1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* * * * **   * * **** **  * *** 
*  ***   *** ***  ***  **** *   * *  * **   *** * *   * *
    {
**** * *  *  ** **    * * ***   ******** **   * *  *** ***  (i=0; i<=strlen(string2)-1;i++)
* **   ***** * ****   * **  **    ****** *    *****  * 
* *** *** *   ** ***     * * * ***** **      *  *   * *  * ***** ***  **  *      (string2[i]==string1[i])
 *    * * **   **** *  *    **** *** ** *  **  * *  **  *** * **      *  *  **
 **  * * ** *  *  *****  * * ****  **  *** *  *    * * ***   **  *    ** * * * **  *  * *   * ** *     ***  **
* ***    ***     *      ** **    *  *  ***** *  *** *******  *** ***  ***  * ******  ***
  **  **  ** * *** * **    * * *** *  ***   * *  *   * **
  *  * *    *  * *  ** *** *****  *  *** ** * * * *   
*  **   ** *  * *  *** *  **   **   *  ** *   * 
* ** *****   **** * **  *    * ***  *     *** *** * *****   **    **   * *   **  * **  *     is a prefix of %s", string2, string1);
** ** *  **** ** *****   **  *     ***   *   **  **  **  
** ***      **      **      * **   **   **** *  ** 
   **** ***** * **  ***  ***  * ** *  * * **   * ** **
* *** ********    *    * ******    **  ** **  * ****  ** * ***   *  **   **  ***   *  is not a prefix of %s", string2, string1);
   ***  *   **  ** *  * * **    *   ***  **** * *    
    }
**** ** *  ** ** **   ** **  ** **     ** ** *  * * *  
    {
 * * ** ******** **** **  *    ***       * ** *  **  **   (i=0; i<=strlen(string1)-1;i++)
 ** *   ** *   *  **** **  * **  *    *   *  ****    ** *
*    * * *   * * *   ****    *** ** **   ***   ** * *    * *** **  * *   * ** ** * (string2[i]==string1[i])
* ***   ** *  **** **  ****   *** *  ***  *   * *  *  ** ***  * * * *** **  ****   ** * **
 *   **  *   *****  ***    *   *** * *   * *  * ***   *  * *  **  * *   * *  ******     ** *   ** *   *  **
 * **       * ***** **** * ***  * ** **  *** *     * **        **  *  *  
  *** **  ****     * ** ****  **  *** * *  ***
*     **** *  *** ***** *   *    *   *  * * **    ***** ***  
* *** * ** ** *  *  * ****  ***    * ** ** **   * 
  *  *    *   * **  *   **   ** *   ** ***  ** *   ***  **  *  * * ** *  *  *  * **   is a prefix of %s", string1, string2);
*** *  *  * *   * *** *  ***   * *  * **  *     * ***
 * *   ** *  **     ***  ** *  *** ** *  *  ***  ** *  *****
****  * *** *** ** *  * * ****  ** * ** *  *** * *   * * **
**  ***** * ***    *** ***  *** * *  *   * * ***  **** **** *  ***** ***    ***   **  ** *  ****  is not a prefix of %s", string1, string2);
 ***   *****   * ** * ** ** *  * *  * ******    
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   * *    * *  *** **    ** *  ***   %s", chaine1,chaine2);
 ** **    **** * ** *  * * ** * ***   *** * *
*  * ** ** *  *** ***   *  **  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
***  **  *   *  * *** *   lenght1,lenght2,c;
   * *  * *     *  ** * *   * b[100];
  * ** * ***  ***    ****** a[100];
  **  *** **  *  * *** **  * d[100];
***  **     *** *  * *     ******** ******
      * * *   *  *** ** *  ***     ** ****  *  ***   
** ******** **** ****** ***  * * * ***   * 
 *  * *  * * *******  * *  ***  * ***    * *  
* *   * **  *****  *  *** * *  ***  
 * *****  ******     * 
*  ****     * ** *   ** **** * *   * *  *   ** *** *** * is a prefix of %s",a,b);
* **  **    *  * ****   ***   *
 *  *** **   **  **  ****
** * ** *  **  ***  * ***
** * ****  *  **     *** *  ** *   * **** ***  **  **  * *  **   *** ** is not a prefix of %s",a,b);
 **** *     * **  * * 
***   *  ** ****** ********* *** ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *  *  *  * * 
#include    ******    * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
   * *** ** *  i;
 **   *  **  *    **  *  *  *
  {
 *  **  * ** *        * * ** * *  * **   A[i]!='\0' && A[i]!=B[i]   )
**  *  * *  * *       *****  **   * * * ****** **  * *  ***  *   *   ** 0;
   **** ** *  * * *   ***  *** ****  * **   ***  *   *****  ** 
 ** * ***   ****     * *   * ***   * ** *****  **   * *  *** * *  *   
  }
*** ** *   *  **  1;
}


