1-11 Exercise 3: Prefix of a string

0 like 0 dislike
13.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 13.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include * *******   ** * *
#include  **** ** * ** * *  

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* *     * * *   * ***  ** *** 
 
**  *  **      ** * *****        *    *  *   
  * *  * **    ***** *  *  **   
  ***** * * *   * *  ** *  *  * ***     *  ****  ** ****   == s2[i])
****  * *  **   ** *  *  *      *  *  ** *   ****** * ** *
******  *** ** **   * ***  **   *    *** **** *   ***  ***  * **** ** *  ***   *    
* ******** *  ** **    * ** *  ** **   *****     **   *
 
*  *   * ****    ***** *  **  *   **
 
  ** ***   *** *********  *     ***     == length)
 *** ** *    * * *  *********  *** 
  **   ****  * *   *** *  * ***  * ***  ****  ** *** ** ** **** *** is a prefix of %s",s1,s2);
 *   * *** *   *  *** ***** **  * 
 
* * *** *****   *  *        ** * ** **
  *  **  *** * ***    ** *  * 
** *  * **   *   * ** * ***  **   **   *   * * *  **   *   *****    **      is not a prefix of %s",s1,s2);
*  *  *      * * *   *   ** * **
 return 0;
 ****  ** **   * *  **   * *  *** * 
 }

int main(void)
{
****  * *  * *   *****  *  *** *  s1[100];
** *      *  **  **  * *  *   *  s2[100];
***   **  * ****  * ******** i,j;
 ****** *   **      **      
 ***   *  * **  *  *  ***  ***   *** ***  *       s1);
   ***** ** *       *     * *  ** ** * ** *  * s2);
   * * *  * *** ****** ** *
 *  ** ** *  ** **** **   *        *
 *    *******  * ******
  **       **    *  ** *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  * **   *  **
#include * ****      * 

int prefix (char st1[],char st2[]){
 ******* * ***** * *  * ** ** len=0, i, cnt=0;
 ** *  ** *  ****  **     
 * *   ******  * ** *  *  ** = (unsigned)strlen(st1);
* *****   **** *  **   ** **
**  ** **** * *  * *  ***** * (i=0;i<len;i++)
   * *** ****   ***** *  **
   ********* *** (st1[i]==st2[i]){
***  ** ***   *    * *     * *** ** ***     ** ** **       * * ** **  ** **  *  **  **
****** *   * ** ***** * * * * *      *** ***** ******* 
 **  * **   * * * **  *  ** * *  ***
***  *   *  **  **  *  **   (cnt == len){
* *  * ** *  * * *** *** **  *   ** * **   *    ***   *   1;
 * * **   * *  *******  * *
**     *  * *****   ** ** * 
   *    **    ***  **  * *   * * 0;
** *    *   ***   **   **  *
}

int main(void) {
 * ** *  * ** * * * ***** st1[256];
****   ***  *** ***     *  ****  st2[256];
   * *    *** ***  *  * * *      *****  *   * * *** * st1);
   * ***  * ***   * ** ****   ** **   *   * *** * st2);

  *    * ** * ** **      (prefix(st1,st2)){
**   *   * ** * * * **** *** ** *  ** **  **  ***   *  **   ** **** * *  is a prefix of %s", st1, st2);
* ***  * **  *** * **    **  *  *
   * ****** ***         * 
*  *  * ****** * **     *  **   *  **  **    ***  **** * *     ***  *  * is not a prefix of %s", st1, st2);

* * **    *  * *   *** *   **    **  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
**  **    **** ******** **** ****          * 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 *       * *      ***** *  ***   *  *  * ** *   *   
  *  * *** *   ****    *  *  *  *  * ** *  * * * * ***  *  *** **    *  ****   ** **     ***
 *** ***     **** * ****   ** *   * *  *  *** **   *   *  *  * * ** ****  *   **   * *   * * ** *  *
** *** * * * ** * *  **  **** **  *** *****    ** *     ** *          *  * * *** * * ** * *      ** ***  * *** *  *      * *** * * * **   ** * **  is not a prefix of %s",a,b);
 **** ** ** **********     ** * *  **   *** ** ** *** * ** ** * * *   *    *  *  **  *     ** *   *   ****** ***  *** **** *    * *   ***
*  * * *  * *** *     **  * ***   *** *  * **      * **        *** **   *  *   * *   * * * ** *  * *   ***  * 
  *** *** **   **  ** * ** ****** * *  * *   *** ***     * *  *** ***   * ***  ** *  
*   * **  ** ***  * *****     **** * **      ** *  ** **  * * **  *  * *  *   ****  **    **  ** ** *** *  **  
** ** ** ****   * **  *    **  ** ** *   *    **  * * *  **  *****  * * **    *    *    * *** *** ******   ****  ******  **  *  ****  *   *   * ***** * ** is a prefix of %s",a,b);
 * ***** * **  *     **  *** ** ***  ***** ** *  * **** ** ** ****   **   *** *  *******     ******     * ***  *    * * *     ****   **    **  *
 *  **  *****  *** * **       ** *   **   * *   **  ** *   * *   *******  * *    *  * *   *  ** * *  *  ****** 
**  **      *   * ****          *** ***   ***   **  *** * ** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*******   ** * **  ******  ** **   * *  ** **   *** *
*  *  * ****** **  ***  **** *  *   * * *** ****** 

