1-11 Exercise 3: Prefix of a string

Question

4.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited Jan 11, 2018 by semicolon | 4.3k views

27 Answers

Page:

Diyiel · Answer 1 · 2018-01-13 00:58:32

Hidden content!
#include *  *   ***  **
#include *  *  **    ****

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
**    *  ** ***   * *   ** 
 
 * *   *     ***** *  *   * ***   *   **   ** *  *****
        * *   * * ***  ** *** 
*  **  **********   ***    *     **       ****   *  ** ** == s2[i])
      ** *  *   * * ***  * *   **  ***  * *  *   ** 
*** ******   **  *    * *  *  * * * * ** * *  *    ** * **    *  **** **    * ** ** 
   * *  * ** *  ** * *     *    ** *** ** * * ** *  ***** ** * 
 
*** **  *  * *  * *    *** **  *  
 
  ** ** ****  ***    *   ** * *  * **  * == length)
       * ** ** * ** ** * **  **** *
* *     * *      *    *     **  * ** *   * * *  *  ** *   ****   *  ******  ** is a prefix of %s",s1,s2);
*  *** ** ** * * * * ******* *  
 
*  *  * ** * ** **  * **  ** *  ****
  * ****** **  ** **    **  ** * * 
    * * *    ******   ****   *** **  *    * * *   ** ** ** *     *** * *    is not a prefix of %s",s1,s2);
* * *** **  *  * **  **  *****  *    
 return 0;
 *****   * *  * *   ** * * ***
 }

int main(void)
{
****   *** ** * *    *  *     ** s1[100];
**  *  ** **** ***  ** *  ****** s2[100];
 *  ***  ***** * **       i,j;
** **  *  ** *****   ****
  **   **  *****  * **** * *  **    *    **   *  s1);
 * * *   * ****  *  * **** **** **  * *  **** s2);
  * *** *** * *   *    *  *  * 
*        ***** ** ** **   *** *******
**** **  *****   * **   
  *** * * * **  ***** ***  **  * 0;
}

answered Jan 13, 2018 by Diyiel (-193 points)

Stephen Richards · Answer 2 · 2018-01-13 00:46:20

Hidden content!
#include *   **** **    * 
#include *  **  * **  *   

int prefix (char st1[],char st2[]){
**  * *        *** ***  **  ** len=0, i, cnt=0;
 *  *     ****  ** ***** ***  **
      ***   ** ***** * *   = (unsigned)strlen(st1);
**    * * *****   ****** 
 *  **  *** *  * ** * * **  ** ** (i=0;i<len;i++)
***** * *  * ******      
 ***   * *** * (st1[i]==st2[i]){
*** * * * *     * *    *** *  * **   * ** *   * ******    **** *  **  ****   * * *** * *
 * **       *   *  *   * * * *  ** *** *       * **  * *  **  
** ********  *******  *   *
  *******   *   *    *  * ** (cnt == len){
 **  * ** *    ******** *  *   *     **     **  *    *  1;
***   *  *   ** *** ****** * **
**   **      *   *  ***  * 
* *** *  * ** * *   *** *  **  0;
 ** **** ******** * * *  *
}

int main(void) {
* *    * ** **   *   * * * **   st1[256];
***** * *  ** * * **  * * *** * st2[256];
   * *  *  * ***     * * ***        *     *    *  * *  *   st1);
 *** *  *  ** *  * ****  *     *   * * ***  * st2);

* **   *   * ******* * *  * ***  * (prefix(st1,st2)){
* *   ***       *  **** * * ******* ** *  *   *     ** **  *  is a prefix of %s", st1, st2);
 **  ***      * ***   *  **
*  *   * ** ******* *   *
*   ****  ***** ***   **  ** ****  *   *   ***   *     * * *    ** is not a prefix of %s", st1, st2);

