1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
  * ****** *          **  *   
* *  ** * * ****    **     *  *** **     * * *  **  ***
    {
* * **  **  * ** * *** *     ** * * *** *  *    * * *********   (i=0; i<=strlen(string2)-1;i++)
*  *  *   * **  *  *     * *** ***  *     ***     * *
 **    *      **** * **  **      ** **  ** * * ***  * * **  *  **  * ****       ** (string2[i]==string1[i])
* ***** * * * ***  *    *** *     *** *         * ***   *  ***   * ***  ** * 
  * ***   *   *   *****   ** * * *  ****** *  * * **  ** * * * **** *** **** **  **** *   ** ***   * *   ** *          
* *  *   *  ***** *      ****   *** **  *     *****   **  ** *  *** *     *** ***   *   
* * ****    **   ** *  * * *   *    *     *** *  *** *  * ** 
* *  *  *  *    * ** * *  *  ** **  * ****  * *  **
** * * ****   **** * ***  *    *  * ** * *  **  ** *  **  
    * *  **    * **** * ****** *  ** ***    *** **   *    *   ****** **  *  ***  ****  is a prefix of %s", string2, string1);
 * * ****   * *    ** *  * * ** * ******* ** * **     *  **
    * *** * *   **   **** ***  *  *** * * ******  *****  * ** *
* *  ***     *** *  * *   * ** *  ** ****  ***** *  **     
* *   *** ********     * * *   **       ********  ***  * ***  ** **   ***  * *   *** * is not a prefix of %s", string2, string1);
** *  * **  **     *       *  *****         * * ** ********
    }
 *  * ** ** * ** *  * **    **      **  **** * *  * 
    {
** * *   **   * **      *** *       *********  * **    (i=0; i<=strlen(string1)-1;i++)
** ***  * * ** **  * *    **  *  ******* *  ****
**   *** * ***  **   *****  * * *  *  *  **   *   *****  **   *  ****  **   * *  * ** (string2[i]==string1[i])
 **  *     * * **      ** ***  * *   * ** ** *** *  ** **    *  * *** **        
** * **  ** ** ***** **   ** *******  **  *  *     **   ** *     **  * ****  ***    * *   *** ** **    *****
       *******   **    ***** **    *  ***   *****  *** ** **  *  *  * *  * * **** * * *
*   **** ***   *   ** **  * ****   *   *** *    ***      *
 *** **  *  ** * *** ***** **** *****  * * * * **   * 
***   * * * **  **   * ***  * *  * **    ***** ***  *
       *  * **  *** *    ***  *    **    *   **** ** **     ** * *  * * *  *******   *    ** * **  is a prefix of %s", string1, string2);
*     **    * *   *  *  * *   ***    *  * *** *    **   
**  *******  *    *  **   **  **  ***  ** *****   
    *  ***  ***  ****** * * * ** * **  * *  * *** 
 * * ****** ** *** ** *****  ** ********  *  **** *  *****   *  ****  *    * *******   *** is not a prefix of %s", string1, string2);
 * **** * * * *** **   *  *** ** *** ** ** * * **** ***
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 * *    ** ** **   **     ** *   *  ** %s", chaine1,chaine2);
***  ****** * ***** **** *        *** ***  *
** * **  * * **  * * *    **  ****  0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 ** ** **   *   * * * *      ****** lenght1,lenght2,c;
 * ** *  * **  * ** *   **  * b[100];
*  * **      * *    *  * * **  a[100];
   * * * ***   * *  ** ** d[100];
  ***** *   ***  * *   *   ****  ****  * * * ***  *  * **
*  *** ***** *    *  *  ***  ***  *** **      *  *   * 
 * * ** **   * ** * *** * *   *    ****
*  *   *   ** ** ** *   **      ** **   
  * * * *  **  * ***  * *  ***    ****  
 * *    ** *****  *****  * **
********* *  * **  **    ** *  ***** ***  *  *    * ****** is a prefix of %s",a,b);
**   *  * ***   ***** ***  *  
 **  *  **** *****  ** * * * * **
* ***   *    **** ***  *** 
  **  * * **   ***  * ***** **  ***     ***  **** * **     *  * is not a prefix of %s",a,b);
    *  *  ******   *    **  *  *
*      ***   * ** *  * * ****** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *  *   ***  * **
#include  * *****   *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*  ***  **** *     i;
****  *     **   *  * ****  
  {
   ** ** * **  ** * ** *     **** *   * *   A[i]!='\0' && A[i]!=B[i]   )
  **    * * * *** ** *  ** ***** *** * ***** ** **  ***  ** 0;
  ****  ******   *****  *   * * *****   ***   ** * 
** ******  *    * ** ********* *     *** *****  ***    ** **** * *     * 
  }
*  **  ** ** 1;
}


