1-11 Exercise 3: Prefix of a string

0 like 0 dislike
11k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 11k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  * * *** *  
#include   * ***  * *   ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** *    *  ** *   ***  ***    
 
 ****  * ** *  *** **  * ***  *  * ** ****   *** ***
*** ***  ***** ** *     ** ** *  *  ****
 **** ****   * *  * ***** **  **    * * **   ****** * * * *   == s2[i])
  *  ***   * **  * * ** ** * *    *****   ** *       *** * 
 **  * **  **   ****  * * *** **** *    *  ** ****** ** * *  ***    ****  * ** ****** * 
  *  **   *  * *  * *  * * * * * *  ** **** *   *
 
 **            * * * * *****  ** ***
 
*** *  *   * *  *      **    *  ***  ** == length)
  ***    * ****  *     ***  *** *** 
* *** ** **     *  *****  ** *   * **  * * **** * *** ***   *** * * is a prefix of %s",s1,s2);
 * * **  * *    *** *  *  ***** 
 
**  **** * **  * * *      ****   
* ** *   *** *****   * * ** *   
 **   *** *      **** *** *****   * ***  **   **    *  *   ***  ** *  * is not a prefix of %s",s1,s2);
* **   * *   ** *       ****    ** 
 return 0;
 **  *    ***  ** * * *  * * * *
 }

int main(void)
{
  *** **   *   *  * * * * **  s1[100];
  * * *  * ** *** ** *    *   * s2[100];
*** ***** *         * **    ** * i,j;
      ****   *  *   ** **
**    ***  ** ** *   ** *    **** *    **** ***      s1);
*  *  * * *  * * * ** **   ***** ****     s2);
**  *** **     **    ****  **   
 *     **** *       * **** *** * 
   ***  ***** *   **** *  **
 *** ** *** * * *    **  *  *   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  **      *  *
#include   *  *      *

int prefix (char st1[],char st2[]){
** * *   * * * * * ***** * ** len=0, i, cnt=0;
* *  *  ******        *  ****** 
  * *   *    * *     ****  * ***  *  = (unsigned)strlen(st1);
      *** * *   * * ** *** 
 ** *  *     ***  *** *** *     (i=0;i<len;i++)
**  ***  * ***   *  **
 **** ** * ** (st1[i]==st2[i]){
* ** * * * ** **  *  ******  * *       ********  **   ***   * * **   **** *   ***     * ** 
** *** **** *  ****  **  *      **** *   **** *    
**    ** **** *** *** 
 *** ****  *  **  *  ****  * (cnt == len){
 * *** ***** ** * **  *  ** ****** * * * * * **    ** * * 1;
 ***  ******  * **  *   *
*  *   *  * ** ***  ****   *    
* * ** * ** ** *** * *  ****  0;
*** ****   ** *  ******** *
}

int main(void) {
****** **  *   *** *  * * st1[256];
* ****        *   ****  *   st2[256];
* * *   * * **** **  ***** *    **  *  *** ** **  *  st1);
 ** *   * *  ** ** *    *  ** **   * * * *  * *  st2);

 *  *  *  ** *    **    * ** (prefix(st1,st2)){
 * ***  ****   **  ***** **  **    **  *      **   **** * **      *** * is a prefix of %s", st1, st2);
**   * *** * *      **** **  *  ***
 *   *  ** *   *  **   **     ** 
** **     * ****  * ** ** **   * *      *  *** *   **   *** *  is not a prefix of %s", st1, st2);

* ** * *     *******  **  *** * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 *  *   * *  * * * ***  ** ****  * ***** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 ** * ** *  * **   * * ** *     *** *      ** **   * * *  
 ***  ****  ** *   ** * ** *** *  *   **** **** ***    * **  * **   *** **** **  *    
      * * *  *  *** *  ** **  *** * ** **     * * *  ***    ** *  ** * * * * *  *****  * *  * ***  * *
*  * * * **  * * ****   *  *  ***  *******   *  ** ***  ** *    **  * *  *  **     *** * * * * ** *  ***  ***    * ** ** **** ***    * *    * is not a prefix of %s",a,b);
** * * *      *   * **** * ** * * * *** **   *   * *** * **  **     * *  **  ***** **** *  * ** *  *    * *****  * **  **    ***  *   ** * **
* **  *** * *   *   *  **    *  ** **** * * *** * * * *  *    *  * * ******   ** **  * *        **** ***  *        
 *** ** **   ***  **    * **  *  ** * ** *    * *     ** * ****      *** *** ** *** * * *
  **   **  **  * *     *  *   ** ***   * ****  *  * * *   *  * * **  **  *       **   ***  ** * *  *  *  ** * *
  *  *** ** *    * *   *    * *  **   ****** * *  *  *  ** ***  * *   **   * * * ***    **** ** * *   ******* **   ***   * * * *       ****  *  *****    is a prefix of %s",a,b);
* *   ** **  *  **    **  ** * **   *    * **  *** *  * ** **  **** **   *    ***   **   ** *** **** *   *** ******  * * ** *** *  *  **  
*  * *  **  *  ** * ** * ****    **   *   * * *  *   ** **   * ****   *** *  * * *** ***    *** ****  
**  * **   * **** * **  **  ****  ***  ***  **  *  **** *  *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
   ********  ***** ** ***       *****   **  
*  *** **  *  *    *** ***  * **  *     **** *  *

