1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 * ** * *  * ** **   ****** **
 * ** *  * * ***  *** *  ** **  ***  *** *    *     ** * * 
    {
* ** *    * * *****  ** ***  *  **** * ** *   *   * (i=0; i<=strlen(string2)-1;i++)
*  *** *     * *  ***   *   ** * *   ***      ** * 
  *** ** ** *** ** *     ***  ******** **  * *   **  **  ****     ** *****    *    **  * (string2[i]==string1[i])
**    **  ******   *  ********  * * ****         * * ******* ** **     *       * 
*  **  ** * ****   ****** ** **  *   **    ** ****  * ** **  *  **  *  *  *** **   * *   **   *** ***** **     
     *  * *  ****** **** * *  *****  ****   * *     *    ***    *** *    ***  **   ** * *    
 **  * **  ** *** *  * ***    *** **      *  **     ****
 *   * * *  ****    ** * *    ** *     ***  *   *   * *   * ****
 *  *  *** *   * * * *    *  * * * ****  * **   *    
**  ** **     * *  *   ** * ** **   ** *  *  *** *    ***  * *   *** ** * ** * *  **  ** *    is a prefix of %s", string2, string1);
*     ****    **        * ** ** * **** * *  * * * *     
  * * * * * *   ***  ** *  *   * ** * * *   * * *  
****  ***  **  ***  *** * *******  *  * ** * ** ****   * ** * 
* ** *   **  **  ****  *  ** * **  ** *   *   **       * **    ** ** ** * * **  ******  is not a prefix of %s", string2, string1);
**** * *  *  * *****  *   * **  * * *  * **  * *  ******       *
    }
 ***  *** **  ***  **   * * **   **        *****  *
    {
***  ** **** * **  * **  ** *   * * *********  ** *  ** **** (i=0; i<=strlen(string1)-1;i++)
*** ** *  **   *** **  * **  *  ***   * *** *  
   * **** * * **  ***  * *  ***      *  * **  *   *   * *  * ******* ** * (string2[i]==string1[i])
 *** **   *      ***  * *    * * ***   ** *  ** *    ***   ****  ******  *  **  **
 * * ***   * ** **    **  * ***   ** **    *  ***    **  *** **** * **** *  * ***  ****   ** * *** *  ******* * *
 **** * * *   **  *    ***  * ** *  * ** ** * *  **   *****  * *** * ** **   *** **   **
      *   * ***  * * * ***  *     * ***  * ***     * **  ** 
 ** ***  **  * * **    ** ** **** *   **  * *****   * ***    * 
   *  ** ****   *******  *   * * *** **   * * * *       
* **** * * ***** **   * * *  *  *   *   * *  *    ** ***     **  *   * * * ***    * *  *    * is a prefix of %s", string1, string2);
 **     * *      * **  **  * * **  **  ****   * * 
*  * *  *  *    *   *** *   ****     **  ** ****    **** * 
  ** * ** * **  ***     **    ** *  ***    * * * 
 ****** ** * * *  *  ***  * **** *** *   * * *  * **   **  ********** * *** *  * **  ** *   *** is not a prefix of %s", string1, string2);
*    *  ** ** ***  *  **  ****   *  *   * ******
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
*     *  ** ** ****** *  * **     **  *** * %s", chaine1,chaine2);
  * **  *** * * ***   *     *     **** **
  **  *     ***  **  * **   * *  *  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
     ***  *   **  ***  * * lenght1,lenght2,c;
 **  ***   **** * * * **  *** b[100];
  ***    * * *** * ******* * * a[100];
* *    **      ***    **  ***   d[100];
  *** *******  **** ***   **  *     *   *  ** 
  * ********  *** *  * ** **  *    **  *  *** ***  *
  **  * ******  ******   *  * ******  
 *   **** *** *  ** *   *** *     ***  *
 * *  **** * * ****  *  *   * * * ** 
 *** **  *   * * ** * *  *  **
 *  * ***** ****** ** * * ** * *  *** ***  * *  is a prefix of %s",a,b);
**  *    * **   *   *  **** 
   *     **  *  *** *** ***   *
   **   *   *** * ** * *
*  ** ***  *** *** * * ****  * * *     * **   *    * **  * **  * is not a prefix of %s",a,b);
* * **   * **  *     *     
  ** * * **  *  ****   **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *****   ***  * ** * 
#include *** * * **   *  **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 **** **   ****    i;
 ** *** ****  * *  *** * * **
  {
  **  *** *     *** * * **     ** *****   A[i]!='\0' && A[i]!=B[i]   )
*  *   * * *****   **  * *  **  *      ******   **     * **** 0;
* ****    *  *      *    * ***  * *   ****  *  
**** ** **   ** **  *  * *** *****   ** **  * ** * ** * ** * *** ** *
  }
 ***** * ** *    ***  1;
}


