1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
   *      * * ** *  ****  ***** ***  
 *   ***   **** ***     ** * *** * *  *  ** * *  **   **
    {
*  **  *** ****  * ** **** **  *  **  *  *  **      **  * * * (i=0; i<=strlen(string2)-1;i++)
     *   ** ****  * ***   *  * ** * *  ***  ***  ****
   *     *** * ***    *     *     * *  *** *   **  ******* *** *  *    ****** * (string2[i]==string1[i])
 **       * * **  **    * *  ** *** *  * **     **  ***   **   * * **** ***
* **** *** ****  *  * ** *    *** *****  * *****  * **   ** ** **   *** **   **** **  ** *   **   *  * ***     **  *  ****
    ***        ** *   ***  * * ***  * *  *  *   *     *  *  *  ***  *   *  *  **   *    **
  * *   **  * ** *      **   ***  *** ***    **   *
 **      *  **   **** *** ***   *   ****  ****   * ******* *   *
*** *** *  *     * * * **     * **      * *     **** * *  
**** * *    **  **  * *    *** * **********  **  * *    *  * ***  *  *  *******    **    ****  is a prefix of %s", string2, string1);
*  * *  **    **  ** ** * * *** ** *  **  *    *  
 ***** *  * *     **** ***     *    *   *** *  ***  *
  **** ** **  *** ****** *   *** **   *  * ** ** ** 
*  *  *  ***** *      ** **  *  **      * * *   ***  ** *****   * *  *    ** **  * ****  *       is not a prefix of %s", string2, string1);
*** **** **** ***** *** *** *     * * **   **  * ** ******
    }
 *** * * ** * *  **   **   ****** ******* ** ****
    {
*  *****  * *   *****   * **** *    * *    *     ** ***  **  ** * (i=0; i<=strlen(string1)-1;i++)
*   ** ***  * *   **  ** ** *    **  * *  **** * ***  *  ***  
     ** * ** ** **  **  * *  *******  **  *    * **** **    ***  *   **** **   * *** (string2[i]==string1[i])
** *** * * ****   *      *    ** ** **  * *   ** **  **      *    
* **      ** ***  ** *  ** ** ***     *  * *** *** **     *   **** *  * *    ****   ** ***   *** *  * * *
** ***    *  ****  *   **  * * **** * * * **   * *    *  *  ****   ** *** * * *  **
  * ***  **  **** * * *** ** ** ******   ****    ***   *  **
*    *  *** **  * * *     ***  * *       *    *    *** **
*   ****  * * **     **** * **  * **** *   **   **
  *  *       ** * ******    *** ***    * * *  ****    *  **** *       * ** * *   ***  **   is a prefix of %s", string1, string2);
  ** **  *  *    ***  *  ***  * **   ** **  *   **   * 
 * * **   **  **** *** *****  ***  *** * **  **   **  * ** *
 * **  * * **********       **   * **** ** **  **  * *    **** *
* ******  * ****   ** * * *    *** * **  *  **** *   * *    * * ******  * *  *****  *  ***    is not a prefix of %s", string1, string2);
 * *  **  ******* *** ****   *  ****  ** ** **    * * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
***** * *** **    **  * **** * * **     %s", chaine1,chaine2);
**  **    * **  * * * * *  * *     * *  **   
*     *** ****  **  *  *** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
***   *    *   *** ** *** *  *   lenght1,lenght2,c;
***  **  **  ** *  *   b[100];
** **  ******    * ***  * ** *  *** *  a[100];
** **  *** * *  **  *   *** * **  d[100];
*** * * **  * ***  *** *** *  *      ** **   *
  *   ***    ** * ** *  *       ****     ****
** * *  **   *********  **           
  *   **** ****** *    *** *       *   **
** *    *      ****     * *  **   *   *
* * *    ***       *****    * *
*** **    * ** **   * ****  *  * **** * **** ***          is a prefix of %s",a,b);
**   * *   * ** *  *   * *
**   *   **    *   *****   * * 
 **   ****  * ** *  ** **** 
  * *  **   ***  *  * ****** * * **   * * **  *  **  **  *  *     is not a prefix of %s",a,b);
*  * * * **        **** * **** 
  * ** * ** **** * *   ** *** *   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * **** ****    
#include * * ****    * ***
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
   *** ** ** * * i;
****  * * * *  * *********  *  
  {
   ** **  *  **  *  ***         *****    **  *  A[i]!='\0' && A[i]!=B[i]   )
*  * *   *   **   **** ***  **** ***  *** * ** *   * *   ****   ** 0;
*  ***** *****  *   *    **  *     * *** *  *****  ** *
*  **  * **   **** *** ** *   *** ** *   *   * *  ***   **** * * ******** * *  
  }
 **  *       *** 1;
}


