1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
****  **  *   * *****  *
 ****  * *   **** * *     ** **   ** *     **   *  *  *** *   
    {
**     ***      * *     *   *   **  *  *** *    * ***  * (i=0; i<=strlen(string2)-1;i++)
*  *   *  *** *  *  ****  **** ** *  ** **    **
 * * *  *  ** *  ***** *  *  *   * ** *** * ***   **    *** ** ** ** ******** *  **  (string2[i]==string1[i])
*   *** * * ****    *** *  **** **     ******** *  ** * * ** **** * * ** * **  *   *    
*     **    *    * *   *  **   *  ** * ** *  * ** *  *** ** ******* * **   ** **         **  *** * **  ** **
    *   * *   *    ** ****  ***  ** **   * ***     *** *     * *******   * 
 * *  *  *  * * * *   **   **** *   * *   *  *  *** *
**** **   *  *  *  ***** * *  ** ** *   ** ** ** *   *   **  **   
  ***     ** **  * * *** ****  **      * **  *   * *******
**   ** *** ** **  **  *  *  ** * ** * *     *   ***   ** * * *** **    ** *  ** ***  **    * is a prefix of %s", string2, string1);
* * * *  **  ** ***  **  ** *  *   *  *   * **** ** ** *** *
* * ******  ***** * *** **  **      * **** ***** * *    * 
** *  ** *  *  *  ** * ** ** **  *   * **  * 
* **  **** *   ***  *** ***  * ***  ** **  ** **   *     ** **** *   *****  *   *  *   *  * *** is not a prefix of %s", string2, string1);
  **   ****  *** **** ** ***** *  *  ** * *     ****  *
    }
**    **  * ****   ** *   ** **  *   ** **  *     ** * * * ****
    {
  *** *** *   * *  ***  * **** * * **   *  *  **  *  *    (i=0; i<=strlen(string1)-1;i++)
 **    ** **  *  ** ***  **** *  ***  ******  ***
*       *** * ** *** ***    *  ** * *  *  * *  *** * ** * *  *  * **  * *******  *  (string2[i]==string1[i])
** ******** * * *** * *  * ** *   **** *  * * *  ******  *  * *** * ** ****  
  *  * ***  **  ******  *  * *  * * * * * *** * *     *** *  **  **  **  ***** *    *   *  ***** *  ***    *  **** 
  * * *  * *  * *  **   *   *  *  * ** ** *  * ***    ***** *  *   ***  * *
  *     *  **  * *****  **  **  ***  *  *    *** **** * **
***   * * * **  *  * *  ***   *  * *   *   ** *  ** ****
** ********* **  ** *  *   ** *   * * **  *** *   *    ** 
* * *  ** *  ***  ***  ** ** *          ******* * * ** **   *  *  **  * **  **** * ***  **   * **   *   is a prefix of %s", string1, string2);
    *****  * *   * *        *  **  ****    **   **   * ** 
 * * * *    *  * ****  ***   ** *** * *  ****     *    **   
* *  *  *  *** *  **   * ** *     * *** *  ***    * **
     * * *   * * * **  *   *     *   *   **** ** *** * *  *  * *    **    *   ** *** * * * is not a prefix of %s", string1, string2);
   * *  ***  *  * *   *   * **  * *** *  *  * ** ****  
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 * ** *  * ** **  ** **  *** *  *  ** ** * %s", chaine1,chaine2);
*****       ** ***   * *****  *    * *  * *
**        *  *  * *  * *    **  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
* *   ** * ** ****   * ** *  *  lenght1,lenght2,c;
* ** **    *  * * *     * * b[100];
***** **   * *** *   *****  ** a[100];
***   ** ****** ** **  ******    d[100];
**   * ***** *** *  ** *   * * *     ** ** *  ***
*  ** *  ** ** **    * *** **  *  **   *  *** * * * *
    *  *** **    ***** *  *   *  ****
 ** * *   ***  * *  * *** *    **  
  *   *  ***   * * ***  *    **** * ***  
   *   * *** ** *** ** *    *  *
  ** * ** * ***  * *       *    *****  * *  ****** * is a prefix of %s",a,b);
**   **** * *** **** * *
*   * * ****  ** *  ** *   * *
*****   *  ******  ***  ** 
* * *      *   **        ** **  **    *     * *  ** * *  * * ***  *** is not a prefix of %s",a,b);
**  * *    ** * ** ** * **  
******** *      *      * ***   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** * *** * **   ** 
#include  ** **** **  ** ** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*   **  *  *** *   i;
  *  *    ** ***    ***   ** 
  {
*** ***** **  * *   *  **   * *  ** ***  ***  A[i]!='\0' && A[i]!=B[i]   )
   *  *    *   ***  ***    *   *** *  * ** ***   *    ** *   *      *  **  * 0;
* *  * **  *  **** * **   * * **  * * * * *** * * * **  
   *** *    *** *  *** ****  * **     **** ** *    * ****    *** *   *  
  }
* * *      ** **   1;
}


