1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  *  *   *****
#include  **  **    ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
  * *  ** ***  ***
 
***    * **  **    **   *  ** *****  * ** * 
   ****   ** * *** * *    *******  
** *  **  **   *   * **** * * ** ***   *  ***     *  *****     * == s2[i])
******  ** ***   ***  * * * *  *** *  ***** **** * ****
  * **     *    *    * * **** * * ***   *** * ** * *  * * * *** ****  * ** ** * **    
 **** *   ** **  ** ***   **** * * *   *  * ********  ** * 
 
 *  *  * *** ****** * ****   
 
  * **       ****          **** *  ** ** == length)
* * * ** ***    * ***** *****  ** 
*    *   ***   ***  ** * *****  * ***** *  *****     *****  *** ****    *    is a prefix of %s",s1,s2);
  *   ** *  *  * *  **** * ** * *
 
 *  * ** *** ***   * ****** *  *  *
  *** ** * *** ** *  **  *****   *  * 
**  ** ***   *    *  *** *   ** *** *** * *    * *   * * *** *        is not a prefix of %s",s1,s2);
 * **** * ****      *  **** *** ** **
 return 0;
 **  *   ***   *     * * *  ***  
 }

int main(void)
{
*****    * *  * *  * *** **  s1[100];
**  *  **** * * * * *  *** ** * s2[100];
*      *   * ******    * ***  * **  i,j;
*   ** *** ****** *   **  *
 * ******* ***  *    ****   **     * *  ** *  * **  s1);
 *** ** * ****    * ** ***     ***** *  ***** ** **  s2);
 *   *   **    **  *  * **  * ***
  ****** *      *    * ** * ** **
*   * **** *  *      ****   
    *     *  **** *     * * *  *  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** ****  * *
#include  * ** ** *    *

int prefix (char st1[],char st2[]){
   ** *** ****  *    ***  *  ** *   len=0, i, cnt=0;
*  *** *  *   * *** **
* *  * ** * *   * ** ******** ** = (unsigned)strlen(st1);
 **     **  **** ** * ****** *  
 ** **   *  ** *** ****** ** (i=0;i<len;i++)
  *  *      ** * **  *  **
*  ** *  *   * (st1[i]==st2[i]){
*  * ***  * ** *   ***  ***     *   *******   ****    **  **   **  **  *    **    **** *
*  **  ** *   *  ***    ** *****   *  ** *       **  * **
 * **     *****   **   
*    *****  **** **  *   * (cnt == len){
 *  * **** *   ** * *   ******* *  *  *   * * **** * **  1;
      * **** *** **  * **
**    * *    *  *    * ***  *
 **  ** *   ***    * *    ** 0;
* *   *   *  **    
}

int main(void) {
 *  *   * * ****  * **    ** st1[256];
 *    *     *   *    * ****    *  st2[256];
***  **** **  *  ******** * *** * ******** *** * * st1);
*  * * *****    ** * *  *     *** ********   st2);

**  ** *     **  *** *  **   (prefix(st1,st2)){
*   **  * **  * **     ******  *  *  *        ****** *  *** is a prefix of %s", st1, st2);
*     *   *  **      *****
 ****   *   **  *    *  ** * ** 
      * *******   * * **** ** *** ** ** * ***  **   ***** **  **   * * is not a prefix of %s", st1, st2);

  ** * *  ** *   *   ***  * * *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*** ** *  *     *    *     *   **** **   **** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*  * ***   * ** *   *   ** * * **  ****    ****   
*    *   ***  *  *  **     * **   ****  * *  *   ****  *****  **  ***********   
*  ***** *  ****  ** * * *   * * ** *** * ** * *****  * ******   **** ** *** * **** **  *   ***  **   * * ** *
**  * *  *    *   *    *  * ** * **    *   **    **    **  ** **        * *   *** *  **** *   * *  ****  * **   * *** *   * **** * *** ** *** is not a prefix of %s",a,b);
 * **  **** *  ******    *     * ***  ****   **   *    *   ***** **** *  *   ** * * ** ***   *  **  *      * ***   **** ***    *  **  * 
 * * ** *******  ** **** * *** *  **     ** *  ******* *** ** *  * * *  * * ** *  **   *  * *  *    
*  ***  **** *  ** ** ***  **    * * * ** **    ** ** * *   ****  *   **  *** *  
***    * *** **  *** ***  **  *  ** *        * * * ** **  ** * * **** **   *   ******* ***  *   ** ****     ** * *
*   *    *   **    ** ** **  *****    * *    ******     **      *  * * * ** **   * ***        **   * *****  *    * ***  **  ***  **** * **  *   * is a prefix of %s",a,b);
 *    *      *    *  ***    *   *   **** ****  * *  *  * * * *   ** *  * ** ** * * **   *  ** * **** ******  ** *** ** *** ****  * ** * ***  *
 ** *  ***  * ***  *   **** *  * *** **  *  **  * *******  * * **   * *     **  **    * *  *   *  
 * **   ** ***    *   * *    * *  ** **  *      *  




