1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 * *** **  ** *  * * * * **     *
** *       ** ****** *********     *   *   *  *****   *** * 
    {
*  *   **  *  *   *      *  ** *  * ** ********* *** *  (i=0; i<=strlen(string2)-1;i++)
   *** ****  **   **    * *  * *    *   *    **  
    * *  **** ** ** **  * **   *** ***   **** **  **  ***  ****  *** * * ***** *  * (string2[i]==string1[i])
***  ** * ** * **  *** *    **  ** * **** *     ** *  ********       *** *   * * *    * 
    * ***  **  *   * ** *   **    * ***** *  ****   * **   ** *  * ** *  * ** * **    **** *   *  *  * * *
  *      *** ** *   * ** ****** *  ** ******  * * *     ** * **  * * * **  **
 *   ***  * *  ***    *      **  ** * * * * **********
* ** ********  *   *  *     *    ***     ***** * ** * *   *   *  *
  ***   * ****  ****  **** *     **   *  **** **       *  **
 ** *  ** *****     *  **      ****  *  *    *  *  *       * **    *       *   * * ** * * **  ** * ** is a prefix of %s", string2, string1);
     * ** * ****  **** * **  ** ** *  *** **    ** ** *
 * * **    ****    **  *** * **** *   **  **  * **** *
* * *   **   ** **    * * * *    * **   * *   *****   ***
  *****    *****    * **   **      *  ** *  ** *  * ****  ** *    *  * * ** ** *   ***   *   is not a prefix of %s", string2, string1);
 ** *** *  ** * * ***  * * *   ***  *   * *   *   * **  *** 
    }
*   ***   ** *  * *  ***   ** * *   *  ****    ** **  *  
    {
   *   * * *  **** ** * **   *  *  *  ** *** * * *   * * (i=0; i<=strlen(string1)-1;i++)
* ****  *   ****  **     * * *   *   * ****  ** ***
 ** ************ *** * *  * * *     * **    *** ***   *   *  * * *  *   *  (string2[i]==string1[i])
 * *  *  *  * * *  **      *   ** *  * ** ** * *  ****  * * ****  ****** *  *  **
   *  *  *** **  * *   ** *   **   ** *    ***** **** ** *     * ** * * *    * *  *** *  **   ****     
      ** ** * ** **** *   *  **  ** ** ***  *   *      *****  ** *** *** * **
 ** * * ****  * **** *  * * * ***** *** ****** * **** **
  * *  * * ***    ****     *     * ***  *** * *  ***** *
  * **** * **  *   *** ****** *   *****  *  ***** * * *
*  *  * **** * ** ****  *  ***   *    **  * * *** ***      * *   *****   *  *** **     * * **  * is a prefix of %s", string1, string2);
*   *****  *    * *   ** * **     * * * ** * ******         
  ***    *   ** ***       *  ** **    ** * * **** *
*   ** **   *** *    *** **   ** *  * * ***   *  ** *
** **** ** ***** **   *  **   ****** **  ** * ** *** ***** *  *** ***   * ** ***   * ***      ***  is not a prefix of %s", string1, string2);
*  *  * * *  **  *  **    *    *  * * **   * * * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
       * * * * * *      **** **  ***   *    %s", chaine1,chaine2);
  *   *  **  * ******* * *   * *  * * *     * *  
  * * *** * ***  *      *  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  *  * * *     *   **    **  lenght1,lenght2,c;
*** *          * **   *****   b[100];
 * *     *   ***    * **  *   ** a[100];
 *******  *        *   * **  ***** d[100];
  **  ** ****  *** ****** *    * **      ** ****  *
*   * *  *  **   * ***  *  * *  * **   ** * ** *    **
 * *  ** *** ****** ***  *  **  *     ****  
*** * ** ***  *** * *** **        * **  ** ***
**  * * * ** ***  * ****  *** * * * * ** 
 *  **   *******     * *** 
* *        *  * **  **      * ** *** * *** *   * is a prefix of %s",a,b);
*     *      *  * ***    ** 
  * *     **    * *   ***  *
 ******* *   *  *****  ** ***
 ** *  ***** ***   * ***  ** ***    *   * ****    ** *** ** *   *    * is not a prefix of %s",a,b);
 * *   ***** *** * ***   * *
  ***  * *   ****  *  * *****  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * * * *  ** *
#include ** ****  *** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* *  *       *****  i;
*** * *  * * * * *** *  * *
  {
*  * ** **  * ****   ****     *****  ** ***  A[i]!='\0' && A[i]!=B[i]   )
   **       * *    * ** *  * * *  * *   * ***** *** ** * *   *   0;
******** **   ******* * *****    **   * ****** **   
  *  *** *     * * *   *** *   *  ** ** *** * **   *****      *  ** * * * *** 
  }
** **     **  ***  1;
}


