0 like 0 dislike
19k views

Write a function that tests whether two words or phrases are anagrams (permutations of the same letters):

寫一個判斷兩個單詞或詞組是不是符合易位構詞的函數。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int is_anagrams(char A[],char B[])
{
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   //The function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
   char A[100],B[100];
   /*INSERT YOUR CODE HERE*/


   /*END OF YOUR CODE*/
   if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
   else printf("Two words or phrases are not anagrams");

   return 0;
}

Example input:

smartest
mattress

Example output:

Two words or phrases are anagrams

Example input:

dumbest
stumble

Example output:

Two words or phrases are not anagrams

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 9: Functions
ID: 39986 - Available when: Unlimited - Due to: Unlimited
| 19k views
0 0
STRUPES!

79 Answers

0 like 0 dislike
Hidden content!
#include ** * ***
#include **** **** *
#include * *****
int **** * ** a[],char b[])
{
*** ** * ****** first[26] = {0}, second[26] = {0}, c = 0;
**
***** ** * **** * * * frequency of ** in first string
***
** *** * * * (a[c] != '\0')
* ** * * ** * ** *
* **** * * *** * * * *** **** * * * * *
*** * * * ***** * * ** ** **** *
**** * *** ** *
** * * *
** ** **** * * = 0;
* *
** ** ** ** * **** * (b[c] != '\0')
*** * ***** *** * **
* * *** ** ** ** **** * *** *** *** * *
** ********* ** *** *** * * ** ** *
*** ** * * **** *** *
* ***
**** * * * * ** * Comparing frequency of * *
**
* *** * *** * ** (c = 0; c < 26; c++)
*** *** * ** ** *
*** * ** * * *** ** ** ** * * (first[c] != second[c])
*** * ** ** * *** * * * *** * ** ** * **** 0;
*** ** ** **** **
* *
* ** ** * * ** * 1;
}

int *** *
{
* ** **** * **** *** **
** ******* * ** **** *** * * **** * * A,B);
* * * ** ** * *** ** **** **** ** * * * words or phrases are * * * ****
* ****** * * * ****** * * * words or phrases are not ** ** * **

* * * **** ** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ***
#include *** * * **
#include * ** * ** *
int * ** a[],char b[])
{
** * ***** * * ** first[26] = {0}, second[26] = {0}, c = 0;
******
* * * **** * **** * ** * frequency of characters in first string
*** ***
*** ** * *** ** * (a[c] != '\0')
* * * * ** ** *
*** * * * ** * ** * * *** * * **** ** * **
** ****** *** ** * * * * * **** ** **
***** * * * * *
* ***
* * * * *** = 0;
****
*** ** ** ** **** * * (b[c] != '\0')
*** * * ** ** *
******* * * * ** * * * * ** * *** *** ** **
** * **** *** * ** ***** **** * * *
** * ** * * * ** * *
** *****
*** * * * ***** *** Comparing frequency of ** **
*
* *** * ** ** ** * (c = 0; c < 26; c++)
** * ***** **** * *
* * * * *** **** *** ** * * **** * ** ** (first[c] != *
** ** * * ** ** ** * ** ** *** ** * ** ****** 0;
* * * ** * * ****
* * *
* ** * ** * **** ** 1;
}

int main(void)
{
* * ** * * ** * * ***
**** ** * * * ** ** ** **** *** * *** ** * *
* * * ** **** ** * * * ** * * * words or phrases are *** * ** *
* * ** * * ** ** *** * words or phrases are not ** ***