 *    **  *  * * * * *  * * *    *  * *   *    *   *  *    *   *       * 0)
****  * *  * *  **   *  * *  * **  **** ** * *   * **   ** ** *  * *  
 *   * ** * * **    *** *  *** ******* *  *  ** *  *** ***    *******  * *    ***    ****   **  * *** * ** ****   is a prefix of %s",pre,str);
***  * ***** *** *   ******    ** * * * ** *   * ***    *** *  ***   *
*** *  * *  *   * * *******    *  *** *** ** *  **  * **  * **
** * ******  * *   ** *** *  *** * * **  * ****    ***  * ** * *  * *** ** **  **
***    ***    * *    **  **  *  * *    *   * *    **   ** ***   **  ***    **  ***     * *  * * *****  *  ** *  ** ******  ** is not a prefix of %s",pre,str);
 * **  * *    ** ******* **  ** *  ***   * *** ** * *****      *  ** 

 *** ***********  * ****** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
***** * *  * * ******  * *  * ** a[100];

* *      ** *   * ******   *  * * * b[100];

 ***  **  *  * * *   ***  i = 0;

** ***** ********* *** ***** prefix = 1;

 *    *  * *   **    ******* ** **** **  * *  * a, b);

 *   *** ******* **   **  ***    len = strlen(a);

***    *  ** * *** * *** **  = 0; i < len; i++)
  *  * ****   *  ******** * **
    * *   *   **   *      * * **   ** ****  *   *  != b[i])
** * *** *** ****  * *  ***     *  ****   ** *   *   * * *  * *
*** **** **   **   * **       ***  **  *  **   **   *    * ** **    *  **    *** ****** = 0;

**   * ***   * ****  ****    *   * ** *   * *** * *     ***          * * **** *   * * *   *  **    *    is not a prefix of %s", a, b);

** * *  *     * * * **  **** * ** * *  *   *   **  ** ****  * ***** *    ***  *  ** *  **
  *  *** * ****     ***  * **** * *** **** **  *** *** *
* ** ** * **  * * **  * 
 * *    **  * **   ** * * * ** **  == 1)
****** *** ***  **     *  * ** 
  *   ** **  **  ****** *** *    *  ****    ***  * **  ***   *  ** * is a prefix of %s", a, b);

*  * * * * *  * * *    ** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * ***  **   ***  
#include   *   **** * * * 

int main() 
{ 
** ** *  ** * * ** * * ******  a[100],b[100]; 
******  *** *  * * ******* i,j,prefix = 1; 
** * *  *** **    *           *  * ** %s",a,b); 
*   * *  ** *  * *   **  len = strlen(a); 
 * *   *  *     ****  * ***   = 0 ; i < len ; i++) 
* * *   *   *         * * * 
* * ** ***  **** *     *   * *  ***** *******  *   * *  != b[i]) 
**  *     *  * * **    * *    ** ***  **  ** * *  ** 
 ** * * ** ** * * ***** ** *** * ******  ** ** *       *****  **   ** ** *     = 0; 
 * * *  ** *    **  ** ********  *  **** ** *      ****  *  * ****       ** * * *   ** ** is not a prefix of %s",a,b); 
* *   ** * ***     *** **       *  * **  ***    * *** *  **   *****  ********   *    
  *   *** * *** * ****   *******  *****  * ***** **** *   

    * *****  **** *     **** * 
*  **  *** ******* *      *** == 1) 
 ** *  * *  *** *    *** *** *** ** ** *** * *  ***  * * ***  is a prefix of %s",a,b); 

