1-11 Exercise 3: Prefix of a string

0 like 0 dislike
5.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   **    ** ***
#include *** *  * * **  ** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
******* *** *   ** *  ****
 
* * * *   ***** * **** ** **  ***  ****  *******  *** *
 ** **  **  **** ***       ***  *** 
**   **  *    * * * *        *     **  **** *  *  **** * * ***     **  == s2[i])
* **  *    *  ******* *  **  * ** *     **   **  *  
** *       * **   **** * ** * ** * * *  * *** *          ** * *****  * ****** ** ** ***
 **  *   **  *  ** **  *    ***     **  ** ** ****   *  **  
 
*      ** * ** *** *** * ****** * ** 
 
** * **** * *** **  *   **  *    *  *   == length)
* ****  * **    *****  ***  ** ** 
***   *  *  ***    ** * *** * ******  ***  ***  * *   *   ** **  is a prefix of %s",s1,s2);
*  *  * ** ** * *    *   ** **** * *
 
     * * **  * ******    *  ***** **  *   ** *  
 * ***   ** ***   *   ** **  *   
* ***   *    ** *  **    *** *   *  * *   * **   * *** *** ***** * *    **  is not a prefix of %s",s1,s2);
   **   * *  * * ***  ** * *   * ***
 return 0;
 ***** ** *   *       ****  ***  **
 }

int main(void)
{
       *** **    * ** *   **  s1[100];
  **     * * ***  * * * *  **  s2[100];
*   **         * **      **   *    i,j;
*       ***  *     *  *
 * * *  *     * ***** *** **   ****     **  * ***  *  s1);
*** * * *** **** ** *  *    *  * * *** *    s2);
 ** *   *  *   *  ** *******   ** 
* *** ** ****  *      **     * *****  * 
** *  **  * ******     * ** *
   * ********* **** *** * *****   **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     ******  ** 
#include ****** *  *  *

int prefix (char st1[],char st2[]){
*  *   * **   *****        len=0, i, cnt=0;
   ****  ** * ** * *  ***  
  * *  *    **  * ** ** *  ** * = (unsigned)strlen(st1);
* **  ** ** * **  **  * *
   ** * **** * ** **    *   (i=0;i<len;i++)
*****  **    **   ***  **  *
   * *  ** ***  (st1[i]==st2[i]){
  * * *  **  * *   *  **   **    **   * * ***  * *** *** * ** **   **  ** * ***  * *  ***  *  
 *   * * ** *** **     *    *  * * *   ***     
**** *    **   ***** *  ** * 
  ****   *  * * **  ****  *    (cnt == len){
  * *    *** *     ** * **     *   ***  *  ***   * ***    1;
 *  *  *  * *   **     ****  * *
*  * *   *  *    * * * **
 * * *****  ** ** * **  *    *** 0;
* *  **       * ** *  *  **
}

int main(void) {
 **   * **   *    ** ******  ******   st1[256];
   ** ***       *  * ****   * st2[256];
*   *  ***   *** *********    * * *** ** *  * ***    *  st1);
  **   ***  *  ** *  ** *  ***   **     **    ***   st2);

  ** * ** *    ** ** ** *  (prefix(st1,st2)){
  * *   **     ***      **  **  *   **   *   ** *  **  ***  ** *  *   is a prefix of %s", st1, st2);
**   *** **  *      *** * 
* *  * *   * **** * **** ** * * **
**  *  * *   ****** *  * ***  * **  ***   *   *** *  * *   **  is not a prefix of %s", st1, st2);

  * *** *   * ** *  **  * *  ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *  **  ****  **     *     ****  * ** **** **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
   * * *** * * **   **  ** *** **     **** * * ***  
* * * **  * ** *  * * ***    * * *  **  * * *** * * ** **** **    * ****      *
** *  * *      *  ***        **** *******   *  *  *  * * *    *** *   ** * **** ****  ** *  *  *  *   *  *
        *****  *  ***   ** ** * **********  ** * *  *** * * **  *  **   * *****   ** **   *       * *****  *** * ** *        *        ***  *   ** ** ** is not a prefix of %s",a,b);
*  *  * *** **   **  **** * *   ******        **    * * * ***** *        **   *  **  *  ***  * *   ******   *  * ** **   *** ** *  ***** * *   
* **   ****  *     *  ** **  *** * * *** *  * *  * *   * *     **  ****  * * *  **     **   *** *         ** * * * * ** 
 * **  * * *** *  ***   *  *******    * * *   **** ***  *****  *  * *** 
  **  * *  *  **   *  * *  ** ***  *  *     *** ** ** ** ****  ** *  **   ***  * **   *   **  *  * * *    *
** ** *** *** *  **** * *    * ** * *****      *****    **** **    ** *  ********  *** ***   *  *****  * **** ** *   * * *   * *   * is a prefix of %s",a,b);
 ****  ****  * *** ** *       ****  ***     * *   ** *  *     ******* **  * * * ** ** *  **** *  ** * ****   ******  ** * *** ** * *  ****  **   * **
*     *** ** *    ******* *  ***** ***  **  * * *   *   ** * *   ******* *  ****  * *** ****  * *   ** * **
  * * ** ***    ***   * * ** *     * * * **     * * * *  *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** * **  **  * ***     ** **     *  ** *****   
 * *  ***  *  * **  **** * * *** * *  **  *** * ** *** 

