1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ***     **     
#include  * **   * ** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
**  *     * *** ** *  **
 
** *** *  *  *   *  * * *  ***  *   *  * ***   * *     * *
 * *****   * ***** *** * *   *  
 **  ***  *     * *  ***    *   * ** * * ****   *  **   ***     == s2[i])
 *  * ******   **** *  *   **   *  *    * ***     ** * *
 ***  *** ****** **** *  *  *      **    *  **   *** *    * **   * ** ** ***   **  *  *  *     *  *** 
  **    ****   *  ****   *   * ** ** *     *** ****  ** 
 
  ********* *** *  ** ** * *  *   * 
 
          ****    ** * **** ****  * **  * == length)
 **    **   * *  * **     *****   
   ** *   *  ***  ****    ** * * ** **  **   **   ** *****  * * ***   *  *  is a prefix of %s",s1,s2);
  ** **   **  *  *    *** ** ** *
 
   ** *   * * **   ****   * 
** *   ** * * * * ** ** * ** **   
*  ****  **  * * ***  **    *   ** * * **  * **    ** ***  *******  *    is not a prefix of %s",s1,s2);
 ******* ** **  **  ** *    * 
 return 0;
 *** ** * ***** *****  ****** **  ***
 }

int main(void)
{
****   **    **   * **  *  ** s1[100];
** * * ** **    * ** *   * *  s2[100];
    ** **        **** *  *  i,j;
* * * ** *  *     * * 
* **  ** ** ** *   ******    ******** ** *******   s1);
 **** *    * *** *  ** **   *** ***    *   s2);
 **  ** *  ***  *    * *    ***
    * *  *   *    ****  ** * *** ** * 
   **      *  * ** *      
  * * ** *** **   *   ****   ** *  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ****** *   *** 
#include  **    *    *** ***

int prefix (char st1[],char st2[]){
** **** * *** ******** * *  len=0, i, cnt=0;
** *** *  *  * ** * * ***** * 
*   *** * ** *   ** **   *    * **  = (unsigned)strlen(st1);
* *   **   *** *** *  *  **
 * * * ** *****   *  * *** *** (i=0;i<len;i++)
**********   * ** *  **** * 
*** ****  * ****   * (st1[i]==st2[i]){
 ** ** * **    *  *   *** *   *** *** *   * *       * * * ** * ** **     *  *
    * ********     *  *    **    **** *      * *
*   * * ** **  **  ** * *
* *  *  *  *** *******    (cnt == len){
   *** ** **   **  **** **** **  * * **    *  * *  *  *  *   * 1;
***   **  ***   *** * *  *** 
 *   **    * *** *  **
        *** *   *  *  **   ** ** 0;
**** * ***** *   *  * *    * 
}

int main(void) {
   *** **  *  * ***** *  ******   st1[256];
*  *** * ***** ** *   ** **  st2[256];
 * **  * *    **  *  ** **  * *** **** ** ** *** *   st1);
   *** * ** **   *   *  ****** * ****** * ** *** st2);

 **    ** * **     *    *     (prefix(st1,st2)){
 **   **   * *  *****  *     ***   * ** * ** **** ** * ****   * ***   is a prefix of %s", st1, st2);
* ** ** *   ** *  *     * **  
 ** *** ** * * ****    *** ***
  * * **   ** * *  *    * * *  *  * **** * * *****   ** is not a prefix of %s", st1, st2);

*    **   * * * ***   * *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* **      **** *   ** *      *     * * * *** *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
   **** ***  *  *** ** ***  *  * ** * **  **** * * 
***** ** *  **   * ** *    *    * *    ***  *   **    *  *   * ***** *  * ***      ** ****
* * *    **   **** ****** *  *   *****  * ***   * *   *   **   * *  * ***     **     *** *** *  * *  * * 
*  **   *  ****  *  *** * **   * *    *   ***      * * ** *  ***    **  ** *  ** * * *      ***  * ***  **  *  ** * **  *   *   *******  is not a prefix of %s",a,b);
 * *   *    *** **  *        * *  *** *********  *** **   ** * *  ** **  **** ******* *** ** * ***  *****  ** ***   **   * *       *** **  
* *    **   *  **  ***  *   * * *   *    **    * *  *   * *** ***     * *   * ***  *    ** *   *** *
**  *  *** * * * **  * ** ** * ** **   ***    *** **   ***** ** *  *   * *** *   * *  
 **** * * **   * *  * *     ***  ** *  *  *** * **  *  **** *   *   ***  * * *      * ** ****** ** *** ** ***  *  *
**   *    *  * * *   *  **  * **    * **  *   * * *** *** *  * ** ** * ***  ***  ***  *  *  * * *** *  * * *      *   **  *   *   **     ** is a prefix of %s",a,b);
  **   ** ** ** *  *  * ** * * * * *  *   *** * **** *    * * **   ***  *  *     * * * **      **          **** *    * ** *** **  * * ******
    * *  * *  *****   ***  * * ***  **   * *  * *  * ** ****** **** * *      **  **     **** *  ** ** *   ***   
    ****  *      **  *** ** *      *     * *  * **  *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
   *    *   * ** *** *********  * ****   **     * * 
*      * *   * **    *** * ***** * **** * **  *   * 

