1-11 Exercise 3: Prefix of a string

0 like 0 dislike
5.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 *** **** **  ***** * **  *   
  ** **  **  *  ** ** *  ** *  ***  **   ** *    * * * *
    {
      *** * * *    ** * * * **  ** ***   **    **  * *     * *  (i=0; i<=strlen(string2)-1;i++)
* *     ** ******  ** *  *    *  * *** *     ********   *
  **     *****       * ****  *  **     * *** ***** ***      *  ** *  ***  ****   (string2[i]==string1[i])
  *   ***  **    ** **  * ***   *****   **  ****  * ** *   ** ** ***** *   *
 *** *     * ** * * ** *  ****** *   ** **    **  * ****** * * * * ****  * ***  **** ** *  *  ***  * * * **  ** 
* ***   *   *    **  ***** *  *  *  * ****       ***  *    * ****  * **  ** **  * 
   * **  * **** *     *****  * ** ** *  * *  *  
****  **  * *** * ** *  *** ** *   ** ***  * ******* ** 
***** **  * * ***   **   * *** ** *   *  *  *  * **** *    
   *** ** *    * *   ** * *   * * *  * **** ***       *    * *  * ***** * *  *  ** *    is a prefix of %s", string2, string1);
***    ***** *** **  ***    **  *    *    **  * 
 ** ** ** ***  **   ** **  * ** * **   *   *******   ***
*** *    ** **** ***  *** *  * * **   *  * * **  * *  
  *  *  * *   * *  *  * *** * *** ** *****   * *  *** **   *    *   **    *****  is not a prefix of %s", string2, string1);
*** *  ** **  ***   *  *  * **   **   **    *    * *     
    }
 **    * ****  ****** *****  ** **** **  ** *  *****  
    {
** ******      *    ** *** *  * *      * **  * * *        * (i=0; i<=strlen(string1)-1;i++)
**** * ** * *    ****  ***  ** ** *  ****** **  * ***
**     *       *** *** ** * ** * ** *  **  ***** * *** **  *  **   *****   **     (string2[i]==string1[i])
  ** ** *   *  * *** *      *** **  ** *      **** **  *  *** *  ** **      ***  **
     * * *    ****  ******  * *** **      * * * * ***  ****   *    *******   *  ***  ***** ****   * *   
** ***    **  * ** * * * ***  ****** **  *  *  ****   **  *** * ******     
*    * ****  *   * * * * ***        *  *** *** **  *** ** ** *
**  *** * *  **  **  ***  *   *  * *  **      **  * ** **  *
* * ** * **  *   *   *  ** * *  ***      *   * * *  
*  * * ***   *        * * ****  *  *** *****       * *  ** **  **  ********* ***  *  *  *   is a prefix of %s", string1, string2);
 ***   * * * * ****** ** * * * * ***  ** *     ** * **
 ** * * ****   **  *  **** * **   *     * ** * * *   * 
  **  ***  *****  ********  **  *** ***  ** * *  *
  **  * **     **  * *** *   *** *  **   *** *** ***  ** * *    **  ***  * * * * **   *** is not a prefix of %s", string1, string2);
* **** * *  *    ** *   *  **** * * ** *********    ***
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* * *  *   ** **    **** * ***    ********   %s", chaine1,chaine2);
 ** *  *     **** *   ***    * *  ** *** *   ** 
**    ***      *  *   ** *  *    0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   *     **** * *  * ***     **  lenght1,lenght2,c;
  **   * ***       ***  * * *  b[100];
**  * ***       *  *   ** ***   a[100];
    **    *   * *  * * *     *****  d[100];
  *    ******* **    *** *  *** ***   **** ** * * *
*    * *   * ** *  *** **    *  *    * ******   *
****  ***  **** ***    * *  * * ****     *
*** * *    **   *   ***  ******  ****** * 
  ** * ** * *  **   ****** ** ** *      
 ** **   * *   *     **  
 **  * **  ** * *   * ***    ****  * *        * ***    is a prefix of %s",a,b);
 *   **   **   **  *    
* *  * * *    *       ***** ** *
 * **  *  **     *  **   
 * *   **  * *  *  * ** **** * **   * *    * **     * * * is not a prefix of %s",a,b);
* ***   *  ***   **   ** *
*      * ***  *    *  *  * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * **  ******** *
#include  ** **    * *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
*  **** ** ***** i;
   ***  *  * * ******  *  * 
  {
 ***  *  * * *******   ** *** ***   *** * *   A[i]!='\0' && A[i]!=B[i]   )
    **      **  ** *  * * *** * ** * ** *  * **  **** ** * *    * ********* * 0;
  ** *     **  *   *  ** *** ** *   *  *  * * ** ***  *
 * ** * ** * ** * * ***  * ******* ***  ***       *   ****  **   **  *   *
  }
***    *****  * 1;
}


