1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 * **  ** *** **   ****** *   
 **   ******* *** *   *     ***    ** ****   ** * *  *  
    {
 *  *  * *  * ** *  ** * *  **     * ****  ** **** * * (i=0; i<=strlen(string2)-1;i++)
 **  * **     *   ******* *     * *  **  *  ** **  * ***
  *        ****     *  * **  ****  **   **  ****  *** *      *     **  *** *** * **   (string2[i]==string1[i])
* *   * * *  *** *  ***   ****** **** *   * * *   ** * *   **  *  * ** ***  * *  
** * ***    **** ***  * **         ***  * ***     * *  *** ** **** ** * ****  **   * ** ******** *  ** **  * 
 * * ** * *  **  *    *  ***   * * *  * ***  *  ** ** * **  *  *   *  *  *** * **** *  
*  ** *  ***   *****  *        *      * *  ***** * **** 
   * *  **      **   ** * *    ****   ***    ** ** ** **  
* * *** * **    *** * ***        ****      ***** **  * * 
* **** * ******  *** ** *  ** * ***** *  **   ***** **** *   * *****    *   ** ****   *** **** is a prefix of %s", string2, string1);
** *** **   ** ** **  ***   **** ***   ***   * *     
** **** ** *   * ***  *  **** * **  *** **    ********  *      
* **** * *   * * **** * *** ***** *  **** * ** * * * 
 *****    *  ** **     *      * *** *  * *   * **  ** ****    * ** *    * **      **  ** is not a prefix of %s", string2, string1);
** **  ***      *  **** **   *  ***    **  **** *     
    }
*** *   *  *      * ****  *  * ********    *     *** * * 
    {
** *  *   *     *  *      *** * ***  **   * * *     *   * * (i=0; i<=strlen(string1)-1;i++)
     *  *  * *** ***  ***   *    ** *  *  *    **     
*   ****   ****       *********** *   ******* **    *** ** ** * *  ** *    ** ***  (string2[i]==string1[i])
**  *  * * *  * *  *  *** ** *  *    ** *** *   *   ***    **    **  **  *  **    *  
**    ** *********  ******   **   ***  **  ***   **** * *** ** *  *  *   **    *****   * **** * * * *****  ** *   * ** 
** *    *** * *** * ** *  ***  *     *** ** *** *****   * ****   *   * *  ***  *** *
 * **   *** ***   *  * ** ** ****  *  * * *  * ** *   * 
  ***** **   * *  **  *  *** **  ** * ** *****   *  *  
   * ** * * ** **** *  *  * * *   **  * *  **      ** *
  *   *  ****  *****  * *   **       *** *       **      *  *  **    *     * ****   *  *** is a prefix of %s", string1, string2);
 **  * * *** ****** **   **  *   **** *   *   ** *    * 
*  *  ** *     *  *  **  * *    * ** * * * * * * *  *  
*** *** * **** *  *  **  * * *  ** *  *  **   *  *
 **   **     ***  **** * *****  *  * **** ** * * * ****** ***  *    *       ***** ***   is not a prefix of %s", string1, string2);
*       ***** *   * *    *  **** ***** *    *****  *     *  ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 ****  **** *  *  ** * ***    * ** *  %s", chaine1,chaine2);
**   ** * **** *****   ***  *******   **  *  
* *** *** * * *   *  *  *   *  * **    0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  **  *** ***  *   ******* * * lenght1,lenght2,c;
*  *  ** ** ** *    ****     * b[100];
 * *   * **  ** *   *** ****   ** * a[100];
*****  * * ***    ***  *** * d[100];
   * ***** * *    ** * *   ** *  * ****  * * * ****  
   *  **  * *** ***** * *  *  *  * *********  ** 
 *    * **** * *  *   * *    ****** * *
** * * ***   ** * *  *   *** ***   ***
*   *  ***  *** ** * *****   *** *** ***
* ** * *  * ** *  *  ** **
****** * *  *** * ***** * *  * *** * * *  *  ******      is a prefix of %s",a,b);
  ***** ***  ***  * **** **    *
 *  * * ** ****   * **** *   **
 *  * * * * *** * * * *
  * *** * **  **** *** ** *  * ** **  * *     *  * **** *** is not a prefix of %s",a,b);
*  **** *  ***      * ***  
** *  ****** *****  **   ****  **    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  *     *    
#include *    *** ***   *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ** ** ***  ***  i;
 **  *      * *  * **** * **
  {
**   **** *   *  *  *  ***   ** *****   A[i]!='\0' && A[i]!=B[i]   )
    **** **** *** *     * * *  ****** ** *     * *  *    *  ** **  *** 0;
****  * **   * * *** * ***** * **  ** *    ** *  
 **     ***    ***    *  **************** ******  *   ** *** 
  }
** * **** **  * ** 1;
}


