1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* *****       ****  * *     * 
  * *  *** ***** * * *** * *****   *    *  *   **  ***  **
    {
*   ** * *** **      * ***   *  *   * ** ** * ****        (i=0; i<=strlen(string2)-1;i++)
* ** ** ** * *    *  **** *   * * *   ****      * **  *   **
**  *  ** *  * **   ** *  **    * **   *** *  ***     ** *  *   *** **   **   * * * (string2[i]==string1[i])
*** ** **  **  ******  **       * *   **   * ****  *  * * *   ******  * * * 
*     * * ********   ******   *   * *   **********    ** * **  *  ****** * * * * * ** *  ** ****** * *  ** **** * * *** **
***  *  ** ***** * ** ***  *****   **** *** *  *  *     *   * *   * * ***** ****** 
 ******   ******      * *         **  ****   *      * * **
*  **  ** *****  *****  *  ****   * *      **** ** * **** ***
   * ** *  *   **    * ***   *    ** * * *     *    * * 
     ***** *** * * **   * *  * * *  *   * *** *  * * *   * * ****  **  *  ** * ***   ***   **  **  ***** is a prefix of %s", string2, string1);
**** ***  *  *   *     * **     *   ****     *****
     * *** **  * * *    * **  ****  * *** *** *** * *
  *********   * * ****  **    ** ***    *   ***  * 
    * ** *  *  * *** * *  ** ******    * * ***  **** *  * ** **  ******    ****** * *   *  is not a prefix of %s", string2, string1);
* * **  **  *    ****  *  *    * * ***** *    *  ***
    }
  ******** ** *   * **  * *** ** **** **   * *           
    {
  * *  * * * *  ** * * *  * * * ******  ** * **    *  (i=0; i<=strlen(string1)-1;i++)
   ** * ** ** *   *   * * * * **   *   * *******   ** * 
   **   *  * *  *    *  ************    **  *** * ******    *****    *     * *** * *  *  (string2[i]==string1[i])
 ** **  *  **    * * *****  * ***  * * *    **  * *  * * *** ******* * * ***
     *  * * **** *  * *** *   ** * **** * ** * *** **  * * * * *  ******* * * * * *****   *    ** * ******* ***
 * ***** ***     *** **  * *  ** * *  * * ****** ** ***   * **  *  **  *** **
 *  * ** **  * *** **** * * **  *** *  ** *   *** * * 
**     * * ****    *  ** *  * **  **  ** **    *    **   
  * *     *   **** * *    ******      *** **** ** *** *
*** ** ** **  ***  **  *****   * ***  *  * *  *   * ** *  **   *  *****  **  * *** *   *    **  is a prefix of %s", string1, string2);
   *******     ** * * ***    * * * *    *   *   *  *** * ***   
  *  * ** *   * *  **  *********      ****     **     * 
***  *** ** ** *  *  * *  **** ** ** **   * *** * *** * ****
***      * *** * * **   ** **   ***** **  **** *   ****** *    ***** * * *   ** * *  ** *   * *   * is not a prefix of %s", string1, string2);
*  * ***  **  ******  ** **** ** *    **  *     ******
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   *   ** *    * ** * ***    *** %s", chaine1,chaine2);
*   **          ***   ****  **** **** * *  * 
 ** * * *   **  **** **  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   ******* ** **      * ** lenght1,lenght2,c;
**      * * *** * *    **  ** *** * b[100];
 *  ** ** **   **  * **  a[100];
  **** **** ***  * **  ** *  *  d[100];
**   * ***  *     * **  * * *   *  **   *   *** * *
  ** * *   *****  *** * * *  **  *  *  * * **   **
   *   *    *       * *** **   * ***** *****
*   ** *  ***   *** * ****  **    *  
 ** ***  *  **    *  ***   **   * ***      
 *    * *    ** ******  
***** * *  **** **     ***  *     ** * ** * *  ** * *  **  is a prefix of %s",a,b);
* ***** *******      *   * 
 ** *  * *   **    ****       
** * *   * ***       *** **
      *    ****  ****    ****** * * * *  **** * ** ***** *   ***   is not a prefix of %s",a,b);
  ** *  * ** *  *****  ** 
***  * **** * *  *  * **   *     0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *** * *    **
#include  ** * ****  *** **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*** ****    i;
* ****   *  * * *  *  *    
  {
   *   ***     *  **** *   *      ******  A[i]!='\0' && A[i]!=B[i]   )
 * ** ** **   * * * * *   ***   *    *     **********  * * * * **      ********    * 0;
  **** * * *   *  ***     ** ****   ** *   * *      
 * *** * **** * ** **** *  ***  * ***** * **    ** *  * **      ***  ** ***
  }
    **  ****  1;
}