* * ** ***     *****  ******  * ** *   *  **   * * *       **   **    *  0)
* ****  * *   **  * ***  *  **  *  **  * **    ** *  *  *   ** * *  **     ** ** 
  *  *      *****  ***  *  *  *****   *** * **   * * **  * * * * **  * ***  *   * * **  * *   * ** ** * **** *   *  * is a prefix of %s",pre,str);
***  *** *** ***  * **  ***     * * **  *** *     **  * *   ***    
** *  * ***  **     * *   * ** **  ******* ******   *  * * ** **
***     *** * *** *  ** * * *  ***     * * * **    ***  ** * *   *  * *      *  
  ***        * ******** **     ***     * *  * * *    *  * * * **** **   *  ******  ****     *   *    *** *** ** **** **  is not a prefix of %s",pre,str);
** *   * ***   ** **     ** *   *** *******  *  * ******  *  ******  ** *   * * * 

*    ******    ***** ***     0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*  ** * ***   ***      * *  a[100];

  ** **   *  ** ***  * * *  b[100];

*  **  ** * *  * *  *  ***** i = 0;

 ** *  **  ****  *  * **** prefix = 1;

 *   * **** **  * ****  ** *   * ** *** *  *   * *  *  a, b);

******   * *  *** * ** *   *    len = strlen(a);

*    *******     *   * * *  **  = 0; i < len; i++)
 *** *    * *  ***  *** *
  * * * * * ** *******   * **     * *** * * * ** * **   *** *   * != b[i])
 * *   ***  ***   *  ** * **  *** *    *    *** **  
* ****** *  *  * * * *      ******* ***  **** ** **** ** *   **** **     **      * * = 0;

 ** **     * * *  * *  ** * **       **** * ***  *   * * *  *****   ** *    ***  ** **  *  is not a prefix of %s", a, b);

 * * *  *** **     *********  **  *** * *   *  ****  * *  *   *    *    *  
 *  * * * ** *    ** ***  *   ** *  **  ***** ***
 **   **** * *** **** **   *
*  **     * ** * * ** ***  **  **** == 1)
* *** * ** ***  * * * * * * ** 
** *  ********   ***** ** *  ***  **   ***  *  *  * **        ** * is a prefix of %s", a, b);

 **  *   ** * * ** *  * *  * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *** * * *  *** 
#include *  **  ***    * 

int main() 
{ 
**  *  **   ***   *  *  * *   *  a[100],b[100]; 
  * *** *  * *  * *  **  ** i,j,prefix = 1; 
  ** * *      * *  *   *  *   * *** * %s",a,b); 
  *  ** **        *    *** len = strlen(a); 
  **  **    *  **  *  * **** = 0 ; i < len ; i++) 
*****  **   **** *       
** ** *** *  *   *** *** **    *** **       *    * ** ***** != b[i]) 
     *    ****  *    *  ****  **** ***   ******* 
**     *** ******** *** ** ** * * **** **    * *    ****    * ***  * *   * ***  *   ** = 0; 
*  ** *     *        **    *   ****     * ***  *   *   ******  * *  * * ***    *    * is not a prefix of %s",a,b); 
***  **      **      **** * *  * ** * **  *  **    *  ****    *** *   ** **   *   ** **  
 *    **   *  *     *  *   *  ** ***   **  * * *    *** 

 * * ****** *     ****    *  * 
* *   * *     **  ** **  * *    == 1) 
* * **  * **     *  * * * *  ** ****     ** ** ***** * * * *  *** is a prefix of %s",a,b); 