int main()
{
  **   * * *    *** *** *** ***  a[n],b[n],c[n];
 ***** ******  ***** * * ** i;
*     *** *   *   *     *   *  * ****** *    **
** ***    * *      **  *  **  ****  *      ** **** 
  * *** ** ** * * ***  *    (aa(a,b)){
 * **  *   * ***   **   **  *****      **   **  *** ** ******* *  ** * ** *  
  *  *   ** **** * ****  *** ** ** **** **     *****      * ** **  *   ***        * ****   ****
 * ** *   ***     *  * *   ** **  *  * ***   * *  *  *     **     *  *  ******  *  **  *   * *     * * *******    * 
*   * *   * * ******  ** ****  **   *   **          *** **  **   ** * *****    *

* *  ***  *  ***        **  **  **    *   * ** ** *  *
* *    **     * * * * *** *****  * *    ** ***        * ** * is a prefix of %s",c,b);
  ***  *       * **   ** *** *
* *   *** **** ****    * ** *
* *  *** * * *    * * **   * * * **   ****** ******** * **** *  ** * **    is not a prefix of %s",a,b);
  *  *      ** * ***** *  *** ***  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *** * *     *
*    ** * * * * ***
int main (){
char *   *  
char *     *
*** *      *   * string1:  ** **  
 **  * ** * * **** * *  
    **** **   * string2: ***  *
 * *** * * ***    *   ** 
* **   *** ***** ** *
** * * *** ** ** *** **  *    *    **   * ***  is ***  * * * *  of *     *  ** ****  
else
   *   * *       * *** *** *    ***   is not prefix of    * * ** *** *  *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** ***** *** 
#include * *  ** ***** **
#include  *** * *   *  *  
#include * *   * ** * ** 
int prefix(char p[],char s[])
{
 *  * * ****   ** *   *    *   *   * 
 *   * ** *   **    *** *   ** 0;
*  *   **** ****    **** if *   ** **    *     
  * *  * * *  *  ****  *   ** ****  1;
*   *   * *  *  ****   * *
 ****   **   * *       ** **    ** * 0;
}

int main()
{
*  *  *  *  * ** ** * *** p[999],s[999];
        *   * ****  ** ****  ** *   ** *
     ** **** *   **      ***  * **     **      

 ** *   **  *** *   * *     ** *
   *  *   * **** **  **  * **   * *  * ** is a prefix of %s",p,s);
   **** **        * *  **** **
****  * **** ***  ** * ***  * * * * *  **  is not a prefix of  ***     *** 

* **      ** * **    0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ** **    *  
int main()
{
*  *  * **   *  ** **** **    length1,length2,c;
    * *  *   **  **** **   ****  a[100];
** **  ****   * *****  ** *  b[100];
   *    ******** *  *   *  **    d[100];
*    * ***** * *   **    ***  *   ** ** ******
**** *     *  **  **   * *        *     *    **  * 
* ******  *  *******  *  *   ** **** *    
 * ** * ** * **  * *** * *  *  ** * ** *
if (strcmp(a,d)==0)
       ****   **   * *   * ***
    ** * ** * ** ** * *  * * *  *   ***      *    ** *      * *  is a prefix of %s",a,b);
  ******     ** ** *   *  *
*     * *  *   * ** *   
  *** * **  * * *   * 
  **  **       ***  **  * *  * ***** ***  ** *    ** ** * ** is not a prefix of %s",a,b);
 **   ****   **  *  **  *
   * ***    ***      0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ** *         **
#include *** **  ** ***

