1-11 Exercise 3: Prefix of a string

0 like 0 dislike

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (11.3k points)
Available when: Unlimited - Due to: Unlimited
edited by | 212 views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
   *  * **** * *  * ** **   
   **      * ****** **  **  **  ** * *  *   **** **
    {
* *      ****    *    *    *  * * * *  **  *  *  *    (i=0; i<=strlen(string2)-1;i++)
*    * ** * * ***** * * *  **   **   ****** * **   ***    ** 
 ** **  *******    ***     *  *  **** * *  *** * ***  **  * * **  ** **  ** *   (string2[i]==string1[i])
** *** * * ***  *  ** *  * ** **    * *  ** * ***   *  *  * ****  * ** **   *** * **
** *    *      **   * * ****** * ***  *    ** *   ** * ** **** * ***** * **  * ** *   *  ** *    **  
** * *** * **   * ** **** * *           * *   ** ***     * **  ***   *    *    *  *  
   ***  **  ** *    **     ******    * *   * *** * *   * *
***** **  *  ******* * *****  * * ****   *     *   **** 
***  *   * *        ** **   ****  * ***** ****** *  *
 **     * *  *  **** *    *****  * *      *   *** *  ** ** ***   *  *  ***      *    **** *   is a prefix of %s", string2, string1);
*** *  ****  ** **   **  *   *   ****   ** *    ** * 
  * **      * ** **    ** *  *    * **      ***  * * ***
*  * **  ****     ***  *   ***   ***** * *** *** ** **   *  
   * * * *  **  *** * * **  * ******** * *** ** ** ***    *  * *  *   * *   ***** *  * * ** ** *    is not a prefix of %s", string2, string1);
 ** *       ** ** **  ***    **   ** * *** *** 
    }
 * ** *** *   **  **  ******* * ** * ****** * ******  *  
    {
* * ** ******  *    * *  * *** *****   * ** ***  ** ** ** (i=0; i<=strlen(string1)-1;i++)
  ***   *    * *** ****** *  *     * * ***  **  *
 *  ** **    ****  *  * * * *    *****   *  *** *** *     **  *****        *   *** * ** (string2[i]==string1[i])
 ****  * * *** ** ****    *  ** *  *  ** * *  * *  *   * ** * *  **** **  * 
 *  **   * ** *    *** ***   *  * *  **** * *** * * *  ** *  *** * * *  ***   * ** * * *  ** ****   ** *
  **** **    *  * *** * ** *   ***   ** *** **  * * * *  **   *    *     ***   *
 *   *   * * ***   ****     *  ** *********** *   *   
*****    * **   * *    ** ***   ****    ** *  *  *   * *  * *** ***
*  * *     *  *  *****    ***   * ****    *   *** *  
*   * *** *******   ** *** * **** * ******   *  *** ** *  ***   ****   ***  ** * ** *  **   *  * is a prefix of %s", string1, string2);
* ** ****** * * **      *****    ***   ** **  ** * 
 *  **  *  *****   *    * *    *  *  *    **  ***    * 
** ****** * *    ** **** * * *** **  *    *** ****  ***
 ***  *** * *  **  * ***** * *   *   ** * * ***** * * **    *   *  *  * *    ***** * **  *  is not a prefix of %s", string1, string2);
    *   *  ** *   ***  *** *  ** *  *  * ***** **********  
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
**  **** ** ****    ** *   * *  * ***  *   %s", chaine1,chaine2);
* *** * *** ***  ** ** *  ** *  ***    * *
 *   ** * *  ******** *    **  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (3.8k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*  * ** *   *  ** * ** *   *   * lenght1,lenght2,c;
***   *       **  * ** * **** * b[100];
* *  **** * **** *  * ** **** a[100];
*  ** *   **  **  **    *** d[100];
    *  **  **  ******   * *    ** *  * **  * * 
  **  *  *   *    ** ***  **** **  **   *   **  
****  * * * ** *   **** * * * * * 
*****   **  *  ***  **  *** **** *
* *    *** ******   ** ***  * ***  *   
*     ***   *** **   * *    
 *  *  * **  ***   *  **       ** * * ****** *** **  *   is a prefix of %s",a,b);
 *** ** ** ***  *  ***** *
    * ** *  *** *  ********
**  *   *  ***   ** ** ** * 
**    *** *    * **    ** ** ***  **  **** * **   * **  *** ***   is not a prefix of %s",a,b);
       * ** *   *  * **  **  ** 
*      *** ******  **   * **  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *** * ******
#include   ** **  ** ** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ****  * ***    i;
***     ** *      **   * *  **   *
  {
** *  ****   *   * **   *** * **   ***  *   A[i]!='\0' && A[i]!=B[i]   )
***     * **  *  *    * **** **    ****   * *     ******* ** ** **  ***    *   0;
  ***** ******   *   *******  *   **      * ***  *** *      
  ****  *** *       ***  **       *   * * ***       *      *   * **
  }
** ** * *     1;
}


