1-11 Exercise 3: Prefix of a string

0 like 0 dislike
14.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 14.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*   ***  **** **  ***** * *  *
 *  *  **    ****** *  ****** *** **** ** * ** ****    * *  
    {
***   ***  **    * **  *  *** *  *** *    **** *        ** (i=0; i<=strlen(string2)-1;i++)
  ***    *** *  *     *  ******    **     *     ****** *   
**   *  *   *   **     *  **  ***  **  *  * *  ***** * ***     *   ***   **  (string2[i]==string1[i])
*     ** *  ***   * *  * ****  **   *    **  * *  *   *  * **** ** **** * ** ** 
** *  ** *  ** *  *  ******* * ** ****  **  *   *  * ** ** **          *     ****** ****** ******* *   * *     ****
* *** *  *   **** ******* **          **  **  * *    *  ** *        *  * **** *
 *    ** * **** ***** ** **** *** *****    *   ** *      
 ** * *  **  *   *   * * *****  *** ***  * ** * *  * ***   * *
** **  ** ** *** * *   *** **  *  ****  **    *   *  * 
*  * ** **   ******* ** * ***  * * *  *  **   ****  * **** ***  *  * *       * *  **  ***      *  is a prefix of %s", string2, string1);
**      * ** **   **   **   *     ***   ***   ** ***
 **  * *    ****   ***      *    * **** ****** ***   *  ***  
  * **    *** ** **** * * *  **   ** ** * ** * ** *  * **
*****   * * *  ** *  * * *       *** *         ** ***   * ** ****** ***   ** *  **  *     *** * *  is not a prefix of %s", string2, string1);
* * ******     ***  **  *         * ** ***     * *
    }
 *** *   ** * *   ** ****    ****  *** * **  *  *   
    {
  *  *  * * **** **  * **  ** **   *  * *  * * *** *     (i=0; i<=strlen(string1)-1;i++)
   * *  * *      *    *     **   ** ** *     **    ** *
**** **   *   ***    *  *    *  * * * **  ** * *  * * *  *    * ** ****      * **** (string2[i]==string1[i])
*** **  * **    **  *    * **        * *** ***      ***     **    *   ****** ** **  
***   ****  *       * **  ** *  * * * **  *    *      * ** **  *     * ***  **     ** **** * *  *  *    * *
    ** * *       **     *   **  * * *  ***  ***  ** **  *  * *  **** **  *  
    ***  ** * **  ****  *****   **    * * * **  * **  *
 *  **** * ***** **       * **  * *****   * * **   *     *   
*   *** *    * * ** *   **  ** *  * ** ** ** *    **  
 * *  ****   *  ***      * ***   ** ****** ** ** *** *  *       ** *   * *  * **    ****  ** is a prefix of %s", string1, string2);
 * *** ** * **    **  * ******  **   **  **  ****  *  ** ** **   
  ** *     * *** *****       ******   **  * ** ** *  *** *****
* *** * **  * ***   * *  * *    **  *** **  ***     
**** ** *   ** *  ** *** * ** *  ** ****  ****     * ***  **** * *  * ****  **  * * *  *  *****  is not a prefix of %s", string1, string2);
****  * ** *** *** ** * *    * **** * ** **    * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* **** ** **    **   *   **    ** * *  *****  %s", chaine1,chaine2);
*  **   ***  *    * * **** * ***   **** 
 ** ** ****  *    *   * * *** * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
******  * * ** **** **  **  *  * lenght1,lenght2,c;
 * *****  * **  **      *  * b[100];
 ****  ***** * ******  *  *   a[100];
* *  ** **  ** *****  * * *  d[100];
 *    ********* *   ******   *   *  *** * * 
**     *      **    * *** *    * ***     **
* *  ****  **     * *    **  ****  ** * *
 ****  **** *  * ** * **     * **   *** 
* **** ** * * * * ****  **    *    * 
 *  * **** * ******** ******* 
***     **  * * ** *   * * *  *     ***  **  * is a prefix of %s",a,b);
 **** * ***  * ***** * *    *
***   *  * ** * **   * * * * *
* *  *** **  ***   **  ****  ***
* ***  ** *  **       * *  **  * ** * *  *****  ***** ** ***  *    is not a prefix of %s",a,b);
**     *  * * *  *  **   *
    **  **  *** ***** **   * ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    *  ** *   
#include ** *** *    *  * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
  * *** * **** i;
   * * * ** *  *   **  ** *    *
  {
 *   *  * * ****   ***** **  *   *    **  ** * *   A[i]!='\0' && A[i]!=B[i]   )
**     * * * * * **     *     ****  * * ** ****    *** * * ** *   ***  *  *  0;
 *** ** ** ** * *** *** *  *   ****   **  **
* * **   **  ******** ** *  * *     * *   ****  **  **  **         * 
  }
 ***** * *   *    * 1;
}


