0 like 0 dislike
4.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 4.3k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include * ** * ***
#include * * *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
****** * ** * ***
 
* **** * ****** *** * * * ***** * ** ***
* ******* * * ** * * *
* *** ** **** * * * * ** ** ** *** ** *** ** * * == s2[i])
* * * **** ** **** ** * ** *** * * *** * ** **
* ***** * *** * ** **** * * ** *** * ** * ** * ** *** *** **** * ** * ** **
* ******* * * * * * *** ** *** *
 
** * * * * * ** * ***** **
 
* ** *** *** * ** ** *** **** *** == length)
*** ** **** **** *
*** * * * ** ***** * * ** * ** * * * * ** * ** * ** is a prefix of %s",s1,s2);
*** * *** * **** *** * *
 
*** * *** * **** ** ** ** *
*** **** * ** * * *
* * * * * * **** * * ** ***** * ** ** *** * **** * * * ** * is not a prefix of %s",s1,s2);
** *** *** ** * * * **
 return 0;
* ** * * * * * * **** * * ** *
 }

int main(void)
{
* **** ***** ** * ** * * * s1[100];
* **** * *** ** ** * s2[100];
** ** * *** * * ** * * i,j;
* * *** ** * ***** ******
* * ** * *** * *** ***** ** * s1);
* * * * ** ** ** ** * *** * * *** s2);
** ** ** *** ** **
* ** * *** **** ** *** *** **
** * ** * **** * *****
** * ** *** *** ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include *** *****
#include ** * *

int prefix (char st1[],char st2[]){
* *** * * * * ** *** ** len=0, i, cnt=0;
* ****** ** ** * * *** *
* * *** * * ***** ** * = (unsigned)strlen(st1);
** * * **** *** ****
* ***** * * * * ** (i=0;i<len;i++)
* * *** ** ** *
*** *** *** * (st1[i]==st2[i]){
* * * * * * * *** * ** * *** * * * **** * ** * * ** ** **** **
** ** * ** ** * * * ** * * ** ** * ** *** *
* ** * * * * * * ** **
** *** ** *** ** * * * (cnt == len){
** *** ** ** *** ** *** ** * *** **** * **** *** 1;
* * ****** * * * * *
* * *** * *** * ***
*** * *** * * * ******** ** 0;
* ****** * * *
}

int main(void) {
** ******* ******* * *** ** st1[256];
**** *** * * * ** **** ** * st2[256];
* ** * * * * ** ** *** * *** *** ** * ** * st1);
* * ** * ** *** * * ** ** ** ** ** * st2);

* ** ** * ** *** *** * (prefix(st1,st2)){
* ** ** ** * * ** * * **** * ** * * * ********* * ** * *** * * * is a prefix of %s", st1, st2);
* * * ** ** * ** ****
* * * ** ** ** * * *
* ** * * * **** ** ******** ** * * * * *** **** **** is not a prefix of %s", st1, st2);

***** ** ** * ** ***** * * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* ******* ** * * * * **** * ** * **** *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* ** * ** * * * * * * **** * ** ** * * * * * *
* * * *** ** ** * ** *** ******** *** **** * ** ******** ** ** ****
* * * * ** * ** ******** * *** * * * ** * **** * * ******* **** * *** *
*** * ** * * ** *** * * **** * ** ** * ** ** * *** ** * * ***** * *** * ***** ****** * * ** * * * * *** * **** *** * * * is not a prefix of %s",a,b);
* * * * ** * * ** *** * ******* ** **** *** *** * ** * * ** ** * ** * * * **** * * *** *** *** * * * * *
* ** * ** ** ** *** ** * * ** ** * * *** *** ** ** **** * * **** * ** * *** ** ***
** * * ** * *** * *** ***** * * **** * * **** * * * ** * * *** *
* * ** * ** ** * * * *** *** **** * * ** ** ** **** ** ** ** ** **** * ** * ** * ***
** ***** *** **** * * ** *** ***** * * *** * **** * * * **** * * * * * ***** ***** ***** * * **** *** ** * * ** * is a prefix of %s",a,b);
* ****** * ** * *** * * ** ***** **** * * ** * * * ****** * * * * ** * * * * * * ** * * * * ** ** ** *** * * *
** *** * ** ** * * * * * ** ****** * ** ** ** ***** * ** * * * **** *** * * * **
* * ***** ***** ** *** ** * ** * ***** **** **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** *** * * ****** * * **** * *** * ** * * *
*** * * * ****** * ** * ***** *** * * *

**** * ** **** * ***** ** *** * * * * * * *** **** * *** * 0)
***** ** * * * ******* *** * ***** ***** * * * * *
*** *** ***** ** * *** * * * ** ** ** *** ** * * ** ** *** ** ** * * * * * * ** is a prefix of %s",pre,str);
* * **** ** *** *** ** ** * * * * * ******* ** *** **
* * * ** * * *** **** * *** * * * *** ***** ***
** * ******* * * * * ** **** **** * * ** ** * *** * ***** ** **** * *
** ** ** ***** * **** * **** * * * * * * ***** * * ***** **** * * * * * * ** ****** * ** * * * is not a prefix of %s",pre,str);
* * * ** **** * *** * * ** ****** * ********* *** * *

* * *** **** ** ** ** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**** ** * **** ***** * **** ***** a[100];

* ** * **** * *** b[100];

* *** ***** * * * * ** ** i = 0;

* *** ** **** *** * * prefix = 1;

* * ** * ** * * **** *** * * * * a, b);

