1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ***  * ** ***  
#include ***    *  *    **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** * ***  **   ***  *   
 
* ****  * *   ** * ******  * *  ******* * * *  * *
  ** ** * * ** *** * **  *  ** *  *  
    ****     *   **    * *  ** ***   * **      * * *** **   == s2[i])
** **   *  ****** * ** * ** *  ** * * *   ** ***  ** 
* *   * **   *  *  ****  * ** *   * **     *   *  **** ****** *  ** ** ** *** ****   *
   ***** **   ***  *** *  ***    **   * *** *  * * *
 
  * **           *   ***** *  ** 
 
 ****  ** * *  * ***  * ******   *   *  == length)
 **** * ** *   * *** * *    *  * *  ** **
***** * **  *  ** * *  ***  *   * *  * *** **   *   *   * **   ***    *   is a prefix of %s",s1,s2);
 *   * ******** *****  *   ***  
 
**  * **      *  **   *     * *****
*   ***  ***       **   *  *****  ***
* *  ** **** *      ****** *     *  *   ******* ** **     *  ** **   * is not a prefix of %s",s1,s2);
**  * ** **  * *  * * *   *****   
 return 0;
    **    *   *  *  * ** *  ***
 }

int main(void)
{
***    **    * *  * ***   * *  *** * s1[100];
 *      **     ** * *    * ***  s2[100];
 *  *****  * ***   * **** i,j;
** * * ** ***   *   ** *  
  **              **  **  ** * *** *      * * **  *** * s1);
 *   * *** *** ** * ******  * *    *   ** *    s2);
*   * *********   **** * * *  *
***  ** *  *** ****    *     ** * ** * *  
*   * **  ***  ** *  *   ***    
 **      **   * **   * ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  ***  *     *
#include   **   **     **

int prefix (char st1[],char st2[]){
**** *    *** * * ** *** ** len=0, i, cnt=0;
*  *    *   **   *  **   **  
***  * *** * * *     ****   = (unsigned)strlen(st1);
***  ** *    *  ***     
** ** *******   ** *  *    ** (i=0;i<len;i++)
  ** * **** *** **   * * *  * **
*** *** * ******* (st1[i]==st2[i]){
 *** *****   *  **** **  *  ** ******  * **       ***** ** * *  ******* ***** **    
   **  ** ** **** * **** ** *** **    * ***  ** ** *  * 
*** ** ******** ****   ***
 **    **  ****  * * ** (cnt == len){
  **  * *** **   *   * **    * *** **  * * **  **  * *   ** * * 1;
 *  ****  ** **  * *    * * * 
** ***   *    ** **   *  *
 * *** **** *   ** ***  *  **  *   0;
*****      *   * *    **  
}

int main(void) {
** **** **  *    *  **  ** *  st1[256];
 *   ** *** *  *** *****  *   **  st2[256];
 **  *     * ** * * *  *   *   * * *     *  ***  st1);
**** * ** *  * **  * * ** *   *  * **  ** st2);

*  * *  * *   *    * * *** * *  *   (prefix(st1,st2)){
** *  *   *** ** *  **      *  * * **    *  ******* *****  **  *** is a prefix of %s", st1, st2);
   ** ***** **       ** *** 
 *** * * * **  ******* *   *
     * *  * **  ** * **** *  * *  * **** **   ***     * *   * * is not a prefix of %s", st1, st2);

   *  * ****   ****   ** * **** * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *   *** ** *  *   * ****    *  ** **     * *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  ***    *  **** * *  **    ** * *    *  *** *  *    * 
*  *** * ** ***  *  *   **  ** *   * * *   ** **   * *  *  *   * **   ***  *   **** ***  
**** *****  **  *           ** * *  *  * ****** *     **    ****** **  * ** * * ***    * ***  * * **** * 
 * *  ** *  ***   **   ****** * ****    **** **** *****   * ** **  * * **** *  ****   *  **** *** ***   ** * *    *  **  *  **   is not a prefix of %s",a,b);
      ********  **  ** *  ** ** ***   * * *******  ** *  **** ** * *** ****** ***  * ***  ***     *  * *  *****  *********   *** ** 
  **  *  ****** *     **  **  ***  * * *** ** * **  **   **       * ** **  *     *       *   **    ****
   ***  ** *** ** *   * *  ****  *   * **     ***** ** **         ***** * *     *  ****  *
* * *** ******** **    ***  *  *  *    * * *   **  *** ***  * ***    ** *** **** *  * *  * *    *   * ** * *  *  * * **  
        *   **  *  *   ** *** ***  **     **  * **** *      ** ***  * * * ***  *  **   *  **  *  *** * * *   *** * * *****    ** * ** **  ** *  * ***  is a prefix of %s",a,b);
 *  *  ** *     **** * ** *   *    *  *  ** *  **  * ***    * ****   *   *  **  *  *     ** ** *  **** **  * *  * ***    **** *** *   *    * *
 ** *    *   ** ** **      ** ***   * ***      * *  *  *  **** * *   ********    ***** * **     **** *  *  * *
 *   ***  * * ** ** * *          * **   **  *** *  * * *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
    ** **  **** *   *  *   *** ** ***** **** 
** *  **** * * * **     ** * * **** ***  *** *

