1-11 Exercise 3: Prefix of a string

0 like 0 dislike
4.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include * * *   ***** * **
#include *    * **** * *****

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
     *   * ** * *  **    ** *
 
 ** * ***    *  *  *  ** *** ** **** * * * ***    * *   **    
  ***  *   **    **  **  **  ***** **  
*    ** *  ** ** * *** * *   ******* *   * ** *** ****   == s2[i])
  *  *   * * ***   *  **     *  * ** *       *  * *  * *
    * * ** ****  **  *   **  * *  *  *     * ***   **   *  **  ** **   * ****       **
 * **  *** *      **  ** ***       * * ****** **   ** **
 
** **** * * * *** *  * * ** * ***  
 
*  *** * **** ****    **   *   ** * ** ***  == length)
****** ***  * **** * *  *  **   * * ***   
* *** ** ** *   *   ** **  ******** * * * **  ** * **** * ******   is a prefix of %s",s1,s2);
 ****     ** ****  **      *   *  ** * **  *
 
* ***   **  *  *  ** *    ***  * * 
***  **  **   ****** *  ** **   * *
***      * *   * *  *  *   *  * *******      *    *     * ***  ** **  *  is not a prefix of %s",s1,s2);
**  **  *   *  ***** ** * *  ** **  * 
 return 0;
 *** ***   *** *  *  *  * * *
 }

int main(void)
{
 *****  *  **** *   *   *   * s1[100];
*** ** *  *  *  ***      ** ** s2[100];
 *** ****  ******* ****     * i,j;
     *    ***     * **  * ** 
   ***   *  * * *** **    *    * *        ****  s1);
 ***   **   ************ *** *   ** *  *    s2);
   * ** ***  *  * * ** **** * 
**   *** ***  *********  **    *   * * *  
*  ** ** * *  *  *  **  ****
**** **** * ** * ** ***     * ** *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *** **  *   **
#include *  ***  * *   * 

int prefix (char st1[],char st2[]){
* *  ***  **  *   ***  * len=0, i, cnt=0;
    **** ****  ****** * 
*  *  *  *  * ** *  ** *  * * *** * = (unsigned)strlen(st1);
  ** *  * *** *  *  * ** **   *
   ** ***   *****  *  * ** * (i=0;i<len;i++)
*  **   *** ** *   ***     *  *
* ******    **  * (st1[i]==st2[i]){
*** *** *   ** ** * * ** *       *   *    ****      ***  *  * * *  * * *     **     * **
 *** *   * ** ***** **    ******** *******     ***
 *** ****  ***  ** *
  *** * *   **   **  *** **   (cnt == len){
**   *  ***   *  * ** **    * ****      * *** *   **  * ***  1;
  *   * *  ***  * **  *   *  **
  * *  **      *  *        
 * ***   *** * *       * **  0;
*    *     *  ***  *  * **  *
}

int main(void) {
*     * *  *****  ** * * *     st1[256];
*  * *** ** ***** *  *   ** *** * st2[256];
*** * ****** **   * *** **  ***** ** **   ***  * *    *  * st1);
** *  ** ** ***  * *  *  **  ***  *    st2);

**   *  ***    **  * *    (prefix(st1,st2)){
     ** ** *** *   ***  **** *      *  *** * * ** ** * ****  * **  *  is a prefix of %s", st1, st2);
 * ***  *    * **  *  * * *** * 
*    **** * * ** ** *  **   **
    *****    ** *** ** **  ** **** * ****  **  ** **   **    * ***  is not a prefix of %s", st1, st2);

 * *  ** *  *  **  * **** * ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  *** *  **   *  *** * **  * *  * *** *** *** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 * ** * * *** ** * * ** *   *   * * *   ****  *    *     * *  
 * *** *   **** *   ***** *** **** ******* ***  * ** *     ** ********* ** *  * * ***** **** *  ****
*  ** * ********* * *** * ****** *     **** *  * *  ***    *****  **** *  ***** *   * *** *  * * **   **  * *  * *   
*  *   * *****   **  ** **           **   **** ***  ***   * * * **** *  *  ** * *** **** *  * **   *  * ** ** *****  ** *  * ***   * *****   ****   is not a prefix of %s",a,b);
 *  *  **** *  *** *****   *** ****    * ****** * ***   *  ***  ** * ***  ***** **  **   **    **     ** * *  *    ** * ****** *   ** * *****   *  
 *    *   * * **  *** * *      * **   *     **** *       *******       * ***  * *** *   * *      * * ** ****
** ** *  * *   *  *** **** * *    ** *    * *  *  *****  * * * * ** *  **   * 
* * **  *    *  **   * *  ****   **  ***  * *** *   * ******** *** ***  ** *  *    *     *   * ** ****  *  
   * *** *** *  *     ** ** * ***** * *****  *     * *****   **  *  * **** **** *  **  * ** ***   * *********  **  * ** **       *   * * **** is a prefix of %s",a,b);
********* *   ****  ** **  **  *  ** ******* *   * ***   *   *   * *    *** ** ***   * * * **   * **  *     **  *** * ***  *     *   *
 *        *** * * * * **  **  *   **  *    * ** *** * *** **   *  * * **  *  ***** *  *  ****   **       * 
* * ***   **   ***  * * *** *   ***  *******  * *     