****** **** **** **** 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:38:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
            ^
prog.c:38:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
    scanf("%s %s", &A,&B);
               ^
0 like 0 dislike
Hidden content!
#include * ** * ** ** *
#include * ** * *
#include ** * * ***
int is_anagrams(char A[],char B[])
{
****** * * * **** * * YOUR CODE HERE*/
*** *** * ** *** * ** * * * * **
*** * ** * * *** * ** ** ** * ** * * ** ** *
* **** ******* * ********
*** * ** * *** *** * * ** ** ***** *** ** ****** * * && * ** * * * *
** ** * * *** ** **** * * ** * *** *** *** * ** * ** ***** * * *** *
*** *** * *** * * *** * ** ** **** * ** ** ** * ** * * && * * ** **
* *** ** * * ***** ** * * * **** * **** **** ** * * * **** ** * * * ***** ** * *
**** *** ** * * ******
** ** ** * * *** * *** *** ** * ** **
* * ** * *** ***
*** ** ***** ** * * * * *** * * * * ***** (cA[i]!=cB[i])
* * * * ******** *** * * * **** *** * **** *** **** * * * 0;
* *** * * * * *** * ***
** * * * ***** * * ** * * 1;
** **** * * * * * * ** OF YOUR CODE*/
***** ** * * ** * **** function should return 1 if two words or phrases are anagrams,
** * * ** ***** * * if two words or phrases are not anagrams.
}

int main(void)
{
* ***** ** * ** ** A[100],B[100];
* *** * ** ** * ** * YOUR CODE HERE*/
* * * ***** * ** ** * * * ***** **** **** * *
****** ** ******* * * ** *** * * **
* ** *** * ** ** (is_anagrams(A,B))
* * * ** ** * * * *** * ****** ** * *** ** * ** * ** words or phrases are anagrams");
* ** ** * * * * ** **** **
* * * * * * ** * ** * ** * * ** **** ***** ** **** * * words or phrases are not anagrams");
* * * * * ***** ** * * 0;
** * *** * * * * * OF YOUR CODE*/
}
answered by (-249 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:50:5: warning: implicit declaration of function 'fgets' [-Wimplicit-function-declaration]
     fgets(A,888,stdin);
     ^~~~~
prog.c:50:17: error: 'stdin' undeclared (first use in this function)
     fgets(A,888,stdin);
                 ^~~~~
prog.c:50:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:53:27: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     if (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
                           ^~~~~~
prog.c:53:27: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:53:27: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:54:10: warning: incompatible implicit declaration of built-in function 'printf'
     else printf("Two words or phrases are not anagrams");
          ^~~~~~
prog.c:54:10: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
** * ** * * ** * ** * * Array1[26] = {0}, Array2[26] = {0}, i = 0;
** * ** ***** *** * **
** ** ********* * * *** (A[i] != '\0')
* ** ** * * * ***
** ** * * * *** **** ** * ** *** * *** *** * * ** ** * **
* ** ** ** *** * * * * * ***** * * * ** ** *
* *** * ** ** *
* ** * ****** **** *** *
* *** ** * * ** = 0;
**** ****** * *
* ** *** * * * * ***** * **** (B[i] != '\0')
* ** * *** *** * * ***
* *** ** * * * **** ** * ** * *** ** **** **** ** *
* * *** *** *** **** *** * ** ** ** **** **
* * ** * * *
    
** * ** ***** * *** (i = 0; i < 26; i++)
**** **** ******* * * *
** **************** *** * * * ** * * * *** *** (Array1[i] != Array2[i])
* ** * * ** * *** * ** * * * *** ** * * * *** * ** *** ****** ** ** 0;
* **** ** * * * *
* **** ** ** *** ** * **
* ** * * * ** *** ***** 1;
}

int main()
{
** **** * **** *** * *** A[100],B[100];

