1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
   * ** * * * * ** ** **
    **  ****  *   * **  * *   *** * *  ** ** * **  **    
    {
**   ** **  **     **   ***** ******  ** ***      ***  (i=0; i<=strlen(string2)-1;i++)
*  **  *  ***  **  ***** **  * * *** **    * ** 
   * ****    ****     * **** **   *  *** * ***  **  **   **  *    * **   **  *  *   *  (string2[i]==string1[i])
 *  *  **** *** **  **  *   * ** ***   * ** * **   **  *    ** *  ** *  ** ** *
    * *  **  *******   * ***     * *    ** * *****   * ****** ** *   **  * *** * **  * ** *     *  **  ** ** * **  
** **    * ****   **  ********* * ** **   *   *  *    *** *  **   * ***  *******  **   *** * * 
 *** ** * ****  **  **** * ***     *   ** ** *  **  ****
 *  ** **  *    ** *   *       *   * ***     *** **   *   
* ** **  * **  **  * *    *   ** * *********      **
    *** ***   * ***   *  ****** ****  ***    *  ****** * * ***  ***** ** ** *   *** * * * is a prefix of %s", string2, string1);
 **         **** * * * **   **  *     *** * *  *** * * 
* *       *** **     *   *** ** *  *****  * **** *  *** *  *
 *****    *** *** *  **** **  * * ** *   *    *****  
**   * ** *    *  *  ***  ** * ***  ***  **  * ** ***         **   ****  *    ** * ** **** ** is not a prefix of %s", string2, string1);
**** * * * *   ****       * * * **  ***    * ****  **  *
    }
** * *   * ** *** ******* * ** ***  *    * *   ****  
    {
**** *   ***** **     *  * **  *** ** *   *  **** ** *** ** (i=0; i<=strlen(string1)-1;i++)
*  **   *    *  * *     *** * *  * * **   *    **** 
 *  * *** * ****  *  **  * *   *  * **   * *   ****      * *** ** * ** *****  *  (string2[i]==string1[i])
******  *  * ** **  ** * * **** **      ** * ** ****  ******* *    ** * ***    *******
    *   ** **   ** ***    * *** ****      **  *  * * **  * ** * * ** **    ***** *  ***** * **   *** ***     
  * * **   *  ** *  ****  ** *  * *     * ******** * **       ****  * ** 
***  * * *  *  ** *****   *  **   **  *** *    *  *  * * *
**     * ** * * ***     **   ** * **** * *  ***  * * *   ****
**** **  * * ** *   *** * *   *** *** *  * 
 ****  *   **  * ***    * *     *    *    **   *       *      * *   *  ****     *  ***** is a prefix of %s", string1, string2);
  * *** **  ***    *     *  *   *  ** ** **   * *   * * **  *
 *******   *     * **  * * **   **  *****    ******   *
 **    * *    *    * ** * * * * **** *** ** *    * 
* * ***** ** ***  ** ***      *     ***   ** * * * * **     ******  **  * * * *  *****    **  * ** is not a prefix of %s", string1, string2);
***  * *  *  **   *  * *** *  *** *  **** **  * * ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 ** *   **      *  ** *  *        **  **   *  %s", chaine1,chaine2);
     **  *   **   *   ****   * ** ** *  *  *
*  * * * ****     *    * ** **  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**   **** ***** * **  *** * *  lenght1,lenght2,c;
**  *  ** **   * **  *  * ** * b[100];
**   ** *** **** **   ***** * * a[100];
 *  *  ** **  *  ***** * **  d[100];
 * **** * *   ***  * *    * ** ***   ***     
*    * * * *    **     *** *  **  *    * **  * 
*** * *  ** ***  *  * * ** ****   *  
  * *** * *** *  * **   *   ****  *  *  * **
*** * * ** *  * *    **** ***** ***** 
* * ***** ** ***********  *  
*  * ** *  *  *  **  *    **  ****  ** *** * **** *   * *** * is a prefix of %s",a,b);
 *  *** * **** * ****   * *   * 
***  *   * * *   *** **         *
***   ***  ***     ****  
 ***  *  **** * ** *  ** * *  *** * **** ** *     ** * *** *  **    is not a prefix of %s",a,b);
 **  **   *  ***** *    ** * *
*    *  *  * *     *  ***   ** * **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **** *    *  * *
#include    **  **  **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* **** *  *  i;
     ** * * *   *** ** *** ** *** * 
  {
 *    ** ** **  * * **   ****     * **  **    A[i]!='\0' && A[i]!=B[i]   )
**   * *  * ** ** ** * ** *     **     ** * ** ******   * ***  *** ***  0;
** *    **  **   ******      ***** * *  * ** ****** ***** 
  ** **  *** **  ** *****   * *  *    *  **  *** * * * ** * **  *** **** **  
  }
*       *  ******    1;
}