int main()
{
*  *   **** **   * ***** *** a[n],b[n],c[n];
  * * * ********* *** ***** ***   i;
 *    ** ***        **** *   **  *    ** **  *  * *** * 
 *    *    *** **  **    *  * * **    *      *     * 
 * * *  **  **  ***    ** (aa(a,b)){
    * ** *** * ****** * * *** * ** **  *** * **** * * ** *** ** *** *  
 * **  *** ***    *  * * **   ** *   ***  * * *  *  * * ***   *   * * ****   ****   *  *** **  *  
******  ** * **  *    * * **** * *    * ********* ***   * *  * **  * *       *  ****   *   ***   ** * *   *  ** *  
****** **** ***** *  ** * ***     * *   **  *** *** *    * ** ***  **** ***  ****      * 

*  **       *  **     *  *  *   * **  * * ** * ** ** * **   *
* *** *******   *** ** * * *     **    * * **  *   **   * * * *    *   is a prefix of %s",c,b);
 * * ***** ****  ***     *   **
**** ***   ** *  ** ** *      
* *  **    **   ** * ***        *  *    *  * *  **  *  ** ***** is not a prefix of %s",a,b);
* **  *       * * ***  ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *    * *   *
* ****   **   * **** *** 
int main (){
char **   **  *
char  ** ** * 
* * ** ***  ***  string1: * *****  
 *  *  * ** * ** **  * *
    ***   * ** string2: ****  
      **  * **** * *** *
** *   *    **  * ***
**  * ******  *   *     * * **  *      is   * ***** * of           **    ** 
else
* ****  *   **** ** *** *** ** *  ******  is not prefix of  *  * * *   * ** **

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ***     * ** *
#include ******   *  ** *** *
#include **   *  ** **** *
#include * * * **       
int prefix(char p[],char s[])
{
* **     * **    ***  **    *** * **   
** *    *** ******* *** ** * * 0;
 * ****  * **      **  if **  * **** **** *
* *  **** ** *** * ** ** **   1;
 *    *   * *  ** *** * *
****** *      * **** * ***  0;
}

int main()
{
** ** ********* * **   p[999],s[999];
****  *    ******** *       *** * **** *  * *** *
*     ** *  *        ****  *      *   *  *    

***    ** ** ** *** *   **   *
 ** ** **  ***  * * ** *   *   ****   *  * is a prefix of %s",p,s);
*** *  *   * *  *** *
  **** ***   ***  **  *  ** *   * * is not a prefix of *    *   *

 * **  **** ******** * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    * *** *  *** 
int main()
{
  ******  *    ***** **    *  ***** length1,length2,c;
*** * *** ** * ****  * * *  a[100];
   ***   * ***  * *  * **   b[100];
 *  *       ** *  *    *       * * d[100];
*    * * *      **********  * ** ** *   *****  * * * * 
     *     *   **  *  * * * ***   *      ** ** **   *
** ***      **            * * *  *** **  **
***   **     *   *   *    *  **** ** * *
if (strcmp(a,d)==0)
*   *  * ** * *   *   *
  **      **  *  **       *  ***    ****  *  * ***  **     is a prefix of %s",a,b);
****  *  * ****  *** **  ** *
*    **  *      *****  * 
* ****  ***   *  *** *** *  
 **   *    **   *** *    * **   **    *  ********   *** *  *    ** *    is not a prefix of %s",a,b);
**  **    ** ****  * * *   * *
***  * * **** **    *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** * *  **
#include    **       * 

