1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ***  * *    *** *
#include       **   * ** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
 *  *** ** ***      **  **
 
  **      *      *     *  * * *  *  * *** ***   
   *** * * ***  *      ** *
*   *  *   ** * *  ****  * ** *    *   *     **      * == s2[i])
 *   **  ***  ***  ***** * ***  **  **  *** * * **  * *    **
* *** * *  ** * *     * ****  **  **   * ** ** ** *** **    ***   *    ****** * ****  *** *  * *
**   *** * *  * **    **     *  ***** *  ** * *** * * * **  
 
  ****** *   ** **     **     **
 
* *  ** **** ** * ** ****  *****   * *** **  == length)
*** **   * *  *  *******   ***     *
***    * *     *      **  **    * *** *   ** * ** *** * ****   *  **   is a prefix of %s",s1,s2);
   ** *   ***  *   *  * ***** ***   
 
 *** **** ** **  ** *****      ** 
    *** *** * ***  * * * *   *  *** 
 * *  * ** ****   **** *    *    * **   *  *  ******  *  *** **   is not a prefix of %s",s1,s2);
** * **** **     *    * ******  **  *
 return 0;
***     *  **   *   **    **     * 
 }

int main(void)
{
* **  * *  **** * ****     s1[100];
  ** **     ** * *** **  *  s2[100];
*  ******     **** ****   * *  i,j;
 *** *** * **       ** **  *  
*   **     *  *    * **   * *    *    **   *  s1);
** **** **    **  * *  ** *   *  * * * **  *  s2);
*** *  * * ** *  *  *  * 
 *   * ***   **  *  ** *** *  *** **   *
*******  ** * **  *********   * 
* ** **  * *  *   *   **   *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***    * * ***  
#include * **   * *     

int prefix (char st1[],char st2[]){
 * * * *  ** *  * * **  * **   len=0, i, cnt=0;
  *** * *  ******** **
 * ***  *   * *  **** *** *** = (unsigned)strlen(st1);
***** *  *  * * *  **  ***
 ***  * **  *     *   **  * *** (i=0;i<len;i++)
** ** *  *****   *** * 
*  *  *** *  (st1[i]==st2[i]){
*       ****  *** *  * * ** *** ** **  ** * ****        ****** **    **  **** *  
* **** ****     * *  * * * *   ** *  **  ****** *  * **
* ** **  *** *  ** * ** *****  
**** * **** * * *   ** ***   (cnt == len){
** * *   * ** *** *****  **  * *    *   **  * ** *    **     1;
* **   ****** * ** * * **  
*  ** ** *  * * * ***  * *  *
   ***  *** ** ** * *   *** **  0;
    ** **  *****  *** * * **   
}

int main(void) {
** **** *     **  ***** * * st1[256];
 ** * * ** * ** *   * *** ** *   st2[256];
  ***  *  *  * ******** * *   *** *  *****  ** *** *  **  st1);
 ** *  * ***   *** ** * ***** *  *  ***         ** * st2);

   *  *  **   *    *** *   (prefix(st1,st2)){
** *   *     * * **  ** **  ***   ***** * *   *  **  *   * *      * **    * is a prefix of %s", st1, st2);
  ** ***   **  *** **     *** 
**     *  **   *     ** * * * ****
*     * * **   ****   *** *  **** ***   * **    **  * * *      *  is not a prefix of %s", st1, st2);

*      **   *  *  * *  ***  ** *** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
****    * *** ** *** **     * * ** * *     **   
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 *** *  * *  ***   * * *   * * ***** ***   ***  * 
** * ** *  *  ********   *  * *     * **     ** **** *    *  *     **  *  ** *** ** *      
 **    ******       * **  *    ** *** ** *     *  *  **         ****  ***** *  *  * ********* ****  ****** 
*  ** * *****  * **    *      * ** *   * ***  * * ** ** **  *  *** ** ***   * * ** *  * *      **  ********   * ***   *   **      **  **** is not a prefix of %s",a,b);
  * **  * *** **** ***  **     *****  *  *  *    * *   * ***  *  * **** *   **   ***  **  **   * * ***  *  ****  ** ** *  ****    *** 
** *    **** ** *   *** * * * * ** **  * * **         *** *   * **  **** ***    *     *  * *   * **  ***   ***    *  
****  * *  * * * **       **   **    **   ***  ***   ** *  ***  * ***   * ** * **
   *** ***   * *   * *********  *  *****    ******  * ** *   *  * ***      *  ** *   **      *** *      * * **** * 
***   *  *  * ** *  *   ****    *  *  ***  ** * * *      ** *** * * ** *** *** ** * *     *   * ** *     * ** * *    **    *** *  * *****  ****  *   **   *** is a prefix of %s",a,b);
 * ****  ** ** ** **** * * *** ** * **  * * **** * ******* *  **    ** *   * ** * * *  **    *   * * *  * *    * * * ***** * *   **  **  * ** * * * * 
 ** *** **  ******   * *   *     * *    ***    * *   * **    **    *  ** *   * *** *    *  * **   *  ***
    *** ** ** **     *   **  * *** ** ***  ** * *  




