1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ** * *** * * *
#include  * *   ** * *   

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** ** *     *   ** ** *   
 
*  * ** ***** ****  *    * *   ****   *  *  * **   * ******   
 * * * **  * *    *  **  *   **   *  *
**** * **  **  ****  **********    ***   * *****  *    *  == s2[i])
*   *  **   **    *** *   *   *  ****   ***    **      **  
  * ***  ******  ** ** **   **** **  * ****   * ***  *  *** *** *  ** ** *      * ** ***  *
** ***  * *  ***  *    ** ***     *  *** * **  *   
 
**   ** *** *     **** * *  **  *
 
*   **  * * ***   **        **  == length)
*** * **   **  ***   ** *  * ***
  * **   *  *  **  * ** * ******   ****    * ***   *  *** * ** * *   * ***   * is a prefix of %s",s1,s2);
   ** * * ***  * * **   * **  ** ***  
 
*  *  * ******* * ** * * ** * *****     *
**  * *** ** *  ** *      **  **** 
 *  * **      *   ** ** * * *   *           *   * ****    ** *  ** * ****  is not a prefix of %s",s1,s2);
 ******* *** *   **** ** ** **** *  
 return 0;
 ** * ****  **** * **   * *****     
 }

int main(void)
{
  ** * * * * *  *  *  *   ** s1[100];
*   ** ** **   * *    *    **  s2[100];
 ***   ** * ***  *  *    *  i,j;
*          * ** * * *     
*  * * *  *** *   **      * ****    **  *  ***  * ***    s1);
 **  **** *** * *  **   ***** ** **** *  s2);
*    ** *  * *     * * ** 
*  * **  ******** ** **   *****   
   *  ***  *** ** *  ** ** ****
 **  * ** **        **    ** *  *** *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  ***** **  
#include ****   *  **** *

int prefix (char st1[],char st2[]){
    *  *         *    * * *  * *   len=0, i, cnt=0;
 ** * *     **** * ** **  *
  ** ***  *   ****     * *** = (unsigned)strlen(st1);
 * * * * *  ***** ***** 
*  **   *  ** *** *  *** *   (i=0;i<len;i++)
      *  *  **   * ** **
*  *   * *** *   (st1[i]==st2[i]){
* *  * * *****   **  *  ****  * *  ***  ** *  ** * **   * *    *  **  ***** * **
*****  ** * ***        * * **    *  * ***** * *  ********
   ** * * * ***  **   ***** 
*  *   **  ***** **  * ** (cnt == len){
* ******* * *** *  *** *****     ****  ***    **  *  *** 1;
* *     *  ***** ****  * *
   *** *  *  ** *  ** *
*** **  *     *  ****    *  0;
  *  ***** ****  *  ** *** 
}

int main(void) {
* * * * ****   ***   *****   st1[256];
 ** **** ***  ** *    ***  *   st2[256];
*****   ***** *  **   **** ****  * ** *** ****    *****    st1);
   *  ********  ** *  **  *   ** *        * *    st2);

  ***  *  ** **** * *  **** *  * (prefix(st1,st2)){
**  **  *  *******    *         * ****    **   * *  *    **** * ** ***** is a prefix of %s", st1, st2);
*** ******* *     *        
 * ***       **      *  ***  *
*   *** ***** **   * *  *  *    **    ** ***   *  ***  *** * is not a prefix of %s", st1, st2);

 ***   * ** ***   * ** * *  *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*   * *  ***       *****   ***  **  *** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
   * ***  * *  ** *  * * *   *** ** * *** * * *** **  * ***
*** *  * *** **     * ****** *     * * *  * * ** * ****   * * ** **   *  * ***  
****  *  * **** **  ** **   * *   *   * *  * ** ** ****  *** * ** ***  ** *  *     *  *  *  ** ** * ** *
  ***  * * **** * *   *       *     ** *  *   ********* * *** * * * **    **   **  *** *  ******    *   * **  **  * * * * **  *  *  ** *** * ** * * is not a prefix of %s",a,b);
   ***  ***  **     * **     * **  *  *    ** ** *  *********  **** ***        **   *   **     **    *** * * *  ********  * *   * *****   ***
*** **   *   *****  **   *  *** **    ****** * ******** *  *  *   ******    *     *  *  ****    ****** * **     ***
 *  * ** **  *  **  * *** **  ** *  *   *  **** * **    **** * ***  ****    *  
    **  *** ** ** *  *  * *    *     *****      ** *      *     *  **** *  *  ** * ***     *    *    *
 ******* ***  **     **** * ****** * ***** *  *  **** * ***   *  * *   * * * *  ** ****  * ***  *****        ***  **  ** * * * *     * * *  ** ** is a prefix of %s",a,b);
*   *****  *****     *    **   ****  ** *    **    * ** * *  *      **     ****   * * **  *    *** *  * **    *  * **
   **  **** **  *   **** *  * **    ** *  ****** **     ***  ***** *  **** ** **** ***** *  ** **** **** * ***
  * * *      *  * *   *   *   *** *    ** **  ** * ****  