int main()
{
****      **** * ***** *  ****  a[n],b[n],c[n];
* *** *  **     ** ***  *** *  i;
******* * *     *  *   *  *  *    * ******* **  * *  **
** ** ***  ****  *  **  **** *     ***  ***** * ***
***  ***  *  *    * * ** *   **   (aa(a,b)){
 * *  *** *  **** ** *** * * **** ** ** **  ****  * ******** **  * **   
* ***  * * ** ***  *  *   *   *    ** *****  *   * ***    *     *     * **  * ***  * **
**  ****       *    * **  **  *   ****** **** *   * *** *    **** **  ** *** **   *    **   **  *    ***  ***    ** 
***  *   **** *****  *  * ** ** ******  * **   * * ****   ** * ** * * * **** ** 

   ** * *   *   **  **   *****   *   *  * ***  **   ** ***
 * * *  * * *** **  **  **   * ****   *   * *  *   *** *  **  ******* is a prefix of %s",c,b);
  *   * *  **  * **   * * *   
 *   **** *   *   **   **    *
  **  ** *  ** ***   ***   ****  *  *** *   * * *      *     * is not a prefix of %s",a,b);
** **   *  **  *  * * ***  * *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  * *  *         
 **   *  *** *******
int main (){
char  * ** *  
char *     
** *  * **** * * string1: *** **** *
 **  *** *    *  *   **   * * *
  ** **  *** * **  string2: ****  * 
  * **** ***** **** * * *** * **
*     *****  *    *
*    ***    * *   *** ** *   *   *   ***  **   is  ***** *  ** of *    ** *  **** * ** *
else
 ** ***  *   ***      ** ***  ************  is not prefix of  ** *   ** ** **  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *         * 
#include  *  **** *  * **  
#include    **   *  *  ** 
#include  **      ** *    *
int prefix(char p[],char s[])
{
* *** *** *           *  *  ****** **
* * *  * *    ***  ** * *  * * 0;
***      *** * *  ****   if ******    **   **   
**   ******      ***    * *** *** 1;
*  * *** ** **   ** *
*    *  **    *  ** *** **   *  **  * *  0;
}

int main()
{
* * * **** *  **  * * p[999],s[999];
 * ***** * **   ** *   **   *  * * * *    * 
  ** *   *   * * * *   *    * *** ******   **

***   *     * * * * **** * ***
 **  * ******* *      ** ***** **** * is a prefix of %s",p,s);
* ** *  *  **    ** ** ** *
  * *   *   ** * *  * * **  ** ***  *  * ** is not a prefix of   *** * *  

 * ***      *     *******  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ***  *** 
int main()
{
 *** * *  **  ** *     **  * length1,length2,c;
* ****  * *** *** *****   *   a[100];
 ***  ** ** *  ***   ** *  * *  b[100];
** *  * **  ** ** * *  **** **    d[100];
    * * **   *     ** ** * * *    *** ***    * 
**** *** *   *    * **** * *      *** * * * * **  **
** * *    *   * ** **   * *   * * * ** 
 **     * *** *** * *  *    *    * *** ** *
if (strcmp(a,d)==0)
*** * ** *    ****** * **  *
    **    ** * *****   *** ** *      **** *   * *******       *   is a prefix of %s",a,b);
  * ***  * * *   * * * * *****
*      * ***   * **    *  *  
 **  *      *  *** * *  * ***  
   * ***** *******  **** *  *  ***      *  ****     **** * * *  **** ** is not a prefix of %s",a,b);
* *     ***  *     **   **  *
**    ** *  *   0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** *   *  *   *  
#include   *** *       * 

