1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* ***   * **   * * *  * ** * 
* *** *  *** ***** * * * *  ****  ***  *  * *  *  
    {
   * * ** *** * ** * * *  * * * *  * *   *  ****     ***** * (i=0; i<=strlen(string2)-1;i++)
********  * * **   * * ** * *** * *** *****   *   * ***  
* *  * ** *  **** * *  *    **  **  * ** ** * * * *   **  * *****  **  *   (string2[i]==string1[i])
 *   **    ***       ** **      * **         *   **   *   ** *       * *** *  *  * *    *
  * *****  *  **** * *   *     *** * * * *      *  *  *     *    ****  ** ***  ****  * *  *  ** **** **** **  * *
*  * ** *  *** *** **** * * *****   * *   ***       *  *** **********  *** 
**          ****  * *    ****  ** * ** * *  ***      
*    * *  * * **    * * ****   *   **** *     ** *  * * *  **   **** *
  ****   * * *  *  ** *  ***  * **  *          **  *    * 
 ** * * ** *  **   *   *  *       ******  *  **   * ***  * *** * *   **   **  * ***** *  *  * *   is a prefix of %s", string2, string1);
 * ***  **** ** ** **** * ** * ***** ***   *   ** 
*  ******    * ****  * *** ****        *  *** ***
 ** **      ** *  * ****   ** *** * * **  ** *  ******
 *  **  * * *       *  *  * ***  * ** ** **  * *  **    ***  * * **  *   * ** * * *  *   is not a prefix of %s", string2, string1);
 ** *       ****  * * ** * ** * **** * * **   * **
    }
  *  *** *** *  * *   *  **** **     *  *  ** *  *    * *  ****
    {
  **  *  * *   **** **  *   * ***     ***   *  *    *  (i=0; i<=strlen(string1)-1;i++)
* * **     **    * *  **      **   *  ***  * *   ** **
*    **  * ******  * ** **    **   ***  ** * *  *  *** *  *      *    *       ** *  (string2[i]==string1[i])
 *   * * ******   * * *  ****** **    **  *  *** * **   ***  *** ** * ***** **   *
 *** *  *  *      * * *** *  *** **  ** *****       * * *  **** * ** * ** * * **** *    * **   **** *** * **  * *   
        *  ***  ** * **** ***   *     * *       *   *  ** ** *    *  ** * **    **
** *** * **** **   * *  ************  **  ** * *****  ** *   *
 ** *  **  * ***  **  ****    * **   *****  *   *  * **  * * 
*   *****  *  *  **  *  *     *  *  ** **  * *
* ** *   ***  ***  * **  *  **  * * *****  *    *  * * ***   *     ** * *  *** ** ** ********  is a prefix of %s", string1, string2);
  *   ***    * *  * *  *         * **  * * ** ** * *** *   * 
**  **  *  *  * *** * * *** * **  *****  ** * **  *   *  
* ** ** *      **  ** * *   *   * ** * *       * *******
* * **** *****    *   ** ***   ** **   **    * *    **** **  ** * *** *   **  * ***** is not a prefix of %s", string1, string2);
 * ** *  * * *  **   * *** ** *    *  **  **  **   
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
  *   *** *  ***** **  *****  ** * ***** %s", chaine1,chaine2);
 * * * * **  *  **  * **   **   *  *   
 *****  * * **** *  *  * ** ***  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
** *   *  ** *  ******  * lenght1,lenght2,c;
 * ** ** * **  * *****  b[100];
** *  ******   **** *  ** ****   a[100];
***** **     **  *****  *   *  d[100];
****  **         *** ** *  **  * **** **  * ** ** **
*    ***   *    *** *** * **  *   *  *  ***  ** ** * ***
**     * **   **        *  ** ***  *****  
*  * *  ** ****  *    ***   **   *    *
 * ***   ** **** *   *  * ** ** *  *  ** *
 * **********   * *  *  **  *
*   ** ***** * * *   *  ** * ***  ** * *  *  *  ** * * is a prefix of %s",a,b);
   *     **  * *  *  **  
 * * *  ***    **    ** *
* * *** ***  *  ** * * * * **
* * *  *    **  **  * * ** **   *  *   **   ** ** *  * *  *****  ****  is not a prefix of %s",a,b);
  *  *****  *   **** * * **
**   * ***  * * *** ***  * ** **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  *    ***  **   
#include ** ***   ** ***
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* * *** ** *  * * i;
* *  *  *   **   *  *   *     
  {
**   *** *   ***     **  *   *****  * * *  **  A[i]!='\0' && A[i]!=B[i]   )
 *    ****  *    *  * ***** *  ** **   ****  ** *       *****     0;
 * * *  * ****   *   *  **   ****  *  ****  ******* **
   *  *** **      * *** * *  * * **   *  *   **  **  * ***  * *  * 
  }
*  **** * ** 1;
}


