0 like 0 dislike
7.3k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 7.3k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include * * **
#include * * * ***
#include ** ** ** **
int * ** ** a[],char b[])
{
** ***** * * * * first[26] = {0}, second[26] = {0}, c = 0;
*** * *
* * * * * * ** * ** frequency of * * ** in first string
*** *
* * ***** **** * **** * * (a[c] != '\0')
*** * * ** *** **
* **** ***** **** ** * * *** ***** * ***** *
* **** ** ** **** ** **** *
* **** ** * ** * *
** **
* ****** ** ** = 0;
* ***
* ** ** * * ** (b[c] != '\0')
* * * ** * **** ***
*** ** * * ** ** **** ** *** * * ** **** * **
***** *** * ** * **** * **
*** * ** *
** ***
* * ** *** ** *** * Comparing frequency of **** *
** ***
* ********** * *** * * (c = 0; c < 26; c++)
* ** * * *********
*** * * * * ****** ** * * * *** (first[c] != second[c])
** * * * ** * ** **** ** * * * * *** * * ** *** * 0;
** **** *** *
*
*** * *** *** 1;
}

int ****
{
***** * * ** * * *
**** * ** * ** * *** ** * * * A,B);
* * ** *** * ** ** ** * ** * *** words or phrases are * * * *
* **** *** ******* * ***** *** words or phrases are not *** * ** ** *

*** * ** *** ** ***** * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * **** ***
#include * * * * ***
#include * * *** ** **
int * * **** ** a[],char b[])
{
*** *** * ** first[26] = {0}, second[26] = {0}, c = 0;
** * * *
*** * ** * ** * **** * frequency of characters in first string
***
** * * * * ** * (a[c] != '\0')
* ** ** * ** **
* *** ***** * ****** * * ****** *** * **
* ** * ** **** ** *** * ** *
* * ** **** * * * ***
* *** **
* *** ****** * = 0;
* *** *
* * ** ** **** ** ** (b[c] != '\0')
* * ** ** * *** **
**** ** * * * ** * ** ** **** **
** * * * * ** *** *** **** * * **
** ** **** * * * * *
*** ***
** *** * * * Comparing frequency of * * *
* * *
* ** * ******* (c = 0; c < 26; c++)
* * * * **
**** ** * ** * * **** *** ** (first[c] != **
* * **** * * *** *** ** ** ** * * * * ******** * **** * * 0;
* * *** *
** **
**** * * ** ** * 1;
}

int main(void)
{
** **** ** ** ** * * ****
* * **** * *** *** * *** * * *** * ** *
** * ** ** **** **** ** * *** *** ** words or phrases are ** **** *****
* * ** **** *** ** * ** ** * words or phrases are not * ***** * * * *

* ** * * ** ** **** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include ******* *
#include ** ** *
#include ** *** **
int is_anagrams(char A[],char B[])
{
** * ** ** ** * YOUR CODE HERE*/
** * ** * **** ** *** * *** *
* ** * ******** ** * * *** *** *** *
******* * * * * * * ***
* * * ****** * * * * ** * ** * * *** * * * *** * && * **** ** * **
* * ** ******* * ** ******* * * * * * ** ** * * ****** * *** *** * **** **
* * ** * * * ** * * **** ** **** ***** * * * * *** * && ** * ****** **
** * * *** * **** * * *** * ** * *** ** * * **** * * *** * * *** * ** *****
* * ** * * * *** *
***** ** ** * * * * * * * ** *** **
*** * * * *** * *****
** * * ** * ** ** **** * ***** * (cA[i]!=cB[i])
* ******* *** ** *** ** ****** ** * * * ** * * * ** *** 0;
*** ***** ** *** *
** * * *** * ***** * *** * 1;
** * *** * *** * OF YOUR CODE*/
**** ** ****** ** * * function should return 1 if two words or phrases are anagrams,
* * * * *** * if two words or phrases are not anagrams.
}

