1-11 Exercise 3: Prefix of a string

0 like 0 dislike
8.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 8.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
    *****    *****   * * *    ***
       ** *        ** *  *    **  **  *** * *********  ** 
    {
  **  * ** *   **  ** *   * **    *    *  *   *      *   (i=0; i<=strlen(string2)-1;i++)
**  *** * * *  **  *  ****  * *  *******  *   *** *  ** *
**  *   * **  ***  *   *   * **  *** * *  * *  *   **   **  *  *   **  **  *  ***    *    ** (string2[i]==string1[i])
    *  *  * ************ **    **  *  ***  ** * ** ****   **  * *    **              ** 
********* *****  *** **** *    * *** *  **  * **  ** **   * ** **** *  *  **  *  *  ** ** * * **   *  *     ** 
  * * * ****   *    ***** **   ****  **** ** **  **  * ***  *  ** * *****   **     * * * 
******  *   *   ******     * *** **    ****  ** **    ** ***    
    * * * * *  *    ***    *  * **  ***** ** *   ********
* *****  **    * **  **  *      ** **** * * * ** **
*  *   **** * * *     *      ** **    * * ** *** **** ***** ****   * *  *****  *******  **     is a prefix of %s", string2, string1);
******   ***** ** * *** *** * * * *  **  **  ** **** **   **
*     ****     * ** ****** **** *****  ***   *  *     *  *
 ***  * * ****  *** * *  * **  *    * ** ***   * * * * *  ***   
 *** * ****  * ** **  **** ***   ***   *********  *   *  ** ***  **     *    ** **    ** *    is not a prefix of %s", string2, string1);
 ***  * *  * *** *  ***      *   *   ***  *** * * *  
    }
   *   * * * * ***  **   ***   * *   *** * 
    {
  *  * *** *  *  ** ****  **    * *    *   **  * * (i=0; i<=strlen(string1)-1;i++)
 **   * **    **     * * **  ****  *** * *******    *** 
*   *****    *** ***  * ***** *  * ** ** * *** **  *         ***   * *  ** *     **  *  * (string2[i]==string1[i])
** ** *  * **   * *  * * *  ** *** ** *** * **      *** *** *    ** *  *  * * *  * 
  **** *        * *** *** **** **         ** * *** * ****  *   * *   *** **  *      ** * ** *  *  *  * **  * ***  ****
     **** * * *     ****   ***  ***  *****  * ***      **      ** *  * ** ** *
****    *  ** *   ***  **** *    * *  **    *    
 ********    * **  **     *   ****  * *** ****   * * 
      * *  *       ***  **      *   * *   *  *   * * *******   *
* *** ***    *        * ** *   * * ** *  *   ** ***   **  *  *****     *   * * **    ***  is a prefix of %s", string1, string2);
 ****    ** *** * * *   ***** ****     **** ** **  * ** *
  ***   **  ** ***   ****  *   * ** ** *** * * *  ** *
* ** ******     *  **  *  *** *  **** *   *  *
* *  ***   ** * * *  * *   **** *   ** ***  * *  *    **      * ***** *  * ***    ***  *  *   *    ** * is not a prefix of %s", string1, string2);
**    **  *  *     *   *     * *  **   **   *  *  * ** *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
    *   * ** * * ******       ** * %s", chaine1,chaine2);
* *   *** * ***   **    ***    * ******* *
****       * **  **  ***     ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*****  * * * *  **** *       lenght1,lenght2,c;
**  * **  * **  ***** ** ***** b[100];
* * **  ***** ** *  ****    ****  a[100];
*  ** ***  *   * ** *  * * *   d[100];
  * *   * *  *   **  **  * **** * * **  ** ******  
 *  **  * ** * **** *     * ***         **  * ** 
** ** **  **    * ** *  *** *   *** ****** 
  * *** *    * **     ** *   ***    **** 
*   *     * **   * * * * *  *** **  *     
***** ***   ** *   ** *** 
** * *  *****    ***** **  ***  * ** * ******* * *  *   * * is a prefix of %s",a,b);
** **** * *** ** *   ** ***     * 
  ***    *   ****  *  * ***   *  
  ***  * ***   ** *   ***   * 
 ***     ******** * *    *****  **** **    ** ***  *   ******  **  is not a prefix of %s",a,b);
   * * * **  ** * ***  **
* ** * *      ***** *  ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include       * *   *
#include *  ***   **  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
      * **  * i;
  * *** **   *** *****  ** *****
  {
  *        *** *  ****** **  **  *  ***     A[i]!='\0' && A[i]!=B[i]   )
** * * ** ** **  ** **  *  **    ****  **      * * * *** * *   ***  *  * ** * 0;
  **  ** * **     *    *   *******  ****  *  * **** * * *
 *  ** * * *  *** ***  ** *  ** ** * * **  * *  *  *** * * * * *  
  }
 * *    **  * 1;
}


