1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*  *  * ** * *** ****** *   *  
  *** ** *  * ****** ** **  *  * ****** * *     **** *   **  * 
    {
*      * *   *   *** ** *  **    ***** *  *   *** **** * (i=0; i<=strlen(string2)-1;i++)
 * *   **   ** *     ***  ***   *   ** ***** * ** * * ***
  *   *** **  *  * * *** *   *** ** * ****  ***  *  *  ** *   *    ** *  ** *     (string2[i]==string1[i])
  **  *         ***    ********** *      * *** ***  *  * *  *  * ****   **  **  * *** 
* **** *  ****** * * ** * *** *   *      ****** *   *   * * **  * ***  ** *   *  * ** ** ***         ** *    * 
*  ******* *   * *  **    ****    *   ****** *** **  **  *******   *      *
  ** * *    ******  **  ****  ******* *   ***   *  ***** 
*   *** *  * * *   ***** ***  *     * ** *  ***  * **** *  ***** 
* *  ***  ** *  **  ** ** *   * ****     ***     **** 
 **** **  * *   * * * *         * *  * ** **   ***  ***       **** *    **** *****   * * ****    * * * is a prefix of %s", string2, string1);
 * *  * ** ***** *    *** **  *    *  *********    *  **
*** ***   ** **    * *   * ** **** **** * *** ** *   * *  * *** **
  ** ***** *****   *****   * **      * ***   * * *   * * **  *
  ******* *  **  * ** *******  *  ** *     * * *     **  * **** **  *  **** ** ** ****  ********   is not a prefix of %s", string2, string1);
**   *  *   * * *******  * *** * * ** **** *** *  ** *
    }
     * **  *  **   **** ***  **  ** * * *****  ** * **   **** 
    {
* *  ****  *  * * *  *   *  ** *** **    *   * **  **** ** (i=0; i<=strlen(string1)-1;i++)
*  ** *  **  * * *** ****  ****  * * **  ** *  * *** ** 
 *  ** *   * * **   ***   *   *  ** ******   * *  ** *   * *** *  * * ***** *  *** (string2[i]==string1[i])
 *  * * ** * ****  *  **** ** * *   ***   *    * * * **  ****  *  *  *  *  * 
  ** *******  ***    * ** *** **  **  *  *** *    ** **  *  **  * * ** ***  *  **     *  **  
 *   *** **      * *   * **    ***** *** * *** **      **** * *  ** **  *** * ***   **
 * **     *** *   ***   *****  * ** **  *****   *
   *** *** ***  *   *  *   **    *****   * ** ***  * *    *
**  * *** **** *****  ****  ****  ****  *** *    *
  ****   *  * * * ***  ** * *  *  * ***  ** *** * ***    **    **  *** ** *  *********   ***  ** * is a prefix of %s", string1, string2);
* ** ** *****  * ******* ** * ****    * *    *     *    **
**  * *   **  *  ***  *    **           * ****    *** * 
*     *** *  ***     * ***    *  * *    * * *  * ** **  *  * * 
** **  *  ** *  *   *** *  *     * ***  **    **  *** * * * * ** *    *    *  * **  **  *   is not a prefix of %s", string1, string2);
* *        *  *** ** *   ** * *** * **   ** **   ** 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
  *** * ***      *  ** ** * ****  %s", chaine1,chaine2);
********   ****** * *  * *  *   **     
*****  **   ** **  *  ** **  *     0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*   *  ***** * *** * *  **  **  * * lenght1,lenght2,c;
****      ******  ****** * ** b[100];
*****  ***   * ** *  *  * **** a[100];
*  *      ****        ** d[100];
 ** *  *** ** **     *** ** * *   ** ****  ******    
   * ****** *    *** ***** *  **  * * ** ***  **
**  ****  * * *  ** **** *  ** **   *  **   
*   **      **  **     * *  ** *****   *
**  **** **     *         *  ** **  
* ****   * *****     **  ** *   
 *  ****  **** **** * * ** *  * * *  * **     * ** is a prefix of %s",a,b);
          *****  **  ** * **
***   **   *     ***** * *
*  * * **** * **    **   **  *
  * *  ***   *    * ****   * **   ** * *  ***   ** *    * *** **   **   is not a prefix of %s",a,b);
*             * * ** ** *** 
 **    * * ***  ****   * *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   *  *    ** 
#include  ***       * * *  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*** *   ** **   * i;
*   ****  *** *  ** **  * ** **  * 
  {
**  ***    ** ***  ** **  * *  **** ***** *   A[i]!='\0' && A[i]!=B[i]   )
 *   ***   ** *     * * *  ** * **    ****   ***  * *    *** * * ***   *  * 0;
***    *  **** ***  ***      ****    *   *   ** * ** *
*** * **  **    * ** *  *** **   ***   * **     *   *  *  **** *
  }
 *     ****  **  * 1;
}


