1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   **  ***   *  
#include * * * * *   ** **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** * * **    **    * ** 
 
 **** *   *  *  **  *****    * **** ** * *** ***  ****   **
*  *   *  **   * *   **   *  *   *  
*  * **   ***    *   *  * ** *  ** * ** *   *** **** * * *  == s2[i])
 *   *   *  *   ***  *    ***   *   *   *        * * *
 **** **  **  *  * * ***      **   ****   *  ***  *** ** *   *  ** **  * ** *  **    
 * * ***** * **  **** *   ** **  * * **** ***** *    *  * 
 
    *** **  * * *   *    * ***   ***
 
******** ** * *     **  *  *  ** ** *   * == length)
     **     *      ** ***** *  **  
*** * *     **      ******      * *  *   *  * *  *  *     ** ***      **  ******  * is a prefix of %s",s1,s2);
*    *  *  ** *    * ** * **  * 
 
******* **  *  * *    *  ****  **** *  **
 **   ***  * *** * *    ****** ***  
* **  *  *****  * **    * ** *  * *  *** *   ***  * *      *** * * *  ** **** is not a prefix of %s",s1,s2);
 * * **  * ** *  **  *** ** *****   
 return 0;
   * * * ***  *** **    ** *** **
 }

int main(void)
{
* * *  *** * * *  *   ** ***  s1[100];
  *      ***** ******* ***  * * s2[100];
 ****** **   ** *  * *  * ****  *   i,j;
 **  **** **    *  *  ** 
*  ** ** * *   *    ** ** ** ***  *    * * *** *  s1);
 *  *  *    **** ** *  *** **** ** ** ***  s2);
 **** * ***  *   * *  *  
 * **** **** ** * *** ***  *  **
    **          * **
* ****  *   *  ** ** **    * **     0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include        ** *  *
#include  ** **   *** * 

int prefix (char st1[],char st2[]){
*** * ** ***  *     *** *  * len=0, i, cnt=0;
  **    ** ** **  ***  * **   ***
****** **  *  **  ****     = (unsigned)strlen(st1);
* ****   **  **   * ***
**** *****   *  *  * *******  (i=0;i<len;i++)
         ** **  **     **  *   
***  **  ** **  (st1[i]==st2[i]){
**    *    *   * * ** *** *  ****   *** ** * ***     *  **   * *** * *  *        * **  
*  **  ***      *   * ** **   *  ***        **** *
**** ***     * * **  ** * *
  *** *    *  **  *   * (cnt == len){
** * *  * *  * ***    **  *   * * * * ****  **    *  *  **  1;
  *  * *     ** *** ** *    
* **** ***      * **** * ****
 ***  *    *   **    **  * * 0;
 *  * ***   ***  **    **** *  
}

int main(void) {
* *  *     ********* ** *   ** st1[256];
* *     ****   **    ****    st2[256];
**  ****       *   *   ***** **** ****  ** ****   * ** st1);
*  ** *  **  *  ** ****  * * * *   ****   **  * st2);

 * **   * ***  * * * **  * * * * (prefix(st1,st2)){
     * * * *   **   **  *** ***  *** *   * * ******  * ** ****  is a prefix of %s", st1, st2);
*** ** * ****  *  ***    ***
  *  **** * * * ***   * **
*** * *  * *  **** **** *** *** ** * *     *   *** ***    *     * * is not a prefix of %s", st1, st2);

 *  ** ***** * * * **     ****   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** ******  **      * *** * **** ***    * *****  ** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*  *   *   *  *    ******   *   *        *    *  * ***  * 
 ** **** **** *   **  ***  * **  *     ****** *   * *** * *  *   * *   *** ****  * *  *  *  * **
  * *  * ** * ***   * ******** *   ***        **  *   ** *    * **   *  **  **    *  **       * **** * 
 *   ** *  *  **** *** *   *  *** * * * *  **   *  * ****** * *****       **** *  *** *  ** ** * *  **   * *  **** * * **** * * *    *  * *******  * is not a prefix of %s",a,b);
   ** * * *  *** ***     *** ***  *    ***    ******* *  ****   ***  * ** * *  *  * **   * *   * *     * **  *** * ***  *   *  **
** *    ** *****       * * **     **  *  * ** *  ****    **  **       * *** * *  * * *   ********* * * ** ** **   *
*   ** ** ***** **** *  * *  *** **    *  ** **  ****** ***    ***** *   **** *  * ** * ** 
* *    *  *** **   ********   * *** ***  *  * **  *** *  *   * **  * * *     *    * ***** * *  *  *   *
* *** **   **      ** * * ****** ** ** ****     *  **  **  * * *****  *  *** **** * * ** *          * ** *  ** *  *     *   * * **     * ***** * * ** *  *  is a prefix of %s",a,b);
***      *     *  *****  * *   *****   *  *     *   *  ***  **    *    **       *  * *   **** * * * **  * * **   *   * *   **  **
*    *   *   **    **  *  * ** ****     *  *  **        **   **   * **  * * **    ****     **  ****  **   *
* *  * * *** ** * *   ***   * ***  * *     * *   ***