int main()
{
  * **** * * *     *   * * *   ** a[n],b[n],c[n];
***  ***  **  **    *      **  i;
 *** **   ** *       * ***        *     **********
 * * * * * * * * ** * *    *  *** ** *  ****  *    ** 
  *  *** *  ******* *    **** (aa(a,b)){
* ** *   ** **  *       * * * ****  ****** ***   ****  *   ** *** *  *
  ** * *     * ***  **  * **  * *  *  **  **   ******  *  * ** *   ***  ** *       ** **  **
* **   * *   * * ** *  ***  ** * *** ***    **  *  * * ***** ** *     **   ** *    * *   **  *****  *  **   **
*  ***** *   ****  ****** *   ***  *** * **    ***  ** * ******** **  *   

   ****      **** *   * * * *** ***  **    ***  
 * *  **** * **   **  *  *   ***  ******* * ** **   *** *        *     ** is a prefix of %s",c,b);
 **  *   ***    **  *** 
**  ** ** **   * *****   **** 
**        * ***   ** ** **      **   *   * ** *   * ** * ** *   is not a prefix of %s",a,b);
 **** **  *** *** ** * *   * **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **    * * 
*  *   ** ****** ** ** **
int main (){
char *   *  
char **** * **
****  **  ****    string1:      * *
 *  * *** *** ***  ** ** ****** 
*  ** *    * **** string2:        
* ** ****       * ***   *
* ****   *  **   ** * 
** * *   *    ** * * ** *    **       ** is      ***   of  ****   *  *   ** ***  *
else
    * * **   *   ***  **  ** ** ***  * is not prefix of **  ** * **  * * * *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   ****     
#include ** ****** * * *
#include     ** * ***  *
#include * **  ** * **  
int prefix(char p[],char s[])
{
 ** *** ***   *  * * *    * **** ** *    
     * *   ******* **  **** * *   0;
**  ***     * **  **  if ***  ****  **** **  
*** *** **    ****   *    * * ** 1;
* **   **  **  * **** * *
 ** *  * *    ** **    **   *   0;
}

int main()
{
**   * *    ***  *** **   p[999],s[999];
 * * ** * * *    * *  **** *  **  **  ****
*  ** ** ** **   **  *  *  *       * * 

 ** ***   ***** ****** * *   * 
       * *     *** * *   **  * *         * **  is a prefix of %s",p,s);
 ****    ***  *****   **
*  ***** ****  *** *** *  *  *** ***  *  is not a prefix of   * *     ***

* * *  ** *  ******  *  *  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *  **  * *
int main()
{
 * * * ** ***  ******** * * * length1,length2,c;
    *   *   *     *      *      a[100];
* * **** *  *   **    **  b[100];
 *** **  *** * **    ** *  **** * d[100];
*  *  ** * **** * * * ** ** ****    *** ****    **
 *  *  * ** *  * **  ***   * *   * ****** *  
*** **  **** ** ***       * *   **      **
  ** *  * * *     *     * * ****** * 
if (strcmp(a,d)==0)
 * * *   ** **    * ***  
 * *  ** *****    *     *** ****    * *  * *  ** **  ** * *    **   * is a prefix of %s",a,b);
* * ***** * ** **   *  ***
   * * *   * ***   *  *   *   *  *
  **  ***      * ***  *    
* * * **  ****  * ** ***   *   * * * * ******      * ** *   ** *   is not a prefix of %s",a,b);
   **   **    * * * **   **
 *       * * **    0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   **   * * *  *
#include   ** *  *     * 

