1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include *** *       ** 
#include **** * *** ** ** **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
 **   * **** ****  *** **
 
** ***    *        * **      **     **** **   *  **  
 * * *  ********** * * * * *** * *
   *   *** *  *  *** ** * * *  **   **  ** *  * ***   == s2[i])
**   **   * * * *     * *    *****   *** *  *  ** * 
*  *****  * **    * *    *  * * *** **     * *  **    *** * *       *** *** *   **  **
     **    *  * ***   ***    ***  ** **  *** ***     
 
 * *  *  ****    * *  **    ** * **
 
** ** **  ******  * ***** **  * * **  * * **  == length)
* ** *  * **    * **   *  ***
 * *    ****      ** * * ** ***  * *    *  ** ** * * ** ** ****  ** *  is a prefix of %s",s1,s2);
** * ** * ***** *    * **   * * 
 
 ** *  *   ** * **    ** * *   ** 
*   *  ***    **  **  * *     *   
** * *   * ****  ***       *   ****  * ***  ** **      *   ** *** * * **   *   **** *   is not a prefix of %s",s1,s2);
 **  * * ** *  *    ** *** ****   ** *   
 return 0;
  ***  ***** ** *  * * * * 
 }

int main(void)
{
*     *  * * *   * ***** * *  s1[100];
*   ****  *  **    * ****  ** * s2[100];
 *** * *    *  *  *      *** *  i,j;
 ******* *    *  ** *  * *
  *  *     ** * *  * *  ** *** *  *  * *   s1);
 ** * *  * *   * *     *        * *  ** ** * s2);
* ****    * *  *    ** **  
***   *  *** **  *** *  *  *    
 *  * * **         *  ******
 *  ***  * * *  **** *   *  *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *******   *
#include     *         ** 

int prefix (char st1[],char st2[]){
        *  * * *   *  *** * len=0, i, cnt=0;
*   **    *    **     ***  
 ** ****     *   ***   **  = (unsigned)strlen(st1);
* ****  **  * *      *   * *
*  *   * *  * *** ** * ***   (i=0;i<len;i++)
 *    * * *    *   **  * * *  
 * ***   ** (st1[i]==st2[i]){
   ***    * **  *  ** ***   * *   *   **** * *  * **      * ***   *** ****   *** **
   ***  * * ** * ** ****** **** **   *   * * **   *  
 ** ** * ****** ***   **
  * ***** *   *  ** *  *  *   (cnt == len){
        ** ** ** * *  * *  *  *   *  *   **   *  ****    * * **  1;
  ********* **  *** * ****   
   ** **     **  * ***  ******* 
* **** *** * *    **   *     **  0;
 ******* * * *  ** * **  ** 
}

int main(void) {
* ** *   ******   *  * ** * st1[256];
  * *  *** * *****     ***** **  st2[256];
     ** * * * *   ***   * * * * * * *     **  ***      ** st1);
***  ****  ** ***   *  **  *   * * *  *  *    *   * st2);

  *  ** *** *** * ***  * *  ** (prefix(st1,st2)){
 *    ** *   * * *   *   * * *** ******* *   ** *** ****   * * *  **  is a prefix of %s", st1, st2);
  ***  *     **   **     ** *  
  *   * **********  *  **** ** ** *   * 
 **   * * * ***  * **** * ****   **   ** * * * ** * *  ** ****** * * *  **   ** is not a prefix of %s", st1, st2);

  * *** *** * ********  *     0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* **  ***   *  *   ** *** *    * ** ***  * * * ******   *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
**  **** ** *   *    * ******* *   **  ** *  **** *** **     
 ***      **  * * *  ***  *** *   *** *    *  *      * *  ** *  *  **  *     * **  * ***** *
*   *       * *  ***** *   *** *  * *   ***   *   *  *  *** **  *** **    ******** ***  * * ** ***     *** 
  * **   **   ********  ***   *   **    **   ***** *  * *     * ***  **  ***  ** * ** ***   *    *  ****** *** ** *  * ***     ******* *  is not a prefix of %s",a,b);
     **** ***  ***  **   *** *** *** * *     *** ** * *  *  **     * *   *** * *  ***** * **  *  ***** *** * * * *   *** * *** *  
 *    * **  **  ***** **  ***  *  * * *    ***   * * * * * *     * **   ** **  *   **** *   **    * *   
* * *** * **** *    * * * ** * *  * * *     ** *******   ** **      *    * * ** *  **
*  *   *** * ***  * ****** *  *   *   * ***  **** *    *  * * *  *   * ** *** *   **   **** *    
 * *      ** * ** * ** *     **      ***  **      * ****  *  ***  **  ** ** *   * **    ** **  **  ***  *   ** * **** *** *  ** **  *  * is a prefix of %s",a,b);
*     * **  ***  ***     *******     ** *   ***     *    **   * *  * **     * * ****      ***  * ** * **  *      ** **   **   * ** * *  ****     * **** 
      *** ** *  * *   ** **      * * *** ** ** * **  *  ***  ****** **   ** *** *  *** ** **   * ***   ****    *
 *      ******    ***** *   * *  **  **  *   * 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 *****  * *** * ** ***   ** * **  **   * * *        * * *
*** **  ****       * ** *  *  ** *    **** **  * *  **