int main()
{
 **** **   *   *  * *  * ****  ** *  a[n],b[n],c[n];
    ** * * **   * * ***    i;
*   **   * *   ** *****  *  * *  ** *  * ** * *  
   *******    *      *  *    *  ** **** * *
  * * *  *  **  *  * * * **     (aa(a,b)){
* *    * *** ***   *** *   *  *     ***  *** * **     *  *******
 **   * * ** ***  *   *  * * ** *  * **  *******  **** *  **  * * **** ***** *      * ** **
 ** * *  **   **  *** *     *  *   ** *   **  * * *  * *      *   ** ***   *  ****  *    **** **   **** **  * ** **
   *     *  * * *   ******     ** ** **   * *   ****   * ** ** *  ** ** *  *** * 

 * **  *  *** ***      *  *  ***   * *  * **** **   ** *  *
*  **  **           *** ***** *****  ** ** **   ** *    ** ***     is a prefix of %s",c,b);
   **  * *  **  ****  ** * * * *
   *   *  * * **        **  
***** **** *  *** **   *  **  * *  *   *    *         *  **  *   * *   *   is not a prefix of %s",a,b);
*  *** **** *    **  **** *  *  * ** *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  ** ** **** *
* **  ***  *** * ** * *
int main (){
char *** * **** 
char *  ****  *
 * * *   *   *  string1: *   * ** 
*  * ** **  * **  *  ***  **  **
  ** * **   * *  *  string2:  ** * * 
 * ** ****  * * * *** * * *
*****  **    **  ** *  
**  **   * **** *    **  ***** * ******  * * * is *  * *    *  of    **    ****  *  *
else
***    **** * *   *  *      ***  * ** *   is not prefix of     * *  ** * * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ***  *** ** **
#include   *  * **   **
#include  **** *** * * *  *
#include  ** ** *  
int prefix(char p[],char s[])
{
**** ** **    *   * ** *   **** *  ***  *
**  ****   ** * *  * ** ***** 0;
 * ***    **   ***    *  if   *** ****   **  *
  ** ***  **  *** * *  *  *   1;
**   **** *   ***  *  ***** 
 *    *     *   * * *** **  * *** 0;
}

int main()
{
     ***** **** ****     p[999],s[999];
*** * *  ** **** * **  ** *   **   **  * ***** *
** * *     *   *   **   *   * ***   *    *** 

    *   ****   ** ** *     ***  * 
*      **** **** * **  * **  ** **      is a prefix of %s",p,s);
*** ****       * * 
*  ***** **  *  *** ** ** **    * *  *   * is not a prefix of **    **   *

*      ** * * * *  * *    *   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *   *  **  *
int main()
{
* ** * **  ***** * * * * *  length1,length2,c;
 **  * * ** ***   **      a[100];
**  **  * * *  **   **** *     * b[100];
  **  *  ** *    **   * ** *   d[100];
***  **   ***   *** ***    * *   * * * *      ****  *
*      * ***  **** *  ***  ** ***  ***       ***   
 * *   *  *     * **    *  *****    *****
    ** ** ******   *  *  *  *  *    *  * *  *   **
if (strcmp(a,d)==0)
     *  **   *** *  **** * 
*  ****    *****    *****  **  *    ** * **  ** *** *    *  * is a prefix of %s",a,b);
* *  ** ***    ** *   * * * **
 **          ** ** *  ***** * *  
* * * **  * *  *  *   ** *   
  **     * ** ***  ***  *****  * ****** ** *  * * ** * *  **  * *    is not a prefix of %s",a,b);
 ** * ** * * ***  ****  *
 ***   *  * ***  * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * ** * *  ** **   
#include  ***    *  * *

