1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*   * ** *  * **** * * **     **  **
 ****   * ****   * *** *** * * *     *      *** *     
    {
****     ***** * ***  ** ** * * * * * *  *   ** *    *   *    (i=0; i<=strlen(string2)-1;i++)
 **   *  ** * **   *      * *   *  * ** * **  *     **  
**  *****  **** ***  ***  ***** **  ******* ****** ***  **  * **** ** * ** *  * * (string2[i]==string1[i])
 ** ** * ***** ** ***   * ***   **    *** *   ****    ** **  *   * * ** * **  ***
  **  *     *** ***   * **      *    *    * *       *******   * ** **    *****  * *   * * *  **    * *  *   
**   ** * *  *** * ****  *  *  *   * **     * **     * **** *  *  *** *  *   *   *** **  * 
 **** * *    *** **** ** **  ****   * **** ****    **** 
 *  ** * **     **** *    *  * ** ** *     ***  * *  **   * *  *  
 *   *    *   *  **** * *    *** ****    * **    ****    
   *** **    * **  * ***       *  ****   *  ** *  ** **   *   * ***   * ** * *  *    * is a prefix of %s", string2, string1);
    ****   * ** * *  *** ***** *****     *  **********  * * 
******** *** *   * *  * ********* ***  *   ***** *      *
* ***** *      *** *  ***  *  ** **** *** **      *** 
** * ** ******   **** * **  *   * *  **** ******    *    *    **        **  ** *  *** ***  *  is not a prefix of %s", string2, string1);
 ***  *  ** *  **  * *   **** **** ** *  *  ** ** ****** 
    }
 *    ****** * **  *   ** *   **  * ** ** *    **** 
    {
  ** *  *****  ** **  ******** *   * * ** ***   *  *  (i=0; i<=strlen(string1)-1;i++)
*  *            ** ** *    * *  ** ** **   *     *  * * 
 *      * * **  *   * *** **  **       * ** *  *  ***   *  *   *  * ** * *    *   *** (string2[i]==string1[i])
***   *       * *   * * *    * *   *   * **  ** ****  ** **** *   *** **** **** *     
  ** *** **  ** *  ** * * *  *         ***** * ***** * ** * **        ** * *** **   *****    *  * **** *
* * * ****  *  **   *     **     * *** *   *   ** *   **  **  * **** * * 
* * *****   *  * ** **  *    *      *  **   * * * **   
 * ********* * ****** * ** ** * * **** * *      ** **   **
** *  **     ***  * **  * **      * * * * **      * *
* * *** ****** * *  *   ***  * ** * ***  ******  **** * *         * * * * *  *   **   *****   is a prefix of %s", string1, string2);
 *    * ** *  *** * * ***** ****   * ****   *** ** ** ***
  * *  *****  **  ** **    * *   * **      ** ** ** ***   **
 *  ** *            *** **   *  *  * *** * * ***  **
 *    * ** ** *   *****  **  ****   * * * **** ***   ***** *** *  *   ***** *  ***  * * *  * * is not a prefix of %s", string1, string2);
  *** ******   * * *   * * ***    **** **  * **
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 **    * **   * **  ** *     *  **   *  * ** %s", chaine1,chaine2);
 **  **    * *      * * * *  **     *  *
* ***     **** **     *  * *  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   ****   * * *   ***  *    ** lenght1,lenght2,c;
* **  ** *  * *  ** ** ** b[100];
* * *    **   **  **** *** *  a[100];
* **** *  * *****      *  *** d[100];
** **  *** **    ** *   *  **    *  *     *
***   *  ** ****  **  ****  *    **       *  
  *********** *** *  *        *    **
  **  * ****   *  *    * * *  ***  *** **  *
 *******  **   **  **  *** * *   
** ***  * * *  *  **  * *
*** *   ***  ***    **  ** ****  *       *  *        is a prefix of %s",a,b);
*       ** ***    ** ** * 
   ** *  * ** **** *  *  
***** * **** *** * ***   **   ** *
** * *     ****    ** *   ** ***  *** *   * ****  * *** **** **** * * ** is not a prefix of %s",a,b);
** **    * ****    * *   *
  *    ****** **  *****   *  **  *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **  ***** * *  
#include     * * * * ***
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*            **  i;
***    * *    *** *   *     
  {
*    *  *   * **  * ***** *  **** ** **  A[i]!='\0' && A[i]!=B[i]   )
  *  * *   *      ****   **** **  * * *    ** * *** * *   *   * ** *  0;
*  *** *  ******     **  * *  **** * * ** * *** * *  * 
 *  ** * ** * * **    *  * ****      ***   *** * * * *   **  *** *** *
  }
  ***   *      *   1;
}


