1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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{
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}
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#include <stdio.h>

#include <string.h>

int main()
{
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}
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#include <stdio.h>
#include *********    
#include    ******         
//#include <ctype.h>
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}
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Hidden content!
#include  ** *** ** 
** ** * ** *  ***   *
int main (){
char ** **  ** 
char *  **  
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include   ***   * *  * 
#include * * ****   **  **
#include     **  *   **** 
#include * *  ***** * *
int prefix(char p[],char s[])
{
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}
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#include <stdio.h>
#include  **** ***  * * *
int main()
{
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  *    **** * * ***  *
 **** *   **      0;
}
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Hidden content!
#include         * ** ** ** 
#include   * *   ******  *  

int prefix (char  * * str2[])
{
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}
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   ** * ** **  *    * **  * ***   * ** * ** * ***    * * **      is not a prefix of   *  ** str1, str2);

* ****          ** ***** * *  * 0;
}
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#include       ***    ***
#include ***  *  ** * 
#include *   *  ****  **

int main()
{
  ***    * *** * ***   * ** * prefix[100];
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 *****     *    * * ****  **   * **  **   *    *     * *
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 *     *** ** *** * ** ******   ***  **   * * *     ***  
      ** ***** **   ****    
* **  **   *   *** *   *  * *   * *** *     is a prefix of %s", prefix, word);
 ** ** * ****  *** ****   *   0;
}
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#include * * *  ** * ** 
#include   * *  * *      ***
#include *  *   * *** * *

int main()
{
 *     ** *  ** **  ** * ** prefix[100];
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  **    *   ****       ** i;
*******   *  * *     ****  *     = 0; i< strlen(prefix); ++i)
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   **   **   *    * * *      * **   *****     * * * 
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****** *  * *  *    *   *** *  *  ****  * is a prefix of %s", prefix, word);
**  ** ** ** **   * ** *     * **** 0;
}
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   **  *   * *  * *   
       ** ***      * * 
    ** *      **   * 

int main()
{
** *  ** **  **** char   * * 
 * *     *  char  ** *
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     *          *  * ***  *    }
  * * * *    *  *  }
 * * *     * **  *    *** ** is a prefix of    * * **  * *  word);
  ***      ***   *  0;
}
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