int main(void)
{
* ** ** ***** A[100],B[100];
* ** ** **** ** ** **** YOUR CODE HERE*/
* *** ***** * * *** * ** * ** * * * * * *
* ** ****** ** ** ** ** ** * *** * * ******
*** * ** * ** ** **** (is_anagrams(A,B))
*** ** ** ** * ** * *** * * * ******* * * * ** ** * * * words or phrases are anagrams");
* **** * ** ** *** * * *
** * **** ** **** ***** * * * ** * **** * * ** ** words or phrases are not anagrams");
** * ** ** **** 0;
*** ** ** *** ** ** * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* *** ** * ** * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* ** * **** **
* ** * * * * * ** * ** * (A[i] != '\0')
* * * **** ** * ***
* * * * * *** ** ** * ** ** **** ** * **** * ** *** ** *
****** * ** ********* ** ** * ** ****** * ** *
* * * *** * * * **
* * * * * ***
** * ***** **** ** ** = 0;
** * ** *** * ** ** * * ** *
** * * ** * * ** **** (B[i] != '\0')
* * **** * * * **
* ** ** *** * **** *** **** ** ** * * * *** ** * *** *****
** * * * * *** * * * * **** * * ******
*** * ** *** **** *** **
    
* ** * * * ** ** * * (i = 0; i < 26; i++)
**** ** ** **** ** **
** ** * * ***** ** ***** * * * * * ** * * **** **** (Array1[i] != Array2[i])
* *** * * * * * ** * * * ******** * ** * * * * * * * ** ** ***** ** 0;
* * ** * ******* *
* ** * * * *** * *
* * *** *** * *** ** * * 1;
}

int main()
{
***** * ** ** * ****** A[100],B[100];

** *** * ** **** ** ** * **** ***
** * *** ** * * ** * **
** *** ** * * **
* ** * * ** * * (is_anagrams(A,B))
* * * * * ***
* * * * * * **** ** * ********** * ****** * ** * **** words or phrases are anagrams");
* * * * ***** *****
* ** * ***** * * ** *** * printf("Two words or phrases are not anagrams");
* * **** * ** * *** *
* *** ***** * * **** *** * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
* **** ***** ** * * **** Array1[26] = {0}, Array2[26] = {0}, i = 0;
* * * * *** ** *
** **** *** ** ** * ** * (A[i] != '\0')
* * *** * ** *** * **
* ** ***** ** ** * ** ** ** * * **** ** **** *
* * ** ** ** * ** ** * * ** * ** * *
** * * * ** ** **** *
* * * **** * ** ***** ***
* * * * *** ***** ** = 0;
** ** * ***** ** ***
**** * * ** * * *** (B[i] != '\0')
* ** ******* * * ** *
*** * * ** * * * ** **** * * * ** ** *** ** * **
** * * *** * ** * ** ** **** * * *
* ** *** *** ** * * *******
    
* ** * ** * * ** *** * (i = 0; i < 26; i++)
** ** *** ** ***
* * * ** * * * * ** *** * * *** * ** (Array1[i] != Array2[i])
* * * *** *** ** ** * ** * ** * ** * * * * * ** * * * * 0;
**** * ** ** ***** ** *
* ** * *** ** * ***
** * ** **** ******* 1;
}

int main()
{
* * *** *** ** * * * A[100],B[100];

** **** * **** * ***** ** * *** *** ** * * ** ****
* ** * * * * * * * * *** **** ** *
** * * ** *********** * *
* **** * ** * * * ** (is_anagrams(A,B))
** *** * * *
* ** * * ** * * ** ** * * ** * ** ** * * * * words or phrases are anagrams");
*** * **** * * ***
* ** ** * * * * *** * printf("Two words or phrases are not anagrams");
* * * ** * * **** *
**** ** * * * * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * *
#include * * *** * *
#include * * **
int is_anagrams(char A[],char B[])
{
** * *** * *** ** ** * lenA = strlen(A),lenB = strlen(B);
** * * * * **** ***** != lenB)
**** ** **** * * ** ** ** * * * * * ** * * *** 0;

