0 like 0 dislike
8.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 8.7k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include * * *** * * * *
#include ** * * ** **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* * * * * * * ***
 
*** ** * * ** *** ******** * * ** * *
* * ** * * * **** **** **
** **** * ** * ** ** ** * ** * * ** == s2[i])
*** ** **** **** ** * ** * ** ******** * * ***
* * ** ** * * * ** *** * ** *** ** * * ** *** *** * ** ** * * **
* ** *** *** ** * **** * * ***** ** **** * ****
 
**** *** * * * * *** * * * *
 
*** * * * * * * * * * * * * == length)
*** ** *** * ** **** *** *
* * * * * *** *** **** * **** * * *** ******* * **** * * is a prefix of %s",s1,s2);
*** * * * * * * * *** *
 
* ***** * ** ** ** * *
* ***** *** * * ** ** * ** *
* ** ** ** * * * **** ** * **** *** * * * ** * * *** *** * ** * is not a prefix of %s",s1,s2);
* ** ** *** ******* **
 return 0;
* ******** * *** * *** * **
 }

int main(void)
{
* ** * ** * ** * ** ** * * s1[100];
* * ** * * * * * s2[100];
*** ** ** * ** * **** i,j;
*** * *** *** * * *** **
* *** * ***** ******* * ** ** s1);
* * *** * **** * ** * **** * ** **** s2);
** ** * ****** *
* **** ** *** ** * * * * *** * *
* * ******* **** ** *
* * * **** **** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * * *****
#include * * **

int prefix (char st1[],char st2[]){
**** **** * * ***** * len=0, i, cnt=0;
* ** * ***** * *
** ******* ** ** * ** = (unsigned)strlen(st1);
* * ** * * * ** * ***
* ** * * *** ** **** ** ** (i=0;i<len;i++)
* * * * ******** **** * *
* **** *** * (st1[i]==st2[i]){
* *** * * * * **** **** * * * ****** ******** **** *** *** * *** *** * ** **
** * *** * ****** * * * ** * ***** ** *
* **** * * *** *** ** *
* * * ** * * * * ** * (cnt == len){
**** * ** * *** ******* * * ***** * * * ** 1;
* ** * * **** * * * *
* **** *** ***** * *
* ** * ** **** ** * * * * ** 0;
* * ** * * * * * ** ****
}

int main(void) {
** ** ** * *** ** * * **** st1[256];
* * ***** * ** ** * ** *** st2[256];
***** * ** * ** * ** * * * *** * *** ** st1);
* ** *** ***** **** * * **** * ** st2);

* ** *** * * * * ** ***** (prefix(st1,st2)){
* * ** ** * * * * ** * * * * * *** * * * * ** ** * * is a prefix of %s", st1, st2);
* ** * ** * *
** ** * * **** ** *
* ** ***** * ** ** * * * * * ***** * * * * * * * * ** is not a prefix of %s", st1, st2);

** * * * * ** * ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** * **** * * * * * * * * ** * **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* ** ** * ***** * * * **** ** * **
** ** **** * * ** *** * ** *** ** ** *** * * ** ** * ****
** * ** *** ** * * * *** ** *** ** ** ** *** * * * * * * ** *** * **** * * *** ** * * ** *
* * **** ** * ******* ** **** **** **** * * ** * * *** ** ** * ** ** * * **** ***** *** *** * *** * * *** ** *** is not a prefix of %s",a,b);
* * *** * ** ** * ** * * * *** **** ** *** ** * * * * ** * * *** * ** ** ** ** ** ** ** ** ** ** ***** *** ** ** * ***
* * ** * *** * ** *** *** ** * **** ** ** * * ** ** * ** ** * ****** ** * *** ** ** * ** * *
**** **** ** * *** ** ** ** ** ** *** ** ******** * * * *** ** * **
* *** *** * * ** * * *** ** * * * ** * * * * * ** * * * * ** * ***** ** * ** *
* * ** ** * ** ** * ** * * * * *** ** **** * * **** * ** *** * ** * * ** ** ****** *** * **** * * ***** * **** **** * is a prefix of %s",a,b);
* ****** *** *** ** **** * * * ** ******* * ** * * ** * * * **** ** *** ** ** ** ***** * *** ** * * *
****** ****** *** **** * ** * ** * **** *** ** *** ** * * * * * *** * ** * *
** * * * ** **** * ** ** **** * ** * * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
****** * * *** *** * * ** ** ** ** * *
**** * ***** *** * **** * ** *** **** * * ** *******

* ***** * ***** *** ** * * ****** * * ** * * ** ** * * 0)
**** *** * ******** ** * ****** * ******* * **** **** *** ** * * *
** **** ** * * ** **** * * * * ** * *** ** *** * * * ***** ** * * ** * ** ** * ** ** * *** * is a prefix of %s",pre,str);
***** *** ** *** ** **** * ** * * * * * * ** * ***
* * ** * * * * *** *** *** ** * * ** * ** *
* * ** * **** ** ** ** ********* * * * **** * *** *** * * **
** *** *** ** * ** ** * **** *** **** *** * * * * * * * * * *** ** *** * ** ** ** * ** * is not a prefix of %s",pre,str);
***** * ** ******** *** * *** *** *** * ** * ** ** ** *** ** * *

* ** ** **** ***** ** ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**** ** ** ** * ** a[100];

* *** * ** * * ** *** ** b[100];

* * ** * * **** ** * * i = 0;

* * * * ** **** * prefix = 1;

* * * ***** ** * ** ***** * a, b);

