1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* **** * *   *** * **** 
**   ******   * * * *** *  *  ** ***** **   *   *   *   **
    {
*   *   * *** * *  *  *   **  * ***     *      ***   *** * ** (i=0; i<=strlen(string2)-1;i++)
* ** **      **   *    *   **   * ***  *  *  **        **
    **      * ** * ***** *  *  *  **    * *  ******   * * ** ****   *  ** ***      (string2[i]==string1[i])
*   ** *  * *  ***  *   *** ******* ** *****    ** * ***    **  **  *** * *
***** ***** ***  * *    **   ********  *  * *   * ******* *    *   * *  **  **   *  *   * *     * ****  *
 ** ** ** * *    *    ***   ** *  * **   ***    *    ** *  ***  * * **  * * ** * * 
  *  * ** *  * ****  * ***   ****    *      * *      **
*   *** *  **  *   **  **  **  * **   *     *** *      **** * * ***
  *   *  **  * *     * * * *** *   *  *  *****  * *** *
** * *   ***     * ** * * *** ***** **   *  *** ***** *   ***  *  * **     * ** *   ** **  ** * is a prefix of %s", string2, string1);
 * **    **  ***** * ****  * * ****   ***    *** ** **
*    ****   ****  ***    ****  **    ******* **  * * ****   
*  *  * *  ** *  **  *****   * * ****** *    ***   * *
 *****    **     *** ** * *  ** * * **  *  * *  **** *   * *   ****    *    ** ***   *  *   is not a prefix of %s", string2, string1);
*** **** ** * *** *  ** *  *  **  ** * **** ***   *  
    }
 ** *  *****  ** **    **     * ****** *** * *   * ** ***  *
    {
  *   * ** *   * * ** ** **    ** ***** **** * **  (i=0; i<=strlen(string1)-1;i++)
***    *   *** *    **** *  ***  *   * **  **** ** **    *   *
 *** * * *         *         **** ** * ** * *****  * **    * **  * *  **  **  ** **  (string2[i]==string1[i])
 * *** *   **  *** **    *** ** **   * *   ** **********   **  ** **  ** *   *   *   **  
  ***** *  * *** ** ****** *   * * ** **    * *     * ***   *     ***  ****   ** * *** * *  ** * ** *   * *   ***
** * * * *   *** *     **   * **     *   *     *  *  ** ** * **  ****      ** *   *** 
  ***     * ** *    *** ***** **    *  **** *    ** ** ** *  
  *      *   *   **** *    **** * *  *      **** * * *  ****  ** 
**  * ***** **** **   ***  *** * * * **   * * ** 
* *  ****  **  ****** ******    ****** * ****    ** **   *  *    **    ***  **   * ** **   ***  is a prefix of %s", string1, string2);
* * **  *     * *    ** * * * ** * * *  * ****   **
 * *    * ** ****** *  *  * ***** * **  **   *** ** 
*    **   ** * * *   *  **   *  ** *    *** **   *   * 
*    * **** ** ** *   *   *** **** ** **   *  **  * *    *  **  **  * **  **** *** ***** *    *  is not a prefix of %s", string1, string2);
*** * ****** ****  *  *    *   *     *       *** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* *** * * *  *   * *  *  * **     * %s", chaine1,chaine2);
 *** *  *     *         * *  **** *  *******
 ***** **  *   *    * *** *** * * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   **  ** **    ***** * * * ** *** lenght1,lenght2,c;
  ** * *** ********  *    ** b[100];
 *****  * ***   * **** *  * **  *    a[100];
****  ***** ** ***   ** * *   d[100];
* **   * ****  ** * *  *    * *** *   **   **  
 *     * * **  *  ** **   *   *** * *  **
**  *****   *  **  *   * *** * *** * *  ****
*  *    *  * **  * * ** * *      **** 
  ****     *  * ** * * ****     ****
   *** *  **  **     *  **  **
* ***   * ** * *****  *  *  *  ***  * * **   **** is a prefix of %s",a,b);
***   **    **  *  ** * *** 
 *  * * *   *   ******      
*  *  *** ****   * *****  *
  **  * **    **  ** * * *** **    *  *** * *** * ** ** *** *  **  ** is not a prefix of %s",a,b);
***   * *** **   * **** *
** ***   *  *  ***     ** * * **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *   *** *  **
#include **  *** ** * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*  *   *         i;
 ** ** ** *******     ** * 
  {
* ** ** ** *   ** * * *  * * * *  **   ***  *  A[i]!='\0' && A[i]!=B[i]   )
    *   *   ***  *    * * * *    *  *   ** *  ***  *   *  * * * * *   0;
 **  **    ***  * **** * * *   *    ****    **   *    
 ** * *  ******* * *   *  *    ** ** * * ** *  * ***    *** **  *   **  *
  }
* ** ****** ***  1;
}


