1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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{
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include **  **   * ***** 
#include   * *  *  *     *
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}
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Hidden content!
#include *      ** * * *** *
***    *  *  *   * *
int main (){
char *** ** 
char ***  **  * 
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include *  *      * ** ** * *
#include ** ***** ** *
#include * *** ****   *  *
#include    *  *  ****** 
int prefix(char p[],char s[])
{
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   *     * *   * **** * *  0;
}
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#include <stdio.h>
#include  *     *   **  *  
int main()
{
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}
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Hidden content!
#include **   *  ***** **
#include * ***  **** *  

int prefix (char  * *     str2[])
{
* ***** *** *  * **   *** * *   length=0,  *  
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* * **    * * ** *  *  *****   0;
}
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#include ****** ***   * *
#include    *** * * * 
#include  ********      *

int main()
{
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*    ******   *  * ** * ** **  * *  * * * is a prefix of %s", prefix, word);
 *** * * ** *     *** **   * *   0;
}
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Hidden content!
#include  * *    * *****
#include ****  *   *     *
#include *    ****  ** *

int main()
{
** ***  * ** ****  *******    prefix[100];
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* ** * * *     *   *** * ***  0;
}
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*  * * ***** **** ** 
* **      ***  *   * ***
  *** *  ****    * **

int main()
{
*  ****  * *  *   char   **  * **
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*    * * **  *    * 0;
}
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