1-11 Exercise 3: Prefix of a string

0 like 0 dislike
13.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 13.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  * ***** *  ***
#include *  * * * ** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** * **  *  ** *** ** 
 
* * *****  ** *  * **   **    *    *    *   ****** *   **
*** *** **  **  ** * * *   **** **  
 * ** *   * **    *** **  *    ****** *   **** *  *     *** * * == s2[i])
 *    ***  *  *   ** *  * *   * **  *   * * *  ** *   *
*****         *      * ** ****  *    ** ** *   * ***  * *  **  * *   ** *** **** * * * *  
* ****  *  * *** * *  ***    *** **  * *   * * ** *   **  *** 
 
**  *   ***  **   * *  **  * ***** *  *
 
 ** * *** **    ** **** ****  ***  *   * **  == length)
********* **   ***   * *  * * **    
  ************   **  * * *  **** *****   * ** **  ** * *   * * *****    *  **   is a prefix of %s",s1,s2);
 * *   **  *  * * * * **** *  * * 
 
* *  **   ** ** * * ***** ** *** 
  **    * *  *      ** ***   ** **   
 * ****  * *    **  * *  ** * *   **  *  * *** *   * * *** * *** *  ******* ** * is not a prefix of %s",s1,s2);
  **   * ****    ****  *   ***** **   
 return 0;
*  *    * * * ** * *** ** **** *
 }

int main(void)
{
********     ***  *   * *  * s1[100];
   ***    ** ***  **   ** * * *   s2[100];
********* ** **     *   * * i,j;
**  **  * **     * **  *
** *  ***      * ** **  **********  * *   ** * s1);
 *   * *** * * ***      * *** ********** * *  ** * * s2);
      *   **  * ***  * *
* *       * * ****  **  * *  ** * * 
  **   ****   * * * **
*   ** *  ***  ****     **   * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * **  *  
#include *   * * *  * *    *

int prefix (char st1[],char st2[]){
* ********* * **     **   * ** len=0, i, cnt=0;
* **  * ****  ** *  ** * *
 ****  *    * ** *  *** *     **  * = (unsigned)strlen(st1);
***    * *  *** * *******    
 *    * *  * ** **** * ** ** (i=0;i<len;i++)
********    * * * ***** *   **
** *   **    *** * (st1[i]==st2[i]){
    ** * **  ** * * ** *  *    ** *  **** * * ** *   ***** *** * ** ** **     * **** * 
* *  *    *** *       * *     * ***   * ** *  * * * *  * 
  * ***   ** *  **  ** *
  *  *  **** *** *****   ** (cnt == len){
  *** * *      ****      **  **  *** *   * * * **  *   *** *    1;
 *  ****  *  ***  *  *  *
  * **** ***  *  ** *  *** 
*  * * ** ** *** *   *  *  *   *  0;
 ** *** ***  * **  * ** *
}

int main(void) {
 *        ****  **  ***  ** *  st1[256];
****  *** *  * * * ** **** * * st2[256];
   *  * * * *     ***** * *  ** * * * *  **  * st1);
**  **  ***     **    ****  ****  *** ***  * **** st2);

 ** * *  **    *** *     **  (prefix(st1,st2)){
**  * *  *  ****   *  *   *   * * *  ** * ****  ****  **** is a prefix of %s", st1, st2);
**     ***** * * * * *****   * 
* ** * * **    * ****  *  * ***
*   *     * **     *  **** **  * **  * * *********   ** ***   * * ** is not a prefix of %s", st1, st2);

   *  * *** *    **** *   *   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  ** * *     * ***  ** *  * *     ** ****      *  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
**   ***   **** *      **  ****  ** *** **  **** **** *** *  
   ***  ***  * ***        * **** * **   *** *******    **  *  * * *     *** *  * **    *
*** **   ****  * *  *  *   ***  **  * * *  * *   **  **  *   ** *** **    ** * **** ***********  ** **  * **   **  *
   **  * **  ****     * * * * **** **  *     *******   * * * *  *   * **      ****   * *** *  ***           *  *  *  ****   *  *** ** * *** ** *** *  *  **   is not a prefix of %s",a,b);
**   ***  *        * ****       **   *****    * **   *****  **     ********  ** ** **** * *    *** **    *** ***   * *** ***  ** *  *  **   
  **** * ***** **   * *  * ****    *  ** ** ***  * * ** *  * * *   **** ***  *   ****   * ****  ** ** *
* ** ****    *  **  * *  * *  *  ** **     **** ****  * * ***     **  *   * * **  * *  *  *
** ****   *  ** **     *  * * **** **** **      *  * * *  ** **  *  * **  **** ***   ** *     *   *  *
*  *  *** ***   **  * * * ***    *** *****     *  * *   *  * * * *  * * ** *** *** *  *  * * ** *     *  *   *  * * ***   *** ** * **   *      **** * * * is a prefix of %s",a,b);
 ** ***** ****   **  *    *** **     *   *   **** *   *  * * **** *  **  *  *** ***    * * * *****  ** **  **** **** * * *****  *  *  * **  *  
*** * *** * **  *** *** ***** **  ** *  * *** ***  ******* ** ****  ***  * * *  **     **** *** * *
 *  * *     * ****      **  *  **** * **    *   ** *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*      ***  * ** *  *  ** *  * * **  * **  *  *****
* ** ** **   *  *    * ***** *      * *   *** **** ** 