int main()
{
*  * * *  * * *** ****  * a[n],b[n],c[n];
*  *     **** * ** **** *     i;
** **  * * **  ** ***  ****  *  * ****  * ** **** 
 **** ******   *  * ** ***  ***  ****   * **
    **   ****  *     ****** * (aa(a,b)){
  *** **    ** * *    ***  *** * * **  ** * *****  **    * *  *    *  
**  ** *    *  ** *   * *   *  *      **  **  * **   ** * * ** **  *   *     **  * 
** * *  ** ***  * * **** * ***** ******  *  ** *****  **  ** * ****  ***  ******  *     ***  *   * **  * * ***
**     ** * *     **    * * ***      **     *  *** ******* ** * *  *    *   ****  *   * 

*  **   * * * ****   *        * *  **  *** *  ******
 *** * *   ** * * ** *   **** *  ** *  ***  **   *** * *    * *  * **  * ** is a prefix of %s",c,b);
 ***  * ***   *  *  *** ** *   
 *  *****       ** * ** *  *** * **
 ***  ****** * * * ** *  **   **** *    ** ** * * * * * **  *    ** * is not a prefix of %s",a,b);
*  * * *** * * ***  *  * *** ** *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   *  *** ***  
   **  *  *       * ** *
int main (){
char *   * *
char    *  *  * *
* ** ** ***  *  * string1:   * *
 **  *  ** *   *  **  *   *   ***
  ** **  *  * string2: ***   * 
 **** *** *     ***   * * 
* *****    **  **   
 **   *  **    ***** **     *  ******* * **  is  **   * ** of * *  ******  *     ** ** *
else
*****   **  * ******* ***** * * *** *  *  * is not prefix of  ******  ***** ****** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *        *   
#include  **  * **  ** *  
#include  * **   * **   *
#include  *** **  **   
int prefix(char p[],char s[])
{
 ***   * **  * *  *  * *  *    * * ** 
 * * **   ** *  ** * *********  * 0;
**   * *   * ** * *  *    * if   *   ** *********     
 ** *** * *****  *** * ***  *    1;
 **   **  ** * *    *    
 *  ** ****  ***   ***  *** *   ***  0;
}

int main()
{
  *** * *   ***  *  p[999],s[999];
*  *   *** * ** *    **   * ** * *  **  *** 
* * ***** * **** * *   **  *****   *   

  * * ** *** *  *** ** * ***** *  
 *     * ** * *******  *  *    **  * is a prefix of %s",p,s);
  ** *    ** **   **   *
 ***   *****    * * **  **** *  **  *  *    is not a prefix of ****  *   **

 **  **  *   *     **   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * **   *   **   
int main()
{
  ***** *    ** ** *   * *    * length1,length2,c;
  *     **** * **    **  *  *  a[100];
 * *    **** *   *     * **  b[100];
* * *  ****   **  *  * * *  *** ** d[100];
 *** *  * *   * ****  * *      **  *** *  ****  *  **
    *   ***  ***  ** ***  ** ***  * *** *   ** *
* * *  ***     *  ******* *** **  ****
*   *  *  ***** **  * *    ***  **** * *
if (strcmp(a,d)==0)
  ***    ****  *******  * * *
**  *   ****   * ***   ***    *    *   *  ****** *  ** ****** **   **  is a prefix of %s",a,b);
 ** * ****   ** *    * * * *  
* * * ** **   ** *** *** *  
 *** *  *  *  * **** *  *
*   *      ****   * *** *   **  *  ***  *****      *   ***      ******  is not a prefix of %s",a,b);
*******   **         *  *** 
* **** ** *** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    ** * **  *
#include ****   ***  *  **

