1-11 Exercise 3: Prefix of a string

0 like 0 dislike
4.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  *** ***  * ***
#include *  *** * * *****

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*    ** *   ****    *** * 
 
* * ***  *** **  *** *** ***    * ** **  ** *****  
 ****  *** * *   *  * * ***  **  **
  *  *   * ****   * ***     ***   * ***  **  * *    *  == s2[i])
 ** **     * *** **  *    *  **  * ****     * ** *   
  ****** *** * ** * *** *  ****  **   **  *  ** * *    **   *   *   * * *    **  **
 *** **** *  * ***     *  ** * * **     *   ***  *** 
 
  * *   * * * *** * ** ******  
 
  ** *  * *  *  **    * * *  ** **  * == length)
  **  *  * *** * *  *** *   ***
*  * **** * ** *****  * *       ***** **    ****   * * * ***    ** * *  is a prefix of %s",s1,s2);
      *  ** **** ***** *  *   *****
 
      * *** * ** *   ** *  *   * *
**  ** *  *   ** ** *  *  *    **** *  
   **** ** **   ** **   * *   *  * * * *  *  **  * **** * ****  *****   * * ** * is not a prefix of %s",s1,s2);
 *  **** * ****  *   **   *  * **** ****
 return 0;
******* *    ** * ***    ** *******  * *
 }

int main(void)
{
     **  *****      * ***    s1[100];
 *  **       *    **   * * * **** s2[100];
*******  *  **    ** *  **   * i,j;
***   **** ***     * **** 
**** * * *   ** **  * ** ******  ** *** * * * s1);
*** * **  *    **    *   ** ******* * **  *** s2);
 **    *  *  *     ** * ***
   ***  * **     ** *  * *    **  *  
         ******* **** * ***  **
 ** *      ** *  *   * *  * *****  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **   ****  * ***
#include *  *** ****     

int prefix (char st1[],char st2[]){
  ** ** **   * *    *** *     len=0, i, cnt=0;
 *    **  * ** *  ** **** *
** * *  * * * * ****** * ***** = (unsigned)strlen(st1);
*        * * ***  *  * ***
**      **           *  * ** **  (i=0;i<len;i++)
  *   *   *** ***** ***
 * ***   * **** (st1[i]==st2[i]){
   *   **** **  **  * ***** *  *   * * *   *** **    ** *    * *        ** * * *     **
 **    ***  *** **    ******  * *    * *** *   * *  
***     *   * **** *      *
 **** *  * * * *  * ***** * *  (cnt == len){
 ** * ****  **  **** *   ****  * ********** ****   * *    *    1;
***** *  * * **** **** *
* **  *  ****** **** *  *****
    * * * *  *** ***  * *    0;
  ***** **   *    * **    
}

int main(void) {
  * *  *     *  *  **  **  *  ** st1[256];
 *   * ***   * *** * *   st2[256];
 *  ****   ***  *   *   *  * ** *  *  **** **** * * *  st1);
 ** ** *  * **** **   ** ** *******  * * * * ** ** st2);

* **  *****     *** * *** (prefix(st1,st2)){
 *  ****   ** *    ** **  **        ******  ***** ** *    **** **  is a prefix of %s", st1, st2);
* *     ***  **   *  **** ***
     **  *  *   *  *    ** ** * * 
* * *   ** **   ***   *  * **  **    * **  *    * **  ** *     **  ** is not a prefix of %s", st1, st2);

 * ***** *  ** **     * **    0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 ** ***  **       * **  *** ***  **     ** ** ****** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
    *  ***** *       * **    ** **     * *    *  
  ** *  * *        *    *   ** *   **      * *** ** *  ***    ** * *** ***  **  **  * *****
***      ***  ** ***          ***  ***  * **    ** ** ***** ***     * *   ** **** **  ****  * *  **   *
 ***    *   *  * * ** **  *    ** **  *         * * ** **  * **** **** *    *     ***  **    * ** *  **  * ** *******     * *  *  *     *  *    * * is not a prefix of %s",a,b);
  *  * ** ***  *** **********      * ** *                 ** * ** *   **  * *   * **  *** * **    *      ** ** ** *  *  *****    *** ***  **
***** *        *      * * *****    *** * *    *    **  *  *  *  ***   * **     * * ***     ** ****  ***
   ****  **** ** **   ****   * *******    *** *   *   *  ***  *** **** **  *   *** 
   * **    ***  **  ** * **   *  *  ** *   **** * * ****  *  **  * * * *     *   *  ** ****   *  *****   *  * *
*    * *   *  ***** **  ** ** * **  **   * * **** * *  * ***  *  ** * ** *  *    **** * *** *    * * ** ** * ** * * *   *  ***** * **        * ** *  is a prefix of %s",a,b);
   * ********  **    *  ***    *** * *  *** ***  * * * *     *  * * *  *   *** **  *** * *  ***  * *  *** * *  *  * ***    *  * * *   * *   * *
* *  *  ** *  * ****   **** *  ****  ***   **     *****  * * **** *  **** *  *** ***** **  **      ** 
*  **  *   **   **  * **    ***** * **** *  * *   * *** *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*        * * * **  * *  * ** ** * *   * **  ** ** * * 
   * *     *   *  *  *** ****    * * *   

