1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 *  *    ** *** *   * *  * 
   *  *  **   *  **  **    *  ** ****     * ****    **
    {
** *   **** * *  * *   * * **** *  * **   ***  * * ** *   (i=0; i<=strlen(string2)-1;i++)
* * **  *  *    **** *  ** ** * ***** *** *   *      **
*  ** ***** * ** * *    ** * *****  **  * *  ****    *   ******  *    ** *    (string2[i]==string1[i])
 ****       *  *  **     * ****  *** *  *   ***   ****** *  ***** * * * ** ** *
*** ** ***    ****  **     *     **   *****      **   *  *  *  *  * ******* * ***   * *** ** * ** ***** ********  
*** *     * *****  *   ** *** **  *  * * *  ****** **    **  *   * ** *** * **** 
 ** ***     * *   ** *   ****     ** * ** ***    ****** ***** 
* ***    *   *    **** * ****  ** *  * ****** * *  *   ***** **   
 **  * **  ***  **  * *  * * ***  *  ** * ** **   *
** * * *  *    ****  *    **    *  **   *    *  **    *  **  ** * * ****     ** *  * *    * *   * *  * * is a prefix of %s", string2, string1);
 **   *   ***   ***  **   * ****  *  **** * ******** *  * *
 *  **   * **      ***   *****           * * **  **   
  ** **   *   ***  *     ***** ** ***  **    ** ** *   
***  * * ****** * * ** *  * * * ****     * *** **  ***      *** * * **  * *** * ** **      **  is not a prefix of %s", string2, string1);
*  *  ** ****       * * *   * *   **   **** *  * *** ****
    }
*   * *  * * **   **   * ** * * *       ** **  *    * * 
    {
 * **   * *   ***  **   *  * **  **     ** * * **  *  ***  (i=0; i<=strlen(string1)-1;i++)
**    * * **    ** **       **  * **   *** *  ***** 
 **** ***   *   *** ***** *** *   * ** * **** *  * * **   *** * *  **  (string2[i]==string1[i])
**  *  * **  **       * *****  *  **  * ***** * *   *   * ******      **  
   ****** *******   **    * * **  ***   * *  ***  **** *   *    **  * * * *  * * *    * * **       * *  
 ** **  ***    ****      ***** **  * **     **  * * ** * **      ***** *  **** *** * 
 *  *    *    *  *   **  *     ** **    *  * **** *     *
* **    *        *  *** * ** **   * ** ***       * *   
****  **   ** **   *****   **     ** * *** * ** *  * **  *  **
 ***   *     **   ***  * * ****** **    *      * *  **** ***   *     * ** **  **   * * * is a prefix of %s", string1, string2);
***   * **** * ***  ***   **  *** ****  * *** *****   * *     
  ***  ** * * **  *  *  *  ***** * ****    **    *
 ***   * ***  ** **  *** * *    **  ***    ***** *     **** *
  * *   **** * ** * *  **  ** ***** ** ***  *   ****        *** *    **  ***** ***   * is not a prefix of %s", string1, string2);
 * * *** **     ** * * * *  *    *  **** ***  ** ** *   * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *  **   * ***    * *    *  * **    *  %s", chaine1,chaine2);
** **  *  * * ** ***** *** ***   * ** *
   * *   *** ***       **    *** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**  *    **** * ** **** *   **  *  lenght1,lenght2,c;
  ***** * *    *  *    * ** *     b[100];
*  *      * **    ****   *  a[100];
** ****  *  **  *** **   ***     d[100];
** * *  *  ** ** **  **** ** *  ** * **** ** *     *
    * **  * * ****   *     ***  * **  *  ** * ** *
 * * *    *     ***  *    *  * ****    *  
         *     * *  * *       ***** * *
*  **  *  * *  *   *** ***        **
*  ****** ***  *     * **  
 * ***  **    **     ** **   *          * * * ** **  is a prefix of %s",a,b);
****  * *   * * **  *  *   
*   **     ** *     * ****** *  **** *
  *   **   *   * *** *     *
 * * ****  *  *  ****** * *  ****  *  ** **  ** *    * *** is not a prefix of %s",a,b);
 ** ***    ****  * *   ***   
  *  *   ******  ** *    ** *    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * ** ** *   ** *
#include   * *** ** *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*  ***** * * **  i;
** *   *******   *   *  ** **
  {
* * ** *** *** ** *   **      ** *    * *    A[i]!='\0' && A[i]!=B[i]   )
  **** *   ***   **** ***** * *     ** *   ***  *      * *    *  * * 0;
 * ** **** * **** **    *** ** *  ** *    *  *** 
**** **   ** * **  **    * ***  *    *  ** * *****  * *     * * * * 
  }
*  * *    * **   1;
}


