1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
***  * *  *  ****  * * ** *    * 
  * *   * *     *** *  ****    **    *  ***  * ****
    {
**  ***  **  *        **      ***  *** *   * * ***  **** ***  *** (i=0; i<=strlen(string2)-1;i++)
***       *     **** **** *  *      ** * *   * * 
*    * **    **      ** ** **    * **  * *     ** *****       * *  *     * *  ** **   (string2[i]==string1[i])
* *  *** *** ***** * ** *** *** ***** * **  **** **** ** *      ***  * * ****** *
* *      ***  ****   *  * *** **  ** ** * ** *   *** *** * * *  **  *   *****  ** *  *  ***    * * * *  ***     * ** 
* **    * *  *** *** *** * ***      *********** **   *** ** ** ** *   ***    *  
**********  * *  ***         *** ***** *   **  * *   **   **
*  * **   ** ****  * **** *  *  ***** ** **** * * ** *  **** 
  ** ** *****  * **  ** * *  *  ***       * *  *  **  ***   *  ** **
*  **  * * **    * ** * ***  *  * * *     ** **  ** *** *   *       * * *  *** * ***  * **  * is a prefix of %s", string2, string1);
 **** *** ******* ****  * *** **  * *** * ***** ***
****  * * *****   **** *  ***  *  *    * **** ****** ***
 *** *  ** * ***   ****** *  ****  *     * *** * *
  ****  *****  ** *  * * ** **** ****  *       ** ***  * ***   **  * *    **** * *  *   *****     is not a prefix of %s", string2, string1);
**   ****   ********* ** ***  ***   * **  *    * * ****
    }
 **** * * *****     *** * * **** *  *     *     *   *  
    {
* * * *     * *   **   * * **  *    *  * *      ***** ***** * (i=0; i<=strlen(string1)-1;i++)
*       ****  *  *  **  ** ** *    **     *   * *  *
 *   *  *   * *** **  *   * * *  ** *  * ** **  *   * * **   *   **  ** *** ** ** * *** * ** (string2[i]==string1[i])
  *  **  ** **  *  *  *    *  ** ** ** ** **  **** * *  * *** *  * ***   * * *  
 * *  *  * **  *         *** *****    **   *   **   ** * **  *  * *  * * ****        *   ***  *  *            * 
  * ** **  *  **    *  *  **** **** *   * ****** ** *  * *  *   **  ** *****
** ** ** ***  * ***  **  * ***   ** **  * ***   *  **** 
*  *** * * ** *** *  ** *  *    *  *   **  * * ** *** *   **       
 *  **  ***  *     ** *** *  ****  ** * ** *******      * **
 * * *  ** ***  **  * * * ******   *  *  ** *   **  * *   *  * * *   * ** *   *  * * *** ****        is a prefix of %s", string1, string2);
  **  * **     * *  * **  *   ***    *   ****  **     * *  **** *
** **  **  **** * * * *    *  * * * * ***      
  *** *******   *  * *** *  **   ** **  ** **  **
 *** *    * **  ** * ** ** *  * ** *   ***** **** *  ***  *   *   ***        * * **  *   is not a prefix of %s", string1, string2);
* * ****   *    * *   ***   **  * * **     *****    *  *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *** * * ***  *   **    * *  **    * %s", chaine1,chaine2);
* ** ** * *** *  **  *** * ***  ****** 
*  **** ****  ** * ** *  * *       0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 * *  *   *  ** ** *    *****  lenght1,lenght2,c;
  * *   ** **   *   *  ****   * b[100];
   ***** * * **    **** *   a[100];
   * ****   * * *        * d[100];
   **** ***** ** * ***  *** ** ****    **    **  * 
**** **   * * * ***** *  **     *** * *  *** 
 **  ** ** ***** * ***      **  ** *  ***** **
  *** ** *  * ***    ** *  *** **   *  *
** * *  *     **   ** ***  **  * * **  ***  **
  **  *  * *   ** *******   ** *
     ***      ** *  **     ** ***** **** * ** ** is a prefix of %s",a,b);
 * *  **** * *** **    *   ***
*** * **  ***** *    **** *    **
*   **  *  *     ****** **  
   *    * * * **  ***  ***** * ** **   *    *** ****   * **  is not a prefix of %s",a,b);
***    *   * ***   ******* *   
 * * **   *  **  * *** * *  ** * **  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **  *  ***  *
#include  ** **   *  *  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
      *  * ** i;
* **         ** ****   * **    
  {
** * *******  *** * *** *  *  * ** ** *  A[i]!='\0' && A[i]!=B[i]   )
** **   * * *    ** *** * **  **  **  ** * **   ** **** *** *   * **** *     0;
***   * ** * *  ** *   ** *  * ** ***   ** *  ** *  * *
*    *****  **    ** *   ****   **  * **    * *    *****  *  **    **
  }
    ** *        1;
}