int main()
{
** * ************ *     *  *** *  a[n],b[n],c[n];
  *  ****** **** *   *  *    *   i;
***  *   ***  **  * * **    ** *  **  *  ** *  
*  ** *  ** * ***** * ***  ***     ***  *     ***
** * * * *    *   * ** (aa(a,b)){
****  *    **       *  **  *   * *   * * * * * ** *  ** ** * *  *    *  * * 
***** ** * *   *          * ** *  **  * ** *** * * ** * **   ** *  *    * ** *****   
* * * * ********* * * *****   ** ** * ** **  * ** * ***  *** **  ** **  **   ***   ****    *  *    *********
 ** **  **   ***    ********* ** *  * ****** **    * ***    ** * *** *** * *

  ** ** **   * *   **  * ***   * * * *** **  ** 
 ** ***  **     *  * ***     *  **  * **** *  *   * **** ***  is a prefix of %s",c,b);
  * ** ** ****   *** *** 
*   **** ** *****   *   * 
 * **   **    * ***  *** ** *  ** ** ** ** * * * ***         *   *** *  is not a prefix of %s",a,b);
 *   * ** **       * * *****   * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *** * * *   ** *
   **   * ** *** *** * *
int main (){
char ***** * *
char **  **  
**  * * *** *  ** string1:   **  
 * * *  ***    *** *  *   *  *
 *   ********** * string2: **  **  *
* *  * * * *****     *  *
 **** * *   **   ** ***
 ** ** * *       *  *     ****  *** is  * ***  of *  *****   *** * 
else
*    ***   *  *      **    **   * *  *  ** is not prefix of ** ****     * * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * *** *   * * 
#include *  *  * ** **    
#include   *  ** *   *
#include   ***  **   *
int prefix(char p[],char s[])
{
**** ** * *  *  *  * *  *  *  *** **  
 * *  *** ***** * *** * ***    *** * 0;
**  **   *  **  *  if   *  ***** * * **  
 *   ***  *  **  * *  **  * *  1;
*  ** *  * * *   **** 
  **  *   * **** * ** **  0;
}

int main()
{
**** **   ** *   * *   *  p[999],s[999];
  ** *  * ** *      * ***      * * ***   ** 
 * ** ***    **  ** *****    *  *  **** * * 

*** * * * ** **      ***  
** *  ***   * * *  **    *  * ** **  is a prefix of %s",p,s);
* * **        * *      ** 
 *    ** *** *   * *   * * * *****  * * *  is not a prefix of **  ** ***

        ****  **    ****  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * ** * * * * * *
int main()
{
  **  **  **  * *** * *  ** *   length1,length2,c;
********  *  *****   ******  *  a[100];
********* * ** ***   *** b[100];
***    *** *  **  ** *    * *  ** d[100];
**   * *  **** * ** *  * *** *** *  ** *** * * *  * **
**** ** *** ****  ** *   ** *****      *   *  *  
**   * *  **  ****  *          * *  * *
   *****  *     *   * ** **     *
if (strcmp(a,d)==0)
*  **    * * * **  *** *  * * 
   * *    ****  **** * * **  **  * * *  *** *   *** * *    ***    *  * is a prefix of %s",a,b);
* *****      *****   ***  * *  
   * * ****** * ****  
      *  ***    **   * *** ** *
   ***   *  *  **  **     * *  *   ***    *     * *    *   * *    *  is not a prefix of %s",a,b);
*  * **    * * ** ***** 
*     * ** ** *** **  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * **    *** *     
#include * * **    *  **  *