int main()
{
* * ****** * * **   *** **  **  a[n],b[n],c[n];
 ***  *   **** *** *   **   * i;
*  *  *** *** ********* *** * ** **** ** ****** *  ** 
*  ** *     * **   ** * * **** *     
 * ** * **   * **** * ** * (aa(a,b)){
**  ******   *  ** * *   * *    *   * *  *  ***  *  **      *  **** **    
** ***  *****   * *    *  ** **   **  *  **   ** * *  ***** **  * ***     **  *  ***  *  
 ** *  * **  **  **** * *  *** ***  * *   *  *  **   *    * *** * ****  * *  ***    ****     ******   **    * * *** *  * 
**  * *  *      ***  *   * * **** * ****** * ***    *    * *     * **** *  *  *

*   **  * ** *     ****** *  **  ***  *    *****    *
 *  * * *  * ** *  ** ****   *  *    *   **   ** **   *** * *  *  is a prefix of %s",c,b);
 *  * ******* ***
******      *    *   ***** *
** *  **  * *    *  *  **  ****   * * * * * *** * *    * ** * ***  ** is not a prefix of %s",a,b);
 * ** **   * * * * *   *  *** ** *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** **      *  
**  * *  * ** * *  ** 
int main (){
char    *  ***
char  * *  *
*   ** ****    ** string1: * **
*   ***  * ** *  *       *  **
**   *  ** *  ** string2:    * 
*     * * **      * *  * * *
****  **  ***  **   *  
 *** **  *   * ** ** ****   ** *  *******  ** is * *** **  of ** * **   *  *  ****
else
**  **** **   * * *  ***** * *  *    is not prefix of *   * *   *    * *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **  *** *    *
#include * * *    * ****
#include   *** *  ** *
#include * * **  *
int prefix(char p[],char s[])
{
* * ***** * ****   *** *   * *  * * **  ***  
*  * **    **** **  ** **   *    0;
** *** * * ** ***   *  *** if  * **    ******  **
 ** ***   * * **** ***** **   1;
 *  ** ** **  **** *  * **
**   **  *     *     * * * 0;
}

int main()
{
*   * *       ***   p[999],s[999];
* * * * *     ** ** ***   ***   ** **  **
****  **     ** *   ** ** ***   * **** *** 

   * *   *  *  * **** *** 
 *   * ** ** ** **   *  * ** ** * * * *       is a prefix of %s",p,s);
*   ** **  * * * *  ***  
* ***      *  *  **    ****  * * ** is not a prefix of ****  * ** * 

** **** * **    **     *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** **  *   *** 
int main()
{
 * **  **   *  **    *  *** length1,length2,c;
* ****  **   *  * ***  **** *  a[100];
    *** * *** ** ****  **    b[100];
  ** * * *** * ** **  ****  *  d[100];
* *    * * * *   *** *   *  *  ***      *   * 
*    * ** ** ****** ** *  ** *  **   ** *    *  *
* * *  * **    *   ** *    *   **  
**  * ** ** *  ****  *  ** **** ***   *  * *
if (strcmp(a,d)==0)
 *   **** * * **   **     
* * * **  *** *   *** *  ** ********     * *   **     *       is a prefix of %s",a,b);
   *    *** **     * ** *** 
  *** *  *** ***** *   ****  **
  ******* *****  * *    **** * 
*  ** * ** **  ** **** * * ****  * ***   *  * ** ***     *** * is not a prefix of %s",a,b);
  ** ***  * ** * *   ***     *
  * **** *      0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include          ** * ** *
#include   **  *** * **    

