1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*** * *   * **   *  * ** * * ** ***
  * ***   *   * ** ** *****  ***  ** *  ** ** ***    *   
    {
* **  * *  * **  ** *  **   *  * * **  * * **     *  **  ** (i=0; i<=strlen(string2)-1;i++)
******* * * *   **** ** * **   *   *  **  ** *   
* *****  * *   **** *** *      * * ** **  *  * *** *   ** *  ****   * **  *  *   (string2[i]==string1[i])
***  **   *** **** * *  *****  ** ** **** * **   *  * ** **  * ** ** ****
 *****  *     ** ** **** *   * **  *** * *  *  *   **  * * ***  ****** ***  * * ** * ** ** *    **  * ********  *
 **     * ***   * * *   *  **   * ** *       *** *     ***   * * *   **** * **   ** *  **
**   * *  *** * *      ******* *   * ** * * * *     ** ***
  ****  *  *  *  * ***   ** * * **   **   *  **  *******  ** * 
      **  *   * *  *   *****  ** * ** * **  * *  ***  
*  * *** ** *        *  *       *    * * ** **** *  ****         *  *  **      * *   *    is a prefix of %s", string2, string1);
  * *    *  *** * *** *  *   ** **      * * ******  
  ** *  **   ** *** *** *    ** **  **       *  ** **  *    *   *
  ** *    * *   *** *     ** * *  *   *  ** *   * **   
  *   *    * ** ** * *  **   **  *  * *** **  ** * * * *   *  *   ***  ***  ***  *  * * * * **  *  ***  is not a prefix of %s", string2, string1);
*   ** **** *** ***** ** ***  * * ******* *  * *  *****  **
    }
  * * ** **  *  *** *** ** * ****   ** *    **  *** * *** * **
    {
** *** * ***  * ********* *   **  ***  ** ***    *** (i=0; i<=strlen(string1)-1;i++)
****    * *  *  * *  ** *  *****  *   * * **     ** *
 * ******* *  * *     *  * * * *       **   *  ******* **** * * *   *  * ***  ** (string2[i]==string1[i])
*** * * * ** *** *  *      **** ******* * ***** *  ** *  ** ** ** * ** * *** *  
 **  *  * *   ** ******** *  * *  *****   * **  **    **   **   *  *   *****   ** **  * ******* **     *  **  *
   ***  ***  * *** * ****  **  *******  * ** **** *  ** *  ***** * ** *** *  * ** 
 *** * *** ** **** ***    *  ****   * * * * * ** *  ** 
 *** ** **  * ****  **** ***  * ** *  *  ***** * * * * ** *      *
  **    ** **  ** ***  ** * ** *** * *        **  *   ***
* * ** ** **** * ***   * **  *  *  *  * *   *  * ** *  *** ** ***  * **     ***  **   ****    * * ** is a prefix of %s", string1, string2);
*     * *       * *  *** ** ****   ***   ** **  ****    ***** *
  *   **   **  *  *  *   ** **   **  *  * * ** * **  * **
* **** ** *    **  *  **** **   ** * *  * *   ** ** ***
      * ** *    * * ***** ** * * ******* * *   *****       *  *    * ** *    ** ****   * *  ** * is not a prefix of %s", string1, string2);
** *       **  *  *   *  **** **** ******  ***  *** ** *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *** * ***  **  * *  * * **** ** ** ***  *** %s", chaine1,chaine2);
****      *  * *****  * **  **  *  
 ** * ** *** * **   *         0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
* * *  ****  *   * **  ** *  ** lenght1,lenght2,c;
* * **   ***  **  * *   *  b[100];
 * * ** *****  *  *** ** ***    a[100];
* **  * * *  ** ***   ****  d[100];
 * *  * ** ** *** * * * ****   ******  *  ****
 **    * *      **  *   ****   ****** 
***   ****  ******  *****  * * *  **    
 * *  ***     **    *   *  ** *   *** 
* *   *   **    **     *   *   * *   
* ****  *  ** * **  **** ***
**   ******* ***** **** **  * ***  ********   ** *  *  is a prefix of %s",a,b);
*  *   **  *   *******  *** * 
  * ** *    ****  * ***   * **
         *     *** * **   
   ************  ****    *   * **   *  ** * **   ** ****  *****  is not a prefix of %s",a,b);
*****  ***********  *****   * *
   **  **  * ****  *  * **   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * * ***  *  * *   
#include * *** **    *   **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 **** *       i;
**     **** ***** * **   *   *  * 
  {
** **  *    **** ***  **  * * *   *  *   A[i]!='\0' && A[i]!=B[i]   )
 ***  **   * * ***     *     *   ** ** *   * *       * **   * *  * 0;
  * * ** * * ****  * *        ** *   *   *   *     * * *  
***    * *    ****    ***  ** **   ** * ***** *    **  *    *  ***  * *  *
  }
 *** **** *** *  1;
}


