1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include    *    **    *** *
#include  ***** *   *  *** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
      ****      * ** **    *
 
 *  **      ****** *****  * ** * * *  ** * ** ****  
   *  *  **    * **   * *****  * 
 *  *  * *    ** *   **  *  ********* * *** *  * *     ****  == s2[i])
  **** **** * *  ** *** *   * *      * * * ***     * 
 ** **    *  *   **   *   **  *  *****        ***  *     *  ** **      * **  ***  *
    **  * * * *** * *      *        *** **  ***       * *****  
 
****** ** **    *  * *** ** *** **
 
*******  ***  * *****  *  ***  ***    == length)
  ****** **   *   *  **     ** * *** 
**  ***    *** * * ***  ***   ****  ** *  *  ***** ******         *  * ** * *** ***  is a prefix of %s",s1,s2);
****  ***  **** *    *    **** ** *
 
 * * **** *  ** **** **  * * * **  
 * * * ** *   *  **  ****** *** * **
     *  * *     **   * *    * ***  ** *** *   *   *** *   * *   *    ***  **** is not a prefix of %s",s1,s2);
   **     ***  * *  **  **** **  *  
 return 0;
  *     * *    ** ***  * *
 }

int main(void)
{
*     * *    *  * *  *** * *   s1[100];
  ***  * ****    ** s2[100];
  *    *  * **   * * * * * i,j;
 ** * **    ** ******  * *  
****    *  ** *   ***** **  * *****   ** * * * *     s1);
 * *  ** **   **  ******   ***    ***  *  *  s2);
*   ** * *** ** * *   *** **
** *** *    **  ** ****    ***  * *
 * ** * * **  *  **  *  ** * 
 ****** *   *** **** *  ****    0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *  *** *
#include ** * ** *   *  * 

int prefix (char st1[],char st2[]){
 * *    *  ** ***** *    * *    len=0, i, cnt=0;
  **** *** ****   **  **    * * 
  *     *  * ***   *     ***    = (unsigned)strlen(st1);
*  * *   ** *   *** *    *
* ************  **    **   *  *  (i=0;i<len;i++)
 * ** *  *  *       *** * *  ** ** **
***  *    ***    **  (st1[i]==st2[i]){
  * *   * * *** ** * *  *********  * *  **  *** *   *  ***   *  **    ***   ***  **    ****  **
   * * * *  ** *** *  ***  * *  *   *   **  * * *  *
*   *    * **   ****** * ***   *
 * ** ** *      ** *   ** * (cnt == len){
* ***  **    * * *     * *  ** ****   * *  **  *****  **** 1;
      * **   *   * * *    *      
**   *   *   *** *        ***  
****       * * * *  *      * *  0;
* ** *** * **   * *      *  ** 
}

int main(void) {
** *   *****  * ***** ** st1[256];
** ** **    ***** *     **  st2[256];
** ***** * *    *  ******* ***    ******    *   * * * * st1);
*  **** * ** *** * ********   ** ***     *** * * st2);

     * * **     *   *    *** ** (prefix(st1,st2)){
 ***  *         *   **  *  * * * ** ** *   ** * *  *  ****  ** * * ** is a prefix of %s", st1, st2);
 ** **  ****   * *******   
*  * **** *   *  *** **  **
 * ** * ** *   ** ** *** * ****    **** ****  *   * ***      *  *   *   is not a prefix of %s", st1, st2);

    *** ***  ******* *  *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  ** ***  *  * ******  *   *** *    ** * * ** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* * * **    *  * *** *  ** **   *     ***  *    ***   *  * 
   * *     *** * **      *** ****    **  *   ** * *** **  *    *   *   ** *  *     ***   * *  **
   *   ** *  ***    *  ** **  *** *   *  * ** **  * **  **   **** ***** ****** ****** ****    ** *
       *  ** *********  *** **   **    **   * ******* *   **  ****  ****** ** *  * * **     ******    * ** *    *  * ** ***    * **       * ** * * *   ** is not a prefix of %s",a,b);
**     * * ** ** * **  * ***     * *  **** *  ***** *  ** *** * ***   * * * * *** * **  *** *  * **** *   *   *** ** *** ***     * *  * * *  
 * *  ******** * *        **   ** *  ** * ***  ***     * *  **   * ***       *      ** * * ******** **   ** ** * *
**     ****  **     ***  ***   *     ****  **  ** **  *   **    *     ****     ***   **  *
** * ******* *   *  * *   *    **  ****  ** * ***    *** * * * **     ********* **  *** * *   ******  ********     * *
 *******   ** * * **  *  *       *  *  *   * *        ***  ****  ****   *  *      *****  **     *  * *   *    ***** ***  ******* * ** * **    *        is a prefix of %s",a,b);
 *     * **   *   *    *   * *****   *  ******   * ****   **  **    * *   ** **          *  *    *  *  ***  **  **   ****  * * * *   **     *** 
*  ***  *  **       * *    ** ***    *** **   ***  ****** *    ** ** **** * * *** ** **   **
*    ** ****       ****  **   ***     * *   ** * * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 **    ****** *** * **  * * **** * ***  * ***** *** 
  *** * ***  *       * ***  *   *  *** *     *