** * ** ********** * * * i,j,k,a[26] ={0},b[26] = {0};
* ** ** ** * * * * ******** = 0 ; i < lenA ; i++)
** ******** *** * * ** * * ***
* ** ** ** *** * * ** * *** * ** *** ***** = 0 ; j < 26 ; j++)
** * * * * * ** ** **** * **** ** ***** * * ** ** *
* * * * ** * ** ** * * ** ** **** *** ** ********** * ** == A[i] || 'A'+j == A[i])
**** * ** *** * *** * * * * * * *** ** * * ** * ** ** **** * *** * * ** *****
* **** * * * ** *** ***** ** ****** ** *
********* * ***** * *
* ** ** * *** *** ** = 0 ; i < lenB ; i++)
****** * *** ** **** * *
*** *** * * * * * **** * *** ** *** * * * *** = 0 ; j < 26 ; j++)
** *** *** *** * * ** ** ******* * ** * * * * ** *
** * * * * ** *** * ** * ******* ** * * ** ** ** *** * *** == B[i] || 'A'+j == B[i])
* **** * ** * * *** * ** ** ** **** ***** ** * ** ******* * * * * * * * * * * * *
* *** ** * **** **** ***** * ** ** ** * **** **** * *
** * * * ** ** * ** * *
**** **** *** ** * = 0 ; j < 26 ; j++)
* * * *** *** ** ****
* * ** ** *** * * * **** * * * * * ** *** *** != b[j])
* * *** *** * *** *** * ** * * * ** * * ** * * * **** * * * * *** 0;
**** * * **** ** * ** *
** ** * * *** * 1;

}

int main(void)
{
** *** * * * ** A[100],B[100];
** * ** ** **** *** ** * * * %s",A,B);

* ** ** ** (is_anagrams(A,B)) * ** * words or phrases are anagrams");
* * * ** * ** * printf("Two words or phrases are not **** ** *

** * ** *** ****** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** **
#include * * ** *
#include ********
int is_anagrams(char A[],char B[])
{
*** ** * * * * * **** * lenA = strlen(A),lenB = strlen(B),i,j,k;
** * * * ** **** * ** a = 0,b = 0;
* ** ** ** * * * * != lenB)
* ***** ** *** * ***** ** ** * ** ** **** ** * 0;
* ** * ** * * * ** * ** ** = 0 ; k < 26 ; k++)
* ****** **** * ** *** * * * *
***** ** ***** ** **** * **** ** * *** ** * * = 0 ; i < lenA ; i++)
** * ** * *** * * ****** ** ***
** ** *** * * *** * ***** ** *** **** * *** ***** * * * ****** * == A[i] || 'A'+k == A[i])
*** * * ** ** * * ***** *** * * * * ** ** ** ** **** ******* * *** ** * **** * ***
** * ****** ** ***** * * * **** ** ***** ** ***
** ** * * ***** ** * ****** *** * ** * = 0 ; i < lenB ; i++)
* * **** * * *** ** ** ** ** ** ** **** ** *
* *** * **** * ** ** * * ** ****** ** * * ***** *** ** ** ***** *** * * == B[i] || 'A'+k == B[i])
* * * ***** * ** * * * ***** * * * **** * *** ** * * * *** * * ** ** * *** * ** * * * * *
* ****** * *** * * * **** * ***** * **** ***** *
* *** * *** *** ** ****** *** *** * != b)
* * * * * * **** * **** ****** *** * ** * * ** ** * * * ** ***** ** * 0;
** * * **** * ** **** ** ***
* * **** *** * * * * * ***** * ** * ** * ** * * * * * ** * ***** 1;
}

int main(void)
{
*** **** *** ** ** * A[100],B[100];
* * *** ** ** * * * *** *
**** ** * * ******* ***** *
**** ** **** *** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** * * ** * printf("Two words or phrases are not anagrams");

** ** ** ** * * ** * * 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ****** *
#include **** **** *** *
#include * **
int is_anagrams(char A[],char B[])
{
* ** ** ** **** ** *** YOUR CODE HERE*/
* * * * **** * * **** **** * i,count[256]={0};
* * *** ** * ** * ** * * * * ***
** * * * *** * ** ***
** * ** ***** *** ** * ** ** * ** ** ** **** * * *** * ** * * * *
** * *** * *
* * ******** * ** ***** * *** *
* **** **** * * *
* * * * * **** ** *** * * **** * *** * ** ** ** * ** ** * ** * ** **
*** * * *** * * *
/*
* * * ** * ** * * * *** (A[i]!=0 || B[i]!=0){
* *** **** * * * ******* * ** * ******** ** * * ** * **
*** * * *** * *** ** *** * ** * * 0;
* * * **** ** ****** **
*/ ** ** * *** *** * **** ** *** *** 0;