 
* *****  * ** **    * *  ***   **** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **** * * *   **
#include  * ** * *   *

int main()
{
 ** * *****   *** *   **   *  * a[100],b[100];
  **** ***  *   *   *  *     i,j,prefix = 1;
** ** * *   **    ***  * *   *  *   *      %s",a,b);
**  ** *  **** * * *  ** * len = strlen(a);
** * *  *   ** ***  ****** = 0 ; i < len ; i++)
*     *  * * **** **  *    **
 ***    *  **    ****  *  * **   ** *     **   *   ** **  ** ** != b[i])
* * *  *** * ***** *  * ** *****           ***** ****    *  
**         ******* *  *   * * **    *    *  *     **** *  * *   *  *****    ****    *** *  * * = 0;
 *   ** * ****  * *  ***    *     **  * ** *** **   *       *    ***  * ***     **  ** * * * is not a prefix of %s",a,b);
*  ****** *** *** ** *** ** ***** **** * **** * **   ** * ***  * *** ***** **   *
***  *   *   * *  **    * *** * * * **  *    ** **

 *   * **    *  * *   * * *
     ***  ** **   ****  * *   ****    == 1)
 **  *    **       ***  ***    * *           *  * *    is a prefix of %s",a,b);


* ***  *   *  **  * ****  ** *  * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **   * *  **  * 
#include      *   *  ** *  

int prefix(const char *pre, const char *str)
{

  ** ****  *    *    ***  *** *  *****    *     *
**  *  *******  * *  ** ** * * *   ** ** **** * * **  0;
****  ** **  * ***      *   *   *       **      **
*   **    ** ** *    *  *** *  **** ****** ******    1;
**     * *   ** **     ***  ** ** return 0;


}

int main()
{
** ** ** **   ** ** *  * * pre[100],str[100];
  ******   **   *** ** ** *  
 **** **** * ***  * **     * *  **   *   ***   *** * * 
   ********        ****   *** * *    
** *  *** *********  * * *  ** ** *  ** ** ** ******   *  *  *** *  is a prefix of %s",pre,str);
*    ** ***** *     * *
     * **  **** *   ** * ****  *    **      * * ** **  **    ****   *  **  is not a prefix of %s",pre,str);
***   ******     ** *** *   ****   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*  **   *   *  * *** * * c;
* * *  **  *****  ***     * * ** ** ***** ** ** 
**   *** ***** ***   *  ** **   *  ** * ***** *  ***    * *** * 0;
  ** ** * ** * *** **  * **  
 * *  **** * *    **      * *  *
** ***  *****     **       *  **  ** *    **     ***** *** * ** ** ****  *  of a string
 ** ***   ***  *  * * **  ***   *** *   ***** **  *** *    *  ** **  * * ** ***** * **    ****   *
 *  *  ** **       ******   *    **   * * * *******  * **   * ***** *  ** ** ******  ***      *   *** *** * *** 0;
 **** **   *** *** * *  *  * * ** * * * **  **    *  ***  
* ** *  * *   ** ***   *    **** ***    ** ****    *** ** *** ** 1;
    }
}

int main(){
**      **  * ****  *      ***  ***  a[100],b[100];
 ** **  *       *** *    ***   *     *    %s",a,b);
****  * *  * * **  **   ***** ****** 
  * * *************  *      *    *** **  *** **   *     * *****  **  ** is a prefix of %s",a,b);
 *** **  * * *  *     *   *   
 ** *    ** *  **** *****    *   ***  * ** * * * * *  *  *    ***    is not a prefix of %s",a,b);
****     *   **   *     *  *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***  * * *   * *  *** * *    *    p[100],s[100],a[100]={};
* * ** * ******  ** *  **** t;
* * * *** * *** **** *** *   **  **  * *
* ** * * *    * *   *  **** **  * *     
* * **  *** ***  * ** *****  * *  *** * %s",p,s);
   **** *   *  ** *** ** ** ** ***
**** * *    ** ****  **** ** **  ** 
     * * **   * **      * ***  ***  *** *
 **  * *   ** *****  * * *  * * **** ****
*** *  * * **  ** *  ** **     *  *  * **** 
*  ** *  **  * *     **** *** ******* *  *  *     ****   *** * is a prefix of %s",p,s);
    *** **  *** * *  * *** *  
** ** *  **  **  **  **    ** * * 
 * ** *   ** *  ****  *    * *   ** * **  * *  *   *   * * * is not a prefix of %s",p,s);
*    * *  ***** ****** 
  *    **** *    *** * * * *   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.39
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 12.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 11.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users