1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
** ** **   **  **** ** ***** * 
** *** *  ********      ** * *  *** *** ******** ******
    {
   * **** *  ***     *   *     ** **** * *  *  * ***** **  (i=0; i<=strlen(string2)-1;i++)
***  * * ***    *    ****  **  * **  ** * ** *** ***** * 
 ***  * *  *   * *   *** *** *  * ** *  *****       *  ***  **  **   ****   * (string2[i]==string1[i])
 ***   * ****  * ** * ** *  *     * *  *** *** *  * * ***   *** **** * *    *** 
  ** **  ****   * * *      ** * **  **     ** ** * * **** *  ******    * * *******  *  ** * * **  **     
**  *  ** *******   * *** **** ******  ***  *   ****  *  **    ** *   *    *  ****  
**** ******    ** **** **  * **   ***** **        *    
  ** *********   * *** *  **  ** ****      ***       ** *    * **
*   * ***  ** ***  *  ****** *  ** * *****    **  *   *
   **   * *   * **  *   * **** * ** * **       **  ** *  * * *  ** * *   * * * * **   is a prefix of %s", string2, string1);
 ****   *  **  **     * *   * * * *  *  * **** *  
 * ***  * * *  *****  **     *  ** * *   ** **** * 
* * * * *     *   **   *  ** ** * *  *  ***  *****  * * 
***    ****  ******* *   * **   ** ** ** *** *** ** *  ****  *    *  ***   *     *  ** *   is not a prefix of %s", string2, string1);
******  * *   **  * ***   *   * * ** *    * **** *  ** * 
    }
***  * ** *****  *    **     *   * * ****  ****    *  *   * 
    {
*    * ** **  **    *    *** **     **  **  * *  **** (i=0; i<=strlen(string1)-1;i++)
** *       *    ** **  ***  **   ********  *  *   *
 *     *** * * ***   * *****    *** ** ****  * *   *  * * *  * ****  **  * *  *  *** ** (string2[i]==string1[i])
  *   *  ***  * ****    *** * *****  *   ***** ** ***   ***  *    * * **********  
 * **     * *   ***  * ** **   ** **  *** ** * ** * **     * **** *   *** ***    * * ** **  ** * * ** *  ***    * *
** * ***  **  ******    *     * * *  ** * * *  * ****** ***  ****   ** *   * ** * *  * 
**** *****       ****     ****   * * * *   ***    ******
  **       ***** * ** * *   * * **  * ***  ** ***** * * *
   * * ** **  **  *       ****  *   * *  *** *   ***  
* ***  ****   **** *  **     *   *      * *     *    **       **    **   * **  ** *    *  *   is a prefix of %s", string1, string2);
*** *  *  ****   **     * * ******    ** *** **  ** * **  
    *  **  *** * ** *****  * *   *** ** * * *****  ****  * 
*  * * ** *** * ***  *** **** *** **   **  ** **   
 * ** *****        ***     ** *   **   ** ***   ****   ***** *  ***   *  *      * * *** *   is not a prefix of %s", string1, string2);
*   **    ** *  *      *  * ****  * *   * * ** * ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* * **** * **   *    **  *  *     * * ***   ** **** %s", chaine1,chaine2);
 * * *  **      **  ** ***** *   *   *    **
*** ** * *   * *   *   ****  *  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
    * ****** **   * *   ** lenght1,lenght2,c;
  * * ***    *  *    * * *    b[100];
***  ** *     * *  **** * ***** a[100];
* * **  *  * *  *  * * ***** d[100];
      **  *  ** ** ** *   ************ * 
  ** * *** * ***      * *****   **  ** * * *** * 
* ** **    * **** *** **  *    * ***    **** 
 * *  **    *  * **   * *     *  *    *  
 ** *** ***   ** * * **** ** *****   ** * **
**  * *   ***  ***** *  
*** *  * ** * * ****** ****  * * **       *  * ** **  is a prefix of %s",a,b);
 * **** *****       ** ** *
    * ** ** * ****  *    *  **  
* *  ***  * *  *  ** *  **  * * 
    *   *   * **  *   *  *  *    ** **** **     * ******     * is not a prefix of %s",a,b);
** * ******* *       * 
 ** * ********    * *   *    *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *   * *  ** 
#include *** **      *  **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
** * *  **** *  ** i;
*** *** ** * * *     ** *  **
  {
 *  *   * *  * *    * * ***  *  ***** *   A[i]!='\0' && A[i]!=B[i]   )
* **  ***  * **   *** * *    * ** * * **        ***    *** ****  *** * *  0;
*     * *** *   * *  * * ** * *****    * **  * *** * *
  **  * *   * **   *      *** ** *    * * **   * *    * ****      *** *   
  }
*****   ****  ** 1;
}