* **  * *   *** *  *   ** **  * ** * *  *  * ** ***    **  ****** * **  **   *  *  * **  ** 0)
 * *   *        *** ***      * *  ** ******    ****  *****   * * *  *
**** ****  ** **** **  *   *     * * ** * **** ** *  *   * *******   **  ******* * *  * **       *  ** *    *  ***  **   is a prefix of %s",pre,str);
*   ******  ** ***    *   *   ** * * **  *   ***   *** **** *   ****  ** 
* *   * *  **  * ***   *   *****   **  ********* * * 
  * *** *****  * **    **  * * **** * ** *   **** ***   *     * *    ** **  *   **
** *** * ** **    * * *  ***** ********    *      **  **   *   *  *  * **   * **** ***** * * * *  ***  *      is not a prefix of %s",pre,str);
  *** ****  **  *    * *  ** ***  *   *  **** ***      *      *   * *      

**    * *  *  * *  **** **  *  ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*    *    *****  ****   ****      a[100];

   **     *** **** ***  *  *  b[100];

   * ** **   ******* *****  * i = 0;

  **   **   ** *          *** *  prefix = 1;

*  *****  *   ** * ** * *   * ** * ***  *** a, b);

       * *   * *  *     ** * *  ** len = strlen(a);

*    **  ***** * ** ***   ** * * = 0; i < len; i++)
 *  ***** **    ****  ***  * 
 **    **   ** **     ** * **** ****     * *   **  **** != b[i])
 * * ** **  *  *** *** *** *      *   * * * *   ***  * 
* * *** *   * * *** **   * *   *   ***** ** ** * **   *    ***  * * * *    ** ** ** ** * = 0;

****    ***  **  *** * * *   *  **  **    *  * *  *  ** *     ******* * * ** **         ****** * is not a prefix of %s", a, b);

*  *   ****   * * *    *     * ** *  **  *   **** *  ***   **  *** * ****      
****   * * *  *  ***  * **  * **    ****  **  * ** 
* ** ******* ****  ***    *
*** *** * * **  **  **   * *   * * == 1)
**    ***** *********    **
**   **    ***   ** * **  **  * * *   *  *         **   is a prefix of %s", a, b);

 ** **   ** *** *   *   *    *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** * ******  **  
#include ** *   *  ** ***** 

int main() 
{ 
*********  * **  *     * * ** a[100],b[100]; 
* ***  *  *  * * *** *** * i,j,prefix = 1; 
    ***** ** ***  *   ** ***** *** %s",a,b); 
 ********      * ** *** len = strlen(a); 
*  *    ****  ** *  * ** ** *    = 0 ; i < len ; i++) 
*  *  * ** *   **   * *****   
 * ******* * * * ** **  * ** ** **      ** *  *** != b[i]) 
 ** ******** * *   * ******  **  *** ** ** **  *   *** 
  ** *  * **    *** * ***  * *  ***  * ** *** * ****  ** * *****   ***  *  * *  *****  = 0; 
** * ********* ***   *  *  ** ** ***  ***  * ***** * * *   * **** *** * * *   ******* * ** is not a prefix of %s",a,b); 
  *  * *  **  *  *****   ****** * ** * * * ** ** *  *      * * *  ***   **  **   *   * 
   *  *  **      *  ********* * *       *   **  ** **  *  

  * *  **   * * *  *  **** 
 ***** * **       ***  *   * ****  == 1) 
 *****       **  * ******** ***** *   *  *   **  *** ***    *  *   is a prefix of %s",a,b); 