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
  * *   *   * *   ***  *  ** * **  ***  *  * *  * * *
*** *      **    ****   ** *    ***  *  ** * ** * **

*  ****  *** * **  *       * ****  ** * ** *** ** **** *** * *** *     * **  *   *   0)
   *  * *  *   *** **   ****   ** * * * **** **  *         ***  * * ** ****   * * *
      ** * ***    ** * **   **** ***  *   **  **** ** *****  **** ****   *  *** **  *  ** *** * ** * * * *  *****  *  is a prefix of %s",pre,str);
 * **  * *   ** * *  * * ***      *   * **   * ** *     * * ** *  * *
   * **    * ***  ** ** * * **   *     * ***  **  *   * *   *   
*   *     * ** ***  ** *** * ****  * ** **** *   *  *   *  **** **** ** * ********  
     *  **** *  *** * * ******* **   ****   * * ** *   *  * * * ***  *  * *   *  * *  * ****** * **** ** * *   **** * is not a prefix of %s",pre,str);
* *   * ****    *    *   * ***  * ** **   ***  *    * **   ** ** *  *   * ***** * ** 

**  * **   ** *** *     **** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**  **  * ** *** ****** **  *  * *  a[100];

* * **  ** *   *** *  **  b[100];

  * **  *  *  *  *     ****   * i = 0;

 *** *** **  ** * *  ***    * **  prefix = 1;

****** **** **     **  * * *  ** * ** *** a, b);

*   * ** *****    *   *** len = strlen(a);

*** *    ***  * **  *  ******** = 0; i < len; i++)
**       **  ****  *  ** 
**     **  **** ** ****   * ***** ** *   * *  * ***** ***  **** != b[i])
* *   ** **    *** **    *      * **   ***  * ** * * * * 
** *  *   ***  **** ***    * ** *  *  * *******  * *  *  **** * *    *    ** *    = 0;

    * *  *** * **    **  *** * ** **  * *  **  *   **    *     ****** **** *  **      *  is not a prefix of %s", a, b);

* * * *   ** *  *   * ** *  **   *  **  ***   **  *  * *   *  **     *   * * *  * *   ***  ***
* *   *** *     * *  * * * ****   ******* *  **  *****  **  * 
***** * ** *****   ** *   *** * 
** ****  ***  * * * * * **** *  **  **  == 1)
 ***** ** * ** *****   **    
****   *** *  *   **   ** ****  * **   ***  * * *  * *    *  ** ** is a prefix of %s", a, b);

 * * * *****     * * ** *      *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * *** ***  ** 
#include ** ** ***** * 

int main() 
{ 
** ** * **  ** *    *  *    a[100],b[100]; 
 ** ****  *  * *   *   *****  i,j,prefix = 1; 
*    *    ** *  *   *    **** * ** *   %s",a,b); 
* **  * * ***  * * ***** ** len = strlen(a); 
      *  *****  *   * = 0 ; i < len ; i++) 
****   **   **  *  *   **  *    *** 
* * ** **    *** *  ** ** *  *  *       * * *     **    != b[i]) 
** *   * * *  **  ****** ** **** *   ** * * * ** * * 
****** *    *   * *  *   *   ******  *     * *  * * * ****    ** * *   *****   **      * * = 0; 
* *   * **  ** * *  * **  *** ** *** ** * * *  * * *  **  ****  **  * * ****        is not a prefix of %s",a,b); 
** *  ****     *   *** ** * *       * *        *      *  *   *****   **   ***** ** 
**  ** *    ***  * * *    *    **  * * ****   ***** * 

***   * ******  * ***  *     
**** ******   ****** * *  ** == 1) 
 **  ***   *    ****  * **  ***   *   * *  * * **  *  *       * **  *  is a prefix of %s",a,b); 