int main()
{
*** **   * *  *  ** ** **  a[n],b[n],c[n];
 *   **  * * *    **  * *** *  * i;
 * ***      *  *  * ** *   *   * *    * * **     
**       * * *   *    ***  **    ******    **   **   
    * **  ** *  *  **  (aa(a,b)){
     * *  **** **     *     *  *  **    **   * *  ****  **  **  ** *  
*   *** *** * **  **** * * **       * ** * **  * *  *   *   **    * *  *    **  * *    *** 
  * *** *** *  *** *   *  ***  **  *   * *  * *  * *******  *** *      *** **   * **   * *  *** *** **** 
** * ** * **  **   **       * *    * *  **   * *** ** *  **** * **   ** ** *    * * 

* * *  ** *  ** *    *  * * ** **  ***      *  * * *  * 
  *  *  ** *  *** ********** ***  *  **** **    * * *****   *  **   is a prefix of %s",c,b);
*  *  ****   ****  * ** *   *
* ** *  **** **** * *     **
  *** ** ****    *  *  **  ******  *  *  *** * * * ** * **   ** is not a prefix of %s",a,b);
    * *   ** **  ** * ****  *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** * *** *
* * *** *   * *  *  * **  
int main (){
char ***  * * 
char *** *  
*****    **   **  string1: * *    
**  **   *    ***   **** **  *  
 *  ** **    string2: *** ** * *
* ***   ***** *   ** *    *  
   * **** *  **  **
 ** *  ***  *  ****  ********  ****  **** is   * **** of **** * *   ***    ***
else
 ** *  **** ** *********** * ** ** ** *  is not prefix of   *** *   * **  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    * *** *
#include **  *  **  * 
#include **  ****    
#include  *   **  *** *** ****
int prefix(char p[],char s[])
{
   *   ** **  ***   *** **  * *        ****
  * *  *    *  * *    * ****     *   0;
** *     *    *      *****  * if  * **   * * *** *
**  * **  * *** *   ** * * * *** 1;
  * *     *   *     *
*   *  **  *****    ***  ** *** * * 0;
}

int main()
{
* *      **  **** *   *    p[999],s[999];
*    **  ** *  **    **        * *  * *****
 *  * ***  *    *  *  * *  *  ** ***  ** 

 *** **  *  *  *  ***     *  **  
**   *   * **** *** **   *** ***  ***    * *    is a prefix of %s",p,s);
    *  **** * * **   *  
 ** ***          *  *     ** **     ***  is not a prefix of **** *    *

*** *     *  *   **  *  ** * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** * *** * ***  *
int main()
{
* * ***    ***    **    ** **    *** length1,length2,c;
 **  ** ** *    *  * **  * *  ** * a[100];
**    ** *    **   * * ***** ** b[100];
**   ** *** **  ** *  * **  d[100];
* ****** **       **  **   **   *  *       *  ***
*  *  ** * ** * **  * *** *  ***    *  * ****** * 
 ** **   *   * **  ** **  * * ****   *  
 * * **** * *  *   ******* *  * * ** ***
if (strcmp(a,d)==0)
 **** *  * ** * ** ****** **
  *  *   **  *   * **  **** *  * **  *  ** * *    **  *   *** *     is a prefix of %s",a,b);
   * * * *** * ** * *****
 **** ***  ** *   * ** *** *  **   
 * ** *   ** *        *** *  *
  ** *** *** * *   * **   ***  ***     **    **   ****** **     * is not a prefix of %s",a,b);
 **   ** * * *  *  
* * *   **  *  *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  *   **  * 
#include ***** *  **  *  * 

