1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include **  ****    
#include    ****  *****    

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* **** * * *    * ** 
 
**    *** * ** ***  *****  *  *   * *** ** ** ** *****
  * *  *** **   **       *  * * **   *
 ** * ** *** ** *  * *   *     * ***  ** *   **   ****** == s2[i])
** * **  *****  *  *    *** *** *  *   *    * ***** *** * 
 ** *  ***         *  *  ***       * *  ** * * *  * **** *** *  * ***   *  * * 
****    *    ** **** ** * * * **  * * *  * ****  *** ***
 
  ***   * ******  **  * *  ** ***  
 
    *  *   *  **   * ** * ***  ** * == length)
* *  ***  * ** *  * * ** *   ** *  
 ***   *  ****** * *  **     **  ** * *  ** *      **  * **  **  *** ***  * **  * is a prefix of %s",s1,s2);
   **  ***     * * * **** **** *
 
   **  ***    *** *** *  ***  *******
 *  **    *   ***  * *  **  
   **  ******* **  * **  **  * *  ***     * *  * *  *   ** ****   * is not a prefix of %s",s1,s2);
 * * **   *  * *** * ****   *    ** 
 return 0;
     *   **    * * **  *** **** *   ****
 }

int main(void)
{
 * *  * ***     *    * * *** **  s1[100];
  *** **  *** *  *   ****   *** s2[100];
 ***** *  * ** **** *  ***     * i,j;
** * ***** *  *  ****  **
 * * **  ** ** *  ***    **  ** * * *  * *   * * *   s1);
  *    ***  * **    **    *    *** ** ***** *  ** s2);
 * ** **  ** *  * **   *****
*** ***** ** * *  ** * **** *  *** *** 
*** * *   *     ** *  ***  
* * ** *** ****  ** ** * * *  **  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  ***   * 
#include   **   * **

int prefix (char st1[],char st2[]){
  * * *   * *  * * *    * ** len=0, i, cnt=0;
** *** **   * ***  ****  *
 ** * * * ** ***    ***   * ** *  * = (unsigned)strlen(st1);
**** **   **  * ** **  *
**   **  * ***  *** ******  * (i=0;i<len;i++)
 *   * ***** **  * *** *  **
 ***** **   ** ** (st1[i]==st2[i]){
*** * ** *    * ** **   **** * *  ** ******** * ** * *  *    ***** ** *** * * ****
 * * * * ***  ***   ** * * * *     *******  * * **** 
    *  ***** * * **   *** *
  ******** **    *   *** * (cnt == len){
***** *   *   **   ** *  **       *** *   *    ** ***  1;
* * * **** *     ***  * *
 * ***  ** * *  *  ** ** * 
   **  **  ** ** * * *** ***  ** 0;
  ** **** *  **  **   *   
}

int main(void) {
 ** * *  *******      **  *  *  ** st1[256];
  *        ** *  ** ******** *  ** st2[256];
  *  *** **** ** **    **  ** ****** ***     * *** st1);
 *  * *  * *   *     * * ** ***  *   * *** *  *  * * st2);

* * **  * ***   *  * *** *** * * (prefix(st1,st2)){
  * *  *** *  *****  ***  ** ** ******** * * * * *   ** *  * *   *   is a prefix of %s", st1, st2);
  *       *  **** *     ** 
      *  * * * ** *  * *** * *  *
  ** * *******      ****   *    * *   * **** * *** *  *****     is not a prefix of %s", st1, st2);

 ** **  *  ***  *   *  *** **  **   ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  ***** *   * ** **    * *    *  * * **** * *   **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
       ** ******* ***  *       * * * * ****  ***    ****** 
* ***  * * ** * **  **     * * *** ** * **  ****   **  * **** ** ** * **  * **     *    *    *
  * * * **    ***   ***          ** *** *  *** *  ****** **  ***       * *  ** * **  *   *** * **** ** *** **
***  ***   *   * *  ****** ** * * *   **   ***** ***  *****  *  * **  *  *    ***   ** **  *   ** ** **  *** *****    *****     * is not a prefix of %s",a,b);
*  * * *** **     *     * * ** ** ***    * *   ***** * *   * ***** ** * *  **  * *    ****   ** *** * *   ***  *  *   * **** **  * * ****  
**     * *** * * ** **  *   * *  ****** ***** * * ***   ***    *  **  ***** **** ** *** ** *  * **
*** **  *  **     *   **    ** * ** **    **   * **  * **  * *  * * *  **    *    **
 ***** *** * * * **     **   * ****    ***  ****** *** *   * * *    ******* *  * *    * * **  ** 
* ***     * *   ****    * *    *  ***    *** ****** ** ***   * *  * *   **** * *  **  **** ** * ***     ** *  **   ** **   **** *  **** *** ******  is a prefix of %s",a,b);
  ******* *** *     * * * * *  ******   ****  * *  *     **   *** *** ** * **  * *   *** *        *****    * *   *     ***     * * * *    ***   * **    
      * * **  * * * *  *  * * **  *  * * *  ******   * **** ** **** * **  ***   **             *    *  *    *
*** *   ** *   **    *   *   * ****  ****  **    ***** **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 ** ** * ** *     **** *   ** * **  ** ** * *   ** ** 
*  *  *** ***    *  * **   * **   ****   * *  ***** ** 

