1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   *    ** * *
#include **** * *     *   

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
  * ** ** * * **      *******
 
  *   *   *  **  * ***  * *    **  * ** * *** *  *
    **  *  *  ** *    *  **** 
   * ** *    *  **  *     **   ****      ***    *     ***   *  == s2[i])
   ****    **** **      *  * * ****  ******      * 
*  ***   * ** *   ******    ** *       *** * ***  *  ***  *       * *  *** * ***    ******
*     *   **      * * *  *   * ** *  *  *** * *   ** *
 
  **         **   * *   * **    * *  
 
 *  * ****    * *** * ** *   **  *   ** == length)
*  *** * * *  ***  ***   ******   **  **
 * ** *   ******  *** ****  *********     ** *   ** * ****   * *    ** is a prefix of %s",s1,s2);
  *   ** *** * *** **        **  *
 
** *      * **  ****  *****       **  *  ** 
** * ***  **   ****   **  * *     *   *
 *   * ** ***      * * ***   * *   **** * *  **  **    ****   *** *** * **  is not a prefix of %s",s1,s2);
* * * *** * ***  * **  **  ** * **  * **
 return 0;
     ** * ***  *********** * **** 
 }

int main(void)
{
*  *  *   **  *** *** * *   s1[100];
****** **** *  *   ***    *  s2[100];
*   * ** ****   **        ****** i,j;
 *  **    * *  *   *  ***   *
* *  ** ** * *** ***    **** ** * *   * ** *  *     s1);
****  ***   * *** **   ********     **    * s2);
  * * **  ***** ** 
 *** *****  *** *** * ** *******  
***  *       **  *   
**  ************  * *  **     0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **      *   **
#include ***  ***** *** ** 

int prefix (char st1[],char st2[]){
     **** **  * ** ***   **** len=0, i, cnt=0;
* * *  *  *** *  *   * *  **
 *  *****  ** *** * ** **  * = (unsigned)strlen(st1);
** *** **  *  **   * * *    *
   **  * *    * * *  ***** **  (i=0;i<len;i++)
    ****  *   *     *  *  *****
  * *  ***    (st1[i]==st2[i]){
  * **    *  **  ****  *** * **  *    * ** **   *** *  *  *     ****        **   *
***    *   * * * ** ******   *  * *** *  **    * *  *
*  *  * ** * ******* * * *  
    * * * *   *   ** ** * (cnt == len){
* ** *** **  **   *  ***  **  *    **   ** * **          *   * 1;
  **   * * ** * *      ***  
**  **  ** * ****  *** 
  **  *   *  *  * ** * *  ***   ** 0;
 ** ** *     * ** *   *  ****  
}

int main(void) {
**    ***    ****   ****    st1[256];
*  ***  *   * *** **   *   st2[256];
*  **    ** * *****  ** * * ** * *   * ** *       * ** * st1);
*  * * ** ** ******  *  ** ** *   * *  * * **  st2);

 ** *   ** *  **  ********* (prefix(st1,st2)){
****   ** * * *** * *   * *     *  * *** * ***  *   *  * ** ** ** is a prefix of %s", st1, st2);
* *  ** *  *** * *   **** 
 *   *** ***    * **** ***** * *  
  *  ******  * ***   **    * *** * *** *** * *  *    *   *  ***  * * *** *  is not a prefix of %s", st1, st2);

**  ** ***  *    ** *   * ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
***  **** *  ** *******  *    * *** * * * ** * * *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 *  ** * *    * * *  *** ***  *** * * ***** *  * * *
* ****      *    ****   ** *** *   * * *****  ** ******* *  *   * * * **  ** *   * 
 **  **  **  **    ***  * * ****   **** **     * ** ** *  ****     * **     *      * *    ** *      **** **
  *   ********  ***   ***  ** *  ****  **  ***  * ** * ** ** *    ***  * *     *** * ****  ** *** ** **  * * **  * ** **  *  ***    * ****  ** *  **   *  * is not a prefix of %s",a,b);
 *     **  * *    ** *   *****  *     ***  ** ** ***** *   *  *** * ************ *****        *   ** *** * *** * * **   *  * **   *  **      ** 
* * * **    *  *    *** ******     **   * **   *****       ***    ******* ** **   **   *    *** 
   *  * * ****         **   **    *  **** ***    *  * * ** *    ** ***   ***
* * * *  *     **   **  * * *   * *****  *     * ***   **    *  *  **        ** **** *    *     * ** * * *
* *    *    **    * **   *    *    ****  *   * *  ****** *  **   ** **    ** * **   *      **  *   * ***  * * * * ******   * * * * *** * *  **  is a prefix of %s",a,b);
**   * * * * * **  * *     ** ***    **** ** **    * *  *     *  *  *********   *  *  **  * **** *  *** * **   * **  **   ***   *    * * 
***   *    * *    * * ***** *   ** **** ** * ***      * **  ** **** ***** **  * **  *** **** **  *   * ***    
* **  *****  * * **  * *    *  **     ***** * ** * *   *     