*  * * *  *  *  * * * *  **** *     * * * * ** **   *  * * *  **** * *** 0)
*     *  **   *** *  **     ****   ** *  ** *** * ** * ** ***    ** * **** 
  * * ****   * *      ***** *** ** **  * *  * *   * ****   ** ** *  *  * * *  ** ** * * ***  **  * * *****    is a prefix of %s",pre,str);
* *  *  ** ** *   * *       ****  ** *****    *        **  * *  ** 
*  *    * *  ** * **   **  ****  *** *******  ** **  ** 
***  **   **** * ** ** *  ****   ** **    * ** *  ** ** * * ***  **  *******  * 
* *   *  **  *****   * * * *   ****** *  **** ** *    ****** * **** *  ****  ******  * * ****  ** **    *  ** is not a prefix of %s",pre,str);
**   ** * * *******    * ****  ** *     ***   * *** * *       * * * **    ** 

    **** **   **   * * ** ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**  ***** **** * **** ****  *  a[100];

*  *    *  *  *  * ******* * ** * b[100];

*   * ** ** *  **    ** *  i = 0;

** ** * * ** ** * * *   * ** * **  prefix = 1;

**  * * * *** * * *    *    ****** **  **   a, b);

  *  * * ** *  *** ** ******     len = strlen(a);

* * *** * ** *  *** *  *   **  * = 0; i < len; i++)
    ** *  * ****   ** * *  *
* *********   * * *      *  * *    **     ***  ****  * *  * != b[i])
* *** ***  **    ****   *    **   * * ** * ** *  * 
  * * ** ** ***   * ***  * *  ****   ** **  ** *****  **    ** *** ** **  ** **   * = 0;

  *  * * **       *   * *****   *** *  **   ** *       *  ***  *  * *********   *   ***  is not a prefix of %s", a, b);

* ** ***  ** ********* * *  *   ***   *   **   *  ****   *******   **   ** *  ****** * *  
*       ****   *** * *  *     **  *** *    *  * * *** *
 * *** **    * ** *   * ***** 
*   *** * *     **     *  **   ** == 1)
 *   * * ** * ** **  ** **  ** 
 ** *      * *****  **   * ** *****  *  ** * ***    *  ***** **** ** is a prefix of %s", a, b);

** ** *    *  * * *****  ** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include       ***** * 
#include ***** **  *  ****  

int main() 
{ 
 * ***  * ** * **  ***  **  ** *** a[100],b[100]; 
 **  *    * * * **  * * *  **** i,j,prefix = 1; 
**** *******  ** **      * *** *** *  *    %s",a,b); 
* * *  *    * *** *   *     *** len = strlen(a); 
    *** * ** *     *****  * ** = 0 ; i < len ; i++) 
 *  *** * *  *     *  * * 
** * *   ** *   **** **  *    ** **** *    **  *  * **  *** != b[i]) 
**  *  ** ******   **** ******           ** *   * * *** * 
***   * ***** *   * * *    *  *  *   ******** *** * *  * *       *  * * ***   * * = 0; 
** * **** ***   ** ** **    ***  *** *   ****  * **  * * *   *  *****   ******  *  *   is not a prefix of %s",a,b); 
 ***** *** ***     ** * ** * *  ***   ** *** **    *   * ** ***   ***    *****  *   * *    
** * ***  * * **   **    **    * ***** **** **   * ********* 

  *   * *******  *    * ** *  
*  * *  *******  *    **  * *    == 1) 
**** ** **  ***   ****    ******    ***  *****  *  * * **   * *  * is a prefix of %s",a,b); 