   ** *  * *  * * **  ** *   **** *****    *  *****    *   **   ***  **** * 0)
*** *     **     * ** **** * **  * * ****  *   **     * ***     * *  ***
 * ****   *  **  ***     **  *  ** *** ** **  ** *** **   * * ** ***** * *    * ***  ****  **   * * ****  * * is a prefix of %s",pre,str);
  ********* * *****  * * * ** * ****   **  ** **       *  * *    * ****
***  * ** *  ** * *** *  **    ** **** * **** *** **    *
   *  ** ** * *   *   *** * * * ** * **  *** *   **  * ** * ********** *  *   
  *   **   * *    *  * ***  ****    * ******** ** **   ***  ** * *  * *   *** *** * **   **  * *   ** ** *     * *      *   *  *  is not a prefix of %s",pre,str);
* ***   **** *** ** ***   *  ** **   *** ** * ******* * *   * **       ** *     *

  * * **  ***  *   *    *  ******  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** ****   * * * * *** *   ** * a[100];

 *  **** **   *  ***  *  ** **  b[100];

    *      *  * ** *  * ** *    i = 0;

*  ***  *********   *** **** prefix = 1;

*** * ** **   **  ****  ** *  *   *  **    ** ***    a, b);

 *** *    * ***  ***  *  * ** * ** * len = strlen(a);

**  *****  **   * ***** ****  ****** = 0; i < len; i++)
   *** *** ** *****   *  ** 
* *   *   *  * **  ****  * *    ** ** * *** *   *  *  *    != b[i])
* *  ****   *** *     ** *    * * * * * **** ** ***  *    * 
 ** *****  *   * *** * *    ******   * *****  ****** * *   ***  **   *** **   **  * ** *  *  = 0;

 * ** **     * ***** *  *  *****  *  ***** * ** ** * ***   ********  *  **  * *   *   *  *  * * * is not a prefix of %s", a, b);

  **           * ** * *  * **  *   ***  ** * * *  **** *  *  *  *     *** ************ 
**  *  **  * **  ** ****    **** *** *** **** **** ***
 ***** ****  ** **  *** ***   *  
*  *  **  ***    * *  * *    * * * == 1)
** ** * * **  ****** * *   * 
   **   * *****   * * ***** *    *  *   *****  *** * ***** *    *  is a prefix of %s", a, b);

 *   ** **    **** ** *** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **      **** * 
#include  **   *  *   

int main() 
{ 
 ** **   * ** * *****  * ****  * *** a[100],b[100]; 
  *  ** * * ***   * * *   i,j,prefix = 1; 
  *** *  * *     * *   * *        *  %s",a,b); 
***** *    ** *  *** **   **  len = strlen(a); 
 ** *   * * *   * ** * *    = 0 ; i < len ; i++) 
   *   * *  *   * **  ** ***  * 
 ****** *     **  ****     *    ***  ** *  *   * ** *     != b[i]) 
** **  * ***** ***** *** **** * ** * **    * 
** ** ***    *  ****   **   *  *  * **  ***  ****** ********** * * * **  ***  * * * * **   = 0; 
* ** *  **** ****  ****     * *** ** ****    ** *** ** * *    ** * *     **** * * * * **   ** * is not a prefix of %s",a,b); 
* ** *   * **  *** * *****  ** *  *****  ** **   * ****    ****   * **  **  *   *   
   *** *      * *** **    *** ** * ****    *   * *** 

* ***   *******  ** *** * 
** **  *** ** * *** *  * *  == 1) 
* ** **   **  * *   ** *    *    * * * * * ** **** ** ** **** is a prefix of %s",a,b); 