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* ***  **   **  * ******   ***   **   *     ** *** 
 * *  * ** *  ** ***     ***  * * **  ** *    *  *

 **   *   **  *** *  * *  *  *   * *     *** *****    *  ****  * * **   ***  * *   * 0)
*   ** * *  * * ** * ****   *** *** * *   **   *  ** *  *  *** ** *  ***
* **  * **     *      *** *****    * ** * *  *   *** *** *  **    *  *   *  ****** ***     **     * *** * ***  is a prefix of %s",pre,str);
** ** ** * * ** **** * *   *  *** * *** *** *  *      ** ** *****    ** ***
  ** ***  **        **   * *  **** ** ***  *  **  *  ** ****    
  * * *   **  **** ***   * * *   *  *  ***  ***    * * * *  * *  **** ***   *
 * ** *  **  *   *  ***   * **** **  ***     * *****  *    **   *   *  **  *   * *** *** *  *  **** *  ** ***** is not a prefix of %s",pre,str);
*** **  **   **** **  ****  * * **   * * * *** * **** ***  * ** ** ***   * * ***

 **** **   **  * *   **   * **     *** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** * *   * ***   **   ****   *  a[100];

**   *  * **  ***  * **  *     *  b[100];

  *  *****  ** *  * *   ** ****** i = 0;

 **   *  *  ****   * * * *  prefix = 1;

 *** * *   **  *  * ***    *  **** ** * ** ** * ****  a, b);

   **** ****   * *  * * * ***  len = strlen(a);

   ** *    ***  *****   *   * *** = 0; i < len; i++)
****   **  ***  *    *   * *
   *    ** *  * * * * **  **    *   *** *       *   *  != b[i])
*    *** ***  **    * *  * **  **  *   ** * *  *****
* * **   **   *  *   *     ** * * *   *    * * * * *   * * *  * **** ** ***   * *****   = 0;

* *        * *** * *         ***  *  ***  * ***  * * *******     ** ** **    * *  * **   ***   is not a prefix of %s", a, b);

** *  ** *      * * ****  * ** **  ****** * **  ******** *    *   ** **   *   *
 * *  *  ******  ***  * **  ** **  **   *   * **
 * * *  ***      * * *  ** *
 ***   * *    ******  * * *  == 1)
 **  ****      * *** * *
 **  ** * ** *** * *  *****  **   * *** ***  ***  * ***   **  *  ***  is a prefix of %s", a, b);

 **   ***     ****  *    *** **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * ***      ** * 
#include *** ***** * *** ** 

int main() 
{ 
**** **  *  *  * *    *** * *   a[100],b[100]; 
*  **  ***** *    *    *** * i,j,prefix = 1; 
    **** **   * *   **  * * ****** * *  * %s",a,b); 
  *  * * ****** *  *     * ** ** len = strlen(a); 
  ** * *****   *      ** * * ***  = 0 ; i < len ; i++) 
*  ** * *    * * ** * ** 
    * *  ******    * ***     * *   * *    *  * ** **          != b[i]) 
  * **  **     **  * ** * *       *** *******     * **    * 
* * * ** ****   ******      * ** * *  *** * *     ** *** ****   ***   **  * *   ** = 0; 
***  * *** ***  * **  *  ******     *  ***    * *  * ***            * * **  ***   *  ***  ** is not a prefix of %s",a,b); 
    * * **   * ***   **** ***  *   * * *   * * *****  **   * *   * * ***  ** 
* * **    *** * ** *       * **  * *  *    *  ** *  ** * 

* * *****     **** **    *  * * 
 * **  *  ***  * *** ** * * == 1) 
  **    *** **     ***   ***** ** * *   * ** *   *** *       * is a prefix of %s",a,b); 