int main()
{
* *   *****  ** **  a[n],b[n],c[n];
** **  * **** * **** i;
***** *   *** **  * ** * *** *  * *  *  ****   **  
     *  **  *  ***  ** *  *****  ** * ** ***** ** 
  ******   * * ** *  * *** * (aa(a,b)){
**    *  ***  * **        ** *  *  * *  ***   ** * ** **  *  *      * * *
*  ***  * **  *** * *   * ** * * * * *  *****   **** * **  *  *  * ** ** *    * **     *   * *
    ** *** *    ***       * * *** ** **      * **** * *       ******    *  ****   * **     *  *   *           * **  
  ***   *  *  * *  ***      *   * *** *** * * *  *** * *** **   *  **  ** * **    

  *    ***    ****  * * ** * **  * * * ** **  *  *    **       *   
   ****  * * ** * ***    * ** * * **  * * * **  *  *** *   *** *  *    *   is a prefix of %s",c,b);
 ****    ** * ***  ** ****  * **
*     * ***   *  ****    
 * * * *   ** *  ****  *****  *** **    ** *** * * **  *   *   **  is not a prefix of %s",a,b);
* * *  ** *** **   ** ****  ***      0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  * **     * *
**   ****   *  * ****
int main (){
char     * ****
char ** ****   *
 * **  *   ***  * string1:   *  ** 
*      * *  * * **** * **    ** * *
 ****     *    *  string2: * *    
********  *    * *  *
*** *     **** ** *** * *
 * * * *  ** ***   **      *** *      is *         ***  of  *    * * * **   *    ** 
else
  * *   ** * **  *    * ***  * ** ** is not prefix of *  * ***   * * * ** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * *  ***** **
#include *   ** *  ** * 
#include    * *    *  * 
#include * *  *   ** *
int prefix(char p[],char s[])
{
 **  **  * ***    ****  * ** ***  ** * **  ****
* ****       *****  * *  * *    0;
 *   *****  *   * *   ** if    ** *  * ** *    
 *  **** *    * *  ****** *** 1;
** ***   *** *  * **** 
   **** ******  *  * *   * **  0;
}

int main()
{
 ****   *   * ** * *  * ***   p[999],s[999];
   * ******  *  *    * ****** *    ***** * ** ****
 ** * ** **  ***  * *    * **   *   *    

   *    **   * *****  ** **  *** **  *
** * ** **  ***     *     *   **  * **  *  is a prefix of %s",p,s);
  * ** **** **     ** 
 *   *** ** ***** * *** * * **  * ** * ** is not a prefix of ****    

******    *    ***   ***  **  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include     ****   *  ***   *
int main()
{
 * * ** ** * ***    *  *  * ** * length1,length2,c;
 *** ** * * * ****  *  **** ** a[100];
**** * *** * * ***    * **    b[100];
**** *** *  ******  * ***** * d[100];
 **** ****** ****  ** * * ** *** * *   *      * 
* ** * **  *   * * **** ** **** ***   * **   ** *  
****     * **** *  **  *** *******   
 **** ** *** *** **     ** ** *    * 
if (strcmp(a,d)==0)
  * ***   ** ***    * * * 
* **  ** * ** ***** ***     **  * *   *  *** ***** *** * *** *     is a prefix of %s",a,b);
************** *      ***  **
 ** * ** ** *   **  * ******
* ** *** ** * ** * *****   *
** * ** *  ***   *****   ** *** *  *     *  *  *   * ***    **   ** *    is not a prefix of %s",a,b);
**** * *** **   ****  *   **
*** *  ******* ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * *        ** **  
#include    ****   ** ***

