1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
**  *  * *  *   *** * *   * *
 ** **  * *  *   *    ****  * * *  * **  **  *  *
    {
 **  ****  ** **  **   * ******    *****     *  **** *  (i=0; i<=strlen(string2)-1;i++)
  *  ****** *** * *  *   ** *  **  * * **  *****    **   * 
  *  ***   **** * *      ** * ** ** *   *    ******* ** ***  *   *   *   *** * ** (string2[i]==string1[i])
**  *  *** *   *    *****    **** **     **   * *   * *   * *    ***** **   ** **  *  
* ** *** *    *  **   * ** * *    ** * ** **     *  *** *    * * ** * *  *  **  ***    *   ** *** **  ** **
    * ** ** * **   *    *  *** *** * * ** *  * ** **       *   **   ** *** *** * 
 *** * * * **  ***** *  * ** *   ***   ******* * **  
** * ***** ** *   ***  * *   * *  ****   ******   *  * *  *
*  *   * ******     ***  **     *** * *   *  **   *      
 ****    * * ******  *** *   * *** *     *  **      *  *** *  **      *  *   *   * * *    *** * is a prefix of %s", string2, string1);
   ** * ** ** ***    *** * ** *  * *    *** * *
    *  * ** *  ***    * *    * **   * *  *       *   **
 *   * *      ***** **     * * *  * ** *****    *  *  **
*  *** *    *** * * ***** ** * **** * **  * * * *  * ****  **     ***    ***  * **     *******    ***   * is not a prefix of %s", string2, string1);
***   *   ***      *** **   *  * **  ***    *** * *
    }
 * **  * *    ****** *  ** *******  * *  **  **   *  *
    {
 *   *  *  *     ** ** * *  * *   ****    ******  *** **** (i=0; i<=strlen(string1)-1;i++)
  * *  * *          **** *  ** * *** ** * * * *   *
* ** *****       *** ** *   ** *** ** * ***** * * *   **** **** *    *  *** *** * *   (string2[i]==string1[i])
*  *    ** *         ****      *  **********      **   * *** * *   *  *  ** *    ** *  ***
 **  * ***   * * * * *  * * *  **  *  **   *    * **  **** **    * ** *    ** ** **  * *  ****  ** ** * ** * ** ****
 **  * * *   * * * * *  *** * *  **    *  ***   ** **   *    *  **  * * * *** *   *   *  **
 *  **** **  *  ***  * *    ** *  **   *    ** * *  *  * *
* *   **** ***** *** * * * *  *  ** *******  *  *** * * *
*  *   * **** ***  *** ****   *  * * *   *** ****** ***
* *** *  *  *     **   *  * * *  * *** *   *** ******* **  *   *** * *    ***   * ** *****  * is a prefix of %s", string1, string2);
* *    ** ****  * *****  ** ******** *** *** *   *  **  * *   
 *********  * ** *  ******** *  * **  *  *   * ** ***
  * * *   ***     ***          * ***     *    *  * *  * *****  *
   * **        * * *  * * * *    *** ***    **  ***     ***     **       * ** *** * * **  ** **  *  is not a prefix of %s", string1, string2);
**  **** * **   ** *  **** *  ****  **   *      **  *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 **  **** **    * **  *    **  *  ***  ***  %s", chaine1,chaine2);
   * * ** * **** * * * *  ***  *** **  *** *
*      ** *** ***  ** * *   **     0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
      ***    *  * **  ** ** lenght1,lenght2,c;
 *  ** *   * ********  *  *    b[100];
 *   * **  * *  **  *    * **   a[100];
* * *  *  * ****  * ** * ** d[100];
       *  *  *  *  ***    * *  *  * ****   *  
 * *  * *****    ******* *  * **       * *** *
  *  *   *** **   *  *  * **** **    
     ***** *  *   ***** ***** ** *** *****
 *   *** ** *     ****** * ** *   *   ** 
** ****  *   * ****    
* *   ***  *     *** **** *** * * * * **   * *   is a prefix of %s",a,b);
**  **  **** **   *   *    
*  *           * *   **** 
**  *** *** ** ** *  *
  *** *  * *   * *** ***   *   **** *   ***      ****  ***  * is not a prefix of %s",a,b);
   ** * *** **  **** 
* * ** * **  ***  ***    * * * *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **  *   *  **      
#include ***        
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
** *  ***   ** ** i;
***  *** ** *    *  ** ** **
  {
* ** **  ****     *****    *  ** * *******   A[i]!='\0' && A[i]!=B[i]   )
** * *  ***   ****** * * * * * **** ** * ***  *** *** *  *   0;
* *** *       ** *   * * * ** *  *      ******    
   * **  ** **  *  * * *  *      ** **    **    ***      ***  ** * ** * * 
  }
       ** *   *  * 1;
}


