1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* * ** *   * * *  *   
** *    ***** ****  * ** **  **     * **      **  * *** 
    {
** *   *****  *  ***   * **  **    *** * * * ** *    ** (i=0; i<=strlen(string2)-1;i++)
**** *****  * * *   **  ** *****  **** ** ** *    ** 
  **   ***  * *   * * ** ** ***   **** ** **   *   ***  *  **   ***** *   ****   * *  (string2[i]==string1[i])
******   **  *  **   *    * * *  * *  * **** **  **  *   *    **     * **   ** ** ** 
   **  *** *   ***  *** ***    **** * * ****  * *  * *  **   ** * **    *  *  ***  ***    *   **     *** *  **  * * 
* ** * ** * **   *    *    **  *** *** * * *** * **  **   * *** *     * *     *** *******   * 
  ******   **  * ** **  **  *  ** * * * ***   *  *   ***   ****
 * ** ** * ** ** ***      *    ** ** ***   **   *  *  **  **  *
* *  ***    * *   * * **  * ***** *    * ** * 
  * *   ***  ** * *      * * ***  *  * * * * **** *      *     * *  ** ** *  ***  **     * *    is a prefix of %s", string2, string1);
 **   ** **  * *** * *  * *  *  ** ** ** * * *   ******  **  ** 
****** * * ** *  * ** *    * *   ****  **  * *        
  *  *** *   * * ** *  *  ** * * **   * *** * 
  *  ** * *  * * ******     *  *  *     ***     ** * * *  * * * *** *   ** *  ****** * *  is not a prefix of %s", string2, string1);
  ******* **     **** * * *  *  ***   *   * *   * *   ****** 
    }
* * * *** *****    *  * * **  ***    *  ********    
    {
*   ** ***  ***** *** **  ***** * *  * ***** ****    (i=0; i<=strlen(string1)-1;i++)
* ***   ***  *  * ********      **  * *  **    * *** **
*     *****     * **  **  *  ***    * *    ****   *  *  ****** * ** ******* ****  * *  (string2[i]==string1[i])
******     * **  * ******  *  *    **** * **   * **      ** ** ** *    *  ** ** 
**   *** * * **** ** * *    *** ***  * *  **   * ** * *** **  * * * ** * **   ***** *  **  *   * *   **    * ** * *      
 ***  **********   ** ***   * ****     *****   **    *  ** * *** * ****   **   **  *** * * ** 
    *  * **  *** *    ******       ***    ******   ** *  *
 **   **    * *  * * *  * *  **** **** **     ** *   **
 *  **  * ** ** *** *      **** *  *** **    *** ****  **
 **   **  * *      * *    **   * **  *** ****     ****    * * ***  ******* *  *   ***  *  is a prefix of %s", string1, string2);
****  ** *  * ***    *  *  * *** **     **  **   *  
* ************ *      *  **  * * *  *   * *  * *  *** * * 
 ***  *  * ****       ** *  ** **** ** * ***   * ** *  
  * *   *******  *  **  * * *  ** * *    ******* * **   ****     **   *   ** *****  is not a prefix of %s", string1, string2);
   *    ***     **   *  *  **  ** *   ** ** *  *  ***  
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
*    ***    *  * ** ***    * * *   %s", chaine1,chaine2);
   **    **   *  ***  ****    * ***** * *  **
***  ***     *     * * **  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 * ***** ** * ***   ***  *   lenght1,lenght2,c;
   ***      * ********* *  **   ** b[100];
*  **  *      * *   * *  **** a[100];
** * * ** ** ****   ***  * ** d[100];
**** *  **************  **  **     * ***** ***  *
 * * **********   *** ** *** * **     *     ** **
* **  **    *****  * ***** **    *  * *
** ******* *    * *** ** ****     ** 
 *        *      ** ** * ** **   **** ** *
** ** ** ** *** ** ** **  * * 
 ***** *** * *** *  *   ** **    ***** ** *       * * is a prefix of %s",a,b);
*   ** ** *  *  ****  
 ***      *   * ** **   *   *
 **** * *    * **  ** **  
 * * ******* *** *** * *  ***  **  * * *  * ** * * ******  * ***  * *** is not a prefix of %s",a,b);
** ***  **** **  * *   ** ****
 *** ***** ****  **   *****  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * **   * *  * 
#include  ****   ** *    
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 *  **  *  ** ***  i;
** ** * ** * *  * ** * *** * * 
  {
* ** ***** **   **   *   *  *  ** *      A[i]!='\0' && A[i]!=B[i]   )
        ** * ******    *      *  * ***  ******     ** ****** ***  * * ** *  0;
 *  ***   *  * *   ** ***      * * *     *  ***   ** 
  * * **  * *  ** *     ***** **    * **  ** *    **    *** ** ***
  }
 *    **    *    ** 1;
}