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* *** ****** **  * ** *  **  *     * ****       *  
 * ** ***    **  * * ******* *   **  ** **

  *  ******  **  *  *** *  *    ***** *****   **  * **   **  * *   0)
  *** *** *** ** ** *   * * * *   **    * * **  *** ** * ****  *  * * **
** * **  * **  **** ****** *** **   * * * ** *  * **  *** **  *   * * * **** * * *    *** **  **  * ***  *   *  *  is a prefix of %s",pre,str);
*  * *     *** *  * *  *   *   ** **  **   * * * **** *  **   * * * * ** **  *
** ** * * * * **   ***   ** *** * ****  * * *    * **   *   
*     * * **   * **   ***** *   **  ****   **   **       * ****** **** ** *  **
   ****   ***  *********** * ** *  ** * ***  ** **  *  ****   *      **   *     * ** * *** **** **  *  * **     * * is not a prefix of %s",pre,str);
 ** **    * * *  *   *   ** ** * *   ****  * **** *  *   *** *** * *     *  ** * 

*** ***  * ***  *  *  **    0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 * ** * *  *   *** *********** a[100];

***  **  ** *  ****   ** ** *    b[100];

* *    *** *      **   * ** **  i = 0;

    *    *   *      *  ***** * prefix = 1;

 **** *  **  *    **  *   ** * *  ***     ***   a, b);

*  *  * *  **   *     *  **     * len = strlen(a);

 * *  *** * * *  *  ***   = 0; i < len; i++)
**  *    **  **  * ** *   *** **   
 *    ***************   **** ****  * ***     ****  *   **** **   != b[i])
    *   *  ** * * *     **    ** * **   **       **
   * * ** ***  *   ** **  * **** *   ******  * *  * **    ** ** ***        **   **  = 0;

** *   **    **     * **    * ***  **  *   ****   * *  ** *  ** * ***  ** ****   *   ** * *    *  *  is not a prefix of %s", a, b);

       **** ******* ** ******* *   *** *    * *  ***  ** *** **       ** * ***** * ***
 *  ****  **   *  *   ****   * *****      *    *** *  **
******  *       *  ** ****  **  **
 *      * *  ******         *** ***   == 1)
* **   *** * * * **  * **      
* * **  *** ***** *  *   ** *  *  ***   *   * * *    *****  **  **  is a prefix of %s", a, b);

  **   *     *  ********  ** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     ** **   * 
#include  *   ******* 

int main() 
{ 
     *** ** **  **  ***   * a[100],b[100]; 
** ** **   *****  ** * *   * ***  i,j,prefix = 1; 
*  *** *  *** **  **  * ****   **  %s",a,b); 
*** * ** *   ***  ** **   ****  len = strlen(a); 
   *  *  **  * ***** * *  ** ** = 0 ; i < len ; i++) 
*    *    ****   * * *  * 
   ***   ****** ** **  *** * *  *** *** ****      *   ** * *** != b[i]) 
****   *****  **** *  **  **  * *****      **  ** *  * 
 * *       * *  * * ** ***** *** **   * * * ** *  ***** *  *  ** ** * *    *    ** = 0; 
**  ***   *  *  *  ****** ** *  ** *     **      **  ** * ***    *   * * **  *** ***  *  ** * * * is not a prefix of %s",a,b); 
 ** *****      * * *** * *******   ** *  ** **** ****    ***   *  *    **      *** ** **  * ***  
**** **   ***  * ********** ***  **      ***   **  

* *** * * *      * * * * 
  *  *    ** *  * * ** ** **  ** **  == 1) 
   *  ** * *   *  * *  ******* * *   *  ** *  ********* * ***  * *** is a prefix of %s",a,b); 

