1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
  *** * ****** **   **  *
*  *  **********  ****** *        *** ***   *  ** * * 
    {
*** * * *  ** * **** **  * *  ** ** *** *    ** * *   *** *******   (i=0; i<=strlen(string2)-1;i++)
   * *   ********* * ** ***    **    ***     ***  *    ** **
**     ** *   * ***** **   *    * * ***    *  **        *  *  * *      ***     (string2[i]==string1[i])
 **** **   *  **    * * * *  ***   ** * **    *  * ** *   *** **** ** * 
**  ******   ***  ** *   *  * * ****  **  *       *  *  ****  ***        *   ** ** *   ** * *** * *   * *  **     
 * ***     ** *    * ****  **   *     *** *  **  *   ****   ****  * ***  *   
 *  ** **       *   **** *******  *   **** **     ***  ** * 
** *  **   **    * *  *** ***           *   * **     ** ** ** *
******  * *  ***  ** **   * *** **   ** *** *    * *
**    * * *  **  *   * **  **    ****  *** *   **    *           * ** ** *  *  ** **     * *   *     * is a prefix of %s", string2, string1);
***  ** * * *  *  ******     * ** * * *        *   ** 
  *        * **    ***   **  *      *** * ** **** *****
*  ** * **  **  **  *   ****  * ***  *** *  * ******** ** *
* ****  *      *     *  ******* * ** ***   **  *      ***** *  *****  ***   * *   *  *** * *  is not a prefix of %s", string2, string1);
 *   **    *  ** * ** *     * * ** ***   **** *   * * 
    }
 * * * * **  *   ****   * *  *  * *   **  *  *   **    
    {
  * **  **   * * **       *  ** **       *  *     * ** (i=0; i<=strlen(string1)-1;i++)
  *  **** * ** **  * * *  ***       **  ***  ** *  *** *
 *  *****  * *  * ****** ***    ** *** * ***** ***  ** ***    *  * **    *    ** (string2[i]==string1[i])
 ***         ****   * *  *** * * *** *   * * ** *  *     *** *   *****  **  * 
* * * ** ** **     ** **  *  *******  ****   ** *** **** ** *   * * **    * *** ** ** * ****** *  ***   * **
 ***** * **** *  * **  **    **** * *** *** **  *     *  ** *******  *** *  **   ** 
**** **  **   * *  *  ** *   * * * *  ** *   * * ***** 
** ******** ** * * *****     * * *    *  *         *** * *   
 ** ** *  * *   ** * **     ***   ** *  *****   *  **  **
 *****  ***** *     * *  *** **** ** ******       * *   ****  * **    *       *   ** **  **** *  ***** is a prefix of %s", string1, string2);
***  * * * *  * *   **  *  ******  ****  *** *     **** * * 
** *   *   *    ***** * *    ***     *** * * **
* *** **  ** ** * ** *   ****  *   **** *   * ***  ****
 *   **     *   **    *    * * *** *  *  *  * *  *  **  *** * * ******     ** * *** * is not a prefix of %s", string1, string2);
* *   **  **  *   *****     *******   *   *    ** ****   ***
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *   *  * * * ** * ****    **   *    * %s", chaine1,chaine2);
  * *   ***  *  **     ** *   *** ** **  
**   * *** **    *  **** *   **   * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**  * ** ***  ********    * **  lenght1,lenght2,c;
* *  * * ** *  **  **   **   b[100];
*****  *   **  *  ***** * * *  a[100];
 * *** ** **   ***   **    d[100];
**    *  **           *** * * ***** **      * *  
** *  *** ** **   * **       ***    **** *  ** *
  ******* * **  * ** *  * * * ****
  *** *  ** ******    *  * *  ****  * 
 *  * * ** *  *** * *****      * *   **
 * *** ***  *   * *** * *
   * * * ***  * * * * ***   * ***   *  ** * * *      **  * is a prefix of %s",a,b);
 * * *     *   * **    ** *  *
 **  * * **** *  *  **  *
** ** *****  *  * **   *  * 
 * * *** **     ***   *       *  *   ******* * **     *****    ** is not a prefix of %s",a,b);
*  *      ***** ****   *
 ***   ** *  * **   ** * * *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *    ****  * 
#include *** *******  * * * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* * *    ** *    i;
    *     * **  ***   *
  {
*** ** *** ** *  * *   ****  ****   * * **  A[i]!='\0' && A[i]!=B[i]   )
 **  *    * ** * ***   ****         ***  *****      *     ****  **   ****    0;
***  *    * *   *  * ****         * *   ** * *
****  * *  ****** * **  *  **  ***  * * **** **  *  *    ** * **  * *  **  
  }
    ** *  **  **  1;
}


