1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
     ** * ***  * **  ** 
 *      * * ******      *** *  *  **  ***   * *  *  * *  ***
    {
** *  **    ** ***  *  * *  * ** ** *  **  **   **    *   (i=0; i<=strlen(string2)-1;i++)
* * * *   * **** *   **    ****    **    * *  *       ** *
  **  * * *  ******  **   ***   * *** ** ** ** **  *  * * *  ***   *      * * (string2[i]==string1[i])
* *   *   * **   * ***   * **    * * **** ******        * *****   ** *      ** *  
    *  *    *   * ** * **  * * ***** **  *     *  ***  *** * ***    *******  **  *       **** ***    
  **  **  * **  *  *  *  ****  **  ****  * *** * **  **    ** * ***  ****  * 
*  *  **       *  ****** ***  *   * **    ** ***      *****
* *    * **  **   *****     ****** *         * *** ***  * ***
 *** ***     ****  ** ****   ***   *** *  *    * * *
* **** * **    * *  *** *** **  *    *  *       ****  **  ***    **  * *  **    ** ** **  **** is a prefix of %s", string2, string1);
  *      **** ***   *** **   **   *     **** *** * * * * * 
** *  *  *  **   * * ***    ** *  * ***   * ****     *    
   *** **   **** ***  *** *    ** ** ** *  *     * ** 
** **** *****  ****    **  * ** * * * ** *  *  **** ***** *  ** * **   * *** *******     * * **    **   is not a prefix of %s", string2, string1);
  * ** **    *  * *   ** *  **  **  *   *  *  ** *   **
    }
******* *** *  *    *   ***** **  * ****  *** **  **   
    {
* * * * **    * ** **  *  *** * ***** ***   ******  ** * (i=0; i<=strlen(string1)-1;i++)
   **** ** *  **  ** *  *** ***         ***** **   ** * 
* ** * * * **  **    *    *  *   * **   ** * * **    * **   ******  ** *  * * * **  (string2[i]==string1[i])
*** *    *  * ****  *   ***     * ****  *** ***  *    *  *  *** *   *  *  *  ** 
   ******* * *  * * **  * * *  *** ** * * *    *   * * *  * * *** * **** *****  ***** * ** ** ** ***  
******   **** ***  ***  *   * ** * *    * *********** ** *   *** * **   **** * 
   * *   **  *** * *  ** **        *** ** **    *   * **  
 **   **  ****** * * *** **** * ****  ***  ** *   *   ****** 
*   * ** * ***   ****  **** **      *  *     * ******  ******  **
** * **   *** **  *  **  ***      *** * * *  **     **  * *   *  **  *  * * *  ** **  is a prefix of %s", string1, string2);
    ***  *  * **       * ** *****  **   *    **** *
 **  ***   * **  ** * ** * *  * * *** **  *  *** *  ******* **
 *  *  * ** ********   **   ****    **** ** ***  ****
* * *              * * ** **** *   *    * *  *   **      *     **   * *******    **  *     is not a prefix of %s", string1, string2);
*** * **  *   *  *  *****  ***  ***    *** **  * *  *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
** *    *** * *** *   * ** * ***  *  * %s", chaine1,chaine2);
 * *       ** *  ** ***  * ***    ***    
*** *  *  * * *****   *    **    0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
***  * * * ***   ******  lenght1,lenght2,c;
 **          * * * ** ****  **  b[100];
*  * *   **    ****  **     *    a[100];
******* *** *   **     ***   d[100];
*  ****** *   ** **  ** * ** **           ***
   ** * * *  ** * * * **   ** ** *** **** *
* ** **  *   * *     ** * *   *  *** *** 
* *** * **** *****  * **     * *   *** 
 *   *******  *  * ****** ** ** *  *   *  
  ****    ***  **   **  *   
 * ** ** * *  * **** *  *  *   *   *  **  **  * *   ** ** * is a prefix of %s",a,b);
            *  *** * * * **  
*    *** *     ** **  ** * *   * 
** *** ** ********      ***   *    *
*   * ****** *  ** *    * ** ****  ** **   **  ***  * **  *   *  *  is not a prefix of %s",a,b);
** *  *      * **     ** **
*   * *** *    *** **    * ****  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  *      * *****
#include  ** *   ** * *  ***
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*  ****    ** i;
  ** *    ** ** ***  *** *  ** 
  {
  ** *  *** ** * *** * *       **    *   A[i]!='\0' && A[i]!=B[i]   )
**   *  *       **  **  * * *  *  *** **  *   * *    * * **  **   * ** 0;
 *  * * *    ***   *  * ** * **** **  ** ** * * ** ***
 * *** *****   * **** *   * *   ** * ** ***    *    * * ****  ***** * 
  }
    *  *  *  * 1;
}