int main()
{
 *** * ***  * **   ***  *   **    a[n],b[n],c[n];
*  *  **   * **** **  * *** * * *  i;
  * **   * *** ** **  *  *   *******  * **  *    
**  **  ** *      *   ***  **** *   *  **  *  * 
 *   **** ** *  ** *   * * * (aa(a,b)){
*   **   * * **** *  ** *** * **    * *  * ***  ** ** ****  *  *  * 
 * * * * * *  **  ***    *******    *  **  *   ** * **** *   *** * ** ** *** * * 
 *  *   **   **   ** *           ******  * * ** ** *****   ****    * *   **** * * * ****  ****   ***** ** ****** **    *  * 
  * *** *     ** **    * * ** ** * * **   ***   * *  *   * * **  * * * ** **** *

* ****   **    *** ***  * * *    * *  ** * ** ** **      
  * *    ** **      ** ** ** ***   ** * *  ***     *   ** **  is a prefix of %s",c,b);
*   ***  *****   *  * * ***     
**  *  **   *  ** *  ****** *** 
*** ** ****     * ***   ***  *   ***  *  *  **   *  * *    is not a prefix of %s",a,b);
 ***  * ****     *   **** * ***  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      * ***  ** ** 
** ** ****** ** **     
int main (){
char   **   **
char     * **  
**     *  *  *  ** string1:  *  
*   * ** ** * **   *  *** * 
***  *    string2:      ***
 * * * *** *  ** *   *** **
*     * ***   ** * *** 
  ** * *     *   * * **  **  * * is *   *** ** of  ***   ****  **   *****
else
* **    *   **  ***  ***** **     *** **    is not prefix of  ****  **  *  ***** ****

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    * *** *     *
#include    *    ***    **
#include * ** *   **   * 
#include  ***  * *  ** ** 
int prefix(char p[],char s[])
{
   ** ***   ***** ***** ******** *
**  **   ** ****** *   ***   ***  0;
** * ****** *  ***     * if  ***   * ***  * * 
  ***        * ** *   *  ** *    ** 1;
* ******  ** * ** * ***
 *   *  ** ****      *  ***   **   0;
}

int main()
{
* **   **** * **    * ***   p[999],s[999];
    **  ***** ** ***  * * ** ***    *** 
************* * **   *     *     * * *** **  *** 

* * **  ***  * *  * **  *   *  *
 * *  ***   *  *  * *    *   *   is a prefix of %s",p,s);
******** **** **  ** * * 
 * ***  *   ***  **  ***        **  *  * ** is not a prefix of   *  * *   *

 *** **  * *** ** * *   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  *****    ** ***
int main()
{
    * *****  * * *   ** **  *** * * length1,length2,c;
** **   ** * *   *  *       **   a[100];
*   ** *  *   *   ***   *****   b[100];
 * *    *  ** ***** * **  *     *  d[100];
 *    **** * ***** *  **     * * ** * * * * *** *** 
** *  **** *  ****** ** ** * **   ******   * ***
* * **** * ****  *    *  ***   * *  **  
* ** ***** * *  * * **  *****   *   *    *
if (strcmp(a,d)==0)
   ** * *  ** **  * *  * **
* * * **    * *  *  *** *  *******   ***    ***   * ****** * *  is a prefix of %s",a,b);
  * * * ****  *   *    *    
**    **** ** ****** ** **   *
** * *  *   **  * *  * *    *  **  
* *   *** ** ** * ***** ** * * **  *** ***  *     * ******           * is not a prefix of %s",a,b);
*  ****  *   *** *  **  
* *  * * *  *      * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *   *    *** 
#include *   *   ** ** *  