** * ****  ** * *   ****  **** *** ****  * *** **   **  *** * ** ** ** **     0)
*  *   **  *  * * * ** ***** * **   ***   *** * ** *  * *** *** **
  **  *    * *** ***  *   *     * *  * *  **   *****    **** ** ** ***** ***  * *  ***   ***     * **** *   ****   is a prefix of %s",pre,str);
        *   *** *  ***** **    *  * **    * *** **** *  **   *
**   *    * **  *  *****    **** ** ***  *  *  ** *** 
* **  *     * *   *  *  **  *  * *  * **   * ***  * ****  *** * * **   * *
 *  * *** * ** ** ** ***  * * **  * ****  ** * *   **   **** ***      *  * ** **   ** *  **** *** * ****    * ****  * is not a prefix of %s",pre,str);
** * *  *      *** ***  * * *    * * ** **  ** ******  * ** *** ***    ** * *** 

* ** *  **** *   **** *     * ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
  **   *  *  **** * * *****  **    a[100];

*  *    *   *  * *****  ***  * **   b[100];

    *  **** *** *  *      * *  i = 0;

  ** *   ***  * *     **   * ** prefix = 1;

    * **  ** ** **  *   *******  *   *     ****  * a, b);

***     **** * ***** **  ** * ** len = strlen(a);

**  * * ****  *** ** **  **  *  = 0; i < len; i++)
 ***** *  **  *  ******* * ******
* * ** * ***  * *  **   * *  *** * ****** * ****** ****  != b[i])
**  *   * *** *   * *  *  * **  * * *    * **   *   ** 
* ***** ** *   * ***     *** ** *** * ** *  ** **  **     **   * *****    * *    *   = 0;

*  * **** * *  ***  * *  * * ** **  ** * ** *** ***** *     **** ** *** *  **  *  *  *     *****    * ******   is not a prefix of %s", a, b);

 * ******   *******  **  *  ***  ** *   **   *  **          ** **   **  ***   * *   ** 
**  *  ******** ** * *** * *  * **   *  * ****  *
 ** ***   ** ****    ***  **
 * *  * **  ** * *** *    *** * ** **  == 1)
*    *  *  *   * * **       ***
 *  **** *** * *    *      * *  * ***  * *      * *  *     ***** *   is a prefix of %s", a, b);

   ***   **  ** * * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****   *** *  
#include    ***     * 

int main() 
{ 
     *  * *******  *  ****** *  * a[100],b[100]; 
  ***    * *   *  ***   * *  i,j,prefix = 1; 
* *  **** * ****** * **   **   *     ***  *  ** %s",a,b); 
** **         **             *  ** * len = strlen(a); 
*  **    *  **  * *  ** *  ** = 0 ; i < len ; i++) 
    *   ****** *   *     *  
* ** * *** * **** ***** *     ** **    ** * * ****    *   *  != b[i]) 
****  ** ***** ***** ***        * * **** *** 
 *  * * **    **   **  * *  * **  *** ***  * * *  * ** *    ***** * *** *** * **** = 0; 
      * * * * *** *    *  ** ***  **   *  *  ***    ** * *     *  ** * * *** *    *** *   * * **    ** * is not a prefix of %s",a,b); 
**     *   *  ** ****         ***     ** * **** ** **   ** **  *** * * **   *** **    *  
* ** * **  * *****  *   * ****  *  *   ******  ******  **** 

  *** *   * ***     **    
 ** ****  **  ***  **   *  * **    == 1) 
 **** *  *    * * * ** **  *  ** *** ****        ***   **  ***  * is a prefix of %s",a,b); 

