1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
   *****   ** ***  **** *  
***  *  *******  *     **   ** **     *   *   ** ** * **   
    {
**** * ** * ****  * *** ** * *** * ***  *  *   *** (i=0; i<=strlen(string2)-1;i++)
 **** ** ** ***** *  ***  **       * ** *  * *  ****** 
    **  ***  ***   ****   * * *    ** * *  *   *  ** *   * * * *     *   *** * * (string2[i]==string1[i])
**** * ** *** ** *             ****  **  **    ** **  ***** ****** * *  
*** **** * * ******  ****** ** ***       ** *  *  * *** ** **** * *  ** * **  ***  ** *  **  * * * *   ** * * *** *
  *  ** *  *  **   **  * **   *  *** ****  ** * *    * *   *  **    * *     * **  *  *
*   **    *  *** **  *      **** ****  ***  **  **** ***
*****  *** *    ** ** *** * ** **  **   * *     *****    **    
   ***** * *** *  *   * * **  * ***   *   *    *   **** *  * *
***   *  *** * **** * ********** *** *   *    *   * ** ** *****  * * *****   * * * ** * is a prefix of %s", string2, string1);
 ***  **     ***  ** * *  **** ** **    *      **  *  
 * *** * *  *  ***  **  **  * * ** *  **   *  **      *** *
***   ***  *      *            ** ***** 
       * **  * *** * *  **  ** **  *******  *        ***   ** *  * *    * *     **  * *   *  * * is not a prefix of %s", string2, string1);
*********  * *         **  *****     *    *  **  ** * * * * **
    }
**** *   **  **   **  **  * * *  * *****  * * **  *   *  
    {
********  **  ***    ***  * * ** ** *****     ** ** (i=0; i<=strlen(string1)-1;i++)
  *    ****  * * * ******  * ***   *  *** **   *** 
    **  *** **     * *  *  *** * *    *****  *** *** ** ***  * ***   *  * ** *** * * **  *  (string2[i]==string1[i])
 ***  ****   ** ******* ***   ***  *    *  * * **    **** ****  *  *********
*  **   * *   *  ****  *      **    ** *  * * ** *  **      *      *          *  ****  *  *****   *  **     * **  *
*** *    *** *   * ** *   * * ** *     **  **   **** *   * *     * * *  * * ***   *
  * *******    * *      * **  ***  ***    * * *** * **  ***** *   
   *      * ***** * * * *** ** ** *** ** * ***  **
 **  **  *       *******  *   ***** **  *  **  ** 
* * *     * * * * *  *  *     * ** *  **  *****  * **   *  *    * ** **** ***** *  * **   ***  ** is a prefix of %s", string1, string2);
********* **     *   * * ** * * ******* **      *
* * ** *** **** ** **  *** *  *** * *****   *  *  **  
 **  *  ** ***   * *  * ***   **  ****  * ***  * * *** ** 
*      **    **   ** *****   ** * * *** * * * *****  *** ** *    *****   * * ** ***   *      *     is not a prefix of %s", string1, string2);
  *** **    *   *  *  *  ***  *** ** * *    
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
**  ** * ** * *  **** * *  * * *** ***** %s", chaine1,chaine2);
*  **      **  * * **** ** * * **   
   * **   * *   **  ***  *     * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*      *   * **  ***  **  * ** *  ** lenght1,lenght2,c;
** *   **    *  * ** *  ** b[100];
   **** *  **  *** * *** **  a[100];
* ******** *    *  *     * d[100];
 ** * *   **  *   *  **  **   ** *****    ** *  
 *   *  **  ******  * **** ** * **********    *
  *  ***  * *       *  ** *****  *   ***  *  **
* *** **      ***  ***** ** **  ****   **  *
  * *  *******       ** *** ** *  ***      
** *** ***  **   *       ***
 * * *  * ** * **** *****  *  *** *      *   * * is a prefix of %s",a,b);
 **    ***  **     * * * ****
* ***   **    * * * *   * *  
  * ***  * ** * *    
  **     * * * * ** *     ** **      *   **   *   ******  **   **   is not a prefix of %s",a,b);
 * * ** **** ***** ****  ** *
        * * **  *** **  *  ** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    * * 
#include    ** ****** *** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
** ****  **  *** i;
 **   *** ** **    *    
  {
 * * ****    ***    * ****    *  * *  * * *   A[i]!='\0' && A[i]!=B[i]   )
 **  * * *    ** **  *  *****  *    ** ** * * ***    ** **     * ***   0;
** **  *   ** ** * * *  * ***** *          * *** * * ***
**  ** ****   ** * *    **** *** * ***  *   ****  *  * **   ****  * 
  }
**  *  *  **   * **** 1;
}