int main()
{
  *      * **  * **      *  a[n],b[n],c[n];
*  **     *  * ****        * *** i;
 *  **  *** ** *** ** *  *  *  * *  **    *  
***    ****** ***** ******  *****   ****     
   * *  ************ * **      * (aa(a,b)){
* ***** *   **   *  * * **** * ****** *  ***  **   * * ******  ** *   ** **   *
 **** **** *    ******   ***     **       **  * *  ***  *  ***** * **  ***  *****  *****
 *   ***   ***    *    **  ***   * * *  **   **     **  * **      **   ** **   * *  * * *   *      *   * **  *  
**  * **     * ** *     ** * *** **  ** * ****      *** * *   ** ***  * *   * ***** * ** **

* * *   **     * *   *           **    **
 ******   *     ****   *** **  * *  * ** * * **    * ********   *    *  is a prefix of %s",c,b);
  *** * ***   *  *** *    
 * **   *       * *  * **
 ** * * ***   ********      *  **** * *    ****   **   * * * *    is not a prefix of %s",a,b);
 * ********    **   ** *****   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    * *    * 
 ****  ***   *   *    
int main (){
char   * ** **
char   * ** ****
* **  *  **  * * string1: ***  ** *
  ** ** * * ****  * * *  **** ***     
   **  * ** string2: ** ** 
 ***   ***     * **  *  *** *
     ***  ***   **  *
* * * *  *  *   ***   **     *  * *  *   is        *  * of * *      * * *   *  *
else
 ** * *** **   **   * **    ***  ** *    is not prefix of    **   *     * *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** **  *   *     *
#include **** **     **** 
#include   **** ******** 
#include   *   **    ****
int prefix(char p[],char s[])
{
   *   *  *** ** * **        * *** * * **
 * *  * * * *    **** *  ** 0;
*   *  *  **  ** **   **  if *** **   *   *  ** 
**    *    **** *  ** *  * **   1;
****  ****  ****  *** ** 
*  * *** * ***   ***** *    **  ** * * 0;
}

int main()
{
 *  ***        *****   *  p[999],s[999];
*  * ** ** *** * ********  **    **** **   *    
 ****  *** * * *    *  *   * *** * ** **  * 

 * ******* * * ***   * * **  * 
 ***  *   *     ** *    * *****  * **  *  * * * is a prefix of %s",p,s);
    *** ** ***** * ** ***
** *    ***     ***  ** ****     *      is not a prefix of * * *****  * * 

*       ***** * *  *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *   * ** ** *
int main()
{
 **  **  *   * **  *  **     length1,length2,c;
  **  *** *  * **   ***    **    a[100];
 **    *   **** * **  **  **  b[100];
 *** *   ***     * * **    d[100];
**  *****     * ** **  * * *** * **  **   * 
  *****    **** ****   **** * ***  * ******  **
  * *  *    *** * *  ** * *  **   * 
*** *****    ** **   * ***    **   *  ** 
if (strcmp(a,d)==0)
    ** **    ** *  *
 *** *       *  *   *      *  ** *** *** **    ** * ***      * *   *****  is a prefix of %s",a,b);
** * *** * *** **   *  ***
 **   * ****  * *    **  *    *  **
 *  *** ** *  * ** *   *   *
***     ****  ** **** ***  ** * *  ***  **  * **** *    *    ** ** * * is not a prefix of %s",a,b);
  ***    *    * **        
 *  * * * * ** * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  *   * * ** *   
#include    * * * ***** 

