1-11 Exercise 3: Prefix of a string

0 like 0 dislike
4.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
     *  ** *  **   * ***
 **    *** *    * **  *   *  ***    ***** ***  ** 
    {
**  *  ****   * **   * **   *   *** *** * * * * * ** **  (i=0; i<=strlen(string2)-1;i++)
 * *****   ***  **    *  **   **  *   ** *  *  ** **      **
**   ***   ****  *   * *      *    * ***  ***  *  * *** * **  * *  * ** *    *  (string2[i]==string1[i])
 *    * **  ***  ** ****  * *** *   * **  ** * ** *** * ***  ***** * * *    ***  
 ***** ****** *      *   **      *** ** **    ** * * * ***   * ***  * *** ***   **  ** * * * *      * ****  ** 
  **         **   * **  * **  ***  * *   * ***  *     *****     * ******  ***  
***  * ***  **  *   * *   **  * * *  *       **** ** 
 **  * ** *     *  ** *   * *  * * **   **   ***  * ** *  
 ** * *    ***  **    **  *  *   ***** **  * ** ** **  
*  * * *  *  *   ***     ****  *    **    ** **  **  *    **  *  *****   **** * *  **** ** is a prefix of %s", string2, string1);
 ***       * ***** * **     * *  ****** ** **   *** *
   *  * * * *** *** *  * **   *  ** ** ***** * *  ** *   **  * *
  * *    * *     * ****  **  *  * * * **       **** ***
*** ****   ****  ** ** ********* * ** *   *   ****** * *  *  **  *  **** *********** is not a prefix of %s", string2, string1);
**    ***   *  * ****  ** *  * * * **** ** *  ***  * **
    }
*  ** *   ***** * * *    ******* ** * *  *** *  
    {
**   *  *   * * **   ** ** ***  ** ** **  ** *   *    *  * ***    (i=0; i<=strlen(string1)-1;i++)
   ***  * *   ** *  *  **      * * ** ***   * *    
 * **  * *  **   *  ** * ** * ***  **  ***   * *  ***     *   ** *   **********    * **** (string2[i]==string1[i])
*  *  * *     ** *** ** **   ** ***   *  ****  *    ** *** * ***    *  **  ***   * ** 
**  ** *****    * * ***   **  * *  *   ** ** ***** **  *  *   *    ** * ****    *       ******** *** 
 *   **     * * ****   ****  *   *  ** **** *** ****    * ****** *  *   *****   
   * ***      ** ** *** ***  ** ** ***      *         
  ** **  ** **   ** **  **  **** ** *  ***** ****  ***  *  **  **
***   ** * ** *  ***   * ** *         **  * * ** 
 ** ** * *  *  *  *   * **     *  *  ** *  *  *** *** ** ** ***  * *** *   *  *  **  * **   *   is a prefix of %s", string1, string2);
**  ****  * * ******     *  * *   * **** ** *** *    ***
 * ****  *  **  ** * *** ********* * ****       **** *  
**  * *   **    **  *  ** **   * ** * * * * * *  **** ***    **
         **** *** * *****    * * *** * ** * * * * *  *     *  ** * *     * *** ** * * **** *  is not a prefix of %s", string1, string2);
* * * * ***    * *     ***  * **    ******    * **** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
***   ** * *   * *   ******  ** ***  * %s", chaine1,chaine2);
 ****** *  *    **  *** *  **    ***  **
   * * *    *  * ***  *  ***  * * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
    * * ** ** ** *  **    * lenght1,lenght2,c;
** *   *** *   *** *  *  ** b[100];
*  *   ** ***  *  * *    *  ** a[100];
 * *** **     *** ***  * * ** d[100];
*** **    * * *  *   *** * * *** *    * * 
 *   * *  **    ******  *** ***   *     ** *** **   * *
 *  * *  * *     *****  ****** * * *   *   ** 
* *** * *   *  *** *    ** * * *  ***   *** * 
*  ** **  * **   *  *   **  * *    *  
    ****  **** *  *  * * * ***  
 * *  *   * *    *  *****  *      **  *     * ** *   ** is a prefix of %s",a,b);
  ******* *  *  *  *   * **
 ****   * *****  **  * ***** *
****  *** * **   *** * ****  *  *
 **  * ***   * ** * *  ** * ** *  *  ***   ** *    **  *  *  *** is not a prefix of %s",a,b);
*  *  ******   * ***  *     * 
 *   ** ***  *  *   *    ****  * *** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ****       *
#include ** *  * * **** *   
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* ** * *** * * ****  i;
  *  *  ***   * * *  ** *  
  {
*** * ***  * *** ***** * **    *****        ** *   A[i]!='\0' && A[i]!=B[i]   )
*  **  ** * ** * **     ***** *        **  ***    ******* *   **      0;
* ****   ******* *****  *  **        *** *     * 
** * *  **** **   *   **  *    * *   *  **    *  *** *  *  ** * * *  *****
  }
  **   *      * **    1;
}