int main()
{
 ** *  ** ****  **   ** * *      a[n],b[n],c[n];
 ** * *      *    * * *   ** i;
 * * *  *    * ** *  *  **  *** ******  ** *** **
   ***           *** * *  * * *  **    **   *    **   *   
 ***  ****   ********** * (aa(a,b)){
**  * ** **  * * **** * * *      *  * **  *  *** * * ** ** *  *  * **
**  * * ** * * * * **  *  * * **    ** * *     **  * * *  * *   ***** **    * *  *** **** **
     **  ***** ***  *  **  * * **     ***  ** ** *    * ****     **  ***  *  *   * *  ** *****  ****  **  *    ****
  ********** ** * ** * * ** ***** ** ****   * *    *     ** *   *** * *       * *** *  *

 * *   ** *** *** * *  *  * *  ***  * *   * *** *******  
*     *  **  *  **** ****  **  *  *  **   * * *  *   ***   *     *  is a prefix of %s",c,b);
  *   ** *******  ** *  ** *****
*    * ** **  *** * *** * ** * 
*  ***** ** *     * ***  *** * ***    ** **  ***** ** * *  * *** *  is not a prefix of %s",a,b);
 *    ** *** * * * *    *   ** **  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  **       ****
*      ** *  ******  * 
int main (){
char      *   *  
char ***  ***
   *   ** ****   string1: *  * ***
** * ****    * *** ***** *******
**  *   *  *   *  string2:  * ** 
  ***     * ** *** ***    
**    * * * * ** ***
  * * * *    ** * ** *****  *** * *****   is  ***  ****** * of   ******  *  **  **
else
 * *****  ** *  ***  * *****   *   is not prefix of     **  ** **  * ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***   *  *   ** ***
#include * * ****  *  *  *
#include **   * *  *  *
#include **   * **    **
int prefix(char p[],char s[])
{
**  * **** ** * * *  *   *****  *  * **  
 * * * *  ** * **  ** *** ** 0;
 *      * ***    *  *** * if **  * *  *   * ***  **  
**   *  *    * **  *  *** *    *  1;
   *  *  *** ** ***
*  *     ****   *  *  ** ****** 0;
}

int main()
{
 * * *    *    * ** * p[999],s[999];
* ***  * * **   **  *     *** ***** *** * ****
*  * *   *  ** *  ** * *      * **    

    * ** *** * ** * ***  * **    
*   ***      *** **  *   *  **** *   *** is a prefix of %s",p,s);
**  * * * * *** **  * 
   * ** * ** *  **   * ****** * *** *  is not a prefix of ** *  * ****  

*  *****   *  ** *    **** *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *** **   * *
int main()
{
  * *** *  *  ***       *  * length1,length2,c;
 ****    **  ******  **     a[100];
 *****    *****  * *** * ***  ***  b[100];
 * ***    ******   * ** * d[100];
* *   *  *** *****  * ** *** * * *   **    ****    
** ***   * * * * ***  *  ****  **   * *   *  *  * **
**  **** **    *   ** *  ***** **** 
  ****  *      * *   ******** * *******
if (strcmp(a,d)==0)
** *  * *  ** *** ** * * ** ***
  *  **** *  *** **   * **  *     * *****  **     *** ** * **   *  ****  is a prefix of %s",a,b);
*    *    *   ******* *******
* ** ** *  *   ** * *  ** * * 
*   *   * * *  ** * ** *   ***   
** *  ** **** *****  *   *  * *  *   * * ** *    * *       ** * * * is not a prefix of %s",a,b);
* *   *  * ***    * * * * *  *  
**  * *** ***     0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *** ******* 
#include   *  *  *****