 
  ** *  * * * ** ***   ** * **   0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *   **     *  * *
#include *  ** *  *** *

int main()
{
 *       ****** **   *  *  ****  a[100],b[100];
 ** *** *  *** *   * * i,j,prefix = 1;
**  * ******  *  *  * *  *** **** ** %s",a,b);
*******   ***** ** ** ** * * *  len = strlen(a);
***     * **    *  ** * * ** = 0 ; i < len ; i++)
* ** ** *  ** **   *  ********  
** * *  * ** *    ****  ** *  ** * * *  *      *   **  != b[i])
   *   **   *** **** ****  *  **  *** ** *  * ** * * * ** 
**  **  ** *  * * *  * **  ***     *   * ***  ***  **  * **   * ***   **  ** ***    *** ** = 0;
 * ** *          ** * *  ***** **    **    *  ** *    ***  *  * **  ***   **    * **  *  **  * is not a prefix of %s",a,b);
  * * ****  * ****  *** ** **  *   *  * ******** **  **  ***  *   ** *   *   ***   
***   *   **** ** * *  *   ** * *  ***   ******* *     ** * 

 *  *      *** *     *  *  *
****  * ***     *   *   * *  *     == 1)
* *   * *  * ** **** *    *** *  *   **   ** **** **  * ** *  *  *  is a prefix of %s",a,b);


 *** * * *** * * *** *** ** **** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * * ** **
#include *** **     * *****

int prefix(const char *pre, const char *str)
{

 **  *     * **** ****** *** ***       *    *     *   
***  * *******  * **  **   *   *** * ** *****   *     ** 0;
*** * **** ** *  *** *  * * **   *       *    **  
  *** ****  *         *   ** *   ***** ** *  * *** * 1;
* *   *   ** *   **** ******  * return 0;


}

int main()
{
** *    ******     *****   *  *  pre[100],str[100];
  *  * * *** *   ** * 
**  *** *** **  * *** *  **** *    *  ** *    * * ****
  * *   **  * * ****  **** *** * ***
*  *** *** ** **   ** **    *** **  *      * *** *   *  *   *  ***  is a prefix of %s",pre,str);
  *   * ***  * * **** ** ** *
 ** **   * * ******   * **   * *****     *  ** *** ***  *  *    is not a prefix of %s",pre,str);
* *  *** ** *  * ** ***  * **   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
** ** ** *     *  *** ***    c;
*  *****   ***** * *  *  * * *  *   ***   ****    *     
*** * * *  ***** * *  ***    ***  **** *   **   *  * *  **      0;
* *** *  **      *   **    
   *   * ***** * ****    ***    *
    *****   * ****   *  ** ****** ***   * ***** ** ** *****    * * **  * * ****      of a string
   *   ** * * * **  *    ********* ** *  ******** * *   * * * ** * * ******* *** **  **** 
* **  * * *   **   **     ** *      ***  ** *     **  * **  *     *****  * *   ** **  *** ***** **** *    ** **** 0;
   ***  **  **  **  * *      *  ***   ***       ***
  **  *    *   ****** * *   *** **** *  *  *** ** *** * *  1;
    }
}

int main(){
 *** **  * *  *   * *  *** ***  a[100],b[100];
    **  *****  *  * *** *     ** ** %s",a,b);
* *** *   *****  ** * *    *  *  
*** * ***  *   *       * * *  *******  * * **  * **  * * * ** *   is a prefix of %s",a,b);
** **   *****  ** **  *  **
 *** * *   **  *  * *** *  ***    * *** *** * ** * **   ***    *   is not a prefix of %s",a,b);
*  ** **  * * **   * **   0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 **  ** *** *  *  *   **     p[100],s[100],a[100]={};
** *****   ** ***  *   * t;
    *   *** * *    ***** ***  *** *    **
* ** * * ** *   ********   * ********
 ***  ***     ****   **   **   ** * * %s",p,s);
   * *  *  **  * ** * *  *  ***
     *    * * *  *   ** ***    * *  **  
   * *    * *      *******   **      * 
*  *      **  *  **  *  *  ** ** *   *     *  
   **  * **    *    *** *** *      * ** ** ** 
  **  **     ***  * ****  * ** *    *** *  *  *    ***       * is a prefix of %s",p,s);
 ****   *  *   *   ** * * 
**** * * *  * *   ** ***  ***** 
** ******  ***  *  *  **   **  * *    ** *  ***   *  * **   * * is not a prefix of %s",p,s);
 **   *** *     * * ****
 **    * ****** * * ** ***** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.1.149
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 9.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users