1-11 Exercise 3: Prefix of a string

0 like 0 dislike
4.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
   * * *    * ** *****     * *
*** ** ** * ***  * ** * **  * ** ** * ****    *** *   * * 
    {
**   *      * **  *  ** *   **  * ***        *** * **  *   (i=0; i<=strlen(string2)-1;i++)
*** * * ***  **   *   *  *   *  *** ** *  ***  *    *
** *   *     ** ***  ** *** *   * * **  *  *  *   * ******  **** * * ****** * (string2[i]==string1[i])
***       *   *** **** *      * *   **      **  ****** *    ** *  * *   *   *  *** *** 
  ***  *  **   * ******     ** *       *** **  **    **  ***   **   *** *    ** **  ** ****     *** ***   * **   
* *  * *** ****  ***    * ** * * **       *      *  * *   ****  *** ***      * ****** 
*** *** ** ***  *     * *   *****    ** * * *  
*   **** * *     ** ** *** ** *  **   * **    **** ****  * **  *  
       ** *  *  ** ***   *** * *   **    * ** * 
* * *   ** * *  ** ** * **  *     *   **  *****   *   **  *  **  ******  * **     *   ***  is a prefix of %s", string2, string1);
 * * **  ****  *  ** *  *   ** ***** **  *** *  *** ** 
* **  *  * ** **  * * * ** **   *******    * **        **
*   * * **** ***  **** *   *  **    **   ****  
 *         ***  *******      *   * *  ** **   *      *  *** * ** **   ** **** ** *   **     ** is not a prefix of %s", string2, string1);
** * ***   **    * *  **** **  *  *   ***  *** ** ***** * * **
    }
    **  *    **  **********       **  ** * **   * ** * **   
    {
******   *** **** ** * * **    *     *  *    *  ** * *   * ** (i=0; i<=strlen(string1)-1;i++)
****  *    **  * * * * **** ** ** **   ** *   * * ** * *  *** 
  **    *** *  * *  * * * *  *  ***** **   * ****  *** * *   * ** **  ** ****    *  **  (string2[i]==string1[i])
 **    * **     *    * ** *  *** ** **  ** *** **  * ****** * ** ***  *** **   **
  *  ******** ** *** * *  **      **  **   * * *****       *** ******* **  * *** **  **   *   * *     ** * 
  *     * **   ** *  * * *******    *** *  *  *  **  ******* *** **   ***  *
 ** **    ***  *** *******  *  ****   **  *   ** ****** ** 
 ***  ***      *    *  **   ** **  *** ** ***** * **   * * ** *  ***
 * *    * * ****  **  * * ***** *****   **     **  *  
***   *  ***    ** *****   *    ** * **   *** **** *  *** ** * *   * *  **      *********   ***** is a prefix of %s", string1, string2);
** *  * *** **** ** **********     *    *** * * *** **  *** 
* ***  **  **** * *       *** *  *** **** * * * *    * * 
***   ** ** * *   ** * *****  *  * ** ** **  * ** ** *  *
*   ** *  **** **    **  **  *   **           ***  ***** *   **   *     *      *  **  ** *  * is not a prefix of %s", string1, string2);
      ***  **   *    * * *  * ** ** *** ** *  ******
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
**** ***    ***    ***  **       **      *  * %s", chaine1,chaine2);
* *** **  * *   ** *  **** **** ** * **   *
 * * ***  * **     ** *  *  ******  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  **    *  * * ***  ****  *** *   lenght1,lenght2,c;
 *  **  **    * * ***** *  ** ** * * b[100];
   *         * * *    *****  *   a[100];
** * * *** * *     ** *  * d[100];
****   * **   * *** ***    ** **** *  **   * *  ****
   * **  *    **    *     **  ** * **  * *  *  ****
 ***** *****  ***  * *   **   **   ** 
*  **  *   ****** *  ** *  ***** 
*   *   * *     ***  * ** **   *  * *  
* **** **      ** *  * ******* 
* **  * **   * *      * **         *     ***  **  ** *   is a prefix of %s",a,b);
    * *  **   ** *  ***  * *  **
*** *    * *  ** **  ***** * **
  **** *  * *** * *  ****** ** 
 ** ** ** *     **   *** *  * *** * ***  * * *** **  *   **** ***   * is not a prefix of %s",a,b);
 **  **  * ***   **   *  
* *   * * **  * ***  ***** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** **     *  **
#include *** *   ** ***
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ** ** ***   *** i;
****  **      ********  *   
  {
* *** **  * *  **   **     **  *  ****   A[i]!='\0' && A[i]!=B[i]   )
*  **  * *  * *  *    **  ***  **  *** *** * *****  ** *     ** 0;
  *  * *  ***   * *  * ****  *  **** *    * * *  *  **** *
********  **  *       *    *  *    **** **   *  ** * **   * *  *   **
  }
  *  * ** *** 1;
}