  * ** * * ** *    *  * **    ****  *** **    ******* * * **** *  * **  **  * 0)
** *     ******   **   * ** *   * **  * *  ** *  *** * * *  *  ***      
* *****  * ** *    *  ****        * ** ****    ** * **** ***** ****    * * **  *  *     ** **  **   ***  **  *   *** ** **  *   is a prefix of %s",pre,str);
  ***** **   * * *   * ** * ***  **  *  ***  *   **** * *   ****     *
* ** * ** * ***** *   ** *** **     * ** **  * **  * * 
* *** ***** *  ****** * *  ** *  * *** *    ** * ***  **  **    *  *   * * *  
**   * **     *  **   * *   ** ****** * * **  **** **** *  *     ** ***   ****     ***** *     * * *  *** *** * is not a prefix of %s",pre,str);
* *  **      *** * **   *  *   * * * *  ******     *     ** ***  **  *  * *  *   *

  ** *   * * *****       *  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
       *  *     *   * ** a[100];

* ***      * *  *  * ***** **** b[100];

** *     * ***      * * * i = 0;

**** ** **   ***  *****   prefix = 1;

 *    ****    ** *    *  * ***** **  * **** ****   * * a, b);

* * * * **    *  **** * *   *  *** len = strlen(a);

***     *  *  * * *  *  ***    * = 0; i < len; i++)
*  ***    * *** *   ** * 
*  * * *   *    *  *  * ** * *   ** **** ** *  *  * *  **   != b[i])
**  ** * ** **  *  *    *  *****   *********** ** **  
* ***  *   **  ***     ******* *** ** *  * * **    ** *    *   * * * ** *   *  *   *** **** * = 0;

*  * *  ** ***     **  ** * *   *** **** * ****   * ** *       * ***** * *  *     * **  is not a prefix of %s", a, b);

   *    *  * ** **  ***   *     * ** *  **  *  **  * * * ****  ** **  ** *  *** *
** * *  *** **** **  *  *  *  * *    *  ** *  *** * *  * 
  **  *      ***    * * * *  
   *   ** *      ******* ***  *  * == 1)
*  **  ***   *  * *    *  ** **
  *  **** ** ***  * * * ****    **      * *   ***** *  *  * *   *  **   *   is a prefix of %s", a, b);

* *** ***  * **   ***  ** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  **** *    
#include ***    **       *  

int main() 
{ 
*  *** * **  ** ** *****   ***** a[100],b[100]; 
 *  ** *   * **** *  * **    * i,j,prefix = 1; 
    ***   ****  * ****  *  * **  %s",a,b); 
*  *   ** * ** ** ******       len = strlen(a); 
** * * ***   * ***** *     *   = 0 ; i < len ; i++) 
     ** ***   * ** **  ** *   
  *** **  * *  * * * ***  **  * * *  ***  *  *  *   **  *** != b[i]) 
 *   ** **   ***     **  * ******* * ********* * *  
 **  *  * *** * * *     ***      * *  *   ***  **  *** *    * *  ***  * *   ***** * = 0; 
*   *  * * * ***** * *****    ****  * *  **     * * *   ******    **  * ***       * * is not a prefix of %s",a,b); 
   *   * **** **** **   **  * **   * **  ** ** ** * ***      * **  *  ****  * ****  
 ** ******  * ****  * *  * * **** ** * **   * *  *   *    * 

  *    ** **  * **  ***   * * 
 **   * *** *    *** **   ** == 1) 
   * ** **  *   * *** *** *   *** *     *  ***  **  **  * ****   ** is a prefix of %s",a,b); 