 
 * ****   *  ***  * ***   ****  * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * ***    * *
#include  *  ***   * *

int main()
{
* *    *** * ** *  **  * *  *  a[100],b[100];
*** * * * **   **  *** *    **   i,j,prefix = 1;
*  **    *    *  ** ** ***  * *    * *   %s",a,b);
 *      *******  **  ** len = strlen(a);
* * ******* * * *** * ****  ** * = 0 ; i < len ; i++)
*   *** ***** * ***   *
 * *  *** * * *  * ** *  *  *  *   * ******** *     *** * *     != b[i])
 * **  ***   ** *   ***  *  * *     ** *   *   *
**  * *  *  * ** *** *  ***   **   *** ** *   ****** *  * *    ***  *   ** * *** * *** = 0;
 **  *****    ** *******    ****** *****    * *  ***  *     **    * * **  **  * *   *  is not a prefix of %s",a,b);
  **   *  *  *  ** ******* *  * **  *  * * **   *  * * *********    * ******  **** ***  
*  *****  *  ** **   ** *   ****  **     ***  * * *  

 ***  ** **    *  ***     *** **
* *  * * *** *** *   *   * *       == 1)
****    ****  *  *    *     *  *  * ** * *** **  *  ****** *** *        is a prefix of %s",a,b);


*  ****   * **     ** **  * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      **  * *** 
#include * *  ** ******  

int prefix(const char *pre, const char *str)
{

 ***  ** ** * ** ****  * ** * *****  *      * * 
* * **  * *** *** ***  **    **  *  ***    * * **  *      0;
* *  * ***    *     * ***  ** **  *  **** ****  *
    * ****     * * * *   *    * * *** *  *  ****  **   * * 1;
    *  ***    ***   **    ***  * return 0;


}

int main()
{
   ***  **   *     *   *** **** pre[100],str[100];
 * *  **** **  *    ***
 ***  * *****    **** *  * **   * ** *    * ******
 *  **   *   **  **  *****  * *   ***  *
**      *** *   * ** * * ********  * *  ***   *** * *   *  * * *    is a prefix of %s",pre,str);
*    ** ***        *** *  * **
* * * *  * * ******  * *    ***** *     * * ***       ** is not a prefix of %s",pre,str);
*   *** * *     * **     ***  *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*  ***** * **  **  * ** *   *****  c;
  ** *** *  *      ** * *  ***  *  ***** ** * 
** *  ** ** *  *  *  **   *  * * * ***  ** ** **  ****   **  0;
**** * ** ** ********* * *
   **   *  * ***  * *  ** ** * *
  **  * *** * * * * ** ***   *    *** **   *      * *   * **   *     **    * of a string
 *  ***    ****    *      ** * ***  * *****   ***   ** ******* *  *  ****    *** *  
****    ****  ***** ***     ** *    ***   * *  **  * *       *  ** ** *  **** **  *******  * *  **** ****  ****** * 0;
 * * ****    **       *     **  **** ***  **   ****
 *******  * ****   ** **  * * **** *   ***** *   ***  ***  1;
    }
}

int main(){
******   ** *   **  *** *  ** * a[100],b[100];
 ** **  **   *       * **  *    * *   *   %s",a,b);
  *****   *    ** *** *** ** * *  *
***  * ** *** *      ** ** ***        *   *** **** ****  *     * *  is a prefix of %s",a,b);
* * * ***      * *      * * * *** 
   *** * * *** * *** * **    * ***   ** *    **** *  * * **  is not a prefix of %s",a,b);
 ***  ** * * ** ** ***  *  *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***  **** **** **     * ** **** p[100],s[100],a[100]={};
 *    ***  *     *   *  * *****    t;
  *    *   *** ** ****** ******   * ***   * 
****    ** *  *****    * ** *  * ** * *  
*** * ** * *** *  ** * * ** *  * **     *  %s",p,s);
  **   ******  *  * * * * **** * 
*  ***  * ********    * *   **** * *
*** * *** *   ** **          *** *  ***
   **  *** *  *  ** *  * * * * **  *  *  * *  
 ****   **********  **     * * ** 
***  *** *   ***   ***   * *        ***   ** * * * *  ** *** **  *    *  is a prefix of %s",p,s);
  ** ** * *      ** *   * ** 
** ** *  **  ** * * ***** * **
* ** * ***  ** *    *  **** * **  *    * *** * ** **   **** is not a prefix of %s",p,s);
 *** * **** * * ** *** **    
**** **** ** *   **  *  *   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.51
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users