1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include *  ***  * * * 
#include **      ** *   * 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* ** *   *   **   * * 
 
  **   **** * * *  *       ***   **** **** ** * ** * ***
 ***  * *    ***   **  ** * ** 
 * **    * *  ** *  * *  *    ** *** **  *****   ** **** **** * == s2[i])
  ***  *   ****    *     *           ********* ****    
  *   * ***     * *   * * ***  * **  ** *     * *   *** **   ***  *****   *   ********
 ***    ****** ****   *  * * ***     *  ** **  *  **
 
 * * ****    * *    ***  ***    ** 
 
** *  *     *     ***  ** **  **     * * == length)
          ***   *   * ** * ***** *
  **  ** ***  **  *** *  * *     *  * *  ****** *    *****   *** **** *   **   * is a prefix of %s",s1,s2);
  **   * * *  ** *** * **** ***    
 
*** **  ** **  ***    * ** ** *
  * **  **  * **   *  ***  *
**  * *  *** **   **   *** *  *  *  **   *  **  **  ** *****   ***  *  is not a prefix of %s",s1,s2);
*   *** *  * * *  **      *  * *   * 
 return 0;
 *** *   ***  *     *      
 }

int main(void)
{
 **  *****  * **** *   *   s1[100];
***      *   *** **  * * *    **** s2[100];
*  * * *** * *** ** **        ** i,j;
  *** ** **    *    * * *
      ***  **   **   ***   * ****  * *  *  **** *   **  s1);
 ****  ******** ***  * * *  *  **   * *      s2);
*    *  *   ***  * **   
*  *  ***     *****  *  **     ** * *  * *
     * **  * **  **  
**** ** ** ***   *  * * * ** *    0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** *** *** ** 
#include   * *   *   * *

int prefix (char st1[],char st2[]){
      ***   **** *     ** len=0, i, cnt=0;
* ***    ** *********  ***  
 *** **** ** ****** *** *** ** = (unsigned)strlen(st1);
 ***  **  ** ***  ** *** *  *
*   ** *  ** * *** ** **** *   ** (i=0;i<len;i++)
       *  **** **** ** *
*     *** **  (st1[i]==st2[i]){
* * ***  * *    *  ** ****  *      ****   *         *** ** * **** * *** * * ***   ****
*  * ** **  * ** * ** * * **     * * *   *  ***** **
 *  *** *  *   *  * ** * *   
*      *****  *  * * (cnt == len){
*  *  *    ** ** *** * * *    * * *  ****** *** *  *   * **** 1;
*  *     ******* *  *   **  
* ***   *   **  * **** * * *** ** 
* ***  ** * *  * *   * *  ******   0;
***** ** **  *   * *** ** *  
}

int main(void) {
   * *** * *  * *** * * * **     * * st1[256];
** *  ***  ** *  *  * ** * *** st2[256];
*** *    ***  ** * ***  ***   * *****    *  * *   * st1);
**** ** ***  *  * *   * *  *     ***   **   *   *  ** st2);

 ***  *    *  *  ** * * * * *  (prefix(st1,st2)){
  * *   *    * *** *  * *** ** *  *** * ** *  *    **** * * *    **  is a prefix of %s", st1, st2);
 **  *   * ** **** * ** ** 
* *  *** * ** *** *       * 
**    ***** *  * * * ***   ******* **  *  * **  ****   ** *   is not a prefix of %s", st1, st2);

 * ****  *    *** ** * *  *** * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 * * ****   *  ***     **** * ** ** *    ***** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*  ** *    ***  ** *   * *   *** ***     ** ***    *  
* *   ***** **** *  ****  ** ***** * **  *** *     *   *** *** ** **  **    ***   
   *** ** ***      **     **  *  **     *  **** * *  *  ** ** **  * *  *         ***  * ****** ****** *   *  
*  *   ****   * *   * **** ***  ***    ** * ** ******    **  * * ** **  ** ** *** * ** **** **  *  ***** * *   * *** *     ***  *    **   ***   ** is not a prefix of %s",a,b);
* **    *    * ** * **  *** *    ** ** ******* **    *   *  ** * *  **    *** ** * *   * *****  **  * ** *  ** *   **   * *****    ** *  * * 
*  * *   * *      * *****  *   * * * ** ** ** * *  * *   * * **** *   *  * **       *  * * ***  *   *** * ** * * * *
**  *        **  * * **  ***** **   ***  *   *** *** *** *   * *  *      **   **   
******  **     * ****  **  *  ** *  * * * *  ** ****    ****    *  * * *** ** * *** ***  *  * *  ****     *
******   *  ***    * * ****     *     *****   ****    *  ***  *      *  **  *   *  ***  ** ***    ***     ***    *   * **  ****  *   ** * * * is a prefix of %s",a,b);
 * *   ** * * *  ************* *     * *      *** *  *** ***  ******   * **  *   **  ***  *   *    * * ******* *  * * ** **  ** * **** *
** * * *  ** *   **** *** **** ** ****  ****   * ***  *******  *** * * * ** *   *    ***    ** **   ** ***** ***    **
* **     **   **      ***  **** * *   ******  * ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 * ***** *       ** *   ** *     ******  *  *** * 
*    *  *  * *** * * *  ** *   *   *   ****** * *   *