int main()
{
* * * *  *  *    *  ** *   * * a[n],b[n],c[n];
* * **   ** ** *** **  *** *  i;
  *    ***** * *    ****    * ** *** *** *** **  ****
 * *** *        * * *     * ** *     * 
****  ****   *** *  * **   * (aa(a,b)){
* ****  * * **  ** *** *  ******* ***  *  **  * *** * **  *  **   *** 
*  **** * *  **   * *          * *   ***    **** * * * * **    ***  ** ****    * 
* ** * * * ** *  **     * *  * ******  *  *      ***  *****  **** **   **    **     * **  *   ** *   **** **** **  
  **  *   **  **  * *  *  *    *** ** *   ** *** ******** *  * ***       * **

  **  **  *** *** *** *    ** *** ** * ***** *** *       ***
***  **** ******    ** *  ** * *** **** ** * *  * **    ******* ** is a prefix of %s",c,b);
******  * **    *      *  *  
***    ** *    * * * ** 
**  *  * **  * *** * **   *    *   ***  ** **  *  *  * **   ** * *  *  is not a prefix of %s",a,b);
 **  *** * *** ****     * *  *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include *****   ****  
 *   *      ** *  * * *
int main (){
char ** *  *
char   **** *
***  *** ** **** string1:     * **  
 *** * *** ** *     *  *      
   *  * ** *      string2: ****** 
* ******* ***** **  **   **
 ** *   **   * *   
***  ** *   ** * *** * ** ** ** ** is    ***  *    of   ****  * *     **
else
***   ** *    * **   ***  * **  ** **   *    is not prefix of *  **  *  * **    **

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include   * * *** ** ****
#include  *  **     * *  * 
#include *     *  ***** 
#include ** *   *  *  *  * 
int prefix(char p[],char s[])
{
 **  *  * * ***  * * *    ***** *  *****
 * ******  *  ****  *** ***  **   *** 0;
*    * *     * **  *      if   **** **  **    
**  **  * *   *** **** ***    1;
    *   * *   * *** * * * 
**** **  ****** ** *  ****  * *  0;
}

int main()
{
* *  ***     * *   **  p[999],s[999];
* * ** *  *** * *** *       *  *  *   ** **
***      **  * ****  *****  **** ** 

  *  * * ** * ** **   ** ***** * 
** * *  *  ***  **  **** * *  *** **     * is a prefix of %s",p,s);
* * ** * **   ****** **
   ** **    * * *    *****    *  ** *  is not a prefix of **    ** *    

 *  *  **   * ***  * *** **** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    **  ***** 
int main()
{
*** ** * *   * ***  ****    length1,length2,c;
  **    **  * ** *****   ***   * * a[100];
   **   * *   *  * *   ***  * * * b[100];
*******  *    * ***  ** * *   * d[100];
*  ******** ** **    **  *** **  ***   * *** * 
  *  *  **** * ****  ****  * *  * ** **   
* *** *       ** ** ** ** * ***   
**  ***    * * * *  ** *******  *** * *
if (strcmp(a,d)==0)
*  **** * *   *  **  *    **   * * 
*  **     **** *       * ** ** * ** * **** ** *******   ***   **  is a prefix of %s",a,b);
 * *  * **     * ****       *
**** **** **      **** *******
***   *    * * *****  *  **  
** * **** ***** **  * *   * *  ** *****  * *  *   **         *  **   * is not a prefix of %s",a,b);
*  *  * *** ***  **** **  ** 
****   *  *  **   0;
}
answered by (-191 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include   **** **  * 
#include    ** * ***  * ***

int prefix (char  **   ** str2[])
{
** ** * ** *  ** **** ***  length=0, *  **
*******   ** *   
****  * **   ** *** *      ** = ***   * 
*  ****** *   *  *** *  **  **
* **  ** * *  ****** *** *   **  * ** *  **  *     **
* ***    * *** **   **** **     * *   **    *  
 * * **   ****   ***   ** *** ** if ***   **  *  *
  * *****  *  *  *    **       * * * *   ** * * ** * * *  
 *  ** **  **      ** * *         }
  * * *                    **** *** 
*** ** *** * *    *  *   (count == length)
***  *  * * *  * ** *  **  **  *** ** *  * 1;
*  **        * ********   ** *   else *  *  ** 0; **  * * **     *    ***
*  * ***   *   ***     *   
}
int main(void)
{
  *  *  *      ** ** * * * **  * *     *      
*  ** *  ** ***   **   ***  
* *****   *  * * ***   * * * **    * *   *    *  str1, str2);

