1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*   *     ** ********  * ***  * 
* ***  ***  *    * *  * ****** **  *****   *** * *
    {
   * *****     **  *** ** ***   **  * * *  * **  *  (i=0; i<=strlen(string2)-1;i++)
**** * ** **    ****      * ** ** *** *****   * * **  *  *
 *     *   *  *  ** * ** ****  * ** *   ****    * * ** ** *** * *     *  * ** * *    (string2[i]==string1[i])
*** *      ** ***  ***  ***         * ** * ****** * *   **  **  * *** 
** * **  * *   * * * *   *** * *    * **       **** *  ***  *  **** *  ****  *  * *        ** * * * * *  * ** *   
  * * *  * *** * ** ** *****    *   *      * * *** * * *** ** *  * **   
*  **** **   **  *     *****      **    * * ** * ******  
*** *  * * *      ***  * *   *    *  ** **  * ** * ** * *   
**   *  * * ** * *******  **   *  * *  * *      ***
    * * ** **  * **    * ***  *  **   *** ****  *  ******   * ** * *   * ***  *  ****  * ****  *    is a prefix of %s", string2, string1);
 *** *   *    *      ** *** ****** **     *   **  *    
*   *     * *   **      *   * ******** *  * * *  ** *  
 *   * ** * *  ***  *  * * **  * * **  *   ** *  ***** ***
*     *** *   ** ** ** * * *** *  *    ** ** *** *  * *  ****  ******* *****     * *  * ****  * ******  is not a prefix of %s", string2, string1);
 **    ****    * ******  *   ***  * ******    *  **   * * 
    }
* *   *****  ** * *  *  * *   *  **** **   *    ** 
    {
  *  * * ** *   ** ** **  **       *  * * ***  * *     (i=0; i<=strlen(string1)-1;i++)
*  **  * **  *****  * **  *      *   *    * ** *  ******  * 
* ** *   * * * *  *  ***   **    **** * *   ****   * *   ********    ** * *  *   * (string2[i]==string1[i])
*   ** ****  *   ***** * *  ***     * * *  **  * * *** ***** *   **   * *   * 
    *****  ***** * * * * * * *   ***  **  * *   * ***  *** ** * * *** *  *   * *  *** **   ****** *  *     
 **    *** *    **   * ** ***  * ** *   ****  * *****    *     *** *    *      
   * * * ***    *  * * * * * *****  *  *  * * *    * **
*** **    * ** ** *  *     * **  *    * * ** **   * * ** * **
***    *       ** * *   *  *******  **   *  *  *  * *   
*** *  ** *** ***   *  * **** **  ***** *  ** ******   **        *** *   *  **    ****      *** **** * is a prefix of %s", string1, string2);
*  **  **** *  **** * ****  **  *    *  * *     **** 
 ****  * **    *    *** *** * *   *   ****  ** *** *   **** **
 *  **  *  *   * *  * ** * **  *   * ** **  *  ** ** *  
*  *** *** **  * *   *** * **  **   *  * * ** *     ******  *      *** **  *** * * ***** * is not a prefix of %s", string1, string2);
***  *    * **     **  ** ** **** ********** **** ****  * ***
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
    *  * **  **  ****** **   *   * * ** %s", chaine1,chaine2);
 *      **        * *  *      ***  * * 
  ** ***** *  *  * **     * * *  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
     ***  **** ***  ******  **   lenght1,lenght2,c;
 ** **  * * ***  *   * * * *  *  b[100];
  ** *** ** *   **  ***  *  * a[100];
*    ** * * * *   * * *        d[100];
*     **  * *  ** * ******   **** ****      * **
 *  *   *****   * * ** * **     *** **** **     
**   **  ***   *  * *****     ***  * * 
*******           * *******     * ** 
**  *     * **** ** * ***  * *   ******
 ** ****  ** * *  ****** *  
 **  * ** * *  *   ****   * **** **  **** * *    ***** is a prefix of %s",a,b);
**** ** ***     * *  ** **
 *** * *  * ** **  *  *  **** 
   *** * * * * * *   
   *   *  *  ** ***   * *           * * * *** *  * * * ** ** * *      * ** is not a prefix of %s",a,b);
  *  ** **  **  ****    ** 
*** *    *   * **  * ** * *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  *  *  *  * * 
#include   ** * *  * *   *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*    *  ****  * ** i;
 ** *  *** ** *   *  *** ** *
  {
**  *** **  * ** ***  * ** **  * ** *   * *   *   A[i]!='\0' && A[i]!=B[i]   )
 ** * ****  ***  ** **  *  ** ***   * **   * *  **  *  ** * ** *   *  * **  0;
 * *  * **** ** *****  *   ******  * * *   ** * **  * ***   
*    ** * *** *** * ** * * *****  ****** * ** ** * ** ****    ** ***** *** *
  }
 *****   ***** ***    * 1;
}