* *  * *****     *  ****   ***   ** ***  * *****   *****  * * * *  *****  **  0)
   ****  **** * ****   *****  *** *    **** *** *****  * *        *** *
*  ***    * ** **  * **  *** *  **  *  * *     **     * ** * * **    **   ** **  *********    * * *  is a prefix of %s",pre,str);
*  * **  ** * * *  * **** * ** * * ** ** *** *   * * ** * ** ****** *
  * **    *  *      * *        *** * **    **  *    ** 
*  * * * ** * ***    * * *** ***  * *  *** * ***   *  *  * * *     *   ***** *******
* *** *   *****  ** * *** * ** ******* *  **   *  *****  * **    *  * *** ** * * *  * * ** *  ** * * **    * *** **      is not a prefix of %s",pre,str);
   *  *  * **    **  ** *  **** *       *  *****   *  *** **  ** *    

  *   *** * *   *****      * * * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** * ** *   * *  *  * * * *   a[100];

 *** **    ***  * **     * * b[100];

   ** **  * ***  * ***  i = 0;

 **  * * ** * **** * *  **  prefix = 1;

 ***** ** **   *   *** *  **    **  *** **  a, b);

* ** *  *  * * *    *** ****   len = strlen(a);

* **** **     **   *    = 0; i < len; i++)
* ** * **  * **    ** * ** 
** *****    **  *** * ** * *** * ** **   * *  * *    * ** != b[i])
* ***** ** **   *  ** **  *** *     *  ****  *   * *
 * *        * * *      ****  ** * *  **  *   **   * ** *  * * * * **    ******* * **** = 0;

 * ***  * * ***  *****  ***  * *   *   * ***   ** * **     * *** *   *  ** **  ** * **  **** * ***   is not a prefix of %s", a, b);

 *  *   *           * ****   * *    *    ****** ****** * *  ** * ** *        *  *** **   **
* * * *  *     *****  *  *  *  ****  *** *** ***  * 
  *  *  * *  **  *  *** * ** **
    *   *  **       * *        *  == 1)
*            ***  * *  **** 
  *    ** *  **   **** ***  ****    * *  *** ****  * *  * *     * * is a prefix of %s", a, b);

  *  ********  *  *  *****
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** **** * * 
#include *** * **  * ***  

int main() 
{ 
  *  *  *** **     **** * a[100],b[100]; 
 ** * ** ** *   *    *    * * i,j,prefix = 1; 
  **    *   * *      *   *  ** *  ** %s",a,b); 
 *  *** ***** *****   * ***   len = strlen(a); 
  *    ***** * **  * * **  * *** = 0 ; i < len ; i++) 
***   ***    *   ** ***** * 
**  * ****   *  * * * *  **   * *** *      * **** * *  * * *** != b[i]) 
     *  *       * ** *   *   **  *  ****     **   * * * *  
* ** * **          *     *  **  * ** ***         ******     ***** ***  * ** **  *  = 0; 
* **** *   * *****   ***** *  **  *   **  *   *  ******  **    ***  ** ** *** **  **      is not a prefix of %s",a,b); 
 * **  ** ** * *  * *    **  * **   *** *****     ** * ***** **  * ******  ** * 
*** **   ** ***       ** **  ** *******  *  **** * * 

****   ** ****  **  *  * 
*  ****   ** ****   *   * * *** * == 1) 
   * * **    ********** *   ** * **   **      * **      **** **  *   is a prefix of %s",a,b); 

