1-11 Exercise 3: Prefix of a string

0 like 0 dislike
1.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 1.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*** ** ***** * ********     
*  ** *    *   * *********  *****  **  *     
    {
  ** **   *    *** **     *** **  *****  *     *  *  * (i=0; i<=strlen(string2)-1;i++)
** * *  * *      *  * * *   * * **  ** ****  * **    
***    **  ** *  *  ** ********   *  * *      **  * *****  *   *  * ** **    ** *  * (string2[i]==string1[i])
******** *   **  *  ** ***    *  **   ****** **** *   ** * *  *         *    *  * **
*  *   **      *** * ** ******  ** ****   *  ** **  * *** **     ***  ** *  *  *  **      **** * *   *****  *   
  * * *** *** *  *  * *    * * * *   *   ** **** ** ** ** ** *     * ** *   *
 ** *  *  ***   **   **  **  **** ** ****  * ** * ** *  **
  *      * *   **** * * **  **  *** ******* **   * * * * **  *  * *
******  *   * ****     **    * ** *  **     *** *  ** *   **
  ** ***  *** *   * * **    * * *     *  *  *    *   *        ***     ****  * ****   * **    * is a prefix of %s", string2, string1);
 * ** **      ** ** **  **  *   * ** ***  *   *    *   * 
**   *   *****    *    * *   * ** ***    *****  ** ***
* *    *  * * * *****  *  *** * *  ** *   *  **   *****  
   ******  **   * *  *   ***** *   **  **** *** *  * *   * *      * ***   ** *       ** *    *   is not a prefix of %s", string2, string1);
**  *** * *  **  ***  * **  * *    *** * **  ** 
    }
***     ** **  * *  * *  ** * *  *** *     *** ** * *
    {
* *****   * * ** ** *  *   *  ****** *     **     *      (i=0; i<=strlen(string1)-1;i++)
 ***   *  * * *  *    ** ** *   **  *** *  *   
 * **** **   ***   ***     ** ***  * *  * *    * *  **       ** *  * ** *  * *    * * (string2[i]==string1[i])
   **** *  *    * *  ** **** ****  * *  *  * ** ** * *  **  **     *****  ** ** *
* * **  * *    ******** *  * *     ** ******   *** * ****  ** ***    **** ****   *   **  *    **  ** *  * ** ** *
   *  *  *  * *   ** ** * **** **  **** **   ** **** **  *   *** ** * ** ***     
**  *      *    **   **     *  *  ** *******   * *    * 
*    *   **    ** *** *  *****  **** * *  *  * *  *   *** *  **
 ***    * * **  *    *  * * **    *****  *   *   *****
**   * ** * *** ** **  ** * **   *  * **  * *** ****** * *  *******  *  **   *** * *** * is a prefix of %s", string1, string2);
* ***  **     * *****  ** ** *** *   *   * * * ***  **   *
 *   ** **  *    *    **** *  *** * ***  * ** * ** ***  *
* * ***  ***  ** ** * **** *   * * **      *****  * 
* ** *  *   *  * ****      **   *  *  * * ** * * **   **  *  ***  * *  *   *** *  * *    * *  is not a prefix of %s", string1, string2);
** ***  **  * *** *  **  *   *  ** **  *** **    **  *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   *** ************* * *     *    *  * ****  %s", chaine1,chaine2);
  *  ** ***  ***   **     * *  *  **** **  **** 
* *  *   *  ***** * *   **    * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 ** **   * * *   *    *   lenght1,lenght2,c;
 *    *  **** *  *  * *   * b[100];
*****   ****** * *   *    * * **  a[100];
** *    **  * * *    **    *  *  d[100];
 * ** ****** * **      * ****  *  * ** *** * ** * * **
*   * *** ***  **  * * *** *  * *   * * *      **
 *      * ***    ** *  *  * * *  *  ** *   *
  *  * *  * ****   **   ****  ** **   * 
     **  * **  *   **    *  **    *    
* ** ***  * *  * *  * *** 
    ******* **** *** *   **  *** ** ** ****   *  *  **  is a prefix of %s",a,b);
 *  **       ** * *  *** ** ***
 * **** *** ** * ****    ***  *
 ****  * *  **  *    * *
 ********  * *** * *   *   ****   *      **  *     ** * * * *   *** * *  is not a prefix of %s",a,b);
***   *    *  **    **  ***
 * *  **********     *  *  *** *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  * *  * *    
#include    * *  * *    *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ** * * ** * i;
   **    ***  *  *  * ** *** 
  {
***** **  **   ** * *   *  ****    * **   *    A[i]!='\0' && A[i]!=B[i]   )
* ****  ** * *  *    **** * *  *** **** * * * *   **   ** *** **** ** 0;
*   *  ** ******   * *   * *  ** ***** *   ****    ****   
* *********    **      **   *  ***   ** *   *******  *** *  *  * ** *
  }
             * *  1;
}


