1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include    * **** *   * 
#include ** **  * **    **
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#define n 100
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}
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Hidden content!
#include ** ******* *   **
* **     ** **  ***  
int main (){
char *  * **  
char     **  
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include   *******       **
#include *** * ****  *    *
#include  *   * * * **  * ** 
#include ***   *    *
int prefix(char p[],char s[])
{
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* *  *   * ****  ** ***  0;
}
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Hidden content!
#include <stdio.h>
#include         * *   
int main()
{
 ****   *** ****   ** *    length1,length2,c;
  **         * *******   * *  * * a[100];
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}
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Hidden content!
#include *** * *  *
#include **         ******   

int prefix (char      ** str2[])
{
  ** **   * ***    *** **   length=0,   ***   
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  **     **    * *       * ** * *  * 0;
}
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#include * *  *    ****
#include *****  * *    
#include **** * * ** ** * *

int main()
{
   *  *   ****  ** **  **   * prefix[100];
*  * * *  ** *     *    *   * * *   word[100];
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 * * *    ** **  ***    ** *  *   * **   is a prefix of %s", prefix, word);
     * *** ** ** * ****   ***    0;
}
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Hidden content!
#include *  *** **** *** *****
#include   * ** ** **** *  
#include  ***   *  ***  

int main()
{
 *  * **** *    **   *    *       prefix[100];
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  *  ***** **** * **  *  **    i;
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   * ** ** * ** ** * * * * ***  *
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 **  * * *  ******* ***  * **** *  * *    *    *  ***  *
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 * *   ** **    *** *** **
  * **** ** **** *** *  ******  ** is a prefix of %s", prefix, word);
  * ****  * *     * *        * 0;
}
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** *  * ** **  ** *
 ****  *   *   *   *** *  * 
***  ** ** ***   ***  ***

int main()
{
     *  *     **  char * ****
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    * **     ** *  }
  *   *** **   * *   **** is a prefix of     **** * * ** * word);
  **  **    *****       0;
}
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