int prefix (char  *    ** str2[])
{
* ***  * **  * * * ***   *   length=0, **  *
***   * *  **  *   ** 
 *    **     *      * **  ***  =  *****   * * *** 
* *   *   *** *  ***      **
  *  *** * *  *** ** ***    *   ** **    **  *
 ***       **** *        *  *** ***    
 ***  *  ****  *    **  *  ***** if *   * ** *    
** * * *   **     * *****        **** * *  * ***** **  *    
  * **  *   *** ** ***** * * *   **   }
* **  **          **** * * *** *******
** *******  * ***   ****      (count == length)
**** * *   * ** * ***   *   * ** **  ** 1;
* *  **    *    **** * ** else  ** ** *    0;   * ** *   * * *** *  
  *** **    ***  *  ***    **  * 
}
int main(void)
{
****   ** **** ** *  * **  * *   *  *   *   
 *  * *     ****  *    * **  
** ***  ***  *******   *   *   *     * * *   ** ** str1, str2);

     * **    * ****   * **  *  *    **
*  **   * *   {
    ** * * * **    *    **   *** ***    ** * **  **** **   is a prefix of ** *  *  str1, str2);
**  **   *  *  *  ** *   * 
    * **  ** *** **  **  * **  **
* ** ** **  *    **  **  * *     *  * **    * *** * **  *** ***    ***  *  is not a prefix of *  * * ** str1, str2);

 * **** * *** **   *   ****     * *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * * **  *  
#include **  *      ** ***
#include  **   * **  * *   

int main()
{
 * *     * **  *    **  ****   prefix[100];
* * ** *  *** * ** *  **     *  word[100];
  * ** ** ** * * * * ***     * **  ** ***   %s", prefix, word);
      * ** *  ***  * * ** * i;
 *** * *   * ** * *  * * ** = 0; i< strlen(prefix); ++i)
 * **  * ***   * *      * * *
  * ***  ***       *  *****     ** * *** **     **   ** *  *** 
     *   **** *    *** * *    * * ** *** ** ***  ** *
  * ***  * ***   **    **   **  ** **   ** * *  **       **   ***     *  *  **** **  ** *******   is not a prefix of %s", prefix, word);
 * *  *    * ** ** ** **** ** **  ** *   ** *** **** * * **** * ** **** ** *  **  *  * ***  0;
           *  ** **  ****** *    ** *   * * **   ***    ** *
* * ****  *** ***   * ****  *
    * *     **** * * ***  **** ** ** *   is a prefix of %s", prefix, word);
    **** *  *   *** *** *** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * ***  **** *
#include *   *** *  ** *
#include    ****   **    *

int main()
{
**   ** ** * ***** ** *  ***     prefix[100];
**  **        * *   ** * ****       word[100];
   * * * *   *** * * * ** **    %s", prefix, word);
 * **   * ***  *****  *** i;
***    *    ** *       * * *  = 0; i< strlen(prefix); ++i)
 *   **  *  **  * *** *   * ** * *
*  ** * ** *** * *** **** *  ****   *  ***** **   **   **     * * 
***     *     *   * ** *    *****  * *   *   ***  * * ** **
 *     * * * *   * **  *   *  *** * * * ****   * *** * ******    * *   ***  *****  ***  ****  is not a prefix of %s", prefix, word);
  ***   ****  ****   *  *   ** * *****  ** *     * *   * ** **  *   * *  *** ** ***** *  0;
    * * * *  * *  * *   *  **   ** ***  *****    **
  * **     *****  **** 
 * * *   ** * ***** *   **   ** * **  * is a prefix of %s", prefix, word);
**  **      * * ** ****** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *  *  * ***  *** *
*      *** ** **
**** * * **      *   **    

int main()
{
  **  **  *   **  char   *     
        *   **   * char ** ***  
  * ***    *****  *  * * *  *  ** ***** *      word);
 *   *  ****** int i;
*     * **** ** for(i = 0; *  *    *     ** ++i)
***    * ***  {
 *      ***   *** ** * *  * * *** **      *  
* **  ***     *     ****      * * {
  ****** * *   ** ** * * * **  *    *  * *  * * **  **** * * is not a * * of **  **  * ** word);
 * ***   **  *   *   *  * ** **   *     ** **       0;
 ***   * *** *    * * **   *   * }
*         * *   }
  *  **** * *     ****  **    * is a prefix of *  *   *****  word);
 **  *  * *   **  *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.13
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 9.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users