int prefix (char *  ** *** str2[])
{
*********    **   ****  * ***  length=0,    *  *
 *** ***     *   *
*** ***  * **  * *   *  **  ** ** = *  *   **** * *  
 ** *     **  * * **  *   
****  *    **  * **   *   *   *****  *  ***     ** 
* **      *     * * *     *    ** *  
       **    *   *    *** ** if   * **  ****
* *     ****      * *           ****    *    * * *****  
*   *  * ** *    **   * ******     }
* ***                  * * ***    * *** 
*   **  **  **    *  * (count == length)
**  * *    **** * ***** * * *** ** *  ** 1;
* *  * ****  *** * ** * else *  *   * * 0; ** *** ***  *  **
* ** * *   *  * * ****** * ***  ** 
}
int main(void)
{
*  * ** ***  ****     *  ***  * * *  ***  *  * 
***  *      * ***     * 
**  *   *     **  *** *******  ** *       ****  str1, str2);

*** * * *    **           *  *** * * * *  
* * * *  *  * * {
  ***** **  * *     **** * ** * ****  **  ** ***** *** **** * *** is a prefix of *   *     str1, str2);
***  * * * **** * * ***  **  
   *  ***     *   ** * *******    *
       ***   * * *     * * * *** ***** *  **   *   **  *  * ****** is not a prefix of *  ** *   str1, str2);

 **  *    **** *   * ***    0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    ** * * * *
#include *    * *  * **
#include **    **  **

int main()
{
  ** *  * * *     ** *   **  prefix[100];
*  *  ** *****  * **  *  word[100];
      **  *  ** *   *** * ** ******  %s", prefix, word);
** ** *    *   *      *** *  * i;
 **  ** *** **  **      ** ******* = 0; i< strlen(prefix); ++i)
*   *****     *      *  *
 *  ** **   * *** * *** ***  ***          ***  ** * *  ***   * *
 ***     *   *      ***  * *** *   *     ** * * * * * *  
 **  ** *  ** ** *  * *  * * * * * **** *  ***** *    ******* *   * ** ***** * * ** *  **** * is not a prefix of %s", prefix, word);
** *   *******  ********    **   *  *** * * ***  *    *** * **    * *** * ****** ** 0;
  **   *** *   * * *  * ***** *   ** *   ** * ***    
 **** *** *   *** ***    **  * 
 * *** * * *  * *    ******  *  * ***  is a prefix of %s", prefix, word);
 * *  * * ** * * * **    **     0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ***       
#include   * * ** **** 
#include ****   ***  ****  *

int main()
{
     ** ******  * *   * ** prefix[100];
      *       **  * * **  *  word[100];
    ****  ******  * **   * ** *   * *  %s", prefix, word);
*****      ****       *  * *  i;
    * *  *  *** * *  *     *   = 0; i< strlen(prefix); ++i)
*** **   ****  *    *
 ***   * * **      * **** **   ***** ** ******   * ** *  *  *** * * *  * **
 * *****   **   **      * ** *     *   *  ** *    ***  **
    * **  **    *  *  *    *  *   * * **     * ***   *** ** ********   ** *** *    ***  **   is not a prefix of %s", prefix, word);
* **** **   ****      *  ***   *    **  **** *  ** ** *  **      * * *     **  *  *   0;
 **   ***  * ***  *   * ***   * ***  *** *******   
* * ***   *       * * * * ** 
 *  *  *** **   *       *   *** ** ** *  * is a prefix of %s", prefix, word);
   *******    * *    ***    ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *   *****   * *  
 * **     *  ** *** * 
  * ***  *   * **   *

int main()
{
  **  **  ****  char * *  * 
* ***** **** char **** 
  * * *  * **  **   **   **   * **  * *    word);
*   * **  ****   * int i;
  *  ***    *   for(i = 0; ****    *    ++i)
**  *   *  *   **  {
** * *     *    ***   *  ** ** * *    ****
 *  ** *      ** ** * ** *** {
 *  **     *  ** **    *   ** ** * ** **    ** *  * **    is not a ** * of ** *   ** ***  word);
**  **  *    *  ** * ** *   *** *       **     *  0;
*  ***   * *   *  *     *  *     }
  **   ** ** }
 ***   * * * **  *  * *  is a prefix of  ** ***   ** **  word);
***  * ** *** ***** **** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 20.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 18.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users