int main()
{
    **  **  **    ***   * ***  a[n],b[n],c[n];
 *    *  ** **  **      *  i;
* *   *    * **  *  **  ** ** ***  * * * *     ***
 *       *  ** ** *** ** * ***** * * * *    * *    
* * *  ***   ***** **    (aa(a,b)){
****** **   * *     **  ***** ** * * * * * *    *  **  * * *    ****  ***  *  
  * * *  *   * ** **  *  ** **  **  ** *  *** *  ****** ** *   ** *  *   *   *   **     ** *  *
* *    *  **  *   ** * ** *  **  **** *** * **   ****** *  *  *       *  * ******* ***  *** *** **   **  ** *   ***  
   ***** *  *****   **  *****  ** ** **      ** * ***** * *  *    * ** ** * * *    *

** **  ** *** *    *** * *  * *   *** *** ***    ****  
**** ** **  ** *   **   **    *    ***  ******* **  * ***  **  * is a prefix of %s",c,b);
*   ** ** ***** * *        *
 **  *** *   * **  *  ***    
 * ***  * * ** *   * *  **  * ** * *  *  * **   ***   ***  *  ***  is not a prefix of %s",a,b);
** **  *  *     ******  * *    * *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *     *  
  ** ** ** *  ** ***   **
int main (){
char **  *   
char **   **
 **  * *  *   * string1:   *   
 * **     *  * *  *  *   ****    * 
 * **  * * *   **  string2: ** *  * 
 **  * *   ***  *   ** *
 * *    * **  *   ** *
****   *   *    ** *   *  * *  *  is   ****** of ****** **** ** * **   
else
 ** * **  ******* ** ** * *  ** * *  *    *  is not prefix of **  ****** *     * * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***   *   **  *  *  
#include *      * * * *
#include **  *    * ** * *  
#include   *** *  ** *
int prefix(char p[],char s[])
{
* *** **   * **       * *** *******  
 *       *  **  **** * * ****** * 0;
 **    *** ***    **  * if *   ** *  ** *   *  ***
  ** ****    ****   *  * * ** *  ***   1;
*  **  ***   **   * *** * *  
       ****** **     *** *  * * * 0;
}

int main()
{
 **  ******* * *** **  * p[999],s[999];
**   * ***    ** ** *  *** * **       **   
 *** **  * * ****    *** **  *  ****  **   * * 

    ****  *****  *  *    **  * * 
     ***  **** *    ****  * *  **  *    *    is a prefix of %s",p,s);
*   ***  ***** *       *
**   *  *   **  * ***  ** * * *** **  is not a prefix of **  * * ** 

    * *       * ** ***** * * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include       * ****** ****  
int main()
{
*  **  * * **  *  **   * *  *  * length1,length2,c;
* ****      ** * * *  ** *    * a[100];
 *  ***    * *    **   *  **   * b[100];
  * **** ***   * *** *** * ** d[100];
   **    **  ** * **   ** ** *** *    * * ** * 
 * * * *   ***  * **  **  ****   *   *
   * **    *  * *      *** *  * **
****  ** ****    ** **** *** *******  * * 
if (strcmp(a,d)==0)
****  * * ** ***** **    *
*   * **  * *  *  ** *   *** * **  ** * * * * ** * *     ****** *   is a prefix of %s",a,b);
    * *  ***   **      *** *    
 *   **** ***    *   * *   *
 ** * ** ***** *    * ***
    *      *** ******** * **  **** ** * * *  ** ***     * ****  *  *  * is not a prefix of %s",a,b);
  **** ** * **  *  * * *
 *   ** **    0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ** *   ** * *
#include  * *** *****  