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 ***   * *  *  *  *  *  ** * * *   *** ****   **
  ** ****   * *** ** **   *   * *  * * * ** *

 * ***  ***  * ** * *   **  * ** * *  * * * * *   ** * *  ***** *  ** ***    ** * * * 0)
* *   * **  * ****  ***  *  ** **  *       ***  *** *  ** *** * *****  * 
  **  * *   *  **   *** *** ** *   **  *     * *****   * ***** **    **      ****  ** ***    ***  *  *  **  * ******  is a prefix of %s",pre,str);
 ***  *** *   *** *  *  * *   **        ****  *  * *    **   **** *** 
 *****      ** ** * *  ***  * ** ** * *  *      *****  ** 
**   ******           **** **  ****   ***  ********   * **    * * *  *   ****      * **
**** ** * **  * * ***   * *** *  ** ***    ***  * ****   *****   * *** ***** *    **    ***   *  **** * * **** **  *  * *********    is not a prefix of %s",pre,str);
 ****  ** ** *   * ***   *  *** ***  ** * * **  ***       * * **   * *   *   *  *  

*    * * * **  *****  *   * * **   0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 **     *  ** ** ***      ***  * a[100];

**  * ****** * * ****  ** *       b[100];

* * *  *   **  *  ***  **  i = 0;

    ** * * * ***  ****   * prefix = 1;

 * *     *  ** *  **     **  * * ** ***  **   * a, b);

**  * *   **   ** *****  len = strlen(a);

*   * **     *   ****      **  = 0; i < len; i++)
**   **  ** *    ** * * *  *****
********* *  ** * *  **        * * *  * * *  ****    ** != b[i])
* * *  *  *  ****** *  ***** * * **   ** ****  *  *******    *
 *  *   ***  * **  *  *****   ******     *** ***      *    *  * *** **  **  * *      = 0;

*  *** **    **      ** * *   * *  *   * * **** *    ***           ** ***    *   **  ** * **   is not a prefix of %s", a, b);

** ** *** *   * *        * * * **  ** *  * * ** ******** **       ** *   ** *  
   * ******    *  ***   *** *  *    * ** *  **   **** * **
*    **** * * * ******   
   ** ***  ***      *** *  *** *  == 1)
     *  ****** *** *   * 
     **  ***   *  *****   * *   *  *****    **  **********  *  *  is a prefix of %s", a, b);

***  **       * *** *  * ** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *   *     
#include **      **** ***   

int main() 
{ 
 ***** *   *****  *     * **  a[100],b[100]; 
 ** ****** * * *  *      ***** ** i,j,prefix = 1; 
 **      * ** **     * *   ***  ** **** %s",a,b); 
 ** *   **  **   *    * *  *** len = strlen(a); 
**    ** *   *  * ** *  **   = 0 ; i < len ; i++) 
  *** *    *****     *   * 
**   *    **   ** *  * * * *  ** **  * **    ** != b[i]) 
**  *    * *    * * **    **** * *** * **   *  * ** 
 ***  *  ***** ***   ***  *         * **********  ** *  *****  * *** ***   **      *  ** *  = 0; 
**   * ****    **   ****   **   * * * *    ****   ******** *  **  * * ****** * *      *  *   ** * is not a prefix of %s",a,b); 
* *  ****  **  **  * * ****   ** * *   ***  ***** ** *       *     *  *   ***** *  * * 
* *** *   ***  * *  *    * *   *         ** *  **      *  

     ** * *  ** ***  * *     
  *  *   **  *  *   *  * *   *  * ** == 1) 
   ** *     *   *     *****     * *** *** *  * *** * *   *****  *   * is a prefix of %s",a,b); 