int main()
{
   **** * **   ** * ***  *  a[n],b[n],c[n];
* *   ** * ** *  * * *  *   **   * i;
* *  *** * **** **  ** *     *** *   ** * *   * * 
***   **  **  *** *  ** **  *  ** ****    *** *  *** *
  * ***  ****  *** **** *  * * (aa(a,b)){
 *  * *     *  ** * ****   *      ***  *   ***  * * * *  * *****  *
*  *** ***  ****  * * ***    * *  ***  **** **** ** * *    * *****  ** *  *     **** * * **  
 * ***     * ******  *  **  *** * * *** * ****** * *** * *** *****  *  *  *******  *   * *   **    ** **  **   *   *  *   *
  **  *****   ****    **       **  **  ** *** * ****** *     ** **  * **  **   *** * 

  *  **** **  **  * ** * ****     ** *** **   ** ***** **  * 
  * * * * ** * *   **         *  ****  *  * *** **  ** * * *   *  is a prefix of %s",c,b);
  *      *  *       *** *     
*  *        * **  * **   *** **
** * * ****  *  *    *   *  * * *   * **** ******  *    ***   *   * is not a prefix of %s",a,b);
**** *  ***  * *******   * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **   ** ****  *
   *** *** *** * *   *
int main (){
char    ** 
char   ***   
** * **** *****  * string1:  * *  * 
* *** ** *   *  **   * **   *****
* **  **  *    string2: ** **  
 *  ** **  *  ** ** *
*** ** *** * * ******
 ** *    * * * **** *    *** *   * ** is  * **  *  *  of ***    **   ***
else
     * *** **  * *** *  *  ** *** * *   *** is not prefix of * * * *    *** ** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  *****  * *
#include **   ** * * 
#include ****** ****   *
#include  * **** *  ** *
int prefix(char p[],char s[])
{
* ******* **** * *  * ***     ***
 *  ** * * * *    ** ** *  * ****** 0;
**** ** *  ***  * *  **   * if **      *  *    *   
* * *     *   ***  * *  * *  * * * * 1;
 **    *****  * *  ***  * 
  * ******  *   ** ***    *  0;
}

int main()
{
 *   * *** * *      **    p[999],s[999];
   **  *   **   ***      * *   *   *  ***  
 *  *  ** **  ***   **  **   ****      *   * 

 ** *  ***    *** ***  * * **
*     ** ***       * *  * *** *    *  * is a prefix of %s",p,s);
****  **   **  ***  *  
 * ** * * ***  * **  *** *** * * *** **** is not a prefix of  ***  **

** * **  * **  *  **      0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include     ***  **** 
int main()
{
  * *    *  * * *     ****       length1,length2,c;
 ****   *****  * **** **   **   a[100];
**** *  ***** *** **      * *  ** b[100];
  *  *  *****   ****  *  * * d[100];
   *** *   *   * *****         *  ***   * **     ***
* **    *  * *   *    ****  **    ***  * ***  
*  *     * *   **  *  ***   ******  ** ***
** *  *  *     *  * * * * **  * * ** 
if (strcmp(a,d)==0)
  *  **** * **      *    
* *  * *     * * ***  ****** * * * **   ** *****  * * **** * is a prefix of %s",a,b);
 *****     ***    * *  **  ** 
***   ** ** *      *** ***
* * *  ** *  *     **  *  ***  
  * *  **   * * * * ** *    *   ***      *****    * * ** * **  ***  *   *  is not a prefix of %s",a,b);
 * ****    * *    *  ******
 * ***   * * *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** **  *** 
#include  ** *   * *   *