* * * ** * ** ** * ** * * *** *
** * ** ** *** *** *** * * *** ** * * *
* *** *** * * ** *
* * *** ****** (is_anagrams(A,B))
* ** * * ** **** *
* ****** ** * * * *** *** ******* **** * * *** ** * ** * *** words or phrases are anagrams");
* ** * ********** * **
** ** * * * *** * * ** printf("Two words or phrases are not anagrams");
** * ** * * *** * *
* *** * *** ** * *** * * ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int is_anagrams(char A[],char B[])
{
****** *** *** * * *** Array1[26] = {0}, Array2[26] = {0}, i = 0;
*** * * ** * **** * *
** ** * ** *** * ** (A[i] != '\0')
*** ** * ** * ** * *
********* * ** * * * * * * ***** * ** * ** * * *
*** * * *** * * * * *** * ** **** *** * *** * *
**** ******* *** *** * *
*** ** * * * * **
*** ** * *** = 0;
*** ** * * ** ** *
* ***** * * ***** * *** ** * ** * (B[i] != '\0')
* *** * ** ** ***** **
***** * *** * * * * * * ** ** * * * ***
* ** * ** * ** * * * * * * ** ** **** *
* *** **** ** * *****
    
** ** * * ** ** ***** ***** (i = 0; i < 26; i++)
* ** *** ** ** * * * * *
* ** ****** * **** * ** ** *** (Array1[i] != Array2[i])
******** * * ** * * ** * * * * * ***** * ** ** ** * ** *** ** * 0;
** * * * ** * * *** * ******
* ** * * **** * ****
* * * * ** * ** * **** 1;
}

int main()
{
** * ****** * * * A[100],B[100];

** * ** ** * * **** **** * *** **** *
* * * ****** *** ** * *** * * ** * *** * ***
** ** * **** *
* * * ** ** *** *** ** (is_anagrams(A,B))
** * ******* ** ***
** * * **** * *** * * * * * *** * *** * words or phrases are anagrams");
**** ** * *
* * * * **** * ** printf("Two words or phrases are not anagrams");
***** ** * ** ** * ***
**** ***** ***** * *** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * * ** *
#include ** ** * *
#include ** * ** **
int is_anagrams(char A[],char B[])
{
** * ** *** **** * lenA = strlen(A),lenB = strlen(B);
** * ** ********* * * *** != lenB)
* * ** * * *** ** ** ** ** 0;

*** * * * * ** * * *** ** i,j,k,a[26] ={0},b[26] = {0};
** * *** ** ** ** * * * = 0 ; i < lenA ; i++)
* * * ** *** * * * ** ****
* ** * ** * *** * * * * * **** * * * * *** * = 0 ; j < 26 ; j++)
** * * *** * *** * * *** * * ** * * ** * ** **
* **** ** * * * * *** * ** * * * ** ** * * * * * * * * ** * * * == A[i] || 'A'+j == A[i])
** ******* ** * * * ** ** ** * * *** **** *** * * * * * * **** * *** *** * ** ** * * *
** ** * ** *** * ** * ** * ***** *** *****
* * * * *** ** * * *
** **** ***** ** *** **** * = 0 ; i < lenB ; i++)
***** ****** * **** ** * *
*** *** ** * ** * * *** ** * *** * * = 0 ; j < 26 ; j++)
****** * * *** * **** *** * ** * ** *** **
* * * *** * ** ** **** * ** ** * ** * * * ** ** **** ** * *** == B[i] || 'A'+j == B[i])
**** *** **** * *** * * **** * *** ** **** ** ** ** ** * * *** * ***** * * ** * **
* * ** * * *** ** * ** ** * * **** *** * *
* * ***** ***** * *
* ** **** *** * ***** = 0 ; j < 26 ; j++)
*** * * * ******* * *** **** *
** ** ***** ** * * * * ** * ** * ** ** * ** * != b[j])
* * ** ***** ** ** * * **** * ** * ** ******* * * ***** *** *** 0;
**** ** *** * ** *
* ** * ** * * * * 1;

}

int main(void)
{
* * *** * ***** **** A[100],B[100];
* * *** ** * * *** %s",A,B);

*** * ** * (is_anagrams(A,B)) * * ** words or phrases are anagrams");
** **** * ** * **** * printf("Two words or phrases are not * ** * **