int prefix (char * * **  str2[])
{
 ***** *** **  * *  * ****  * * length=0, **     
  * **  **  * **  *
*** * * *   **** * ***  *   **  =   *    **** ***  * 
   *  ****    *  **  *   ** *
* *    **   *** ** *  *** ** *   ***  *    **   
***   ** * ** * *  **  ***** **      * 
**   *** **  * *  ** **  **     *  if  *  * *  **  
   ****   ***    ***  **         *** * ****  **     **  *  **   *  
  *  * ***  *  *  *********    }
  *   *           * **  *** **   **  
**   *  * * *   *  * *** (count == length)
**   * *   *     *    *  *   ******* * * 1;
***  * *  ** ***  *  **  * else *    *  0; *  * ** ****  *** 
***  *  * *   *   **   *          
}
int main(void)
{
*  **** **  ******* *  ****    *   ** *    
* * * *   *   ***  *  * * **  *
* **    **   ***  ** ** *  *   ****** **    **  str1, str2);

**  * ** *  ****  *  * *    * ***** 
***  *   *  *  {
*****  ** * *** * *  ******      ***  *  ** ** **** * **    is a prefix of     ** **  str1, str2);
 *   *    ***  *****   * **
 ** ***  ***** *** ** * 
*  ***  *  *  ** * **** *********  *     ***  ******   *  ****  is not a prefix of **  *    str1, str2);

* *  **  ** * ***  * **** ***  **  * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** * *** * **** 
#include    * ** *  ** 
#include * * *    *  ** **

int main()
{
      * * * **       * *  * prefix[100];
** *  ** ****  ****    *** *** ***  word[100];
 **** **  ***    * * **** ***** ***** %s", prefix, word);
*      ** **   * * *  ***  i;
* ** * ***  * ** * *   **** = 0; i< strlen(prefix); ++i)
** *** *  * **     **  **** ** 
**   *   ** *  ***   *     * *  ****         *** **   *********** ** *
      * * ***   ** **  **   *  **** *   *    **    
*  * * * *    * **  * * * ** *****  *  ****    **  *    ** * *  * ** *   *  * *** * * * is not a prefix of %s", prefix, word);
* * **** * ** ** *  **       ** *  ****** *  * *** ** ** **  *  ** *  ****  ** *   *   0;
****    *   * * ** ** * *  *** **  ** **** **   *** **   
  * *  *  ***    *   * *  * 
 *   ******   ***  *   * * ** * * ** *  * * is a prefix of %s", prefix, word);
 * **** *** *  ****   * ** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** ***  * **
#include  *   *  * ***  *
#include * *** * **** 

int main()
{
***    *  *  * * *** ***** prefix[100];
*   *  **** * * * ***   * ***   word[100];
*   ******     *** *** *    * *  **  %s", prefix, word);
 ***   * *** * **********   *   ** i;
* * *  *    *  *****  ****   = 0; i< strlen(prefix); ++i)
  ** ***      **  **    ***  
 *         ***  ** *  * *** * * * ** * *  **  **    ********** **** * * **
*  ****  *  *  * **  ***  * *  *     ****** **  ***   * 
** *  *  ***     *  ** ** ** * * * *** *  * ** *  *  **  * ***    * **** *   ** **  *  *  is not a prefix of %s", prefix, word);
**   ******* * **   * * **    **** *  ****** * *  * *  ***   **   *  ** ****  0;
*  **  ******** ** ** * ***  *  **   ** **     * *** **  **
 *** * ***** ** ** ***  ****  
  ** *  ** ** ** *********   ** * ** *** *   is a prefix of %s", prefix, word);
** * * *  ****  **   *   *       * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **     *  *** *******
**   *       *******
* * *            ** *  *   

int main()
{
** *  *   *** char  * * *** *
  *  * *** * ***  char *  ** *
****      ** *    *   * *  *     *  ** *  word);
*****      ** int i;
 **        *  ** for(i = 0; ******** ** *** **    ++i)
** ***   ***  *  {
 ** ** * * ***  * * *  **  ****   **** *  *  *** *   *
* *         ****** ****  *   {
 * *    *  ****  * *  **  *  ****   *  * **   ***  * *   *  is not a  * of *   ****   **   word);
 * ** *  **  *  *  * *  ***   ***  * ** ** * **  0;
  * * *  **  *   * * **    *   *  }
*   *     *  **  }
  *  ****      *   * *    * **** is a prefix of  ** *    ***  word);
*   ** **  *  * **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users