1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
** *   **  ***   * *    * * ** * 
**   *  * **  ** **** ***   ** *  * ***  *** *     ***  
    {
** * ** *** *    *   *   ** *   * **  **   *** *  (i=0; i<=strlen(string2)-1;i++)
*** **   * ** **  ** ***     ***** * * *  ** *   
 **  * *  *   * *  ** **** *     * ** **  *** ***** * ********* ******  ** **  ***** * **** * (string2[i]==string1[i])
** *  *    * *  **         *   *** *  **     * ** *  *  * * *****    * **  * 
 * * *  *  ** ** ****  *  ** * * *  ** ** ********  *  *********  *** **     ** * **    ***** ** * **   ** * **   
    **    *   ***  *  ****** *** ****** *   **** * **   *  **** ** ** *   * * *  ** *
* *  *   **  * *** * *    ** *** **      **  *   ********  *  *
** ****  * *   *  ** ***  * *  * *   *** **  * **  * **  * *  * *  *
**   *    * ** *****  * *** *  **** **** *** *  **   **  **
* *   **  *** *   * **  **** ******** *       * *    **  * ***   ***     *   ****   ***** is a prefix of %s", string2, string1);
*  *   **  * ** *   ***  ** *   **  ****  *   *****  *  * * * *
* ** ** *     *** *  ** *** *  *  * * ***  *** *   *  ** 
*  *  **  ******* ***   ** *  **   * **    *     *** ** **   
   *    ***  * **** *** *** *      **** *  *    ******  * **  *** *  *  * * **** ** ** * *****    is not a prefix of %s", string2, string1);
*    * * *  ** **  * ** * * * *        *    *  *   ** 
    }
* ****    **  ***  * * * *****  *  * * **   * ** * ***
    {
**  * ** **  **   **** *       **  *  * *  ****** *  *   * *    *  (i=0; i<=strlen(string1)-1;i++)
  *   *  ******  ***** * * ** ** ** *     *** * *  * ******
 * ***  **    *     * **  * ***   * * *    *****   * *   * **** *  *  **** (string2[i]==string1[i])
***** ****** *     **** ***   **   * **   *    * **   ***   * **  ***  *   
   ****  **  *  *  *    ** *  **       * *  ** * *  *  ***  *  * ***  ** * ** *  ***    ** ** **** *   **  *** *
  *   * * **** ** *      ****  ** **** * * **      * *  ** **      ** * * * *******  ****
** * *  **  **  *   ***   * * * * *** * ** ** *    *****  
**   ***  **  * *   * *  *            * ** ***  **     * *  ** 
 ** ***  **   *  **** * *  *   **    * ** * ** ** * * 
***   ***   ****       ***   ** *   ***  ** **   *  *  *** ** **    ** * * *  ***  *** *** ** is a prefix of %s", string1, string2);
*** ****** ** ********* ***** ******    ***   * **  *
** ****** **  * *****  *** **     **  **    **  * 
   **  **   *   ** * **** * *  *  * *  * * ***** **
*** ** ***   * *  *  * *****    * * * ******* *  *   *  ***  * * *** ** ****  *****   * *    * is not a prefix of %s", string1, string2);
******* ** ****    *      *  ****    * ***   ** *  * * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* *** ***  * * ***   * *   * **  *  *     %s", chaine1,chaine2);
* *  **** * ** * * *****  *** * *  ** *** 
 *  **       ** *    ***   *   * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**** **      *       *****  lenght1,lenght2,c;
 * **** ***   * **    * * *  b[100];
** * *****    ** * ** * ****  ***  a[100];
*** *   * **  *           **  d[100];
** ** *  * **    * * *   ***  *  ***  * * *   *    *
 *    *  *** *   *   * **  * *   *   *  **    ** **
*  ********   *   *   ** * * ** ***** ***
* ****  * ***  ***     *   *****  ******* * ** 
     * *  * **  **  * **** **   *     
**  * **** *******  ***   
* *  * *** **  **** *   ***   * * ** *     * * **** * is a prefix of %s",a,b);
 **  *** ** *     *     * **
**    ** *   **** * *  *  *
****    ** ***  * * **  **   *
*     **  * ****   **  * **** *   *  *  * *   **        ** **  ** ** is not a prefix of %s",a,b);
  * ** * *** ****   **     
*    ** * **  *  * *** ***** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   ****** *  *  
#include  *  *    ** *     *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 *** **  *      ** i;
*  ****** ** *   *  *    ** **
  {
  * * * ** ***  **** * * **** * * *** *  * **  A[i]!='\0' && A[i]!=B[i]   )
 *     * * ** *  **** * * ** * ** **** **  **   *** * **** ** **  ***  **   0;
* ***** *  * * ** * *    *  * * * *    ***     *    *  
**** **  ** *  *** ***  ** ********  * **  *    ***  * * ***     * * *   ***
  }
 *  *******  *  1;
}