int main()
{
 ** * *  *    * ********** a[n],b[n],c[n];
  *** *  *** ****  ** * *   i;
 * **  *  ***     ** *  **** *** * * * **** * ** * *
      * ****  *** **  * *     *     * ***   ***
   *** * * *    ****   ***  *  (aa(a,b)){
**   * ***** * * *    **** * *      * *  ** * *  **   ******     * * *   *  * *  **
 **       **** **        ** *   * **  * *   *     ** ****     *  **  * *    *  ***  ** *  ***** * 
** *  *  ****** *  **   ** *  *** **     ***  *  ** *** * ** ** *******  *****  *  *  ***  **  **   *  * *****
  * ** *  ***** ***   ***  **        ****     *  ** * **** *  ** **  *   ***** *  

 * * * * ** *   ***** *  * * * ** ***   **     ***      
*****    ******   *  * *** **  *  *********    *   *****   **  *   * * is a prefix of %s",c,b);
 *  *  * **  **  ** *  ***  
**   * *   * * *  ** * * * **
 *** *   *** ** * *  ** ***   **   **  * * * *    **** ***** *  *   * *   is not a prefix of %s",a,b);
** * *  **  *  *   * ** *   ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **   ** *
 **** *** *    *     
int main (){
char  * * * **
char   *  *   
 * ** **  * *  string1:  *  *
*  *    * *       * * **      *  *  *
* * **      **  string2: *** 
 * ********   *   ** ** * **
   *** * ** *     **
*   *** *    **  *****  * *  * **   is    *  **** of       * ***  **** *
else
  * **  *  * *  *    **  *  *** **  is not prefix of   **  * *  *  **  **  * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***      * 
#include *  * * *    
#include *** * * ****  
#include    *    *** *
int prefix(char p[],char s[])
{
*    ***       ***  *** *   ****    
* ***     *    * * *   * * * 0;
* * *         * *  ** *  *  if  *    ** * *       
 **    ** **** *  *  *   *  *    * 1;
* * * *  *  ******* ** 
* * * * ** ****** *** ***    *  0;
}

int main()
{
** * * *   ** **    p[999],s[999];
*** *  ** ***       *    ***     * ***** 
 *  ** **** ***    * ***    * **  * ** 

      *   * ** *  * *  *  ***  *
* *  ** *  * ** ***** ** ***** *     **** * * is a prefix of %s",p,s);
 ** ** ****   *    * * 
* **  * **  * ******    * ** * *  *   *  is not a prefix of  ** ** ***  

 *    *   ***    ** * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *   ****   ***
int main()
{
* **** **    **       **   * *  length1,length2,c;
**    ** *  ** ***   ** *   ** a[100];
*  * * ***  ****  ******* ** *  b[100];
  **  *** * *     * * * ****  d[100];
   * * * *  *   **   ***  * *** ** *  ** *  * * 
  ***** ***  *  * *    ******** * ***** ** *   ***** *
* * * ***   ** * ***** ** *        
 ** *** *     ***  * **  ** * **** *    **  
if (strcmp(a,d)==0)
*** *  ***  ** **** *** *    * 
*** * ** *** * *    ***  ** *     **   *  * ** *  ***  * * ** *** is a prefix of %s",a,b);
   ** *  ***    *    * ****    
*   *   *   **   ***  ** * *
   ** ** * ******* **** ****
** *  *  ****     **** **  *     ** * **   * ***    *  **  **   * * *  *  is not a prefix of %s",a,b);
 *    *** ** *** ** **  *
**  * * * **** ***** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  * **    * 
#include * **    * * * * *

