1-11 Exercise 3: Prefix of a string

0 like 0 dislike
4.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 4.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
* ** *  **  ***** **  ** ** 
  *  *  * **  **  ****** *  ** **      ****  *** * ** * * 
    {
   *** ****  **  **   *** *  *** * **  ****** **  *  (i=0; i<=strlen(string2)-1;i++)
 * **** *** *** ***  **  ***  ***   *  *   **  **  **    * **
* * *    ***   ****** *    *     * *  ***  *  * ** **  * *  *  ***** *** * *** (string2[i]==string1[i])
 * *   *** *    **** ** ***    *    *    ******    *** * **  ***** *** ***     **
* *    **** ****      ****  ***   *  *  ***     **** ***   * * *   ****** *  *   *** ** * ** ** * *  ** *
*** *   * **  *** * *** **     ***  *  ***** ***  *** * ***    *   *** *** * *  ** * ***     
  * *  *  * *   * ***   **   * ** ***  * *** *** *   *
**** ***  **   **   * * ** ****  *  ***       *   *  *  *    *  
 ****    *  **  **  ** **  *  **          * * **** ** 
*   ****** *******  ** **   ***** * *   *  * *    * *  * ****   * *   * ****  **  * **  is a prefix of %s", string2, string1);
** * **   ***   ** * **  *******  *** ** *  ***** ** 
    *   **   * ** **  ** **   * * *****  * ** * ** * **
* **  ** * *   ***   ** * **  ** ** ***     **        ** 
 * ** * **** ** ****  * *** *     *       * *   *  * * **  ****  * *** *   * *   *  *  * **   is not a prefix of %s", string2, string1);
*    * * **   *  ***** **  *  **     *  * *** **** * *  
    }
    * ***   ** * ***   * *      **  *     **  **  * **  *     **  
    {
 ***   ***  ** * * ** ** * * ***   ** *     ***** *** (i=0; i<=strlen(string1)-1;i++)
  * ***  **     ****      * ** * *** *** *   *  *
**  **  *  *** *  * ** **  ** *** **   * **    *    ** *  ****   *   **    **    (string2[i]==string1[i])
 ** **    **  *    *** *   *  ** ***  *  **  *  ** * ** * * * *  ****    *     **  * 
** **    **  **    *      * ** * *   *   * ***     * * *   * * **        *  *  *******  ***  *  ** *  **    *  
* ** * *  *   * * * **  * *     *  ***  * **** ****   *   ** **  *    *      * **
 *** *  *   * **  * **    *  *  **     *  * * ***** *  
****    * *    **  *  **  * **     ***  *   ** *** * ** *  
 ***     * **   **** **  ***   * *  ** *  *  **  *   *
   **** * **** **       *     * * ** **   ***** * *    * ***   ****** **** ***  ** * **** is a prefix of %s", string1, string2);
*   *******   * ***     *  *      *** ** ****   *
* ***     *    *** *   **** **** ***      *****   ** *
***** **  * *  ** *     ***    ** **    ** ***  * *     ** 
      * ** * *   *    **       **    **  *  **** *****  *   * ** * ** *       * ** ** *****  ****** is not a prefix of %s", string1, string2);
****   *      * *  **  *  * * *    *** * * **         *   **
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 ***  **  *  *   **  ** *  *   ** *** %s", chaine1,chaine2);
* *  *  *  *   **    *   * ****** *** ** 
**  *     ** *      ** *   ** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 * * *  **** * ** ** ***      lenght1,lenght2,c;
   * *  *   * *    * ****  *  b[100];
*****   *  *  *  **** *  * *   a[100];
  ** * *  * *    *    ** * d[100];
 *****  * *  ** *** ** ** *        * ** * *  ***  * *   
  ** * ****    *  * ***    * **** ** *** * *  ** 
  *** * *** ** *  ***   *   ****   * **
*    **      * *****  * **  ***** 
*** *    ** ** ***  *  *  ***   **  *
**  ***** *   *  *  * * *
* *** *  * ****     ***     **** **** **  *          *  * is a prefix of %s",a,b);
**   **   ******  ***  ***  *
 ** *** ****** * *   **
 **  *   *** *   ** * ***
 *      * *       ** ******* *  *** *   **   ****   *  *  * is not a prefix of %s",a,b);
** ** ******* **    * * ***
** * * *** *  **** *** * ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** *  **  ***
#include ** **   * **    ***  *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
**   *    *    ** i;
  *  * ***  * * ** ** *** **
  {
  * ** *     **  ** *** ***     ***     A[i]!='\0' && A[i]!=B[i]   )
* *** **  **   **   * ***    **  *   ****  **    ** * *     *  *** ****  0;
**  * *  *  *    *  ******  **   *  ** * *  ***    *** * 
*** * *  *** * ** *  *  *   * **   **  *      *     **    * *      ******** 
  }
** ***** ** *  1;
}


