0 like 0 dislike
10.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 10.8k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include * *** **** *
#include * * ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* ** * * * ** ** ** *** *
 
* * **** *** *** * * * * * * * ** *** * * *
***** * * *** ** ***** *
* ** ** * ** ** *** * *** ** ****** ** * *** **** == s2[i])
****** * ** * *** ***** * **** * *
*** * *** * * ** ***** ***** * ** ** * ** *** * * ** *
***** * ** *** * *** ** ** ** *** * ********
 
* ** *** * * * ****** * *
 
** * ** * * ***** ** ** * == length)
** ** **** ** * *** *** ** * *
* * * * *** * *** * * * ***** * * * ** * * * * * * **** **** * * is a prefix of %s",s1,s2);
* **** ****** * * * * * **** **
 
** ****** **** * ** * * ** * ** *
* * ** ******* * * * * * *** *
* * * * **** ** * **** ***** **** ******* *** * *** ***** ** * * is not a prefix of %s",s1,s2);
*** * *** **** ** ** * **
 return 0;
**** * * * * * * *** ** *
 }

int main(void)
{
*** * * * * **** * * s1[100];
* * ** * ** * *** * ** s2[100];
* ****** *** i,j;
***** ** ** ** **
* ****** ** * * ** * ** ** *** * s1);
* **** * * * ** * * **** ** * s2);
* ** * * * ** * ** **
* * * ** * ***
** **** *** * ** ** ** ****
* ** * ** * * ** ***** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include *** * ***
#include * * *** *** * *

int prefix (char st1[],char st2[]){
*** ***** *** * len=0, i, cnt=0;
* ** * ** * * * * * * **
*** ** *** * **** * * = (unsigned)strlen(st1);
* * **** **** ***** ** ***
* * *** * * * ** * (i=0;i<len;i++)
* *** * * * * * **
* * * (st1[i]==st2[i]){
* * ** **** * * * * **** *** * *** * * *** ** ** *** **** ** * * **
*** ** ** *** ** ******* * ** * * ** * * **
*** ** * * ** * ** *
* * *** * *** ** * * (cnt == len){
* ** ** ** *** * **** ** * ** ** * *** ** ** **** 1;
** ** *** * *** * * *
** * * * * * ** **
* ***** * * ** * ** ** 0;
* ** ** * * ** ** *
}

int main(void) {
** ** * * *** **** st1[256];
* * *** *** ***** * * * st2[256];
** *** ** * ** ***** *** * ** * * * ******** st1);
** * ** * *** ** * * ** * * *** **** st2);

**** ** ** ** * * *** * (prefix(st1,st2)){
** ** ** * *** * ***** * * * ** *** ****** is a prefix of %s", st1, st2);
* * * *** * * ****
** * *** ** *** * * * * *
****** *** *** ** * **** * * ** ** ** * * ** ***** * **** is not a prefix of %s", st1, st2);

** *** * * **** * ** ** ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** ** * * **** ** * * **** * ** * * * * ****
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* ** * *** *** * * * * ** * * * * ** **
* ***** * ** **** ** * ** * * *** * * ** * * ** * **** * *****
**** * ** ***** *** ** * ***** * * * ** ** *** *** * ** **** ** * * ** * * * * ** * *
* ** * * *** * * * ** **** ** ** * * * *** * *** **** *** * ****** * * * ***** **** * * * * ** ** * * * * * is not a prefix of %s",a,b);
* * *** * *** ***** * *** * ****** * **** * ** *** * * * * ** ** * * * * *** ***** * * *** * ******* * ******** * *
**** * * ** * * ** ***** ** ****** ** * ** *** * *** * ** * ***** * *** * **
* ****** * * * * ** * ** *** * * * *** * * *** ** ** * *** ** *** ** * ****
** * ** * * * * ** * *** ********* ***** ** * ** * ** ** * *** ****** ******* ****
* * **** ** ** ** ** * ** * **** *** ** * * * * * **** * **** * ** * * ** ** ** * * * ** ***** *** * * * * ** * is a prefix of %s",a,b);
** ** *** * * ** * * * *** * * * * * * ** * ******* ** ****** * * * * * * *** * ****** ** ** *** ** *
*** *** * *** * * * * * * * * * ** **** **** ** ****** **** ****** * * *** * * *** *
* *** * * * ***** * * ******* *** * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* *** * ** * * * ** * * * *
* ** *** * * * ** * ** ***** * ***

* * ** ** ****** ******* ** ***** ** ** *** * * ** * * * * * ***** * 0)
*** ** ** * * * * * * * * ** * * * * * **** * * * ******* *
*** * ** * ******* * * *** ***** ***** *** * ****** ** * * * ********** * ****** is a prefix of %s",pre,str);
* * **** *** ** * ** * * **** ***** *** ** ** ** * *** * *
* ** *** ** * ** ***** *** * ** **** ** *
* * ** *** ** * ** * * ** * ** * * ******* * ******** * ** * *
** **** *** * *** *** * * * * * * * * ** ** * * *** * ** *** **** *** ** *** ** ** * * is not a prefix of %s",pre,str);
**** * * ** * * *** ****** * * ** ** *** * ** ** **** ** * *** * * ****

** * ***** ** * * *** * ** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**** * ** * ***** * * * * a[100];

* * * * * ** ** ** * b[100];

* * *** ** ** ** i = 0;

* * * ** **** * ** prefix = 1;

* ** ** **** *** *** ** * * * *** a, b);

* * ** *** * * ** * len = strlen(a);