int prefix (char  * * *** * str2[])
{
* * *  * * *** * **   ***** * length=0, * * **
  * * *   **  * *    
* ** **** **     **** ********* =  **    * ** *** 
*  * **** ** ** ***  * **  *****
***     * **** ******   **      * ** ** *  **
**    *   * ***  * ***   * *      ****** *
*  * * *  *****      **  *  ***    if   *   *  *   
**   * * *    *   **** **         ** **** * ****   * **  
*   **  *** *****   **  * ** *     }
 *  ** *          * **  *     **** 
   *   *   * *  (count == length)
********  * ** ***** * **   *     ** **  1;
  **    ****  *  *  *   *   ** else   * * *      0; *** * ***   *** **  * 
* **    *      ***    *   * 
}
int main(void)
{
  * *   **** *     **  * *   ** *** ** *    * * 
*   **     **  *****  ** ** *  * *
**  ****  *** ** *    ** *    ********  *  *   *** str1, str2);

* ** *   *** *** *        *  * *** * *********
 * ** ***  *    *   {
  * * ***   *     **      ** ***** **    *** *  *  **  ** * *  is a prefix of * ***** * str1, str2);
  ** ** * *** *   *  ***   * *  
* *  *   ****  *    *     ****
  *  ***  ******      * *  **  * ****  *   *  ****  *  * ** **   *  *** is not a prefix of  **  *  *** str1, str2);

***  *   ***    * * *   * * * **** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** *  **   *   *
#include  *   ** * * ** *
#include  *   * ** ****  *

int main()
{
***  *     * * * ******** *   prefix[100];
 *** * ***   * ** **** ******* word[100];
 **     **      *   * *  *    ***** ***  * %s", prefix, word);
  ** *  * *   ****  *   **** i;
 **  ** * ** **  **      *** ** ** = 0; i< strlen(prefix); ++i)
** * **  *  *** ***** * **  * 
* * **   * *** *   *****  **  *    ***   *  **  *** **  * *  *** * *
    ***     *        ****** * ** *   * **   **  ** *  *  
**** * *   *   * *   *       * ** **   **  ** * ***  *  ****  *       * ** ***  ** ********** * **  is not a prefix of %s", prefix, word);
*  **    *** *** **  *** **  *     *  * *  **     ****  * * *   *  * *    * *** *  *  * 0;
 * ***     **  ** *****   **   ***   ******* *  * **
  * **** ** ** * * *      *
* *  *  ** * * **   *  *   **     ** is a prefix of %s", prefix, word);
*** * **  *      **  ****     0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **   * *****  
#include    *  * **   ***** *
#include   ** *    **** 

int main()
{
  * ** ** *** *****    *  ** **   * prefix[100];
** * *   *   **   **  *    * **  word[100];
*  * * *  **  ***** *  *  *   *    * * %s", prefix, word);
   * * ** *** *  *   * *     i;
   *  **  *     ***** ** ** **  = 0; i< strlen(prefix); ++i)
*   *** **  *** *    *       
 ******   * *  ****** ******* **   *****         *  * *** *   **   *  
  * **   * ***** *** **   *     ***       ** ******  *
***   * *    **    * * *    * ***    *  ********  *  ** * * *  **   *****   * ** *  *   *    * ** is not a prefix of %s", prefix, word);
*** ** *  * *   * **    *** ****** *** ******     ******* *      * *  *  *****  0;
* *    ***  *  * * *** * *    **  ** ***     *** * * *  *  
*** ** ** * ********* *  * * **
* * *   * ***  * * **  *  *   *  *  *** is a prefix of %s", prefix, word);
   ***  * ******* *  * ** ***  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* **    *  * * * *** * 
*    *  ***  ** **   **
*  ** *  * * * * * ** *

int main()
{
 **   * *** * char     
 * **   *     * char   **  
****  ***   ****   * *  ** * ** **  * *  word);
           * int i;
 *** ***   **   for(i = 0;    ** *   * ***     ++i)
*    *  *** ** {
**  *  *  ****  *** *      **** *  * *  ** * * 
  ***  * ******   *** *  *    * {
   **   *  *** * ****    *** *   **   **        *  ***  **    is not a  **   of   **** **    ** word);
*  *   *  *  ** ****   *   **** * ***  ** *  ** * 0;
*   * **  *  **    ***  *  **   }
    ***     **  * }
 * *  *      * * *  ** *** * *  is a prefix of * **     * word);
*** *         *** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 21.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 19.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users