1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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{
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include **  * **  ****      * 
#include    *     ******  
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#define n 100
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}
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Hidden content!
#include   *    ** ** * 
** *    *       * *** *
int main (){
char * * *  *
char *   * *  *
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else
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include *** ****     
#include *  * *   **
#include    * * ****  ** 
#include **  **** **   *
int prefix(char p[],char s[])
{
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* * *** ***** * * **  0;
}
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Hidden content!
#include <stdio.h>
#include **    * * ******
int main()
{
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}
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Hidden content!
#include * *  * *   
#include  * ** * ***  * 

int prefix (char  *****   * str2[])
{
*  *** ** * * ***** *   ***      length=0, * ** * *
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  **  **  ***** * *   *  **** ****      *** ********   *  ** * is not a prefix of  * **  str1, str2);

 *     ** * ** ** ***    **   0;
}
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#include * ** *    * 
#include * * **      ** ** 
#include ** * * ***   ***

int main()
{
  *   * *   *    ***  **** ** * prefix[100];
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 ** ****   * *  *  *  *****  *   i;
 * ****  ***  * ***** ****  *** * * = 0; i< strlen(prefix); ++i)
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*  * *****   * *   *  * * ***  * 0;
}
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Hidden content!
#include  ** **   ** 
#include **  *     ** *   **
#include * ***  ** * 

int main()
{
*  * ****   *   * *     ** prefix[100];
 **    *   *  * ***** ***   * * word[100];
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 *  *******  *   ** i;
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* ** **  *          *      * 
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  * * **** ** ***** * 
*  * *  **   *******   *** ****** * * is a prefix of %s", prefix, word);
* ****   ****    ******  * * * 0;
}
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 ** * **   * ***  
 * *    *   ***     
***      **  *******  *** *

int main()
{
   *** ***    **  * char **   *    *
*  *      *     char  * ** 
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 ** ** *   * ** * }
*   *   ** * ** ***  * ****  * is a prefix of ***** *    **   word);
*   * ** *    ** * * 0;
}
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