int prefix (char **** ** str2[])
{
   ** ** **  **   *   **  ** *    length=0, *    **
   *  ****   *  *
**** ** * * * *   ** * *** ** = *** *** ***** 
* ***** *** *    *** * *
  **** *** *    ***  * **** *   ** *** **  ** *
*  * * * * * **  * ** * ******    **   ***
   *****    ***  * **    * **  ** if   ** **       
*  *****     ***   *        ** * * * * **    **** *  *  
*   **  ** ****** *** * *  *  *  **     }
 * * *          **  * **** * * **  
*   * * *  *  **** * ***** *** (count == length)
*   * *  * *       *  **   *   ***  *  1;
 * *  *  ********  **  ** else  * *   ***** 0;     *    *  ***
* *  ****  ***  *  * * ***  *   
}
int main(void)
{
  *** * ***** **  *  ** **  * *  *  * *****    * 
**  * *  *****   *  ****  * *   
 ***  *    ***   *  * * **  *    * * *    *    str1, str2);

* *  *** * * *   ****     *  **  *  **
   ** * *  *  {
  * *** * *     **** * *  * * *  ***  *  *   ** **** * ** is a prefix of  * *** * str1, str2);
*  *        *** **  ***  
 *     ***   ******  *   ****
     *  * **    * * *   *** *   *      *  ***  * *    * ** ****   is not a prefix of       ** str1, str2);

*   * * * ** **** * *  *****  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    **  ***  *
#include   *   ***  *  *
#include   * ** *** **  

int main()
{
*** ***  *  *  *   *****  *  ** prefix[100];
 **** **** ** *** *** *   word[100];
 *   *  *  *  **   *  **  * ** *** * * %s", prefix, word);
  ** * ** *   *    * ** * *  i;
  **  * *      * *  **  ** *** = 0; i< strlen(prefix); ++i)
 **    *   * ***  ** * ***  * *
 *** * ** **** ***** * **   *  * * *******   * * ****  *** **   *
**** * ****    *   *   ** * * *   **  **** **  *     
*  * **   *****  **  ***   *  *  ****        *  *    **   ***** ********* *  ******* ** *  * * ** is not a prefix of %s", prefix, word);
*** *** *  **   * **       ** * *** *   *  * *  *  ***       ** *****  * *   * *  *  *  0;
   **      ****  *** * *  *   **  *   * ** *  * *  ****   
      * ****** **** * **   *  **
**** *       * * **  **   *      ** *** is a prefix of %s", prefix, word);
 ** * ***** *  *** *  * **** * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****** *  *    
#include  *  *  *     *   
#include  ** ** * *  ** 

int main()
{
*    *** ****  *  *   ** * ** prefix[100];
 * * ****       *   *    * word[100];
****  ** **   **** * ** ********* ******* %s", prefix, word);
* ***   * **** * **  * **  i;
    ******  **** *  *  *  * = 0; i< strlen(prefix); ++i)
***** * *  *     **** **  **  **
*    *** * *     * *          * ** * *** * **** * * * **  *  *  *   ***  * *****
 *** *  ** **   *  *  **** ****** * *** *  *  **     ** 
**      *** *  **     *   * **  *  **   * * * *     *       *      ****           *****   *   is not a prefix of %s", prefix, word);
 * *   *  * *** *****    *  ***        *** *  ***     *   ** * *    ***   ***  **   **  0;
 * *  ***  ******   * *** *   ***    * ***      **
  *** ***  *  ** *   **    *
*       *  ****    *  *     ** *  *    ** * is a prefix of %s", prefix, word);
**  * * * **   **** * * **    0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  *  * *   **  *  
   *  * *  **   *
 **   *  *******   

int main()
{
**   ** **** * char  * ** **
 *   * ** * ** * char * ** *
*** ** * *     *   *** *  *   *  *  **** * *  **** word);
 *   *   ** int i;
 **  **  **** for(i = 0;  *      * ***** ++i)
**** * * * *   *  {
  * * *** *  *  *   ***    *  * *  **** * 
  **        * *    **     {
* * **    *  * *  *  *  * * *** ** * **    * *** ** ** **  ** is not a  *     of ** **    *** word);
*****   ****     ** **   ** *  *    * *      * *   *  * 0;
***  * **   **** * ** * * **   }
 *  **  *  ** }
 *** **      **    * * * **  *   is a prefix of  ** ** * *     * word);
 * ** ** * ****   * ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.142
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users