int main()
{
*  * *   * * ** * *  ***    ** a[n],b[n],c[n];
 ***    * ** * *    *** * *   i;
*****  *** ****** * *   **     ** * * ****  ***  ***
 *** * *    * * *     ** ** **  **** ***  **  
** *  **   **  **** **** *    (aa(a,b)){
 *  ***      *  * ** * *    **** *     **  *  *  *  ******** 
*  *    ** * *  ** *   ** *  * *   **   * *   **    * ***** **  **  *       * *** *** *   * *  
 * ** **** * ** **  *** ******  * * ** *** *    * ***   * * *** *  ** ** * * ***** * *  ***** **   * **  *  * * ** * ****  
***  ** * ** **** **   * **   * ** *  ** ****** *  * *  ** ****   ** *  **  *  * * *

**   ***   *   *   ***    **  ***** * * ****       * * **
***** *   * **  *  **  * *  **     ***  **** *  *** *    *   *   is a prefix of %s",c,b);
*** * **  * *     * *  **  *
*     *****    ******* * **    * 
* *     *     * *   **       **   ** *   *  ****   *** ***  is not a prefix of %s",a,b);
* * * **  ***   ****** *  *  *    0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  ***** ***
  **     * * *   *****  
int main (){
char  **** ** 
char *  *     
    *  ** * string1:  *  ** 
  *    **  **  **** *****   *   * 
* *********   ** string2:    ******
  **  *** **       **   *     *
**  **  *     ****   **
****     * *    *  * *    *   **** *  *  * is * *  **     of   *  **     *****     
else
   *     **** ***** **  *  * ** * ** ** is not prefix of   ****   **   * *    

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ******   **  **
#include *** *        
#include * * ** *       * 
#include   * **** **   *  
int prefix(char p[],char s[])
{
* * **   ** * ***    * * *  *** * * 
**  * * * * * *  * * *   **  ***  0;
* * ****  ***  *  ** **   ** if  *     ** **** 
**   **     * ** * ***  * **  *** 1;
  ****     **   *    *  *  
  ** **  *   ***  **   *     ** 0;
}

int main()
{
* *  ** **  *    *****    p[999],s[999];
  ** * * *    *    * ****  ******** *   *  
     *  **  **   **    *  *  * **   * *   

*   ***** * *  * *   * ** ** 
*   * **** ** ** * * *  *  * * * * is a prefix of %s",p,s);
*  *******  ***  *
** * ** *  *  *** *  *** *   *  * *** ** * * is not a prefix of  *   * * **  

     ***   *  * *  ** * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *   ** **** * *
int main()
{
*   ** *  *  *** * ** ** length1,length2,c;
***** *** ***** * *** *  * *   a[100];
** ** ***** **** **    * **  b[100];
 ** ** **** *   **  *     ****  d[100];
***  * **  ** ****        *       * ***    *** 
****  *     *           * ****   *** * *** 
*    **** *** *** *  *     *******  ** *      *  
  **    ***  *** **  ** *  *   *  * ** 
if (strcmp(a,d)==0)
* ****  *  *   **     * ***
  ***** **  *     ** ** ******* *  ** *** ***  *  ** *   ** ****     ** is a prefix of %s",a,b);
*****    * *** * *   * **  
      *  **  *   *     **  **
* *  ** ** * *  **********  
 ** **  ** * **    *** * ** *** * *   *            *** *   ***  **  * is not a prefix of %s",a,b);
** ** *  ** *  *  * ***** 
**   *  **    *  ** * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  * ** * * * *
#include  **  *   *   **