int main()
{
**  * * ** *   *** ***   *   **  a[n],b[n],c[n];
** *******  *** * **  * *  i;
**  * * **** **  *** *** **  ****  **  *   ******  * 
 ** ** *    *   *****  **** ***  * ***   *** * ***
*  **  * *** ** **   **   (aa(a,b)){
 *  * **  **** *   ***    ** *      * * *   ** **  *  **  *  ***   *    
*   *  ****  ****   ** *****   *   **  *  * *     * *    **   *  * * **  * *   * ** * * ** *    
* * *    * ** ** *** ****  *  ***      **    *    * *   ** ** * *       *   *  *    **** ***** ** ** ** *  ** * ***     ** 
*  *  **   ***    *  *    *** * **  **   * *** *   **      *  ** ***   *   * **   **

**    * *  * ***    *  * *    ****   ****    *   **
 ***** ****   **    *****    *  * *****  **    *  *  **** **** * is a prefix of %s",c,b);
*  * *    *** ***    *  ** ***** **
  ** * ****     *** ** ******   *
   *****  *   ***     ** **   * * * ***** *   ***  *** *** *  * *  is not a prefix of %s",a,b);
**   **  **** *       *    * *  *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * **    ** *  
******** ***** *    * **  
int main (){
char * ****** 
char * *****
 ***  * *      string1: *   *
 * * * *    * *     * *** **  **** 
   *** * *   * string2:    *  ***
*    * * * * * *  **  
*  * * *****      
***** *  *** *    *****   *****   *  ***  * *  is *  **  *  of  *** *  *  **** *
else
   * ** * * ****   * *  *      ***  * *  is not prefix of *** * *  ***** * *****

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **   * * **  *
#include *  * ** * **** 
#include * * *        
#include * ***  *** *
int prefix(char p[],char s[])
{
 ***     * ** *****  * *  *  *** ** *    * **
     *  **** ***     **  * ****  * 0;
 * ** *** * ** * *       if  *  *  * ** *   
*  * * ****** *   *    *  * *  **     1;
  ****  *** *  *     * ***
*  *****  * ****** ***  **     0;
}

int main()
{
    ***  *   ******     p[999],s[999];
       **   *** *** ** *   *    ***
  **    **   **  ***         *  * **

 ****** *       * **** **    ** *
*********** * *  ********  *   * ********* **** is a prefix of %s",p,s);
*   *  **** ** * * 
*  ** * **** ** *    ***   * ** *  *****   is not a prefix of   ****  ** *

 ***   *******     * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    ****  *** *
int main()
{
  * ****   *   ****  ***** **   length1,length2,c;
 ***    ** *   ** * *  *   *  * *   a[100];
**  *  *   *** ****  *   * * b[100];
* **    * *** **** ****  * * * d[100];
*** *** *   **  ****      *     **  * * ** ****   * 
**** *    ********* *  ** *      *   **  **  ***    
**  * *     * ***  ***   ** * * *   *****
 * *  * **** **** * * *   * **    *  * 
if (strcmp(a,d)==0)
  *   *  **** * **  ******   *
* **  **  ** * *  *     **   ******    ** ****  *    *  ** * * *  is a prefix of %s",a,b);
*   * *  *   ** ** ** **  
 *  * *  ***  * ** * **  *** *
*  * *  ***   **  * * * * *** 
 ** *  * ** **  * ******* **  ***  *** * *** *** ** ***   * * ****   * is not a prefix of %s",a,b);
** ** *  *  ** *    *** 
   * *     **  * ***  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *****   *
#include * *     **** *    