* ** * * *** ** = 0; i < len; i++)
** ***** * ***
*** * * * **** * * * ** * ** ** ** ** * * != b[i])
* * * * * **** ******** *** *** ** * *
*** **** ** **** * **** * **** * * *** **** *** **** **** ** = 0;

* ** **** * * ** * * * ** * ** * * *** ** * ** * * **** ******* *** * * is not a prefix of %s", a, b);

*** * * ** *** ** ** *** *** * * * **** *** * * *** * * * ***
*** * ***** *** ** **** **** ******** * ** * * *
* ***** *** ** ** *** ** *
* * * ** * *** ** ** == 1)
* * * * **** * * **
* * * * ** ** * * * ** ** ** * *** **** * * is a prefix of %s", a, b);

** * ** ** * * *** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * ***
#include **** ** *** * * *

int main()
{
* * ** ** * * ** * * * * * a[100],b[100];
* * *** * * * *** ***** i,j,prefix = 1;
* * *** * * ** **** ** * %s",a,b);
** ** * ** * * ** len = strlen(a);
* * * * ** ****** ** ** = 0 ; i < len ; i++)
** * * *** * *** *
* **** ** * * *** *** *** * *** * * **** ** != b[i])
** *** ** * **** * * *** *** ** * * ** **
**** * ******* ** ** *** * ** *** * * * ** * * *** * ********* * * * = 0;
****** * * * * * * ******* *** * ** * * * **** *** * *** * * ** *** *** ** is not a prefix of %s",a,b);
* * *** *** **** * * ** * * * **** ** *** * ** * **** * **** * *
**** * * * * * * * *** * *** **

* * ** ** * * * **** ****
*** *** * ** ** ** *** *** == 1)
* * ** ** ** **** * * *** ******** ** * *** * * * *** ******** is a prefix of %s",a,b);

 
*** * ** ** *** * ** ***** 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ****** ** ** * **
#include * ** * ***

int main()
{
***** ** * * *** a[100],b[100];
* * * * ** ** * * * i,j,prefix = 1;
* * * * * * ****** * * ** ** %s",a,b);
*** * * ** * ** len = strlen(a);
** ** * *** * = 0 ; i < len ; i++)
* **** * * * * * * *
* ** * * ** *** ** * * * * ** *** * ** * *** ** != b[i])
* * *** ***** * ** **** * ** * * ** ****
** ** ** * * * * * ** * ******** * ***** * ** *** ** * * *** * * *** = 0;
* * * * ** *** **** ** * * **** ** ** * **** ** ********* * * * *** ** * ** ** **** is not a prefix of %s",a,b);
* ** * * * ** *** * * * * * ** * * * **** **** ****** * * *** ** * ****
* *** *** * ****** * * ** *** ** * ** *******

** ** ** * ** ** ** *
*** * * * * * ** * * * == 1)
* **** * ** * * * ** ******** ** * ****** * * * ** is a prefix of %s",a,b);


*** ****** * ** * * ** * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *** * *
#include ** *** *** **

int prefix(const char *pre, const char *str)
{

* *** * * ******* ** * ***** * * * *
* *** * * * *** * * * ** * ** **** * * 0;
**** * * ***** * ** * * * * * ** * * ** * *
****** * * * * * ** *** * ** * *** * 1;
* ** * *** * * ** ** *** return 0;


}

int main()
{
* ** * ** * * ** * pre[100],str[100];
***** *** * **** **
* * * ** * * ***** * * ***** * * * *
** * *** ** * * * **** **** * * ****
* ** ** * ** ** * * * * ** *** * ** ** * * is a prefix of %s",pre,str);
*** * *** * * ** ** * ***
** * ** *** ** **** *** * * ** * ** * * is not a prefix of %s",pre,str);
* *** **** ** **** * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**** * * ** * * * c;
* **** * * ** *** ***** * * *** ******* **
***** ** ***** * *** **** ** * * * * * * * 0;
* ****** * ** ** ** * *
*** *** * * ***
* ** ** * * ** * ** * * *** *** * * ** * *** * *** * **** of a string
* ***** * * * * * * ** * ** * * * * ****** * **** *** ************ * ***** *
* ** * ** ** ** * * ** ****** * *** **** ** ***** **** ** **** * * ** * * ** ***** 0;
**** * ** * * * * ** * ******* *** * * ****
** *** * **** * ** ** * ** ** **** *** ** * * ** 1;
    }
}

int main(){
* * ** ** ** * ** ****** *** * a[100],b[100];
* ***** *** * * * ** ** ** * ** * %s",a,b);
***** ***** * ** **** ** * *******
** ** ** ** ** *** * * ** ** * * ** ** ****** * ** * * is a prefix of %s",a,b);
** **** * * ** **** ***
* * * * * ** * * **** ******* **** *** ** * is not a prefix of %s",a,b);
** * * *** * * * * * * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** *** * * * ** * *** * p[100],s[100],a[100]={};
*** * ** **** * * * **** t;
* * ** *** * **** *********** * *** *
* * * * * * *** * * ** * **
** * * * *** * ** ***** * * * %s",p,s);
* ** * ** * **** * ** * *
* **** *** *** * * * **** ** ** *
** *** ** *** * * *** * * *** ****
* * **** ** ** * * * * * * * *
** * * * * * * * ** * *** ** * *
* * ** * * ***** **** *** * ** * ** ** * * * ** ** is a prefix of %s",p,s);
**** *** * * * * *
*** ** ******* *** **
*** ** ***** ** * * * * *** ** ** *** * *** * is not a prefix of %s",p,s);
** * * ******* ** *
*** ** *** * * * * * ** * * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.189
©2016-2025

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 15.7k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 10.7k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 14.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users