1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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}
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#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include *****     *
#include ** * ** * * *** 
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}
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Hidden content!
#include ****  *  ****
 **   *  *     ****    ** *
int main (){
char     * *** 
char *  *    *
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include  **  ** * *  ***  
#include  * **** * * **  *
#include    * ** * **** 
#include * ***** ** ***** 
int prefix(char p[],char s[])
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}
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#include <stdio.h>
#include  **  *****  * *
int main()
{
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}
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Hidden content!
#include   **   ** * *     *
#include  ****** *   * *

int prefix (char *****   str2[])
{
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**  ***** **    *   **** * * *  0;
}
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#include  * *  *     ** **
#include ** *** * **
#include ***** **  *

int main()
{
  * ** *     *  * * *   prefix[100];
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*** *    ****      ***  ** **   0;
}
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Hidden content!
#include   ******* *   
#include   *     * *** ** 
#include  ** * * *   *

int main()
{
    *** * *         * * * ***** prefix[100];
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 *  * *    *** *      * * * *  ***  * * is a prefix of %s", prefix, word);
*** **** *  **** *** ** *** **** 0;
}
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* *  ********     **
        ****     ***  *
 * ** *  * **  *** * * ***

int main()
{
 ** * ** * ***  char  ** **
*   *    ***  * char   * ***
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*** * *  ***  * ** * ****  is a prefix of   ***     ** word);
 ******  * * ** ***** 0;
}
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