int main()
{
 **   *  * ** * * * * ** a[n],b[n],c[n];
 * *  *  ****** *  ******* *    i;
 * * ** ***  ** **     * ** * *   * ** *** ***  
* * **  * *   ** * *   ** ***   ****** *  **** 
* * ****** **  *** ******  * **** (aa(a,b)){
********** ***  ** *       **   * ** ** *******   *     ****  * * ** **
       ***  *** * ******        **  **    ****    ****    *   **** ** ***   *   * ***    * *  
 * * **  * *  **    * *****    *     * ** ***  ** ** *   **  ** *   **  ** *   ***  *   * * *  *  *** **   ***  * * * **** 
*  ** * * *****    ** *     **  *    * *  *** *       **   *  *   **** **  ***** ***  *

*    * ****  *  * * *   *  ** **        *** ***    ***   *
* ***    ** **  * *  **  *  * * ** *  **   *  * ****** * **  ***  * * ** is a prefix of %s",c,b);
 * ** ****   *  ****  ***  **  **
 * *  *** *** *  ** ***  * **
**  ** *   * *    ** *  * **      * *** *** * *** * ****      **  * *** *  is not a prefix of %s",a,b);
  *  * ***     **       * ****   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * *  ***  * 
**    ***     ** *   *   
int main (){
char  ** * * * 
char **   
**    **     *   string1:     ***
****    ***  * *   *** *** *  *
  *   *  **  * string2:      **
     *  ** * *  * **  * *** 
 * ***  ****   *   *
 * *  *   **   **   ***       **  is    ***     of **    ****** * 
else
* ** **** *** * ***  * *  *  ***     **  *  is not prefix of * *  * ** *  * ***  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * * ***   *
#include      *     *
#include ** * ** *  *  
#include    **  *     * ** 
int prefix(char p[],char s[])
{
* *  *     *  *** **   *  * **  *  * *   
 *** * ***  *** ***   ** * * * ** * 0;
 ***  *  *     ***  *  if       *  *  **   * 
 ** * *  ** * * *   * * *** ** * 1;
* **    ** **  * ** * *
**   * ****   **  **  * ***  0;
}

int main()
{
* *****      * *  ***  * * * p[999],s[999];
 *  *  *** **       * * * ***    **** **  * **  
 **  ***    *  *      **  ******  ** * * ** * **

***  *** **   * * *      *  *  
****   *   *      **** *  * ** *  is a prefix of %s",p,s);
  *      *   **  *** * 
*** **  * * ***   *** ** **   * * ***  *  * is not a prefix of  * *  * *  * 

 *** ** ** ****    ** * * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** **  *   * * *  
int main()
{
***    * **  **  *  **** *  *  length1,length2,c;
 *    * *      ******** * ** *** a[100];
 ****  *  * **** *** *  **   b[100];
       **  *** *   * **** *** ** d[100];
   *  **  *   *  ** * **   * * ****   *   * **   *** 
     *   ******  *** *** *  ** **   ********   ***
 * ** * * *****      *  ** * *   **    
   **  * * ***** ** *   *****  * * *  ***
if (strcmp(a,d)==0)
**    *  **   * *** *   *
   ***  * **    ****  ***  *    **** **  ***   **    *****  is a prefix of %s",a,b);
*  ***** ********  *** **
**  ******   **   * *    * 
* ** **  *** *** *  **** 
**   ****    ** **** **** **** *  ***    **  * ** *  *   ** *** *  * is not a prefix of %s",a,b);
*  ** * ** ***** *    **    
  ** * **  *   * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** *  *  
#include  *  *  *     ** **