int main()
{
 *       *******  *   *  a[n],b[n],c[n];
   *      *********  *    **   i;
* *   *  *  *  *  ** *  *  *  **    *** **   *****  
* * * ** **  **          **  **** * * ****    ****
        *** * * *  *  *****  (aa(a,b)){
  *  * *  * *   *  *    * *  ***** ** ***    ***   **  *  * ** ***  **** **   
** *  **** **  * *** ** ** *    ** **** **  **  *  *  *  **  *** * *** **  **    * **** *   
********   **    *  *  *      *****   * **  *  * * * *   ***    ***   * ** *  *     *** ***  ** * ****   *****
   *     **  ** *  *  **   *  *   **** *         ** *   ** *  * * *****   *    **  **

****     *** * * *** *** *  *  **** * *   * * * *    ** 
* **** ****  *  **  *  * *  * * * ***  *    *** ***      * * *** is a prefix of %s",c,b);
** **    ***** *  *  ** ** 
*   ***   ***   * **   *  ***     
  *    *  *  ***    * ** **  *   * * * ** *** * ** ** ****   ** * * * is not a prefix of %s",a,b);
   ** ** ** ** *     *     *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *   *  *****
  *   *** * * *  **  **
int main (){
char **  **** 
char   * *  **
 * *   *      string1: ********* 
*   ***  ** **  * * * * ********   
 *  ****  ** ** string2:   ***** 
  * ** ** ***   **** *   
* ** **    * **    **
* *  ***  ** **  *     *   * **  * **** is    ***  **** of    ***      **  ** *
else
 ** *** * *   **  ** ****  *     ** is not prefix of  ******     ******** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **   * ** *    **
#include * *   * *   ***** 
#include     ******  **  
#include **** *    *  
int prefix(char p[],char s[])
{
 *     *   *   ** *  * * *  * ** **  *  
*  *** ** *  **** **  **** * * 0;
   * ***** *** * * *   *  if * * **   * *  
 **  *   *     *   *    *     **   1;
    ** ***** **   ** * *   *
  * * ** *  ** *****    ***  *   * 0;
}

int main()
{
 *** *    ****  * * * p[999],s[999];
**** ** *  *** ***  **** ** *  ** ***   *  * 
 ***   **  *   *** *  *  * **     ** * *   ****

      *** **    **        * * 
*  * ***** *  *  ****  **    *** ***** is a prefix of %s",p,s);
  ******  *** * ****
 *  * **  **** * ** **** **  **     **** is not a prefix of *   ** *  * 

 ****   *  ***** ****   ** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *   * *  * **** 
int main()
{
*  * *    * *   * * * * ** * length1,length2,c;
  ****** ****  * **  ** * *    * a[100];
***** ******* ** * **** ***    * b[100];
   *  *     *******  *  d[100];
 **** *  * ** ***     *   *    **  * * ******
*  ***   *   *   **    *    *** *  * *  
**  ** *     *******  *** *   *** **   *   
*   * *  *** *    *** * * * *  **  **   * **  *
if (strcmp(a,d)==0)
  **** ******  ** *    * ** *   
**** **   **   *   *  * *    * *    *       *    ** *** * ***  **      is a prefix of %s",a,b);
 * *****        ** **    * *
** ****** ** ***     **** **
* **  *** *     ** ***  *** ***
** * *   * ***  ***  *  *    * *  *  ** ** * *     * *    ** *** *** is not a prefix of %s",a,b);
* ** *        * *** *** *  * 
** **  ** ******     0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **  * * **
#include  ** *   *  * *  