int prefix (char   ** * **  str2[])
{
  ** *  ** *****     *  **      length=0,  ** ***
**   *       * * *    
**** * **  ***  ** *    *  **    =  ***   ** **
* ****  *  ** *   ** **** 
* *  ***     *   *** * **  ***  * *****  ** *  *
*** *  *    *   *  *     *   * *** ****    * * 
  **   *     * ***   **    *  *** * if **  ***    *
    **  *  **   ** * *  ***        ** *  **   * ** **      
*  **** * **    *     *** *       }
*** **          *   *    * *** * 
**** ** * *   ** * ** ***  (count == length)
 *  *  *    *  *    * ** ***   * *    *  1;
****  *** *     *** *  * ****   else   *    ** * 0;   *  * *   * **  
*   **  * *   **     ** * *  *  
}
int main(void)
{
   *       ****  *  *** *****    ** ***  **
** * *  **** **  *  
  * *  *  *  *  * *  * ** ** **   **  **  ** **  str1, str2);

*   ***   *** *   *  * *      * ***  * ** 
**  *      ** * {
  * ** *     ** **** ****    ** ** ** *   *  ***** * ** * ***    **  *   is a prefix of   **     str1, str2);
* *** ****** **** ** **    * 
       ******   ** *  ****   ** 
 **  ** *****   * *****  ******* ** ***   ****  **  ***   * ****  is not a prefix of * * **   str1, str2);

** *     ** *  *** * * **** *    0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** *  ***
#include ** *** *   ** * 
#include    **      * ***

int main()
{
   ******* * ***  * *****     *  prefix[100];
 *   *  ** ***         *** *  word[100];
 * *   *   ** * * *  *  *   * * **  %s", prefix, word);
****** * ** * ***  ****  * * **** i;
       * **       **    ** **  = 0; i< strlen(prefix); ++i)
 ***  * ** * *** ****** **  *   *
 *  *** *   ** *   * * * *** *  *   *  ** * *** ** *     *  * **  **  * 
* * ******  *  * *  *    *          ***   ** **  *  * ** ***
** * *    * ** *** ** **  * ****** * *** *  *** * *      ***** ***   ** * * * ***** *  *** **** *   is not a prefix of %s", prefix, word);
 * ***   *** * * *  ** *  ***   *    * * * **** ** ***    *   *   * *  ** ** ****  0;
* * *  **    * * ** *    **    *  *      * ** ***    
 * * ** ****  *  *** *   *
* *   *** **  * ***** * *   * *   *   * ***** is a prefix of %s", prefix, word);
* *** ***** **   ** **** ***  ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *****  ******  *
#include **   * *  *   * **
#include    *  **** *

int main()
{
  *  **   *  *****  **  *   *  prefix[100];
  *** *    ** **   ********** * word[100];
      *  * * ***  * *    * **   *   *  %s", prefix, word);
*   **** *   * * **** **   * *  * i;
 *  ****   **  * ** *    ** **  = 0; i< strlen(prefix); ++i)
*  ***  *     * *** * ****  
    * *  ***  * *  ** *   ***  ****     *** *  *  ***  **      **
**   * *      * *** *   * * **     **   ** *  *** **  
****  *  **  **** ***** *  *** * ****    ** *** **** * * * *    * **  ***     ** **** ** ***  is not a prefix of %s", prefix, word);
*    *  *** **   * * ** * * ** *  ** * *** * ** *  * ** **   *     *   ***   * * * 0;
 *** *  * ** *   *  * ******  * * *    *    ** *   ***
*****  * **   *   ** *  ***   *
* *  **   *   ****  *   * * *** *   *  is a prefix of %s", prefix, word);
** ***** **    *   **   *** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ** *  *  * ** ****  
*  *** *  **      *** 
*  * *  **  ****  *  ***

int main()
{
* **  *  * *   char ***** *  
  * *    **** * char  ** **
* ****     *  **     **  * *  ** * * ***  *   ** word);
 *  **    ** * ** int i;
 *  **  ** *  * for(i = 0; ***  **  **  ** ++i)
 *   **  *  **  {
  *   *  ***  *  * *****   * ** **  ****
*       *****   *****   * * {
** *  * * ** *    *   * ***  * *  *   **  ** ***  * ***  *  is not a **** of  **  ***  * * word);
  **   * **  **** ***    **  * ***  ****  0;
 *  * **   * ***    *  **   ***  }
* *  * * **   * * }
 **   *    **   * ** **    * is a prefix of * ** ***  *  * word);
*** **        * **  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.93
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users