int prefix (char  * **     str2[])
{
***** * * ****  * *   *     * length=0,    ** 
 * ****   ** ******
******  ** *  ** * ** * *     =  *  *  *  * ***
* *  *  * *  **       *** *
***   * ** * *   * *  **  **   * *  * * * *  ** * 
  * ** ***  *  *  **   *  *  *** **   **
* * *  *  **  *   * **  **   if *** ** **** 
 ** ****   *    *    ***   *       *    ****** *  * ***     *  
 ********* **     * *  *   *****    }
**   ***          *** *  ***   *    
 * *** *   **   **   (count == length)
***   * *   * * *** **  **  *  ** ** * * **  ** 1;
* *  *  ***   ***** *  * * ***  else  ******     0;       **       * **
  * **  *   *** *    * *    **  *  
}
int main(void)
{
**   *  * **   * *   *  **   *** ***    * * *
 *  ***        * ** * * * **
  *** * ** *   ** *  * ** *** *** * **** * *         str1, str2);

 ** **      * *   * *    *        **** ****  
* *  ***** **   **   {
  ******   *  *  ** *   *    *** *    ** * *** *  * ******   * *  is a prefix of **** * * str1, str2);
 *     *  ** *  **** ***  * * 
*     *** * *** *    *   * ** 
  * *  ** * * ** **  * *  ** *  *** * *  *    **    *   *** is not a prefix of   **    * str1, str2);

****  * *  ***** *      *  ***   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ********* *****
#include **  *  *** *  
#include * ** **  ** *   

int main()
{
* *  *    * **    ** *  *  *  prefix[100];
** *****        *** ***** * *     word[100];
** **    ** * **   *     * * ***       * ** * %s", prefix, word);
 ** *  * **    *  *   **    *   i;
  *** **    * * **** *    **** = 0; i< strlen(prefix); ++i)
***** **  * ** ** * * * **  **
*    ***   *****   * ***  ** * *****     * **** * *** ** *** **  ** 
*     *  *   *  ***  * *  *  ***  * *  ** ** **   * **   
    *   *     * ***   * * **  * *** *       ** ** ****   * ** ****   * * * **    *  **   ****   ***** is not a prefix of %s", prefix, word);
 *  *  *   ***     **    ** *  * * **    **  **  * ***** **   *** *  *  *  * **  * ** **    ** * 0;
 * *  ** *** *      *  ****  *   *    **    ***       ***** 
**  **  **  * ** **   * **
 ** * **** *** * **    * * ***     ** **  is a prefix of %s", prefix, word);
  **    * **** ****          * *  ** * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***** *  *** 
#include     ***   *  **   
#include * *     ***  ** *

int main()
{
  *  *     * **   * *  *      * prefix[100];
 ***** **    * ******   * **** word[100];
   * *  *   *  * **   * *    ***  *** ** %s", prefix, word);
 * **  *   *   ** *    *    *   i;
* **** *    ****** ** *** * * = 0; i< strlen(prefix); ++i)
*  * ** **     * *    * *    
 ** *  * *    *** ****     *     **** * ** ** *** ********     **
*   * **    * *    *       *  * ***  *  * * * *    **   ** 
   *****  *  *    *   *****  *  *** ** * *    * *  **   *  *  **     * ****** ** ****   is not a prefix of %s", prefix, word);
 **  * * * ** ** ****** *   *    *      **   **    ** ** ****  ** * **  * **   ***     * *     * 0;
 *** * *   **  * *  **    **       * * * *  * ** *       
   ** *****  * ***  * *****    
* **  * *     * *** **** ** *  *** ** is a prefix of %s", prefix, word);
* ****      *   ***  * * * * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   **   *******   * *
* * *******      *  *  
  *      *   **  * *

int main()
{
 * * ***        *** char   ***   **
*  *   *  *** * * char **** 
* *  **    *     **  ****  *  ** * *** ** *       word);
***        *  * int i;
    * **  * for(i = 0; *  * * **    ** *  ++i)
 ***       * **  {
** *   *  *   *  *** **   * ** *  *  ** * **
   **  *   ** * ** *  *     * *   * {
***** ** * *  *  ** **   ***  *   *   *    * * * **** ***** is not a   **  of *** ***  **** word);
** *      ** * *  ** * ** ** ** * * ** *  ** * **   **  0;
*     ** *  * ** * ** *     **** * }
*     ***  * *  }
 ***  *  * ****     ***** *   is a prefix of ** *      *** word);
 *     *  **     *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.234
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users