int prefix (char   * ** * str2[])
{
*  * * ***  **  *  * **   *    * length=0,     **  
 * *  **  ** **  * **  
 ******  *** ** ***    *  **   = *  ** ****** 
* *** ** *   ******    * 
   ****** *** *     * ***  *  **  ***** * ** * *
   *** *   *   *** *  *****   *  ** **  ** 
*  **    ***   * *   *  *   * if * *** *  
*    * *****   *          ***   * ** *       ****  *  *   
 ***  ** *** *   *   *  * * *  *   }
* *****            ** *   * ** ** * ***
******   *    *  *  (count == length)
* ****  *  ****  * ** ** * *  * **      *** 1;
* **   ***  **        **  **  else    * *   ** 0; *** ** * * *    *** * 
*** *  * ***  *     *   * ***** 
}
int main(void)
{
* * **  **  * ** *  *****  *    *  * ** *
 *** *** **   ** *   **  **    *
*  *  * **     **  * ****   * *  *** **    **** str1, str2);

  * *  ***** *   ** * * * * * **   * *   *** 
   ** ****  *** * {
**** ** * ***   * *   * *    **   ***  *     * *    *   *  *    *  *  is a prefix of  *  **       str1, str2);
   *  * ** ****       ** ** ***
  *  * * *   * * *  * *   
*  **  **** ** * **** ** *  *      ***  *** *  *     ***  * is not a prefix of * ****  ** str1, str2);

 *   *  *** ***** **  *  * *  * *** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ******* *   ** 
#include   * *  ***  * 
#include **  *   * ********

int main()
{
   ** *** *   *      * *     *  * prefix[100];
*   * ***   *** * ***  *  **  word[100];
* ***** * **     *     *      **   ***  %s", prefix, word);
 * ***  * **  ****  ** *    *   *** i;
*   ****  **  **  * **  **  *** *  = 0; i< strlen(prefix); ++i)
   **  ** *  **  ** **** *
**    ***  * **  *   *   **  *** ** *   * ** **  **  ** *   * *  
    *  * *   * * **    ***    *    * *   * * **     *
**   **  *** ** *  *  * * *   *   ****** *   *    *  *   ****    * ** *  **    *** *  ** *** is not a prefix of %s", prefix, word);
 *  **  * * * ** ***** *  ****  * ****     * **   ** ** * * * **    ** *  *  *  * *   ** 0;
 ** *    **    **        * * *** *   *  *  *   * ***
  * *** ***  **  *  *  **  
  **  * *  * **  **  *** * * ****** * **   ** is a prefix of %s", prefix, word);
 ** **** * ******   ** **    * ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *******    ** ****
#include        **  *
#include **** ** * **      * 

int main()
{
 * *** *   **  *  *******   ** prefix[100];
   ** * *** *** * ** ***   * ** word[100];
*** * ********    * *  *   * * * *****    %s", prefix, word);
*** *** * ****     *        i;
    *** ***   * ***  ** *  ** = 0; i< strlen(prefix); ++i)
*     ***** *  * *   * * *  *
** **  *  **  *  ***  * ***  *** *    *     **  * *** **     *   **
****     ** ** **     **   *  **  ***       **   ***
 * **   *  *** *  ** * *   **  *  *  **  ***    *  * **  *** * **  ***   *  **** *   ***  is not a prefix of %s", prefix, word);
 **   * *  **  *  ***** * **  *  **** ****   *    **  ****** ** *      ****  0;
  ** *  ** * *  ** **  * **  ***** *   *** *  **   
 * * * * *  *****  *  * *  *
  ***  ****  **  ***   * **  ** ***  ***   * is a prefix of %s", prefix, word);
 * * **    *   ** * **     ****  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * * *  ** *** * * *   *
*  * *    ****  *  * **
** *** *** ***   * *** **  *

int main()
{
* * **  *   *  * char *** ** *
  *  *  *  *****  char  ***** 
**  **    * ***  ***     *    *  *    ** * word);
*   **     **  **  int i;
*    *  **  **  for(i = 0;  *** * *            ++i)
*  **       ** * {
* *** ** *  ** *    ** *   * * ** * * *  ** 
***  * * *   *    ** *      *  *** {
    **    ***  * * ***** ** *  *        *  **   * ******  is not a *** of **       ** ** word);
 ** *** * *     ******** * *  *  *   * *   *   * 0;
* **        * *    *         * }
* *  *      ***  }
  * *        ** *      ****  **  is a prefix of  * * **  ** **** word);
** *         * * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.50
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users