1-11 Exercise 3: Prefix of a string

Question

9.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited Jan 11, 2018 by semicolon | 9.9k views

27 Answers

Page:

Diyiel · Answer 1 · 2018-01-13 00:58:32

Hidden content!
#include *  ***  * * * * 
#include     **   *** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
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** ******  ****** **  *    ** *****  
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* *** *   ***    *  ** *  *  *        
 }

int main(void)
{
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* ****  ***     **** *  *    s2[100];
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}

answered Jan 13, 2018 by Diyiel (-193 points)

Stephen Richards · Answer 2 · 2018-01-13 00:46:20

Hidden content!
#include ****** * *      **
#include  * **  * *   ** * 

int prefix (char st1[],char st2[]){
*** ** ***   *   ** **    len=0, i, cnt=0;
* *  ** **      *    ** * ***
  ** * ****  ***   **  *  = (unsigned)strlen(st1);
*** **** ** * * **    *******
  ** ** * *  *******   *   ***     *  (i=0;i<len;i++)
* *  ** ** ** *****      
 *  *  **  * *  *  (st1[i]==st2[i]){
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    *  ****    * **   * *   * **     *  *     
 *****      **  * **  * **  * *
 *   **     * *** * * * * ** (cnt == len){
** ** ** * *** * *******  ****     ***    **   **  1;
 *   **   **  * * ****  ***
  *  ** * * * ****  *    ***
*      ***     ** *     *   *    0;
 *   * ***  *  *  * * **  
}

int main(void) {
 * ** ***  * **  **   *  ** **   st1[256];
 **  *  *** ***   *  * ** *  st2[256];
 **   *  **  ** *   *  ** *  *** **  ** ********* *        st1);
** **    * ** **** *   ******  * *** * ***   ** * st2);

 * ***       ** **     **   (prefix(st1,st2)){
    *****  **   ** * **   *   **** * * ****      ****  ***  *  is a prefix of %s", st1, st2);
 *   **** ****    ** *  *  *** 
* * *  ***  * ***    *** **** 
 **   **** *** **  *** **  *   ** ****  *** *** *****  * * **   is not a prefix of %s", st1, st2);

  *****         ** *   ** * * * 0;
}

answered Jan 13, 2018 by Stephen Richards (323 points)

ryan · Answer 3 · 2018-01-11 22:07:28

Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *** * *  *  ****  **** ******   **    * **    *****
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
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** * **  *  *** ** * ***  * * *     *** * * * * *  *




}

answered Jan 11, 2018 by ryan (-301 points)

Headshake · Answer 4 · 2018-01-11 21:22:34

Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
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 *  *  *  * *       ** ****   **** **       *       * *    ***** *   *  * ** *    * **

*****  *** * **  * *** * * 0;
}

answered Jan 11, 2018 by Headshake (-281 points)
edited Jan 13, 2018 by Headshake

Sabrina Lin · Answer 5 · 2018-01-11 21:03:22

Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 *  ****  **   ** *   * *** *** a[100];

  *  * **** **  ******  ** *  b[100];

* * * **** * *     **   **    *  i = 0;

  ****  ***** * **** * * * * prefix = 1;

    * *  **  **  *   *** * * * *  *****   * a, b);

*    * ** **** *    **  * * len = strlen(a);

**   ** ** * * *      * *    = 0; i < len; i++)
   * *  * *** * * * ** ****
 * * * * **  ** * * ********* **    *** *  *** *** * ** **** *** != b[i])
  ** **   ***  *      **   ***  *    ** * ***   **** **
 * ***  **          * * * * *  *   ** **   * *  *    ***    *   *  * *      ** = 0;

*  **  *   *  ***     **  ***** * ******** *     *  ***    * **   *** ** ** ** *   **  * * ** is not a prefix of %s", a, b);

******* ***   *  * ***    *   * ***  ***** *   **     ***  *   * ****   **      
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* ****    ** *** ** ** *   *     
*** * * * * *** * ** *   ** *  *******  *  ** * *  *    *   * is a prefix of %s", a, b);

   *****   *  * *   ** ****   
}

answered Jan 11, 2018 by Sabrina Lin (-285 points)
edited Jan 11, 2018 by Sabrina Lin

watty1998871108 · Answer 6 · 2018-01-11 21:00:46

Hidden content!
#include  **    * ***** 
#include   **  *  *** *   **  

int main() 
{ 
**  * *****    ****   * a[100],b[100]; 
***   **** * *  **  * * *  i,j,prefix = 1; 
**    *****     *   * **** ***     %s",a,b); 
 ** * ** **  * **** ****** len = strlen(a); 
** *    * **    ********    * = 0 ; i < len ; i++) 
 *   *   *      * **  **  
 **   *  ***    *  **** * **    *   ** **   ***  ***  *  != b[i]) 
**   * *** *  *******   * ** **   * *     *    * *  
*  **** * **   **     *    ***** *   ** *   ** *   *   * * ***    ** *  ********  = 0; 
*   ** ** *   *       **   **      * ** ***   ** * * **  *  * * * **** *** *  ** ** * *  is not a prefix of %s",a,b); 
***** ***    **  ** **** *   **   *  ** *** ***    * * *** ** *  * ***      * * * 
  * ****** ** * **   *  ** *  * * *  ***   *** *  **** ** ** 

**** * **  *    * *  ** **** *** 
**  *******      * ****      * == 1) 
 ******  **  * ****  *   *  ** ** *******  * *  * * ** **** ** *** is a prefix of %s",a,b); 