int main()
{
 *  ** ***  * *  ** *   * *  *  a[n],b[n],c[n];
***      ** *       * * ** ** i;
*  **  ** * * ** * * ***   *  ** * ****** ** * **  
*   **  ****  * ** **    ***    * *** *  *** 
 * *** *** *** * **  *   * ** * (aa(a,b)){
** *  **  ** **    ** ******* ** ***     * * *   *  **   **   *  ** **  
** *     * ***   **   *   ****    ** **  * *   ***** * **  *  *****    ****** * **   ***
   ** ***** ** *   *****   * * * ******  * **    **  **** **  ** * *      * * * ** *  * * *** ***  *
 ** *    ** * ** * **  ****** *** **   **     * **      * ** *  *****  *****   *  *

***  *  ** ** *  **  *   ** *      * *    * *   **** *
 **     * ******  ** **** * *  *  * ****** **  *   *  * * *  * ** is a prefix of %s",c,b);
****  *  * ***  **   *   *** * * 
** **  * *** ** ***    ******
  ** *   ** ****  **  *    *  ***  *    ****** * *** * *    *** *  *   is not a prefix of %s",a,b);
* *******   * * * * ** * * *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  * *** *      
* ** * * * *  **      ***   *
int main (){
char   *****  
char * * ** 
****  **  ** string1:   *   * *
** *** ** **  ******** * **  **  *  
  *  * **      string2:    ** * *
*** * * *       ** ** *
**  *  **  *   ** * ** 
*  *        *** **   ****** *   *  ** is ****    * of   ***  *   * ** *
else
****     *   **  ** *  **  * *    ***  is not prefix of * ******  *** ** *** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *     **  *  
#include * *      ** * * *
#include    **  **   ***
#include ***  *   * ***
int prefix(char p[],char s[])
{
* ** *  * ** *** *    ** ****** ***   
****    * *  ** ** *  ***     *   0;
**   **  ** ** * * if * ***** *  **  *
  **  **  **** **       ***** ** ** 1;
 *    *   *   *  *  * * 
 **  ***   **   ***  * ***** **    0;
}

int main()
{
 *  * ******  ** **    ** * p[999],s[999];
*     * *   * *  ** ** **** * ***  *     **
*  * **    *   *  *     ** ***  *  * *   *

 *** **  * *  *   * ** * *  **
* **** *****  ****  * *** *  * **  ***  is a prefix of %s",p,s);
 *  * *   ***  ***  *   * 
******* * **  ** *     * * *  * *    **** * is not a prefix of *** ***  **   

* ****** *  **   *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ***   ** ***  
int main()
{
*  ** **  ** ** *******  *   * **  *  length1,length2,c;
 *** * *  **  ** *  ****    a[100];
    **  ** ** *  *     * **       b[100];
*   *  ** *****  * *   **  **   d[100];
**      * ** *     *   *  * **  * * * *    *   *
*   *       * **** ***  *  *  **     * * *** *** * *
 ***   *** *  **   *  * *******  * 
 * *  *  ***  **    ***   * *   **  *** * *** ***
if (strcmp(a,d)==0)
 * * **  *  *  *****    **
*****  ***  ** * ***** * **   * * **   *   **** ** ** ** *  **** **** is a prefix of %s",a,b);
* * **   * *   *** *  ***
**** ** **   ** *  ** ** ** * 
**  *   *****  *    *    * * *
 ** * *  ** *   * *  ********  * *  *  *         ** ****       * is not a prefix of %s",a,b);
     *  * * **   ** **  **** 
  *  *  **   *   * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ******* *  
#include *  * * ** **    *