int prefix (char ** ***  str2[])
{
  *****  *  ** * * **** *   *    length=0,  **  *
   *     ** ***      
* *    * *  *  * ** ****  *** *  =     ***    ****
* **  * **  *  ***     * * *
 ** *   *****     * ** **  *** * * **  * **** **  **
  ***   * *  *     * **   **** ** ** *   
    *** *  ** *** **   * **  *   *** if *   **** ****
 * *        * *** **  *          **  ** ******** *  *  
 *  ****     * * * ****  ****    *    }
***   *            *     *  *  * *   **
*   **  *   *   * * *  * (count == length)
  ** *  ** * * * *    * ****** * *    ** * 1;
  **  * * *   *  ***   ** *  else ***  *   * ** 0; * * ** * * * ***   
   *** *****  ** **   * **  * 
}
int main(void)
{
 **  * * ** **   * * ***      ******     
  ***  **   *** * *** *** * 
   * **  * * ** **    *  ** ***  *  *  * ** * ** str1, str2);

 ** **   *  *     **   ****  *   *** ** * *
*** *  *  * ***  {
******   ***   *   * *  *     ** * **    *** **  * *  * *  **** ** **  is a prefix of  *  **     str1, str2);
* *  *   *** ****     ** 
 *  *  * ********** *  **  ****** *
*     *        * ** *  ** * **  *  ***  *  * *   **** * *  ** * is not a prefix of * ** *   * str1, str2);

  **  *  *** * ** * ****** *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** **   *   **
#include       *** ** * * 
#include  ****   *** * **

int main()
{
*   *  ***   *** *   *   * *  ** prefix[100];
 *  ***      *  * *      word[100];
 *    **  *    *** ***** ***  **      * *    %s", prefix, word);
 *     *  *    **** **    i;
    ** ****      *  * *  *** *  **  = 0; i< strlen(prefix); ++i)
  * *** * ******* * 
****  * **  **  **  * **  *****    * **** * **  *  ***** *****   
*** * *   ***  *  *      *   *  *  *    *  **   *   * 
    *  ***   ** * ** *    ** *   *** * * ** *** * * **** **      * ****   ** ***   *  is not a prefix of %s", prefix, word);
** *   *    *     * **  *  * **** *   ***   *  **** * * *** *** *  **    ***    *  * *** *** 0;
**** ***       ****  *** * *** **   * * **  *   **  
 *   ******* ***** ** * ***   *
*  ** ** ** *  * *    * **  * *  **** * is a prefix of %s", prefix, word);
   *  ***    *    *  * ** * *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *** *   ******
#include       ****  *     
#include  **   ** ***  *   

int main()
{
*    * **  *    **  *     **  prefix[100];
  ** * *   *  *  **       word[100];
****    *    *   *   * **  *  **     ** %s", prefix, word);
 * *     *  ** *   * **    **   i;
**  **** *        * ******* = 0; i< strlen(prefix); ++i)
** ** * *       ** *** * * * ** 
  * * *  **   *     * *  *  *** ******  *** ** **        * *  * **  **
   ****** *     *** *    ****  *  ** * * **** *   * *
* *   *  **      * *  ****** **  *  ** ** * ***  **  * * * ** * **** * * * * **   *  *  **  * *   * is not a prefix of %s", prefix, word);
*   **** *    **   * *   **    * *** ** **  * *      * **********  *  ** *********  0;
**  *** ** **  *** **  ** * *   *** **  *  *   ** *   * ***** 
 * **   **  **  * * *  *** * ***
 * ****  ** ** *  ** *  *   *** **   ** is a prefix of %s", prefix, word);
*** * **     *** **** ***** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *  ****  ***  *   **
* * ****  * * ***   * ***
 *  * * * ***** ***   * 

int main()
{
 *****  *   *     char    **  *
**   **  *****  * char *    ** 
*         *    *  *   * * *    **       word);
***   * ** * int i;
 * *  *   **  for(i = 0;   ****  * **  *  * * ++i)
* *  **   *  {
 *    ****   **            ** *** * * *     ****
   * *  * *    *    *   **** **** {
 ** * * *   **   *   *   * **  * * **    *  * *  *  **  **** * is not a **  of ***   * *  ** word);
* * * * * *  * ******    ***   * *   * ** **  *** 0;
* ***  *  **       * *  **** *  }
**    **    ** *  }
*   *  **  *   * *   ***    is a prefix of *****   *  * word);
   ** **** *   *     *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.59
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 14.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users