int main()
{
 *  ****** *  *** * *  * a[n],b[n],c[n];
*** *  * *  ***** **  *   i;
   * *** *  *  **   **  * * **  * ****** *   *  **  
*    * ***  * ***  ****      **   *  * **  *  *****  
*****  **    *     * *  ** (aa(a,b)){
*  ** * **** ** * ** * *** * * **    **** * *  * * *  * **      ****   
  *  ** ** * **      * **    *   *** **  *  * **  ***  * * * ** * ** * * * *       *   **** ** ** * *
 ** **  **  * * ** *     ***   ** *****  * * *  ** * *  ***    ** **  ***  *  *  * ***   ** * ***  **** *   
  ***  ***  * ** *  *    *  * * *** *      **** * ****** *   ** ** **  ** **    

 *      ** * * **** **   *  * **    **** *    ** ***  * ** 
* **       **  *   ***** ** **      * ***   *** **  * ** * *  **      *    is a prefix of %s",c,b);
 *    ******      *  * *  *
*    * * *  **  * **   **  **  *****
*  ******  **** ****    * ** ** *      ***  **   ** ***  *** * is not a prefix of %s",a,b);
 **   ** *   *   **** ** *   * *  **  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **  **** * * 
* ***    * ** * ***  *
int main (){
char  *** *  **
char * *****  *
***  *  ***** string1:     ***
* *****   * *   **** *     * ****
   ** *  ** ** **   string2: ** ***   
* * * ** *  *  *  * *   ****
 ** * *  * *        
*   * *** ** * * **  **  ** * **  **    * is *  ** **** of ***   **    ****  * 
else
***  ****   *   ****  *        *** *  * is not prefix of *  ** *  **** **   * *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *** *     *** 
#include    **   * ***  
#include    ***   * ***
#include   **   * *  * *
int prefix(char p[],char s[])
{
 ** *    **    * ***    *****  *** **  **
    * *** * ** *** *   *** ** 0;
 *    * *      * * *  *   if  **    *  ******* 
*        ** *   ***  **** * 1;
* * ** *** *   * *  ***
  ***    * ********  * ***  *   0;
}

int main()
{
   ** **  ***  ** ** *****   p[999],s[999];
  ** *    *     **  *  ******* **   * *  ****
  * *  *  **   ** ***   * * **  ** ***   *    **

  ***   *** **      **  ** ** *  
    ****  *   *  ***  * ** **   **** ***  is a prefix of %s",p,s);
  **** * * * ***    *   
* *  *** **** *   *   ****   *  **   * is not a prefix of   ****  *  *

* *  * *    *  *   **    ** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * * ** ** ****
int main()
{
    * * ********* *** * *** **** length1,length2,c;
* ***   *   ** *** ******   **** a[100];
 * * * *** ** ** *  *****  * b[100];
***  ***  ****** * *  **  **** ** d[100];
 *  ***  *  **  ****  *** * **   **** * * * * *  
*****  *** *  * *     *  **  ***** * ** ***    ** **
*****           * * * **      ** **  * *  *
*   ** ** *   *  * * ****  **  ** * * *
if (strcmp(a,d)==0)
 *   *** ** ***  ***      
 * *    *   **   ** **** * *     **  **   * * *  ****      ***    is a prefix of %s",a,b);
**** * ** *  *****  *  
   *    *  * * * **   **** 
    **        * **    ****
* *   *  ***  * ***  * **** ** * * * ** *  *  *** * ** *      **  is not a prefix of %s",a,b);
 * * ***   ** *   *** ****
 * ***  *     *  *** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *  *  *** ** * 
#include **  * * **    *