int main()
{
 *    * * * *    ******* *      a[n],b[n],c[n];
*** * * * *****   * *  *** **** i;
* **  **       *    * ** * *  * ** * *  ** **
** *** **     ****  * ****   * *        *** *  * 
 *  ** * *   **** * * **     (aa(a,b)){
  *  * *** * **       *** * **  **     **   ****** *   *    * ***   *** *
**   ** **        * **** * * * ****  *   *  * *  * *  ** * *  *   ***  *** ** *   * * *
** *****  *   * *    *    **   *   *** * *  **** ***** *** * *   * * * * *** * **  * **    *** **   ** *    * ****  *  
   *** * **  **** *  ** *** *****  **  *       **  * ** *** ****** **  ** *

**     ******* * * * *     * **   ** * **** * * ** * * **
** ****** *  **** *   **   *** ** ******  ****   * ***  * *     *   * **** * is a prefix of %s",c,b);
******  * ***  *   ***   
** * **  * *** ** **  ***  * ***
* *  * *     ******** **  * *   ** *****  ****  * *****    * *   *  is not a prefix of %s",a,b);
*  * ** * * * *   ****      0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    **  ** *  
*   *  *      *   ** 
int main (){
char  *   * **
char     *    
 ** ***  *  *   string1:    ** 
**   *   ** ** *  **  * * **  * * 
 *    **   *  *  string2: *  *    
  *  ***     * **  **  * 
 **  ** *********  
 *** ***** **** * * * *    ** *  * **     is    * *  *  of  *** *  *   *   *** 
else
   * *     ****** ****   **      *  *** is not prefix of  *** **** **   ** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ***  * *  * ***
#include *  * ** * *  *
#include ***** ***** * ** **
#include   ** *** *******
int prefix(char p[],char s[])
{
 ** *      * *  * *   * ***  **  * * ** *   
* *    ** *  **** *   **       0;
 *      * **  * *  if  *  *  *  * *   *
* **    *  * *   **  *****   *  1;
*       **  ***  * * * 
** * **   ***  ** *** *** * *   0;
}

int main()
{
 * *** *     * * * * ** p[999],s[999];
 *****     * ****  *  * * **     * 
* * ***    *  * * **  ***** **** * 

   ** *     *******      **    
  ***  * ** * *   ***  **  ****     * *  is a prefix of %s",p,s);
**   **    * **    
 *   **  * *  *  **** ****   * * is not a prefix of * **** ** **  

**  *  * **  * **     **  ** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *   **     * ** ***   
int main()
{
   *   ***   **    ***** * length1,length2,c;
    *   ***   *******  **** *  a[100];
*  * *****          *   *  *  b[100];
**** * * ***  * *** **** **** d[100];
** *  *    ** *   **  ***   *      **  ****
* *  **  *  * ***     ** *   * *   ** * *  *  
  * **  * * * ***        *** **  * *     *
    *    *    *  *** *    *    ***   * *
if (strcmp(a,d)==0)
 *** *  *   * ***   *   **
  * ******    *** *    *****   **  ** *** *   **** ****  ***  ***  is a prefix of %s",a,b);
  *** * ** *  ** * **   * **  *  **
  **  * *** *  **    ** **  *   
  ** *      **  *** ***  * * *
 *****  ***     *  *           * * * *  *  * *   *  *  *** **  * **  is not a prefix of %s",a,b);
    *** **  *  *  * 
* * *  *  *      *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *** * * ** *
#include  ***  *      * ***

