1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include *** * *  *  ***
#include **** *  *  **** 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
     ** ****  ***  *  *
 
 ***   ****  *   ** ****   ** **  * *****    ***   **
** * *   * *   **** **  *  *   *   
   * * * * * * **  * ********* *    * **   ** * * **   * ***** == s2[i])
*  ***    *** ** **   **  *  *** ** *   ** *****  **  ***
*** *   *** * * **   ** ****          *     ***   *** ***    *   *      ** *    *** * *   
 * * *  * *** **** ***  ** *      **   ****  * *  *
 
 ****        ** **   *  ** * **  
 
* * *  *  *            * * *  ***** **  == length)
 ***** **   * **    *   *****
 *  * *   * *     *** *   * *      *  * * * **  **   ***      * *    ** *** is a prefix of %s",s1,s2);
   **  * *** **  **  **** *     ** 
 
*    *  * ******  ** ** ** *     
 **  *   * * ** *   * * * *  *    * 
****  ***  * *   ****  **   **** *     ** *  **** *   **** ***  *  * *****    is not a prefix of %s",s1,s2);
 *  *** *   * **   *  ****    * *  
 return 0;
* *   * * ** * **   **  * *  *
 }

int main(void)
{
* * *  *   *  *        *  * **  s1[100];
**     ** **   * ** *   ****** s2[100];
  ***  **     *  * *   ******* i,j;
 **  * *   * * **  * ** 
 ****    *    ** **  ** *  * *** ***   *  * *    ** s1);
*  **** *   *   *     ** **  *  ** * ** *     **  s2);
**    * *       ***** * *
***  *** * ** ***  *  * * *  **   *
 ** * ** *  ** *  * ***   *
 ****  *   * * * *  * *  *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * ***** 
#include  * *   *   * 

int prefix (char st1[],char st2[]){
*** * *  **** *  ***  * ** len=0, i, cnt=0;
 * *  *    *   *** ***  **
   * *** **    **  **  *   *  = (unsigned)strlen(st1);
 ***** * * ** ***     * *** *
 * *  *** ** * * ** ** **  ** (i=0;i<len;i++)
*      *  * ***  ***    *  
** ** *   * ** ** (st1[i]==st2[i]){
**  *   * *   * ***** ** * * *  *  ****** ** * *        **  ****** * **   *   * *   
 ** *  *****     * **** **  *** * * *******  *  * * 
 * *  *   *   *   **** *  
******* * *  * *   *** **  *   (cnt == len){
*   *    ***  *****     * ***  *** *  *** *** * * * ** 1;
  * *** * * *    *   **
*   *    **   * * ** ***** ***
 **** **** ***  ***  *   **  **    0;
*  ****  *** * * * * * ****
}

int main(void) {
*** ** ***  * ***  *    *  *** st1[256];
* *  * *** ***  ** * * *****  *  st2[256];
************* * *   *   *** ** * *   *    ***   *  *  st1);
 ** **     **   *******  *****       * *** st2);

* ** ** ** *  *   * ** *** (prefix(st1,st2)){
**  *  **** ** ***  **** * **   ***    **  *     *  *  *   *   *  ***    is a prefix of %s", st1, st2);
  *  *      ****** *    * *   
***   *    ***  * *  * **** *
*** * * ** *****      *         *    * ** **    * ** ** **    ** *** * is not a prefix of %s", st1, st2);

****      ****** * *    *  *** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*  ***   ***  ** ** ** *** ** * ** ****    *  ** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  *** ***  ***  ****   *  *** ** * ** *    *  *  * *
**    *** * ******   * ** *  * * *****  * * *   *    **  * *        *** *** **  * *  
 ** * ** ***** *  * *** *  *  **   **  *** *   ** ***  *******   **** **  * *  **  *** *** ***** *    **
   * ** *  * * ** **** ***  *   *** * *  ** ** **  * ** *****    * *** *   ******  ***** *  ****  * *****  * ***    * *  *  *** *** *** *  **   * * ** is not a prefix of %s",a,b);
**  **    *    ** *     ** *****     * *** *  ** * **  * ** *  ***  *  **           *****  *   ******* **    ****  ***     ****** ** * **** 
** ** * *** *      *** ** * ***  * * **  * *** ** * *** **   * * *  ** * ***** ***   ***** * *   *  *
 ** **  * *   *****  *  ***    * * *  *      **  * * *   ** * ***   *  * * *  ****
** *  *** * *** *  ** **  *  *    *   ** **   *  * * **          **  ****   * *  * * * **  **     ** * *   ******** * *
 ****  * *  ***** ** ** *** * **  ** ** * * ***  * *    ** * ***     **** *** * **  *     * * * *  **  **  ******** *** * **  ** **   ** ** *  *** is a prefix of %s",a,b);
 **   * ****   * * *   ** ** *  **  ***  ** * ***  * ****  * ***    *  **  * ***  ** * *** *** *****  **** **     ***    **    *  * * **** 
 * *  **  **   * * ** ** *  *  * *****  **   ****** *   ***  ***** ** **    *   ** *  *  ***  ** **  ** **   **** *
 ** ***** *       ****    ** * **  **  ***   **  ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*  *  ** *   *** *** *  ****  ** ** *** * ***** ***** 
   ** **  ** **  * * ** * *  *** *   * **   ** * **  * * 