int prefix (char * **  ** str2[])
{
*** ** *** ********   ** * * length=0, * **  * 
*    * *  * ***** *
** **    * * ** *    * *** ***  = *** ** *   *  ***
* *     *    ** * * **
 ** **** * * * ***  * * *   ***  *     *   * 
*     *   * *** *     *  ****   * **** * ***   
  *  *  **   *** *** * *  * if * * ** *    
  * *  * ** *   *  **       *  **  * ** ******    *     
** *   *** **** *  ****** ** ** * ** *    }
    * *         **  *    *    * ***    *
 *****      *   ** * (count == length)
  ***  * *   ****  *  *** *  ** ** * *  * ****  1;
 ******    *  **  **        else    **    * 0; * *   *** **     ** * *
*  **         * *     * 
}
int main(void)
{
 ***  * **  *        *  * **     ** ** *
** **  *    *  ** ***  
**** *  ***** * *   **  **  ** *   * **        *  str1, str2);

*     * ** *   *** *    ** **   * ***  ** 
** * *    *  *   {
*  **  *  *         * *   *     *** *  * * **  ****  * ** * * *  is a prefix of  ** **  *   str1, str2);
**** * **   *  ** *   ***** 
* * ***** **   **   *  ** 
 *    **  ** * *   ** *   * **  *    *** ****  **  *** * *      * is not a prefix of  *    * str1, str2);

**  * *  *  * **      *** *** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   * *** *
#include *     ** * * * * **
#include *  * * ***   * **

int main()
{
  *  **  *  ***** * *  ** ** * prefix[100];
* *  *** **   *  * ***     *  word[100];
****  **     **     ***  *     *    * %s", prefix, word);
**  *    * * ** *   *  * * i;
   ***** ** ******  *  * *   *  * * = 0; i< strlen(prefix); ++i)
* **   ***  ** ** *   ** ** * 
   *  * * *************  * ** ** ** ** * **   *** *    ***  * * **  
* *     **  *  **  * * *  *** ** * * *   ** *   *  * 
* ** ** *   **    * ***  *   ***    ***  *  *  * ** ***  *  **  ** *** *** * **  * ** is not a prefix of %s", prefix, word);
 *****    **** ** *** **  **   ** ***    * * **  *  * *** ** * *******  * * ****** * 0;
 *****      *** * *  * **********  **    *   ****  *** *
    * ***  * *    * ********
** * ** * **  ****  *   **** *   ** **   is a prefix of %s", prefix, word);
     *** ***       *****  **  * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *******   *  
#include  * *** *   *  
#include *     *** ***  **

int main()
{
***** ***   ** *  *** ******   * * prefix[100];
*   * ** ****   **  *****      * word[100];
* * **  **   *  * * ****  ***  * ***  %s", prefix, word);
  *  * ***   ***  *  **  *** i;
  * **** *     * *** ***     ***** * = 0; i< strlen(prefix); ++i)
*   *  *  *   *    * **  *  *
* * *  *  ** *  ****  **   **  *   **  ***      *    **   **  ***      * **
***** * * **  ***** * **** *** **  * *  ***  *   *
 ** *** **** *   ***** *****  **  ****  *   * * *** *******  ******* **    *     **  **  * *****  is not a prefix of %s", prefix, word);
**  * ****  *  * ***   *  * **  * *   ** ** * ** **  ** ***** * *     *   ** **  0;
*    *  * *     ***    * * *   **  *** ** *   **  ***
 *****  **  *   * *  *****    
  *      **  **   *  * ***   ** **    * *    is a prefix of %s", prefix, word);
**     * **       ***   ****** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  * ***  ***   *  
*  *   * ** *     **     
*   * ** ****    *** *****

int main()
{
 ** *      * * char *     *
*  *****   * * ** char **   ** 
 * ** ***  ***   * *** **   **  * * ****  word);
****  *   * *** int i;
**   * * ** * ** for(i = 0; *  *   *  **  * *  ++i)
 ******    ** **   {
*** **** **  ***    *  **   * **  **   ** **  **** *
*     * ****  ***  *** ** ** {
*****     *   **  * *         ** * ****   **   ***** ** * is not a * *** of      ** **   * *** word);
**  * *   *    ******  **     **  **    ** *      0;
*** *****   *    ** * *   **  * }
    ***  **  ****  }
*       *    *   **  *****  is a prefix of  *** **   **  *  word);
* * ** *  *     *   * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 18.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 16k views
12,783 questions
183,442 answers
172,219 comments
4,824 users