int main()
{
***  * **** **  ***  **         a[n],b[n],c[n];
*   **** * ** ***** *** i;
 ** **  *   ** *** ** * * *  *  * * * *   ** * **  
 ** ***  *  **   * **  * *****  * *  * * ***     **
*  ** *** *  ******* * * *   (aa(a,b)){
 *** *****   * *  ** * *     *  **  **********   **        **  ** ******
*   **** * * ** * *    *** * ****   ** * **   **  *  ** **   *   * *     * **   ***   **** 
 * ***  *** * *  ***   **    * **  **** *** ** **  **** ** *   ***   **** * *  ******** ** **  * * * **** *  *  * *   *    
*** *  * *  *  * *      ** * *******   ***  * *   *  *    **   * *** * * * *

** **   *  *  * ** * * *******   *  ****   *   ** **    *** 
     ** *     **   ***** ** **  ** **   * *  ** *** ***  ** ***  * * ** is a prefix of %s",c,b);
 *   ** **  ***************  ** 
   ** * *   *  *      *  *
**  * *** * * ***     * ** ***   * ** *  *  ****  *  * ** *  * ***    is not a prefix of %s",a,b);
 * **** * * * *** ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *   * **  ***
**** ***   * *  *    *  
int main (){
char *** ** 
char **   *** 
    **   *  **** string1:       
 * * ** *  *  * * *  **  *    
* *** ***** ** * string2:    * * * * 
** ******   *  * ***   *** ****
 ** * *  *   ***   **** 
 **  **  *   *  **    ** *  * *     *    *** is  ****   *  of  *** *  *      * ****
else
***** *    *     **   *  **   *  **    is not prefix of   ***   *    * *  *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *        ***  
#include ***   * * *  * *  
#include * *****  ***   
#include **   ****   * *****
int prefix(char p[],char s[])
{
 ** ****   ** *  *   **** **** *   **  *
*** *  **  * * ** *** * * ** ** ** 0;
* *   *** *** ******     if *** *   *        
** *    *  **  *** **     ****  1;
*****  *        * **   
 * * *** **   *    *****  ** *  0;
}

int main()
{
* * *   ** ** ***  ** p[999],s[999];
** *** * ***** **  *  ***    *  *  *******
      * *** **  *   * ***  **   **   * **

 *** *      *** * *      *   ** 
* ** ** *  * *  * *      **     * *  *** * is a prefix of %s",p,s);
      ***  **   * ** 
     ** *** **  ** * * ** *   ** *    * is not a prefix of ***** *  * ***

* **** *  *  *  *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **      *    *  * 
int main()
{
 *  ***  **  * *** **    length1,length2,c;
 * *  *** *** ** **      a[100];
* **    **   * *   * *    **** b[100];
 *     ** * *  ****  *   *  * *** d[100];
 **  ****  **   ****    *   * **     * **  **
 * ******* * *  * **  * ***    **   *    **  ** 
 **** ** *  ***   * * * ** *  * **    
** *** * **    *     * * * * * **    ***
if (strcmp(a,d)==0)
*    ** ** * * *   **  *  *
 * *  *        **      **** ** *    *** **  *   *   **  **   *  *   * is a prefix of %s",a,b);
 ***  **   ****** * *** **   *  *
    * *  *   *  **  *  **  * **
*   *** *  *   **        
  * * *  **   *  ** **** *   ** ** **** ******      **  *  *  is not a prefix of %s",a,b);
** *  *  * ** *  *** ** *** * 
 ** ***  **  **** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *  *   *** **
#include   ***   * ***  