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 ****      *  **     ** * **** ***** * * *    ********* 
*   * ** * *  *   ***    *** * ** ** *   ** 

 *   ** ** ******  *  ***  *  ******** *      **   ** * * *** **   * *  ** **  * 0)
 ** * *      ** * ** ***  * ***** ***    * ** * * *** ***** * **  ** ** ***  
 ***  ***    ******* *    * *** *  *  *** * *   **    *  **** *******  ****  *  *****   ***    *  * *   ** * * is a prefix of %s",pre,str);
 * *  * *  *** ** * *  * ** * **** *  ******* ** * **** **    ** ******  * *
** *** *   *  ****** * **   *  **** * ** **   ****** 
  *      **   **** **   ** *   ** * * ** ** * * ** ***  *   ***  * ** *   *  ** **  *  * 
*  *  *    ***** * * *     *   ****  *      * * * *** * *  *   *****     * * ****   * **** *     *  * **  ** **  *  *** * * * **  is not a prefix of %s",pre,str);
  **   ** **  *** * * * * ********     ** *  **  ***  ******   *  ****  ****  *****  

 **  ** * * *** *  ****  ** * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*   *      ** ******  ****  *  a[100];

 *   *** *  ****  * *   * *  * b[100];

     ***  *  *****  * *  i = 0;

* *   ***     *** ***  **  **  prefix = 1;

** **** *** * *     **   * *** * ** * *  ****    *  a, b);

** * ** * *  *   *    *    *   len = strlen(a);

 *        ** **   ******  ** **** = 0; i < len; i++)
*** *** *  * ** * *  **   
*  **** ** *  **     * **         ** ****** *  ** *  * *    != b[i])
          ** *  ** **** ***  **  **  *   * ** *       *   *  
 ** * *   **  ** **  * ** **    ** **  **   ** ****** *    **   ** **   * * **  *   * * * = 0;

 ** *** **  *** **  * *** ***    *   *  **  ** *   ** **** * * *** *  * **   ***    **** is not a prefix of %s", a, b);

** ****  * *   *  * *   *  * ***    * * *   ******   ** *    ****    *     *** ** ***
 ****** *      *****   **   *  *** * ** ** **   * * 
* ** * ** ** ** *  ***  **
  ***** * *  * *  *** * *  * *  **** == 1)
  *** *  *   *  *** * * ** ** *
  *** ** **         **   **   *** ****      ****** **** **  *  *  **   is a prefix of %s", a, b);

 ****   *  **** * ** *  ***  
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include         * *** ** 
#include *   *  * * ****   * 

int main() 
{ 
*  *   *** * ***  **  *   ** a[100],b[100]; 
***   * **   * ***   * * * * * *   i,j,prefix = 1; 
 ** *    *   * ********      * *   * %s",a,b); 
    *   *   ***  * *** ** * len = strlen(a); 
*   * * ****  * ***   * **  ** = 0 ; i < len ; i++) 
*  * * * ****   **     
 *  *** * *  * *** ***  * ***** * * * ** * * ** * ** != b[i]) 
 **      *****    *   ***  **  **     ** ** *  ** 
**    * **    *  ****** ******  **   *** ** ****** **  *   *     ** ** ***  ** *     *** = 0; 
 *** *  **  *** *** ******  *      *** ** * * ** ***  ** *   *  *****   *  *  * *  * * is not a prefix of %s",a,b); 
 ** ***   * * **** *  ** * * ** ** * * **** * ** ** ******* * *  * *    **  *** ** ***  *   
*  ****   ****    ***   ***   *** ** * ** **    *** 

 *       ** *  *** *    **  * 
* **  * *** * ****  * ****      ** == 1) 
*    ***   * *   *** ** **  **     * **   ***  * **** *   ***    is a prefix of %s",a,b); 