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
  ******  *   * *** *****  *  *  *  **  ** 
** * **  * ******* ** * * ****  *   **    *   ***  * *  

*     *  ***** **  ** **   *    **   *****    **** ***  *   ** *   *   *** ** 0)
**   ****** *   *** * *  * *  ***  ****  *** **    *** *       *    ** * * ***
* **  **  * * *** *** *** *     **  ** * *   *    * *   *    *         *   ** ****   * **** ****   *  ** * ** * ***      * is a prefix of %s",pre,str);
***    **  *      **    *    **   **    **    * *** *  *   *******     
*  * *   * ****** *** *    ** * *   **   * ** ** * ***
 *  * ******* *   ** ****  **  *** **     ***  * * *  *** ** ***     ** * *    **    * *
* *       * * *  ** ***  ** *      * **  ****   ***  * *    * * *    ***    * ***  **  ** ** * *** **     ** ** **    * is not a prefix of %s",pre,str);
 **  ********   * ******* ** **   ****   * ***** ****   ** * * *  *  *    * ** * 

* * * * **** * ** *  *     **  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
  **  * ****      **   *   a[100];

  ** *   * ** ** *    * *  *   b[100];

 *     ** ** *  *  **   i = 0;

  *****    *********  *   ** * prefix = 1;

 ** *     ** *       * *  **  *** **  * ***** * a, b);

**** * **   ****  **   ****  ** len = strlen(a);

  ** *****   ** *   *  **   **   *  = 0; i < len; i++)
** *** * *** * ****  *  *    ***
*** ** * * *** *** ***** **    **  *  ***** *  *  ***  ****  != b[i])
 *  ***  *  **   **** *   ** ***    *  * **    *     
** ***  * * **** *   ****     ***  * * * * * **  ** ***  ** **   ***   = 0;

  ***    **  **  * ***  **** **** **  **   **  *  **     ****        ** **  *   **  ******* * ***    is not a prefix of %s", a, b);

   **   *** ** *  **  *      *  ****  *  *   *   ** ****  ** ** *  ** *  **** **** *  *
  * *      *** * *  ***  *  ** * *** ** ** **  ** * *   *
* *****   **** * *  *   
** * *** * * *    ***  ***** ****** * == 1)
***** *    *     *     *  
*******  ** ** * *** *  ************  ***  *** * ***  *  *** *  *  is a prefix of %s", a, b);

*  ** * *** ***** **      
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * ***** *****  
#include   ****  * ***** 

int main() 
{ 
***  **** * *  *  * * *  ** *   a[100],b[100]; 
 * *   * ******  *  *  *   i,j,prefix = 1; 
** ***  *      ***** ** *** ***   *****   %s",a,b); 
 *  *  **** *   **       len = strlen(a); 
** *    ***  *** ** *****       = 0 ; i < len ; i++) 
 * *** *** *  *   *  *      ** 
**** **   * * **  *** * ***         *  * * ** ***  *    * != b[i]) 
     ** * **    * ** **  *    *  ******* *  ** **   * 
* *** * *    **  **  *** ** *  **  *** ** * *   *        *  *      *    * ***  ******    = 0; 
* ***  * ** * * *  * *     ** ** **   * * * ** * *   **** *  ****** **  ** **   * * * ****      is not a prefix of %s",a,b); 
*  * * ** * * ****  *  **       **  * * ***  **    * **    **    **   ***     ****  ** 
* ***    * *** **  *  ****** ** *** * *    **   ******* 

   * ** *  * * ** *   *  ***  
* *** **  ** ** * *  ***  **     ** == 1) 
**   * ****  *   ****    **   *** ***     ** ** ***** *** *** * * is a prefix of %s",a,b); 

