***** *  *** * 0;
** *   *  ***  ** *   *     *  
* ** *    *    ** ***  * ****** 
  * *    *  ***  * **** **   * ** ** *** ***** *** * *    *      ***  ****  *** of a string
** ********* ***  *  ** *** ***  *** ** * *    **    ***** **  *   *     **     * **    ** **** 
*  **  *  * ***   *     * ***** **  *  * *** ***  **    * **      ** **   * *   ***    **** *   * *  *  **  **     ***  **  *  0;
*  *   * * *  ******   *** ****   * * ** **  * 
 *      *** ** *   * * *   *******  *    **  ***  ***** * *   1;
    }
}

int main(){
 *  *  ****** * * ***  ** **  *  a[100],b[100];
*  * *  ***  *      *    * ** *     ** * %s",a,b);
 ** ** ****    **  **   *** * ** *
  *** * ** ** ****  * * *    * *   ***  *   ** *     ***   ** is a prefix of %s",a,b);
   *****    *   *      **     
  ** ** **   ** * **     **   *      * **  * ******    ****     * ** **  **  is not a prefix of %s",a,b);
 * * *    *  * * **  ****  *****  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**  * *   * * * **   *      * p[100],s[100],a[100]={};
 ** * *  * **** ** *       *  t;
***   *     ****** * *** *  *  **** 
***  *****   ** **   *  * * * *   
*   *       *    *   ***      ** ** *  %s",p,s);
 ** * *  ****  * *      * **** **
  ***    ***** *****   **   **  * 
  *  *** ** **    * **   **     ***  * 
 * **  *  * ******   ** **  ***  *         *
* ** *  *  *   * ** **    * ***     *
* ** **     **  *  *   * * **  ******      ** ***   ***    ***  **   is a prefix of %s",p,s);
* *  *** *   * ***   **  
     ** *** *** * * ****
* **   **  * **  **  ** **     * ****   ***** * *  ******** *  * is not a prefix of %s",p,s);
  *  * * ****  ** ******   **
**  *   ** *  **** ********** *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.157
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users