1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include *  ***      *   
#include  * ** *** * ** * 
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#define n 100
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}
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Hidden content!
#include * *** ** ** *  *   
      ** ** *** **  * ** 
int main (){
char  *    ** 
char  * ** *
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include *   *   * *******  
#include  ***  **  **  *  
#include  ** ***** *** * 
#include **   ** ** * ** *
int prefix(char p[],char s[])
{
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* *   * **       ** *  *  ** 0;
}
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#include <stdio.h>
#include *  ***     *  
int main()
{
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   *** * *   **** 0;
}
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Hidden content!
#include ** ********  **
#include **** *** *     

int prefix (char    * **** str2[])
{
* *  *   **  ****  * *  *   *   **   length=0, * **  * 
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{
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*       ** ***  ** **   *** *** *   0;
}
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#include **  **   **** **  
#include * ** **  ** *  * *
#include      **       ** 

int main()
{
     **  **** *        *     ** prefix[100];
 ** * *      *  ** ******** word[100];
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**        *  **    **********   * * ******   **   **    
  ****  *   * *  * * * *
*  * *  * * * * **    * * *****  * * *    is a prefix of %s", prefix, word);
 *  * **  * **   ****   * ** ** 0;
}
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Hidden content!
#include ****  *** *  **
#include  ***  *** * *
#include *   ****  *   ** *

int main()
{
*    ** ****      * *  *  * ** * prefix[100];
 ***  ***  ** * **  *  word[100];
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*    **   *       * * * ** * i;
  **  *** **** ***** * *** * **** = 0; i< strlen(prefix); ++i)
   * ******  *   ** ** 
 *  *** *       *    ** ** * ***  ***     *** **  ***    *  ***    ****
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 *** *  **** * * * *  *** *    * **      **** * is a prefix of %s", prefix, word);
  * *   ***  * ** ** *** * *    0;
}
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  ** * *  * * ***    * 
 ***   *   **** * * * **** **
 *  **** * ****   *

int main()
{
** * ** *  *** char    * *
 **  * *  * * * char   *  *  
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* * *  *  ***    *   }
 ** ***   **  * ** ** * *   is a prefix of   * *     *** * word);
 *****  ** * *  *    0;
}
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