int prefix (char  ***** str2[])
{
 *** *******      ***** *   length=0, *** *  
*   * *    **  * * *
 *  * *  *   **   ***  ** **  *      =    *  ****** *  *
       * **   *** * ***   *
 *  *   *       ***  ***     ***  * * * ** * * * *
*** * *   *****  * *  **  *** ***  * **  
** *****  **  *     *  ** *  *** if   * * * * *
**  ** ****    *   *         * ***** ****         **     
*******  ** * ** *       *** **    }
** ** *            ** *  **    ** 
  **     *** *  ***  ** (count == length)
 *** *   ***  ** ** * *    * *   *****  **   ** 1;
    *  ******** *  * ***  **   else * * **** 0;  *   ** ** **   ** *  
 *     **  ** * * * *** ***     *    
}
int main(void)
{
** * * * *   **  ***  * * **    *  *** ***  **
 **    * *   * ***********
 *   * * *  **  * ** * *  * *** *   ** * *  *   **   *  str1, str2);

* * ****   *** **** * ** * **  *  * * **** *
 **  * * * * * {
  ****** * **  * ***   * ***  ****   *    ***   *  * ****     *  is a prefix of ** **    str1, str2);
  *  * ***  ** *** *** **  ***
****   **  ********   *    ***
  *     ** * * **** *    *   ***    * **   * *****   *  *  * *  * *** is not a prefix of ***  ** str1, str2);

   * * *  * **   * ***** *    0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** ***  *  
#include  * ***** ***   
#include  **  **   * ** *

int main()
{
  *** ** *** *  *  **  * * prefix[100];
    * *** *****     ***** *  *** word[100];
**  * *  * ***** **     ** * ** **** **  %s", prefix, word);
**   * **  * *    **  ***  * i;
 *    *    * * ** ***  **   ** ** = 0; i< strlen(prefix); ++i)
 **  *   *  * * * *  *  ** 
* *  **** ***  ****** * * **** * *  **    *   **** *     ** **  * *   **
** * *  *   **     * ** ****  ***  ** *** ***  * *** ** *    * 
 *   **  * * *  ******* *** * *  * *** ****  ***** * * **  *** *  * **  **  ***  **    *** **  *   ** is not a prefix of %s", prefix, word);
 ** ***   ** **  ****  ***  * **  * *  * ***   ******     **** *   ** *** *  0;
  ****    * *** *  * ** * **   *  * * ** * * **       
 *** ***    ****  * ***
* *  **** *  ** * *  **** ** * ****** * * * is a prefix of %s", prefix, word);
 *    * ** ******   *  *** *  **** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * * ** ** ** 
#include *   * * ** *  * 
#include   ** *   ****** **

int main()
{
 * **** **  **** * * *  *  ******  prefix[100];
 *****  *   *  **   *  ** * * *  word[100];
* * *  *  **** * *    ****** *  ** * *   %s", prefix, word);
*****    * ***    ***  *****   i;
    * **   * * *** * *** *    = 0; i< strlen(prefix); ++i)
*         *  ** *  *** *  * *
 ******          *  *  **   * ** *  **     ** ******  ** * *** * 
 *   ***  **  **  ** * * * ** **     * * * 
  ***   **  *  ********   ** *  **  **** * **** ** *** * *   ** ** *  ***** **    * ** **** is not a prefix of %s", prefix, word);
***    * *   *  *** * ***   **** * **** *** * **      *** *****  *  *   *  ****    0;
 * **   **** ** ***  *   * *      *    *****    ***  *   
 *   ** **  *  **   * **** *   
 *   **     ** **  *  * * ****    is a prefix of %s", prefix, word);
*     **** *  *  * *** * ***   * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*   *  *    * ** * *
** *  *  *  ***  ***
******  * * * *   * * ***   *

int main()
{
** ****  *  * *** char ****  **
*   ** ***  *   char ***  *
  * ** *  * * **  **    * *  *    * **  * * * word);
* * * *  *  int i;
  ** ** * **     for(i = 0;  * *   ** ** ** *** ++i)
** * ***   * *  {
 *   **  ** *    *    **       *   **  * * **
 **  **  ****      * ** * *****   {
  *** **     **** * * **** *  *     ** **   *     ***  * ** **   is not a *  * of     *  ***  *  word);
*  * **  **** *  *** *   ***    *** *    *  * *    0;
  * ****** *  **   *  *   *** *** }
** *     *   *  }
* *****   **  *   **    **   * ** is a prefix of * *  *  * *    *  word);
*     ** ***  **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.133
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 5.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 5.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users