1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
int main (void)
{
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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*  ***** **   *     *  * **    *  0;
}
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Hidden content!
#include <stdio.h>
#include   ***   ***   *
#include    * * *  *  ***    
//#include <ctype.h>
#define n 100
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{
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}
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Hidden content!
#include   * **  *  **  * 
* ** ****   ***     * * 
int main (){
char *   *   
char   ** *     
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else
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include   *   * * *** ** ***
#include   ***    ** *** 
#include  * * **   *  * * *
#include   ** ** **  
int prefix(char p[],char s[])
{
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{
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 **  ** * * **  ** *       * 
 *  * **  *  *  ***  **  *    *****  *      is not a prefix of * **   *      

 * ***   *     * * * ******  0;
}
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Hidden content!
#include <stdio.h>
#include  **  *    *  * *
int main()
{
***     *  ** * * ** * * ** length1,length2,c;
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 *** *****    ***   ** *** ***** b[100];
 *** ** **    * **** ****   *     d[100];
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  *  *** *  *  **** * 
*   * **   ** *    0;
}
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Hidden content!
#include **     ****** **
#include ***  **  *  *

int prefix (char ***  * str2[])
{
*  *  **     *   ***** *  **   length=0,   ** *
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*** * **    * ***   **  *      * 
}
int main(void)
{
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    **    ** **   **   * ****  
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**  *  *** *    ** ** **  ** *** *   *  **   * ** * * *****    *** is not a prefix of   *       str1, str2);

  ***** * *  * ** * *****    * 0;
}
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#include * *    ** ** * 
#include *  ***  ***  ***   *  
#include *    **    ****

int main()
{
** * * *** * **   ********** ***  prefix[100];
** ** *    *  **** * ** ****  * word[100];
    *****  * **** **** **   * * **   * %s", prefix, word);
   ***  ***    * *** *** ****   i;
 * * * * ***  **  ** ** ** * * ** = 0; i< strlen(prefix); ++i)
       **   ** *        * ** *
  **  *  * **** *   **  ** **    * *  * * ****  *  *   * *  *** *** 
*****  *   * *   * * ** ***  **  * *   ******  * *****
 ****     *      **   ******* * *  * *    *  **** *      **  ** ** **   **    **** *  ** *** is not a prefix of %s", prefix, word);
***   * *  *******  *     * * *  *  *      **** *  *   *** ** *** **   *****    ** * 0;
* *  *     * **** *  *  * * * ******* *     ***  
*   ** ***    ** ***      *  *  
*** **    **  *    * *   ***        is a prefix of %s", prefix, word);
**  ** *  *      *  ** * **    0;
}
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#include    * *  *  * ***
#include   **   *  ** **
#include ** **   *   *  * 

int main()
{
*  ** *    **  *  ***  ***   ** prefix[100];
 *** *** * * **  * * * ****** word[100];
*       * *    **  *** *  * ** ** *  * %s", prefix, word);
 *  ***  **   *  **        i;
   * *  *  * *   ** ***  * ***     * = 0; i< strlen(prefix); ++i)
****  *** **  *  *    ***  
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  * **   *   *    **  *  *    *   **** ** ** ** ** ****** 
*   *  **** * *   *         *     *   *   ***   *     **   **    *   ** *    *  **  *** ** ** *  is not a prefix of %s", prefix, word);
  ** *  * *  * *******  **  *  *     ** ******  ****    ***   * * * * * ****  **** **  *** * 0;
 * *       ***  ****   ***   *  * *    *  ** * ***     * ***  
  ****** *  ** **     * 
* ** * *** **  * ** **  ***  ** ** *  * is a prefix of %s", prefix, word);
        ****  ***  ** ***  *  *  * 0;
}
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  *    ***** *  *  *  * *
 ***  ***  *  * *   *** ** *
* ** * *  *  *****  **   

int main()
{
***    *   * *  char *   * * 
   ** *  *  * char  ** 
*         ***  * *      ** **   * *** *   word);
* * * * * *  * int i;
**  * *  *     for(i = 0;  *  ***    ** *    * ++i)
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 *   ** *     **      * *   *** * * *   ****  ** 
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** **  *   ** ** *    **    *** **   *   *  **     ** * is not a *   of ***     **  *** word);
**   **     **     **** ** ** *  * **   *    *  ** * 0;
 **  *   **   ***        * * * **  }
   ****     *  }
 * **** * **      ***** * ** is a prefix of   * **  *  ** *  word);
**  *    **     * * 0;
}
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