int main()
{
*  ***     *** * *         *  a[n],b[n],c[n];
 *****  *****    ****** ** ** i;
********     *        ***   *     ** * * *   ** ** *  
*** ***    ***** **  ** *****   ***  ** *  *  *    *** 
 *  *** ** ****  *** ****     ** (aa(a,b)){
*   ***   ** * * **   *      *  *    ** ***  *  *        **  ** ***
 *   *   *  *  **   * *  * * **** **   * ********** ***   **    ** *   *  *  *  *  * * *    * **   **
******      *****  **   ** * **   *   * * ***  * ***** **    ** *   ** *  **      *** * *   *** *  ** *** **    ** 
 ** * ***** ** *  *  ***** * *  *  **  *** **   * *   ***  ** *  *   *  *** 

 * *  ** *** * **  * **   **** *    *  * *  * **   * * 
       *  *  *   **  *** ******   * ** *   *   *   *  ** **  * * * *****  is a prefix of %s",c,b);
  *  * ******** * * *     ** 
   **  **    *       **
*   **      ** ** * ***   *  **          * *  * ***** * ** *  ***  *  is not a prefix of %s",a,b);
* * * **  * ********    ****** * * **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  ***    ** 
* *  *  ** * * * **** *
int main (){
char  *   *
char *****    **
  * **   * * * string1: *  * *
  * *   ****     * *      *   * 
*    **** * *** string2:  *   
*    **  **        *** 
 ** *   *  **       *
  *** ***** ** * *    * **  *  ***       is  *      *** of **   **      ** * * *
else
** *   * *  *  * *      *** **   ** ***   *   is not prefix of  *     *  ***** **     *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * **   **** * *  
#include * *** *   **** 
#include        * *   * *
#include * * **  *  ** **
int prefix(char p[],char s[])
{
*   * *** ******  ****   *  **  *
 ** **** * ** * **** *****    0;
*  * *    * **  **** ** *  if  *   *   *  ** * *
   * *        ** * ***    ***** 1;
***   *****   *   **  *
* * * ****  **  * *     **   * 0;
}

int main()
{
***    ****   *  **    p[999],s[999];
  **  *  **** *  * *  *  *    * * *    ** *   * **
***  * ***  **** * * *  ** *** * *

 * ** * ** * *** *       
    * *******  ** *  * ** ** *****  is a prefix of %s",p,s);
* ***    **     * ****
 ****    **  **          ***   *    **  is not a prefix of   ******** 

**   * ** *** **  * ****   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * *** ** * ***
int main()
{
*   *  * **  ** * * **  *  *  * length1,length2,c;
    ** ** ***  ** ** *** ** ** * a[100];
  * * *  ** ** **** *    *     * b[100];
   *   ****** **  **   **** *  *  d[100];
* *  **  *   * *    ** *     ****** ***   *** 
  * **** ** *    *** *****  ****  ***  ***** *   
******   **   * ** * * ****** ********
  *  * *    *   ***     * *  *     *** *
if (strcmp(a,d)==0)
**  ***** ** * ** *     *
 * **   *  * * * ******* * *     **     ****** * *  ** ** * is a prefix of %s",a,b);
 ** ***  *   ***      **     ** *
  **** *** *   *  ** ***    **  *** 
* **    ******** ******  **
  **  ** *****  * ***    ******* * *  ***  **  **  ***  *  **** is not a prefix of %s",a,b);
* *   ** *     *    ** ** **  
  *  *   * *  *    **  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  * * 
#include * *  ** * * **  