int main()
{
**** **** ** *   * * ** ***** a[n],b[n],c[n];
** ** *** **   ** **  i;
*** *  *         *  *  *** * * *  ** **  ** * 
 * *   *** *      **      * ** ****  * *  *   *
* *  **  * **   ** ******  * (aa(a,b)){
 *     * * * ***  * *    *******  ** **** **  * *  *   *  **    * * * *
*** ** ** ** **** * *** **  * *   *  *  *  ** ** *  **     * **         ****  ***  * *
**     * ***   *  **** * *** *   **   * * * * *** **** * *    * **  * *** **** **** * ***   *** ** *** * **  *** ****  ** 
     * **   *****   * ******* * *  *** *** *** *    **  ***  * **   **   *  *

 * *** * ***** ** ** *** ***   *****   ***    *  *    
****  * *** *  ** **       ** * * ****  *  *  * *   * ***  ***** ** ***  ** is a prefix of %s",c,b);
  *   ****** **  *    ***  **
 *** * *  ***  * ***     * **
 **  *   ** * ** **   *   **  *   * *  *** ** ** * **   *   ** ** is not a prefix of %s",a,b);
  * *  *     ***  **  **** ** **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** **** *** 
  * ** * * ** **  **** *
int main (){
char ***   *  
char * *** * **
 *      *  ** string1:   *** 
***  ** ** * ****    * *  ***  
   ******** **  string2: * **   *
*  ** *** ***  *    ****  *
* ***     ***      * 
    * * *  *    *  * * ****** ***  * * * is   **   *  of  *  ** *   *  *  
else
   *  * *  ****  **** *     ****       **   is not prefix of   ** **  **   * *   

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **  * *   * * * * 
#include   ******  *  *
#include  * **** *** *
#include  * **   **     
int prefix(char p[],char s[])
{
   *   ** * * * **  * *    ***     * ** 
*** **  * * ** *** * *  *** *** 0;
 *  ****** *****   * if     **** *  * * ***
     ** ** *  ** **** *   *   *  1;
** **    ** ***  *     ** 
*  ****   **  ** ***   * **** 0;
}

int main()
{
**  ** * ** *   **      p[999],s[999];
     *  ***** ******* *   *  ** *   *** **
 ****** *  **  *  *******    **  * **  *    **** **

***  *  *  *  **    *** *
  **   ***** *    *    ****** *    *** * is a prefix of %s",p,s);
  ****   **** **  *     
* **  *     * ** * *      **       ** *  *** is not a prefix of **  ***   *

*  *** ** *** * ******* 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include       * ***   ** 
int main()
{
**   *   *  ***  * ** ****      length1,length2,c;
  *  * **** *** *  *  *    ***  a[100];
* ** ***** ***** *   ****** b[100];
  * **     **  ***  *  *      d[100];
 * * *  * **    ****** *   *  ** ******   * *
 ***  * * ****** *** **    ** ** * * * * * **** *
  *  **** **    * * *   **  * **** *** ** * * *
  *  *     * * *   * *    ***  *  ** *** *    * *
if (strcmp(a,d)==0)
**  ***** * * ***  *** * 
* * **     *  ** * *  *** * *    *   *  ** **    *****   ******  * * ** is a prefix of %s",a,b);
  *   * *    ** *  *** **    
 ***   ** * ** *  * *  *    
 **  **   *** * *   * *  ***
  **   *  * **   * *  **     *  * ** * ** ** * *** ******** is not a prefix of %s",a,b);
* *   * *** ******  * *   ****** 
 * * * ****   **  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     ***   *
#include * * ***** *    *