 
**  * **** ** ** **   *  **  *    0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** * *  *  * *
#include *    ** **    * 

int main()
{
 ** * * *  ****  * * * *** a[100],b[100];
******   **  * * *** * ** ******* i,j,prefix = 1;
 ***  **  *        ** * **** * *** ** %s",a,b);
  * **   *   * * *      * * len = strlen(a);
**  * * **** * **     * ***     * = 0 ; i < len ; i++)
***  ** **  *  *    ** **  *  
***** ***  * **  *** *** *** **  *  ** * **  ************** != b[i])
  ** * * * ** *  *  *  *  ***** *** *     * *  **  * * **
*  *    * ** * *  *    *  *    *****  * * ** ******  *     * *    **** * * ***   *    **  = 0;
** *  **** *  * * *    *** * ** * *   **********  *** * ****    ** **** *  ***   ** **  is not a prefix of %s",a,b);
* ****** ** ***   **    ** **    *  ** **  * *   *  * *   **  ******    * ** *** * *
 * * * *** *   * *  *   **  ****  *   ****  * *  *  *  *

  * *  **  ** ** *  **
** ** * * * *   *  * * * *  * *** == 1)
** * *   *  *     *      * ****  **** *  * **  *** *** ** *    * is a prefix of %s",a,b);


  * **  *  ***   **** ** **   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** ***     *  * 
#include   *  *** *  *  * 

int prefix(const char *pre, const char *str)
{

** * *      **  *  **  * ** *  * ** ***** *  * * 
* *  ** *** *   *   * * *      ** ** * ***** **      * * * 0;
**** ** ** *** * ** *  **  *  *** **   * *   **
  * *      *  ******   * *  *  *  ** **  *  * **  ****   * *   1;
***   *  *     *** *   *** * return 0;


}

int main()
{
*  **     **  *    * ****  pre[100],str[100];
*   *  * *** ***  *  * ***
  *  ****    * *** **  ** *  *** ** ***    ** * ** 
** * *     * ** ***  **** ** ******
  *** * * * ** **   **   ***   *****   ** *  * * *   **  **  *  * is a prefix of %s",pre,str);
  ****** *  **   * *******
**** ***  *    ****    *** *** * ** *       * **** ***   **  **  **  is not a prefix of %s",pre,str);
**  *    ****    *** *    *  ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
     * *  * *  *  ******  **** * * c;
*   ** **   ***     * ****      * **  ** *  * *  * **
* ** * * *       *** ****   * *** *  *   **      ******* *** 0;
 ***       **   * *  * 
   **********  *     ****** *
**  ****    *** ***** * ******* *   * *    ****** ****** **  **  *** * * *   of a string
  **********  * * *  *   *     *** *  *  *  *    ** * *  *  ***   *        ***  * **   * **
*     **     *    *   **    ** ***** ***        *  *** *  *  *   *   ***   ***  *  *  * *   ***   *** *  * **  ** *  0;
       *      **  ** ** *  ***    **     *  ******** *****
****  **   * **   * *  * * * **    *  * *   *** * ** **  1;
    }
}

int main(){
 ** **  *  *   * *  *****   *   a[100],b[100];
*** *    *   ********* *   ***  **** **  %s",a,b);
 **  ***  * *  * *     *****   *   * 
 ***  * *  *  *   **  *** *  **  * ** * ***** *       *  ***** * *** is a prefix of %s",a,b);
      ** *       *****   *  
***  * ** **     * *   *     * *  ** **  *  ** *   * * * *** *  is not a prefix of %s",a,b);
*** *  * *    * ** *   ****    0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ***  ****  * * *  * *** ******* * p[100],s[100],a[100]={};
*  **   ***     ****    **  t;
* *  *       *   ****  ***  **** *  * **
** **    ***         * ** * * *  **     * 
*   **  *  *  * ** * *  *    * *    * **  %s",p,s);
  *  **  * *  *   * ** *  *    
*  * * **  **** ***   *** ** *******   
 ** **   *  * ** *   * ** *** * *    * *  ***  
*  *      ** *    *      ***  *  * * *** *** * 
***  ** ** ***** ** **   *  ***** **
***** * ***** *  *   *** *   ** *  *  ******  **  **********   ** *   * is a prefix of %s",p,s);
 **  *   *    * * * ** ****** * *
 * *  **   ** * **  *** **   *
 * * ****  ** ******    ** *   *** *  **** ****** ** **  **  is not a prefix of %s",p,s);
****  ** **    ** *     *
  *  *          ** **   *** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 19.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 12.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 17k views
12,783 questions
183,442 answers
172,219 comments
4,824 users