1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  * ** **** *** **
#include  ** ** ** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* * *  *** *  * *****  *    
 
  * **  * *   * * * ** ****    ***  ***** * *  *   * ***
*  *     ***   ** * **     ***
**   ** **  * * * ***** *  *  ***** * *** **** ***   * * ***** == s2[i])
*   * * **     *   * *** **   *    ******** ***  * *  
* *** **     ****   **   * *       ** **   * *  * *   *  * * *  *** **  **** ***   * 
**    ****** * **   **** * * ** * ******  ****   * *****   
 
  * ** ***  ****    * *  * ** *  *  **
 
  *  **   **  ** *** ** *   **         * *  == length)
 * *   ** * *   ** * ***  *  *  *  ** 
  *   *** *   **  *     ** *** * **  * * ** **      ** * *    ****      * * is a prefix of %s",s1,s2);
*    *  **   **   ***     * ******* *  *
 
 *** **  * ****    **    ** *** *******
*   ** ****    ***  *    * ** *   
  ***    *  ** ***   *  **   * * * ****  *** * **    **    ***   ** *   *   is not a prefix of %s",s1,s2);
 ** *  * ** ** **  * * * **** **    * *
 return 0;
**  ***** *  * ***** *    *   ** * 
 }

int main(void)
{
  **  ** *   ** ** * *   s1[100];
****    *  * * * *  * **        s2[100];
*    * **    ******  **** ** * i,j;
 * *    **   *  * *  * * 
   *    * ***  **** *  **   ****   * ** * ** ****   s1);
* *   *  *  * * *  **  **  ***    * **  *****      s2);
 *  ** *       *  * *** *  
** ** * *  ** *      * *   ** * **** *
 **** * *  *** * **      ** * *
 *** * * * * ***** **    * **     0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **    ** 
#include * *  * * * *** 

int prefix (char st1[],char st2[]){
    *  * * * **  *****   *    len=0, i, cnt=0;
*   **  * ****   ***  ** 
 *        ** ** * *  * *    = (unsigned)strlen(st1);
** * ** **  *   **   * * ***
******** * **  ****** * ******** (i=0;i<len;i++)
* *  *  * *******   *   * 
  *  ** * * *** ** (st1[i]==st2[i]){
 *     *  * **** ** ***** ** **  * ** *    *** * * ******   **   *  * *** *  *  *
*** *  * ** * *   * * *   *  **   **      *  * **** 
     *    **   * *  * ** ** *
*** ** *     *    **** *  **  (cnt == len){
* ** * *  **** * *  ****  *   ** ***   *** * **    ***** 1;
*  **    *  *  *****  *** *
*  ** ** * * *******    *
** **  *** **    *  *  *  * **   0;
* *  * **  * * * * ****   **
}

int main(void) {
  *** * ***  * * ** *     *   ** ** st1[256];
** ** ** ***  * ** * * **  * ** st2[256];
 * *  *  *** **** *   ** *    *  **  *   * * * *   **** st1);
  * ** **      ******   ******  *** ***  ** **   *  * st2);

   *  **   *   ** *     * *  * (prefix(st1,st2)){
* *  **  ***  ** **  * ** ** ** * *** * ***  * ***   ** ***** *  ****** is a prefix of %s", st1, st2);
   *** **   ***     * *  **  
*** *  * *   **    *****   
** *   *   ***  * *    ** ****  ** * * * *    * *  * ** * * * ** ** is not a prefix of %s", st1, st2);

**    * *** ** ** ** * *     0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  *  ****** *  * **   * **   **  ** * *  *    
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
    *  **  ** *  ***  * *  ** *  ***   *** *** * ***
**     *   *****  ** * ** ****   * **      *  ** * * * **** *     *    **** *  **  
  * **** * **   ********   **** * ****   *   *   *   * * **  * *  ***   ** * * ** ***  * * ** ** * * ****
***** * * ****     *** * **  * *   ** * * ****  * * *  ** *   *    ****** ****  * * *  ****** * **  *   **  ** * *** ** * ** ** *        ****  is not a prefix of %s",a,b);
* * ** * *   * *****  ** *   * * * * **  *  ****      *    *    ***** *  ***** * *    * *** *  **** * **  * * **   ***   * * * *** 
***        *** * *** *   * * ** * **    *  * *    *    * * **** * *   * **   ** *  *********  *  *  * 
 *** *   *  * ****    *   ****  * * ***   * *** **  * **  **  **** ***   ** *  **  *  
*****   ******  *** *  ** ***  * *    * * *   * **   *** * * * * *  ****** *** **  *    *  *    * **
 * ***** ****    **  **        *****  ***  *   *****  * **  *** ** **  * * *     **  ** * *       ***        *   * *    * ** * ***** *** *** **  *** is a prefix of %s",a,b);
* ***  **   ****     ***  **  ** **  *    **  * ** *********************   * ****  *  *    *** ***   **   *  * ** ********* *****  *** *    *
 ***  **   * ** *   *  **   * ** *  *     ***  **   *    * ** *  ***      *** * * ****  * ** ** * ***
*   ***** ***     * **   ** ** *  *** *  *   **  *    