 
 **   *    *  **  *   **  ** * * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * *  * ***   *
#include *     ** ** * 

int main()
{
  *   * *****  ** **   * ** a[100],b[100];
   **    ***  *  *** * *   *  **  i,j,prefix = 1;
    * * ** * *** * * ** *** *    *  * ***  %s",a,b);
 ** *  *  ** *     * *  *  **  ***  len = strlen(a);
     ***  * ** *****   * *   *  * = 0 ; i < len ; i++)
   *** * **** **  **** **  
 * ** * *****   * **** **    ***  ** * ***  *   *  **   != b[i])
* ** * ** ** * *  * ***    ** * *  *** ** * **   *  * **   * 
  **  *****  ********     ***    ***  **  **  * *** *  * *** ** *  *   ********** ****  = 0;
* *  ***     **  ** ** **  ** **    ******  * * ***  **  ***    * *   ****   *   ** * is not a prefix of %s",a,b);
** * *** ***** *   *     ***   * *** **  *  ** *  *     ** *    **** *         **    
***   ** ** * *  * *  ****  * * ********* ***   ***** *  

   * * ** *    ***      * * * 
 * *     * ** * ****** * *       **   *  == 1)
* *  * ** *   **** * * ****  ** * *  **** *** ****  ***       **  is a prefix of %s",a,b);


 * *******  **   *  ** *  ****** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * ***    **
#include  ** **   ** * *  

int prefix(const char *pre, const char *str)
{

* *** **  ** ****   * *  * * **  *     ***** * * 
 * ***  *   * ***  * * ****  ****  **  ** **** **  *   *  *  0;
** * *  * ***  *   **     **   ***   *  ***  **
 * *  * ******   *    ** ***** **  * *   ***** *** *  * 1;
 ******* *  *  **   **       * return 0;


}

int main()
{
  ***  *** ** **       * *  pre[100],str[100];
 *  * ****   *  ** ** *
  * *  *     *** **    *   * *  *    **   *   **
**   **  *  **** * ****  ******  *  **  ** 
    *   *****   ***  *  **** ** * *    *  * *  *   * *   * *   **   * is a prefix of %s",pre,str);
 * *    *     **** * *   * 
 *******   * * *** *     *   ***   *      * * *  *** * *  ** ** * is not a prefix of %s",pre,str);
* ****    **  *****   ** ***   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 *    *** ** ***  *    **** c;
 * * ****  *  *  ****  *  * ** *      * ***  * ** *
**  *  *  *   *  ****** *  * ** ** ****    * * *  0;
 *  *  **  *  * * * *** * * * *
  *  **  *  ** * * *  * *
 *    * ***  *  ** **    ****       *******    *** *  **   ***  **** * of a string
     *******   ***  ***** ** ***    * ** * * ***    *  *** *  * *** ***  **   *  
     *   **** * **         ***   * * *    ***  * **  ******* **     **  ***   *** *     *    **  0;
 * **  * ** * * *  *   ***   ** *  *** *    *   *  **** *   * *
 ****    ** *  *  * * **    ******       * *** ******  * 1;
    }
}

int main(){
  * * * * **   ***** * * ** **  ** a[100],b[100];
 ** ** *   ***   * *     ** *  **  ****  %s",a,b);
** ** * *  * * *  *     * ***  * * ** ***
 * *****   **** *** *   ****    *     ** * ** ** ** **     *  ***  is a prefix of %s",a,b);
**  * **    *   *   ***      
 * * ***  ** ***  *****  * * ***** *  *  * ******  ****  *  ***   *  ***  is not a prefix of %s",a,b);
** *  * *   *     *** * **  * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**  * *** ** *   * **  * * *  *  p[100],s[100],a[100]={};
*  **  *  **  ***    * * ** ** t;
 * **   *  **** *  * * ***      ***  * ** 
   * **  *** * * * *  * ** * ** *** *   *
*  ** **  *   *    ** *   ***  **    *    ****** ** %s",p,s);
     * ****   *   *  **   ** ***   **
*  ** **  ***** *  *  **** ***** **
 ***  ** ** **    ****** 
 *  ***** ** * ** *    *   * *** ******  ** 
*** ***       * *  * ***** ** *  *  *  **** 
** *  ** ***  ** ***  ********   * ***   *** **   ******** **  is a prefix of %s",p,s);
     ** * *** * * * *   ** 
*****  *  ****  *****      * * * 
  *    **** **  ***    *       ****** ** ** * * * * *  *  is not a prefix of %s",p,s);
* *   ** *  * ****        * 
 ***   ******       *  *  ** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.60
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 9.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users