int prefix (char  ** *   str2[])
{
* ** **  **  *****    * ** *    length=0,  * ***** 
* ****   **** *    *
* ** *     * *   *  *  * *    = *  ***  * *
**           **** * * * 
*** **  *     ** *   **   *   *  **  * ***** ** **
*  *    ******  ****  * *   *    * *****  * **
  *     ***    *  *        * ** if  * **  *  *
*   **   * *** **    * *        *  *  ****  *  ** ***   
** ****** *   * ****  * **  **** **         }
  *   *         *    **   *     * **  *
*  * **      *   *   * (count == length)
****   *   **    ** *   *   * *    *****       1;
*  * *      **   ** ***  *  else * **    * 0; ***   *  ** ***
    *    * ** *****         
}
int main(void)
{
**** ** **** **  * *  *     *  ** *    * * 
** *** *  *        ** *** *
 * ** ***** *  ** ****  *  ** ****     *  * * **  str1, str2);

** * * ** **  * **  ** *    **  *  
*  ** *   *** **  {
 ** * * *  ** **  *  ***  ** *        ****  * *** ***  *  **  ***  is a prefix of *** ****  str1, str2);
 **** * *  ****** *  *     *   
   ***   * * ** *    *  * * **
 * **  ** *   ** ***   *     * * * *  *   ****  *     ** *  * *  ** is not a prefix of * ** **   str1, str2);

      * *  *   * ** *   ******* 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include       *  **** *
#include ******  *   ***   
#include *    *     *   

int main()
{
**    ****** ******   *** prefix[100];
*  **  * * ****  * ** *** * * word[100];
    ***  *    * **  ***  **    ** **  * * %s", prefix, word);
****   ***** * * * ***    **  i;
   ****  * **         ** **    * = 0; i< strlen(prefix); ++i)
 * * *   * *    *  
***  * *   ** ***  *        *  * *** ** * * **  **** * *   * **  ** * * 
  *   ***  * * *   * *** *    ***   *  ** *   *   ****   
**  * **  ** ** ** *** ** *    *   ** *           ***  * ***  ** ***  ****  *  ****   **    is not a prefix of %s", prefix, word);
***    * ** * * * *   *** **  *     * ****      * **   ***   ****  * ** *    *  ** 0;
*    ******* ****  *   * **** *   * *** **  *  ** *     *
*   *** *   ** *  * **    
***     *  ** ** ** *    ****  *    ** * **  is a prefix of %s", prefix, word);
* * *******    ** * *   * *  ***    0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **   * *     
#include ** *  *  **     *
#include ** **** **  *  

int main()
{
 **  ***   *    *  * *    prefix[100];
*** * ******     ** * ****   word[100];
 * **  *****  ***** ******   **   * *  * %s", prefix, word);
* **    * * * * * * *    ***   i;
*    *    **  ** *  *** *  *  = 0; i< strlen(prefix); ++i)
*  *    *   **** ** *    *
 ***  *   * * *** ** * ****** **    ***   *    * *  **  **** **  
 * *****  *  *  * * **  *   *  **** * *  **  * * **
***** ***  *****  *   **   *  *  * *    **       * *  ** **  *  * ****   * **       *    *   *   ***  is not a prefix of %s", prefix, word);
**  *  ** **   *   * *    ****  ** * * **** * **   **     *** * **  **** *       **** ****** 0;
**** *  **** **   *** *** *      ** * *** *  **** * *
  ** * *** *   *  ** *  ** ** * *  
** ***  *** **  **   * *     * * ***    is a prefix of %s", prefix, word);
   *    **   ***   ** * *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 **   **** *  *   ***  
* ** *  ** ** *****  **
*  ****  * * ** *****     *

int main()
{
** *   * * * char    ** **
 ** **  *     char      ****
  * ***  ***    **   ** * *    *  ** **   word);
 *** * **    *** int i;
   * *** *****   for(i = 0;  *  *  ****  ** ** ++i)
 ***  * *   {
* * ** *   * * *   **** * *****   ** *  * **
** * ****     *        ** **** {
 * ***     **    *   ** *   *   ****    * ***  *** ***  is not a * *  of ********  * ** * word);
**  *  **  *      *** *   *  *   ** ** *** ***  0;
 *   *  * ** **       ** * }
* *  *     *** **  }
   *     ** *      *    is a prefix of  **  *       ** word);
*** ** **  ***   * * *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 20.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 13.5k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 18.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users