int prefix (char * ***   str2[])
{
 **  *    *  * ** **  * * length=0,  *  *
 * *   **    *    * *  *
** * * **   *  * **   * * * ** =  *    * ** * *
*  * * * *  *     ** *******
*** **   *      *** *** *   *   **    * * *
* * **   *  *    ** *  ***** **  ** **   *
*** *** ****     * * * ***  *  if **    ** **  **
**  **   * **   * * * * *         *   * **  *    *  *  ***  
  *  *  ** ****   ** * ****    ***   }
* *            *      **  *   
    *   *     *  ** (count == length)
* **  * *  **** **   *  ***    *  *  ** 1;
    ** * *   *** *  * *  * else   **  *   0;   ******  **     **  *
**   ** *  **** * * * ** ** *  *  
}
int main(void)
{
  * ***     **   * *****     *    *
 * **** * * * ****   *** * **
*****  *  ** ******   * ******* *  ***  *** **** * str1, str2);

***  *** *     *  *** *      **   * *       
    *  *  * * {
  * *  *  **    **  * ****** * *******   * ** ** *     *   *****     * is a prefix of  **   ** str1, str2);
* *     ***    *** * ** ***
 *** *   ***  *  ** *****    *
*   ** *  *   * *****  *** * **  * ******  **  **        **  *** is not a prefix of  *** **  str1, str2);

 *  ****  ****     **    * ** * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  ***  *    ***
#include  * ********    
#include       ** * * 

int main()
{
* *** *  *       **  **   **  * prefix[100];
 ** * * * *   ***      *  ***  *   word[100];
*   * * ****        **** *  *  * *  %s", prefix, word);
*  ***** ***** ** **     *  *   i;
**     * *   *  *   *** *****  = 0; i< strlen(prefix); ++i)
** ** *      **  *   **      
* *   *  **   *****    * *         * ** *   *  ** * ** ** ** *  *   *  ** *
  *     **** * **  ** ** *  * *  **** *   * **   
*** ** * ** ** * **   *** **  * ** * **  *** **** *** **  **** **  *   *  *** *     ** ** *   is not a prefix of %s", prefix, word);
**   *  ***  *  * * *** *    ************* ** ****    **** **  ***  *  *  * 0;
    ****  *    ** ***   *  ** **** ** *    * * ** **  *  *
      **    ***  **  ** *  
 *   ** **   ** *  *  ** *  * *  * ** * * is a prefix of %s", prefix, word);
* * **   ****   ******   *  **  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **  *  ** * 
#include   **  ** *  
#include *  * *  * **** * 

int main()
{
*  *  * *  **** * *****  *  prefix[100];
* *    * * ** ** * **  ****   word[100];
*  ***  *****   *  ** *  **** *  * %s", prefix, word);
*** * **** *     ***   *  i;
** *  ****   ***  *  ** *  *   = 0; i< strlen(prefix); ++i)
***  * *** *****  **** * **
* *   ** **  *  *  **** ** * **   *     ******* **  *  **  *  ****   **
 * *  *     *  * * *    *   *   ***   *      * *       
*  *  * * ***   * * *  **    * **  * *   * ** **   * *   *   ****  ** * *      is not a prefix of %s", prefix, word);
 * * *  * *  *  * *  *** *   * * ***  *  **    **   ****** **  * * *  * *  0;
  *  * * *    *  **  *  *     ** ** * * * **  *    
 * *     * *** **  **  * *
*** * **** **   *** *     * * ***    is a prefix of %s", prefix, word);
 *** * * *  **    ****    ***  **  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   *   *     * * * ***
  *       ***  **   *
 *  *      *     **   

int main()
{
 *   * ** *    * char  **   * *  *
* *     **    char  *    * 
*  **  *   * **  *  ** **   **  ** ** *   ***  word);
**  * * ** *  int i;
  **  ***   **** for(i = 0; *  ** *  * *  *    ++i)
 ***   *       {
  *  ****  *****   *   *    ** *  *  * ****   * ** 
**  **  *    * **  *    * ***  * {
 *  * *  ***    *     ****    * * * * *     *   * ***  *   is not a ** ** of * * *****   word);
  * *      ** *   * ***     * **   *** * *      **      * 0;
 **  *  * * * **  **    *      }
 ***** ***  ***  }
** *  *    * **   ***     is a prefix of **** * *        word);
***** *      *  *   ***  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.3k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users