 
 ** **     * * * * ******  0; 
}

answered Jan 11, 2018 by watty1998871108 (-127 points)
edited Jan 17, 2018 by watty1998871108

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

Sammi0208 · Answer 7 · 2018-01-11 21:00:08

Hidden content!
#include <stdio.h>
#include  * *    *    *
#include  **   *** *   * 

int main()
{
  ** ****  **   *** * * ** ***  ***  a[100],b[100];
 *  * **  ***  * *  *  * * * i,j,prefix = 1;
* **  ** * ** * *  **  *     *   **   *  %s",a,b);
  * *  * *  ***  ** * * *** *  len = strlen(a);
**  *   *****  * *** * * * * *  **  = 0 ; i < len ; i++)
*    ** *** *  *    **      
* *    ***   **  *  *  * *   ****  **  **** ******  *    != b[i])
*    ** * **  ** ** * * *   * *    ** ***    *    * 
*** *** ** ** *** ******* *   * *  **   *  *      * ******   * ***   **  **   *  *** *  = 0;
* * ***** * ***    * *  *  *  * ***** *  ** *     *     * *  * * ***  * * *   **  * *    ** **  * is not a prefix of %s",a,b);
 *  ***  **** * ** * ***  ***  *   * *  * * **** ***  *   ** * *****  *** **  * ** *
 *   *   **** * * *       * ** *  *****   **** 

*  ****  * * *     ** *    *
 *  *** ** **** **        * **  ** == 1)
* ****  *   * *  * *  *  *  *   ** ***** ** ** * ** ****     **  **   is a prefix of %s",a,b);


**     * * * * **    *    ** **      0;
}

answered Jan 11, 2018 by Sammi0208 (-255 points)
edited Jan 11, 2018 by Sammi0208

410530022 · Answer 8 · 2018-01-11 20:46:02

Hidden content!
#include  *    **** * *
#include   *  * *** *  *

int prefix(const char *pre, const char *str)
{

**   * **  **  ****   * * * *   *** *  * *      
 *****  ** *     **   *    *    * * * ********     *   0;
*   **      * ****    *       *** ** **   * *  **
***** **       *      * ****  *********  **  * ** * *    ** 1;
* *  * ***  ** *  *      **    *  return 0;


}

int main()
{
     ****** **  *  **  *   ****  pre[100],str[100];
*   * *  * ***  ** * ** 
* **    * *  * *  **    **  * ***  ***** *** *
  *  ***   ** ****  * ***  **   *  * *    **     *
* *   **   * **      **   ** **    ********    *  *** ****  ** *   is a prefix of %s",pre,str);
* * **** *  *************  *
* ****** ***   ** ** **     ******   ***  ***    *  * **** * ** * ***** is not a prefix of %s",pre,str);
  ***  ****     *  *  * **  0;
}

answered Jan 11, 2018 by 410530022 (-196 points)
edited Jan 11, 2018 by 410530022

LinJingYao · Answer 9 · 2018-01-11 20:28:50

Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
** *   * ****** *     ****  ** c;
 ****   *     *   **** ***  ***  * **  **** * *  
*** *   * *** ** * ** *   * * ** ****** ** * ** * ** * * 0;
 *   ** *  *** * * *   ** **
   ********* **  * *   * ***   *  
*  ** ** *   * ****  ****      *   *      *  *** **    * *      **    *** **    *  ** of a string
******** *  * ** **** * *    **  * * *     * *   *    ** *** ***  * *  **** *** *  *
***** *** *** ** **  *  *   * * * ***** * ***    *       *     * * *   * * *   * ****  *    *  *  * 0;
 ****** *     *  * *  **** *   ** *** * ** * *  *  * * * *
 ** ***** ***  **   *  ** *  * *** *  **      *   * **  1;
    }
}

int main(){
* ** * *     * * * *     ***   *   * *  * a[100],b[100];
     ** *  * *   **** **    **   * * * %s",a,b);
* ** *   *  * **  ****** * * ** **   *
*** ** ***  ***  **  **   * **  ***  *    **     *****  * *  ***  *** is a prefix of %s",a,b);
* *   * **   ** ***** *** *
   *** * ***** *** ****  * ****** ** *** *****  *  *    *   * * is not a prefix of %s",a,b);
 *  *   * * ******  * * *  ** * 0;
}

answered Jan 11, 2018 by LinJingYao (-498 points)
edited Jan 17, 2018 by LinJingYao

VincentXV · Answer 10 · 2018-01-11 20:05:37

Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * *  ** *     **    *    p[100],s[100],a[100]={};
*   *******       ** **   t;
* ***  **   ** * ** *  * **   ***    ** 
    ******  *****   * ** * *******  ***  * * 
**      *** *   * *** *  * ** *** * **  * %s",p,s);
*** *       * *  * **   **     **
  *** *   * * **  ** *  *    **  
*  *  **  **** **   *  ** ***   ** * ** **  
  ** **** **  *  *     * * * *      *    * ***** 
* *  ** *** *   * * *      *****  **
* **  ** * ** **      ** *   * *  *   *** * *    * *   ** * *   *    * *  is a prefix of %s",p,s);
 *  *  *  **** * *     *      
  * *  * ***** ***** **   * *** *  *  *
 ** * *  * *** *****    * **     *  * * ** **   **   * * is not a prefix of %s",p,s);
  ***     *   *  * *  *** ** *
  **  ***      ***** ****   *    0;
}

answered Jan 11, 2018 by VincentXV (54 points)

1-11 Exercise 3: Prefix of a string

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