int prefix (char  *     str2[])
{
 ** **   *** ***  ****  *  *   length=0,  ***    
 *** ***   * *   ****** 
** * *   *     *   ***       *  =  ** *     *  *  
 **  ** *** ** * ** ***   * *
 **  * *   *    *  *    * *** **   *      ****
  **  ** ***  *     **     *** **  *   ** * * 
*       ** ** *    **** *   * * if     * **   * 
    ***     *** *  **** **       *** **     ***  * **   *   
  *  *** *      ****   ** *  *    }
   *****            **** * *   ****** 
* **  * ** *  *  **   (count == length)
* * **  * * **      **  * *  * *** **** *  *  * 1;
*  *  *  *** *  * *   ** **  else **** ** * * 0;      * * **  ** * *
   *    * *    *** * *   **   *  
}
int main(void)
{
* ** *  * * *     ***  * **  *  ** *** * *  **
****  * * *  **  **  *
** *      **   *  *** * * **    * *** ****   * ***    str1, str2);

   * *  **** *** **    * *     * *  ** **      *
*   ** *   **    {
   *  * *   * ******* ** **    **   **   **   **** *  *** *    is a prefix of     **  *** str1, str2);
** * ** **** **    ** *** * *    
* ***  *  *  *  **   **   *
** * * *****       * *    *    ** ** *   *   *   *      ** **  ** is not a prefix of * **   *  * str1, str2);

*  *****      * * ***   ** **** *     0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * ** *     *
#include  **    *    ***
#include  ****** *  *  **  

int main()
{
*** **  * *  *** *** *****   prefix[100];
 *  ** * *******  **   *** word[100];
    ** ****  ***    ***     * ****  ***  %s", prefix, word);
  **  * ** ***  **   *    ** i;
*******    *    *    **** * *** * = 0; i< strlen(prefix); ++i)
  * ** *  * ** *   *    **  *  
* *****  *  ********* * * ** *   * * *   *  *****   *******  *   ***  
**  * *  *   ***      *  * **     *  **** *  * * * 
*    *  ******  **    *  *     *** **** *** *****      *   ***  ** **  ***    ** * * **   * *     *  is not a prefix of %s", prefix, word);
 *** * **   * **   **   *  *  ****    *    * *   ** * *   * ** * ****  **  ** *  ** ** *  * 0;
*  *     **** *  * ** *** *** ** ***** ** **  **   * 
* * ***** **     * **     *  *  
*  *   * * ** **   *  *    **   ** *  ** * is a prefix of %s", prefix, word);
     *   ** **  *  **  ***** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    **   *  **   
#include    *  ****  *  
#include * *     ** *

int main()
{
** *   ** *   * * **     *  ** * prefix[100];
*   *   ** ****  *   ** **  word[100];
  *      ***     * ***  *  **** **** * %s", prefix, word);
* *          *** *   ***    ** i;
   *** **  *  * **  * **  = 0; i< strlen(prefix); ++i)
*  *        ****    ** * **  
 *     *  **  *       ***  **  ** **  *  ******* *   * * *  ***   *
*   * **  ***  **** * * **  * *   ** * ****** **** 
    **** * **  ****  ** *     *  **   ***  *      *** ****  *****  **** **    ** ******  *** * * *  * *  is not a prefix of %s", prefix, word);
  * * * * * *  * *   ****    *   *     * *   *  *    **** ****  *   * ** *** ***  *   0;
* *****  *** *  ** **  **    *   *   *  *   ***  **
 *******     **  *****   **   *
    *** *  * * *   ** * ******* *** * is a prefix of %s", prefix, word);
* *   ** *** **** **   *    0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ****  *   *  * ** ****
 ** * * ** **** **  *****
 **   ***   ** *   *** *

int main()
{
   ***  ***    char ** **   
** *** *     *      char  * * *
***   * * *    *  **   ***   * *   *** word);
*  *    ** int i;
 **    * *   *  for(i = 0; ** **      *** ++i)
 * * * *   * *   {
** *  * *    **  * *   * * *   ** **** *** *  *    *
 *  ** *  *** ** *  *   *          {
*****   * *     ***   * ** *    *** * * * *  * ****** **  is not a  * ** of   *     * ******  word);
** ** *   **   * ** *  ***  ***    ***   * * ***      * 0;
*   ***  *  **  * *  * * * *    }
* ** *       **** }
* ***** ** *  * ** ****  * is a prefix of *    * ** **** word);
 *** * * * * *    0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users