** ******    *  **  * * *  *     *  * **  ***  * **       *   ****  *  **   0)
 * *  * *** *  ** * ** **  *     ***  * *    ***  ***  *  * ***  *     * * 
 *   ** **     * **  ****   *  *   * *******  *** *****   *  * * ****   **   * * *******      *** ***    *  *   is a prefix of %s",pre,str);
 ** * ** ****   * * *    **  **   *  ***** * * *  *     * *        * * * **  *****
   *  * * * * **    ** ***   *  * *     *         **     **   
*  ** * *  *     ** **** ****  * **  *   *    * *     * *** ********  **  *    ***
  *  **  *    ***  ***** ****  **     * * * *  ** ** *  ****  **** *** ****  *** * *    * *****     ****  *  * * *  *  is not a prefix of %s",pre,str);
** **** * * **  * *   *****  *  *   * *   * ****   ***    *****      * ***  ** **     

 **  ** * *  ***    * *  * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
   *    *  **  *    * **        a[100];

 *  **  **   ** *** * **** ** b[100];

 **** * ***    ***  ** ** * i = 0;

  ***  * ****      *   * ***  prefix = 1;

*  *  ***  *    *** **  **   * * *** ***   ** ** *  a, b);

** * * * **** ** ******  * * len = strlen(a);

*   **              ***** * **** ** = 0; i < len; i++)
 *   * * * * ** *    **
     **   *  *   ** ******  * **  * ** * **    * * **  *      != b[i])
    ** *  *  * *** ****  **    *** ****   * **    **  **
 * **    **   ** *  ** **** *     **   *  *****  ******  *  * * ** *** ***     ***   *** * = 0;

*   ** *** **** *  **      *** *** *  * ** **  * *     *  **   *** *   *   *  *  * * *** **  is not a prefix of %s", a, b);

      ******* *     ** *  *   ** ***   * * * **** *  * * *****       ** *  * * *
  *  **    *** **** ****  **   *** * **   * *  * *  *
* ** *  * **   * *** ** *  
   *  **   *    *****   ** *** *  * == 1)
 * *  * **  *    **** ***** *
 * *     ***** ***   ** * ****  * **   *** ***   * **** *****  * *  is a prefix of %s", a, b);

* **   *   **** **  **** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** ******  *** 
#include ** *   *** *  * * 

int main() 
{ 
   * ** **   *   ** * *  * a[100],b[100]; 
* ** * *  *   *** ***  * *** i,j,prefix = 1; 
 *  *   **    * *   *** *    ****    **   %s",a,b); 
  * ****   *  * ** *** * *  len = strlen(a); 
 * *  *  ***** *****  * * * ****  = 0 ; i < len ; i++) 
** *       ***  *  *  ** *  
     *  *  * * * **  ** * * *** ** *    *  *   *** * * *  ****  != b[i]) 
*  ***** ****  ***  *** * ***  *   * ** **  **   * *    
 **  * ** *  * ** * **   **   *  ***   **  ** * *    *******    * ****** ****  **  **   ** *   = 0; 
 ** * *  ******  ** **     **  * ****** * ** * **   *      *   ********** *   *    * *  * ** is not a prefix of %s",a,b); 
 **  ****    ****** ** **  *  *  *  *  **   **       **   * ** ***   * *        ** 
* ** **   **   **** ** * *   **** *   ***  *  * * **** ** 

 * ** *****   **   * **  
 * * *  * * * * * ** **         == 1) 
  *     **  *    ***  *** * *  **** * *   * *****   *     **** is a prefix of %s",a,b); 