 *   **    ** *  *** *** *** ****   * *** *       ** *** *      ** * * ** *  0)
 ** ****** ** ***   ***   *   *   *  * ***    ****  **  **   *   *** ** * 
* ** **** ** ****     *  **  *** ***   *************  *  **   *   ** *     *** **  * **  *  * * *    **** *    is a prefix of %s",pre,str);
 **  ***** **  ** **  *** *   *** **  *   *** ***   *    *** * ***      * * **
  **  *  **   * *****  * *     ** * **  ** ********
   ***   * **** ** *    *  * * *** ******** *    *   ** **  *******  * *    *  *  * *
* ** * ******      **  *** ***  **    * **  * **  ** *         ** * * ***  ** **   **   *  *** **   *** **** * **  ****  ** is not a prefix of %s",pre,str);
*  *     *   ***   *** **    **  *****   *   *  **    * *     *  ** ****  * *  **  * 

* ** ****  * *   **      ** * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*  **  * *     ** *  *  **  **  * * a[100];

 ***** * * ******* *  *  * ** b[100];

*    * * ** ***  ** *   *  i = 0;

      *         * *  * * **** prefix = 1;

        *         ***    ** ** **  ** *** **** * * a, b);

   *  ** *   ***  ** ** * *  * len = strlen(a);

** *** **     * * * *    ** ***   = 0; i < len; i++)
* ****      * *** *******   
*      **** *   *   * *   *  ***  **   **   ** *  **   **  != b[i])
 *   *   * *  * **  ****     **  *** *  *****  **   *  ***    
** * *   **  * *     * ** * ** *** ****   *** *** * **  ** *    **** *****    *     = 0;

*  ** *  *  * * *** ***   **  *  * *** *   **** *   *    * * **   *  * *** ***   ****      is not a prefix of %s", a, b);

****  * * **    **** **  *    ***    ** ****  * **   **     * * * * *****  *  ***  **  
 *   *   ** *  *  **   * ** *  *  * * * * * *** * *** *  ** *   
*  * *      *  **** * *    *
 *** **** ***  *   ***** *** **** == 1)
 *******  *** ** * **  *  ******
 **   ** * ** *****   *     *  **  *   *   * * **  **    * *  *  * * is a prefix of %s", a, b);

* *  * *******  * *  *  *   
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** ** **   *****   
#include  ** * **   ** **  

int main() 
{ 
*****     *  *   **   ** ***   a[100],b[100]; 
 **** ***** * ****   **   ** * i,j,prefix = 1; 
    ** **     **  * *  *****   **** **  %s",a,b); 
**  * **  ****  * * * *  * len = strlen(a); 
**** **  * * * ** ** ***** = 0 ; i < len ; i++) 
* * ** **    ** ***     *  
   * *  * * ********  * ** ***   *  **  **    * *** **    != b[i]) 
*** ***   ****** ****  **  ***  *********   *  *  
    *   ***   * * *  **  **** * ** **  ** * ***** *  **  * *      * **** ****    *   *  = 0; 
    **  **  * *  **  *********** ***  * *      **   *     **     * * * *  **    *******  * is not a prefix of %s",a,b); 
** ****** * *** *** ***  * * ******  * * * ** ******  * *  *   * * *   * *    
 ** *   **  ***   * ** ** ****  ************* **** *  

       * * *  *   * ***  
** ** * *  **     **     *   == 1) 
 *  * ** ** * *** * **  **     *  *****    * *  ******  *  * is a prefix of %s",a,b); 