* * * ** **     ****  *    *       *** 
 **  * * ***  {
* *     *   ** ** * ***     * *   **   *     *  **    * **   * * *  is a prefix of      *  str1, str2);
 *     *  *** * *  ****
   *  **** **    * **** *  ** * * 
** *** *  * ***  *  * *****   ** ***  * *    ******** * *** ****    * is not a prefix of *** * ** str1, str2);

** **  *  ***    **  ****     ** **   0;
}
answered by (-276 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include   * * ** *  **
#include **   ** * **  * 
#include **  *  ** * * 

int main()
{
** *****   ***    ** *  prefix[100];
  *    ** ****  ** **     *** word[100];
*     * **  *  * **     *** **** * ***    * %s", prefix, word);
*   ** ***   ** *****    *  * i;
*  * * ****** * **   *  *** * = 0; i< strlen(prefix); ++i)
  * *   *       ***   ***  
 * **      ** ***   *   ** *   * * **  ***  *  ****  *      *    *  ****
* *  ***  * * * **  ** ** ***  *** ****  *****  * *   * **
*   ***  **   *    *   *  *  *     *******  *  **** * ** * ***  ****  *    **** *  ** *    *    * is not a prefix of %s", prefix, word);
  *     ** *  **** *     *  *  ** * *  ** * * *   *   ******   *    *   *     **   *  0;
   *  **     *  *  * *   ** *    *  *    **** *   * 
 ****** **** ** **** *  
 *  ** **    ** **  ****** *   ****** is a prefix of %s", prefix, word);
  * **  ******   *** *** *  *** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
#include    *  * **  * * 
#include  * ****** *   *
#include ******  **** * 

int main()
{
*   * *  * ** **** ** prefix[100];
 * ** * ***  * * ******  **    word[100];
  ***      *** ***** * * *     *  * ** %s", prefix, word);
    * *   * ***  *    * * **  **** i;
 **** *   **  *  ****** *** = 0; i< strlen(prefix); ++i)
 *   **     * *  **  *    ** *
   * *  **** * * ** * **  * *    **** *   ****** ***** *     ** * *
   ** * *      *  *   *  ** ****  ** *  *     * ** * * * 
***       *   **** *  *    ****      *     ***   * * ***   ***  *** **  *****  *      ***  is not a prefix of %s", prefix, word);
** * *** * * * *** ***** **    *   * ** *  *** **** *           ***** *    *  *** *  *   **  * 0;
*      *  *** **** ** *   **** ** * * *  **     *** *    * *  
* *      ******* ****  
** *   * *    ** ***  *   *** **  * is a prefix of %s", prefix, word);
       * **** **** * *   **  **  * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 like 0 dislike 
Hidden content!
 * *       *  ** **  **
* *     *  ****  * **  **  
  *   * * *** *  * * 

int main()
{
**  * * * *  *   char **  * ****
** *    *  *** char    *  *
      * ** **   * *** * **  *   *  *     word);
 * ** * ****** int i;
 **   *  *   for(i = 0; **  **    * * *     ++i)
 * ****   * * *   {
**  *     *   *     *  ***  **  ** **  
*  **       **   * **  **  {
 **      * *    * ** **    *    *  * *    * ***    *  *  *  * is not a ***  of ** **   *      * ** word);
**** ** *  * *   *  **  *** *  ** *  ***    ** 0;
   ***** *   *    *      *    * * }
 *** ** **  *  }
   *** * **   **   ** *   **   is a prefix of  *  ** *   * ** word);
****  *  * ****  *  * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
Page:
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.63.43
©2016-2019

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
Available when: Unlimited - Due to: Unlimited | 211 views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (11.3k points)
Available when: Unlimited - Due to: Unlimited | 220 views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
Available when: 2018-01-04 18:00 - Due to: Unlimited | 236 views
8,792 questions
72,281 answers
47,105 comments
2,034 users