int prefix (char   ***** str2[])
{
    *   *  * ******* ** ***  length=0,    * * 
 * * * *  *****  ** *  **
 ***   **** ** * *   *  ***  = *** *   *    *
*     * *     *** ***  * *
* ***    ** **  * ***  **     **  *  *  *  
 ** ** **       **     ** ****     *  * * * ***
* **    * **    *  *** *  * * if *** *    * *
 * **  * * *** ** *  **  *         *  *** ***   **  * * *    
 ***  *** ** ***   ** * ****    }
*  ** *            * ** *   ** * * **
 ** *  **   ** **  * ** (count == length)
  *    * *** *   *   * ** *   ** ***   1;
  ** **** * *    ** ****  else *     **  ** 0;  *****  **   ***  *
***  *  **    * * *  * **  *** * 
}
int main(void)
{
** * *** *** *  **    *  *    * *   * *  
**        *****     *         
  *  * ****   ** * * **** *     *  *     ****** str1, str2);

*  *  ** ** * **** ****   **     *  *** 
*****  *** **   {
  *    **    ** *  ***    **   * **  ** ***           * **     * **  is a prefix of * * *  *  str1, str2);
*  ***   ** ** ** * *
 *  *   ** * *  ****** ** *  *
* *** *  * *   *      ** *  * *** ***    * * * *****  * ***  *    **  is not a prefix of     *** *  str1, str2);

**  **    *   * ** *** ** *  *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***   * ****
#include  *      * *** * 
#include  *   *   **   * *

int main()
{
 **** ** **    * *   * ** *  prefix[100];
** ****    **** * * ** *    **  * * word[100];
 *   **   *          **         *** *** %s", prefix, word);
 * ******* *  ** *     * ** * i;
      ** *   *** **  **** * *  *** = 0; i< strlen(prefix); ++i)
 **    * ** * *   * *     
  ** ** *******  ***    *        *  * * * * *  **    * ** *  *  ******* *   **
*  ** ***     * *** *       * ***** *** * * *  * 
     *    *    * ***      * *  ******** *  ** *     *  *  ******* * ***  ** * ***  * * is not a prefix of %s", prefix, word);
** *  **** **           **   *** ***** * ******  * *   ****** * ** ***  *   * **  * 0;
 *   * ** **     **    ***   ******     * *   *  *
 ****  *     ***** ***  * ***  
   **  * **  *     ** * * ***  *** *  is a prefix of %s", prefix, word);
 ****   *   **  ***** ***  * * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** **      ** ***
#include   *     ***  *  
#include   **  ***  *  *  *

int main()
{
* ****** * * *   ***** *  ** prefix[100];
  ***     * ******  *  * word[100];
*   *  **  ***    ** * **** *    ***   * * * %s", prefix, word);
*    **** ***     *          **  i;
*** * ****    *** * **  * ***   = 0; i< strlen(prefix); ++i)
  * * *  *   **** *  *   
 ***  * *   ** ***    * * *** ** * **    ***** * ** *   ** **   ***  
 * *  **    ******  *    *** * ****** ** **  ** ***
* *   *  ****  * * ****  ****    ** * ***      *    ** * *   *   * * * *  **** *   * * *  ****  is not a prefix of %s", prefix, word);
    * ***  * * * ** *      *   *  *  * *  *****  ***  *** ***********  * * * ***    *  *  0;
 *   ****** *****     *****   **  * ****   **    **  *** **
 * *  *  *  * *    **  **
   * *   ***     ** ** **   * * ****     is a prefix of %s", prefix, word);
   * *   * *   **  ***    ***   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
       * *** **** ** * 
** *** ******** *   * 
*  * ***    ***  * * **  **

int main()
{
*      *   ** char   **   
 *  * * ** *   * * char  ***
     ** *     * *   *       ***  *    ** * word);
  *** ** *  int i;
***   * **  *  * for(i = 0; ******   *      *  ++i)
 * *  *   *  * {
  ** ** **   **    * * ****** * *** **  * *  
  * *     *** ** ** ****    *   {
 ** ***   *** **  *    * *  *   ** *   **      * ***  * ** * is not a  **  of     * * **   word);
** **    *** **   *  **** *  **  *   **  *   *    **** 0;
   ** *  ****** * *   *  *  * * }
* ******  ** *  }
*  ***     **** *     ** ** ** is a prefix of **  *   * * * * * word);
   *   * **  * * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.169
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users