int prefix (char *  **  str2[])
{
**** ** ****  **  **    length=0,  ** *   
  *  *  ****** **  
* ** ** ** *** *  **      ***  =  **   * ***  * *
****     ****** *   **  
**  ***  ****  *   ** * *  * *     *   * 
**       * **  * * *  *    ***  * **  * * 
  **    * *     *   *   * ****** if *  **    *
*** *   *     ****         **  *  *****  **    *     
    ** * **  *  **   *   *   *  **   *    }
 *  ***           * *   **  ** ***
* *   **   *     *** (count == length)
**  **** *** *   * *** *  **   *   * * *     1;
***** * ****** ****   *  *  ***** * else ****** *  * 0;  **  **   ***    *
* **   ** **    * **  *  *  ** * * * 
}
int main(void)
{
** * * *  *  ***      *     *   **   *  *** 
    *  *****   ****    *  *** **  
 ****** * **    ****   ***       ****  * *       str1, str2);

 *  *** ***  **  * *  *  **   * * **** 
*** *  ** ** {
 *** *      * ** ***     *** ** * * * *** *   * ** *  **  *****       is a prefix of   *      str1, str2);
 * *  * **    **  * * ** *
*  *****  * * * * ***  *  ****** 
**  ** *     ** * **  * *    * ** * * *     * ** ** * *   ***     ** * * **   is not a prefix of * **  *  str1, str2);

       * ** **   ********  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***   * *  ** ***
#include ***   ****   *
#include    *  *      ** *

int main()
{
   * *   *  **** **** *   ** *  * prefix[100];
* **  ***  * ** * *  *   word[100];
  ***  * *    *  *  *  *       **    *  * %s", prefix, word);
 ***  **  *******    * * *  **** i;
  * * ** ***** ****  * * ***  = 0; i< strlen(prefix); ++i)
**  **  ****** * * *     ** * 
** * **** **  * *   ******  ** ** ***     * *  **  * *   **** ****** ***  
*   **  * * ** **   **  ***   **** *  *** ***  *
 ***  ** * *  ** *    ***   ***  * **  * ** ** ***** ** *** * *  * ****       *** ***  ** * is not a prefix of %s", prefix, word);
  * **  **  * **   * * * ** **   *   *     *     ** **   ** ***    **       0;
*  *****  ** *  *****   *  * * ***** * ** **  *** *
**  * ** *  **  ******  ****
*  * * *   * * *****  ** *  * *    ***   is a prefix of %s", prefix, word);
*     *** ***** *   ******  ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *****   *
#include  * ** *   ** *  **
#include *  ***   ***    **

int main()
{
*  *  **     *  ***** *  ***** prefix[100];
  ***   *   *** **  **** * *  word[100];
 * * * **** *** *****     * *  *   *  **  %s", prefix, word);
   ** **     ** *    *  * *    * * i;
 *** **  ******    *** ***  *   = 0; i< strlen(prefix); ++i)
* *    * *******  ***       *  **
 ***   * ****  *** **** **       *  * *  * *   ***** **   ****   ** ***
 * *  **** * **  ***  ** * *** **    *** *  ** ** ****
 **  * ***  * *** * *     * * * ** *  *       **   * *  ** * *  *     **  **  ** *  ******  * is not a prefix of %s", prefix, word);
** *****  ***  * * **      ***  *    ** *  *       * ** ** *  * * **    ***** * **  *   0;
 ** *   * * ***  *** *  ** * * *   * ** *  * **  *****
** **     ****  ****  * **
** * * * **    *    *   * * * * ** * * is a prefix of %s", prefix, word);
***  *  *** ** **  **  *   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ** *  * **    *** * 
  **  *  *** * * ** *  
  **    ***** * *   *

int main()
{
 **   *    ** ** *  char  ** 
*      * ***   * char   **
 ** *  **    * ****      *** *  ***  ****    ** word);
***** * *   *  int i;
 *  * *  *** for(i = 0; ***    *   *  * ++i)
  *   **  *      {
 ****  **  *     **  **    **** **  **** ** * *** *
* * ** **    *   * * * *  ****** {
 * **   **   *  *** *          *** * *    *  *******  is not a *** of  * *    * * *  word);
* *     **  ** **  *    *  * *   *  * *    *   0;
      *     *  * ****    }
*    *     **  ***  }
*****  ***  *   *  ***    is a prefix of     * **  *  ** word);
**  * **  * * ****  * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users