** **** **   *****  *  *    0;
}

answered Jan 13, 2018 by Stephen Richards (323 points)

ryan · Answer 3 · 2018-01-11 22:07:28

Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *   * **  *  * *  * * *  ** * ****   ** * **  **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* *     *** *    *     ****      ** *   *  **  *  *    *  * 
     *** ** *     *  *     ** *   * ** ***  ** * **     ** ******* **    ***  
***** *    **    *   *  ***** ***  * *   **  *****      *  * *   *  *  ****  *** ****  *** *   ***    ****
     ***** ***     *  ** **     * **** * ** *** * ** ** *   *****   *** * ** **  * *    * * **** * *  ***   * *  ** ** **  *    *   *  * ** * ** *   ** *  is not a prefix of %s",a,b);
  ***   **** **  **   ** **  **   ***** *****  *  ****  *  ** ** *   *** ****  *  *  **  **** *  ** * **** *** ******* **     *      *   **   *
* * *   ***** ***  *  *   ** *        ******  ** **    ** *  *    *** *  *    *********   *  * *   **  *
  *  **** * * ** * * **       **  **** * *  * ** **   * *  * ** ***  *  *    *** * * 
   * * ** *******   * ***** *** ** *  * **  * ***     ** * ** *   ******  **    ****** ** * **  *       ** ***  *
 *******  * *** * **  *  * * * * ***   **** ****    *  ** * *   *    *          *        *   *  ***    *    ***  *  *  ***  * * *      * *****  * is a prefix of %s",a,b);
** * *   ** *  ****  *  *   *****  *********  *   * ***  **   *   *  ** *   * * *   ** *  *** ***   **  *  ** *   ****** * *  *  *     * ** ** 
* ***  *** * ** **   ** ** * ***  * *** ****  * **     *** * * *****   *** * ** * ** **   *** **   
***  *** * *   *** ****   * *** *  * **  *        ****   **




}

answered Jan 11, 2018 by ryan (-301 points)

Headshake · Answer 4 · 2018-01-11 21:22:34

Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
  *** * ****   *****   * ****  *    * * * *     
* **** ** *  ***  ** * * *** *     *  *  * ***  * *

 *** **  *  *      *   *  * **  *   ***** *****       * **  * ** ** *** **  * * 0)
**     **  * *  *** ***** *   * *  **   **      * **     *  * ***   
*     *     *  ** * ***** * * **   *** * * * **   *****  **  * ****  *      ***  ** * *  ** * *** ****   *** ***  *** ***  * is a prefix of %s",pre,str);
 *     **   * *  *    *   ** *  **   ** ****   * *    *  *  *****  *** * **   **
* *    *  *     ** ** * ****      * *  *  *** * ** *****   *
  *   *****  *   **     *  ******   ***   *** ** *  **    *  ** *** ***  ***   ***
  ***     * ****** * *  * * *****  ****   ****** *   ***** * **  **    * *  *********     **   *    * * ****   **    is not a prefix of %s",pre,str);
    ***  *  *     ***  *   ** * *    *** **  **** **  ** **    *    * **  ** *

**    **  *  * * **   * * 0;
}

answered Jan 11, 2018 by Headshake (-281 points)
edited Jan 13, 2018 by Headshake

Sabrina Lin · Answer 5 · 2018-01-11 21:03:22

Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* **  * * **  ** *  *****    a[100];

***   ** ** ***  ****** **    * b[100];

  * **   **** * *** *** i = 0;

 ** ** **    **    ** **  ***  prefix = 1;

  ****** *** *  ****  *  * * ** ** **   ****  a, b);

 **** ** *  * **      **   *    len = strlen(a);

* * *** ** **   *  **  ***   ** = 0; i < len; i++)
 * *         * ** *  * **
  **  **** *  * * **  ****     **   ****    *  **   ** != b[i])
 *  *  *   *  *   * **** ** * ***       *     ***** * **
 * *   * * * ****   ** *  **  ***** **     *  **** *****  ** *  ****  * *  **** * *** **    = 0;