int main()
{
   *  * ** *  *** *    *** a[n],b[n],c[n];
* *   * *****  *  *    i;
**** *  *   *   *  ***  *  **** * **** * * *** **  
*  ** *   * ***** *   *****  *    **     * 
   * **   *  *   *  * *  * ** (aa(a,b)){
* **** ** *        ***     ** **    *** ** *** *  ****    * *     *  * **
 * * *  *** * **** *   ** ** **  *** *    *  ** ******   **  * * *  *  **  * * * 
 * ** *   ** ****** *       *    *  *  *     * *  *   *** ** *** *  * **     ** *      *** * * ** * *  ***** * *********
 **       * ***   ***  ****     ** **    *  ******     ***** **  **  *  * * ** 

*  *     **** ***    * * **** *  * **    ****   **
*     **  * * ** *  ** *   *  **  * * *********  **    ***   * * **  is a prefix of %s",c,b);
* ***  **  *** *** * **** *
  *   *** * **   ** *   ****** 
* *    * *   *  *  **  *** ***  ** *      ** *  * ** * ****** is not a prefix of %s",a,b);
 *    *** *       *  *  **     * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **   *****  * 
 *  *     *****     * *   
int main (){
char   ** * **
char  *   *****
*    * ***** ***** string1: * ******
* ***   **     * * ***   ***
  **  *  * ** *** string2: *******  *
 * *   * *  *   * **   ** * 
*  *   ** * ***
  ** *  ****  *  * *  *  * **** is  **   * of  * *** *  *     * **
else
 * *  ** *  ***   * * ** * **** * is not prefix of ***  ** ** * * *** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***********
#include **  *    *   
#include *  *** *******
#include *  *  ****  
int prefix(char p[],char s[])
{
****   * *   *    *  ***** *          * *
** * *   * ** ****   ** ******   0;
  * ******      ** *  ***  if * ***    ***  *  
* * ** * ** ** ** *****   1;
**  *  * ***  *** * ** ***
**** * *** **  ****   ** *  ** 0;
}

int main()
{
*  ** *****   **        p[999],s[999];
**   * *    ** ** *  ** ** **  ** *   *  * ***
*     *** * ****   ****** *** ** * ***

  *** * *  * ****  *   * *       
  ** * *  * **    *   * **** **  *** ******* is a prefix of %s",p,s);
*    * *   *   *    ** 
   *** * *  **** *  *  * * **  * ****** is not a prefix of *   ** **   

 * * ** **        *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include      *  **  *
int main()
{
    *  *****   * * * * length1,length2,c;
 * ** * **  ** *   *** *  * *****  a[100];
 *** *   ** ***  * * **   *  * b[100];
 **    **  **  *  **     *** d[100];
  ***    *   * ***     ** ** *   * *   * 
 * *   *  * ** ********  **** *   * * * ****  
***  *    *  *  ****    **  * * *  
* *    * *** *   ** * *   *  *** ****  **** 
if (strcmp(a,d)==0)
******  * ****  * *  * * * * 
 *** *  *  * * * ***    * ** * *    **  ** ***  * **    *    **    **** is a prefix of %s",a,b);
***** * *  **   * ** * 
*  ***    ***  **  ******
*    *  * *   *    * * 
***  *  **  ** ***  * * * ** **  ** * **** *   **   * is not a prefix of %s",a,b);
*  * **** *  **** *  **
   ** * *  ***  *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  **  *****  ** 
#include ****   *  ** **