int main()
{
** ** *  **   *** * ** *** *      a[n],b[n],c[n];
 ** ***  *  **  ** ***** i;
* *    ** * **  *****  *        **** *  ***   * 
*         *******   ** *   * ***** * * **   
*  * * **  ***  * *  ** **   ** (aa(a,b)){
* *   **  * * *****  * * ****  * *   ** ** * * * *****   *  ***  *     **
*** * * ** * * * *****  *  *   * *  **  *    ****  ****  ****** * *** *  ** **   ** **** 
 *  * * * *  * *** * ** ** * * * ** * *****    * ** *** *  **    *    * **  *** * * **  * ***   ** ****   
 * * *** **   * ***** * ** * *  **  * *** ** ***    * ***  **  **   **    *   *

* ****  *  * **  ***  ***  ** *  ** **** **  * **** 
  ** *****  *  ****    * ** *   *    ** ***   ***  **  * *** ***   is a prefix of %s",c,b);
*   *    ***    *     *    
      * *  *   ***  * *  * 
 * ***   **    ******  *     **   ***   * *   ** *    ** **  *  * is not a prefix of %s",a,b);
*  **  * *    *******   *  **     * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *  **   * 
   ***   * ***   *** 
int main (){
char      **  *
char ****** *
 ** ****   ** * string1: ***  *  *
 ***  *  ** **  **** *  * *  * ** 
  * * ***  string2:  *  *   
   ***   *   * ***  *  *****  **
*** ***  ***  *  * **
   *    ** * * ***  **     *  *  ****  **   is     *  **** ** of   *** ******* * * **  **
else
    * * ** **********   ** *  * *  **  is not prefix of ***  *** *** * * ** * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   ****   * * **
#include *    * ***  ***
#include **** ****  *** 
#include * ***  ** *
int prefix(char p[],char s[])
{
**  ****   * *  **  ** ****** * ** ** ******
 * * * * **   *   *   **  *  * 0;
* *    ***  *  ** *  *** if   ** ** *      *
* *  ** *  ***** *  *   ** *  * * 1;
 *   * **** ** ***  **
   *         ** **** *      ** * 0;
}

int main()
{
*  *   * ** *   * *   **   * p[999],s[999];
*   ** ** *****     * ** ** **     ** ** **    **
** *   **  *  *  ***   *  *  ***   *   **

   ** *  * ** * *** *  * *
*** ****  *  *  * *  *   **  ** * * *   *   is a prefix of %s",p,s);
  **** **** *  *   *
 *    * *** * ** *   *  ** **    *    *   is not a prefix of  * *   

 **  * ** **    * *  ** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   ***** * **    ***
int main()
{
** ** * * ***   **      length1,length2,c;
  ****    *** ****    *   a[100];
 * *  * *  *   **      * * b[100];
  ****    * * **  ***   *** d[100];
* ****** * *  * ** *      * **  *  * ** * ** * * 
** **  * * * **  * ***   *    ** * **  **** **
* *** **  *   **** * ***        ***  
**    *  ***** * * *  *  *      *** 
if (strcmp(a,d)==0)
  *** * *  * *   * ***  **
  *    *  **** *   * ***** *  **  * ****** **  * ** ***   is a prefix of %s",a,b);
  ** ** **  *  **  ***** *  
** *   * * *  ** *  ***    *** **
    *  **  **** ** ***  *  *
  ******* *** ******   *** * ***** *      * **     *** * ***    ** is not a prefix of %s",a,b);
*    * *** * *  *** * **** ** 
* ****  *     * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** ** *** 
#include  *****  *         