 
*** *   * *  *  * * * ***   *     0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *    *   * 
#include *  ***    * **  

int main()
{
 *   * **** ** ** **    a[100],b[100];
 ** *****  **    *** * ***  *    i,j,prefix = 1;
 * ***    **       *****  *  *  *** * *  * %s",a,b);
***      **  *   *   *** len = strlen(a);
   *  * ***        ** ***** **  = 0 ; i < len ; i++)
    **   * ***  *  * *** *  
   ***  *** **  * ***    ** **** *  **    *  *   *** **    != b[i])
* ** *    *  *   *** ***  * * ***** * *  * * *   ****   **   *** 
* **  **** * *** *  ***   ** **  * ** * *** ***   *   *     *  *  **  *  ****** **  = 0;
 * ** **** ** * ** *  ***** * *** **  ** * *   *  * * * ** **  ****** *** ** *   *      ** * *  ** * is not a prefix of %s",a,b);
*   **   * **     *  *     ** *  ****  * *** **** *   * * ** *  * **     * ***** 
***  **  * *** ******** ***   *  ******    ** *    *** 

      *  **   * *  *  * 
**  *** *  *  ** **  * *** **   *    * == 1)
****** *     *** ***       **   ** *   * ***        * * *** ***    *   is a prefix of %s",a,b);


 *  *** *****     *  ** **** * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  *** * ****
#include * *   ** * **    

int prefix(const char *pre, const char *str)
{

*** *    * ** * * ***** *    * **    ** * *   
***** ** **   **** ** ** *   *  *     **  ** * *   *  **  * **  0;
** *** *     * *  **  * **  ****       ***** **   * **  
 * ****  ** * *     **   **** **  * * ***  *   **     *  1;
* * ********  ** * *    ** * *** * return 0;


}

int main()
{
   *  **     ** * * **  *****  pre[100],str[100];
****  * **   ****     * * 
* ****   ***   ***  *    *  ***   ******** ***
*   *  * **   *   * *  *  ** **   ** * 
** *  ** *  * ** * * * * *     * *    * ****** *** **  ****    is a prefix of %s",pre,str);
 *  *   **** * ** **   * * **  
**** ***** ***   **  **   ***  ** * * *  ***  ** ****  * * *   ********   is not a prefix of %s",pre,str);
  *  ** ***    *  ** *      ** **   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 ** *  *****  *** **  *  * c;
 * *  *  * *  ** *       ** **  **  * *   **
    * * * *  *  **    *       * * *  *   *** ***  *  **   * 0;
*   * **   * ***   * **  *  *
  * *** **  *  ** * * *   
 **      ** *   ** * * * ****   * *  ** **   *  * ***   * *** *     ** ** **   *   of a string
 ** ****    *  **      * *  *      *** * *** ***  * * *   **** **  * *   ***** *** *
 * *    ** **  * *    * *** **  *****  * * * **  * * *****    *   ***  * *          **   *    * *  *** * **     * 0;
 ** *     * *** **   *  ** * *  ****   ****** * * * *
 *  **  *  **************   *   * *   * * **   *** * *  **   1;
    }
}

int main(){
*  **   ** ** **** ** ***  a[100],b[100];
    * *    **   **   * **  ** ***     * %s",a,b);
* *****  **  * ***    *** **   * *** 
  **  ** * * * * ** ***   ** * *   **  **   *** ** * ***  * is a prefix of %s",a,b);
 ***     *    **** *  *** *   ** *
  *** * * ****  **    * * **** **   *** * **  *******   **   *** *    is not a prefix of %s",a,b);
*** * *   ***   *     ***** *  ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
     *  **  *    *  **  **   * p[100],s[100],a[100]={};
    ** *    *** ***   ***        * t;
*****  *   **** *   * **** *** ****  *   ** ***
  * *****       **     * * * ** *  *     *
**  *     *  *  ****  *  *    ******** ** %s",p,s);
*    ** ** **  *  **  *  *  *  *** ** *
 *     ** *    *** ** *  *****      
 * * * **    * **  *        * *     ** ***
  ***** ** **    *       **** * *  ****   
* * ***  ** *** ** * ** *****    * *  
    **** ** *   ** *   * * ** *   ****    * ** ** ******   ***  *** is a prefix of %s",p,s);
* ***** * * * ** ** **  * 
**    *  *  ***   ** * ** * ***
*  *  *** * *  *    **  ** * ****    ** ** *   **  ***   ****  *****  * * is not a prefix of %s",p,s);
 *****    **  **  **** *
*     *  ** * ** ****     * *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.99
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 12.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 11.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users