1-11 Exercise 3: Prefix of a string

0 like 0 dislike
11.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 11.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
  *  **** ****** * **  ***
 ** * *     *** ** *** ******  ***  * ***** *** * * 
    {
*   * ****    * * *  ***   ** * *   * **  ** ***  * ** ** (i=0; i<=strlen(string2)-1;i++)
* ** ******* *** **   *    *  *   ** *   *  ** *   **  *    
 **    * ****  ***  * *** *** ***  * *    * **    **   ******** *** *****  *  * * (string2[i]==string1[i])
*  * ***  ***     ** ***  ** *****  **   * ** *  **  *** * ** **    ** * *** ********** 
*** *    ** * *   ** *** ** ***** *   *     **  *  *   * ****   *      ****  ** *  ** **  * *** ******* **   * 
****   * * ******  *    * *  ****  * **** * *  *    *** * *   **  *  ** 
 **  ** *    *  * *** *  *** *   *   **  **  ****   
**    **  ** **** **  *** **  ** **** * *   ***  *  ****   ***
 *    *  *** * *   * **** *  ** *    *  *  ********  * *   **
 **    *** **   *   * ** * * ****    **** *** **  * *  **  * * *   *  *****   * **  ****  *     is a prefix of %s", string2, string1);
**  **** * *       ** ** *  *  * ******** *  ***        **  *
*  **** ******* *   ** *  *  *  ** ***   * ******* **
* ****   *   *  ** * * * *  ** ***   *   * ** *  * *  
 * ***    * ** * *****   *  * *  *   * *** * ***  **** *  *  *  ***  *** ***  *  is not a prefix of %s", string2, string1);
 ** * **** *    ** ** ***  ** ** * *  * * **
    }
   * **** *** * *     *  *    *** **  ****  * 
    {
***     ***  * *  ***      * * *  ****  **   **  *  * ** ***  (i=0; i<=strlen(string1)-1;i++)
  ***  *  *  * *  * ***  ** **  ** ** *  **  ** * *
    *****      ***  **   ***    ****** * * **  ****  * * ****  ***  *    *  * ** ***  ** (string2[i]==string1[i])
  *   ** * * *    ** **** *****  ** **       ** **  ** *** **   * *  **  ** ** ***  
 ***   *  * ** * * ** **   * * * ***   *  ** * * * ** *   **   ***  ***  *  ** * **   *  **   **  * *  * **** * 
  * **   **** *   ** **    * ***     **   *** **     ** *****   * *  * * **  ** 
 *** * ** *   **** * *   * *   **  **   * 
* ** *  ** * *   ** *   *   *** *** *      **     *****   
****** * **         *  *** *    * ***     **  *   ***** **
***   *  * **  *   *   ** * **     **   * *   *     * *     * *  *  **  *  *  ****  **  **  ****  *** is a prefix of %s", string1, string2);
   *   ***  **    *        *  ** *  ** *   * * *   ** ***
*   ****     ***  **   *   * *  **   **  *  *  * *  ** ** 
**     * *  **** ** **  ** ** * * * *  *    *** ***
   **  *     *** *   * ** *  *  ***** **  *  * **** *    * * *  *** *  * * *** ** *** **** **   is not a prefix of %s", string1, string2);
 *  *  *   * * ***     ***      *  *  *   ******  ***  **
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   * * * *  * * *****  *  ** *   ** * **  * * %s", chaine1,chaine2);
** ***** *  ** ** **  ***  *** * ** **  
   ****  ** * * *****  ******  ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**   *  * ***  ** ** ***   ** ** * lenght1,lenght2,c;
*  * *  ***  * *  * ** ***  **   b[100];
   **  *** ** * *  ** *    a[100];
  *  ***   * *  **    ** **  d[100];
*     *****   ***    ** * *  ***  *   ****
 * *** * ***  ****   *  ** *  *  *  **  **
  * **  **** ** *****  * *   *   *******
 **  *  * *** ** *  ** **   *   ***   *  
 *** **   **** *   *** **     *  ** **  
 * * ** *      * ** ** * *  *  
  ** * *  * * *** **   * * ****   ****  ******* ** ***  * is a prefix of %s",a,b);
  ** * * * ******  *   * **
  *  ** ** *      *** **    *
**    **  * *  ****     **
 ******     *    ****     ***** ***  * * * * *   **  ***  * * * ***  is not a prefix of %s",a,b);
**** * * *** * * ***   *    *
* * *  **** * **      *    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * * **** *   * 
#include ****** ***     **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
******      ***  i;
  ********** * *  * ****  ***  *
  {
*  *   *    *  * *  ****     ** * *  A[i]!='\0' && A[i]!=B[i]   )
**        ***    * ** * *  * *   *      ***   *  **  * ***  *     ***  ** 0;
 *     * * *  *    * * *        *** * ***  *  * **  *   *
  *** * *   **  * *** *   ** **  *   *    * * ****   **** ***** **  
  }
***   * *** ****** 1;
}