 
  *  *  ** *** ** ** ****       ***    0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ***       
#include  ** ** ****    

int main()
{
 **  *       *  *   ** ** **   a[100],b[100];
* ******** * ***  **   ** * * i,j,prefix = 1;
***  *   *   **  *   ** * * *** *  ** * %s",a,b);
   * ** ***   ***** *** * ***** len = strlen(a);
* ** **  *   **  **  **  * *    = 0 ; i < len ; i++)
* ** * * * ** ** *** ** **  *
*     * * ** ** *       * *    **  *  * *  ** ***  *  ** *  != b[i])
  ***    *     **** *** * * ***  ** ** * *  *** *   * 
  * **    *** * **      * *  ***** *  ** ***  * **** *     *****  * *   **** *****  = 0;
*  * ****   *  ****  ** ***  * *  * ***  **  ***  * *  * ** **    **      ******    * * **** * **** is not a prefix of %s",a,b);
 *  * *  *  ****      **** *   * *   *   *** *  *   ** * *  ****       *   * * **   
* ***    ** *   *     *  *  *   **  ****   *** * *   * *****

***    * **   ** ** *  *   ***
** **   *     ***    *  *  ** *  *****  == 1)
******   *  ***   * ***    ** *    * * ** ***    **** * **   ** *  is a prefix of %s",a,b);


**** * *     * *     *** *         * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****  * ***   
#include *   * * * **  *****

int prefix(const char *pre, const char *str)
{

   * *   *   ***    **  *  **  * ** ** **  *   *** 
 **** ***  ****   * ****  **   *   * *** **** * *  * * *  *  * 0;
  **    *****  *** ** *  *** *  ** * * **       **  *
****  **  * *****  ** ***   * * *** *    * *  *    *   ***  1;
 **   * * * **  ***   ** ***   return 0;


}

int main()
{
 *****      * *   **** * ** ** pre[100],str[100];
  ***  *** ** **  ***
****  *** * *** * * *  ** *  *** * * ** ****    **   * 
* *  *  ** * *  **   ** * **  *****
****** * * *      ***  * ***** *  ** ** **   * **   ***  ***  * ** * is a prefix of %s",pre,str);
 **** ***   **  **  **  ** *  * *
* * ***    ***    *****  *  ** *  *****   ********   **  * ** * is not a prefix of %s",pre,str);
* * * ** * *   ** *** **  **** * *  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
  * *   *   * * **** ** * ****** c;
 **    *  * *   ** * *** * ***** ** *    **
  *** ***   *** * ** *   * *  * *  * * * *      *    ** 0;
 *  **  *  **  *      
 * * * *   ** *  ****  *   * 
*** **** **  * * *** *  *  *  * *   ** *  * * **   * * *  ****  * *   * *** *   * * of a string
 ******* **** *  **   **   *  * * **  *    ** * ****** **** ** * ****    *     *  **    
 ***  *****  * ******  ** * **** ****  ** * ** * ** * *   *  * ** **  *  ***   *      * *   * * ** * **** * 0;
*  * *  * ** ** ***      **  **  *** *       * * ***  
**  ** *   ** **** **   *   * *  ** *   **   *  * *     * *   1;
    }
}

int main(){
** *  *   * *** ** **** * a[100],b[100];
 *    **     *   ** * * * * ************ * %s",a,b);
** *    * * ** *   * ** *    ** 
** * ***  * * * * ****  ***      *******      ** ******   *   *  is a prefix of %s",a,b);
       ** ***  *  *   ** * *
 ** **         * *** * **  * *   *** * * ** ** *  *  *   * *** *  *  * is not a prefix of %s",a,b);
  ** *** **   ** * *  * * ****   0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * *   ***** ******* * * * * p[100],s[100],a[100]={};
*  *  ***  *  *  **** * *  *   t;
   *** *   ***** *  * **  *  *****
** ** * **   * *    ****** * ***  **
* *  **** ****  * ***  * * ***      * %s",p,s);
****   *  ***  * * * *     * *  *   * *  *
    * ***  **  **  **  ** **  **** * 
 *  *  *    ** **** ** **  **   *  *** *
 *  *  * *  *      ***  * * ** * ***      ****  
**  *    *     ** * **  ************ *
*****  *  *** ** **  * * *********** * ***    * *  **  ***** ** **** *    is a prefix of %s",p,s);
*****   ****    ** ******  
* *** **      ** *     *    
 **** ****** * ***  * ***  *   **   **  **** ** ***  *  ** * ***    * *  is not a prefix of %s",p,s);
 *    * **  **  *     **  **   *
**   * **    * ***   ***   * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 18.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 16.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users