int prefix (char  *  ** * str2[])
{
  ** **  *  *** *   ***** **    length=0, **    
*   * *    *  ** *  
* *  *  * **  **  *** ** *  ****  =   *  *     *   *
    *      **  ***** *     
  **  ** **  ** *  * *   ***   * *   **  ** *  * * 
** *  * *   **             ** * ** *   * *
* **     **  *   ** ** **  * *   if *  *      **
*       *** *  * **        **   * *  ***  **  
* *   ***** *****     **    **   }
 *              *** *  *  *  ** *  
** ** *** * * **  (count == length)
** **       **  ****   *         *** ***** 1;
* ****   *    *    ** ****  else  *       * ** 0;  ******    * * * *  *
*   *         **    *     **   
}
int main(void)
{
 ****     *** ** * ***  * **    ***  **      
*  * ** ***  * *  ******* * 
 * * * **  **  *     * **      ** *** * ***  ***** *  str1, str2);

 **** ***** * **** ** *  ** ***   ***** ***** * 
***   **  * * ** {
       * ***** * ** *  **     * **    **  *  ***  * *    * *** * is a prefix of ******* *    str1, str2);
     *   *****  **  **** * ** 
 **     *  *  *    *     * **** 
 ** * *  ***** * * * *  * **  ** *  *** * *      ***  ***   *  **** ****  is not a prefix of ** *  * str1, str2);

 ** * *   **  * ***** ****  ** *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * ****** * 
#include  **  * *     * * *
#include **    * **   

int main()
{
   ** *   ** * ****  ****    prefix[100];
* *    *  *****       * ****    * word[100];
**    *  *  * * *** ** * ** **** *  ***  %s", prefix, word);
 ** *  **  * * * *  ***  *  * i;
 ** *** * **  *    **  ***  = 0; i< strlen(prefix); ++i)
  ****   * *   ** *  *  *  
 * * **** *** **   * *****   * * ***  *  *  *   **     * *   * ******
**   ***  ***  **** * *** * ***** ****   * * ***   **
    *****   ** * ***  *  ***    ** * **** **   * ** * *   *       **  *     ** ***  **    *** *  ***  ** is not a prefix of %s", prefix, word);
 *** * * **        ****   * ******* ** **** ** *** ***** * ***  ** * * *    ** *    * * * 0;
* * **   *  *     * ******* ********* *    * * ** **  *
  **  * * **    *  ***  **   *
  * *** * * ***  *   * *  ** * ****** ** is a prefix of %s", prefix, word);
 ** ** ** * *****  * * * **     *  * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * * ** * **
#include  **   *  *    *
#include  *  *******  **  *

int main()
{
**   **  *  * **** *  ** ***  prefix[100];
  *  **  *    *   *** ** *    word[100];
**  * ***  * * ** * * *** *  ** * * *   *** %s", prefix, word);
 ********* *** *****   ****    i;
***        * ***     **   ** = 0; i< strlen(prefix); ++i)
 **  * *  **  ***         ** *
       **  *   **    ** * ** ***   ** *   *  ** ** * *** *   ** ***  
  *  * ***  *****     *** ** *    *  ***    * *  *  *
**     ***    ** *  ***   ****    *  *   *  *  * ***  * *********   *  *      ****    *** * *  *    is not a prefix of %s", prefix, word);
**  *      * ***    * * ********* *     * *** *  *  * *** ******** **  * * * 0;
* *  ** * ****** *** *        ** *******  *   * ****** 
* ****   ** *  * **
   *** ** *   ****  **  * *   *     * is a prefix of %s", prefix, word);
 * *   * ****** **  * *   ***  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *** *  * *  ** ** *  **
 **  *  * **  *  * * 
 * **    * * *  *  * ** 

int main()
{
   *   * **  ** char  * ****   *
   **        ** char *** 
  ** *  ** ***   * *  ** **** *** **    word);
 *  *** * ***  int i;
* ***   * *  ***    for(i = 0;    *  * * *    ++i)
 *** *  *  {
**         *    *      * ***    **** *  **  **
* ** **   *    *         ****  * {
 *       ****     * *   *  * *   * *    **   *  ** **   is not a ***  of *       **   * *  word);
** ** ** * ******      **    *   * * *   ** * **  * 0;
  *  * *   * *       **  *  *      }
   ** *       *  }
   **  * ****    ***  *  is a prefix of * * **   *** * word);
   *  **  **  *** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.4
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users