int prefix (char *    *  str2[])
{
***    **  * ** *** * ** length=0, * ** **
* ***     * *** 
*  *  **  *  *** *    **   ** = * *  **  *** ** 
* * * * *  ** ***      * 
  **    ** *  **   * * **   ****  *  * ** *  **  * 
*  **  *  **    *** *** ***  *  * * * 
** *       *            ****  if * **      *   
***  *  **     **   **       *  *    * ** ** **  **   *  *  
 * ** * *    ***  *   **     ****    }
* ** *           ***  * ***** **
*  *** *  *   ******  (count == length)
**   *           ****  *  * ***   **  *   * 1;
 ** * *   **   *   **    * ***  else  *  ** **  0;  **** *  * ** * 
  *    ****     ** * **  ***    
}
int main(void)
{
*****      *   *     *  *  ***    *  **  * * 
*   *       * ******** **  ** * 
   *  *  * * *   * *     * **  * *    * **   *    * str1, str2);

**  * *    **  *  ** * ** * * *  ** * *
*******  ***    * {
 *    *       ***   *****  ***     **   **  * * *  * ***** *   * *  * ** * is a prefix of **   **    str1, str2);
  **   ** **     **  **  ** 
   ***     * *****  *  * * **  * 
  **   **** ** *     * * * *  *  *   ** *  * *** * *   *   **   **  is not a prefix of **  *   str1, str2);

* *** * ** *  **  ***** ** ** * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   ***** *  
#include * * *    *     * 
#include *  *   *** *** 

int main()
{
   *   ***  * * **  * * * ****  prefix[100];
**    *  **  ** **   *  * * word[100];
  *** *        *   * * *** *  ***  ** %s", prefix, word);
 *  *   **  *** **    * * *  i;
   ***       ***** *  *  ***  = 0; i< strlen(prefix); ++i)
* ***  *   *  *   ****  *  *
 * *  ** *****      *  ***  * * *  **  *   ** * *  * **** * ** * *  *    ** *
 * *** * *   **   ***     * *  *   **  *   * ** *  * * *
** * * *  ** **  ** ***  *        * ***    ** *   * *  *****  *  *** ** *  *    **** *     is not a prefix of %s", prefix, word);
* **  **  *  **** **   ** *** ** *** * **** * *** **   ****    ***  ****  0;
  **   * * **  **** ** * * * * * ** ** ** * *** *  *** ** ****
*    *  ****   ******* ** 
  **  *  ** ***   * **    *     * ***** is a prefix of %s", prefix, word);
*      *  *  **  * *       * *** *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * * *   ***  
#include * * * **** ***
#include  *  * ***  *  *

int main()
{
*** * * *  ** * **   * *     prefix[100];
*   *     *      * **     *  * word[100];
     * ****** *** * * * * *  *  ** *   * %s", prefix, word);
*    * ** *  ** *   *  **** ** i;
   ** *  **   * **  ***  ** ** * *  = 0; i< strlen(prefix); ++i)
* * *  **  ****    *** *     **
 * **** *    * ***     ** ***   * *   *****   *  ***   *  * *** ****     **   * 
        **  * * *  *  * * * *   **** ****       * *   *
  *    ******* *  *    *   ***    ** *  * **    ***** **** ***  **  * *  * ** * ***   ** *    *  *  is not a prefix of %s", prefix, word);
*   ***** * ** **** *  ** ***   * *   *** ** * * *  * * *  ***  ** *   *** * * *** ***   0;
  *** *  ****  ** **  **     ***  ******** ******    
* * *****  ** * *   * *  *
**    *  *  *** * **  **  ** ** *   is a prefix of %s", prefix, word);
*   ** * * * ***********  *****    0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * *    ** ** ***  *
** **    **  ****   *   ** *
 * * *  *****  * *  ***

int main()
{
*  **** ***  **  * * char * **** 
* *  ***    * * * char *     
*  *  *    *  * **  * ** * ****  *   *  *    * word);
 **   ****  int i;
*  ** **   * * for(i = 0; *    *  *  ** ++i)
*** *   *    * {
*  **     *  *   * *      * *** **    
* ** *    ****   ** *  ** * *  {
 *** **  ***   *  *** **    **   **   ** * *   * * **  *** is not a    * of *    *   * *  word);
*  ***   *  * ****   * ****   ****** *   **  *  * ****  ** * 0;
*** * **    *  *   * *    ***** }
  *   *  *   ** }
*   ** ***** * * * * *** is a prefix of **   ** **  *  * word);
   **    * * *    ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.125
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 12.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 11.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users