int prefix (char *  *  *  str2[])
{
  * ** **  ***** *** **   **  *** length=0, ** ***
*** * * *    ** *  
    *****   **  ***   ****  = ***  *    **    *
****         ** *  *  ** 
 **  **  * ** ** **  ** * ** **    *  ** ** *  *
***  *  *    * *   *   *     *   **    
 * ** **** *    **  ***  ****** if    **  *  ** 
* **  ** **   * *  **       ****      *  ** * * * **  
***** **  **  *  ** * ** ** *   *      }
** *           *  * * * *****    *      
  * *   * *   **   * *   ** (count == length)
***  * * * ***  * * *     **     * *** ****** 1;
*      *** ****  **  ** *  else *    * ** 0;   ***   **  ** 
* * *  *      **  ** * **  ** 
}
int main(void)
{
***   ** ***   *    ** *         * * ***  *  ***
*  **** ** * ** ***** * * * * 
 *    ******  **   * *  *  ** ** ***  *  ** * str1, str2);

* **** *** * ***  ** ****  **  * ** **  **
********** * ***   {
*****  *    * *  ** *    * **** * **  *** *  ******  ***** *  * is a prefix of  ** ** * str1, str2);
 *  * *** * ****     *     
***  ** * ***  *** **      
 * *  * * ** * *** *  **** *  ****    * ** *  * * * *  ***    is not a prefix of *** * ***  str1, str2);

   *** * ***  *  *  *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *     * * ** *   
#include  ** ***     *
#include *** **     * * 

int main()
{
* *** *   * *          *** * * * prefix[100];
** *   * **   * * *    * * * * word[100];
  **   **  ** * ** **  * ***   * *** **   %s", prefix, word);
  * ** ** * **** * **** i;
 **    ** *  *   ** ***  *** * = 0; i< strlen(prefix); ++i)
   ** * *   *** ***** *  
 **    **     ** *   ** * *   *  * *** *   * *** ****  **    *  *
*  *****   *   *    * **  **  * *** * *   *  * ** *
 * *  ****  ***  * ***** ** ********* **  **   **  * ** ***  * * * *** ***   *  *****  ** *   is not a prefix of %s", prefix, word);
   **     ***     **  **   ** *   *** ***  *          * **      * * *  * ** ** * * 0;
 * *  ** * *  **      ****    ***  **  * *  *** 
*****   ** *** **    *  *    
 ***  * ***   ** ***    **  * *   ****** is a prefix of %s", prefix, word);
 **** *******   ****   ** *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ** * *  *
#include **     **** * ***  *
#include **     **  **  

int main()
{
*  * ***              **** ** * **  prefix[100];
 *   *** ***   ***  *  ***** ** word[100];
* ****  *    *   * **   *   *** *     %s", prefix, word);
 ** *******  **    ** ** **  i;
* * *   ** *** * * ****** ** = 0; i< strlen(prefix); ++i)
***       ***    * * **
   *  *      * *  *  *    ** *   **** *** ** ****  *    *   ****   * *
*    *** * *    *      ****** ***** *  **   ***  **
   *** *** **   *  * **  **  * *  **   ** ** ** *** *  *** **  * * *   *  ***** ***** **    ** ** is not a prefix of %s", prefix, word);
   *  * ***  **   *     *  * **  ***   *  * *****   ** *  *   *  ***  *  * 0;
* **      ** * **    ***  *  ***     *** *  *   *
 ** *******  ** ** **  ** **
 *  * * *  *   **** ** * **** * ** *****  is a prefix of %s", prefix, word);
******     **    * * * * *  **  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  **   ** *** *  *
* * ***  *     *     
 *    *** * *   

int main()
{
***** * *     * char   *  **
   * * *   * ** char  *  *****
**     *     * * * **  * * *    *  **     word);
**   *   *   **** int i;
   ***     ** **  for(i = 0;   *    *   * *     ** ++i)
  * ** *   **  {
 **  *** *** * ***    *   ** * ** *** ** 
* ***           *** ** * * ** {
   ** *  ***   **   ***  * * *** * *   *          *   ****  is not a *  *  of * *** **  *   word);
    ***  *  ** *    *   **  * **     * * **   * **  * 0;
***  **    *   * * ** * ** **** }
* *          **  }
  ** *    * * **       **** is a prefix of ** * *** *  word);
 * * *****      0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.26
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users