int prefix (char ** ** *  str2[])
{
 * **   * *** ***  * *****   * * length=0, ***** ** 
 * **  ** **** * * * ***
** **    *   *  ***  * ** ** ** =   ***   ** *   *
 * ** * ** ***** ***      * 
**   ** *** **  *   *  **  *  * ** **    *   ** ******
    **   **** * *    * *   *** **   *    *** 
**   *** *** *    *  **    *   if   *  *      
    **   *   **     ***          *  **   ** ** ***   *   *  
* *    * *** *** **  *  * ** ** ***    }
  * * *          *** **  * * *** * *
* *  * * ** *  *  ** * (count == length)
 * **   **** ** *** *    *  * * **   ***** 1;
* *  ***    **  ** * *  * else *  * *  **** 0; *     **  **** ****
**   **   * ***    ****** ***  
}
int main(void)
{
**   *** ******  **   * *  *  ** ** ** 
* *** * ** * * ** *  *  * 
***  * *  ** *      *      ** ***   **** * *    **  str1, str2);

    *  * ** * * ***  ***   *  ***  ** **  
    * **   * * *   {
 * **    *      **  *  *   *      * * * ** ** ** * * *  *   ****  is a prefix of **  ** *  str1, str2);
* * **** ** *  **  ***  
 **  *  ** * * ***  * ********  *  
  ** *  * * * **  *           **  *  *  ***** * *  * **** ******** is not a prefix of    **      str1, str2);

   ***** * * **** * * *** ******* 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** * ****  * *  
#include  *     * * *** *
#include * ** ***      ** *

int main()
{
  * * ***   *****     **   *   * prefix[100];
 ** *  ******  ** ****     **** word[100];
  * ***    ***     *  ** **  *    * * **  * %s", prefix, word);
* * ** *** ** * **   ***** i;
** ***    **** ****     **  * * * = 0; i< strlen(prefix); ++i)
**  * * ***  * **** **
* * *  **   * *  * *     * *  * *** ** **     * *** ***   *** *  
    *   **    *     *    *   *     *   * * * ****   *   
  * **  *  *  *    **   *  *    **  * * *   * **  * *   ** *  *  * ****  ** **** *   * ** *  is not a prefix of %s", prefix, word);
 * *   ** ***     ** * * *  *  ** ** ******* ******* * ** *** * *   * *     *   **  0;
 ***  * *** * ***  ****    * ****  ***** **** * **** 
  ***  **  *  **  *  **   * *
 * * * **  *  ** **  *** ** *   *  * is a prefix of %s", prefix, word);
*** ** **** ***      * *   * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    **** ***   
#include   * *** * ** *  *
#include    * ** **  *

int main()
{
      * * **  **  ** **    ***  prefix[100];
*  * **  *** * * * *  *    * *   word[100];
  **  *    *** * * * * *   ***  %s", prefix, word);
****   * *  *  *** *  **** i;
*** *   * *     *   ***  ****   * = 0; i< strlen(prefix); ++i)
**      ****   * *      *  *   
*** *** *   *   *  * * * ** *   * *** *   *   *  ** ****   
  **** **   ****** **** **********        * * ** *   * 
 ********   *  * *  *  ***   **** ** *** ***  * **   **  ** *  ****      *****   *   *****    * * is not a prefix of %s", prefix, word);
  * * ****   *****  ***     *  ** ** * **  **   *   **  **     **    **   * * *    0;
*****  ** * ***** *  *  **  *     *  ******   ** * * ***
 *    **  ****  *  *** *   
* ** ****    * **** *  **   * *** **  *  is a prefix of %s", prefix, word);
   *** * * **  **  **  *** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** * ****   *    * * 
   **     **  *** ***   *
*   * * * **            * *

int main()
{
* *   **  **    char   *  *****
  *       ** *** char  **  *** 
* ***   ** ** *     ** *****    *   * **  word);
 *   ** *     int i;
   * * **    for(i = 0;       * *    ++i)
   * **  * *   {
***  * *    ** * *   *** *** *  * *  ***   
    *****    *        * *     * * {
  ** * *  * *   ** **  ***   * **  ******* ****    **** is not a    * of  **  *     word);
** ****   ***     *  *  *  ****  ******  * * *   ***   0;
* ** * * *** ** *  * *  ** * }
    * *     * *** }
*    **  *  * ** * *** ** * ** *   is a prefix of       *    *  word);
*    *  * *  *      0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.200
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users