int main()
{
  *    ******* **    * *  ****** * a[n],b[n],c[n];
* *  *  *   ** *  ** ** **   *    i;
  *** *   ********* **      * **   *   
*  **  ** * *   * **  *   ** *  *    *   *** *
*******      ** **  **   **      (aa(a,b)){
**   *******   ****** * ********  *   *  * ****   **     *   *   *   
****** * **    *  ******* * *  *             *  ****  ***** *  * *** * ** ***  ****  *** ***
***** **   ***  *  **    **** *   *  ** *    **   *  ** * * * ** **  ***** * ****  *****  *   *     *    ** *  *  *   * *  
** *  **  *** *** *  * **** * * *  *      **   *   ***  ****  *  *  ***     ******  

 **   * ***     ***  *    *** * *   *  **** *  ***  *   * * 
 * * * *  ***  * *  *   ** **** ***   * * * **  **       *  ** * is a prefix of %s",c,b);
******   * *  ********  ***  
 ** * ****  * ** * ****  ****
**   ** *  ***    *   * *    **   **      ****  ***   **    ***  is not a prefix of %s",a,b);
  *** *   *  * ** **** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * **** * ** **  **
* ** ** *** * **  * 
int main (){
char *  * **    
char    *** 
*  *  *** * * * string1:  ******* *
     ** * ****  * * * ** *    
***  **** *     * string2: *   *   *
   * **      ** *  *   *  * 
**** ***    **   * *
******  ** ***     * *** **    *  **    is    **    of *   *      ***  
else
 ***   **  *** ***  * **** *  * **   * *   **  *  is not prefix of *** *** * * **   

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  *  **** **   
#include * * *  *  ***  *
#include * * ******** * *
#include  * *  * **    * ****
int prefix(char p[],char s[])
{
****** **    ***    * **** ** *******   * 
 *   * *   **   **  **   **  * 0;
 * * **    * *   * *    **   if **** * * ** 
 *  *** ***     ** **   * * **    1;
**    * *  ***  * ** * 
   ** **  *  *  ** *  * * *    *  0;
}

int main()
{
  *  **  * **   * *    p[999],s[999];
 * *  ********    *  * * * **  *  *   ** ***
   ** * ** *  *   *   *    **    **** ** *  *  

 *         * *** ****  *** ****
  ** *****   * * **   * ** * * * *  **** is a prefix of %s",p,s);
  **   *** * ****
  ***** * **** * *  * *  *  *     * **   is not a prefix of  ******* * 

* * **** * * ***  ***** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  * *  *   *  * * 
int main()
{
  ** *  ***   *  **** ****  length1,length2,c;
* ** *  *  *    * *   **** *** a[100];
 *  ***  *  **   *  * * ** b[100];
     * * *   * **   * **** *** d[100];
  *    *** * *  * *  ****  *** * *    *   **    *
**  *** * * ** **   *   ***     ***     *
***      ****   *  ** * **    **** *
   *****   ** * ***  * *   ** * ** * *  * *
if (strcmp(a,d)==0)
        *** * *   * *  *** 
    *  ** ****      *********  ***    *  * * *     *  *****  is a prefix of %s",a,b);
   * * **  * * * ***  **** 
 *  ***** *   *  **  * * *     ** 
 * * **  *  ******    ***  *  ****
*** *  ** *** *   ** * *** *  *** *   *  * * ** *   * *  * * *  * is not a prefix of %s",a,b);
   **   ** **     *     *   *
  *** ** **    0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * ** ** * *  
#include ** ***** * * 