int prefix (char ** * * str2[])
{
*  * *** *  **   * *******     *   length=0, *     
  **  *  *** * **** 
 *  *** *   ***   ******  * * = ** ** ** **  **
 * ***   * **  **** ** ******
* ***  ** **  ***  *** ** * ** *   ** ** **
     * ***  *  * *    ****  ** * *   *  ***
*  * *** * ***  *  *  **  * *  if  * **  ****
* * *    *   *    * **          **** ** **** *  *       
**     **  *  **   * * *** *  *  **   }
* ***           *  * ***  **    
    ***   *****  *   * * *   (count == length)
 *  *   * *    **   *  **  * *****   *  1;
** ** *  * * **  * * *    **  else    *    **** 0; **   *** ** * *    * **  *
 * * *  * * *       ** * ***   * 
}
int main(void)
{
*** *  ***** ********  * *    ***    **  *  * * ** 
*          ***   *  *  * *
  *  * * * ** **   ** * * *   *  *  *       *****  *  str1, str2);

 ***  *   *****  **   *   ***** ** ****** 
 ** *   * *   ** ** {
 **    **   **  **** **     *     *  ** **** ***  *  *   *  ***  * is a prefix of   **  ***  str1, str2);
* **   ** * **  * *     *** *
* ** * *  ** *  ***  *  *     * *
*  **** * *** *  ***   **    * *  ** ***   *** * **   *     ****  * *  is not a prefix of *      *  str1, str2);

**  *  *    * **  *   ***** *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** * * ** **
#include  ***  * **  *
#include * * *** *** * *  

int main()
{
******* *     *** *  * *   prefix[100];
       *    * *** * *  word[100];
**  *   * **** **   *    ******  * ** ** * %s", prefix, word);
** * **  * *  **     * ***** i;
 ****  *  ******* *   **  **    = 0; i< strlen(prefix); ++i)
* * **  * * ** * ***  * ****
* **   *  * *     ** **  *  * *    * **  ***  ** *  * **  **   *** *  *
* ***  * * * ** * *** * ** ****   **    **** *  **  * **   * *
*** **    **    *        ** ***** *          *  *** *    **      ****  **** *  *** * ****    **  is not a prefix of %s", prefix, word);
 ****     * *   ***   ***   **  *  ******** * ***   *  * * * ****   * *  *  * ** **    *  0;
 ** **   ***** ** *   ***** *       *   *      * * *  
  *******  *  *** *** * *** *  
** ** *** * ** * *  * *  **  *** * * ***** is a prefix of %s", prefix, word);
***  **     * *   *  * ***  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  *   ***** 
#include ** ***    *  * *
#include ** * *   ****   *  

int main()
{
***** ** ** **** ** ** ** ***** prefix[100];
     ** **** * **    *** *  ** word[100];
*** **** * **  ***** *******  * * *  ** %s", prefix, word);
** * *    * *    * * **** * i;
*  **   * * ***** * * *  * *      = 0; i< strlen(prefix); ++i)
***   *** ** **** *  ****
**  * * ** ****** ** **    *  *    *  **  *    * ** **  *** *  *
** *   ***  **** *****  *  **    ******* **   * ** 
 **    *     *****   ****** ** * ** **    **    **** * * * * ** *  *** **   * ***** is not a prefix of %s", prefix, word);
**** *  *** *  *  *** *** *   * * ** *** **** * **** *  * ** *** *   *** * *    0;
*** ** *** ** ********    *  ** ************* ***** * ** *********
**  *  ** ** ** **   *  **  **  
****  *  **** ****  ** *  *   * **   *   * is a prefix of %s", prefix, word);
 * **  *     * *  **** ***   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  **          * **   
   *   * * ***   **   
 * * ** **  * **  

int main()
{
 ** * * * * ***  char  **  *
 **  *   *   char *  ** * 
*      ** *** *  ** ** * * **    ***  * *  word);
 ***  *     * ** int i;
 **  **    ** **   for(i = 0;  * * ** *  *  *  ++i)
** ** * **      {
**  *  * *      *    *   * **  * *   *   
 ****  *    * * *  * ****  {
*  *  *  * ***   ** ** * * **    * ****      * ***    **   * ***  *  is not a     of *  * **     *  word);
** * **     *   **  *** * *   ***   * *   * ***  *    0;
  *  *      *   *   **    ***   }
*  ** * *   *  }
*  ***  * *   *  **  *** ***  *   is a prefix of *  *  * *  ***  *  word);
*     * **   * * ***   0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.43
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users