* ***** * * *** *** (i = 0; i <256 ; i++)
*** *** * * **** *** * * * * *** ** ** * (count[i] && i!=' '){
*** ***** * * ** ******** ** ** ** ***** * ** * ****** ** * * * * * ** * * ** * * ** **
* ** ** ** ** ** ** *** * * **** *** ***** * ** ** * **** *** 0;
* * ****** * * ** * * * ** **** * * * ** * * *


**** * * ** * * ** ** * 1;

** *** ****** * OF YOUR CODE*/
** * * ** **** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* **** ** A[100],B[100];
****** ** * ** * * ** YOUR CODE HERE*/

**** ** ** * * ** ** *** ** *** *
** ** ** * ** ** *** * *** *

* * *** * * * *** * * * ** * = '\0';
  // **** ** * * ** * = '\0';
*** *** **** * ** ** **** * * i;
* *** ** * ***** * **** ** ** *****
* * * * * * ** *** * ** * *** **** ********* ** ** ***** * ** ***
** ** ** * ****** * * ** ***** * * ** * ** * ***
*** ** *** * * **** *** * *
*** * * * ** *** ** ** ** * * ** *** * ** ** ***** * ** **
** *** * * *** * * ** * *** * ** ** * **** ** * *

* *** ** *** * **** ** OF YOUR CODE*/
** ***** **** * ** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
* * ** ** * ***** printf("Two words or phrases are not anagrams");

** * * *** * * * ** ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ******* ****
#include ** ** *
#include ** ***
int * * * A[],char B[])
{
**** ***** ** * ** YOUR CODE HERE*/
* *** * ** * ** ** ****
***** **** * **** * *** ** * ***
* * *** * * * * * ** ** *
** ** *** *** * * ******* * * ** * ** * * ** * *
*** ** ** ** * ** *** ******* * ***** * ** ***** *
* ** * ** * * * ***
* ***** *** * *** * (A[i] || B[i])
* * * * * * * * * * * **** ** 0;

*** ** ** * ****** (i = 0; i < 256; i++)
** * * ** ** * ** * *** ** ** * ***** * ** * *
* ** * * * ** * * * * *** * ***** *** * *** * * * * * * * * 0;
* * **** *** ** * * 1;

* * ** *** * *** * OF YOUR CODE*/
* * * * * *** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * ** * * * ** * ** *** *
* * ** * ** YOUR CODE HERE*/
*** * * * * * * * *** ** * ******** * * * *** *
** ***** * * ** ****** *** * * * *** ****** ***

****** ** *** * OF YOUR CODE*/
** *** ***** *** ** ** ** ** * ** *** * words or phrases are * * ** **
** * ** * * * ** * ** * ** words or phrases are not ***** **

*** * * * * * * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ****** * **
#include * * ** *
#include ****** **
int ** *** A[],char B[])
{
*** **** * * ** ** *** * * * YOUR CODE HERE*/
**** ** * **** *** * * * * ****
** ** * ** * ** ** ** * * * ** * *
**** * ** * ******
* * *** ** * ** * ** ** ** **** * * * *** * *** *
* **** * * * ** *** *** * * ***** ** * ** **
* **** * * ** * *
* * * **** * * ** (A[i] || B[i])
**** ** ** * * ******* *** * * 0;

* * * *** ****** *** (i = 0; i < 256; i++)
** * * * ** ****** * **** * * * ***** *** ** * *
* ** * * *** ** * * ******* ** ** * * * ***** ** ** * ****** ** * *** 0;
*** **** * * * ******* * * * 1;

* ** ***** ** * ** * OF YOUR CODE*/
****** ** ** ** * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int ** *
{
* ** * *** *** * * *** * * * *
* * ** ** ** * ** * YOUR CODE HERE*/
* * * *** * *** *** * * * * * * **** *
**** **** ** ** * ** ** * ** * **** ** * * **

* * ** * * * ** **** * OF YOUR CODE*/
** ****** ****** * ** * ** *** words or phrases are ** ** ***
* * * ** ** ** * ** *** words or phrases are not ** *****

* * ***** * ** * 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.25
©2016-2024

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.5k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 3.8k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 3.1k views
12,783 questions
183,443 answers
172,219 comments
4,824 users