* **** *** *  *** *    *   * *  *******   * ** ***   * *   *     ***** * * 0)
** ***   *   ****   ** * * *  ****   *  ***  ** *   * *** * ** *****
**    ****   ***  ***** *   * * ** *  ***   *   *** **  **    *    ***  *   **** ***  ***     ** *** *    *    * **   is a prefix of %s",pre,str);
    ** ** ** *  ** * ****  * *  * **** *   *  ***  **  * * **  ** * *     
   **** *   **    ****** ***   **  *  * ** * *** *   ** * 
* *** **** ** *  **** **      ** **  * *** *** ** * ** * *  * ** *  *  ****
   * *   **** **  *  *  ***   * * ** ** * ***** ** ***      *  * *** *  *  ********   *  *  * *  *   * *     **  * *   is not a prefix of %s",pre,str);
* * *  * ******   * *     ****** * **  ****  **   * *****    ***   *****  * *  **   ** 

** *  *    ***  * * *  * *****   * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*  *   *      *    ***        *** a[100];

  * *** *** ** * * **  * * *  b[100];

 **   ****  * * **   * ** ***  i = 0;

 * *  *  ***    *  * * **  *  *  *  prefix = 1;

* * ** *** ****    ** *  *  * *   **  * ** a, b);

  ** * ** ** * *  ** *****   *   len = strlen(a);

***  * ***   *    *** *  *********   = 0; i < len; i++)
 **    * **   ***   * *** *
****  ** *  *  ** * ** *  ** ****    *  ******* ** ** != b[i])
   ** **  ******  ****  *   ***** *  **** ****  * 
  **     ** **** *   *  *  ***  ***     **   ** *** *    ***** ***  ******   *  * *   = 0;

   ***  ****** ** *  **      * **  *** ** **  * * * ******** **  ** *****   * ******* ** is not a prefix of %s", a, b);

 * *    * **  ********  * *** * * **    ****  ****  **  ****     *  ******* * ***    *  *
   * * **** *   * * ** **    ** * **  **  *   *******
** ** *  *       ** ***  
*  * *** * ** *     ** * * ** ** == 1)
 **        ** ***   ** *   **
 ** *** ***** * * ****  *  ***   * ** *   *** *** ***   *    * *  *  * is a prefix of %s", a, b);

 * ** *    * *  ** ***  *    *   
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *        ** *  
#include           ***   

int main() 
{ 
****    * * *****  *  ** **    a[100],b[100]; 
*     ** ***** *     *  *   * i,j,prefix = 1; 
   **** *  ***  * *****   * *  ** %s",a,b); 
*   ** ** * ****   *** ** *  len = strlen(a); 
 * ** **   *  ** *  *  * *  **   = 0 ; i < len ; i++) 
* *    ** * *      ******  
  *   **   ****   **    *   *  ** ** **   *** *** *   != b[i]) 
 *** *** * **  * * **     *   **    ** *  ****  * *** 
  *********  ** * **  **  ***  * * *   * * ***   *  * *  ** * *  **  * **** *** ******* = 0; 
 *** ** * * * *    * *    ** ***** *** *   **  **   *  ****** ***  * **     ** *** *  * **  ** is not a prefix of %s",a,b); 
**  * ****  *   * * *   *  * ***   *  *  ** *    *  ** *** * *** *  **** ***   
* ***  *    *   ** *****  *** * ** *  **    **** * 

* *****  ** ** ***   
     *    ** ****  ****** * ** *   ** == 1) 
 *  **   ***  * ** * *** *  * *   *  *  * ****    *** ****   * is a prefix of %s",a,b); 