*  * ** ** * * * **   **   *  *    *  **   * *         *  *** **** * *  *     * 0)
 *    ******* **     **  ******  *  * **    * *** **  * ***      *      ** *** ** *  *
** ***** *   *** ***  *  ** *  **** ** * ** *       *    *** * * * * *  *  ******     * *** *** *** *     *** *  is a prefix of %s",pre,str);
 **    ** *    **** *****    **  **** *     ** ** * ** * **********  *   *
********* * ****  **  *      * *  ** **  **   ***  ****   
  ** *  *  * **   *  ***   *   **  *  * ****** *** *  ***  ** ** * * ****** *   ***
**  *  **  *  * **       ***** *  *   * **  *  *     ** *  ***  ***         **       ** *  *     *  *   **** * * is not a prefix of %s",pre,str);
* **  *  * ******   ** *  *  **  **  ******    * ** **   * **  ** ******* **    

*     *  * * **   *  * *** ** * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
   ***  *** *** * ***       * a[100];

  *** * * ***   *  ** *   b[100];

 *     *** *  *** ** *     i = 0;

*  **  * *   **   *** ***   * * prefix = 1;

  * ***    * **      ** * ** ** **  *  *  **** *  *   a, b);

* ** *   * *** ** **  * **   len = strlen(a);

  ***   * ** *  *     * * **    = 0; i < len; i++)
  *** *  *   **   *  ***   ** 
   * ***  *   **   ***  ** * *   * *  **  *   *  *  * *   != b[i])
 ** **  *  ******   *      *   * * **** ** ** * **    * ** 
 *       ** **  *    * * ****  * ***   * ****** ***         * *  * **** * *      * *  ** = 0;

* *   *  **** * *******   ** * * *   *   * ****  * ** * *      * *     ***  * *   *   *  **     **     is not a prefix of %s", a, b);

 ****     *    * ** ***  **  *****  *** ** ***     *    **  * *   *** **   * *       *  *
 **  ********  * ***   ***  **     *** *    * **  ** 
**  * * * ***    ****
***       **** * ****   *****  * * * == 1)
**** *   *   ****  ** * **  **
*** *  * ** * *** * **   *     ***  ****  **** ** *     ****   *  *** is a prefix of %s", a, b);

 * * * ** *   **   ** ** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * *****  
#include *** *    *  * **  

int main() 
{ 
*** *   *  * *  *** *  **  * a[100],b[100]; 
**  *    * *** * * ** ****   *    i,j,prefix = 1; 
***     **  **    *  **       ***  *  * %s",a,b); 
  ****     *  ** *  *  * *  *** *   len = strlen(a); 
 *  **  *  **** ***     **  *  * ** = 0 ; i < len ; i++) 
*   *   * * *** *** * *   * 
 ***     * * ** *  ** * * ** ** ** ** **       *   **  ****   != b[i]) 
  ** *   **   ********* *   *  **  *  ****** ** 
** ***** *  *     * **** * *  *****    ***** **   *   **   *  * ***** ** *  * ***  **** * ***  * = 0; 
****  **  * ***    **    **  *  *     ** *** ***  *  * *         * *** *     **   *   * ***** **   is not a prefix of %s",a,b); 
*   * * ***   * *****    * *  **  *  *   * *  **  *  * * *  **     * *** * 
*  *  * * ** *   * *   *   **  *  *  *** * *    ** 

   * * ** ***** * ** *  * 
*  *** * **  ** ******      * ****** == 1) 
***     * *****   **         *************  * ***  * *  *** * **   **  is a prefix of %s",a,b); 