int prefix (char ** ****  str2[])
{
** ***  *** ******* ***  *     length=0, **     
 ** *   ******** ** **
*  ***    *      *  *  = *  * **** * **  
 ***     ***    **  ***   * *
* ***    ********   ***  * * **  *     ** *
*  **    * *  *   *   * **  *** *      *** 
**   *   * ** * *****  *  **  if  * *** *  * *
* *  *   ** ** * ***          *  * * **** * *** *     
       **  *  ****    * **** *    }
** *****            *    ***   ***  **
  *   ** **  *  * *  **   * (count == length)
 ** * *    **   * *  * ** ****** * *** *   *   1;
*** * **      * * *  **  * * * * else    **  * 0; ** ** *****  ** **  * 
       * * * *** **  **  ** 
}
int main(void)
{
 ****   ****  **** *   ***    *  *  ** *** **   
* * *   **  * ***  * **** 
*   **** **** *   **** **  ** *  *  *****  *    **** * str1, str2);

     ****  * * ** * *   *  ** *  *** *** *  *   
  *   *    * *  **  {
  * * ** **  *  * ** *  *  **  **     *     *******  * ***** * *  ******  **  is a prefix of *    ** * str1, str2);
*    ****    ***  ***  ***** * 
*  * ***********    * ** *
    *  **  *** **    *    *  *   *    *  * **  ******  **      * is not a prefix of   ***  *  str1, str2);

  ** ***       * **  *     ***  * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     ***  **
#include   *  ** **  *
#include ******* ***  * 

int main()
{
 **     ***  *** ****  *** ** prefix[100];
* **   * *** * * * *  *    * word[100];
**** * *** ** *   * ***  **  *  * *        %s", prefix, word);
***  **   ******* *        *  i;
*   *   *   *  ***   **  ****  **  = 0; i< strlen(prefix); ++i)
*  * *   *     ** *    ** * *
** *  * *     *   * * ** ****  ** ****   *** * * ** **   **** * ****
* * * ***   ** ****** *   *  **  *****  *      ** ** * *
 *       ** ***** *   *     **  ****   * ** *       ** * * ** ** **      * *  **   * *  *   *  is not a prefix of %s", prefix, word);
**  ** **  *** * *  * *  ** ***  ****  * * ***** ** *** * *  ****  * *****  ** * 0;
 ****  ****  *    *  **  **  ** **    *  *****  ***
 **  *  *        **  *   *
    *  * *  * *        ***  *   ** *** *   is a prefix of %s", prefix, word);
*  ** ** *     * *** ** **        *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * ** *****  
#include  **    ****  * 
#include * *  ** *    *

int main()
{
*     * **** **   *  * **   prefix[100];
 * ***** * *   *     ** **  * word[100];
* *   ***   * *** * *   **** ** *****  %s", prefix, word);
*     *    *   *   *  * *  **  i;
** * ** * ***  **** *******  = 0; i< strlen(prefix); ++i)
 *  * **     * * ** *  *** ***
**  ***   * *  **    *     * * **  *   *******     *  *   *   ** ** * 
 **  *   * ** *   * *   **     ** *  *  *** *   ** **
* * * *   * *  *** ***  ***  *     ***    ** *    *   *   * ** * *** * *   *** * *    **    **   is not a prefix of %s", prefix, word);
   *  ****** **  * **  ** ***       ***  * *** **** ****   ****    ****  **  ** 0;
  **** ***** **  ***  **   * * *   * * ** *** * *  * * 
  * *** ** ** *** *** 
* *    * **    **   *          **  **  * is a prefix of %s", prefix, word);
 *  ***  **** *    *  *** ***  **  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * *  *  ** ****
  *** *   * *    *  *  
*    *  * *     *    ****

int main()
{
 *  * *  ****   char *****     
  ** **  *  **    char      *
  *  * *  **     * * ** * *  *  *****  word);
 *** * *  ** int i;
**   ** *  *        for(i = 0;   * ** * * *** ** ++i)
 * *** *  ** ** {
 * **  ** **      * * ***   * ***  ***   ** 
 * *         *   *** ***  *   {
 ****    ******   **   * **   *   **      ** *   ** *    is not a      of    *      ** * word);
* *** *    ** *   * **   *  **      **   * **  ** 0;
**  ** **  *     **   **  * ** *  }
***  * *   *  *   * }
* *        ***   ****** *  is a prefix of        *   *  word);
   **  **   * * *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.130
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 9.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users