   ******    **  * ********  *** * *  **  * **** *  **   **  *   ***  ***** *  * * *** **** * ** is not a prefix of %s", a, b);

* **  *    *  *   *  ** ****     *   * ***   ***** * ** *** *   **  * * **  *
 * ** ** ***     *  *  **   *  ***      ** * *** *   *
 *   *  **  **        *** ****
 *** *** *   ******  *    *   * ** ** == 1)
 * ** ***** ****  *  *   ** 
           *** **   **  *    * * *  * * ** * *** *  **   *** **  *  *  **   is a prefix of %s", a, b);

    ** ** ** *** *** ******* 
}

answered Jan 11, 2018 by Sabrina Lin (-285 points)
edited Jan 11, 2018 by Sabrina Lin

watty1998871108 · Answer 6 · 2018-01-11 21:00:46

Hidden content!
#include  **** * **   *** * 
#include  *  ***** ***** *  

int main() 
{ 
* ****   *  **   ***** ** **  a[100],b[100]; 
   *  *  ***   ** * ** **  * *  i,j,prefix = 1; 
**   *  **   ***   **** ***  * **  *   ***   %s",a,b); 
   **  *   *   *    ***     len = strlen(a); 
 ***    ******  **** * **  = 0 ; i < len ; i++) 
*  ****  * ** ** * ** ** *  *   
   *  **   * ** **  *   *****   *** **    *** ******     ** != b[i]) 
*   *** ** * **  *  * * * **** ***    *    * ** * ** **** 
**** ****  *   * **       * **  * ** * * *  * *   **** ** *  * *********  *** = 0; 
 ***** **   ** * ** *  *  *     * *      ** **   ** *** * ** * *** * *  ** *** **** * *** ***   * ** *  is not a prefix of %s",a,b); 
**  * *   ***   ** *  **     **   * ****    **   * ***  * ***  *    ***    *     *** 
  *** * *     **  ****** ****   * *   ***     **  **  

  *** **** **  * ** * *****    * 
  ********  *  ****** **** ** == 1) 
* ***  *  ****    * ***** *   **  ******         *  * * ***** *** * is a prefix of %s",a,b); 

 
  *********   * *****   *  *  0; 
}

answered Jan 11, 2018 by watty1998871108 (-127 points)
edited Jan 17, 2018 by watty1998871108

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

Sammi0208 · Answer 7 · 2018-01-11 21:00:08

Hidden content!
#include <stdio.h>
#include  *    *    **
#include   ** **** ** * * *

int main()
{
 ** *  **   *     ** ***** * ***    * a[100],b[100];
 **** *  ** * ***         i,j,prefix = 1;
 *  *    *****  ****      * * *  * * * ** * %s",a,b);
 * **   ** **    * *     * len = strlen(a);
* * ** * **   ** ***  *****    **      = 0 ; i < len ; i++)
* ** **   ******** *   * ****
 *   ****    * * *   *     **  **  * **  **     *****  * * *   != b[i])
*** ******  **    *        ***  *   * *** ***   **    **
  * **   *  *** **   *** ** ******  *   *        *    ** **     ***   * ***** * **** *    = 0;
*  **  **  * ****  ** * *  **    * * ******* ***  *   ** *  *  ***    * **      ***   * *  is not a prefix of %s",a,b);
*   * *     ***  *  ***** *** **** *** *  *   ***   *** ****** ***  * **  ****  **    *  
** * * *    *******   **  *****     **         *  *  

  *  *  * **** *   *** ***** 
 * * ** ** * *   ******   **** ** == 1)
*   *** *****  ****   ****     *   ****  **    *  *      * *  *  * is a prefix of %s",a,b);


** **      * *   **  *  *    ** ** 0;
}

answered Jan 11, 2018 by Sammi0208 (-255 points)
edited Jan 11, 2018 by Sammi0208