***** * ** * **** ***** len = strlen(a);

** ** * * *** * * * ** *** = 0; i < len; i++)
**** * **** *** ****
** * ** * * * * ****** ** ** * ***** * != b[i])
* ** ** ** * * * *** *** * * ** **
*** **** ** * ** *** **** *** ** * ****** **** * *** * *** * ***** **** = 0;

* ** * **** * ***** ***** **** **** * * **** * *** **** ***** ***** *** *** is not a prefix of %s", a, b);

**** ** * * * * ** * * ** ** *** * ** *** ***** * * * ****
*** **** * * *** *** ** ** ** **** ** **
** ***** **** * ****
* ** * ** * ** ** * * * ** == 1)
* * * **** ***** ** **
** * ** ***** * * ** ** ** * * * * *** *** is a prefix of %s", a, b);

* * ** ** * * * ** *** **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * *****
#include ** * * * * * **

int main()
{
** ** ** ** * * * *** * a[100],b[100];
** * ** * ** * *** * ** * i,j,prefix = 1;
* ******* * * ** * ** * **** ** %s",a,b);
* * ** * * * * * len = strlen(a);
**** * ***** * * * * * * * = 0 ; i < len ; i++)
********* *** * ** * *
* * ******** **** *** ** * ** ***** * **** ** != b[i])
* * ** ** * **** **** **** ** ** * ******
* * * ** * * * *** * * * ** * ** * **** * * * * * *** * * ** * * = 0;
*** * * * * * ***** * * ** * ********** * **** * ** **** ** * is not a prefix of %s",a,b);
** * ** ****** * * *** * * *** ** *** * *** * * *** *****
* *** * *** * * * ** * *** * ***

** * ***** * * * *
* *** * ** * * **** *** == 1)
* ** **** *** * ** * ***** **** * *** ****** * **** is a prefix of %s",a,b);

 
* * *** * **** * ** 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** * **** * * * ***
#include * **** * ****

int main()
{
* *** * * **** * ** * a[100],b[100];
** ** ** * ***** i,j,prefix = 1;
** * * * ** ** *** * ** **** * %s",a,b);
**** ***** * *** * * * len = strlen(a);
** * *** * * * ** * = 0 ; i < len ; i++)
* * * **** * * ** *****
**** **** * * ** * ** *** * ** * *** ** * != b[i])
** **** ******* **** * **** * * ** ***** ** * ** ** *
** *** ** ** * **** ** * * ** * ****** * * ** ** *** * * = 0;
*** * *** * ** ** * ** * * * ** *** * ** * * ** **** *** ********* * * * * is not a prefix of %s",a,b);
* ** ** *** ** * ** * ** * * * ** * **** **** **** * * **** *
* *********** * *** **** * * *** * **** *

* * * * * * * * * *** ** ** *
**** * ** * * * ** * ** *** == 1)
* * * * * * * * * ** * ** * ** ** * * ** * is a prefix of %s",a,b);


** ** * ** ** ** * * ***** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * *** **
#include *** ** ** *

int prefix(const char *pre, const char *str)
{

* *** **** * * * * * *** *** * ******* * ******
* * * **** * * *** ** ** *** ***** *** * 0;
** * * * * ** *** * * * * *** ** **
*** * * *** **** *** ** * * ** ***** * **** * * 1;
* ** ** * ** ** ** return 0;


}

int main()
{
** ** * * ** *** pre[100],str[100];
* ** * * ** **
* * ** ** ***** * * **** ** *** ** *
** * * * * ***** ********* * ** *
* * ** * *** * ** * * * ** * * *** * * * * ** is a prefix of %s",pre,str);
*** * * * * ** * * * * *
* * * ***** * ** ** * * ** * * ** * *** * * * is not a prefix of %s",pre,str);
* **** **** * ** * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* * * ** * ** ** ** c;
* ****** * **** *** * ***** ** *** * ****
* * * * **** **** ** * * * * * ** *** * * ** ***** 0;
** * *** * ** * **
* ** ** *
*** ** *** ** * * * * ** **** * * * * ** * * **** * **** ** * * * of a string
* * ****** *** ** **** * ***** *** ** ***** * ***** ** * * * *****
* *** * * ****** * * *** * * * * * * ** * * *** * * **** ** ** * ****** * ** ******** * 0;
* * *** * * * ** * * ** ** * ** * **
** ** ** ** ** *** ** * * ****** ** * * ** 1;
    }
}

int main(){
****** * ******** *** ***** a[100],b[100];
* **** * ** ***** *** ** * %s",a,b);
**** ******** *** * * * **
** * ** ** * ** * ** ** **** *** ***** ** ** * * **** *** * **** * is a prefix of %s",a,b);
** ** ** * * ** *** * ** *
* ***** *** * * * * * * ***** * * ***** ***** ** is not a prefix of %s",a,b);
** *** * ** ** **** * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * **** * * ** p[100],s[100],a[100]={};
* ** **** * * ** *** *** t;
** ** *** ** * ** * * *** * ****** **
* *** * *** ** * ** * *** *
* * *** ** * ***** * * **** %s",p,s);
* * ** ******** * ***
*** * * * ** * * *** * ***** *
* ** ******** *** * ** *** * * *
*** * ** * * ** * * ** * ** ********** * *
****** * ** * * ** * ** ** **
** *** **** *** * * ** * * * * ** * ***** ** * is a prefix of %s",p,s);
**** * * * * *** ** * * **
* * ** * * *** * *
* ** ** * * ** **** * ***** * * * * *** * ** is not a prefix of %s",p,s);
*** ** ** * *
*** ** * ** ** ******* 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.99
©2016-2025

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 12.7k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 8.5k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 11.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users