int main()
{
 * *   ***  * ** ***    * *   a[n],b[n],c[n];
** * * * **  *** ** *      *  *   i;
*** *  ***   ***** ** ** **   *  *     * ** ****
* *** * ** *  *         *    *  *   **    ***  *  *
 *** ** **  ** **** *** **** * (aa(a,b)){
** * **  ***  * * ***   *  * ***  *******   * *  * ** * * * *    *
*   *  ** * * ***** *  ** **    *** *  ***  **   **** * ** *  * *      * *****      * *** 
**  **   *   ** **  * ****  *****   ****** **** * *  ***  *** * *    *    *** * *    ***   *** *  *** 
 * * ***  ** **  * ****** *  *   ******** **   ** *** * * *  *   **  ***   ** *** 

     * *** *   * * ***      *** * *      *  ** **** **
 *        **  ** **** * * *  * **    *  ** ***  ***  * ***** ****    *   is a prefix of %s",c,b);
**** **       *  *    ** * **
  **   *      ** ***  *   
** * ** *   ***     *** * *** **  *  ** * *  *****  *  *****   **** is not a prefix of %s",a,b);
* * ****** *   ***   ***  ***   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  *  ******
 * *      *    *  **  
int main (){
char  * *  **** 
char **** **** 
*** **  *  ***** string1:  * **    
***  ***  * **  ** ** ** ***   * *  * 
****  *  *   ** string2: **  * *
*  * ***** * **    
* * * *   **  ****  
*  * * **  ** *** *   *    * * ***** * * is *******  * of *   *****     **
else
*        * * *** * *   ****  ** ** ** * * is not prefix of  **   **     ***  ** ** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * *** *   * * ***
#include   * * * **** * 
#include * ** *  *  *   * 
#include ***  **** ** * 
int prefix(char p[],char s[])
{
   ***** **** * * *  * ** ***     **  * *
 * *** *  *   ***** *  **  * * *  0;
* **   * ** *    * * *   * if * *  ****   *   
 *** ** ** ** ** **** ** * *     1;
 *  **** * * * *** *   
** ***  **         ******   *    0;
}

int main()
{
*   **   *   ****   * p[999],s[999];
   *   *  *  *   ** * * **  ***** *
*  * **  ***    *   * * *  *** * *  **  *

*   * **  ********   *** ** * *
*******  ** *** *  *** *    * * **** is a prefix of %s",p,s);
* *******   *  *   *  *  
  *   **  **     *  *  *      *   * *****    is not a prefix of  *  ** **** *

 ** *  ***** **   * * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  ***     *** * 
int main()
{
*** * ***   ***  * *   ** *   length1,length2,c;
 ** * *   *  ****   *   ** a[100];
**** * ** * * ** ***  *** * b[100];
 **    ***  * *      *  * *  d[100];
*  *** ** *** *  * **  * * *  * * * **  ***  * *
  * *    *  **  **** ****  ***    *        ** ***** **
* *   **** ** *    * *  ***     **   *  * *
 *      ** *  *  *  *  * * * ***  * *
if (strcmp(a,d)==0)
  * * * *   ********  ***     
*  * ***   *  ***    * *    **** *  ********* *  *     *   *** is a prefix of %s",a,b);
*  ** * **   *** ***   **     
** ***  **** *  *  *****  ***
   **  * **   ** **  ****** 
*   * **  ****** *  ***   *  *  *** * ***    ***  *    ** *  * ** is not a prefix of %s",a,b);
***  **  *  ***    ** ** **  *
    **  * *    0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** * **  * *  
#include     * * * **  *****