** ** * * **** *** 0;
}
1/100 answered by (-255 points)
edited by
0 0
prog.c: In function 'is_anagrams':
prog.c:38:1: error: expected declaration or statement at end of input
 }
 ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** *** * **
#include * * **** * *
#include **** * * *
int is_anagrams(char A[],char B[])
{
* * * **** *** * ** lenA = strlen(A),lenB = strlen(B),i,j,k;
** * * ** * * * *** * a = 0,b = 0;
*** * **** * * * *** * *** ** *** * != lenB)
* * ***** * *** * ***** * * * * * ** * * 0;
** * *** *** * *** * ** ** * = 0 ; k < 26 ; k++)
** **** **** **** * **
* ** * *** * ****** * * ** * ** * * *** * = 0 ; i < lenA ; i++)
* * ***** * * * * *** * * ** **** *
** ** * * ** ***** ** **** *** * * * *** * *** * ** * * * ****** * * * == A[i] || 'A'+k == A[i])
* * * * ** ** * * * ***** ****** * *** ** ** ****** * * * ***** ***** ** ** ** * ** **
* ** * **** * ** * ** * * ***** * * **
* *** *** * * **** ** * ** ***** * *** *** * = 0 ; i < lenB ; i++)
** *** * *********** ****** ***** * * ** * **
* * * * ** ** ** *** ** * * *** *** * * * * * *** * * * ** * * * * == B[i] || 'A'+k == B[i])
** * * * * * * ** ** * ****** * *** * *** ***** ** * * ***** * * ** ** ****** * ** * * ** *** * *
* * * * ** * *** ** * ** * * * **** ****
*** * *** * ** *** **** ** * * * ** * * != b)
* ** * **** * ** * ** * *** * * * * * ** * * *** * * * *** * 0;
* * ** * * * ** **** ** **
** * * ***** ** * *** ** * * * *** ** ** * * ** * * * * * * ***** ** 1;
}

int main(void)
{
** * * * ** *** *** A[100],B[100];
**** **** * ** **** **** ** * **
****** * ** * * ** ******
* *** *** ** * * (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** ** ** * * **** printf("Two words or phrases are not anagrams");

** * *** * * * ** 0;
}
answered by (-255 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** *** *
#include * *** ** ** *
#include ** ***** ***
int is_anagrams(char A[],char B[])
{
*** **** *** ***** * YOUR CODE HERE*/
* * * ** * * i,count[256]={0};
***** * *** * **** ** ** *
** ** ** * * ** * ** * *
*** *** ** *** * ** * * *** **** * ** ** ** ** ** * *** ****** **
* * ** ** * *** *** * **
*** ** * * ** **** *** *
* **** * ** * ****
****** *** * * ****** * ****** ** ****** ** * * * * * ** ** ** **
*** ***** ** ** ** * *
/*
* * * **** * * * * ** * (A[i]!=0 || B[i]!=0){
* **** *** ** * * * ** * * ** ** * * * * **** ** * *** * * *
** ***** * ** *** * ** * * * ***** ** * * * ** 0;
***** * * * * * ** ***
*/ * ***** ** **** * * *** * ** * 0;

* * * * * * * * ** (i = 0; i <256 ; i++)
** *** *** **** ****** * *** ****** **** * * (count[i] && i!=' '){
* * *** ** * ** *** * *** * * ** ** *** * ** ** * * * ** * *** ** ** ** * * * *** * ** * *
* *** ** * **** ** * ** * * ** *** * **** * ** ******* **** ** * *** 0;
** * *** **** *** * ** *** * *** *


****** *** *** * *** ** *** 1;

* * *** * ** * OF YOUR CODE*/
* ***** ** ** * * * function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int main(void)
{
* * * ** * ** A[100],B[100];
* * * ***** YOUR CODE HERE*/