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
    **  **   * * ** *  ** **      **  *    * 
** *   ****  *  ***    ** **  * *** *  *   *  **

*  **  * *** * *     *******   *** **    *****   * **  ***** * *   **    0)
 * *  ***** ** *   *   *   ** * *     *** **  *** * ***** ***  * ****  **  
  * *   *  **   * * *  ** ** ****  ******* **    *  ** ***** ** *     * *   ******* * ** ** *   ***** * ***    * *** *   * is a prefix of %s",pre,str);
* * *  ***  ******* *    * ** * ** * ** * *** **  *   ******  * ******
  ***  * *  ***    ** *      *    **    ** * ***  ***   ** 
****   * **   *    *    *****   * *   ***   ***   * ***** *  *   ** ** *** 
*      **** *  **  ** *****   *   * *   **   ** * **    *   **    **    * * **  *      ******** *  * *** *** *  *  *    *     *  * is not a prefix of %s",pre,str);
*** * ****    *** * **********  **  ****    *     **   **   ** *  ***    *    **  * * * *

**  * * ****   ***** ***   *    0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* * *  *  ** *** ** * *  *   * a[100];

***      * * ** * * ***  * *   **  *  b[100];

* *  ******  * **** *    *     * * i = 0;

** ** ***** *** *   *   * * * prefix = 1;

*   ** * **  *   ***  **   * ****      *  **   **** * a, b);

 **** *              **   **  len = strlen(a);

** *****  *   ** *   *    ****   = 0; i < len; i++)
   **** **  ** *  ***  ** *  ****
  *** **    *** * * * * *  *** ** ******  *  *   * * **    *    != b[i])
    *      ******* ****  *     ***   * **** * *****   ** **   ** 
 ** **   *   ** * *   * ** ******* *  * ***** ** ****    **  ** *  ****** *   ***  = 0;

  * *   **** **  ** *   *      ** *      *  *  *      *** * ** ****      * *** *** ***   *     is not a prefix of %s", a, b);

***         *  *  ***     ***     *    *  ** ** *     *  ***     * **  ***  **   * *   **  
  ***  *   * * *** ***    *** * *  **  * ** * * * * **     
 **** *    **  ***** *     **
  * ** ***  ****** * ** *** *   == 1)
  **** *** ***   * * * ***  
*     *** * *** *   ****   ** *** *    * * * *   **     *       *  is a prefix of %s", a, b);

*** * ** ** *** **    **  ** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** *****  * 
#include    ** ** ** * ***  *  

int main() 
{ 
 *   * *********     * * **  ***  a[100],b[100]; 
* **   ***   * * * *    * **  i,j,prefix = 1; 
 * **  * ** **** *     * *  *   *   * %s",a,b); 
  ****** * * *     *  *   len = strlen(a); 
 **  *** *  * *** * **  **** = 0 ; i < len ; i++) 
*** *****   * *    ***  **  
 *     *  *   *      **  *      * **   * * *    ** **** *        != b[i]) 
  *   *  **  ***** *   **  **   *  * ** *    *  **   
 *** ***  **  *******  ** *****    ** **  *** **  *** * *** * **  *     * **** ** ** **  * = 0; 
* * *    *  * * *  ** *      * **** *** *** ****  * *****  ****   * * ***  **   is not a prefix of %s",a,b); 
*********  * **    **** ***  ****     **  * **  * ** * *     ** * *** *** *   *  
**     *    **  * ** **** *   * **    * ** * *  * ** ** 

*** *** *****  **      *     
*  *** ** * ** ** *  * *  * * ** *   *  == 1) 
* * ***   * **** **          * ** *  **  ** **      ***** * *** is a prefix of %s",a,b); 