 
   *  * *****    ***  * * *****    0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **** ****    * **
#include  *  **** * * * *

int main()
{
*   ****  * *   *  ****    a[100],b[100];
 ** *    * ****    * * * i,j,prefix = 1;
  * * *  * ****         *********   *** *** %s",a,b);
 ** *** ** *** *   *  **  len = strlen(a);
***** * *   *    *   * **  * *   * = 0 ; i < len ; i++)
 ****   * * *  *  * * ***  *
    **  *    **   *  * *    *   **** ** * **  *  * ** * != b[i])
 * ***  *******  * ** *  * ** * *     ** *  **** *  ** **   
* *  * ***  * *   * *    **** *** ** * * *  *  ***   **     * *  **  * *  * *  * **** * = 0;
* *  **   *  *  ****   *    *   ** ***  * *** * *   ***   *** ***** **  ****  **   **    * is not a prefix of %s",a,b);
  * * *  ****  *    ****   **  *  ** ** *  *   * *  ** * *** * **** ** * * *
 *  *** ***  ***  *   **  * * ***         **  ** 

* ** *  ********* **  *  **  
*   *   *  *  ****   **      * *  == 1)
 ** * ** * * ***  *** ** *   *** *  **  ** **  *  * *  *   * *** is a prefix of %s",a,b);


**  * *     **      *   **   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  *  ** 
#include  * **  *    * *  

int prefix(const char *pre, const char *str)
{

****  ****     * **  * ** ****   ** * * * *  ** ** **  
* * *** *        *  *** ** * *   *  * ****   ***** ****  0;
 * * *   * * ** **  *     ****** * **  **   *****    *
        *     * * * ** **  **    * * * *  *   ****   * ****  1;
 ** * * *   ** * ** ***    return 0;


}

int main()
{
***  *  ******   * ** **  *    *** pre[100],str[100];
*****  *  ****   **** *   
** * *   ** * *    ***       ** *    *   *      
*   ** * ** ***    **  ***** ****  ***      *  *
**  **   ** *  * ******   ** ** * * *  *  ** *    *   * * **    is a prefix of %s",pre,str);
   **  *** * **  **   *    
** **    **  * *   ***        *   *  **** * *** ** *  **    *   **    *  * is not a prefix of %s",pre,str);
 * *** ***    **** ** **  ** **** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 * **** *** * **  **** *******  c;
**   *** * *********  ***** * **** **  * * **** *  
***  *****  * ** *   *     *** **   ***  *** *** **   0;
 *** *   **** *  **   **
  ****  ** * **** * * ***  *
 *      *   **  *  * **  *** ** * ***  * ***  *** * * *** **   **   **  ** *****  of a string
***  **  * * **       **  *  ** ** * ** *  *****     *   ****   ***   *    **   ** *  *****
***  ***  ********* *  **** *   **    ** ***      **   ** *****   *    *** ****    ** *** *     * * * * * ** * **   * 0;
*   * * ****  ****  *  *******    * ****  * *  ** *** 
**   *** **    *** * * * *     ***  *******  ** **** * 1;
    }
}

int main(){
** *     *      ** *  ** ** * a[100],b[100];
*  **** ***   * * ** * *  *** *   *  *   * %s",a,b);
 ****  *  **     *   * * * ** **** 
****** **         **   *  *  **** *** * *  * *  * ***   **   * **  is a prefix of %s",a,b);
** **  *   * ** * **  ** * * 
*  **    * ** ***   **** * * ** ** *  * **   *   *  *** * ***  *   is not a prefix of %s",a,b);
  **     ** **** * *  *   *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
    ***    *** * ** ** ***  *   * p[100],s[100],a[100]={};
 *    * * *        *** *   * t;
    **      ** *  *****  * *** * **** * ****
* ***  *    **  * * *** *   ** * *  **       * *
 ** *    ** ** *    ** ******  *** * %s",p,s);
  *   ***  ***       *    ** 
*** ****   **  *  * *****  *   ****  * * 
 *   *****  **    *       *   * ** **  * 
 *** * * **  ** * * ***   *    *****   ***  *
***  *** *  ** ** ** *  ****  ** ***** ** **
  *   ** *  *    **  ** *  ***  * *  * * **  ****** **     is a prefix of %s",p,s);
  * ** *     *   ***   * ** 
   **  * *  **     *** *  
 *     ** ** ** ***     ****   * ** * * * *** **** ** *   *   * *****   is not a prefix of %s",p,s);
  * **** **** ** *     *  **
   ** *    * *  **  *   *  **  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.90
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 5.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 5.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users