int prefix (char *  * * *** str2[])
{
   ***** * ******** ** ** ** length=0,      ***
**** * * **** * 
  * *** * * ** *** *** * * **   = ** *      * *** 
***** **  **          * * ** *
 *  * *  *****  * * *****      *** ** ** *    *
 **** *  *  **      ****  **    **  *  *   *
***  **  ***  **  *  * ** * if  *   **   * 
*  ** * * *  **  ***   *             ****      *** * ***   
   *  **  ****   ***     * ****     *   }
    * *          * **** * *** *   **** *
****    *** *  *******  (count == length)
 *** ** * ******   *  * **  * ** ***** * *** 1;
 ***      **  ***   * *  *** else  **        0; **   ***  *  *****
*   *   **   * **   *  ** * * 
}
int main(void)
{
     *   **      **  *** *   * *  **  * * **
*   * **** *    **  ** * 
   ***    *   *  *   *  **  ** * * *** **  * *  *   ** str1, str2);

 *  *   **   *     **   *  * * * ** * *** ***   
*   * **  *   {
 ** ****** ** ***    * * *** *** **   *   * * ***        is a prefix of  * *      str1, str2);
  **** * *  ***     *  **   **
 *   *   ** * * * *      *
* ***  * *  *****  ** **   *** *** ** * * *****   *     * *  is not a prefix of * ***** str1, str2);

 * **    *    ***   * *  **** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * ****** 
#include * *  *    *   *   * 
#include  ** * *     *

int main()
{
   ** ***  * ** *  * **** * prefix[100];
 ** * * * *   *  ** ** *** *** word[100];
 ** * **  *  * ****** *******   ***   * %s", prefix, word);
*  **  * * ** ***  * *  * i;
*   *  * * * * * *** ****    *    = 0; i< strlen(prefix); ++i)
*******  **  *   * **  *  *** ** 
   ** * **  *    ** ******     * *  *  ******    **   * **   *
*            ** *** **** *     ***** *   **  *** ** **** * 
* * *  * **** **** **    *** * * *       *** *** **** * * ** *     *  ***   ****** *   *   * ***  is not a prefix of %s", prefix, word);
*   ** ***  *    *    ****  **   ** *  *    ** ** **     * ** *   * * * * 0;
**  *  *** * ***** ** ****** *  *  *   **  ***  *  *** *   
  *     * *    *  * * * *** **
* *    ** * *   * *  **** ***** *** ** **    ** is a prefix of %s", prefix, word);
*    * ***** ****  **  *     ** * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *    ****   *
#include   *           **
#include  *   * * * **   

int main()
{
 *****  * *      **  *  ***   prefix[100];
**** **   *   *****  * * ***  * word[100];
* ** **   ** ***   **** ***** *** ** * %s", prefix, word);
 ***** *** **  ** *  **** ** *   i;
    * *    *  * *** ** * * *       = 0; i< strlen(prefix); ++i)
** ***  *  *      *   * ** **
**  ** *** ** *****  *   ** *** *   **       *   *   ****      ***   
*****     *** ** *****     *  ***  ***   *** *   * * ****  
  *  *  * **  *  * * *   *  *       * * *     * * ****  * **    ** *      *   **   ***   *   ** * is not a prefix of %s", prefix, word);
* *  ** * **   * ***  *   * ****  ** *** ***** *   **** **** ** **    * ** **    *** *** *** ** 0;
         *     ******** **  *  **** ** *  *   ** * *  **     
* **** * * *** * **   * * **  
  *** * ** ****   ***     *     ** is a prefix of %s", prefix, word);
  *  **  **    **  *** *       0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** *  *****  *       
      *  ** *** **
*      **  *  * ***  

int main()
{
    **  ***  ****  char **   **** 
* *  * ***  * *** char **** 
**   * **** *   **  **  * *     **  * word);
 *** *   * *      int i;
 *   * ** **  **** for(i = 0; **  **  ***   ** ** ++i)
  *         ** *  {
 * *    * * *   ***   ****  ** ******  *  *  
***  ** *   *   *       *  ****  {
   *   *   *  **  *  *   ***   ** **   *  ***   ***** *  ***** is not a *  of  *     *  *  word);
* *  *** **     *****  *   **   *  *  **** *  *   0;
*      * * *    * **      *  }
** **    *** *  * }
 ** *       * * ** **  ***  * is a prefix of *  ** **  * *   word);
* * * *   ***      *   0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.126
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users