int prefix (char *   **   str2[])
{
* ****** *** ** ** * ***   *    length=0,  *****  
  *  ***  * ***  * 
**** * ***  *     *    *  *    =     *  * ** *
  *     *** ****  ***  
  **** *** *****    * **   ** *   *     * *     
 ** *   *****   **   *   **** ********* **    
*   *    ***   * **  *  * * ** *   if  **    *    *
*  **  *     ***  *         *  ***  *  ** * *  * *  
*** ** ** ***  ***   ***  **   }
    **             ***    *    * *  *
*      * * *   *****  * (count == length)
 **  *   *     * *  **  **  * * *    1;
     ** ***** ***    ***  else    **    * 0;   *     *****  
 * **  **  ****  *     *  *  * ****  
}
int main(void)
{
***   * **  **** *  *  *   *    ***** * 
 * *  ** **       *  ** 
    *     **   * * *    ** ***  * **  **   * * **** str1, str2);

  *****   * * **    * ***  ***  * *   *** *  
* *  **   * ***  {
      *** * * *  * ** *  ** ******    *    *   * ** **   * * *** is a prefix of  * ** *  * str1, str2);
*  *** *** * * * *** *   
 *   *   *  ** * ** ****
 * **  *** ** ***   ** *  **      *********     **  *** * *     *  is not a prefix of  * *      str1, str2);

***  ** * ** ** * ** *** ****    0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * ***  **
#include * **  * **  ** *
#include  *  * **  * *** ** 

int main()
{
 *   *****      * *** ***  *   *  prefix[100];
    *****     * *** *  **  ** *  word[100];
 *   ** *  * *   * ** *  **   **** ***    %s", prefix, word);
 ****    ** ****          * i;
*    * ** * * *  * *****   * *  ****  = 0; i< strlen(prefix); ++i)
  ** ** * *** *  *** *    
* *** **** ***  ******  * **** ** * *    **    ****  **   **  * **   ****  
     *  * ** * **  * **** **     *  * *****   *    ** 
  ******  ***    *** * *  * * **     **   *  ** ** * *        * * ****** * ** *    *  *     is not a prefix of %s", prefix, word);
* * **** **       *   * *   ** * *** ***   **********   * *  * *    ***    ** *   **  **** 0;
* *  * * ***** *   *    *  * * * *   ** * *  *****  ****
*     ***  * * ** *      *
 ****  ****** ** **  * ** * **      *    * is a prefix of %s", prefix, word);
 * * **  * *     * * **  ** *  * ****  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***** * ** *** 
#include ** *  ****
#include **   *****   ***

int main()
{
 **  *   ****** *** **     *** prefix[100];
 *  **  * * ***** *   * *    ** word[100];
 *  **      * *  *  * **   * *  * %s", prefix, word);
*** * **    ******  * *  *  i;
*   **  * ***    *  ***  *      = 0; i< strlen(prefix); ++i)
 **    **  * ***** *   *** * 
** * **    **   *   **  *       * *****   **  *    * ****    *   *******
 * ***  ** **  * *   * **   ****  * ** ** *  *  ***  *  
*****  ** * *  * *    * ** * *   **  * * *  *      * ******** * *  *  ** **  **    ** * ** *   ** *    * is not a prefix of %s", prefix, word);
  ** ** * ** ** *  ** ** *******  **     * *  * *  **** * **        * **   0;
   ******** ** *********   ***  *******  *** * ** * * ** *  
*** *    *** ***   *    * * **
*   * *** *   *  * *  **   **    * ****  is a prefix of %s", prefix, word);
 ** *** * ** ******   *** **** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**    ***     * *  *
* **  * **  * ** *   **
 *     *  ** **  * 

int main()
{
**** *   *     char  ***  * *  
* ***   ***   char *     
** **** ** * *  ***  * ** ****  **   word);
 *** * *   *** *   int i;
 ** **  **  *** for(i = 0; ** *  *   * ** *  ++i)
 *  *  * * ** ** {
  *  *  **  ** ***    ** **  * **      ****       *  
* * **   * *   **  *    *****   {
  *   *     **     * * *  *    **  *  *  * ****      * is not a *  * of    *    *   *** * word);
   * *    ** *   *   ** *   *  * *       ** **  0;
****** * ** * ***  *** *  * }
** *  * *  * *  }
*    *        **   *  **** * ** is a prefix of    * * *  * *** word);
  ** *   *  * ***  ***** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users