** ** * *** * * ** * len = strlen(a);

* * * ** * * ** * **** * = 0; i < len; i++)
**** * * * * **** *
*** * **** ***** * * ** *** * *** **** ** * != b[i])
* * * *** *** ******** * * *** * ********** * * *
* ** *** *** * ***** * ** * ** **** * * * * ** ** ** *** * *** = 0;

*** ** ** * ** * ** * ** *** *** ** * * * * *** ** * * ** ** ***** * is not a prefix of %s", a, b);

* ** * ** ** * * *** * ** ** * *** * * * * **** * * * **** ** ***
** * *** *** * * ** * *** **** * * ****** *
* * * * * * **** * *
* ** ** ** *** * * ** * * ** == 1)
* ** * * ** * ***
* * * ** ** ** * * **** * * ** * * * * * * *** * ** is a prefix of %s", a, b);

** * * * *** * ** ** ******
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** ** ** **
#include * ** * * *** **

int main()
{
* ** ** * * ** * a[100],b[100];
*** *** * * * ** * ** i,j,prefix = 1;
**** ** * ** *** * ** *** *** * %s",a,b);
** * ***** * *** ** len = strlen(a);
* ** ** * * * *** *** ** = 0 ; i < len ; i++)
* * * ***** **** ** *** *
** * * *** *** * ***** **** ** ** * *** ** != b[i])
* ** ** ** ** **** ** *** * * * * * * **
*** * * ** * ** ** **** ***** * * ** * * * * * * ***** ** *** * * = 0;
** * * * * * ** * * ** ****** * ** ** ***** * * ** * ******* ****** ** * is not a prefix of %s",a,b);
* ** * ******* ** * ** * * **** ** ** ** *** ***** **** * * * ** * * **
* ** ** * * * * * * *** ***** ** ** **** * ** **

** ** *** **** *** *
* * *** * * * **** ** * ** * == 1)
* ********* ***** ** * * * * * ** * ** * ** *** ** * is a prefix of %s",a,b);

 
* **** * ** ** ** ** 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *
#include * * * *

int main()
{
* * ** ** ** * *** ** * a[100],b[100];
* ** ** * *** * i,j,prefix = 1;
* *** * *** ** * **** ** * *** %s",a,b);
******** * *** * ** * len = strlen(a);
* * *** ** * ** * * = 0 ; i < len ; i++)
* * * ** * **
** *** **** * * *** ** * ** *** ** ** * *** * != b[i])
* ** ** *** * * * * *** * *** **
** **** ***** ****** * * * * **** * * * * * ****** = 0;
* *** ** *** * *** * *** ** * * * ** ** ***** **** * * * *** * ** ** * is not a prefix of %s",a,b);
* *** * *** * * * * ** ****** * * * **** ** * **** *** *** ** *
** * *** * * * * ** * * *** * ** * ***** *

* *** * * ** * * * ***
*** *** ** * * == 1)
*** ** * * ** *** * * * * * * ** * *** ** ** * * is a prefix of %s",a,b);


* * ******* * * ** * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include *** * * * *
#include **** ** **

int prefix(const char *pre, const char *str)
{

* ** ** * * ******** * ** **** * *
*** *** * * * ** ** *** *** ** * *** ** *** * * 0;
**** ** * * ** * * ** * * *** * ** * * *
* * * *** ****** ** * * ** * * **** ** ** * ** 1;
** ** ** * * * * ** return 0;


}

int main()
{
*** * * *** ** ** pre[100],str[100];
*** * * * ******
*** * ** *** * ** * * *** * * * * ** *
*** * ** ** ** * ** *** ** * *** * *
* * ***** * ** ** **** * ** ** * *** ** * * *** * **** is a prefix of %s",pre,str);
** * ** **** ** ** * **
*** * ** ** *** **** * ** *** * * ** * * ** ** ** *** is not a prefix of %s",pre,str);
** ** ****** *** ****** * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**** ** * *** * * * * ** * c;
** * * ** * * ** * ** * **
****** ** ** **** ** * * * * **** **** * 0;
* ** *** * ** * *** *
* ** ****** * * **** *** * *
* * **** * * * *** ******* * ***** *** ** * ** * * * ** ******* * of a string
* **** * * * ** ** *** ** * ** **** ** * ** ** ** * * ** ***** ***
****** ** * * * * **** * * ** ** * ***** * * ** * ** * * * * * ** * ****** * ** * * ***** 0;
* * *** * * ***** * * * * ** * ** *
*** ** ** *** * * *** ** ** *** * * ***** *** 1;
    }
}

int main(){
* ** **** * *** a[100],b[100];
* * ** ** * **** * ** *** * %s",a,b);
** ** * * * * ** ** ** **
***** * * * **** ** * *** ** * ** * ** * **** * is a prefix of %s",a,b);
** * **** ** * *** ** *
** * ** *** ** * * ****** * * *** ***** **** * * * is not a prefix of %s",a,b);
* * * * ***** ***** * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * * * ** * ** p[100],s[100],a[100]={};
*** ****** * ** * * * ** ** t;
* *** **** ** ** ***** ******
* * * *** * ** ** *** *** ** *
* * ****** * * * * ** * ** * %s",p,s);
***** **** ****** * *** *** ** *
* *** * * ** ** * ** * *
** ** * **** ** ** ** ** *** ** **
******* * ** * ** * * *** *** * **** ***
* ** *** ******* * **** * *** ** *
* ** *** *** * **** * * ******** ** * * ** * * ** * ***** is a prefix of %s",p,s);
*** * * ** ** * **
** *** * ** ** * *
* * ** ** ** * ** ***** * *** * * ** is not a prefix of %s",p,s);
* * * * ** * ** * *
* ******** * ****** * ** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.244
©2016-2024

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 5.7k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 5.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users