1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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{
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}
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#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include **    *   *  
#include   *   *   **    * ***
//#include <ctype.h>
#define n 100
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}
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Hidden content!
#include *  *  **** ** **** 
* *****  *   ** * *****
int main (){
char ****** 
char   * ** **
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include * ** **      ****  *  
#include   *    ***  *
#include   **  *    **
#include  ** *    ****   
int prefix(char p[],char s[])
{
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   * *  **      ** *  **   0;
}
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#include <stdio.h>
#include *    ** *     *
int main()
{
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}
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Hidden content!
#include    ***  *   **
#include *  *    *** * *  *

int prefix (char  **** ** str2[])
{
  ***   *  *  *** *  *    length=0,   *  ***
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  **  ****** * * ******     *** 0;
}
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#include *   ** * **   **  
#include *  ** **** *  
#include  * *   ***  **

int main()
{
**  * **** * * * * **  *    ** prefix[100];
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**  * ** *** * * ******  * 
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 ***  **   ****   ** *    *** ***  * * ** * *  *** *  ** *  
**    ** * *  *     * * *
***   * *    ****** **   * *  * * **     * is a prefix of %s", prefix, word);
*  * *    * ** *    * * *** * 0;
}
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Hidden content!
#include ***  **  *       
#include ** *   * ***  
#include  * ** ** * **  ***

int main()
{
  * *  * **  * *  *****  prefix[100];
**   * *** * *  * *   word[100];
 *****  ********     ***     * * ***  %s", prefix, word);
 ** ** * *  *******   *** *** i;
 ** * *    ** * *** **    *  **** = 0; i< strlen(prefix); ++i)
   * ** ***     * ** ** 
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 * * ***  ***    *    * **
  * *  *  ***  *     * ** *  **** ****  is a prefix of %s", prefix, word);
* ***      ***  * *** * **   * * 0;
}
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*           **** *   
    * * * * *  * **
 * **    *** *  *   * *

int main()
{
**  *  ** *     char  **** * 
***  *    *    char *  ** 
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** *  * **   **  *** **     *  *   * ***   *  **  *    is not a * *** of      *   *  ** word);
     ** * **      ** *    *** **  ** * *     *    0;
** *** **  ***   *     * *  }
 * *    ***** }
*   * *     **  **  **  *** * is a prefix of  **  *  word);
********  ** ** * ** 0;
}
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