 
 *   ***      *  **  *** * *   0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** ***   **  * * 
#include     *****  ** 

int main()
{
** *    * **  **  ** ****** ****  a[100],b[100];
 ** ****** ** *  * **  * *    i,j,prefix = 1;
** ***** ** *****   ***     **** %s",a,b);
 **  ** ** ********   *****  len = strlen(a);
  * * * * *      * * ** *** ** **  **  = 0 ; i < len ; i++)
 **        ** *****  *    * ** * 
  *  *   **  *      **     **  *  *** * * **  * * ***** *   != b[i])
* * *   **  ** * * * * *  **  **** * *  *      * **   * 
* **  * *  *     ** *   **  ** * ***  * *  ****  *********** * *  * **  *  *    * * ** * = 0;
   **  * * *  * ***   *  **    **  ***** * *   *  **  * * *** ***** **    * ** * *   ***   * *   is not a prefix of %s",a,b);
*  **** ***** ****          *  ** ********     *  **  * **  * ***  ** * * *  *** * * * **
      **   **** *** ** ***  *      ***    * * *****

*  * *** *  ** ******   *
** * ** **  ***  *  *  ** **** *  * *  == 1)
*          **  **  **  ***   * **   *  * * * ***   ** *   **    is a prefix of %s",a,b);


*  *****  **** **     **  ***   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    ***  **  **
#include   * ***  *   *  

int prefix(const char *pre, const char *str)
{

 * *** ** *   *  * * * * *  *  **  ***    *   ***
**  *  **  * * ****** * ***    * * * * * **  *** *  ** *  **  0;
** *     *****  ** *     ***      * **** ** * **
****  ****  * *     * *** * **  ** ****  **   1;
 *      * ***  *   * **  * **     return 0;


}

int main()
{
 ****** * ***    ** * **  * * pre[100],str[100];
** **       **************
  *  *****   * ***** **  **** *    *     * *  *  *    *
  *** ** *   ** * **    *** ** ****
*** *    *** **   **    *  *    ** **  **** * ***  *        * *** is a prefix of %s",pre,str);
   *    ** **   **    ** ***  **  
*** * ****  *  ** ***  *** **  * * * **   ***   * * *   *** **** is not a prefix of %s",pre,str);
* ******** *  ** * ***  *   *  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**  * **** ** **     ******* c;
* * *  *  * * *   *    * ** *     **** * *** 
* * **** *** * **    * * **  ***   * ***  *   ** *  ***  0;
  * ** **  **   *   * 
*      ** **   ***  *******    **
 ******  **** *** ******  *    ***      ***       * * ****  * * *      **  of a string
* ** * * *****     **   ** * * **** *********  * *******    * * *      *** **  **   *    ****
*   ** ** *    **** **   * *  **    ** **** *  **  * *  * *** ** *  *  * ***  * ****** * * ** ***  ** * ******  0;
******* * * * ** *   *   * ***   ****     *    *** * * **  
 * ** **** ****  ***  ***  *  ***     * **   * ** ** *    1;
    }
}

int main(){
** * *  ** *   * **       a[100],b[100];
 * **       ******* *     * * *  * %s",a,b);
***  *** *  *   * **    * ****
* * * * ***** **  * *  **** **   *** * *** ****  * ******* *       is a prefix of %s",a,b);
  * *  **  * *** *  *  *   ** *** 
*** **  ***  * **  ** * *   * *  ** ****   *  **    **** *   ** **** ** * is not a prefix of %s",a,b);
 *  ***  * *     **  * **   * *  * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* **  ****      *****  **    ** p[100],s[100],a[100]={};
  ** **  ***   **  *  ***   **  t;
  ***   ****** * * ** *    *   * ** *  **
**  ***  ***  *       ****  **  ***  **  **
* * *** **   * *** ****    ** * * ***   * ** * %s",p,s);
** * ****   ****  * * * ****  **   * 
 * * *   ***   ***  **  *   ***
***   *   * *   * *  *******     ** ** 
 *  *   ** **      **    **  ** *  *** * 
*****  * * ***  * ** *   ****  *  * 
**   ******** **    * *   *   *  **** * * ****  ***            *    ** **  *   is a prefix of %s",p,s);
* * * **   * * **** * *** ** *
  *  * *    *    *** *  *  * * *
 ** * *  * * ***  *  **** **   * * **** ** * * *** *    *  *   is not a prefix of %s",p,s);
  ****   **  *    * ***
 * ***    ******      ***  *  * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 18.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 16.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users