 
 *      *** * **** ******  **    * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **** *** *
#include ***** * **   

int main()
{
* * *   *** * *    *  * ** a[100],b[100];
   * ********  *  ** * * ** i,j,prefix = 1;
* * * * ** *** ** **** **   ** ***  *    *   * %s",a,b);
 **** *****  *** **   *  *   *      len = strlen(a);
*   * *   * **  *  **  *******  = 0 ; i < len ; i++)
**    *    ** *  **** ***  ** *
* *  **  *** * *  * *** ** *   **  *  **** ** * ***** ** != b[i])
* **  **  ******* * *** * *  * ** * * *     * *** * * * 
 *  * ** ***  **    ****  *      *     *** *   *****    *  * *    **    = 0;
*   * * *  * **   *    *** ** *** ** *     * ****    **** * * *   ************  *  *****    is not a prefix of %s",a,b);
*  ** *   *         *   *  * * *  *  * *   * ** ****** *  *  ****  *   * *  **  **  
**  **** **   * * **     ** * ***** * *  **** * *    ** **

*    ** *  ***** ** * *  **   
* *        ***  *   ** ********   == 1)
*  ***    * * *  ****  *    *** **** ***   **  **** * * * *** * *** * * is a prefix of %s",a,b);


 * ***  ** *  **   *  **  ** *  * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    **  ** *  * 
#include  *** * ***** * * *

int prefix(const char *pre, const char *str)
{

** ** *  **  *  *** * ** **** *  * * **    ***   
** * **  ***  * *** ****  *  * * * *    ***  *   ****     *  *  0;
    ** *   ** *    **** ***  *   * * ** **  ** 
 ** **  **   *** **   *    *       ***** * **  * *    **   **    1;
*** *       *     **  *     * return 0;


}

int main()
{
**   **   **     * ***** *   *  pre[100],str[100];
     ** * ***   **  *   
 *** * *   **  *** ** ***  * *  *  ** ****      *    *   *
**  ***  ****   *  *** ** ** *  *  ****   *
*  * **  ** *   * ***  ****    * ****** **  ***   ****   * * **  *** is a prefix of %s",pre,str);
 ***      *   **   *** *  **  * *
* *  *  *   ***  * ** *** **  **** *  * *  * ***   **  ** ** ** is not a prefix of %s",pre,str);
* **  *  **** ** * **  * * **  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
   **   *   * *  ***  **  c;
 ** *   * ****** ** *   * ** * ** *  * **     *
  *   ***** ******    *   ***  *  **** *** **    * * **    **** **** 0;
*  ** * **  **  **  ** **** 
*** * *  * * ** ** *  * **   **   
  *   * *  **** **   * *   * ********** *  *  *** *    ** *** *** * **  **      * * *  ** of a string
 *    *  *  ** ****      *** ***  **   * ******* ******* **   *  * ** * ***   *** *  * * 
  ***  *** ***   *  ** *    **  * *** *** *** ****** * **   **  *  * *  **  ** *  ** ** ** *  ** ** * *  *  *  **  0;
* **   ** * **   * *  **  * * **    **     **** * *  *   
 * *** * ****** **** ***    ***** **   * ** * ***  ** * **   1;
    }
}

int main(){
*   **   * ** *  ******* ***** a[100],b[100];
 ** * *  *  ** *****   ** *   * *  * *  *  %s",a,b);
 *    ** ** **   * *****  * *  ** * ***    
* ** * ** *  *** * **   *** * ***  *    *  **** ** * ****   ** * is a prefix of %s",a,b);
 ** * **   **** *      ***
  * **  *  * * ** *  **   *** *   *   *     ** * *   ******   *  ** is not a prefix of %s",a,b);
** *  *    ** ***** **   ***     *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * * **  * *   *  *** * *     p[100],s[100],a[100]={};
    *  *  * ***  **   * ** * * t;
**       * ***  * *** * **   ******* 
 *      * * *****   *  ***  * * *  * **   
*     *    * *  **    * **  * *  * *  * *  %s",p,s);
* ******** *** ** ** ****     ***  
 *     *  * ** * *** **** * **  **
***** *   ****** **** *   ** *   * 
**  * *** ***      * *  **  * *  **** * * *
** * *    ****      * *   *** ** ** * 
   *****  *  *   ** ***  *** ***  *  **     * *   **  *****   *** ** *  is a prefix of %s",p,s);
*   * **    * *   **  
**  *  *  **     *     ** *  *   *
   *   * *** *  ** *** ** *  ***  * * *  *****  *    ****  ****  *  is not a prefix of %s",p,s);
* *    **  ** **   **    * ** ** 
    * * * *****   *    ** *** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.5
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 5.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 5.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users