 
* ***** *     ***  * **  *  * *  *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  *****  *  
#include   ***** ** *** **

int main()
{
 *  * * *  *  * *   * **** a[100],b[100];
**   *     **********  ****  i,j,prefix = 1;
*  * ***   **   *   *  **  **  *  %s",a,b);
* *  ** * **  ** ** * ** *  len = strlen(a);
** * * * *  * **** *     * *   *  = 0 ; i < len ; i++)
   * **   **   ***  **
**  *    **** *   ****     *   *  **  ****     ***  != b[i])
 **** **    *  ** **   * ***** *** *  **  *** *  *
 *  *  * *** **   **       *  **  ****  *    ** *** ** *  ** ****  *    * * * ** = 0;
  *  **  **  *  **  *** ***** * **   *  ** ***  ** ****   **   **  * **     * **     ******  is not a prefix of %s",a,b);
 *    *    *    *  * *   ** ***  * ***     *  *** * **** ***    **** **    **    *  ***  *  ** 
 *  *  ******  *  ****** ****   ** *  **  * *   *  * *  *

 ******   **    *   **** 
******   * **   **  *** * *  == 1)
***   **** * * *     ***  * ** * * **    *   ***  * * * ** *  is a prefix of %s",a,b);


* * ***    * * *     *    * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** ** ** ** 
#include * * ***** ***   

int prefix(const char *pre, const char *str)
{

 * * *    ***     *  *  ******  **   ****    * 
**  *   **  * * ***  *  * ***  * ** **  *** * ** * *  0;
****   **     * ****  *  ** **** * ** ** *   * * ***  *
 ****  *   *  *** *   * * ***** *   * *  * *  ** ****  *** **  1;
**        * ** ** * * *     **  return 0;


}

int main()
{
  * **  * ** * **  *  **   *  * pre[100],str[100];
 ****  * **  *    
  ***** * * *   * * *  *    ** ***  ** *** ***  *****  
     **  ** * ***** ****** * *   * **
   * **** ***     ** **   ** *  * ******** ** * ****   ***** * **  *  is a prefix of %s",pre,str);
*** **** **  * ** ** **** ***   
 * ** * ** * *  *** ** ** * *** * * ** *  **  *  *    ***   ** * * is not a prefix of %s",pre,str);
* *** **   **   ******  **      0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
   ** **** **   * * ****   * c;
**** * **  * ****  * *    *****  * ****    * *     
*  **  ******     ** *  **  *    *    *****   **** *    0;
 * * **  ***** ** *   * * ** *** 
*   * * * *  * * *    **      **
* **  *  ***    *  *** * *    *** **   *    * ***     ***    ** *** ** *    *****  *    of a string
    *    **  **** ******** ** *  *   ***  ******    *  *********   **** *  * *      *  ***   *    ***
  * * *** *  * **  **   ****   * **     *  *   * * ** **  **  ** ***** *     * *** ** * * ** *  ** *  * **    **  0;
*   ** *  * *   ***   *  ***  *  ****  ** *  * ** ***** * 
 ** ** * **  *  *   **     **   * ***     ** * * *   *** 1;
    }
}

int main(){
**  ** * **      *** * *   *     * a[100],b[100];
*  * ** *  ****   *** *   ***** ***  ***   %s",a,b);
   **    * *  *   ***********  **  *** 
 *   *** ***  ****  ***  **  *  **     * ** **   * * ** **** * *     * is a prefix of %s",a,b);
   **** *      **** **  ***   *
  ** *    ** * **    **  *    **   ** ** ****    *** **  **     ***  is not a prefix of %s",a,b);
 * * *** *** * * * **  * *  * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
    **** *  ** ***  ** *** p[100],s[100],a[100]={};
*  *  * *  ** *   * **  *  t;
*       *     *     *  ** *    *     *** ** 
 **  * * *  ***  **  ** * ***** * *   **   *
* ********    *   *  *  **  * **   *  * *  %s",p,s);
*  ***   * * ** **  *   *        *******
***  ****    * * **** *    **  **  *** **
 **  ** **  ** *  *     **   * **        
 *  **     * *   * ** *    *  ****  * * * 
  * ******    * *** ** ** **  *  * ***   *** 
*  **  *   *      * ** ****   ** * **     * **** * ** ** *   * **** ** **    is a prefix of %s",p,s);
 *   ** * ** *       * ****
 ** ** ** * * *** ** *  **
***   ***  ** ***   * **    * ** *   *   * **      **  ** **** is not a prefix of %s",p,s);
 *       ***    *   ***
****  ****     *  ** * **  **** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.59
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users