int prefix (char  * *    str2[])
{
 *** **  ***     *  ** **** length=0,   ****** 
** * * * *   * ***  *  *
 ** *    **  *** * **  ******  * =  * ** ******** * 
   ** ***      *** **  * *
 ** **  *** ** *  * *   ***  ** ** * ******  *
***   ** *** **  * *   * * ** ****** *  *
 **   *   * ** *  ** * *** * ***  if **   *   
* ****  *   ***    *        *      *     *  **** * *   
 *****   **  * * *   * ***  **   *** *   }
* *  *           *    ** ****** ** **
*     **  ****     *   (count == length)
 * ** *   * * ** ** *  ** **  *  *    1;
 *  ** *  ****     *** * * ** ** else **** *  0;   *  **    * ** **   *
**  *  * *   ** ** *** * ***  
}
int main(void)
{
  ** *** ** *    **  ****    *  ***   *
* *  * * **   *  *    *    *** ***
*   *  ** * ********* * * * *****  **   *   * * str1, str2);

 ***** * *  *  *  ** * **   * **    ** ** 
 **    **   {
* *** ** ***  * *        * * ** ** *  ****  * *  *   ** * *   * **     * is a prefix of  *  * * str1, str2);
 * * *  *     **   *  ****
  * *** * *    ** *  *  
*          *       *****  ***  ** *     *** ***    *** * *** **  is not a prefix of **** * ** str1, str2);

 * ** *** * **   ****   ***** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *  *  *  * 
#include  *   *    * **** * 
#include * **  ***  **  

int main()
{
** *  ** * * * * * * *  *** *  *****  prefix[100];
 *  ** *    *   ***** *   ** * ** word[100];
***  ** * ** *    * ** ** ******    %s", prefix, word);
*  * **  **   * * * ***   ** ** i;
** * **  *** *  *  * **    = 0; i< strlen(prefix); ++i)
**  **      *  * **** **** ** * 
*  * *  **  *   *     * * *** * ****  ****  **  ******      ** **** *    
* ***  *  ******      *  *   **** **  ** ** *   
*    **  *  ********    **** **  *** *  *    *  ***    *   * ** ****  ****   ** ****   **  *      is not a prefix of %s", prefix, word);
*  *   * *  * *** *** ***  * *  **   *******  **** ****** * **  ****  **** * ***   0;
**  * **     ** *****  **   * *    ** * * ** ***    * * 
*  ***  ***  *** ** *   *  *  **
**   * * *     **  * *****  * *******  is a prefix of %s", prefix, word);
* *** *  **  *  * * *     ***** *** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *  *  *   
#include * **     *  ** **  * 
#include  *   ******* ***   

int main()
{
** ** **** * *  ***    *   * **   prefix[100];
** * **** *   * ***    ***** * word[100];
*  **  * *  **  *   * * ***  *  *  *  %s", prefix, word);
    * *******    ****** ***   i;
 *      * ******  *** *   ***    = 0; i< strlen(prefix); ++i)
 ***  ****  ***  * **   *     
**   *     * ********  *  **  ***    **** *********** *  * * * *   ** 
 * * *  *****   **    *     * * ** *** *  *  *   *   ****
* *** *   **  ****      *  ** ** **** *   *  * **  *****  * ****     **   **  *  ** **   ********* is not a prefix of %s", prefix, word);
  * ***  **** **  ***    ** * *  ***  * * ** **     ** **  *** ***     *  **  *   **  *** 0;
  ***  ** ***** * ** ****  *  * *  *     * *  *** *   * *** *
   * ***    *** ****   * * 
  **   * * * ** *  *** **  *  *    * ***  **   is a prefix of %s", prefix, word);
 *         ***** **  ** * ***    * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * ****  *  * *
* ***** * * *   ******  *  *
****    *  ** **     *  

int main()
{
 ***    **  * char      **
 *    * ***  char  ** 
* ***  **    *   ** ***  ***  ***  * **   word);
 ** * *   ** *   int i;
   * * * **  ***  for(i = 0; *  *** * *  **  * ++i)
   **   *   ** {
 **** * * **   *** ****  ***** **  ***** *     ** 
** *    **    *** *      *   {
** **  * **** *  ** ** * * * * ** ** ** *  * * * **    * is not a    *  of  ****   *  *** word);
*    ** *** *      *  ***    * * ** *     *  **  0;
   * **  **        *** * * * ** }
    ****  ** * * }
  * * **** *   * ** *     * * * * is a prefix of ** ***   * *  word);
**  * * * ****    *   0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users