 
* *** *        **   * * ** ******** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *** * **** *     
#include * ** *  *   *       

int main()
{
   * *  ***    * ** **** ** * a[100],b[100];
**   * *  * **  **** **      * *     i,j,prefix = 1;
* *   * * * *  ***  ***       * * ** *   %s",a,b);
* **** *** * ***** *   ** *  *    len = strlen(a);
   *     ** ***** ****   *  *   * = 0 ; i < len ; i++)
 * **   * **** **   *   **** 
* * *  *  ** * *  *  **  * * **** * ****  ******* != b[i])
    ****  * *   *   *  **  **   *  **    *** ** **  
   * ** *   **   **     * ***  **  ***** ** ****    **    ** ** *  ** **   * ** = 0;
 **   ** ** ** **  * *  ** * *   ***    * **  **   *  * *      ** *  * *** **   ***** is not a prefix of %s",a,b);
 *   * *   ** ****   *  *  * *****   *** ****   **** **   **** ***** *** 
*  *   * * *  * ****  *       *  ** **** *   ***    *  *** 

* * * ** ** **    *  **  **   ** *
**  *     *  ** * ***     **** * * == 1)
 * *  * **  *    ***  * ***      **  **** *  **  *      * ** is a prefix of %s",a,b);


*   ****  ****    *  * ***** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *    * **   *  
#include   ** *   * 

int prefix(const char *pre, const char *str)
{

**  *   ** **  ***     * *** *  * *  *  *  * **
 *****  * ** **  * ***  ** *    * *****    ******      *   0;
* * **      ** ***  * ***  **  *    ***** ** * *** **
*  ***  * * *****  *** *** * * *   *   **  *  ** * * **** 1;
** ** *  **  *** ** ****** return 0;


}

int main()
{
 **** *   *****  **  ****  * **  pre[100],str[100];
***** *   * *** **  * *  
 ***** **  ** *** *** *  * * **** * **   *****  
  *   * * *   *   ***   *******   ** * **
  *     *******  *  * ****    *  *** * * ** * *       *  ****  * *** is a prefix of %s",pre,str);
 *  **    **** *** ***   *
*  *****   *   ** **  *  *   *    ** *  * * * * **   *** **  ** is not a prefix of %s",pre,str);
*** ** ** *  * ***      * ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*** *****  ** * *     ** * **  c;
   *  *   *  * ** * * * *   *** *  *    **  * **** 
 ***** *         *  ** **   * * *   * * ** *  *  *  *** ** 0;
 * * ***     * *  ***  **
 *  **  *   **   * **    **  *** 
* ****  **  * * *   ** *     *   ** **** * ** ** *  ***   * *   * *    ** ***   **** of a string
  * *** *    *** ** *  *   *  *  ****  *** * *   * *   ****  *** *** *** ** *    *     *** ** 
*    ****     *  *  * *     * **   **  *   *      **** ** *  ** * ***** ** *    *  * *****    ******** ** **** * ** 0;
  *  ** ***  *   ** * * * * **     *  *     ****  * *  
 *     ** * * ** *    ** ** * *   *   *  **    * *  *  1;
    }
}

int main(){
* * * *   ****  *** * * ** *    * a[100],b[100];
   **** * ** *  ***  ***  *  ** *   *   *   %s",a,b);
        *    **    *  *     ** *** **
 * * *  **** *  * *****  **  * *   *** *  * *  **** *   ***   * ** * *   is a prefix of %s",a,b);
*    ****   **    ***  *  *
  ** *    * *****   *  *     * * ** *  * ** * **** **  * *    ** is not a prefix of %s",a,b);
   ** ** **   *  *  **  **  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  *  *  *** * * ** **  * ** *    * p[100],s[100],a[100]={};
* * *      *     *  ** **     **  t;
**  * * *  * ***  ** *  ****  **** *** ***  ** *  
*  * ** * * ****  *   *  *      **   * ** * * 
****** *  ***** **  * ** * *   * * *** ***** %s",p,s);
*** * * *  *  **         ** **  * ***
*   * ** **   *** ***** * ***   
***  **     *   * **   ** * ** *** **  **
* *  * *     * *   ** *  ******* *  *   
 ************ *  *    ***** ****    **   * 
 ** ** * * *******  ***** *** *  ** ***   *****     ** ****   * is a prefix of %s",p,s);
*  ** ** *  * *  * *** ***
**  **   ** *  **  ****  ****  * * *
 *** **    ***      ** *** *** * *  * **   *****  *********  * * ***** is not a prefix of %s",p,s);
 **  ** * * ** ****   ***
 **    *** ****  *      *****    ** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.185
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 14.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 9.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users