int prefix (char * * *  ** * str2[])
{
***   ** **   * *  ** ** * length=0,   ****
   *  ***** ** * ****
 * * **  * * ** **  ** *   *   * * =   ** *  **    * *
   * ****    * *  * * * 
 *  *  *  ***  **   *  * * **  *   *     **    *
 **      *****   **  * ** **** *** * **    * **
   *  * * **  ** ** ** * *  * *   if *** *   * **
* * ***  *** * * * ** *         * * ****** *     *   *  
* **  *****  **  **  * * *   *  *  *   }
 ***  *           *  **   *** *  * *
 * ** *   ** * **        (count == length)
   *    ****     *  ** ** * * *  * **  **** 1;
 * ******* * **    * ** **** else *  ** * *   0; *    ** *  * ** * * * 
  **      ** *** *  *   * *     
}
int main(void)
{
** * * * ** *** *   ** *   *   * ***** *  ** 
* * *   **      **** ******
 * * *** *** ***     ** **   * ***  ***  * *   *  * str1, str2);

 ** *  *** * *** * *   ** *   **  ** * **
 ***** *   ***  {
***  * *   *  *    ** * ******** **** **  **  *  *** *  *  *    is a prefix of  *  *  * str1, str2);
 **   * ***  * **  ****  **  *** 
*  * * *  * **  ******** ** * *  
* **   **    *    ***  * *******  *  *  **     ***   ***  *  ***  is not a prefix of    *  *  ** str1, str2);

   * * ** *    * *    **   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **  **  *   *
#include  ** * *** *  * 
#include *       *    *

int main()
{
**   * ** * *  *       *** prefix[100];
*** **** ***  ***   * *****  * *  word[100];
* ** ***   *   *   * *  **** ** *   %s", prefix, word);
*******   * *  ** *   ****** * i;
 ** ****      * * * *** ** * *     = 0; i< strlen(prefix); ++i)
*   * *   * * *  ** *** * 
 **   *   * * *  * * *** *    ***  *****   ******  * **    *** ** ** * ***** * 
 ***** ** *** *  **   * *   * *********     * *
 *  *****    *****   * *  * **** * * *  * *  ** *  *   ***    * **  **** * * * *      * ** * * is not a prefix of %s", prefix, word);
**   **  **  ** ****   *    **  *  **** **  *****  * * ****** *******      * ** * *      *  0;
    *** ***  * *** **  * *  ****   ** ** *  *  **  **
*** *    ***    ***  *    **  *****
 * *** *  **** *** **  *** **    * ***** *** is a prefix of %s", prefix, word);
 * * * *  *   ******  **** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * ***  
#include * *  * ** * **** ** 
#include    **  **  ***

int main()
{
   ** * *   *  ** ***   * * *   prefix[100];
**    ** *   ** **** *  **** word[100];
 * *** * *** * *** *      **   *    *  **   ** * %s", prefix, word);
 ***    * * *******     **  *  i;
*   * * *  *   *  **  *** *  *    * = 0; i< strlen(prefix); ++i)
  ***  * * ** ** * *******    **
 * ***** **** ****** ** **  ** *    * * *** **   **      **    * *  
***** * *  *   *  *  * *****  * * ***  **   ** *  *  
   ****  * ** *   *  * * **     *** *  **  *** * *  * *******  *      *   **  *   *** ****  is not a prefix of %s", prefix, word);
********* **  ******* *  **  ** ***  *  **  *  * ***** *       * ** *   ***    ***** 0;
*  ******  **  *  * * *  *  *** * **    *  * * ** *  *  
* **   *** ***  * **       *  
 ***     ***  ** **    **  * *   * ** * * is a prefix of %s", prefix, word);
   *    **  ** * *  *   *    * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*     *   **  *** *    
*  **  * * ** ** *
 ** *  ****  ** * 

int main()
{
**  *     * ** * char    *   *
     *     ***   char *   * *
 ** ** *   *         ** * * *  * **  **      word);
*     * * * int i;
**    ** **  for(i = 0; * * * *  **  ***  ++i)
*  **  ** **** {
* *** **    ** **  * * ** **** **  *** ** *****  *  
 ***     ** *  *   *   *  **** {
** ** **  * ** **   *** **   * * **    *  **   * *    ****   * is not a   * of  ** *** *  * * word);
*** **   *  ** ** *  *** **     * *    * *  **   **  0;
 **  * * *** * *       * ***    }
**** * *  **  * }
 *   **    ** *** * ** ** is a prefix of  ** ***  ***** word);
* **  *  **** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.78
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 9.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users