 
     *  ***  *    * * ***** * *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   *   *
#include         * ****  

int main()
{
  *  *** * * ** ***** **   *** a[100],b[100];
  *** **    ** ** ** ** * i,j,prefix = 1;
**       *  **        **   * **  *  *** %s",a,b);
  * **  ***** ***  ***  ** len = strlen(a);
*   *   * * *  ** ** *** *   **   = 0 ; i < len ; i++)
***  *  *   *  *  ** *  *   * *
*** ***    ** * *****  ****   **  * * ***************  != b[i])
*** * *  ***** * ****  ** **  **     *  **** ******* *
 * * *  * ** * *****         * **** *  **  **   *    *  **   ******* * **       *     = 0;
     *** ** * *    *   * *  * **** ***   **    *** ** *  **    *  **  ** **     **  * **        ** is not a prefix of %s",a,b);
  * *****  ******  ** *  ***   *  **    * * **    ***  *    *  * * * * ** 
** ***    * * **  *  * **** ***    * ****  * *   ***   ** ** **

* *** * ****    *     *** * 
*  **  ** * *     *  *   ** *** ** * == 1)
 *** * **     * **  ** *  ***  ***    * **   ** ******* *  * ** is a prefix of %s",a,b);


**     * * ** **  **  * ** * **   ***  0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  ** *** *   **
#include **   **   * *     

int prefix(const char *pre, const char *str)
{

 ** *  *    ****   ** * **  *  *   *   *   *** 
*     ***    * ***  **  ** * ** * ****    *    * **  0;
  ** * ****** ** **** **  * ******  ** * * ***   
* *   ****   * ***      *   *** *   * *  **     *     * * 1;
*  ***** **    ****        *  return 0;


}

int main()
{
*  **  ****   *     * pre[100],str[100];
  *** **  *       ** *  
*** ***    ** * **** * * *  *   * ** **   *  **** **** * 
 **  ***  * *****     *  ** * *  *** ****** *  
*  ***** **  *** * ****   * * ** ***   ***  **** *   ****  *  * * **** is a prefix of %s",pre,str);
*  **** * ** * ***  *  *  **  **
*****  * *    *** *  *  **  * **** ** **  **   * ** ** **  *    *  ** ***   is not a prefix of %s",pre,str);
 *  *  * * *  *   ***  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**   * ** **  *  * **  *  ******** c;
*  *** ** * ** ** *****   ******   *  *   *   ***
  *     **** ***   ****       *   ***  * *** * ** ***  *** *    * 0;
 ** **  ***      * *  **   *** *
 *  *  **  * *** *    **    
* **   * * *** ***** * *** ** ***  *  ***    * **  * ** ****** * *  *   *  *** of a string
* ***      ** ** * ***  *** **   *    *  **  * * ** * * ***  *  * * *  ***      **  *   *  * *
****   *** **   * *  ***** *   *   * ** * ** * * * ** * *   *** *     *  **  *     * *  * *  ***** **** ***    0;
 * ** ** *  * *** ** **  * * *  * ***  * *      **     
   * ****     ** * *     * * ** *    *   * * *** * * *  1;
    }
}

int main(){
  **  ****  ** *** ****  * ** * *  a[100],b[100];
*    * *  * *    *   ** *  **** *    * %s",a,b);
  ** *   * *  *    *   **  *   ** ***
  * *** **     *   *******  **** *  ***  * *   * * **** * **   is a prefix of %s",a,b);
 **** *   *  **  ******  * ****
 **** **   *    * * *****    ** * ***     *  *    ******* *   * * is not a prefix of %s",a,b);
 * *  * *  ***** * ** **   * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***    *  ** *****       *   ***** p[100],s[100],a[100]={};
     **  **   **  * *****     t;
  ******   * ***   ** * *   ***  ****
      * *** *** **   **  ***  *  * ** * *
  ****  ***   ***    *   * *   ***   * %s",p,s);
 ** ** * *  ***  **  * ** *    *   *  
**  *****  ** *      *  * *  *** * 
  * * **  ***  ****     *  * *    * * 
   *  ** *    ***   ***    ** ** ******  *    * *
    ******** **   *      *    * ** **  **
    ** ****** *  * ** *  ** ** ******      * *** ** * ***      *  * is a prefix of %s",p,s);
 *   *   *** *   * ****
 ** **  ***  ** *  * **   *** 
* *  * ** *** *   * * *  *  ** **  *   *   *          * ** is not a prefix of %s",p,s);
*  ** * ****  ** * *  ** * ** *
    * *********  * *      *** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.38
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 12.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 11.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users