int main()
{
**    * *   * *  *      *** ** * a[n],b[n],c[n];
  *** **    * *  * **     *  i;
  **  *  ** *** * ** *  * * *  *****  *    *
 ** *   **  * *  *** * * * ** *  *  ** ** ***** 
 *  ** * ** *  *    * **  **  (aa(a,b)){
    * **      **   ** ** **  ** **** **  ***  *    **** *    **** ***  *
   ***  ** *   **** *  ** **** ***   ***** **    *  **  *   * * ** * *    *  * * ** 
* **  *  **** * ***   * *** ***  **     *** ***  *     ***  **** *   ** **  **   ** * * **** **   **** ******    ***  * *
 *   * ***       *  *** ***  *** * * **  *    ***  * ***  **  *  *** ** * **  *

****     *   ** * **     ***  ** * *** **  ****    ** *
* ***   * ** * **  *   ***         ******  * **    ** *   **  *** ** * is a prefix of %s",c,b);
   ** *  *** ****  *       
*    **** ***   *** * **  ** *
 *   *  ** **  * ** *  *   *     **  *  *   ** ***   * * *   *** ** * **** is not a prefix of %s",a,b);
** * ** *       **   **    *   ***  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ******   *  ****
    ***   ** * **  *   
int main (){
char  *** * ****
char * *   *  
 * *******  *    string1:  ** * *
**  **      *          ***
** * *      *** *** string2:      ** 
***  * **** *** ****** 
* ****** ***  **  **   *   
  ***  * **** *  *  *****   **   * *  *** is * *** *   ** * of ** * * ***** * **      
else
 ***  ***   **   *  * * **  **  **** ** is not prefix of  *    * * *  ** **    

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * * * * *   **
#include * *    *    ** **
#include  *   * **   * 
#include   ** *   ***  *   
int prefix(char p[],char s[])
{
 *   *** **  **  * *   ** ********
** *      * ******* ** * 0;
  ***    **  *  ** * **  *  * if *   * * *  ***   *
** ***     * * ***** **    * * 1;
***   *  *** ** *     * *
* **** * * *  * **  * **   0;
}

int main()
{
    * *** * ** ** *      p[999],s[999];
 ***    *  * **** *   *    * * *  ** ***** 
   *   *    ** *****    * **** *    ** *** 

  *   ** *  ******* * *   * * * *  
** *  ****** ** ** * ****  **  **   *  *      is a prefix of %s",p,s);
 * ** *  * *** * * ***
 *     **  * *     *** ***** * * *  *  *  ** is not a prefix of  *     *      

     * *  * *  ** *  ** *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  *    ***** 
int main()
{
***  * **** **   *   * *  ** * length1,length2,c;
    *   *     * * * **  **   * a[100];
   **    ***     *    * * *****  b[100];
** *   ** *   * **  **      **  d[100];
*      *  ***  **** *   * ** * *** * *   * *  *
**  * ***  **  **  *   * ** **    * *** * *   ** 
* **  ** *    *  *    **  *** * *  ** * *     
 *     * ***    ***  * * ***    * * * 
if (strcmp(a,d)==0)
 *   *   * *   **     * **** 
****** ****   * *   **** *    ** *****  ** * **      **   * is a prefix of %s",a,b);
 * * *        ** *  *** * *    
 ***  *    ***  ** ****    
  **  *  **    * **  **  **
*  ****   ***  *** **    *    **** **  *   ** ** *   *  * * * *****   * is not a prefix of %s",a,b);
   ******* *  **    * ***
*     *  *  ***  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** ****** * *
#include   **  * **** ** *