int prefix (char ** ** * str2[])
{
 *     *****  **  ** * **  *** length=0,  * **
 *   * *** *   ** * 
 *** *  **     * ** *****  ***    = *** * *** *   **  *
**** * * *****  **  
 * ***   *    **  * ****   *    ***   *  *     
 *  **        *  *      ** * * ** * ***   *
**  *    *    * **    *** ***   if        *    * 
  *        **** * *  * *          * *  * * * * ****   ***   
 * *   **** ** ** * ** *       }
*** *   *          ** ***   ***** **  *  
 **** *      **** * * *** * (count == length)
     *      * *  ******* ***    *     * ** * 1;
*   *  * ***** **  **  ** ** else     **    0; ***  *****  ** ** *
  * *    * *** ***  *  **   
}
int main(void)
{
 *** ** ** *  *  * * * ****** ****      *   * *  
****  *  ** * ** *** *** ** *  
     *     ** ** * *      *******  *   * * str1, str2);

 *** * *** *** **   * *  **  ** *  
** ***  *    ** {
* ****** ***   *** *****  * ***   ** ****  * *** **  * * is a prefix of   * * *  str1, str2);
 * * *  **** * **  **** * *
 *  *** * *** **  *     * * 
  *** * ******  *  **  *** *  *   **** *     * *** ***  * * * * * is not a prefix of ****** ** str1, str2);

********   ***  *  * ** * *    * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **    ** *  * **
#include  ** *  ***      
#include   *   ******* ***

int main()
{
*  **  **  * * * * *  **   ***   prefix[100];
  ** * * * ****  *     *  *  word[100];
 * * **** *    ** **   ** ** * *    **** %s", prefix, word);
  **   *  *   * *  * * ** ** *  i;
* *   * * ***     **  * ***** = 0; i< strlen(prefix); ++i)
  *    * *      **   **** *  
**   *** * ***   *   *     *** **         *    ***  *** ******      * ** *
 *   *  * ***   *   **  *  ***  *  * * ** * *   *
 *** **** ***  ***  ***  *******    *  ** **   * ** ** * * ** * *  * * * *   * *   **   **    * is not a prefix of %s", prefix, word);
 *    ** * ******** ** ** **  * *** *    *    ** *   ** * *****  *** * *****    0;
**  * **  ***     **** ** ***********     *    *  * * **
  * * * * **   ********  * 
**  * * *     *  **** ***    **   ** *  is a prefix of %s", prefix, word);
*** * * * **    * *****   * * *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **     *   * 
#include ****   *    * 
#include *****       *

int main()
{
 *** *    *  * * *  **  * prefix[100];
* * *** * * **   * * *****  **  word[100];
** * ****    * * **    *     ****   ***   %s", prefix, word);
**  ** * *   *  ***   *  **   i;
  **  **   *** ** *  ***  *  *** = 0; i< strlen(prefix); ++i)
***** **********    * **      
***  ***       ***   ** ** * * *   ****** * *  ****    * *  **  *  **       
*   *** *** *** *  ** *  * * * *  ***** *  **  * * 
* *   * *       *   **  *** *** *** *  *** *   * ** *           * *     * * ** *   ** **** * is not a prefix of %s", prefix, word);
*****  **   **  *  *     * **** *   * ***** *** * **   ***** *  **   * *  * **   *  0;
**   ****   * ***  ** ** * *** *** *** *     * ** * **
***   ** ***  *    * * *  *  **
 * * **    ** * * **  * **** *   * * * * is a prefix of %s", prefix, word);
  **  **  ** **** * **** *  * **  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *  * ** * *  * * 
***   * *****       
   ****  ****  * * *  * 

int main()
{
    * **  ** char **   
 * * ***  *   * char       
  *    **  * *     *    ** * * ***      *  * word);
* * *     *  int i;
**  *     *   * for(i = 0; **   *  *   *  * ++i)
  ***  *  ** *** {
**  *  * **  * * *         *   **  *  * * * ** *
** *  *    **** * * *** *     * {
* *    ** *   ***            ****   **  **    * ** *    is not a  *** of  ******    ** word);
**        *** * *  * ** *  ** *   *** * ** * **  **  0;
**       *  ** *   **  * ** *** }
**** *  *  * * }
*     **  *** * * * *   ** is a prefix of    **   * * * **** word);
   *    *     ***** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.46
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 5.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 5.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users