 
* *  *** *    * ***   ** *  **   0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **** ****  * *
#include     * ***** *    *

int main()
{
**    *  ** *     *   **  * a[100],b[100];
* *    *  * *** *** **********  i,j,prefix = 1;
 ***  **    ******** **    ** * * *** * %s",a,b);
    *  *  ******** * * **    **** * len = strlen(a);
* **  *   **** *  *  ***  ** = 0 ; i < len ; i++)
   *** *  ** *****  * * * **
*   **  * *   ***  ** *     * * *  *   * ***** * * * ***** != b[i])
 ** **  * **    ** ****  * * * ***    *     *   * **  * 
* * ***  **** ***  * *   ** ***  **   ** * * ***  *  *  **   * * *    * *     ** ****  *  = 0;
 *  * *   *   ***** *****     ** ** **         * ** ** ********  *  **** * *** ***  is not a prefix of %s",a,b);
  *****  *** ***** ** *     **  *    *  ** *  ** ** * **  * *   **  ****
    *  * ** ***** ****  ***  *    ** ***     *  * * **

* *  *   * * ***  * *  
****    * **  ***** **** **   == 1)
   * *** * *** **** * *   ***   *   *    *   *       ** ***  *** is a prefix of %s",a,b);


  * **  * **    *  *  *****   ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     **   *
#include * * *  * *    *

int prefix(const char *pre, const char *str)
{

  *** * *** *  **** *     * * * * *    *  *   * *  
* ***    ** ***  * ** ***   *  ******     ****** * *  **** 0;
*** **  **   ** **  *   *******  *** *** *  *
 **    * **  ****** **    ***   **     *** ***   **  1;
  *  ** *     * * ***   *    *  return 0;


}

int main()
{
 ***   **   ** ** *  ** ****  pre[100],str[100];
     *     **  *
 *  ***** *  ***   ** * ** *    ** *   *  ** 
  ** * * * *   *     ******  **  *  
 * *** * ** **       *   **           *** *** * ** **   * **** ******* *  is a prefix of %s",pre,str);
 *    ** * *  * ** *  **  **  
* * *    * **     ****        *    ***  *  * *** * * * * *   is not a prefix of %s",pre,str);
 *   ** ***  **  ***  *** **** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 *   *   ****    * * * *    c;
* * ***** **    **   ** ** *** ** ** ******
* ****   ** ** *  *   ** ****** **** ** *  * *  ***** * 0;
  *  ***   *   **   *
 *****   * *  *** *   *** *  ***** 
*    *  ** *** **** * ***  * ** ****  * * * *** **   ** *  *    *  ****    *** *  * ** * of a string
 *  * ****  *  **    *** *  * * * ***   * **   *  * **  **   ***** * ** ** ** *   *   * ******
*****   * *** ** * *   **         *** * **     **  ******* ******   **  * *  *** ** **    **** ** ** *  * * *** 0;
  *  *** **  * ***         **  * ** *****  *    ***  ***
*  *  ** **     *** ***** *    *  * * *  **    ***     *** 1;
    }
}

int main(){
*****    *   * * *** * ***  a[100],b[100];
*  *  * **  **   ***** *    * *   ***      %s",a,b);
  * ***      ***  *  ****** ** * 
 ***** **  ** **   ** *   * *    *** **   ***  * *    **** ** is a prefix of %s",a,b);
 *  ** **  * * *    * *  **    
* * *   *****  * *  ***   * *  ** ****      **  ****     *** ****** is not a prefix of %s",a,b);
** **   **  *  **    * *  ** * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 **           **  * * *** ** **    p[100],s[100],a[100]={};
*     * *  ****   ***     t;
****    **   * ** * ** ***      *  *** ***
 * *  *  ** ***    * * **** * * ** **  * 
   *** **  * *** **** **  *  *   ***  **** %s",p,s);
  *   **     ***  *     ****** *  
 * * * * *  ****  *   ***** **** * 
** **   *  *****    **  * ***     **  *
*   *****     * *  * **  *    *   **** *****
 * ***   * **   *  ** **   ** ***** **  ***  *
 **    * * * *    ***  *  ***  ** *** * ***  ***  * ***** *   * **  is a prefix of %s",p,s);
  * * ** * ** * * * ***  *   
**     **** * * **  *     
 *    * **   *   *     * * * *****   ** * ** *** **  * *   * * **   *  ** is not a prefix of %s",p,s);
  * *       *** * ** **     ** *
******  **  ** ** **** * ****** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 19.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 12.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 17.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users