1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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{
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}
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#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include  ******* * *** ****
#include *  ***   * ***
//#include <ctype.h>
#define n 100
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}
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Hidden content!
#include **      * 
    *** ** ***  ** *** ****
int main (){
char  *** ** 
char  *** *
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include     * * **     **  
#include  ** *    **  **
#include *  **  *      
#include ** ** * *    *
int prefix(char p[],char s[])
{
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 *   * **** * *  * * ****  **  0;
}
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Hidden content!
#include <stdio.h>
#include * * *    *  * *  **
int main()
{
*** *** * ***  **  * *     length1,length2,c;
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}
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Hidden content!
#include *  *  ***   *  
#include ***  *  ***   

int prefix (char  **** **  str2[])
{
****   ** **   *  ** *** length=0, * **   
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{
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 ** ** *   * ** **** **  *  *  * 0;
}
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#include  ** ***    * *** **
#include   *** *   *       
#include ***** ***  *  * 

int main()
{
***** * *   **   ** *****   **  *  prefix[100];
  *         ** *   *  * * *  * * word[100];
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****  ***** * *  *  *  *
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***** * *** ***** ** * *  *      ** 0;
}
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Hidden content!
#include ** * **  ****
#include  ****   * ***
#include   ** * ** ** *** 

int main()
{
    ****** * ***  *  *    ** prefix[100];
 *  * ***        * * ***       word[100];
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**      *  *  ***    *     *** * i;
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 * ***     ****   * * ** 
*  ** *** *** *  * *  * **  **  *   *   *****   is a prefix of %s", prefix, word);
*   *** *** **** ** *** * * *    0;
}
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Hidden content!
 *  *   **     ***    *
 **    * **   *** **  
  *   ** ** *   ***  

int main()
{
* ***  * *  * char     **   
** **  * **  * char  *  **
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 *** ** ****     * * *   *  *  *  ****  ** * 0;
  *   *    * ******* * **      ***    * }
 ** * *      * }
 **  **  * * **    * *** ** is a prefix of **      ** word);
*******     **   *    0;
}
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