 
*  **   *  ** * *   * **   **   *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *  * *********
#include   ** ****    *

int main()
{
 * *  * * * ** ** *   *    *  a[100],b[100];
* *    ** * ***** * **   *** i,j,prefix = 1;
       *** ***   *  *    **  * *  *  *****  %s",a,b);
** **  * *    *  *****   * len = strlen(a);
   ** * *** * *** **  *****    = 0 ; i < len ; i++)
  ****   * ***   ** *   **
***     *    **   ** **** *   *   **    ** ** ** ** * != b[i])
*  ** * * *     ****  ** *    *** * ** ** *  * ***  *    *  
** ***** * ** *      ** * ****  *     *      * *** ** *   * *  * ** ****    ***  *** * = 0;
**** *   * *  ***     *   * *** ** *  ** ** * ******* ***  ************ *** **  *** *****  ***  is not a prefix of %s",a,b);
 * *  *   * ****         *** *** *     * **  *  ******* *   *  **  ** *** ** *  *  *
    * **       *  ** *** ** ***     * * ****  **  **

********   *  **** * * *
   ** * * *  * *   *** * ** ***   * == 1)
* *  * ** *****  * ***  * ** ** *  * ***  *** *   *     ** * * is a prefix of %s",a,b);


* *    ** ** ** **  *******   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** * *    **
#include    ** **** *** * * * 

int prefix(const char *pre, const char *str)
{

* ** **   * *   *** **   *  * **     **** * **  *
    *  *    * *  ** ** *** ****  * *  * * **   * *  **    **  * 0;
 ***  *****  **    **  *** *    *  **** * *  *  *  *
* ** * **        * *   **   ****  ****  * *   **   * * *  **  1;
*  **** **  ** *    * * **    return 0;


}

int main()
{
**     * **   * *****    **** *** pre[100],str[100];
** * *   ******  *   * *
*    ***    * *    * ** ***  * ** ***  ******
*****  *** ***   ***** *  *  ***    **** * 
  **      **  * * **    **  * * * **    **   **      *  *         * * ** is a prefix of %s",pre,str);
   * * ******  ** * *** *  *
* *   ********   *  * * ** * ** * ***  *     **  *   *   * **  *** is not a prefix of %s",pre,str);
 *** *    *****  *   * *  *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 *    ***     *  ** ** * * *  c;
 ** *  *    *  ****  ** *   *  **  ****  * * 
**     *  * ** * *  ***** *      *  ******  ***** ** ** *  *  0;
* * ***** ** ***  *  *****
* * *    * **   * ** *** * * *
* * *   ** *  ***   *****      * **       *  ******* *   * ****  **    * * ** *  of a string
     ****   * **** ***   ***   *     *    *****    ** *  * *  *** **** ****  ** **   * *  * ****
** ****** ***   ** *   *   *    **   ****** *   * ******** *  ***   *** ***** ** ****** ****  *  * * * *** *** 0;
 ** ***   **** *******  * **   * **   ***    ** * ** *
 *** ** ***  **** * * *  **  *** ** ***           *   *   1;
    }
}

int main(){
  **** ** *** **** ***  *    a[100],b[100];
 **  *****   ***  *  *  * ***    *** ** %s",a,b);
*  *  **   * ** * *** ** * ******** *  
*****  ***** * ** ***** **   ***  * ****  ***  ** **  *  ** **** *** * is a prefix of %s",a,b);
****  * * * *****  *   *  * ***
*******  **  *   *      ** * * *   * * * * * ***** *  is not a prefix of %s",a,b);
* **** *  *     ***  ****** ** *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * *    **   * *** *** ** * * p[100],s[100],a[100]={};
      *   ** ** * *   ** ** **  *  t;
 * * * * * ***     **  **** *   **  * *  
**** * * *****  * *  *   *   ***  * ***    **
  ** *  *** * **  **    * ******  * %s",p,s);
          *     * *    *  ** *  *  *  
***       **  ** *  ****  * **  
* **   ***  *** *  **  * ** * *   *
*** *     *** ***** **    *  * *  *  *** **  
**  *** ***       * ****   * * *     ***
 ** *   ****  ** **   ** *  * * ***  ****    **** **     ***   *  * * * is a prefix of %s",p,s);
* ** ***  ***   ****   ****
     ***  ***  **  **  * *  **  
 *  * **  ** *   ***   ** ****   ***  * ***    * * ** **** *  ******  is not a prefix of %s",p,s);
**** *  *****  *** * *        *
* * **** *   *  *** * * ****   **     0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.9k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users