int prefix (char **    *** * str2[])
{
*** * *  **  *******   * * length=0, * *  * *
  ** *****  *  ** *  
 *  *  ** * * * *** **  ** * * = ** ** **   
*  *   * ***          *  
  * ** * ** *****    **  *   * ****  **   
 * * *  **** *    **      ****   ** *         
  * **    **   **   *  * *   *** * if     *  *** 
*  *  *     * *    *         *   **    **  ** * **    
**    *** * * ** ******   * * *     }
** *** *          *   * ** *  * *       ***
* ** *     *   *  **    * **  (count == length)
   ****  ** *  *    * *  *** *   * ***  ** 1;
*** *** **     *   *  *    * ** else ****    *** * 0; *** *   * ****** 
*****   *   *    *** *   *  *  * 
}
int main(void)
{
   * * ** *** **  **  * ** **  * * *   *  
*****  ******   * *    **   * 
 ***   *  **  *    * **** ** *    ** **   **   * ** str1, str2);

**** * *  * ** ***   *  *  ***   *  **    * 
* *  *     ** *      {
* **** * ** *   *  *     **  *  ** ***    ***** *  *  * *  *  ****    is a prefix of  **  *** str1, str2);
*   *** ** *  *  *  ** **** *    
    * **  * **  *    * ***** *** 
* *    *   *  *  **    *   ***   ***  *** **** *  * ** * ** *   *******  is not a prefix of * *  *  str1, str2);

** ** * * * ** **  ******    * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * **  **  ** 
#include  ** * ***** *  * ***
#include *   ** *** **   **

int main()
{
  *   ****  ***  *      * * prefix[100];
*** ***  * * **     *****     word[100];
 **  *  *  ** *  *   *   **** * ****** %s", prefix, word);
* * * * * * ** ** *   * **** **  i;
 **  *****  ***      * * *****   = 0; i< strlen(prefix); ++i)
*  *   *** **  ** ** **  *  *  *
  *  * **     ** *  * * *       *** **  ***   *  *  *   **     *** **  *
      *   ** * *** *  *  **     * *** *  * * *  ** *   ** 
**  **   *  ** *    *   * ** *  *  ** ****  * * *  * * ***** ********  **  **    *** * ** **  ** *  * **** is not a prefix of %s", prefix, word);
* *** ***   * * * *** *  * *    * **         *  *   *  ** *** * * ***** *  ****  0;
    *     ** *   *   * *    ***   **    * *** ***
  **  **** * *** ** ***  **    
* **  ** * ** **** * *  * * *   * *** **  is a prefix of %s", prefix, word);
*  *  ******  *  * * * ** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** * *   ***  
#include *   *** ** * 
#include   * * *   ***  * 

int main()
{
* *** * * * *   ** ** ***** *  prefix[100];
**** ** ** ** * *  ** * *****  word[100];
  **** ** ****   **    ****     *  * %s", prefix, word);
***   * ** *   *   **     *   * i;
 ****     **** **      * * ** = 0; i< strlen(prefix); ++i)
** *   *** *  **  ***** ***
 * * *   * *  * ** ** * * ***      * **   **      ***  * ** *    
*   *  *       *     * **  ****  ****   *   **** *  *
 ** * * *** *   * **  **  * ** * ***** **  * *   *     ****   *** * *  *  ***  * * **** * ** *** is not a prefix of %s", prefix, word);
*****     *  **    *       ** **   ** ***  * ** ** **** * *** *   * * *      0;
  ******  * *    **  ** ***   ***   *   ** 
* * **  ***    **   **** 
   ** *  ***   *   * *  ** *    **** is a prefix of %s", prefix, word);
   ******* * * **    *** ***  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** *** *    ****  ***
*    *        *  *   * 
***     *  *    *   * **

int main()
{
* *    * ** **  * char *  *** 
 * * * *  *  *  * char * * ***  
  * *    * **   *    *  * **     * *  ***  * *   word);
   *  * **   ** int i;
   ** * **   ** for(i = 0;   ****     *  *  ++i)
* *        {
  * **  *       * *  * * **  ** ***     
 ** * * **  **  *  *  *  ***    *   * {
 ** *  *      **  * *   ** *      * ** *  *  * **   is not a  ** of   ***   ** *  word);
 * ** **     *** ***  *  ****    *    ** * **   **  0;
*  * **     **    * **   **   * }
**** *  **    ** }
 ** * * ***     *   * is a prefix of  ** * *  ******* word);
* ** *  **   *  *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 14.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users