 
*    *      *  *   *   *    *  ** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    ** ** *    *   
#include      *  ****    

int main()
{
   * * *** **  *  * ** * a[100],b[100];
 *** * * ** * ***   * *  *** * i,j,prefix = 1;
    *  *   *****  ****  ** ***  * *    %s",a,b);
**   * ***** **  *** *     * len = strlen(a);
 **  *   **    ** ** *  *  * ** *   = 0 ; i < len ; i++)
   * *  * * * *   *** * ****   *
**** ** ** *  * **   **** *  **  *   *   *    *     ***    != b[i])
 *  * ****   ** ** * *  * * ** *** ** *  * ***   *   
 *   * ****** **** * * **  ***   **  ***   ** *** ***  **** ***   ** * **    = 0;
 **   ** * **          ** ** *  * *** **** *     **    *   * ***  ** **    **   is not a prefix of %s",a,b);
    **** * * * *    *** * **  ** **   ***  *** ** *** **    ********* *** * * ** * ** **  
* ** * *  * *  ***  *  ** ** ** **     * *     *** * * 

**   **   ** ** * * ** *  
 *  **   *  **      * *   ****** * ** == 1)
     ******* * * * *** ** ** *** * *  * *     *    **   *  *** is a prefix of %s",a,b);


  **    * ** * * * ** *  * **** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *      * *   
#include * * ****    ** * 

int prefix(const char *pre, const char *str)
{

* *   *  ** * *  ** * **  *** *  **   *****  ** 
*  **  **           ****   * *    ** * **     * ** *** * 0;
***** ***   **   *** ** ** ****    **   *** 
* * * **  **   *  * *  ***** **** ***     * **       ***  *** 1;
  * *** *     *   ** * * **  return 0;


}

int main()
{
** * * *    * *** ** **  **** pre[100],str[100];
*       *     *   * *     
 ***    *****   **       ***    *  ***  **   * *  
** *    * ******* * *     ** * **  **** ** 
* *  *** *** *     ****    ****** *  ***  *    * * *   *   * **  is a prefix of %s",pre,str);
 * *   *** ***      ***   *  *  
      ** * **      ******  ****  **     ** *  * ***** * **   * ****  * is not a prefix of %s",pre,str);
* * * *  **     *    * **** ****** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 * * ** **  * **  **  *    *** *  c;
 **** ** * *** *** *   *** **   **   ** * *   * *
 * * ** *   **  *   ** **      *  **  **  *** * ***       0;
**  *    *  *   *  **  
  * *   **     * *****  * **  ** 
 **     *** ***   **** *  * * *  * ******   *** *   * * *   ***  **** ** ** of a string
**    ** ********* *  * *  ** * **   *  * *****     * ***  *  * *   **  *** * * **   ***  *  *
**** *****    ** ** ***  *  ***   ** *   *        *      **  **  *  *  **  * *   * * *       **   0;
*  ******   *  * *  **  *  ***   *     **  *  * **   **  
** ** ****   *  *     * * ***     * ** ** * * *** *   **  *** 1;
    }
}

int main(){
 ** ***     **  ** *   *   *  ***  * a[100],b[100];
   * * *****   ** ***   *   * **** ****  **    %s",a,b);
 * *  ** * * ****  * ** *****  *
   ** *  *****  ******* *** * ***  ***   * * * *      ***** ** * ** * is a prefix of %s",a,b);
* * *   ****** * *   *    ******
 * *** ***  ** *    *  ** ** ******   *     ** ****  ** **  *   *   * * is not a prefix of %s",a,b);
 * * *   **  ****   **   * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  *      ** ** ***  **   ****** *** p[100],s[100],a[100]={};
** * * ***  **** *    ** * * t;
  ***** *** * * *   ** *  *** * *   * 
 ***** *  *****      ****** *   * ** * *** 
     * **  * * **  ***  *  **  ***    * %s",p,s);
     ** *     * * *  ***** ***  *
 **** * **     *  *** * * *     ** *
 *   * ** * *  **    * *  **  *
** *  ******** ***      *   ** *  ** **      *  **
***** *  * * ** **** ****        * * ***    
** * * * *  ***** *  * * * ****  ** ****  * *  *  ** *    * * ** * *  ** is a prefix of %s",p,s);
 **  *****    * *   * * *** 
* ***** * * *   ****    
*  ** * *    * * * *  * * *** *    **  *** **      ** * * * **  ***     **  is not a prefix of %s",p,s);
**  *  ****** *  **    **
*  * *** ****** *    * ** * * * ** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.167
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 9.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users