 
   *    ** * *  * *     ***** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *****   *  * *****
#include ** *****  * * * * 

int main()
{
     ** ** **  * ** * * *  **  *** a[100],b[100];
 * * ** **    *   ** **  i,j,prefix = 1;
    ** ** * **   ***   *** ***  * **  ** %s",a,b);
  ** *    *  **   *****   * * len = strlen(a);
****** * * *** **  *****   *   *  = 0 ; i < len ; i++)
     *** *  * **** * *    **  
 *   *      * *     **** * * * *    * * ** * *    ***** ***  != b[i])
 * * ** **   *  *   ***   ** *    * * *  ***   *  *   *
* *  *    ** *     *  **  **   **  *** * * * **     ******* **   *   * ***  *   * * *  ** = 0;
* * * * *   * *  * ***       **  ***      ** * **   *  * ** *  **  * *  * ** * *      ** ***     is not a prefix of %s",a,b);
** **   * *   **   * *  *   ** *** *  * ** *   ** *  *   ** * **  **   *  **  **
  *       ***  * *  **  *****   * * ** **  **    * ** 

**  **   ** * * *   ***    *
 * * *****  **** ** ** **    ** == 1)
 ******  ***    **    * ** * * *  ** *    ** ** *  *****   is a prefix of %s",a,b);


**  * * ***    **     ****** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ** *****  
#include ** *   *    *

int prefix(const char *pre, const char *str)
{

    * * ***   * **  ****     * **  **** **  **    ** ***
* *   ** *   ** ****    ** *  ****      ** * ** ** *  *   * *    * 0;
**   * * *  **** * ****** ***   ***** *** ** *   **    **  
* **  **  **     **** ******  ***  *****    **      *  1;
  * **** ***    *** *     ** ** *** return 0;


}

int main()
{
* **** *** ******  * * pre[100],str[100];
  *   * ** **         * **
 ** ****  ** *  ****   **  * *   ***  * *  *** **  
 ***   *   ***  * *  * **  ** * *  *   * 
    *  *   *   * *****      ** * *  ** *    * * *  * ** ***  *  *  ** * is a prefix of %s",pre,str);
***  ***  **  ** *  ****  ***  *  **
 *  **  *** ******  ***  *** **  ** *  *** ** *   **  *  * *  *   * is not a prefix of %s",pre,str);
  ***   ** **  ** *  **** *** *  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
   * *  *   ** * * **** * c;
  *   *** ** ** *** *****  ****  ** *  *** *  
       * *  ** *  * * * **    *     ** ***    **  * * ***   0;
**      * ** * *  ****  * **
***    ****** * * **   **    *
 * **  * * ****** * ***  *  *    ***  * **  *   *  ****  ** * ** ***** **  *** * * of a string
*   ****  * *      * **  ***  * **   ** * **** *  **  *** * * ***  * *  ****** ** *   * 
** ****** *******          *** *** *  ****    *  *     **** * ***   * *  *  **    *  **** *  **    * **    **   *** *** 0;
 *** ** **** *  *  ******  *** * * ***** *  **  **   
  *********   ***     *** * **   *** * * *    *** 1;
    }
}

int main(){
****** * *     *  ******  ** * *** * a[100],b[100];
*  *  **  *   *   *  ** *  **    ****     %s",a,b);
      ** *  *****  **  **   ***** * **
  ****** ***        ***   ***** * ****  ****   *   * ******* ****   ** is a prefix of %s",a,b);
 * ***   * **  *  ******   **** 
 * *      ***** * *  * * *** **      ****** * ***   * ** * **** * * *     is not a prefix of %s",a,b);
* ****     **** ***   *   **  **  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**  ***  *** **    *  **    ***   p[100],s[100],a[100]={};
   *  *  *   * **  * **  * * * t;
* *  ** * *     * *  ****** ** **  *    *
***   * ***    *   *  **  *      ** *     
 **  ** ***    * *  *  * **  *  *** * ** %s",p,s);
** *  **** *  *  * *  ** **     ** *  ** *
**   **    *  ***************    *** *  **
     *  *    * * *  *** *  **  *   *
    * **   *** ** *     ***    * * ** *  * **  
*   * * * *  * *** *****    ** *** 
  * *** * ** *   *  *  *  ***  ***     ** *   *** **    * ** *  is a prefix of %s",p,s);
 * *   ***  *** * ***    * 
  ***  *** ***   **** *   *
    **       ** **  *   *      *** * * **  **** *** **  * ** **  *  ** *   ** is not a prefix of %s",p,s);
****              ** ** **
* ***   * **  * ** *  ** ***** * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 20.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 18.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users