int main()
{
  * ******  *** **  **     ****  a[n],b[n],c[n];
**** * *  ** ** **  * *** **** i;
 **  *  * ******* * ***     ***** * *    ** 
*** * * **  *** * **    ***  *** *  **    *   * ** *  
* **** ** *  *** * ** *  *  *   (aa(a,b)){
    * *  **** *** * * ****    *  * *   *  *** *  *    **  ***  * * **  *  *** 
**  **  ** **  * * * * *      **   ** *** ** **  *    *    *   *  * * * *   **  *     *
**** *  * *** * ***** * * *  * * **   *   * ** ** **  ******  *   * * ** *  *  *  * * ****** * ***    * ** 
* *  ** ***   ****  *  *     * *  *** ** *   **  ** ** ** ***       *  * **

*   *  **   *   * ******** ** *  * ****      *    *
*  *  ** *  *  * *  * *  *  * **    * *   * *   * ** * * *   *** * **** is a prefix of %s",c,b);
 ***** *             * * * 
  ***  *** *******  *  ** * 
 *** ******** **  ***  ******** * *   *** * * **  *  **** *  **** * *    is not a prefix of %s",a,b);
 **   *   *   *  *** **  * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  *  *    **
   *   *****  *** 
int main (){
char *    *   
char * *   **
**   **   * *   string1: **  ***
 ***  * * * *        *     *  * *
* *** **** *  ** string2:    ***  *
*** * ** *  *** ** * * *
  *  ***  ***** *  
     ****  * ** * *  * ** *   *  *   ** is   ******* of **  **** **   ** 
else
* ** ***     **    **  *  * **  ** * **  is not prefix of   * ***   ** ****  **

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  **     *  *
#include      *    * ** *
#include ** ***   ** * 
#include          *******
int prefix(char p[],char s[])
{
*****              *  *    ** ****  *
******  * ** * *  ***  *   * ** ***   0;
*  ** *****   **   * *  * if    ***** * * *
 *  * ** ** *   **** ***   *      1;
 *  * * *  **** *  ** *   
  * *****   ** *      * * **   0;
}

int main()
{
* * ** ** * **  p[999],s[999];
*** **  **  *  ******** ** **  * *   *  ** ** 
 *    * * *    ******** * **    **  

   * * **** *   *   * * **   *   **
** * * *******      * * ** *   *   *** *  is a prefix of %s",p,s);
*** *** * *   *   **    
** *  ****  * ****  *** * ** **     is not a prefix of **   * * * 

* * ***  **    *  *** * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *** *  ***   *
int main()
{
 * **     *****   *   ** *  length1,length2,c;
 *  *** **  *  *  *** *   *    ***  a[100];
** ***    **  * **** **  *        b[100];
** * **  ** * * *        ** **  d[100];
 * * ***  **  ** * * *   *   * **    *   ** *****
*  **   ** * ****   ** *  **    ** ** *  * *** *    *
 ***   *        *  ** * *  * **   *   
 *  *** **  * ***    *      ** ****  **   *
if (strcmp(a,d)==0)
 **** *   **   ** **       *
*   * * ***** *****  ** * * *   **  * **  *  ** * ** *   ***   is a prefix of %s",a,b);
*  * *  ***    * *    *  ** * 
 *       *  ******    * *   * ***
 *** **   ** *  * * *  
*     *  *** *    ** * * * * *  **  * *  **   ***  *     * *  ** is not a prefix of %s",a,b);
   ** ***  *  ***** *  *
 ** ** *  * ** *  *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***      *   *
#include  *   ***** * *  * 