int prefix (char * * *  str2[])
{
   ****  * ** * ** * *** *  length=0, *  *  **
  ** ** *  * * *   *  
***    *** * * * **     * ****** *** =  ******* ** **
 *   **  ****  ******  **  **
 * *  **  * **  *  ***  **        **     *
*  * * **   **    *  *     *  **  ****  * * 
  *     * * **   ** * *    *  if   * **   *
   * **  **     *** **       ***  *  **** *  *   
**  *      *    **** * * **   ***   }
    * ***         *  ***  ** *   *** *  
    ** * *   * **   ****      (count == length)
* ** ** ****   * **      **    ** *  ***   1;
   * *    * **** **     ***** else *  * **  0;    ******  *  * *  
**** ** * *  *   **   *    * 
}
int main(void)
{
* *   ******** ***  *    **** *    ***  
* ** ***  *     ****  *
  *   *   * ** ****   *****  *       *   * str1, str2);

     ***    *  *     *   ***  * *  **  * 
 ***   *  ** *   {
* **   *** **  **  **** **  *  **  ** ** *  *  *    **     * is a prefix of  *   * ** str1, str2);
* *** *  * ** *   *****   ****  *
**** * * *     ** **  ***** 
 * *  * * * ***  ***   ** *  *    * *  *  *  *** **   * * * *     is not a prefix of * **       * str1, str2);

*     ****  * * **  **   ** *****   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****  *****   
#include   * ****  ******
#include *   **  *** 

int main()
{
*  *  ** *** *** **  *  ** * prefix[100];
*    *****   **  ***  ***     word[100];
*  *  * * * * * *  ***  **** **   * **  %s", prefix, word);
  *  ***  ** ****    ***** ** i;
 * **  * *  * ***   *  **  = 0; i< strlen(prefix); ++i)
     * ***  **  *   * * * ***
***  ***   **** * * * **   *** *** * ** *    ***  *   ** ** *  *** **
******* *  *****     * *****  ***      *  * *   **
 ****   ******   *  ** * ***     *   **  ** * *   **  * *********   *         **   ****   * * * *** is not a prefix of %s", prefix, word);
 ***   * **  *   *******   * *   ******** *  **   * ***   **   *** ** * *    *   * * 0;
**** * * *  * *   *   **   ******** *  **** * **  
 **     * *  *** ** ** *  
 * *** ******* *  * ** ***** ****     *  is a prefix of %s", prefix, word);
* ** **    *  ** **  * *    *     0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  ** **    * 
#include   * *    *** *  
#include * ** *     * *    *

int main()
{
****** *    ** *** *** * * *     prefix[100];
*** * ***** ** ** ** * * ***  *  word[100];
* *****  * *   **  *        * * **    *  %s", prefix, word);
*** ***  *** * **** **  *    i;
   ** * ** **    ***** ** * **  = 0; i< strlen(prefix); ++i)
  *  *  * * * *****   ******   
 ** ** ** * ******   *  * *******  **  * *      *    **  *  * ***
  * *   * * *    *   **  * **  *  *        **  *
* * **   * * *    * * ** *** ** ****  *** **   ** ** ** ***   ****    *   ** ****  * **   is not a prefix of %s", prefix, word);
 *   ***  * * * * ***  *  *    ***  * *  * *     * * ** ** * *** *  *    **  ***   0;
 ** **** * **   * * ** * ***  *** *     **   * ** **   **  
  * *** **    ** ***  ******
* *** **   **** **   ***** ** **** is a prefix of %s", prefix, word);
 ***    *   * *  * * **  *   *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  * * * *    ***  
 *** * ****  ****   * ** *
* *   *   **  * **  * **

int main()
{
 **  **   **** char *  * ** 
*** ** ****  * char      *
 *   **    *** **      * **     * * ** *  * word);
 ******  *  * ** int i;
  **     ** *** for(i = 0; **      *  * ***  ++i)
  ***    *  **** {
 ****      *  **   *** **    **  * * **  ** *** *  * *
* *    **** **  *     ** * * ** {
 **** *  **   * *  **   *****   **  **  * * ** **  **   * * is not a   ** of  **   **  ** *  word);
   * *   ***  *    *** * **  *  **  * *  ****   *  ** 0;
***  ****   *  *  * *  ** }
 * * *  *  *     }
* *  * *  *            *  **  is a prefix of  *   ** *  *  *  word);
    *** ***         0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users