int prefix (char ** **  str2[])
{
** *   ** * **  ** **    **** length=0, * **
***   *  *** ****
 ***    *  **  * *** * *   *      =   *  *   **  *
** ******  *** *  * * ******
***** * **** * *** * * *****   * *** ***** *
         *     *  ** ***   ** * *     ***   ** 
** *   ***      * * ** *    ** *** if  ***  **   
 *  ** **     *    *  **         * * * ****  ** ** **   
   **     *** ****  ** ***  *    *    }
**   *  *          *    **  *    ***  **  *
***   ** * *  * *     ** (count == length)
* * **    * **     *  *  ** * *  *   ** 1;
*  *******  *   *   *   * else **    * * 0; * * * *   **   *****
   *   * **   * *    * *  ***  
}
int main(void)
{
*** * ******  ** *   *     *** **** ** **** 
*   * *   *   ** ****  * *
*        **** **  * **** * * *** * *  * * * **      str1, str2);

*** *******  *   * ****      ** ******
 * *****  *** * {
*  ** **** *   **    ****** * ** ** *  *** *** ***   *** ** * *   **** * **    is a prefix of   * ** **  str1, str2);
***    *  **  *  ** **
** *  *** ** *****  *         * *
* * *    ** *    **  *    **** **** *  *  * *  ** * * * ***** ***    ***  * is not a prefix of ***    *  str1, str2);

 *  *****  ** *  * *** *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *    * *  * **   
#include * *  ***  ** ** 
#include * ****   ****

int main()
{
 **    *     **** ***   *   ** prefix[100];
 ***     ***  *   * ***    word[100];
*   * * *    ***** **  ** **   ****  * *   %s", prefix, word);
  ***    *      ******  i;
     ***   *  * * * ******* *  * ** = 0; i< strlen(prefix); ++i)
***    *** *   **      **  
   ** * **  ***     * * * * *   *** * * ******      ****   * *  *  **    
* ** *   * *  *  ** ***  **    **   *    ** * *****  ** 
 * ***   *** * * ***** ** ** *  *  **        *** *** **  **** ***  **  * *  * **  ** * *  is not a prefix of %s", prefix, word);
 *  *  *    * *        ***   ** ** **  *  * ** * *    ** *** **  **   *** **** *  ***   0;
* *** ***   *   ** **  **  * *    *  * * *****      **  * 
**  *  *  * **  ***   ** ** * *
***    *    *****    *** ***  *  *   is a prefix of %s", prefix, word);
**  *   ***  ** **    * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****   **** ****  
#include * ***   *** * **
#include  ****      ***

int main()
{
* **   * ***       ***  **    **  *  prefix[100];
*** ******* ** **** *  ** *   word[100];
**      ***  *  *** *****  *  *  *   *** * ** %s", prefix, word);
*** * **  * * * *    * * *** i;
*  ***  * *   ***** **** *  * = 0; i< strlen(prefix); ++i)
 ** *** * * **      *   * 
*     *  **  *   **  * * *   * ** **  **    ** ****** * ***  * * **
 *** ***       ** * **     **   * *   * *   * ***  *** ** ****
 * * *      **  ***** * *   ***** ****  * **  **** ***   **    **** *   *    ***  * *****   *   is not a prefix of %s", prefix, word);
*** ***  *** *   * * **  ** * ** *  ** **     * ** *  * * ** *********    ** *** 0;
   *  *****     **  * *    ** ** * * *  * **    ***** * *  
   * **** *  **  * ** *   *  * 
*  ** *  * ** * **  ** **  ** * **     *  is a prefix of %s", prefix, word);
 ******* *****   *  * * *  ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****** *****   ***    *
 *****  * *    *   
   **  *  *   **  * ** *

int main()
{
*     ** *  char  * ***** 
 *  ****** *         char   ***  
 *** *    ** * ****   ***     ****  *      * word);
* *  *  ** int i;
*   *   ** *** for(i = 0; *  * *   ** *** * ++i)
*  **  *    * **  * {
* *   **  * * * *** * ****    **     ****    *  ** **  
 *** **  ** *  ***  ** ***  {
  * *     *       *       * * ****   *  **     ***   *  *  is not a *  of  * ****    * word);
* ***   * *  *****  ** * *  ***** *** ***   **  0;
* ***  *   *   *   *     }
 ****     *  **  }
* *** *    **       **** **** is a prefix of *** **  ** * ** * word);
 *  ****   * ** * *  *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.99
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 7.9k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 7.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users