int prefix (char    ** * str2[])
{
**  ****** * *  ***    length=0,  * ***
* *   *  * **   * *
    * * * ** *** ****  * * ** = * ** *** * *** 
 *  * ** ****  *  * *  ****  **
********  ** * * ** * ******** **   **  * **  ***
**** ** * * ****  ******  ***  *     *   *
*    ** * *      *  **** *    *    if  *  ****      
    * *   * *  * ***        *   ****  ****   * ** *  **   
**  *   **   * *** ** * *   * ***   }
 * *  * *           *  * *  **   * *  *
 * **** ** * ***    **  *  * (count == length)
  *** * ***     * *    ** *   *  *** *** 1;
   **    ***** ***   ****  else   ** *      0;   ** *  * *  **  ** 
   **         **  * * ** * * *  
}
int main(void)
{
 **  * ***    *     **  **   *** **  * *    * 
  *  *  ***  *** * ** *
*  *   *  * **** **   *  ****  ** ***   *       str1, str2);

 * *****  *****     ***  **    **** **  ** 
 ** *****  *** ** *  {
** *  *  * ***** *****    *  * ** **  * *     * *** *      *****    is a prefix of * **  **   str1, str2);
  **  *** ** * ****** ****   *
   * ******  ** *** **  * *  *****
 *    **   *  * *** * * * * ****  *   *   * *   **  *  *  * *  * ** ***** is not a prefix of     **  * str1, str2);

 *   *  ***  *   *   *           *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **    **    
#include    ***   ***** ** *
#include  ****   * *   ** **

int main()
{
  ** **  * **  **** ***  ***  * prefix[100];
*** **   ** ***  * *** **** word[100];
     *  * * *** *  * ****  ******  %s", prefix, word);
*  *   *  * * ***** **   *  i;
 * ** **        * * * *  ***  * = 0; i< strlen(prefix); ++i)
***  * ** *   *   * *  **  * **
**** ** **  * * *   * ***  *  ****    * **   * * *  **    *  ** **** ****
* **   *  ** ** *  ****   * *  *   * * **   * *** *
   *  *** **   **  *** **  *  ** **** **** ***   ** ***     *** *****  *  *  *   *    *  is not a prefix of %s", prefix, word);
 * *  ** * * * * ******* * ***  ***  * *  ** ***********  *   ** * *  ***   *  *   *   0;
   *  **  * * ****** **    **    *   **** ** * * 
**** ****        * *** * * *  *
  *   ***   ***** **** * *    ** **** * *  is a prefix of %s", prefix, word);
****** ***** *   *   * * *** * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  * *** *      **
#include *   *** ** **     
#include **** ***  *** *** *

int main()
{
* *** *   ** * *  *  *   * *** prefix[100];
 * **   ***       ****  **    * *    word[100];
  ** **** * * *  *  * ** **** **  *  * %s", prefix, word);
     ***     *  ** * * *      * i;
***  ***** * **  ** *    ** ** * = 0; i< strlen(prefix); ++i)
**  * *  * ******  ** ****  
 ***   *  * * ****    * ***  * *   *  *  *** **  *  **       * **  * *  **
**** *         ** ***    ** ***     *   *   *  ***    
* *    **   * * * ** * ** *     *     * **  * ***   ** *  **    ** ***  *  ******     **  ** is not a prefix of %s", prefix, word);
*  * ***     ** ** ****  * *  **     * ***   ** *   ** *  **  ***** * *  * ** *****  0;
  *  * **   **** **  * ** * * **** *  **    **   * 
*** ***  * *** *  **  ** *
**    ***   **** * *  *  **  ****  * is a prefix of %s", prefix, word);
** * **  **  ****  * *    *      0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *** *  **   ***    ***
 *  *    *     * *
*        ***  *    **** *

int main()
{
** * *  ** ***  char    **   
  *  **   ******* char ** ***** 
*     ** *   *   * * ******    * **   *  * *  word);
*  **   *******   int i;
* ***    **** for(i = 0; **       ** *  * ++i)
 *  * * *    *  * {
  **     *  ** * *   ***  *    * * ***  * 
* ***      *    ******  *   {
*   *** *     ** *  ****        * **   * * * *   * *   ** ** is not a *  ** of  ** * *       * word);
*    *  * *   ** * * *** * ******      ** ** *** *** * 0;
 *  *  *   *  * *** *  ** **  *  }
   **  ** **  }
*  *   *** **  * * * **  ** is a prefix of  *  **  * *   word);
 * ** **  *** **  ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 16.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users