1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include ** * *****  * ** 
#include   *  *    **  
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}
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Hidden content!
#include  *  ** *  ** *  *
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int main (){
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include * *** ***  * * ** 
#include  * *  *** ****   *
#include  ***    ** ** 
#include   * *** **   * **
int prefix(char p[],char s[])
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***  **** * ***      *   0;
}
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Hidden content!
#include <stdio.h>
#include ** ***    *  * ***
int main()
{
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** *  **   *    ** ****    * *
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}
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Hidden content!
#include ****  * * ** **
#include    **  * *  ** *

int prefix (char   ** * * str2[])
{
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 ***   * ** **  **    ***** ** * *  0;
}
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#include **   * * **  
#include       *    **
#include   *  *       *

int main()
{
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****  *  **    * ***** *   *   * is a prefix of %s", prefix, word);
** *  * *   ** *     *    ** *   0;
}
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Hidden content!
#include **** **** ** * * 
#include     **    ***  *
#include ***   * *  ***  

int main()
{
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 * ***** * * **    ** *  *  0;
}
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Hidden content!
* **       *  **   
* *  *** *      * * * **  ****
 ** **   *         ** **

int main()
{
 *****  * *** **  char ****  *
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*** *     ***    **  *      **  }
 **  * * ****  }
 ****   **   **  *  * *** is a prefix of *    * **  ** word);
 *  **     *   **  0;
}
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