int prefix (char   **  str2[])
{
*** ****       *** ***   ** length=0,  **** **
  * **** *     **** *
  *   **  **  ***** ** ***     =  ****  ** *** 
* *  *  *  **  ** * *
*  **** * * *** * * *  ****  ****  * *** * * ** * * **
*** *  ****  *   ***   *  *       *  *  * 
 **** *  *     *  **  *** *   if *  *  * **  * *
 *  *  * *   *****  *              * *   * * * * *****  ****   
***  *     ********   **   * *   *   }
 *   * *          ***    * * **  ** 
 **  ***** ** * * * ** *  (count == length)
 *  * *  *     *     **          *  *      *  1;
       ***** *  ***  * * *   *  * else  ** ** * * 0;    *** **    *    * 
   ***  ** *  ** *   *      * * 
}
int main(void)
{
**  * ** *****   *  *  **    *  ** *  ** *** **
**   *  ** *  *   ****** 
      ** * * *  *** *** ***  ****  ***  * *    * *  * *  str1, str2);

 **  * * * **    ****   * ** **  *    ********** 
  *  *   **** {
  ** * * ** ** ***    * *** * ********  * *  ***** ***  ***** *  * *  *  is a prefix of **      str1, str2);
 * *  *      ***   * *    *  **  
**  * * **     * *  **** ****  
 * ****   **  *** **  *** *    * ** *  * *** *  * *    ** * ** *  * is not a prefix of  *   **  str1, str2);

* **  ** * * * * * * * *  * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    * * *    ** *
#include  **    **  * *   *
#include * *      *  * *

int main()
{
** * *  *  **   *** ***  * *  * prefix[100];
** ** * *        *   *   word[100];
*  * *   ** *  *  *  **  * *   ***  %s", prefix, word);
****  ****   ** *  ** * i;
***  **    ****** * * ****** = 0; i< strlen(prefix); ++i)
   **      ** *   *    * ***
**  ** ***   *      * * ****   *  *  *** * *** * ***** *** *        ******
***  *              *     * * *   * *** * *  *****
** *  * **** * ******  *   ***  *   ** **  * ***  ** *      * * **    *   *** * * **  is not a prefix of %s", prefix, word);
 * ** **  **   *    ** ** ***  *  *  *      * **     **    **  **     * * * * *   0;
  **   *   * *** **  ** *****  ** ***  ** *   ** **   
 *  *    *  ***** *     * *  
        ****  ***    *****  * **  *  * is a prefix of %s", prefix, word);
*   **  ******  *  *  **** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***   ***  ** * 
#include * **   *  ***** 
#include *     ** ** ***

int main()
{
 **  *** * *  * **  *  * * **** prefix[100];
*   *** ***  ** *    * * ** * ** word[100];
 ** ***  *    *****    *   * ** ** ***** %s", prefix, word);
   * **     * ***  *   **   *   i;
* *  * *   **   * * * ***  ** *** = 0; i< strlen(prefix); ++i)
  *** *** ***  *  ***** 
  * ***** *    ******     *  *   ***  *  *  ****   **  * *** 
   * **  *** *  *  ****  *    **   * ***   * *   
*   *  * ******  * **  ******   ** **   * *** ****  * **** **       * *  **  ** ***** * *  * *  ** is not a prefix of %s", prefix, word);
*  *   ****   **  * * *   * * * ***   * *** * * *    **  * **  ***  **  * * *     ** 0;
****    * **   * ** **  *  **********  *      *    *** *    
** *** *  * *   *   ***  *  *  * 
  *** **   **  **   * ** * * *  * is a prefix of %s", prefix, word);
* **    *  *  **** ***   * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *     * * * *   
 ** * * * * *   ** **
**  * * * *  * ** **

int main()
{
***  *   **** ** char   **
    * *  **  * char  ****  *  
*  * **  ***  ****     * *   *   * ****   *   **   word);
  *** ***  *  ** int i;
 ** *  ****   for(i = 0;  *       * **  ++i)
**   *   *  * **** {
 **   *  * ***     * *    *    *  **   ** **
  *    * *  *   ** **     *****   {
*  *  * *****  * ** *  * * * *   *     ***    *** *  **      is not a *  of *         ** word);
   *  ** *  ** **   *  *   *   * * * * * *******  **  0;
  **  **    **    *  *  *  *****   }
   ** ** *  * ** }
 ** * * ***** *  * *  * *  is a prefix of * **  * * word);
***    * *  *   *   0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.50
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 5.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 5.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users