 
*** * **** * *  *   **     * * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  *  ****** *
#include * *  ** * *  ***  

int main()
{
** **  **     * *** * ***   ***  a[100],b[100];
**   **  **    * * * *  *   i,j,prefix = 1;
 * *** * *   *   *  * ********    * *  %s",a,b);
*     **  *     *** *** *    * * ** len = strlen(a);
* *** ****  * *  ***   *  ******* = 0 ; i < len ; i++)
 *  ***** *      ***** *   
   *  * *   **   *  *  * ***    **** * **  *  * *  *   * ** *** *    != b[i])
 * *  *   * * * *   *** ** *   *  *** **  *  **  ** ***
*   ********  ******** *****  * **  * *  *** *   *    ***  **   * **  *  *  * *   ***  *  * = 0;
* ***   * ** ***  *  *******  **    *****  ** ***** *    *******   *** ** * *  ***** ** *    * **  is not a prefix of %s",a,b);
 ***  *   * * *  ***  **** ***  ****   ****  *** * *  ** ***   *   * *    *** * ** 
* ******     *   *   ***  * ****   *   * **   ***  *

* ****  *    **   *  * * *  
* * * *** *   **  **     *** * ***  * *  == 1)
  *******  * **  * * ***  * **  ***** ** * *** * *  * ****** *  *     ** is a prefix of %s",a,b);


  ** *** *    *** ****  *  * *  * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * * ***  **  
#include * ***** *     

int prefix(const char *pre, const char *str)
{

 * *   ***  *** *  *   *  *  *    *   *  *** *** *   *
**** ***    *    *  *** **  *    ** ** *****    *  *  0;
     *** **  *  ***   *   * *  *****   *    ***
   ***  *      * **  * ***    ***** *** *    *   **   ****** 1;
 **** ** ** *     * ***     return 0;


}

int main()
{
*   ** *  * *   *  ***  ** ***  pre[100],str[100];
* * *** ** ** *** * *
*  ***** ** **    * **  ***      * **** ** *  ** *  *
**   **** ** *      * ** ***  ** **  *   ****
 ****  **   **   *    ****  * ***      *    ** ***  *      *  ** *  ** * is a prefix of %s",pre,str);
*      ******    * ** * **   *
   **  *  *  ** **   ***  * *  * *  ** ***    * ** *****  ***  is not a prefix of %s",pre,str);
* *  *  *    ***    **** * *  * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *  * ** * ** ** **** ** c;
* *      ****  **  * *****  **** *  * **** **     
*** *** *   * *  *  ** * **  *  **    **  * ** *   * * * * *** 0;
  **  * * *  * *  *    * *** 
  ***  *  **** *** *  *       
*     * **  ***   **** *****   *  **   **     *  ** ***** * *   ** ** *      ** ** of a string
   *   *   * * * * *  ***   * * ***      ** ** *   ******           **   *****     *   *** **   
* **  ***  *     **  ****** **  **   ** *  **    ** * *    *         ** *  *  * *       ** ******* ****  *   * * **  *  0;
 **  *   * *** * *  * ***  **** **     ** ***  *** ** *
* *   ** * *  ** *   *********  *  ****  * * ***  *** **  *  1;
    }
}

int main(){
***** **  * * ****    ** **    ** *  a[100],b[100];
  ** *** *        *  ***   **** ******* *  *  %s",a,b);
*  ** ***   *   ***   *  * ***   *  * **    
  ***      * * *    *******  **      *  ***    **  *     *    *    is a prefix of %s",a,b);
 ** * ***   ** *   *  ** ** 
* * * *****    *  * * *  **     *****  *   * ***   ***  *  **    ** ***** is not a prefix of %s",a,b);
      **  * *** * *   ** *  * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ** * **  * *** *   * *** * p[100],s[100],a[100]={};
* *  ******* * ** *  **** * * * t;
   * ****  *******  **** *  ****   * * 
* **  * **   *****   * **      **  ***
 ***  *   **** ***  *** * **** ** ** **  %s",p,s);
**  *** * *   ** **  ** **  *** *** * 
  **    ***  *****     ***    * *   
  ** *   ****** ** ***** *   *   
* *   *    *** *** *  **     ***     *  
** *  ********  * **  *  ***** *** *** * *
* ***  *  *    * ***   *   *   ** ***  * *  ** ** * **** *  is a prefix of %s",p,s);
* * * ** *    *** ***  *****     * *
  *** * * * ***  ***  *  *  * *** 
 *  *  * *** * *  ******** *** * * * * ** ****     *   *  *   * ** * ** is not a prefix of %s",p,s);
  **  ** ***      *  * **  
 * *       ** *    *  **  ****   ** *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.70
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 16k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users