 
  *** ***   * ***     **   *  * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    ****  * *  
#include *   *  ***  *    * *

int main()
{
**  * **      **  *     ***** a[100],b[100];
  ***** **  * **  ****  i,j,prefix = 1;
*  * *  *    *** *  * * ** **  *     * *   %s",a,b);
   ** *   *  * * * *     *** len = strlen(a);
*    **   ***  * ** *** *     = 0 ; i < len ; i++)
****   *    ** **  *  *       
*** *** **  *** **    ** *   * * **** * * * ***  *  * *  ** != b[i])
* ***  * **** ***** **   ****  **   ****  * ** ** ** ****
 *** *  **   *     * * *  * * **       * *  *  **     *     **** *  ** *    * ***  *** = 0;
**** * *    ***** *    ***  *** **  **  *****  **  **  **  *** **   *   * ***** ** ****  **   is not a prefix of %s",a,b);
** *  *** **    *   * *   *****  * *    ** **** *   *  *  *  ****** *   *** *** *       *
* *   *  *** * *** *  * *  **  *  *      * ** ******* *** 

* *  ****  * * *  *** 
    * ***  **  * *    *    *** == 1)
*     * **** ******   * *  **      *   * *  ** *      ****  ******** ** is a prefix of %s",a,b);


* ** *** *   *   * ** *  *** * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ***     
#include  *   **   * **** *

int prefix(const char *pre, const char *str)
{

****** * **   *        * * *  * ** **   *  ***** ***
 **  *    *****   ****  ***  *  ** *   ******* **   * *   ** 0;
**  ** ** *  * ******  **  *  * ***    *  *   *   ***  
** **  *  *  **  * **   ** **  *     ***** *  **     * ** * ** * 1;
  *** * * *** *  *****  ***  *   * return 0;


}

int main()
{
*  * **** **   * * *  * **    pre[100],str[100];
**  ** *  ** * ****  
*    ***  *** *    *  ********  *   * **  *   * *   
    ** ** **   * ***** *****   * *  **   **
* *  ****  ** * *  **   *** * * *** ***  *    ** *   **  *    ***  ** is a prefix of %s",pre,str);
 **** ** ***  *****  *    *     
    ** * *    ****   **       ** *  *   * *   *   *   *  **  ** is not a prefix of %s",pre,str);
* *** *** *   ** **  **  * ** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 * ** * *  ******* ***        c;
 ****      *   * * * ****  ***  *** *    *   
  ** ** ****  ** * * *****      * **  ** * *  * ** **   * **** *  *    0;
* **** ** ***  *  **   **** 
       *   *** * * **** * ***  **
** * ***** **  * *   *     ** **** ****  ***  **   ** ** ***  ***  **  * *   of a string
  * * *    * ****      ****      * *   **  ** *     **    ***   ** * * *  ***  **** * **   * 
* *****       * **   ****** *****     *    ****  *** *  ** * *   *  *    * *  * ****** * *  * ***** ***** 0;
* *  *****  **     ** *** *** * * *** **    * ** *   * * ** 
 *    *    **  ** **     * * ** ****  * ****   *  ** *  * 1;
    }
}

int main(){
* *   **  *   **     ***   **  * a[100],b[100];
**         * * * **    * ** ** *** ***  * %s",a,b);
  ** *   ***  *  * * *       * * * 
   **** * *   *  ***   **  *   ** *        ** *    **    * **  * * is a prefix of %s",a,b);
***** ******* *  ** *  **  
 * * **** * ** *** *** ** ** * *  ****  * ***   * *** **    * **  ** is not a prefix of %s",a,b);
 ******   *  ***    * **   * *  * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***** ** ***  * ** *  ***     p[100],s[100],a[100]={};
  ***   *** *** ** ***   * ** t;
  ** * *   *     *   *   * *    ******
  **     *  ** ** *     *  * ** *** ** * **
 ** **  * ***   *****      * * **     %s",p,s);
   * * *****  **  *  *  * * ** *    ** *
*  *  * * *** **  * * *** * *   *** ***** 
 ** **    ** * **   * **    ***   
  ***  * **  ** *** *    * *  ** ** * * * * 
*** *  ****** ** * * ** **** ***   *  
*   * *    * *  * ** *   *** **  ** *  ****   **  ******  *  is a prefix of %s",p,s);
*  ***   * * **  *  **  **
** ****** * *** *  *    ***   
** * *** * *** * *   * ***   ***  *    ** *  * * *     *    **  * *  *** is not a prefix of %s",p,s);
***     *     * *  * **   
 * * *****     *** *  *  *   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.224
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users