* * * * * ** * *** * ** ** *
* * * * **** ** *** *****

***** * * * ******* * * * = '\0';
  // ** *** * = '\0';
* ** ** ** ** *** *** i;
****** *** * * * *** * * *
** *** * ** * * ** * *** **** ** ** * *** *** *** * ** * * **** ** **
*** ** * ** **** ** **** * * *** * * * * * * *
** ***** * * *** ** ** ** *** * * *
*** ** ** * ** ** * ** *** * *** * **** * *** ******** ** ** * ***
*** * *** * * * * * * ** * *** * **** * * * ** *

* ***** ** **** OF YOUR CODE*/
** *** * ** **** (is_anagrams(A,B)) printf("Two words or phrases are anagrams");
** * ** * * **** printf("Two words or phrases are not anagrams");

* *** *** * ** *** *** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * ***
#include * * * ** *
#include * ** * * * *
int * * ** * A[],char B[])
{
* ** * * * ** * YOUR CODE HERE*/
*** ** ** * * ** ** * * * *** **
** * ** ** * ** ***** ** *** * * * ** ******* *** *
* * ** * * * ** ***
* ** * ***** * * * *** * **** * ** ** ********** *** * * *
** * *** *** * * ** ** * ** **** **** ** * ** **
* *** *** ******* *
** * *** ******** * ** * (A[i] || B[i])
* ** * * * * ** ** * * * * 0;

* *** ** *** ** * ****** (i = 0; i < 256; i++)
** ** ** * * *** ** **** *** ** * ** * * *
**** * * *** ** * ** * *** * * * * * *** * * **** * * * *** ** 0;
** ****** * **** * 1;

*** * ***** * *** * OF YOUR CODE*/
*** * * ******** **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* * *** * ** **** ** * ***
* * * *** * * *** ** YOUR CODE HERE*/
** *** * ** * * * *** ** *** **** * **
* * * * *** * ** ** ******** ** ** ** ***

** ** * *** * *** * OF YOUR CODE*/
** ** ** ** * * * * ** *** ***** * * * * * *** * words or phrases are ***** * * ***
** **** * * * * * * ** * * * words or phrases are not ** * ********

* *** * *** *** * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&A);
                ^
prog.c:30:16: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%100s",&B);
                ^
0 like 0 dislike
Hidden content!
#include ** ** * *** *
#include * * * * *
#include **** * **** *
int *** * **** A[],char B[])
{
* ******* ****** * YOUR CODE HERE*/
* **** * * *** ** * ** * * ******* * *
**** **** ** * ***** ** *** ** * *** * ***
** ** ******** *
** * ** * **** * ** * * * ** * ** * ** * * * * * ******
* * * * *** * * ** ** * **** * ** ** * * ** ***** **
* **** * * ** ** *
* ** ** **** *** * * * (A[i] || B[i])
**** ** * ** ** * * * ** * * * * * 0;

* * *** * * ** * ** * (i = 0; i < 256; i++)
*** *** * * ****** ** * * **** ** * * ****** * * *** *
* **** ** * ** ** * **** *** ***** *** * * ** ***** * *** *** * * ** 0;
**** ** * *** * * ** 1;

***** **** * ******** *** * OF YOUR CODE*/
** * ** *** ** **** function should return 1 if two words or phrases are anagrams, 0 if two words or phrases are not anagrams.
}

int * *
{
* *** * * * ** * * * ** **
*** ** * ** * * * **** YOUR CODE HERE*/
* * *** * ** * ** ** * * * * **
***** * **** *** * * * ** ** * **** *

* * *** ** * ** ** * OF YOUR CODE*/
* * * * * * ** * * **** * * ** ** ** * words or phrases are ***** *
* *** * *** ** * * * ** words or phrases are not ** * **

** ** * * ** 0;
}
answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:29:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&A);
             ^
prog.c:30:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&B);
             ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.77
©2016-2025

Related questions

0 like 0 dislike
47 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35785 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
45 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 35784 - Available when: 2017-12-07 18:00 - Due to: Unlimited
| 9.5k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users