410530022 · Answer 8 · 2018-01-11 20:46:02

Hidden content!
#include  * * * ******  **
#include    ** * **   **  *

int prefix(const char *pre, const char *str)
{

 *   ** *** ***  *** **   **   *  *** **   ***  **  **
****** *     * * **   * ** * *  **** *   *  * * **  *  0;
   * *  **    **  *    ** *** *** ** *  * * *  *    ** *
* *   * ***    * *  * *   ** *   ***  * ** *** *  *****  **  * 1;
 **  *     ***   ***  *     return 0;


}

int main()
{
*  ***** *  * ** **  ** **   pre[100],str[100];
     * *  ** *  **  *** 
 * ** *    ***    ** *****      *  **   ** * ** *     * 
 * * * **** *  *  ** *  *    *  *** * * * 
*   *   **     *  ***         * *   ****   *  *    * ***    *   * * is a prefix of %s",pre,str);
 * *  **     * ** *  **** *
   *  *   *   **** *****  ** *  *    * * ** ** ***    ***  **    **  * is not a prefix of %s",pre,str);
   **           *  * * **  ** ** 0;
}

answered Jan 11, 2018 by 410530022 (-196 points)
edited Jan 11, 2018 by 410530022

LinJingYao · Answer 9 · 2018-01-11 20:28:50

Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
***     *** **  *****  *  *  c;
  * *   *  * ***     **   *   **   *  ** *   * 
      * * *  ** *    *  *  * **** * ***  ** **   *  * 0;
***** ** *  **** *  ** ** *     
 ** *  **  *  *   *** **** * **
 *** ****     *     ****   *   **  *** **** ****** **      ****** *  * * * * of a string
  **    *  * *****   * * ** *   ***** ***   * **               *   * **  *  ***
    *   *** ** *   **  *  *    **** **  * ***  ** * ******* **   **  *** **  *  **** **  * * ** ***   **  * ** * ** * 0;
  *** *** *  ***** *  **   *        * *   *  **
***  ****      * *********    *   ***   * **  * ***  * 1;
    }
}

int main(){
 **   **    * *  ****    **  a[100],b[100];
***** ** ******* *** **   * **    * * *   *** * %s",a,b);
*** **** *  ** *** *  *   * * **  
** * * ** *   * ** **    *** ** ***   ** *******    ***  * ***** ** is a prefix of %s",a,b);
   *   * **  *  ** **  *   * 
 ****     ***  * ***  **  ** **    ****** *  ***   * *** * **         *  is not a prefix of %s",a,b);
*** * * *    **   ** ****  **   0;
}

answered Jan 11, 2018 by LinJingYao (-498 points)
edited Jan 17, 2018 by LinJingYao

VincentXV · Answer 10 · 2018-01-11 20:05:37

Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * * *   *    *   * ***   *** p[100],s[100],a[100]={};
 * * *  *   **  ** * *   * t;
****   ****   *****     **** **      * ** **
 * *  **  **   ** ***   ******   ****     ** *  
  ********  *   *   **  **  *  *   %s",p,s);
 *  * ** ***  ** * ** *     **  * **
  * ** *  * **   *  * ***** ** ** 
** ** *   ** ** ***** ****    ***** 
 **** ***  *** ***   * **   * ** ****  ***  
** *  *    ** ** * *** **   *** *  * 
** ******* ***     ****    *********** *    * *   *         * ***  is a prefix of %s",p,s);
*** **  ** ** **** *** * *
*  ** * * *   *** **** * **  *
**    ** * * ** **      ***      * ****  **  ****  *   * *    ** * is not a prefix of %s",p,s);
 ***   **  *   **  * * * *
****  ** *** *** * *    ** *** 0;
}

answered Jan 11, 2018 by VincentXV (54 points)

1-11 Exercise 3: Prefix of a string

Please log in or register to add a comment.

27 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Please log in or register to add a comment.

Related questions